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  • WPF - How do I use the UserControl with a dependency property and view model?

    - by user320849
    Hello, My goal is to have a user select a year and a month. Translate the selection into a date and have the user control send the date back to my view model. That part works for me....However, I cannot get the ViewModel's initial date to set those drop downs. public static readonly DependencyProperty Date = DependencyProperty.Register("ReturnDate", typeof(DateTime), typeof(DatePicker), new FrameworkPropertyMetadata{BindsTwoWayByDefault = true,}); public DateTime ReturnDate { get { return Convert.ToDateTime(GetValue(Date)); } set { SetDropDowns(value); SetValue(Date, value); } } The SetDropDowns(value) just sets the selected items on the combo boxes, however, the program never makes it to that method. On the view I am using: <cc1:DatePicker ReturnDate="{Binding Path=StartDate, Mode=TwoWay}" IsStart="True" /> If this has been answered, then my bad. I looked around and didn't see anything that worked for me. Thus, when the program loads how do I get the value from the view model to a method in order to set the combo boxes? Thanks, -Scott

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  • Ruby on Rails: building a model with an attribute not in the database?

    - by randombits
    I have a model that sets one of its attributes based off of a form parameter that a user submits. The model is a child resource to a parent resource Home. A hypothetical example is the following: A class Person has an age attribute. The user submits a birthdate as an HTTP POST parameter and from that, I need to derive the age of the user. So I'd do something like this: @home.people.build(:name => params[:name], :birthdate => params[:birthdate]) Rails would barf on that for obvious reasons, complaining it doesn't know what the attribute birthdate is. What's the proper way of going about this? Is it possible to use the build constructor with the supplied solution so that my foreign key relations are also setup properly? If not, what's a better way to work around this problem?

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  • NetBeans Platform - how to refresh the property sheet view of a node?

    - by I82Much
    Hi all, I am using the PropertySheetView component to visualize and edit the properties of a node. This view should always reflect the most recent properties of the object; if there is a change to the object in another process, I want to somehow refresh the view and see the updated properties. The best way I was able to do this is something like the following (making use of EventBus library to publish and subscribe to changes in objects): public DomainObjectWrapperNode(DomainObject obj) { super (Children.LEAF, Lookups.singleton(obj)); EventBus.subscribe(DomainObject.class, this); } public void onEvent(DomainObject event) { // Do a check to determine if the updated object is the one wrapped by this node; // if so fire a property sets change firePropertySetsChange(null, this.getPropertySets()); } This works, but my place in the scrollpane is lost when the sheet refreshes; it resets the view to the top of the list and I have to scroll back down to where I was before the refresh action. So my question is, is there a better way to refresh the property sheet view of a node, specifically so my place in the property list is not lost upon refresh?

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  • Is it good choice to move a Sublayer around a view using UIPanGestureRecognizer?

    - by Pranjal Bikash Das
    I have a CALayer and as sublayer to this CALayer i have added an imageLayer which contains an image of resolution 276x183. I added a UIPanGestureRecognizer to the main view and calculation the coordinates of the CALayer as follows: - (void)panned:(UIPanGestureRecognizer *)sender{ subLayer.frame=CGRectMake([sender locationInView:self.view].x-138, [sender locationInView:self.view].y-92, 276, 183); } in viedDidLoad i have: subLayer.backgroundColor=[UIColor whiteColor].CGColor; subLayer.frame=CGRectMake(22, 33, 276, 183); imageLayer.contents=(id)[UIImage imageNamed:@"A.jpg"].CGImage; imageLayer.frame=subLayer.bounds; imageLayer.masksToBounds=YES; imageLayer.cornerRadius=15.0; subLayer.shadowColor=[UIColor blackColor].CGColor; subLayer.cornerRadius=15.0; subLayer.shadowOpacity=0.8; subLayer.shadowOffset=CGSizeMake(0, 3); [subLayer addSublayer:imageLayer]; [self.view.layer addSublayer:subLayer]; It is giving desired output but a bit slow in the simulator. I have not yet tested it in Device. so my question is - Is it OK to move a CALayer containing an image??

