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  • How to access MySQL when I delete the root user on openSUSE 11?

    - by Negin Nicki
    Unfortunately I deleted MySQL users with the command delete from mysql.user and now I can't access MySQL. I tried looking at MySQL - ERROR 1045 - Access denied, but it is not proper for me because I don't have any user for MySQL. I uninstalled and reinstalled MySQL but I can't access MySQL. What should I do? I wanted to have phpMyAdmin without login and I ruined the whole thing. After uninstalling and having no result, I tried to delete the directories of MySQL and again installing them but again no result and now I have this error: Error 2002:can't connect to local mysql server through socket /var/lib/mysql/mysql.sock I don't have any user to reset the password of, but if I have by reinstalling which I don't know how to connect to MySQL. I tried MySQL -u root I tried MySQL I tried mysqld-safe and etc in the link

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  • php mysql array - insert array info into mysql

    - by Michael
    I need to insert mutiple data in the field and then to retrieve it as an array. For example I need to insert "99999" into table item_details , field item_number, and the following data into field bidders associated with item_number : userx usery userz Can you please let me know what sql query should I use to insert the info and what query to retrieve it ? I know that this may be a silly question but I just can't figure it out . thank you in advance, Michael .

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  • A better way to build this MySQL statement with subselects

    - by Corey Maass
    I have five tables in my database. Members, items, comments, votes and countries. I want to get 10 items. I want to get the count of comments and votes for each item. I also want the member that submitted each item, and the country they are from. After posting here and elsewhere, I started using subselects to get the counts, but this query is taking 10 seconds or more! SELECT `items_2`.*, (SELECT COUNT(*) FROM `comments` WHERE (comments.Script = items_2.Id) AND (comments.Active = 1)) AS `Comments`, (SELECT COUNT(votes.Member) FROM `votes` WHERE (votes.Script = items_2.Id) AND (votes.Active = 1)) AS `votes`, `countrys`.`Name` AS `Country` FROM `items` AS `items_2` INNER JOIN `members` ON items_2.Member=members.Id AND members.Active = 1 INNER JOIN `members` AS `members_2` ON items_2.Member=members.Id LEFT JOIN `countrys` ON countrys.Id = members.Country GROUP BY `items_2`.`Id` ORDER BY `Created` DESC LIMIT 10 My question is whether this is the right way to do this, if there's better way to write this statement OR if there's a whole different approach that will be better. Should I run the subselects separately and aggregate the information?

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  • Deleting Duplicates in MySQL

    - by elmaso
    Query was this: CREATE TABLE `query` ( `id` int(11) NOT NULL auto_increment, `searchquery` varchar(255) NOT NULL default '', `datetime` int(11) NOT NULL default '0', PRIMARY KEY (`id`) ) ENGINE=MyISAM first I want to drop the table with: ALTER TABLE `querynew` DROP `id` and then delete the double entries.. I tried it with: INSERT INTO `querynew` SELECT DISTINCT * FROM `query` but with no success.. :( and with ALTER TABLE query ADD UNIQUE ( searchquery ) - is it possible to save the queries only one time?

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  • Ajax, php, mysql not working mysql limit

    - by Hofmeister Ákos
    I have 3 files. list.php $articles = $mysqli->query("SELECT mainPictureBig, title, writer, writeDate, link FROM articles WHERE category=$this->category ORDER BY writeDate DESC LIMIT 0,10"); while($article = mysqli_fetch_row($articles)) { echo "<a href=\"".$this->url."/".$article[3]."/".$article[4]."\"><div id=\"listElement\"> <div id=\"listElementWallpaper\" style=\"background-image: url('category/img.jpg');\"></div> <div id=\"listElementContent\"><div id=\"listElementTitle\">".$article[1]."</div>".$this->giveWriter($article[2]).", ".$this->giveDate($article[3])."</div> </div></a>"; } $maximumElements=ceil($numberOfContent / 10) * 10; It's working, so there is no problem, it lists the first 10 elements from the sql table, and i got the $numberOfCOntent part also. Than i have a button: echo "<div id=\"listMore\"><div id=\"buttonOne\" onclick=\"listMore($this->category,$maximumElements)\">Load more</div></div>"; There is also no problem, i load the .js file, and it looks like: var from = 10; function listMore(categoryId, maximum) { $( "#listMore" ).slideUp( 200, function() { $( "#listMore" ).html("<center>Loading..</center>"); $( "#listMore" ).slideDown( 500, function() { $.post( "http://localhost/ajax.php", {type: "listMore", id: categoryId, sqlFrom: from} ) .done(function( elements ) { $("#listBody").append( elements ); if(maximum > from+10) { from = from+10; $( "#listMore" ).slideUp(200, function() { $( "#listMore" ).html("<div id=\"buttonOne\" onclick=\"listMore("+categoryId+","+maximum+")\">Load more</div>"); $( "#listMore" ).slideDown(200); }); } else $( "#listMore" ).slideUp(200); }); }); }); } And it's also working, and the problem is in the PHP file. As you can see, i'm sending an integer the "from" variable, the PHP file: $articles = $mysqli->query("SELECT mainPictureBig, title, writer, writeDate, link FROM articles WHERE category=$id ORDER BY writeDate DESC LIMIT $from,10"); It's also working, but not loading the next 10, only the next 9. So it skips the very next row and loads the rows only after the very first, so only 9. I tried to write here only the important part of the code, so i skipped some echo part etc. Any idea?

