Search Results

Search found 23449 results on 938 pages for 'browser close'.

Page 212/938 | < Previous Page | 208 209 210 211 212 213 214 215 216 217 218 219  | Next Page >

  • Javascript and jQuery (Fancybox) question

    - by songdogtech
    Javascript and jQuery (Fancybox) question I'm using the Javascript function below for Twitter sharing (as well as other services; the function code is simplified to just Twitter for this question) that grabs the to-be-shared page URL and title and it is invoked in the link with onclick. That results in the Twitter share page loading in a pop up browser window, i.e.<img src="/images/twitter_16.png" onclick="share.tw()" /> In order to be consistent with other design aspects of the site, what I'd like to be able to do is have the Twitter share page open not in a standard browser window but in a Fancybox (jQuery) window. Fancybox can load an external page in an iFrame when the img or href link contains a class (in this case class="iframe" ) in the link and in the document ready function in the header. Right now, of course, when I give the iframe class to the link that also has the onclick share.tw(), I get two popups: one browser window popup with the correct Twitter share page loaded, and a Fancybox jQuery popup that shows a site 404. How can I change the function to use Fancybox to present the Twitter share page? Is that a correct way to approach it? Or is there a better way, such as implementing the share function in jQuery, too? Thanks... Javascript share function: var share = { tw:function(title,url) { this.share('http://twitter.com/home?status=##URL##+##TITLE##',title,url); }, share:function(tpl,title,url) { if(!url) url = encodeURIComponent(window.location); if(!title) title = encodeURIComponent(document.title); tpl = tpl.replace("##URL##",url); tpl = tpl.replace("##TITLE##",title); window.open(tpl,"sharewindow"+tpl.substr(6,15),"width=640,height=480"); } }; It is invoked, i.e.: <img src="/images/twitter_16.png" onclick="share.tw()" /> Fancybox function, invoked by adding class="iframe" in the img or href link $(".iframe").fancybox({ 'width' : '100%', 'height' : '100%', 'autoScale' : false, 'transitionIn' : 'none', 'transitionOut' : 'none', 'type' : 'iframe' });

    Read the article

  • JavaScript window object element properties

    - by Timothy
    A coworker showed me the following code and asked me why it worked. <span id="myspan">Do you like my hat?</span> <script type="text/javascript"> var spanElement = document.getElementById("myspan"); alert("Here I am! " + spanElement.innerHTML + "\n" + myspan.innerHTML); </script> I explained that a property is attached to the window object with the name of the element's id when the browser parses the document which then contains a reference to the appropriate dom node. It's sort of as if window.myspan = document.getElementById("myspan") is called behind the scenes as the page is being rendered. The ensuing discussion we had raised a few of questions: The window object and most of the DOM are not part of the official JavaScript/ECMA standards, but is the above behavior documented in any other official literature, perhaps browser-related? The above works in a browser (at least the main contenders) because there is a window object, but fails in something like rhino. Is writing code that relys on this considered bad practice because it makes too many assumptions about the execution environment? Are there any browsers in which the above would fail, or is this considered standard behavior across the board? Does anyone here know the answers to those questions and would be willing to enlighten me? I tried a quick internet search, but I admit I'm not sure how to even properly phrase the query. Pointers to references and documentation are welcome.