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  • How to resolve the only ImagePicker control view in landscap mode and whole application in portrait mode?

    - by Wolvorin
    I have tried almost all the answers during last two days provided by Google and SO but no luck :( What I want is my whole application is in portrait mode only. And it working fine in ios 6+. The only support required at now. But the problem is I need to launch UIImagePickerViewController with image source type camera in only landscap mode. What I tried till now is : (1) I try to create one category for UIImagePickerController for orientation. -(BOOL)shouldAutorotate { return NO; } -(NSUInteger)supportedInterfaceOrientations { return UIInterfaceOrientationMaskLandscape; } - (UIInterfaceOrientation)preferredInterfaceOrientationForPresentation { return UIInterfaceOrientationLandscapeLeft; } Like this. But the camera view is not proper aligned. It just follows the orientation of device with some +/- 90 angle but not what I required. Even the button of the camera shown by camera view as camera control is also follows the camera view, ie. the view is rotated to 90 anti clock vise and stays to that way. Is there any way to use the camera with proper alignment? or have to use other framework to work with it? Please help me. I stuck with it for last two days.

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  • Can I use Pub/Sub model with Many Publishers and Only One Subscriber?

    - by rauch
    I need to send some files from different machines to only one Server. As I understand, I can use JMS api + (for example) ActiveMQ as broker. There are two models: p2p and pub/sub. I would like to use pub/sub model, but the problem is that I haven`t few subscribers, I have only one Subscriber(Server) and many Publishers. The question is the following: can I use pub/sub model for my situation and How can I send files from different machines to Only One Topic, on that Server sibscribed? May be any other ideas, thanks a lot.

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  • What's the best way to share one Entity Framework 4 data model among multiple applications (meant to

    - by Ivan
    A project (a "solution" to say in VS terms) of mine consists of an ASP.Net 4 Dynamic Data Entities web application, some WinForms applications, some WPF applications, some services. All they are intended to work with one SQL Server database, generated from an Entity Framework 4 model as table-per-type, with lots of inheritance and multiple self-referencing relations. Where do I best put my model? In a separate class library, a copy in every project, in one project, etc. What naming should I best use? Is it good idea to name it MySolution.MyClassLibrary.MySolutionEntities, or just MySolutionEntities or just MySolution? Can you share any useful experience on this subject?

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  • Where could I get the information about the in-memory layout info of .NET Object Model?

    - by smwikipedia
    I want to know the in-memory representation of .NET constructs such as "interface", "class", "struct", etc. There's an excellent book for C++ object model - <Inside the C++ Object Model by Stanley. Lippman, I want a similar book for .NET and C#. Could someone provide some hints about books and articles? I have read about the "Drill Into .NET Framework Internals to See How the CLR Creates Runtime Objects" Anything more? If this info is not publicly avaialble. Shared source one like Mono or Shared Source CLI could be an option. Many thanks.

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  • How do I dynamically assign the Model for a .find in Ruby on Rails?

    - by Angela
    I am trying to create a Single Table Inheritance. However, the Controller must be able to know which class to find or create. These are based on another class. For example, ContactEvent with type = Letter needs to grab attributes from a corresponding Model called Letter. Here's what I've tried to do and hit a snag, labelled below. I need to be able to dynamically call assign a value of EventClass so that it can be Letter.find(:conditions =) or Calls.find(:conditions =) depending on which type the controller is acting on. def new @contact_event = ContactEvent.new @contact_event.type = params[:event_type] # can be letter, call, postcard, email @contact_event.event_id = params[:event_id] # that ID to the corresponding Model @contact_event.contact_id = params[:contact] @EventClass = case when @contact_event.type == 'letter' then 'Letter' when @contact_event.type == 'call' then 'Call' when @contact_event.type == 'email' then 'Email' SNAG BELOW: @event = @EventClass.find(@contact_letter.letter_id) #how do I make @EventClass actually the Class?SNAG # substitution of variables into the body of the contact_event @event.body.gsub!("{FirstName}", @contact.first_name) @event.body.gsub!("{Company}", @contact.company_name) @evebt.body.gsub!("{Colleagues}", @colleagues.to_sentence) @contact_event.body = @event.body @contact_event.status = "sent" end

