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  • php: parse error on mysql query

    - by dwstein
    I'm getting the following error: Parse error: syntax error, unexpected T_VARIABLE in /home/a4999406/public_html/willingLog.html on line 48 on the following code (line 48 is first row of this code): $rows = mysql_num_rows($result); for ($j=0; $j<$rows: ++$j) { echo 'ID: ' . mysql_result($result, $j, 'id') . '<br />'; echo 'First: ' . mysql_result($result, $j, 'first') . '<br />'; echo 'Last: ' . mysql_result($result, $j, 'last') . '<br />'; echo 'Email: ' . mysql_result($result, $j, 'email') . '<br />'; } Anyone know what i'm doing wrong?

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  • MySQL: Return grouped fields where the group is not empty, efficiently

    - by Ryan Badour
    In one statement I'm trying to group rows of one table by joining to another table. I want to only get grouped rows where their grouped result is not empty. Ex. Items and Categories SELECT Category.id FROM Item, Category WHERE Category.id = Item.categoryId GROUP BY Category.id HAVING COUNT(Item.id) > 0 The above query gives me the results that I want but this is slow, since it has to count all the rows grouped by Category.id. What's a more effecient way? I was trying to do a Group By LIMIT to only retrieve one row per group. But my attempts failed horribly. Any idea how I can do this? Thanks

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  • Mysql Count

    - by Buda
    I have the following query: select MIN(q.a), * FROM ( sub-query1 ) as q UNION sub-query2 How can I return the number of elements in query1 as a row of master-query? If i use count (*) i´ve only the count CountElementSub-Query1 i need some like that rowA, rowB, rowC, CountElementSub-Query1 rowA, rowB, rowC, CountElementSub-Query1 rowA, rowB, rowC, CountElementSub-Query1 rowA, rowB, rowC, CountElementSub-Query1

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  • MySQL: Select remaining rows

    - by Bjork24
    I've searched everywhere for this, but I can't seem to find a solution. Perhaps I'm using the wrong terms. Either way, I'm turning to good ol' trusty S.O. to help my find the answer. I have two tables, we'll call them 'tools' and 'installs' tools = id, name, version installs = id, tool_id, user_id The 'tools' table records available tools, which are then installed by a user and recorded in the 'installs' table. Selecting the installed tools are simple enough: SELECT tools.name FROM tools LEFT JOIN installs ON tools.id = installs.tool_id WHERE user_id = 99 ; How do I select the remaining tools -- the ones that have yet to be installed by user #99? I'm sorry if this is painfully obvious, but I just can't seem to figure it out! Thanks for the help!

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  • MySQL: averaging with nulls...

    - by Zombies
    Is there a simple way I can exclude nulls from affecting the avg? They appear to count as 0, which is not what I want. I simply don't want to take their average into account, yet here is the catch, I can't drop them from the result set, as that record has data on it that I do need.

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  • Show the specific field on mysql table based on active date

    - by mrjimoy_05
    Suppose that I have 3 tables: A) Table UsrHeader ----------------- UsrID | UsrName ----------------- 1 | Abc 2 | Bcd B) Table UsrDetail ------------------------------- UsrID | UsrLoc | Date ------------------------------- 1 | LocA | 10 Aug 2012 1 | LocB | 15 Aug 2012 2 | LocA | 10 Aug 2012 C) Table Trx ----------------------------- TrxID | TrxDate | UsrID ----------------------------- 1 | 10 Aug 2012 | 1 2 | 16 Aug 2012 | 1 3 | 11 Aug 2012 | 2 What I want to do is to show the table like: --------------------------------------- TrxID | TrxDate | UsrID | UsrLoc --------------------------------------- 1 | 10 Aug 2012 | 1 | LocA 2 | 16 Aug 2012 | 1 | LocB 3 | 11 Aug 2012 | 2 | LocA Notice that there is one user but different location. That's based on the UsrDetail table that the user on a specified date has moved to another location. So, it should be show the user specific location on that date on every transaction. I have try this code but it is no luck: SELECT trx.TrxID, trx.TrxDate, trx.UsrID, User.UsrName, User.UsrLoc FROM trx INNER JOIN ( SELECT UsrHeader.UsrID, UsrHeader.UsrName, UserDetail.UsrLoc FROM UsrHeader INNER JOIN ( SELECT UsrDetail.UsrID, UsrDetail.UsrLoc, UsrDetail.Date FROM UsrDetail ) AS UserDetail ON UserDetail.UsrID = UsrHeader.UsrID ) AS User ON User.UsrID = trx.UsrID AND trx.TrxDate >= User.Date How to do that? Thanks..