    Read the article

  • how to lucene serch in android

    - by xyz Sad
    Lucen with android logic ..??? public class TestAndroidLuceneActivity extends Activity { @Override public void onCreate(Bundle icicle) { super.onCreate(icicle); setContentView(R.layout.main); try { Directory directory = new RAMDirectory(); Analyzer analyzer = new StandardAnalyzer(); Document doc = new Document(); doc.add(new Field("header", "ABC", Field.Store.YES,Field.Index.TOKENIZED)); indexWriter.addDocument(doc); doc.add(new Field("header", "DEF", Field.Store.YES,Field.Index.TOKENIZED)); indexWriter.addDocument(doc); doc.add(new Field("header", "GHI", Field.Store.YES,Field.Index.TOKENIZED)); indexWriter.addDocument(doc); doc.add(new Field("header", "JKL", Field.Store.YES,Field.Index.TOKENIZED)); indexWriter.addDocument(doc); indexWriter.optimize(); indexWriter.close(); IndexSearcher indexSearcher = new IndexSearcher(directory); QueryParser parser = new QueryParser("header", analyzer); // Query query = parser.parse("(" + "Anil" + ")"); Query query = parser.parse("(" + "ABC" + ")"); Hits hits = indexSearcher.search(query); for (int i = 0; i < hits.length(); i++) { Document hitDoc = hits.doc(i); Log.i("TestAndroidLuceneActivity", "Lucene: " +hitDoc.get("header")); // Toast.makeText(this, hitDoc.get("header"),Toast.LENGTH_LONG).show(); } indexSearcher.close(); directory.close(); } catch (Exception ex) { System.out.println(ex.getMessage()); } } } i have this code but i m not able to understnd plz send me related or modifed and set it main.xml show me some out put plzz..its does not serch after "ABC" plz tell me wat is the problem in logic any thing missing???..

    Read the article

  • Not able to play videos (from youtube) in WebView

    - by user1205193
    I am using a webview to display a video (could be from youtube or vimeo) in my app. In order to not load the video webpages in the default Android Browser, I am also extending the WebViewClient so I can override the shouldOverrideUrlLoading method. This way the video webpage loads successfully in the WebView. However, when I click on the embedded video on the WebView, it does not play. If I do not override the shouldOverrideUrlLoading method, and let the video webpages load in the default Android browser, the videos work just fine. Any ideas why the videos are not working in the WebView? Also, the main reason why I overrode the shouldOverrideUrlLoading method is because if I do not do that, then when I exit the Android browser to come back to my activity (by hitting the back button on the phone), I see a white screen. Upon hitting the back button twice, I am able to get back to my Activity. I am using the emulator to do this test. Here is my code: public class YoutubeLink extends Activity { WebView myWebView; String video_url; private class HelloWebViewClient extends WebViewClient { @Override public boolean shouldOverrideUrlLoading(WebView view, String url) { view.loadUrl(url); return true; } } @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.youtubelink); //Retrieving data from ListSample.java Bundle extras = getIntent().getExtras(); if(extras !=null) { video_url = extras.getString("video_url"); Log.d("inside YoutubeLink.java", video_url); } myWebView = (WebView) findViewById(R.id.web); myWebView.getSettings().setJavaScriptEnabled(true); myWebView.setWebViewClient(new HelloWebViewClient()); myWebView.loadUrl(video_url); } @Override public boolean onKeyDown(int keyCode, KeyEvent event) { if ((keyCode == KeyEvent.KEYCODE_BACK) && myWebView.canGoBack()) { myWebView.goBack(); return true; } return super.onKeyDown(keyCode, event); }}

    Read the article

  • inserting unique date into txt document

    - by durian
    I'm trying this script to insert only a unique date into a text file, but it isn't working properly: $log_file_name = "logfile.txt"; $log_file_path = "log_files/$id/$log_file_name"; if(file_exists($log_file_path)){ $not = "not"; $todaydate = date('d,m,Y'); $today = "$todaydate;"; $strlength = strlen($today); $file_contents = file_get_contents($log_file_path); $file_contents_arry = explode(";",$file_contents); if(!in_array($todaytodaydate,$file_contents_arry)){ $append = fopen($log_file_path, 'a'); $write = fwrite($append,$today); //writes our string to our file. $close = fclose($append); //closes our file } else { $append = fopen($log_file_path, 'a'); $write = fwrite($append,$not); //writes our string to our file. $close = fclose($append); //closes our file } } else{ mkdir("log_files/$id", 0700); $todaydate = date('d,m,Y'); $today = "$todaydate;"; $strlength = strlen($today); $create = fopen($log_file_path, "w"); $write = fwrite($create, $today, $strlength); //writes our string to our file. $close = fclose($create); //closes our file } The problem is with the if else statement where it should be written if it's already in the array.