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  • How to Inserting message into View that depends on session value. ASP.NET MVC. Best practice

    - by Andrew Florko
    User have to populate multistep questionnaire web-forms and step messages depend on the option chosen by user at the very beginning. Messages are stored in web.config file. I use asp.net mvc project, strong typed views and keep business logic separated from controller in static class. I don't want to make business logic dependency on web.config. Well, I have to insert message into view that depends on session value. There are at least 2 options how to implement this: View model has property that is populated in controller/businessLogic and rendered in view like <%: Model.HelpMessage1 %>. I have to pass web.config values from controller to businessLogic that makes business logic methods signature too complex. I don't want to make configuration source abstract (in order to let business logic read configuration values from its methods directly) also. Create static helper class that is called from view like <%: ViewHelper.HelpMessage1(Model.Option1) %>. But in this case logic what to show seems to be separated into two classes: business logic & viewHelper. What will you suggest? Thank you in advance!

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  • How do I construct a Django form with model objects in a Select widget?

    - by Thierry Lam
    Let's say I'm using the Django Site model: class Site(models.Model): name = models.CharField(max_length=50) My Site values are (key, value): 1. Stackoverflow 2. Serverfault 3. Superuser I want to construct a form with an html select widget with the above values: <select> <option value="1">Stackoverflow</option> <option value="2">Serverfault</option> <option value="3">Superuser</option> </select> I'm thinking of starting with the following code but it's incomplete: class SiteForm(forms.Form): site = forms.IntegerField(widget=forms.Select()) Any ideas how I can achieve that with Django form?

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  • Showing custom model validation exceptions in the Django admin site.

    - by Guy Bowden
    I have a booking model that needs to check if the item being booked out is available. I would like to have the logic behind figuring out if the item is available centralised so that no matter where I save the instance this code validates that it can be saved. At the moment I have this code in a custom save function of my model class: def save(self): if self.is_available(): # my custom check availability function super(MyObj, self).save() else: # this is the bit I'm stuck with.. raise forms.ValidationError('Item already booked for those dates') This works fine - the error is raised if the item is unavailable, and my item is not saved. I can capture the exception from my front end form code, but what about the Django admin site? How can I get my exception to be displayed like any other validation error in the admin site?

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  • Where is the best place to call the .tolist(); inside my controller classes or inside my model repository classes

    - by john G
    I have the following action method, inside my asp.net mvc web application:- public JsonResult LoadZoneByDataCenter(string id) { var zonelist = repository.getrealtedzone(Convert.ToInt32(id)).ToList(); //code goes here Which calls the following model repository method:- public IQueryable<Zone> getrealtedzone(int? dcid) { return tms.Zones.Where(a=> a.DataCenterID == dcid || dcid == null); } Currently I am calling the .tolist() which will interpret the Database from my action method, but my question is where is the best place to call the .tolist() inside the controller or inside the model classes and why ? thanks

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  • how to model editing of multiple related resources on the same webpage?

    - by amikazmi
    Lets say we have a Company model, that has many Employees And has many Projects If we want to show the projects, we'll go to "/company/1/projects/index" If we want to edit 1 project, we'll go to "/company/1/projects/1/edit" What if we want to edit all the projects at once on the same webpage? We can go to "/company/1/edit" and put a nested forms for all the projects But what if we need a different webpage to edit all the employees at once too? We can't use "/company/1/edit" again.. Right now we do "/company/1/projects/multiedit", "/company/1/projects/multupdate"- but as you can see, it's not rest. How can we model this restfully?

