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  • Check if string is serialized in PHP

    - by Industrial
    Hi everyone, I am in the middle of building a cache layer for the Redis DB to my application and I have come to the point where's it's about to take care of arrays. I wonder if there's any good (high performance!) way of controlling an string to be serialized or not with PHP? Thanks a lot!

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  • .htaccess or PHP protection code against multiple speedy requests

    - by Phil Jackson
    Hi, I am looking for ideas for how I can stop external scripts connecting with my site. I'm looking for the same kind of idea behind Google. As in if a certain amount of requests are made per a certain amount of time then block the IP address or something. I thought there maybe a htaccess solution if not, I will write a PHP one. Any ideas or links to existing methods or scripts is much appreciated. Regards Phil

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  • PHP getting Twitter API JSON file contents without OAuth (Almost have it)

    - by DexCurl
    Hey guys, I have this script working fine with OAuth, but I accidentally nuked my 350 API hits with a stupid while statement :( I'm trying to get data from the Twitter API without OAuth, I can't figure it out (still pretty new), heres what I have <html> <body> <center> <hr /> <br /> <table border="1"> <tr><td>ScreenName</td><td>Followed back?</td></tr> <?php //twitter oauth deets $consumerKey = 'x'; $consumerSecret = 'x'; $oAuthToken = 'x'; $oAuthSecret = 'x'; // Create Twitter API objsect require_once("twitteroauth.php"); $oauth = new TwitterOAuth($consumerKey, $consumerSecret, $oAuthToken, $oAuthSecret); //get home timeline tweets and it is stored as an array $youfollow = $oauth->get('http://api.twitter.com/1/friends/ids.json?screen_name=lccountdown'); $i = 0; //start loop to print our results cutely in a table while ($i <= 20){ $youfollowid = $youfollow[$i]; $resolve = "http://api.twitter.com/1/friendships/exists.json?user_a=".$youfollow[$i]."&user_b=jwhelton"; $followbacktest = $oauth->get($resolve); //$homedate= $hometimeline[$i]->created_at; //$homescreenname = $hometimeline[$i]->user->screen_name; echo "<tr><td>".$youfollowid."</td><td>".$followbacktest."</td></tr>"; $i++; } ?> </table> </center> </body> </html> Neither of the two Twitter functions require authentication, so how can I get the same results? Thanks guys, Dex

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  • Set php file permissions so only my server's curl can run

    - by robr
    I have a PHP script that I don't want anyone to be able to run through their browser. It sends emails and is called via curl by my server's cron, yet needs to be in the public www directory. What permissions or owner do I need to set the file to to allow only my server's curl to execute (or do I mean read) the file? I'm on centos. Thanks!

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  • PHP + Mongodb error

    - by mdm414
    Hi, I followed the windows installation instructions in mongodb's website but I still can't connect to MongoDB through PHP because of this error: Class 'Mongo' not found Why isn't the file containing the Mongo Class not being loaded? Thanks

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  • Undefined function in php

    - by Bidyut
    I wrote three methods in a class and one is calling another, but when I call the function outside through the object, it is showing an undefined function error for the second function. Here's my code: function resize_image(){ } function image_resize(){ $a = resize_image(); } When I run this, it shows resize_image() as undefined. Here's the error: Fatal error: Call to undefined function resize_image() in /home/vacayge/public_html/Major/Alpha1/classes/cUserImages.php on line 2090

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  • how can I reset field after check it with php

    - by mjd
    Hi all, I have a html form that sends the data from 2 fields (memer no. , pw) via axaj (getElementById)to php file to check them with database info. . I did every thing well but I want to reset both fields if one of them is incorrect . How can I send reset order back to html form ? notice - I didn't use submit button just normal button to keep in same page. Thanks all

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  • MOOTOOLS calling sexy.error() from PHP

    - by Mikey1980
    I am very inexperienced with PHP and I've having trouble calling a mootools function. Here's my code: echo '<script language="JavaScript">'; echo "Sexy.error('Test!');"; echo '</script>'; When I try it with a simple alert('test') it works just fine.. I'm confused?!?

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  • Submitting form in php file accessed by Ajax?