    Read the article

  • Selecting a form which is in an iframe using jQuery

    - by Khnle
    I have a form inside an iframe which is inside a jQuery UI dialog box. The form contains a file input type. The jQuery UI dialog contains an Upload button. When this button is clicked, I would like to programmatically call the submit method. My question is how I could select the form which is in a iframe using jQuery. The following code should clarify the picture: <div id="upload_file_picker_dlg" title="Upload file"> <iframe id="upload_file_iframe" src="/frame_src_url" frameborder=0 width=100% scrolling=no></iframe> </div> frame_src_url contains: <form action="/UploadTaxTable" enctype="multipart/form-data" method="post" id="upload-form"> <p>Select a file to be uploaded:</p> <p> <input type="file" name="datafile" size="60"> </p> The jQueryUI dialog box javascript code: $('#upload_file_picker_dlg').dialog({ ... buttons: { 'Close': function() { $(this).dialog('close'); }, 'Upload': function() { $('#upload-form').submit(); //question is related to this line $(this).dialog('close'); } }, .... }); From the javascript code snippet above, how can I select the form with id upload-form that is in the iframe whose id is upload_file_iframe ?

    Read the article

  • .NET, ASHX, "Server cannot append header after HTTP headers have been sent" after sending PDF Streem

    - by Inturbidus
    I visit my ASHX file, and it outputs a PDF perfectly. If I visit the very same ASHX with a different query string (I append DateTime.Now.Ticks to the end each visit), and I get this error: Server cannot append hader after HTTP headers have been sent. My code is below: copy.CloseStream = false; document.Close(); var r = context.Response; r.ExpiresAbsolute = DateTime.Now; r.BufferOutput = true; r.ContentType = "application/pdf"; r.AppendHeader("Content-Type", r.ContentType); r.AppendHeader("Content-disposition", "inline; filename=" + context.Server.UrlEncode(formType.File_Name)); r.BinaryWrite(copyStream.ToArray()); r.StatusCode = 200; r.End(); originalReader.Close(); copy.CloseStream = true; copy.Close(); There is no other place in this code that headers are sent. You are seeing the entire interaction with the Response object. I've tried to use r.Flush(); and r.End(); I've also tried not sending them if they are already there, but this causes other issues.

    Read the article

  • jQuery: If user clicks out of div

    - by Paul Knopf
    I am creating a popup in query. All is well with the popup on hover. I made it see a timer starts when user's mouse leaves the div to close it. If he enters the div again before the timer is done, then the timer is cleared. This is fine, but what if a user clicks out of the div? I want that to also close the div. The only problem is that I don't want to attach click events to the wrapper on the page (because it includes the popout menu). I have seen techniques that wraps entire screen with a transparent div, and then attach a click event to hit. Although this may work, it confuses the user if he clicks the hidden div intending to click a link. He will have to click the link twice. Once two close the div (hiding the link), and another time to actually click think. Also, you loose in mouse cursors attached to any masked elements on the page (such as links cursor pointer, etc). There has to be a way to check if the user clicked out of the div without a modal and without attaching events to the entire page (page wrappers and child elements included). onclicksomewhereelse="closeme();" lol.

    Read the article

  • i see the file but when i open it nothing is in it in c++ i/o stream and dont know why