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  • Where should my "filtering" logic reside with Linq-2-SQL and ASP.NET-MVC in View or Controller?

    - by Nate Bross
    I have a main Table, with several "child" tables. TableA and TableAChild1 and TableAChild2. I have a view which shows the information in TableA, and then has two columns of all items in TableAChild1 and TableAChild2 respectivly, they are rendered with Partial views. Both child tables have a bit field for VisibleToAll, and depending on user role, I'd like to either display all related rows, or related rows where VisibleToAll = true. This code, feels like it should be in the controller, but I'm not sure how it would look, because as it stands, the controller (limmited version) looks like this: return View("TableADetailView", repos.GetTableA(id)); Would something like this be even work, and would it be bad what if my DataContext gets submitted, would that delete all the rows that have VisibleToAll == false? var tblA = repos.GetTableA(id); tblA.TableAChild1 = tblA.TableAChild1.Where(tmp => tmp.VisibleToAll == true); tblA.TableAChild2 = tblA.TableAChild2.Where(tmp => tmp.VisibleToAll == true); return View("TableADetailView", tblA); It would also be simple to add that logic to the RendarPartial call from the main view: <% Html.RenderPartial("TableAChild1", Model.TableAChild1.Where(tmp => tmp.VisibleToAll == true); %>

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  • Adding a footer to a table in another view?

    - by cannyboy
    The app I'm making has a settings view which I want to show on the first run of the app. Normally (after the first run) this view will be pushed onto the screen and there will be a "Back" button in the nav bar. However, on first launch I don't want there to be a back button. Instead, I want to add a 'Done' button at the footer of the table... and then the view can be popped. Here's my code (in my initial view's viewDidLoad). I have removed the back button, but don't know how to add the footer and button. NSUserDefaults *prefs = [NSUserDefaults standardUserDefaults]; if ([prefs stringForKey:@"firstRun"] == nil) { SettingsViewController *settingsView = [[SettingsViewController alloc] initWithNibName:@"SettingsView" bundle:nil]; settingsView.hidesBottomBarWhenPushed = YES; settingsView.navigationItem.hidesBackButton = TRUE; // add footer button here? [[self navigationController] pushViewController:settingsView animated:YES]; [settingsView release]; [prefs setObject:@"OK" forKey:@"firstRun"]; } else { //something }

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  • In Entity framework, we can use Model first, DB first, Code first but how can we create table programmatically

    - by AukI
    In entity framework we can use 3 approaches model first , code first , database first but each one of them needs manual hand touch(means creating database or create model or write the POCO class codes or entity class codes) before proceeding to the next step ( using EF in context ). What if I want to create database and tables and table relationships programatically and still want to have to features of EntityFramework 4.3. To be more specific , from this example http://support.microsoft.com/kb/307283 we can create database , tables and everything using SQL command but we can't have the advantages of entity framework. So if we want to have that what should we do?

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  • Any tips of how to handle hierarchial trees in relational model?

    - by George
    Hello all. I have a tree structure that can be n-levels deep, without restriction. That means that each node can have another n nodes. What is the best way to retrieve a tree like that without issuing thousands of queries to the database? I looked at a few other models, like flat table model, Preorder Tree Traversal Algorithm, and so. Do you guys have any tips or suggestions of how to implement a efficient tree model? My objective in the real end is to have one or two queries that would spit the whole tree for me. With enough processing i can display the tree in dot net, but that would be in client machine, so, not much of a big deal. Thanks for the attention

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  • asp.net mvc. Inserting string data from model into javascript. best-practice

    - by Andrew Florko
    Hello everybody, I have to populate javascript code in html layout (hidden fields, method params) with string data from model. Html.Encode is not appropriate for my task because it encodes ' symbol, bypass : (that ruines object attributes declaration) and so on. I wrote static helper class that is used from View like this: alert('<%=ViewHelper.MakeJavaScriptSafe(Model.Message)%>'); I hope there is asp.net in-built function I don't know about for this task. Does it exist really? Thank you in advance.