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  • Check if row exists, if not add it [MySQL]

    - by Steven
    I need to add a row to a MySQL database table but only if the row doesn't already exist. My database server just went down so I can't test this, but will this work as expected? INSERT INTO `blocks` (`block_file`,`settings_group`) VALUES ('announcements','announcement_settings') WHERE NOT EXISTS (SELECT `block_file`,`settings_group` FROM `blocks` WHERE `block_file`='announcements' AND `settings_group`='announcement_settings') It seems like sound logic. Is this a valid query or is there a better way of doing this?

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  • I need to simplify a MySQL sub query for performance - please help

    - by Richard
    I have the following query which is takin 3 seconds on a table of 1500 rows, does someone know how to simplify it? SELECT dealers.name, dealers.companyName, dealer_accounts.balance FROM dealers INNER JOIN dealer_accounts ON dealers.id = dealer_accounts.dealer_id WHERE dealer_accounts.id = ( SELECT id FROM dealer_accounts WHERE dealer_accounts.dealer_id = dealers.id AND dealer_accounts.date < '2010-03-30' ORDER BY dealer_accounts.date DESC, dealer_accounts.id DESC LIMIT 1 ) ORDER BY dealers.name I need the latest dealer_accounts record for each dealer by a certain date with the join on the dealer_id field on the dealer_accounts table. This really should be simple, I don't know why I am struggling to find something.

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  • Storing data in a MySQL database using MySQL & PHP

    - by comma
    I'm new to PHP and MySQL and I'm trying to store a users entered data from the following fields $skill, $experience, $years which a user can also add additional fields of $skill, $experience, $years if needed so in instead of 1 of each field there might be multiples of each field. I was wondering how can I store the fields in my MySQL database using PHP and MySQL? I have the following script but I know its wrong. can some one help me fix the script listed below? Here is the PHP and MySQL code. $skill = serialize($_POST['skill']); $experience = serialize($_POST['experience']); $years = serialize($_POST['years']); for (($s = 0; $s < count($skill); $s++) && ($x = 0; $x < count($experience); $x++) && ($g = 0; $g < count($years); $g++)){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = "INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $skill[$s] . "', '" . $experience[$x] . "', '" . $years[$g] . "')"; if (!mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } } Here is my MySQL table. CREATE TABLE learned_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill TEXT NOT NULL, experience TEXT NOT NULL, years INT NOT NULL, PRIMARY KEY (id) ); CREATE TABLE u_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill_id INT UNSIGNED NOT NULL, users_id INT UNSIGNED NOT NULL, PRIMARY KEY (id) );

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  • Complex MySQL table select/join with pre-condition