    - by user320950
    #include<iostream> #include<fstream> #include<cstdlib> #include<iomanip> using namespace std; int main() { ifstream in_stream; // reads ITEMSLIST.txt ofstream out_stream1; // writes in listWititems.txt ifstream in_stream2; // reads PRICELIST.txt ofstream out_stream3;// writes in listWitprices.txt ifstream in_stream4;// read display.txt ofstream out_stream5;// write showitems.txt double p1=0.0,p2=0.0; int wrong=0; int count =0; char next; in_stream.open("ITEMLIST.txt", ios::in); // list of avaliable items /*if( in_stream.fail() )// check to see if itemlist.txt is open { wrong++; // counts number of errors cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ out_stream1.open("listWititems.txt", ios::out); // list of avaliable items /* if( out_stream1.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ in_stream2.open("PRICELIST.txt", ios::in); /*if( in_stream2.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ out_stream3.open("listWitdollars.txt", ios::out); /*if( out_stream3.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ in_stream4.open("display.txt", ios::in); /*if( in_stream4.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ out_stream5.open("showitems.txt", ios::out); /*if( out_stream5.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; }*/ in_stream.setf(ios::fixed); while(!in_stream.eof()) // reads to end of file and gets p1 which is itemnum, clears and gets next character { in_stream >> p1; cin.clear(); cin >> next; } out_stream1.setf(ios::fixed); while (!out_stream1.eof()) { out_stream1 << p1; cin.clear(); cin >> next; } in_stream2.setf(ios::fixed); in_stream2.setf(ios::showpoint); in_stream2.precision(2); while(!in_stream2.eof()) // reads file to end of file { in_stream2 >> p1 >> p2 >> count; // gets p1,p2, and count which is current total in_stream2 >> p2; p1 += p2; p2++; cin.clear(); // allows more reading cin >> next; return p1, p2; } out_stream3.setf(ios::fixed); out_stream3.setf(ios::showpoint); out_stream3.precision(2); while(!out_stream3.eof()) // reads file to end of file { out_stream3 << p1 << p2 << count; out_stream3 << p2; p1 += p2; p2++; cin.clear(); // allows more reading cin >> next; return p1, p2; } in_stream4.setf(ios::fixed); in_stream4.setf(ios::showpoint); in_stream4.precision(2); while (!in_stream4.eof()) { in_stream4 >> p1 >> p2 >> count; cin.clear(); cin >> next; } out_stream5.setf(ios::fixed); out_stream5.setf(ios::showpoint); out_stream5.precision(2); out_stream5 <<setw(5)<< " itemnum " <<setw(5)<<" price "<<setw(5)<<" curr_total " <<endl; // sends items and prices to receipt.txt out_stream5 << setw(5) << p1 << setw(5) <<p2 << setw(5)<< count; // sends items and prices to receipt.txt out_stream5 << " You have a total of " << wrong++ << " errors " << endl; in_stream.close(); // closing files. out_stream1.close(); in_stream2.close(); out_stream3.close(); in_stream4.close(); out_stream5.close(); system("pause"); }

    Read the article

  • How would a user stay logged in to a REST-based website?

    - by unforgiven3
    A year or so ago I asked this question: Can you help me understand this? “Common REST Mistakes: Sessions are irrelevant”. My question was essentially this: Okay, I get that HTTP authentication is done automatically on every message - but how? Is the username/password sent with every request? Doesn't that just increase attack surface area? I feel like I'm missing part of the puzzle. The answers I received made perfect sense in the context of a mobile (iPhone, Android, WP7) app - when talking to a REST service, the app would just send user credentials along with each request. That worked great for me. But now, I would like to better understand how one would secure a REST-like website, like StackOverflow itself or something like Reddit. How would things work if it was a user logged in via a web browser instead of logged in via an iPhone app? What happens when a user logs in? Are the credentials saved in the browser somehow? How would the browser know what credentials to send with subsequent REST requests? What if it's a JavaScript call to a webservice? How would the JavaScript call include user credentials? I'll be quite frank: my understanding of security when it comes to websites is pretty limited. I enjoyed working with REST services from an app perspective, but now I want to try and build a website that is based on REST principles, and I'm finding myself to be pretty lost. If there is anything in the above question that is unclear that you'd like me to clarify, please leave a comment and I'll address it.

    Read the article

  • Javascript function objects, this keyword points to wrong object

    - by Rody van Sambeek
    I've got a problem concerning the javascript "this" keyword when used within a javascript functional object. I want to be able to create an object for handling a Modal popup (JQuery UI Dialog). The object is called CreateItemModal. Which i want to be able to instantiate and pass some config settings. One of the config settings. When the show method is called, the dialog will be shown, but the cancel button is not functioning because the this refers to the DOM object instead of the CreateItemModal object. How can I fix this, or is there a better approach to put seperate behaviour in seperate "classes" or "objects". I've tried several approaches, including passing the "this" object into the events, but this does not feel like a clean solution. See (simplified) code below: function CreateItemModal(config) { // initialize some variables including $wrapper }; CreateItemModal.prototype.show = function() { this.$wrapper.dialog({ buttons: { // this crashes because this is not the current object here Cancel: this.close } }); }; CreateItemModal.prototype.close = function() { this.config.$wrapper.dialog('close'); };

    Read the article

  • How can i get a file from remote machine?