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  • MySQL Query Problem

    - by user559744
    Hello guys, I'm getting following error message. Please help me. Thanks Notice: Trying to get property of non-object in C:\xampp\htdocs\my\include\user_functions.php on line 34 Here is my Code $conn = db_connection(); if($conn == false) { user_error('Unable to connect to database'); return false; } $query = "UPDATE user SET passwd = '".$new_passwd."' WHERE username = '".$username."' "; $result=$conn->query($query); if($result == false) { user_error('Query Error'.$conn->error); return false; } if($result->num_rows == 1) { echo 'Password changed'; } else { echo 'Failed '; } here is my db_connection function db_connection() { $db = new mysqli('localhost','root','','php_login'); if(!$db) { echo 'Could not connect to database server'; } else { return $db; } }

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  • mysql query for change in values in a logging table

    - by kiasectomondo
    I have a table like this: Index , PersonID , ItemCount , UnixTimeStamp 1 , 1 , 1 , 1296000000 2 , 1 , 2 , 1296000100 3 , 2 , 4 , 1296003230 4 , 2 , 6 , 1296093949 5 , 1 , 0 , 1296093295 Time and index always go up. Its basically a logging table to log the itemcount each time it changes. I get the most recent ItemCount for each Person like this: SELECT * FROM table a INNER JOIN ( SELECT MAX(index) as i FROM table GROUP BY PersonID) b ON a.index = b.i; What I want to do is get get the most recent record for each PersonID that is at least 24 hours older than the most recent record for each Person ID. Then I want to take the difference in ItemCount between these two to get a change in itemcount for each person over the last 24 hours: personID ChangeInItemCountOverAtLeast24Hours 1 3 2 -11 3 6 Im sort of stuck with what to do next. How can I join another itemcount based on latest adjusted timestamp of individual rows?

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  • mysql select when matching multiple rows

    - by user1735943
    I have a project where I need to select only the users that answered to some questions in a certain way (based on a filter). The filter table (filter) looks like this question | answer Q1 | A Q2 | B The user table (answers) looks like this user | question | answer 1 | Q1 | A 1 | Q2 | D 2 | Q1 | A 2 | Q2 | B How can I select from the user table only the user(s) that match the filter? I tried "SELECT user FROM answers WHERE (question = Q1 AND answer = A) AND (question = Q2 AND answer = B)" and it doesn't work -- I get an empty result. Thank you.

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  • MySQL, PHP, How Many in GROUP

    - by 0Neji
    I'm trying to create a table which outputs a list of users and how many times they've logged in. A new row in the table is created every time that someone logs in so there is multiple rows for one user. Now, I'm trying using the following statement to pull the data out: SELECT * FROM logins GROUP BY user ORDER BY timestamp DESC Which is working fine but now there is a column in my HTML table which should show how many times the user has logged in. How do I go about counting the amount of rows in each group?