    - by Howard
    Hello, I have the schema below CREATE TABLE `vocabulary` ( `vid` int(10) unsigned NOT NULL auto_increment, `name` varchar(255), PRIMARY KEY vid (`vid`) ); CREATE TABLE `term` ( `tid` int(10) unsigned NOT NULL auto_increment, `vid` int(10) unsigned NOT NULL default '0', `name` varchar(255), PRIMARY KEY tid (`tid`) ); CREATE TABLE `article` ( `aid` int(10) unsigned NOT NULL auto_increment, `body` text, PRIMARY KEY aid (`aid`) ); CREATE TABLE `article_index` ( `nid` int(10) unsigned NOT NULL default '0', `tid` int(10) unsigned NOT NULL default '0' ) INSERT INTO `vocabulary` values (1, 'vocabulary 1'); INSERT INTO `vocabulary` values (2, 'vocabulary 2'); INSERT INTO `term` values (1, 1, 'term v1 t1'); INSERT INTO `term` values (2, 1, 'term v1 t2 '); INSERT INTO `term` values (3, 2, 'term v2 t3'); INSERT INTO `term` values (4, 2, 'term v2 t4'); INSERT INTO `term` values (5, 2, 'term v2 t5'); INSERT INTO `article` values (1, ""); INSERT INTO `article` values (2, ""); INSERT INTO `article` values (3, ""); INSERT INTO `article` values (4, ""); INSERT INTO `article` values (5, ""); INSERT INTO `article_index` values (1, 1); INSERT INTO `article_index` values (1, 3); INSERT INTO `article_index` values (2, 2); INSERT INTO `article_index` values (3, 1); INSERT INTO `article_index` values (3, 3); INSERT INTO `article_index` values (4, 3); INSERT INTO `article_index` values (5, 3); INSERT INTO `article_index` values (5, 4); Example. Select term of a defiend vocabulary (with non-zero article index), e.g. vid=2 select a.tid, count(*) as article_count from term t JOIN article_index a ON t.tid = a.tid where t.vid = 2 group by t.tid; +-----+---------------+ | tid | article_count | +-----+---------------+ | 3 | 4 | | 4 | 1 | +-----+------------ Question: Select terms a. of a defiend vocabulary (with non-zero article index, e.g. vid=1 = term {1,2}) b. given that those terms are linked with articles which are linked with terms under vid=2, e.g. = {1}, term with tid=2 is excluded since no linkage to terms under vid=2 SQL: Any idea? Expected result: +-----+---------------+ | tid | article_count | +-----+---------------+ | 1 | 2 | +-----+---------------+

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  • MySQL AND alternative for eatch table in a join

    - by Scott
    I have a simple join in a query however I need to have a condition on both of the tables "confirmed='yes'" but if one of the tables doesn't have any that match the query returns with no rows. Database: .----------parties----------. | id - party_id - confirmed | |---------------------------| | 1 1 yes | | 1 2 no | | 1 3 no | +---------------------------+ .-----------events----------. | id - event_id - confirmed | |---------------------------| | 1 1 no | +---------------------------+ Query: SELECT p.party_id, e.event_id FROM parties p LEFT JOIN events e ON p.id=e.id WHERE p.id = '1' AND p.party_id IN (1,2,3) AND e.event_id IN (1) AND p.confirmed='yes' AND e.confirmed='yes' It returns nothing but I want it to return party_id 1 with a empty event_id. I hope this make sense and I not missing anything, Thanks for your help!

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  • MySQL AND alternative for each table in a join

    - by Scott
    I have a simple join in a query however I need to have a condition on both of the tables "confirmed='yes'" but if one of the tables doesn't have any that match the query returns with no rows. Database: .----------parties----------. | id - party_id - confirmed | |---------------------------| | 1 1 yes | | 1 2 no | | 1 3 no | +---------------------------+ .-----------events----------. | id - event_id - confirmed | |---------------------------| | 1 1 no | +---------------------------+ Query: SELECT p.party_id, e.event_id FROM parties p LEFT JOIN events e ON p.id=e.id WHERE p.id = '1' AND p.party_id IN (1,2,3) AND e.event_id IN (1) AND p.confirmed='yes' AND e.confirmed='yes' It returns nothing but I want it to return party_id 1 with a empty event_id. I hope this make sense and I not missing anything, Thanks for your help!

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  • MySql for Visual Studio 1.0.2 GA has been released