    - by programmerist
    How can i get a file from remote computer? i know remote computer ip and 51124 port is open. i need this algorith: 1) Connect 192.xxx.x.xxx ip via 51124 port 2) filename:123456 (i want to search it on remote machine) 3) Get File 4) Save C:\ 51124 port is open. can i access and can i search any file according to filename? My code is below: IPEndPoint ipEnd = new IPEndPoint(IPAddress.Any, 51124); Socket sock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP); sock.Bind(ipEnd); sock.Listen(maxConnections); Socket serverSocket = sock.Accept(); byte[] data = new byte[bufferSize]; int received = serverSocket.Receive(data); int filenameLength = BitConverter.ToInt32(data, 0); string filename = Encoding.ASCII.GetString(data, 4, filenameLength); BinaryWriter bWrite = new BinaryWriter(File.Open(outPath + filename, FileMode.Create)); bWrite.Write(data, filenameLength + 4, received - filenameLength - 4); int received2 = serverSocket.Receive(data); while (received2 0) { bWrite.Write(data, 0, received2); received2 = serverSocket.Receive(data); } bWrite.Close(); serverSocket.Close(); sock.Close();

    Read the article

  • Why is this Javascript that writes out a Google Ad not displaying properly on the iPhone?

    - by Dave M G
    I have this Javacsript code that checks to see if there is a DIV named "google-ad", and if there is, it writes in a the necessary code to display the Google Ad. This works great in browsers like Firefox, Chrome, Safari on Mac, and Android. However, when I bundle this code with Adobe's Phonegap Build, and deploy it to iPhones, it behaves strangely. It launches a browser window displaying just the Google Ad alone. In order to keep using my app, every time I change a page and a new Google Ad is loaded, I have to close the browser window to get back to the app. Why is this code launching browser windows outside of my Phonegap app on iPhone? if(document.getElementById("google-ad") && document.getElementById("google-ad") !== null && document.getElementById("google-ad") !== "undefined") { if(userStatus.status == 0) { document.getElementById("centre").style.padding = "137px 0 12px 0"; document.getElementById("header-container").style.margin = "-138px 0 0 0"; document.getElementById("header-container").style.height = "132px"; document.getElementById("header-username").style.top = "52px"; document.getElementById("google-ad").style.height = "50px"; document.getElementById("google-ad").style.width = "320px"; document.getElementById("google-ad").style.backgroundColor = "#f0ebff"; document.getElementById("google-ad").style.display = "block"; window["google_ad_client"] = 'ca-pub-0000000000000000'; window["google_ad_slot"] = "00000000"; window["google_ad_width"] = 320; window["google_ad_height"] = 50; window.adcontainer = document.getElementById('google-ad'); window.adhtml = ''; function mywrite(html) { adhtml += html; adcontainer.innerHTML = adhtml; }; document.write_ = document.write; document.write = mywrite; script = document.createElement('script'); script.src='http://pagead2.googlesyndication.com/pagead/show_ads.js'; script.type='text/javascript'; document.body.appendChild(script); }

    Read the article

  • FileConnection Blackberry memory usage

    - by Dean
    Hello, I'm writing a blackberry application that reads ints and strings out of a database. This is my first time dealing with reading/writing on the blackberry, so forgive me if this is a dumb question. The database file I'm reading is only about 4kB I open the file with the following code fconn = (FileConnection) Connector.open("file_path_here", Connector.READ); if(fconn.exists()==false){fconn.close();return;} is = fconn.openDataInputStream(); while(!eof){ //etc... } is.close(); fconn.close(); The problem is, this code appears to be eating a LOT of memory. Using breakpoints and the "Memory Statistics" view, I determined the following: calling "Connector.open" creates 71 objects and changes "RAM Bytes in use" by 5376 calling "fconn.openDataInputStream();" increases RAM usage by a whopping 75920 Is this normal? Or am I doing something wrong? And how can I fix this? 75MB of RAM is a LOT of memory to waste on a handheld device, especially when the file I'm reading is only 4kB and I haven't even begun reading any data! How is this even possible?