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  • Problem with PHP & MySQL

    - by Shahd
    I wrote this statements but it is not work :( ... can you tell me why? HTML: <form action="join.php" method="post"> <label name="RoomName">Room1</label> </form> PHP: $roomName = $_POST['RoomName']; $roomID = "SELECT RoomID FROM rooms WHERE RoomName = $roomName";

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  • MYSQL accentuated characters é display as %E9

    - by Jk_
    Hi guys, I'm pushing data from as3 to MSQL through a little php script! My problem is that all my accentuated characters are displayed as weird iso characters. Example : é is displayed %E9 Obvisously the collation of my field is set to utf8_general_ci Even when I try to INSERT the data from a simple php script without as3, I get the same mistake. <?php mysql_connect("***", "***", "***") or die("Error :" .mysql_error()); mysql_select_db("***"); $query ="INSERT INTO test (message) values ('éèàïû')"; mysql_query($query) or die("Error updating DB"); ?> Any idea on what am I doing wrong and how I could fix that? Thanks in advance. Jk_

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  • Windows Embedded CE DiskPrep PowerToy

    - by Bruce Eitman
    Kurt Kennett from Microsoft has offered up a handy new tool. This tool is useful for creating a boot disk for x86 Windows CE systems that use the BIOSLoader. This is especially useful for creating disks with formats other than FAT16, which are fairly easy to create. I am letting you know about this new tool, but I have to be honest in telling you that I haven’t used it myself because it is for Windows Vista and Windows 7 – which I don’t have available right now. But you can bet that I will be setting up a virtual machine to give it a try. Here is what Kurt has to say about the tool: Download the DiskPrep Tool  DiskPrep can prepare any hard disk that can be attached to your development PC so that it can boot your X86-based Windows CE OS Design. USB disks (including disk "keys"), Compact Flash Cards, and SD cards all work if your system bios can boot from that type of media. FAT16, FAT32, and exFAT all supported. DOS is not used - the program prepares the bios loader on the disk and only uses that. If you use Windows Vista or Windows 7, you can use VHD files for VirtualPC. This allows for rapid prototyping of a self-booting system. Copyright © 2010 – Bruce Eitman All Rights Reserved

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  • Embedded Web Server Vs External Web Server

    - by Jetti
    So I've thought of creating a web application in either Lisp or another functional language and was thinking of embedding the web server into the application (have my application handle the HTTP requests). I don't see any issues with that, however, I'm new to creating web applications (and in the grand scheme of things, programming as well). Is there any drawbacks to handling HTTP requests within your program instead of using a web server? Are there any benefits?

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  • Transitioning from Oracle based CMS to MySQL based CMS

    - by KM01
    We're looking at a replacement for our CMS which runs on Oracle. The new CMSes that we've looked at can in theory run on Oracle, but most of the vendor's installs run off of MySQL vendor supports install of their CMS on MySQL, and a "theoretical" install on Oracle the vendor's dev shops use MySQL none of them develop/test against Oracle Our DBA team works exclusively with Oracle, and doesn't have the bandwidth to provide additional support for a highly available and performing MySQL setup. They could in theory go to training and get ramped up, but our time line is also short (surprise!). So ... I guess my question(s) are: If you've seen a situation like this, how have you dealt with it? What tipped the balance either way? What type of effort did it take? If you're to do it over, what would you do differently ... ? Thanks! KM

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  • best practice? Consumer data in MySQL on Amazon EBS (Elastic block store)

    - by jeff7091
    This is a consumer app, so I will care about storage costs - I don't want to have 5x copies of data lying about. The app shards very well, so I can use MySQL and not have scaling issues. Amazon EBS has a nice baseline+snapshot backup capability that uses S3. This should have a light footprint (in terms of storage cost). BUT: the magnolia.com story scares the crap out of me: basically flawless block-level backup of a corrupt DB or filesystem. Is there anything that is nearly as storage efficient as EBS at the MySQL level?

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  • On MySQL 5.1 for Windows, why can't I assign DBA role to the "root" user?

    - by djangofan
    On MySQL 5.1 for Windows, why can't I assign DBA role to "root" user? The MySQL Workbench allows me to add all the other roles except for DBA. Also, when I "alter schema" on any table, while logged in as root, I dont see all the tabs that show me all the database properties... I only see the first tab that allows me to change collation only. What is wrong with this picture? How do i give root all priveleges? I've tried a few variations of GRANT ALL PRIVILEGES etc. from the command line but nothing works. My root account is unable to alter column names, indexes, or options of any given table that I create. I can create tables and delete them but I can't alter them.

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