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  • Full Text Search like Google

    - by Eduardo
    I would like to implement full-text-search in my off-line (android) application to search the user generated list of notes. I would like it to behave just like Google (since most people are already used to querying to Google) My initial requirements are: Fast: like Google or as fast as possible, having 100000 documents with 200 hundred words each. Searching for two words should only return documents that contain both words (not just one word) (unless the OR operator is used) Case insensitive (aka: normalization): If I have the word 'Hello' and I search for 'hello' it should match. Diacritical mark insensitive: If I have the word 'así' a search for 'asi' should match. In Spanish, many people, incorrectly, either do not put diacritical marks or fail in correctly putting them. Stop word elimination: To not have a huge index meaningless words like 'and', 'the' or 'for' should not be indexed at all. Dictionary substitution (aka: stem words): Similar words should be indexed as one. For example, instances of 'hungrily' and 'hungry' should be replaced with 'hunger'. Phrase search: If I have the text 'Hello world!' a search of '"world hello"' should not match it but a search of '"hello world"' should match. Search all fields (in multifield documents) if no field specified (not just a default field) Auto-completion in search results while typing to give popular searches. (just like Google Suggest) How may I configure a full-text-search engine to behave as much as possible as Google? (I am mostly interested in Open Source, Java and in particular Lucene)

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  • Function behaviour on shell(ksh) script

    - by footy
    Here are 2 different versions of a program: this Program: #!/usr/bin/ksh printmsg() { i=1 print "hello function :)"; } i=0; echo I printed `printmsg`; printmsg echo $i Output: # ksh e I printed hello function :) hello function :) 1 and Program: #!/usr/bin/ksh printmsg() { i=1 print "hello function :)"; } i=0; echo I printed `printmsg`; echo $i Output: # ksh e I printed hello function :) 0 The only difference between the above 2 programs is that printmsg is 2times in the above program while printmsg is called once in the below program. My Doubt arises here: To quote Be warned: Functions act almost just like external scripts... except that by default, all variables are SHARED between the same ksh process! If you change a variable name inside a function.... that variable's value will still be changed after you have left the function!! But we can clearly see in the 2nd program's output that the value of i remains unchanged. But we are sure that the function is called as the print statement gets the the output of the function and prints it. So why is the output different in both?

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  • c++, object life-time of anonymous (unnamed) variables

    - by Joe Steeve
    In the following code, the object constructed in the last line of 'main()', seems to be destroyed before the end of the expression. The destructor is called before the '<<' is executed. Is this how it is supposed to be? #include <string> #include <sstream> #include <iostream> using std::string; using std::ostringstream; using std::cout; class A : public ostringstream { public: A () {} virtual ~A () { string s; s = str(); cout << "from A: " << s << std::endl; } }; int main () { string s = "Hello"; A os; os << s; cout << os.str() << std::endl; A() << "checking this"; } This is the output: Hello from A: 0x80495f7 from A: Hello This is the gdb log: (gdb) b os.cxx : 18 Breakpoint 1 at 0x80492b1: file os.cxx, line 18. (2 locations) (gdb) r Starting program: /home/joe/sandbox/test/os Hello Breakpoint 1, ~A (this=0xbffff37c, __in_chrg=<value optimized out>, __vtt_parm=<value optimized out>) at os.cxx:18 18 cout << "from A: " << s << std::endl; (gdb) p s.c_str () $1 = 0x804b45c "0x80495f7" (gdb) p *s.c_str () $2 = 48 '0' (gdb) c Continuing. from A: 0x80495f7 Breakpoint 1, ~A (this=0xbffff2bc, __in_chrg=<value optimized out>, __vtt_parm=<value optimized out>) at os.cxx:18 18 cout << "from A: " << s << std::endl; (gdb) p s.c_str () $3 = 0x804b244 "Hello" (gdb) p *s.c_str () $4 = 72 'H' (gdb) c Continuing. from A: Hello Program exited normally. (gdb)

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  • How can I get Syslogging to work on the JVM?