    Read the article

  • How to pass value in url using web request GET method asp.net

    - by Narasi
    Am new to .Net and web service..i like to pass id through url..how to do that?whether it was done post or get method?guide me string url = "http://XXXXX//"+id=22; WebRequest request = WebRequest.Create(url); request.Proxy.Credentials = new NetworkCredential(xxxxx); request.Credentials = CredentialCache.DefaultCredentials; //add properties request.Method = "GET"; request.ContentType = "application/json"; //convert byte[] byteArray = Encoding.UTF8.GetBytes(data); request.ContentLength = byteArray.Length; //post data Stream streamdata = request.GetRequestStream(); streamdata.Write(byteArray, 0, byteArray.Length); streamdata.Close(); //response WebResponse response = request.GetResponse(); // Get the stream containing content returned by the server. Stream dataStream = response.GetResponseStream(); // Open the stream using a StreamReader for easy access. StreamReader reader = new StreamReader(dataStream); // Read the content. string responseFromServer = reader.ReadToEnd(); // Clean up the streams and the response. reader.Close(); response.Close(); Thanks in advance

    Read the article

  • How to set the the height of cell progamatically without using nib file ?

    - by srikanth rongali
    This is my program - (void)viewDidLoad { [super viewDidLoad]; // Uncomment the following line to display an Edit button in the navigation bar for this view controller. self.title = @"Library"; self.navigationItem.rightBarButtonItem = [[UIBarButtonItem alloc] initWithTitle:@"Close" style:UIBarButtonItemStyleBordered target:self action:@selector(close:)]; // self.tableView.rowHeight = 80; } -(void)close:(id)sender { // } - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithFrame:CGRectZero reuseIdentifier:CellIdentifier] autorelease]; UILabel *dateLabel = [[UILabel alloc]init]; dateLabel.frame = CGRectMake(85.0f, 6.0f, 200.0f, 20.0f); dateLabel.tag = tag1; [cell setAccessoryType:UITableViewCellAccessoryDisclosureIndicator]; cell.contentView.frame = CGRectMake(0.0f, 0.0f, 320.0f, 80.0f); [cell.contentView addSubview:dateLabel]; [dateLabel release]; } // Set up the cell... //[(UILabel *)[cell viewWithTag:tag1] setText:@"Date"]; cell.textLabel.text = @"Date"; return cell; } I am setting the frame size of cell in tableView: but the cell is in default size only. I mean the height I set was 80 but it was not set as 80 height. How can I make it. Thank You

    Read the article

  • Apache and linux file permissions can't browse file or directories

    - by dardub
    I just copied my magento site over to a local server running CentOS 5.4. The browser said it can't locate the location of the stylesheets. The stylesheets are within /skin/frontend/my_new_interface/design2/css. I tried to view in the browser and I can't view any of the files within the css directory. I verified a million times that I'm typing in the correct location. I can view files within /skin/frontend/my_new_interface/design2. Can't browse directories within browser however. I typed in ls -l css and get: -rwxr-xr-x 1 apache apache listed for all the files I tried chmod -R 755 and the directories I changed the apache conf Options Indexes But still when I browse the directories I get Forbidden. However, in another fresh installation of magento in the same www dir, I am able to browse directories. As far as I can tell both installations have same ownership and permissions. I also tried find . -type f -exec chmod 644 {} \; find . -type d -exec chmod 755 {} \; which was recommended in the magento wiki I've just run out of ideas.