    - by fernando
    MySQL for Visual Studio is a new product including all of the Visual Studio integration previously available as part of Connector/Net.  The product is now released as GA and is appropriate for use in production environments.  It is compatible with MySQL Server versions 5.0-5.7 and Visual Studio versions 2008-2012.  It is now available as part of MySql Installer for Windows (http://dev.mysql.com/tech-resources/articles/mysql-installer-for-windows.html). The 1.0 version of MySQL for Visual Studio brings the following new features:   Workbench Launching.   MySql Utilities Launching.   Table Script Generation.   The functionality of the core libraries (ADO.NET, EF, ASP.NET providers is available as the separate download of Connector/NET 6.7). Features available from previous versions:        Server explorer connections     Design time support     Entity Framework designer (Database First & Model First)     Stored Routines Debugger     Intellisense     ASP.NET Website Configuration Tool Workbench Launching  ------------------------------------------- A context menu for connections in Server Explorer allows to launch Workbench (if Workbench is installed). MySql Utilities Launching  ------------------------------------------- A context menu for connections in Server Explorer allows to launch a prompt for MySql Utilities (if MySql Utilities is installed). Table Script Generation  ------------------------------------------- A context menu for tables is available in Server Explorer to generate the script for a table. The full list of bug fixes for "MySql for Visual Studio" 1.0 follows: 1.0.2 - Fix for Documentation not found (Oracle bug #6915712). - Fix for intellisense completion, now Views are displayed together with Tables calling intellisense (Oracle Bug #16881451). - Fix for parser syntax, now the parser supports the clause ALTER TABLE table_name RENAME {INDEX|KEY} old_index_name TO new_index_name introduced in MySql 5.7. (Oracle Bug #16881481) - Fix for Debugging a routine produces an error when binary log is enabled (Oracle bug #16941181). - Fix for WorkItem 552: MySql for Visual Studio Installer fails when installing against VS2008. - Fix for bug Vs plugin installer is not working (Oracle bug #16973339). - Fix for bug Release notes file has no notes about (Oracle bug #16973326). 1.0.1 - Fix for "README" file and "Release Notes" file referes to connector 6.6. - Fix for Parser fails to recognizes a complex view (Oracle bug #16815427). - Fix for Altering table's primary key in designer not working (Oracle bug #16866053). - Fix for Web configuration tool is not shown on mysql for visual studio (Oracle bug # 16902696). - Fix for Model first is not supported using mysql for visual studio (Oracle bug # 16902743). - Fix for Mysql for vs should not be installed with connector/net version < 6.7 (Oracle bug # 16902774). - Fix for Resolve assemblies dependencies between MySql.Data (Connector/Net version) and MySql.Data (WI # 460). - Fix for Showing an exception related to resources (Oracle bug #16903039). 1.0.0 - Added new option on Connection Node for Server Explorer Window in Visual Studio to give the user the option when WB is Installed to open the MySQL Utilities console window. - Added new option on Connection Node for Server Explorer Window in Visual Studio to give the user the option when WB is Installed to open the SQL Editor Window using the same connection. - Implemented a menu option to generate table script from server explorer context menu (Tracker task 433). - Fix for bug If using repair option, then vs2010 doesnt allow to connect to db (Oracle bug #16238242). - Fix for bug "Can't change the name for a view in view editor" (Oracle bug #13805346). - Fix for Debugger cannot debug stored procedures with a main begin labeled and declare statements included (Oracle bug #16002371). - Fix for bug If using repair option at Installer, then vs2010 doesnt allow to connect to db (Oracle bug #16238242). - Fix for "Cannot change the name for a Foreign Key in table designer" (Oracle bug #16238068). - Fix for error when trying to set primary key for a column with same name as mysql keyword (like INT) in table designer   (Oracle bug #16238102). - Fix for databases not displayed in connect dialog for mysql script when correcting credentials, after entering a bad password   (Oracle bug #13805337). - Fix for Debugger fails trying to debug a stored routine in a MySql server hosted in linux without lower_case_table_names option enabled   (MySql bug #69065, Oracle bug #16770384). - Fix for Debugger issue, Values through watch tab shouldn't allow to be modified (Oracle bug #14545448). - Fix for Visual Studio Mysql editor colors cannot be customized (Oracle bug #16453324, MySql bug #67994). The documentation is available as part of Connector/NET at http://dev.mysql.com/doc/refman/5.7/en/connector-net.html  Enjoy and thanks for the support!  --  Fernando Gonzalez Sanchez | Software Engineer |  Oracle MySQL Windows Experience Team, Connector/NET  Guadalajara | Jalisco | Mexico

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  • With Its MySQL Database-as-a-Service CERN Empowers Scientists

    - by Bertrand Matthelié
    The European Organization for Nuclear Research (CERN) is one of the world’s largest and most respected centers for scientific research. Founded in 1954 and located near Geneva on the Franco-Swiss border, CERN was one of Europe’s first joint ventures. Today, it has 20 member states. The organization uses the world’s largest and most complex scientific instruments to study fundamental particles and the origin of the universe. Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Cambria","serif"; mso-ascii-font-family:Cambria; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Cambria; mso-hansi-theme-font:minor-latin;} Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Cambria","serif"; mso-ascii-font-family:Cambria; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Cambria; mso-hansi-theme-font:minor-latin;} Challenges Better support the scientists associated with a CERN research program who selected MySQL as their database. Empower users, enabling them to be as self-reliant as possible. Minimize complexity and costs for the CERN IT department to support the growing number of MySQL deployments. Solution Delivered a MySQL Database-as-a-Service offering to the CERN employees and the scientists associated with the organization. Allowed researchers selecting MySQL for their project to get access to a database instance hosted by the CERN IT department, either from the start or once their application has become critical. Implemented the service using Oracle’s server virtualization software, Oracle VM, for increased flexibility and reduced costs. Empowered users with a self-service approach, providing them with tools to manage MySQL themselves while handling backups and other basic database administration tasks for them. Enabled scientists to rely on MySQL with increased reliability, security and manageability while reducing complexity and minimizing costs. Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Cambria","serif"; mso-ascii-font-family:Cambria; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Cambria; mso-hansi-theme-font:minor-latin;} "The Cloud model has allowed us to deliver a self-service platform to our MySQL users, empowering them while minimizing costs for CERN." Tony Cass, Database Services Group Leader, IT department, CERN.