    - by Synesso
    I want to do syslogging from Java. There is a log4j appender, but it doesn't seem to work (for me anyway ... though Google results show many others with this issue still unresolved). I'm trying to debug the appender, so I've written the following script based upon RFC3164 It runs, but no logging appears in the syslog. // scala import java.io._ import java.net._ val ds = new DatagramSocket() val fullMsg = "<11>May 26 14:47:22 Hello World" val packet = new DatagramPacket(fullMsg.getBytes("UTF-8"), fullMsg.length, InetAddress.getLocalHost, 514) ds send packet ds.close I also tried using /bin/nc, but it doesn't work either. echo "<14>May 26 15:23:83 Hello world" > nc -u localhost 514 The Ubuntu command /usr/bin/logger does work, however. logger -p user.info hello world # logs: May 26 15:25:10 dsupport2 jem: hello world What could I be doing wrong?

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  • Java how to replace 2 or more spaces with single space in string and delete leading spaces only

    - by Nessa
    Looking for quick, simple way in Java to change this string " hello there " to something that looks like this "hello there" where I replace all those multiple spaces with a single space, except I also want the one or more spaces at the beginning of string to be gone. Something like this gets me partly there String mytext = " hello there "; mytext = mytext.replaceAll("( )+", " "); but not quite.

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  • How to inject php code from database into php script ?

    - by luxquarta
    I want to store php code inside my database and then use it into my script. class A { public function getName() { return "lux"; } } // instantiates a new A $a = new A(); Inside my database there is data like "hello {$a->getName()}, how are you ?" In my php code I load the data into a variable $string $string = load_data_from_db(); echo $string; // echoes hello {$a->getName()}, how are you ? So now $string contains "hello {$a-getName()}, how are you ?" {$a-getName()} still being un-interpretated Question: I can't find how to write the rest of the code so that {$a-getName()} gets interpretated "into hello lux, how are you". Can someone help ? $new_string = ?????? echo $new_string; //echoes hello lux, how are you ? Is there a solution with eval() ? (please no debate about evil eval ;)) Or any other solution ?

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  • Problem overridding virtual function

    - by William
    Okay, I'm writing a game that has a vector of a pairent class (enemy) that s going to be filled with children classes (goomba, koopa, boss1) and I need to make it so when I call update it calls the childclasses respective update. I have managed to create a example of my problem. #include <stdio.h> class A{ public: virtual void print(){printf("Hello from A");} }; class B : public A{ public: void print(){printf("Hello from B");} }; int main(){ A ab = B(); ab.print(); while(true){} } Output wanted: "Hello from B" Output got: "Hello from A" How do I get it to call B's print function?

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  • WPF: Change padding depending of container ?

    - by Alex Ilyin
    I have UserControl named MyUserControl, and another UserControl named MyContainer. I want MyUserControl to have padding 10 if it is placed inside MyContainer and 15 otherwise. Shortly, I want <MyContainer> <MyUserControl> Hello </MyUserControl> </MyContainer> to look like <MyContainer> <UserControl Padding="10"> Hello </UserControl> <MyContainer> and <MyUserControl> Hello </MyUserControl> to look like <UserControl Padding="15"> Hello </UserControl>

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  • html - problem with word wrapping

    - by pakita883
    Hello! I have some text in div, and I want it to wrap to fit document width (without any scrolls!). I don't want to have word-break, like div {word-wrap: break-word;} For example (this is what I want to get): hello world! today is a good day. But not: hello world! today is a good day. or: hello world! today is a go od day.

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  • Silverlight textblock binding question + MVVM

    - by AdrianDN
    Hello everyone, I'm trying to create a simple textblock control and I'm trying to insert a property from my ViewModel in the middle of the string. E.G. "Hello, My name is XX, bla, bla." (XX is a property from my ViewModel) <TextBlock Text="Hello, My name is {Binding SelectedUser.Name}, bla, bla." /> Is that possible? Regards, Adrian

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  • Common Lisp's equivalent of \r inside the format function?