    - by dronnoc
    Hi people, I am trying to figure out how to submit a form in a page being accessed by Ajax? here are some code snippets to help demonstrate what i am trying to say. HTML BODY - THIS IS WHAT THE USER WILL SEE. <html> <head> <script language="javascript" src="linktoajaxfile.js"> </head> <body onLoad="gotoPage(0)"> <div id="fillThis"> </div> </body> </html> AJAX FILE var xmlhttp function gotoPage(phase) { xmlhttp=GetXmlHttpObject(); if (xmlhttp==null) { alert ("Your browser does not support AJAX!"); return; } var url="pageofstuffce.php"; url=url+"?stg="+phase; url=url+"&sid="+Math.random(); xmlhttp.onreadystatechange=stateChanged; xmlhttp.open("GET",url,true); xmlhttp.send(null); } function stateChanged() { if (xmlhttp.readyState==4) { document.getElementById("fillThis").innerHTML=xmlhttp.responseText; } } function GetXmlHttpObject() { if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari return new XMLHttpRequest(); } if (window.ActiveXObject) { // code for IE6, IE5 return new ActiveXObject("Microsoft.XMLHTTP"); } return null; } PAGE OF DATA <?php $stage = $_GET['stg']; if($stage == 0) { echo '<a onClick="gotoPage(1)">click me</a>'; } elseif($stage == 1) { <form> <input type="text" name="name"> <input type="submit" name="submit"> </form> } elseif(somehow can reach here) { show data from form. } ?> Can anyone perhaps help me get past the form and display the data in the same page? Also, i have looked around, and i don't think anything around has what i need... correct me if i'm wrong though :) Thanks in advance, and i hope i didn't put in too much detail :) Dronnoc EDIT Forgot to mention what I've tried; I have tried submitting the form to itself (same file) and that destroyed the ajax link, and opened the page. i have also tried just having the button move the page onto another step, but the $_POST variable is empty... i am at a loss, so does anyone else have any ideas?

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  • Android : Connecting to MySQL using PHP

    - by user1771128
    I followed the following article http://blog.sptechnolab.com/2011/02/10/android/android-connecting-to-mysql-using-php/ I am able to execute my php file. I executed it individually and its working fine. The problem is in the android execution part. Am posting the Log Cat for the error am facing. Tried putting in a List View with id "list" but the error stil 10-28 16:08:27.201: E/AndroidRuntime(664): **FATAL EXCEPTION: main** 10-28 16:08:27.201: E/AndroidRuntime(664): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.city/com.example.city.City}: java.lang.RuntimeException: Your content must have a ListView whose id attribute is 'android.R.id.list' 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1956) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:1981) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.access$600(ActivityThread.java:123) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1147) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.os.Handler.dispatchMessage(Handler.java:99) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.os.Looper.loop(Looper.java:137) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.main(ActivityThread.java:4424) 10-28 16:08:27.201: E/AndroidRuntime(664): at java.lang.reflect.Method.invokeNative(Native Method) 10-28 16:08:27.201: E/AndroidRuntime(664): at java.lang.reflect.Method.invoke(Method.java:511) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:784) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:551) 10-28 16:08:27.201: E/AndroidRuntime(664): at dalvik.system.NativeStart.main(Native Method) 10-28 16:08:27.201: E/AndroidRuntime(664): Caused by: java.lang.RuntimeException: Your content must have a ListView whose id attribute is 'android.R.id.list' 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ListActivity.onContentChanged(ListActivity.java:243) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.policy.impl.PhoneWindow.setContentView(PhoneWindow.java:254) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Activity.setContentView(Activity.java:1835) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.example.city.City.onCreate(City.java:35) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Activity.performCreate(Activity.java:4465) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1049) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1920) 10-28 16:08:27.201: E/AndroidRuntime(664): ... 11 more

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  • redirect images to php script

    - by Jonathan
    I want to be able to redirect all requests to navigate to an image to a php script which will then show the image but with a nav bar at the top. However using rewrite (im using IIS btw) means that I can't embed those images. Any help will be greatly appreciated.