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  • Perl DBI execute not maintaining MySQL stored procedure results

    - by David Dolphin
    I'm having a problem with executing a stored procedure from Perl (using the DBI Module). If I execute a simple SELECT * FROM table there are no problems. The SQL code is: DROP FUNCTION IF EXISTS update_current_stock_price; DELIMITER | CREATE FUNCTION update_current_stock_price (symbolIN VARCHAR(20), nameIN VARCHAR(150), currentPriceIN DECIMAL(10,2), currentPriceTimeIN DATETIME) RETURNS INT DETERMINISTIC BEGIN DECLARE outID INT; SELECT id INTO outID FROM mydb449.app_stocks WHERE symbol = symbolIN; IF outID 0 THEN UPDATE mydb449.app_stocks SET currentPrice = currentPriceIN, currentPriceTime = currentPriceTimeIN WHERE id = outID; ELSE INSERT INTO mydb449.app_stocks (symbol, name, currentPrice, currentPriceTime) VALUES (symbolIN, nameIN, currentPriceIN, currentPriceTimeIN); SELECT LAST_INSERT_ID() INTO outID; END IF; RETURN outID; END| DELIMITER ; The Perl code snip is: $sql = "select update_current_stock_price('$csv_result[0]', '$csv_result[1]', '$csv_result[2]', '$currentDateTime') as `id`;"; My::Extra::StandardLog("SQL being used: ".$sql); my $query_handle = $dbh-prepare($sql); $query_handle-execute(); $query_handle-bind_columns(\$returnID); $query_handle-fetch(); If I execute select update_current_stock_price('aapl', 'Apple Corp', '264.4', '2010-03-17 00:00:00') asid; using the mysql CLI client it executes the stored function correctly and returns an existing ID, or the new ID. However, the Perl will only return a new ID, (incrementing by 1 on each run). It also doesn't store the result in the database. It looks like it's executing a DELETE on the new id just after the update_current_stock_price function is run. Any help? Does Perl do anything funky to procedures I should know about? Before you ask, I don't have access to binary logging, sorry

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  • How to know about MySQL 'refused connections'

    - by celalo
    Hello, I am using MONyog to montitor my two mysql servers. I get alert emails from MONyog when something goes wrong. There is an error I could not find out why. It says: Connection History: Percentage of refused connections) - 66.67% the percentage is not important, this is just about having refused connections. I get this email every half an hour. So this is like a constant situation. This must be my mistake, because I just set up those servers and there is no chance somebody else could be interfering the servers. MONyog advices me: Try to isolate users/applications that are using an incorrect password or trying to connect from unauthorized hosts. A client will be disallowed to connect if it takes more than connect_timeout seconds to connect. Set the value of log_warnings system variable to 2. This will force the MySQL server to log further information about the error. I added log_warnings=2 to my.cnf and I enabled logging like this: [mysqld_safe] . . log_warnings=2 log-error = /var/log/mysql/error.log . . . . [mysqld_safe] . log-error=/var/log/mysqld.log . . I cannot see any warnings at /var/log/mysql/error.log I can see some warnings at /var/log/mysqld.log but they are about something else. In sum, my question is how can I detect refused connections? Please let me know if any more info is required. Thanks in advance.

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  • GROUP BY ID range?