    - by liszt
    Basically, I'd like to do the following, only using Common Lisp instead of Python: print("Hello world.\r\n") I can do this, but it only outputs the #\newline character and skips #\return: (format t "Hello world.~%") I believe I could accomplish this using an outside argument, like this: (format t "Hello world.~C~%" #\return) But is seems awkward to me. Surely I can somehow embed #\return into the very format string, like I can #\newline? Yeah ehh, I'm nitpicking. Thanks for any help!

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  • Replace method doesn't work properly

    - by John Smith
    Hello I have a string and when i try to use replace method in for loop it doesn't work String phrase="hello friend"; String[] wordds=phrase.split(" "); String newPhrase="sup friendhello weirdo"; for (int g=0;g<2;g++) { finalPhrase+=newPhrase.replace(wordds[g],"");} } System.out.println(finalPhrase) It prints out "sup hello weirdo" and i expect it to print "sup weirdo". What am i doing wrong?

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  • Removing quotation marks in JSONObject

    - by Spike Williams
    I'm using the net.sf.json.JSONObject to create some data to be sent to a front end application, and I don't like the ways ts adding quotation marks to every field name. For example: myString = new JSONObject().put("JSON", "Hello, World!").toString(); produces the string {"JSON": "Hello, World"}. What I want it to return is {JSON: "Hello, World"} - without quotes around "JSON". What do I have to do to make that happen?

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  • Ruby proc vs lambda in initialize()

    - by Jimmy Chu
    I found out this morning that proc.new works in a class initialize method, but not lambda. Concretely, I mean: class TestClass attr_reader :proc, :lambda def initialize @proc = Proc.new {puts "Hello from Proc"} @lambda = lambda {puts "Hello from lambda"} end end c = TestClass.new c.proc.call c.lambda.call In the above case, the result will be: Hello from Proc test.rb:14:in `<main>': undefined method `call' for nil:NilClass (NoMethodError) Why is that? Thanks!

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  • Why cant Git merge file changes with a modified parent/master.

    - by Andy
    I have a file with one line in it. I create a branch and add a second line to the same file. Save and commit to the branch. I switch back to the master. And add a different, second line to the file. Save and commit to the master. So there's now 3 unique lines in total. If I now try and merge the branch back to the master, it suffers a merge conflict. Why cant Git simple merge each line, one after the other? My attempt at merge behaves something like this: PS D:\dev\testing\test1> git merge newbranch Auto-merging hello.txt CONFLICT (content): Merge conflict in hello.txt Automatic merge failed; fix conflicts and then commit the result. PS D:\dev\testing\test1> git diff diff --cc hello.txt index 726eeaf,e48d31a..0000000 --- a/hello.txt +++ b/hello.txt @@@ -1,2 -1,2 +1,6 @@@ This is the first line. - New line added by master. -Added a line in newbranch. ++<<<<<<< HEAD ++New line added by master. ++======= ++Added a line in newbranch. ++>>>>>>> newbranch Is there a way to make it slot lines in automatically, one after the other?

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  • Scala return type for tuple-functions

    - by Felix
    Hello Guys, I want to make a scala function which returns a scala tuple. I can do a function like this: def foo = (1,"hello","world") and this will work fine, but now I want to tell the compiler what I expect to be returned from the function instead of using the built in type inference (after all, I have no idea what a (1,"hello","world") is) I thought I remembered the classname being something like Tuple3[Int,String,String] but that doesnt work for me. Suggestions? :D (ps: I love stack overflow!)

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  • Get the common prefix substring through Regex

    - by Dreampuf
    like this text = " \t hello there\n \t how are you?\n \t HHHH" hello there how are you? HHHH Could I get the common prefix substring through regex? I try to In [36]: re.findall(r"(?m)(?:(^[ \t]+).+[\n\r]+\1)", " \t hello there\n \t how are you?\n \t HHHH") Out[36]: [' \t '] But apparently that common prefix substring is ' \t ' I want use for dedent function like python textwrap module.

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