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  • How to read a complex view model on POST?

    - by Interfector
    Hello, I have an user view model that has the following properties: public User user; public List<Language> Languages; I send the above model to the view and use html helpers to build the form, so I end up with something like: <form action="/Users/Edit/5" method="post"><input id="user_UserId" name="user.UserId" type="hidden" value="5" /> First Name Last Name Email Language - en en Now, I try to read the POST in something that initially was something like : [AcceptVerbs( HttpVerbs.Post )] public ActionResult Edit( int UserId, FormCollection form ) { and cannot get the user.UserId variable, user.FirstName variable etc. Any idea what needs to be done to be able to read this kind of POST request. I'm kind of reluctant to modifying my ViewModel as it is very simple and easy to maintain as it is. Thank you.

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  • MVC 3 Nested EditorFor Templates

    - by Gordon Hickley
    I am working with MVC 3, Razor views and EditorFor templates. I have three simple nested models:- public class BillingMatrixViewModel { public ICollection<BillingRateRowViewModel> BillingRateRows { get; set; } public BillingMatrixViewModel() { BillingRateRows = new Collection<BillingRateRowViewModel>(); } } public class BillingRateRowViewModel { public ICollection<BillingRate> BillingRates { get; set; } public BillingRateRowViewModel() { BillingRates = new Collection<BillingRate>(); } } public class BillingRate { public int Id { get; set; } public int Rate { get; set; } } The BillingMatrixViewModel has a view:- @using System.Collections @using WIP_Data_Migration.Models.ViewModels @model WIP_Data_Migration.Models.ViewModels.BillingMatrixViewModel <table class="matrix" id="matrix"> <tbody> <tr> @Html.EditorFor(model => Model.BillingRateRows, "BillingRateRow") </tr> </tbody> </table> The BillingRateRow has an Editor Template called BillingRateRow:- @using System.Collections @model IEnumerable<WIP_Data_Migration.Models.ViewModels.BillingRateRowViewModel> @foreach (var item in Model) { <tr> <td> @item.BillingRates.First().LabourClass.Name </td> @Html.EditorFor(m => item.BillingRates) </tr> } The BillingRate has an Editor Template:- @model WIP_Data_Migration.Models.BillingRate <td> @Html.TextBoxFor(model => model.Rate, new {style = "width: 20px"}) </td> The markup produced for each input is:- <input name="BillingMatrix.BillingRateRows.item.BillingRates[0].Rate" id="BillingMatrix_BillingRateRows_item_BillingRates_0__Rate" style="width: 20px;" type="text" value="0"/> Notice the name and ID attributes the BillingRate indexes are handled nicely but the BillingRateRows has no index instead '.item.'. From my reasearch this is because the context has been pulled out due to the foreach loop, the loop shouldn't be necessary. I want to achieve:- <input name="BillingMatrix.BillingRateRows[0].BillingRates[0].Rate" id="BillingMatrix_BillingRateRows_0_BillingRates_0__Rate" style="width: 20px;" type="text" value="0"/> If I change the BillingRateRow View to:- @model WIP_Data_Migration.Models.ViewModels.BillingRateRowViewModel <tr> @Html.EditorFor(m => Model.BillingRates) </tr> It will throw an InvalidOperationException, 'model item passed into the dictionary is of type System.Collections.ObjectModel.Collection [BillingRateRowViewModel] but this dictionary required a type of BillingRateRowViewModel. Can anyone shed any light on this?

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  • How do you use a view with arguments as the site front page in Drupal?

    - by Justin
    I have a Drupal site and I have setup a view to power the front page. My goal is to be able to pass 0-2 arguments to the home page, that get passed into the view. However, I still need the normal Drupal pages to work. The list of arguments is known. For example: mysite.com/berlin/birds would pass in "berlin" as the first argument and "birds" as the second argument to the view that powers the front page. mysite.com/berlin would just pass in one argument, "berlin" mysite.com/admin would load the normal admin pages in Drupal I'm not clear on how to achieve this. Is there a hook I can use? I can't find one or think of one. Is there a way to specify this in the argument for the view itself? Perhaps I can write a hook that interjects when the URL is being loaded, and rewrite in the background? The solution I currently have is to add these paths (since my arguments are known) to the menu system. This works, except that when I the pages they aren't the front page, so the pages don't use the node themes I want (they use the node details theme).