    - by d0ugal
    Given a data set like this; +-----+---------------------+--------+ | id | date | result | +-----+---------------------+--------+ | 121 | 2009-07-11 13:23:24 | -1 | | 122 | 2009-07-11 13:23:24 | -1 | | 123 | 2009-07-11 13:23:24 | -1 | | 124 | 2009-07-11 13:23:24 | -1 | | 125 | 2009-07-11 13:23:24 | -1 | | 126 | 2009-07-11 13:23:24 | -1 | | 127 | 2009-07-11 13:23:24 | -1 | | 128 | 2009-07-11 13:23:24 | -1 | | 129 | 2009-07-11 13:23:24 | -1 | | 130 | 2009-07-11 13:23:24 | -1 | | 131 | 2009-07-11 13:23:24 | -1 | | 132 | 2009-07-11 13:23:24 | -1 | | 133 | 2009-07-11 13:23:24 | -1 | | 134 | 2009-07-11 13:23:24 | -1 | | 135 | 2009-07-11 13:23:24 | -1 | | 136 | 2009-07-11 13:23:24 | -1 | | 137 | 2009-07-11 13:23:24 | -1 | | 138 | 2009-07-11 13:23:24 | 1 | | 139 | 2009-07-11 13:23:24 | 0 | | 140 | 2009-07-11 13:23:24 | -1 | +-----+---------------------+--------+ How would I go about grouping the results by day 5 records at a time. The above results is part of the live data, there is over 100,000 results rows in the table and its growing. Basically I want to measure the change over time, so want to take a SUM of the result every X records. In the real data I'll be doing it ever 100 or 1000 but for the data above perhaps every 5. If i could sort it by date I would do something like this; SELECT DATE_FORMAT(date, '%h%i') ym, COUNT(result) 'Total Games', SUM(result) as 'Score' FROM nn_log GROUP BY ym; I can't figure out a way of doing something similar with numbers. The order is sorted by the date but I hope to split the data up every x results. It's safe to assume there are no blank rows. Doing it above with the data you could do multiple selects like; SELECT SUM(result) FROM table LIMIT 0,5; SELECT SUM(result) FROM table LIMIT 5,5; SELECT SUM(result) FROM table LIMIT 10,5; Thats obviously not a very good way to scale up to a bigger problem. I could just write a loop but I'd like to reduce the number of queries.

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  • xampp mysql and rubby

    - by user115079
    I've installed ruby and xampp server. now i am trying to use xampp mysql for ruby application. i copied xampp mysql lib (libmysql) from C:\xampp\mysql\lib to C:\Ruby192\bin (as told on some post on this forum). now after that when i try to create a resource using following command, i get an error. command: rails generate scaffold ShortUrl url:string error: C:/Ruby192/lib/ruby/gems/1.9.1/gems/mysql2-0.3.11-x86-mingw32/lib/mysql2/mysql2.rb:2:in `require': Incorrect MySQL client library version! This gem was compiled for 6.0.0 but the client library is 5.5.16. (RuntimeError) i know that there is version issue b/w ruby mysql client and xampp mysal. now i need advice that what is better solution? upgraded xampp mysql or downgrade ruby mysql version. Personally i want to upgrade xampp mysql but i read on some post that xampp mysql can't be upgraded. please advise.

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  • MySQL - Powering Online Media & Entertainment

    - by bertrand.matthelie(at)oracle.com
    @font-face { font-family: "Arial"; }@font-face { font-family: "Courier New"; }@font-face { font-family: "Times"; }@font-face { font-family: "Wingdings"; }@font-face { font-family: "Cambria"; }p.MsoNormal, li.MsoNormal, div.MsoNormal { margin: 0cm 0cm 0.0001pt; font-size: 12pt; font-family: "Times New Roman"; }a:link, span.MsoHyperlink { color: blue; text-decoration: underline; }a:visited, span.MsoHyperlinkFollowed { color: purple; text-decoration: underline; }p { margin: 0cm 0cm 0.0001pt; font-size: 10pt; font-family: "Times New Roman"; }div.Section1 { page: Section1; }ol { margin-bottom: 0cm; }ul { margin-bottom: 0cm; } If you're reading news, watching videos, or playing games online, you're probably relying on MySQL to do so.   Facebook, YouTube, BBC News, Zynga, thePlatform and many other leading Media & Entertainment organizations chose MySQL to power their online news, gaming, social networking, advertising or other applications.   During the past decade, the Media & Entertainment industry experienced a spectacular transformation.  The mobile Internet is becoming the dominant media platform, and the boundaries between the different types of media (i.e. Print, TV, Radio, Internet) have increasingly blurred as we've gradually come to perform more and more of our daily activities online.   To better understand how MySQL can help you win in the fast paced world of Media & Entertainment, check out our whitepaper "MySQL - Powering The Online Media & Entertainment Industry" in which we cover:   ·       The key trends shaping the evolution of the media & entertainment industry.   ·       Their implications, and the requirements they place on the infrastructure of information & entertainment services providers.   ·       How you can leverage Oracle's MySQL technologies to quickly and cost-effectively deliver new highly scalable and highly available online media & entertainment applications.   You're welcome to download it here.