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  • seperated mysql statement query in php

    - by stone
    So, I can run the following statements from within mysql itself successfully. SET @fname = 'point1'; SELECT * FROM country WHERE name=@fname;` But when I try to pass the query through php like this and run it, I get an error on the second line $query = "SET @fname = 'point1';"; $query .= "SELECT * FROM country WHERE name=@fname;";

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  • php symantics of setting cookies and redirecting without getting header error

    - by salmane
    I would like to do the following in php : setcookie('name', $value, $Cookie_Expiration,'/'); then some action header("location:http://www.example.com") the problem is that I get : warning: Cannot modify header information - headers already sent by (...etc ) could you please let me know what i am doing wrong and if there is a way to do this? by the way , this code is before any output is made ...the cookie setting part works fine on its own and so does the redirection code....the combination fails thank you

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  • Get values from HTML in a multidimensional array and calculate values using PHP

    - by Frank Nwoko
    I have searched but could not get solution on this issue. I am working on an application which will generate unknown number of items and have users select the quantity from a drop down against each item. Eg. Item(s) | price | Select qty Rice 23 3 Beans 22 4 Eggs 52 5 ... ... ... unknown Please, how can I capture the above in an array and also calculate the total value for all selected items and corresponding fees? I have the following HTML code: <form id='form1' name='form1' method='post' action='item_calc.php'> <?php ..... while($t_row = mysql_fetch_assoc($get_items)) { echo "<p><label>$t_row['$item_name'] <input type='text' READONLY name='item_price[]' value='$t_row['$item_price']' /></label> <input type='text' READONLY name='item_fees[]' value='$t_row['$item_fee']' /> <select name="item_qty"> <option value="1"> <option value="2"> <option value="3"> <option value="4"> <option value="5"> </select> </p><p>"; } echo "<label><input type='submit' name='submit' value='Submit' /></label></p> </form>"; Please, how can I get item_price[] + item_fees[] * item_qty for all selected items? This is what I have tried: for ($i = 0; $i < count($_POST['item_price']); $i++) { // Do something here with $_POST['checkbx'][$i] foreach ($_POST['item_fees'] as $tkey => $tvalue) { //echo "Key: $tkey; Value: $tvalue<br>"; } foreach ($_POST['item_price'] as $pkey => $pvalue) { //echo "Key: $pkey; Value: $pvalue<br>"; } $total = $tvalue + $pvalue; } echo $total;

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  • PHP class function.

    - by Jordan Pagaduan
    What is wrong with this code? <?php class users { var $user_id, $f_name, $l_name, $db_host, $db_user, $db_name, $db_table; function user_input() { $this->$db_host = 'localhost'; $this->$db_user = 'root'; $this->$db_name = 'input_oop'; $this->$db_table = 'users'; } function userInput($f_name, $l_name) { $dbc = mysql_connect($this->db_host , $this->db_user, "") or die ("Cannot connect to database : " .mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "insert into $this->db_table values (NULL, \"$f_name\", \"$l_name\")"; $result = mysql_query($query); if(!$result) die (mysql_error()); $this->userID = mysql_insert_id(); mysql_close($dbc); $this->first_name = $f_name; $this->last_name = $l_name; } function userUpdate($new_f_name, $new_l_name) { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "UPDATE $this->db_table set = \"$new_f_name\" , \"$new_l_name\" WHERE user_id = \"$this->user_id\""; $result = mysql_query($query); $this->f_name = $new_f_name; $this->l_name = $new_l_name; $this->user_id = $user_id; mysql_close($dbc); } function userDelete() { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "DELETE FROM $this->db_table WHERE $user_id = \"$this->user_id\""; mysql_close($dbc); } } ?> The error is: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\jordan_pagaduan\class.php on line 21 Cannot connect to database : Access denied for user 'ODBC'@'localhost' (using password: NO) The code cannot define this "$this->db_host" as "localhost".

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  • php extracting complete url with variables

    - by salmane
    Hi there, Using Php I would like to extract the current Url of a page including all variables attached to it. $_SERVER['PHP_SELF'] only return the url without the variable . any idea what function I need. example : www.site.com/?v1=xyz&v2=123 using $_SERVER['PHP_SELF'] I get only : www.site.com as opposed to the whole url. using $_GET[] individually is not an opton since I am not sure what variable are attached to the URL. thank you

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  • [php] call_user_func_array problems

    - by Knarf
    I have a class with this in self::$DB = new PDO("mysql:dbname=$dbname;host:=127.0.0.1" , 'root' , ''); and then this public static function __callStatic($name, $arguments) { return call_user_func_array(array('self::$DB', $name), $arguments); } How does I make it right/work? Warning: call_user_func_array() expects parameter 1 to be a valid callback, class 'self::$DB' not found in D:\Mine Dokumenter\My Dropbox\www\Framework 3\database.class.php on line 19

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