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  • Utility App with Navigation Controller and Table View on FlipSide.

    - by wdt
    Hi All. I am relatively new to the whole MVC way of looking at things. I have an application that is based on the "Utility" Application template. Everything in the MainView and FlipsideView is working great but now I need to add a TableView and Navigation Controller to the flipside. Without the navigation bar being on the MainView. So only once the user has tapped the info light button will the nav bar display on the flipside with a table view. I have been able to impliment the Table View on the side and populate it with data from an array. I am now struggling to link in a navigation controller so that the tableview can become interactive. When I place the nav bar code into the app delegate it appears on the MainView and not the flipside view. Where do I place the navigation bar code so that it will display on the flipsideview. I cannt seem to get the code in the right place. Also I am not sure I have the right code, do I put the UINavigationController code in the FlipSideViewController.m ? I am not grasping the concept of the naivgation controller fully I think . . . Here is the code to bring up the FlipView - (IBAction)showInfo { TableViewController *controller = [[TableViewController alloc] initWithNibName:@"TableViewController" bundle:nil]; controller.delegate = self; controller.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal; [self presentModalViewController:controller animated:YES]; [controller release]; } Now I need to get the TableViewController to have a navigation controller and a table view Thanks in advance.

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  • Should I re-use UI elements across view controllers?

    - by Endemic
    In the iPhone app I'm currently working on, I'd like two navigation controllers (I'll call them A and B) to have toolbars that are identical in appearance and function. The toolbar in question will look like this: [(button) (flexible-space) (label)] For posterity's sake, the label is actually a UIBarButtonItem with a custom view. My design requires that A always appear directly before B on the navigation stack, so B will never be loaded without A having been loaded. Given this layout, I started wondering, "Is it worth it to re-use A's toolbar items in B's toolbar?" As I see it, my options are: 1. Don't worry about re-use, create the toolbar items twice 2. Create the toolbar items in A and pass them to B in a custom initializer 3. Use some more obscure method that I haven't thought of to hold the toolbar constant when pushing a view controller As far as I can see, option 1 may violate DRY, but guarantees that there won't be any confusion on the off chance that (for example) the button may be required to perform two different (no matter how similar) functions for either view controller in future versions of the app. Were that to happen, options 2 or 3 would require the target-action of the button to change when B is loaded and unloaded. Even if the button were never required to perform different functions, I'm not sure what its proper target would be under option 2. All in all, it's not a huge problem, even if I have to go with option 1. I'm probably overthinking this anyway, trying to apply the dependency injection pattern where it's not appropriate. I just want to know the best practice should this situation arise in a more extreme form, like if a long chain of view controllers need to use identical (in appearance and function) UI elements.

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  • Converting a view to Bitmap without displaying it in Android?

    - by sunil
    Hi, I will try to explain what exactly I need to do. I have 3 separate screens say A,B,C. There is another screen called say HomeScreen where all the 3 screens bitmap should be displayed in Gallery view and the user can select in which view does he wants to go. I have been able to get the Bitmaps of all the 3 screens and display it in Gallery view by placing all the code in HomeScreen Activity only. Now, this has complicated the code a lot and I will like to simplify it. So, can I call another Activity from HomeScreen and do not display it and just get the Bitmap of that screen. For example, say I just call HomeScreen and it calls Activity A,B,C and none of the Activities from A,B,C are displayed. It just gives the Bitmap of that screen by getDrawingCache(). And then we can display those bitmaps in Gallery view in HomeScreen. I hope I have explained the problem very clearly. Please let me know if this is actually possible. Regards Sunil

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