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  • MySQL: "UPDATE command denied to user ''@'localhost'"

    - by Uncle Nerdicus
    For some reason when I installed MySQL on my machine (a Mac running OS X 10.9) the 'root' MySQL account got messed up and I don't have access to it, but I do have access to the standard MySQL account 'sean@localhost' which I use to log into phpMyAdmin. I am trying to reset the 'root' password by starting the mysqld daemon using the command mysqld --skip-grant-tables and then running the following lines in the mysql shell. mysql> UPDATE mysql.user SET Password=PASSWORD('MyNewPass') -> WHERE User='root'; mysql> FLUSH PRIVILEGES; Problem is when I try to run that MySQL string the daemon spits back a ERROR 1142 (42000): UPDATE command denied to user ''@'localhost' for table 'user' as if I didn't use the -u argument when I started the mysql shell, either though I did. Any help is muchly appreciated as I am lost at this point. :/

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  • Three Ways to Take Official MySQL for Database Administrators course

    - by Antoinette O'Sullivan
    The MySQL for Database Administrators course is a 5 day course that teaches the key skills essential for MySQL Database Administrators. You can take this course in one of the following three ways: Training on Demand: Get Instructor-led training within 24 hours through streaming-video from your desk. Live Virtual Class: Live instructor-led training from your desk. Over 1000! LVC events on the schedule for the MySQL for Database Administrator course. In Class: See below for a selection of locations where you can take this training For more information on this course or teaching schedule, go to the Oracle University portal and click on MySQL or search under your country/location. A selection of the In-Class schedule for the MySQL for Database Administrator course:  Location  Date  Delivery Language  Mechelen, Belgium  10 Sept 2012  English  Prague, Czech Republic  27 Aug 2012  Czech  Nice, France  24 Sept 2012  French  Paris, France  24 Sept 2012  French  Strasbourg, France  10 Sept 2012  French  Dresden, Germany  20 Aug 2012  German  Gummersbach, Germany  27 Aug 2012  German  Hamburg, Germany  23 July 2012  German  Munich, Germany  16 July 2012  German  Munster, Germany  6 Aug 2012  German  Stuttgart, Germany  9 July 2012  German  London, Great Britan  9 July 2012  English  Belfast, Ireland  27 Aug 2012  English  Rome, Italy  30 July 2012  Italian  Windhof, Luxembourg  26 Nov 2012  English  Nieuwegein, Netherlands  1 Oct 2012  English  Oslo, Norway  10 Sept 2012  English  Warsaw, Poland  9 July 2012  Polish  Lisbon, Portugal  3 Sept 2012  European Portugese  Madrid, Spain  25 Jun 2012  Spanish  Baden Dattwil, Switzerland  19 Nov 2012  German  Zurick, Switzerland  8 Aug 2012  German  Istanbul, Turkey  27 Aug 2012  Turkish  Petaling Jaya, Malaysia  25 Jul 2012  English  Singapore  16 July 2012  English  Brisbane, Australia  30 July 2012  English  Bangkok, Thailand  30 July 2012  Thai  Edmonton, Canada  10 Sept 2012  English  Vancouver, Canada  10 Sept 2012  English  Ottawa, Canada  30 July 2012  English  Toronto, Canada  30 July 2012  English  Montreal, Canada  30 July 2012  English  Mexico City, Mexico  25 Jun 2012  Spanish With these three delivery options and an impressive LVC and In-Class schedule you should find an event to suit your needs. If you are interested in another date or location you can register your interest on the Oracle University portal.

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  • Is there any good hosting for asp.net and MySQL

    - by HAJJAJ
    HI every one ,I have account with one of the hosting company, and i did my project in asp.net and I used MySQL for the database. the hosting company is not giving me the full privileges to create new user or to create new stored procedure!!! this is what they said for me: Due to the shared nature of our environment we had to make some modifications to your procedure (namely the definer). We also had to review your procedure to determine if it would be compatible with our environment. While your procedures will work (via phpMyAdmin or some other interface), it is unlikely they will be accessible via the Connector/.NET (ADO.NET) that your application is likely using. This is due to a security restriction with how that connector works in shared environments. http://dev.mysql.com/doc/refman/5.0/en/connector-net-programming-stored.html "Note When you call a stored procedure, the command object makes an additional SELECT call to determine the parameters of the stored procedure. You must ensure that the user calling the procedure has the SELECT privilege on the mysql.proc table to enable them to verify the parameters. Failure to do this will result in an error when calling the procedure." Unfortunately, giving read privileges on the mysql.proc table will give you access to the data of our other customers and that is not an acceptable risk. If your application can only work using stored procedures, then MSSQL will probably be the better option for your site. I apologize for the inconvenience and the wait to have this ticket completed. So is there any good hosting that any body already used it to publish his asp.net and mysql project ??? this is one of my stored procedure and i think it's sample and it will not harm any other uses!!: -- -------------------------------------------------------------------------------- -- Routine DDL -- Note: comments before and after the routine body will not be stored by the server -- -------------------------------------------------------------------------------- DELIMITER $$ CREATE DEFINER=`root`@`localhost` PROCEDURE `SpcategoriesRead`( IN PaRactioncode VARCHAR(5), IN PaRCatID BIGINT, IN PaRSearchText TEXT ) BEGIN -- CREATING TEMPORARY TABLE TO SAVE DATA FROM THE ACTIONCODE SELECTS -- DROP TEMPORARY TABLE IF EXISTS TEMP; CREATE temporary table tmp ( CatID BIGINT primary key not null, CatTitle TEXT, CatDescription TEXT, CatTitleAr TEXT, CatDescriptionAr TEXT, PictureID BIGINT, Published BOOLEAN, DisplayOrder BIGINT, CreatedOn DATE ); IF PaRactioncode = 1 THEN -- Retrive all DATA from the database -- INSERT INTO tmp SELECT CatID,CatTitle,CatDescription,CatTitleAr,CatDescriptionAr,PictureID,Published,DisplayOrder,CreatedOn FROM tbcategories; ELSEIF PaRactioncode = 2 THEN -- Retrive all from the database By ID -- INSERT INTO tmp SELECT CatID,CatTitle,CatDescription,CatTitleAr,CatDescriptionAr,PictureID,Published,DisplayOrder,CreatedOn FROM tbcategories WHERE CatID=PaRCatID; ELSEIF PaRactioncode = 3 THEN -- NOSET YET -- INSERT INTO tmp SELECT CatID,CatTitle,CatDescription,CatTitleAr,CatDescriptionAr,PictureID,Published,DisplayOrder,CreatedOn FROM tbcategories WHERE Published=1 ORDER BY DisplayOrder; END IF; IF PaRSearchText IS NOT NULL THEN set PaRSearchText=concat('%', PaRSearchText ,'%'); SELECT CatID,CatTitle,CatDescription,CatTitleAr,CatDescriptionAr,PictureID,Published,DisplayOrder,CreatedOn FROM tmp WHERE Concat(CatTitle, CatDescription, CatTitleAr, CatDescriptionAr) LIKE PaRSearchText; ELSE SELECT CatID,CatTitle,CatDescription,CatTitleAr,CatDescriptionAr,PictureID,Published,DisplayOrder,CreatedOn FROM tmp; END IF; DROP TEMPORARY TABLE IF EXISTS tmp; END

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  • MySql service stops under 2008 r2 x64

    - by volody
    I have installed MySql 5.5 server under windows 2008r2 x64 Apparently I can see that MySql service stops even if is configured to start automatically What can I do to find out why this is happening? MySql database is used as backend of ASP.Net web site Is it possible that web site was not active for a while and system stop mysql service? Update: It was mysql-5.5.7-rc-winx64. I could be an issue with this version (release candidate). Now I am trying to install mysql-5.5.8-winx64 And I have an issue with configuring MySql to work using name pipes I did uncheck use of TCP/IP protocol and configuration wizard just hangs Update: I have found workaround. It is required to configure MySql to use TCP/IP first, then reconfigure to use named pipes It looks like this link also has some information about the possible problems How should I diagnose ERROR 1045 during MySQL installation?

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  • Monit can't detect MySQL, but I can

    - by Matchu
    Monit is configured to watch MySQL on localhost at port 3306. check process mysqld with pidfile /var/lib/mysql/li175-241.pid start program = "/etc/init.d/mysql start" stop program = "/etc/init.d/mysql stop" if failed port 3306 protocol mysql then restart if 5 restarts within 5 cycles then timeout My application, which is configured to connect to MySQL via localhost:3306, is running just fine and can access the database. I can even use MySQL Query Browser to connect to the database remotely via port 3306. The port is totally open and possible to connect to. Therefore, I'm pretty darn certain that it's running. However, running monit -v reveals that Monit cannot detect MySQL on that port. 'mysqld' failed, cannot open a connection to INET[localhost:3306] via TCP This happens consistently, until Monit decides not to track MySQL anymore, as configured. How can I begin to troubleshoot this issue?

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  • MySQL Connect Keynotes and Presentations Available Online

    - by Bertrand Matthelié
    72 1024x768 Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Following the tremendous success of MySQL Connect, you can now watch some of the keynotes online: The State of the Dolphin – by Oracle Chief Corporate Architect Edward Screven and MySQL Vice President of Engineering Tomas Ulin 72 1024x768 Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Cambria","serif";} MySQL Perspectives – featuring power users of MySQL who share their experiences and perspectives: Jeremy Cole, DBA Team Manager, Twitter Daniel Austin, Chief Architect, PayPal Ash Kanagat, IT Director; and Shivinder Singh, Database Architect, Verizon Wireless You can also access slides from a number of MySQL Connect presentations in the Content Catalog. Missing ones will be added shortly (provided the speakers consented to it). Enjoy!

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