    Read the article

  • rehabilitating a button

    - by Michele Petraroli
    if($('.click').one('click')){ $('.click').click(function(){ $('.mainContent').animate( {"height":"+=620px"}, 800, 'easeInBack'); $('.eneButton').animate( { "top":"+=310px"}, 1500, 'easeInOutExpo'); $('.eneButton').animate( {"left":"-=310px"}, 1500, 'easeInOutExpo') $('.giardButton').animate( {"top":"+=620px"}, 2000, 'easeInOutExpo') $('.giardButton').animate( {"left":"-=620px"}, 2000, 'easeInOutExpo'); $('.click').off('click'); }) } if ($('.close').one('click')){ $('.close').click(function(){ $('.content, .sec').fadeOut(250); $('.eneButton').animate( {"left":"+=310px"}, 1500, 'easeInOutExpo') $('.eneButton').animate( { "top":"-=310px"}, 1500, 'easeInOutExpo'); $('.giardButton').animate( {"left":"+=620px"}, 2000, 'easeInOutExpo'); $('.giardButton').animate( {"top":"-=620px"}, 2000, 'easeInOutExpo'); $('.mainContent').animate( {"height":"-=620px"}, 3500, 'easeInBack'); $('.click').on('click'); }) } the animation is working fine in both ways but I need that users may restart the animation again when its closed. as you can see from the code you do one click and an animation starts, then you select a list of categories which you can close with a click on a "X" like in windows, when you do that the animation start again till all look like as the begin. Now if I click again on it the animation doesnt start no more. any clue?

    Read the article

  • C++ File manipulation problem

    - by Carlucho
    I am trying to open a file which normally has content, for the purpose of testing i will like to initialize the program without the files being available/existing so then the program should create empty ones, but am having issues implementing it. This is my code originally void loadFiles() { fstream city; city.open("city.txt", ios::in); fstream latitude; latitude.open("lat.txt", ios::in); fstream longitude; longitude.open("lon.txt", ios::in); while(!city.eof()){ city >> cityName; latitude >> lat; longitude >> lon; t.add(cityName, lat, lon); } city.close(); latitude.close(); longitude.close(); } I have tried everything i can think of, ofstream, ifstream, adding ios::out all all its variations. Could anybody explain me what to do in order to fix the problem. Thanks!

    Read the article

  • Mouse management in JavaScript games

    - by Jakob
    Im using JavaScript, the HTML5 canvas-element and WebGL to make a simple 3D-game in first person view for fun. Ideally, I would like to control my movement by using the keyboard to move and the mouse to look around, like you usually do in FPS-games. As you probably understand, there are some limits to this in the browser, since the mouse cant be captured: When using the onmousemove event, no further movement will be detected when the mouse pointer reaches the border of my screen (which means that I wont be able to run in a circle for example) Seeing the mouse move across the screen is not the end of the world, but it is a little annoying From what I know, it's impossible to hide the mouse as well as setting it's position in JavaScript. Hence, my question is this: If we cant to those things, what can we do in order to get close to the desktop gaming experience when it comes to the mouse in the browser? And I mean right now, using current APIs. Not "what could be changed in some standard to make life easier". Also, I realize that I could use the keyboard to look around, but then we're back in 1995 when Quake were actually played like that. And of course I know that it would be easier to write a desktop application or use Flash at least, but Im trying to push JavaScript's limits here. Apart from those things, what are your suggestions? Any kind of reference, existing game, crazy idea, hack or even browser specific solution would be appreciated.

    Read the article

  • youtube video downloaed succesfully on local, but on server(online) only 0 byte flv is downloading

    - by I Like PHP
    i m using php tube class to download youtube video. Video is automatically downloaded in a folder by submitting youtube video url. everything is working fine on local (XAMPP), but when i upload this to server(online), THEN ONLY 0 byte flv file is saved. i also debug the code both side( local and global ). i get the url like this( on local) http://www.youtube.com/get_video?video_id=1jNWCFwqPvM&=vjVQa1PpcFMyYCECyfmYENWklpwXGyhVgJpSFPgNAEc%3D whereas on server i got link like this http://www.youtube.com/ get_video?video_id=1jNWCFwqPvM&t=vjVQa1PpcFNS3SPxIXi8hy-NF4qZFFrScDXCjGLLrLc%3D when i copy the link getting from local and paste on browser then a download box appear on browser, whereas when i copy the link getting from server and paste on browser then only a blank page appears please solve my problem, where is the error??? how to know that pear is installed or not on server? on server side sometimes i get link like http://www.youtube.com/get_video?video_id=1jNWCFwqPvM&t=vjVQa1PpcFNS3SPxIXi8hy-NF4qZFFrScDXCjGLLrLc%3D but sometimes i get only http://www.youtube.com/get_video?video_id=&t= please guide me how to solve these? Thanks in advance to all my seniors

    Read the article

  • jqtouch - panels appear on page, class="back" not working in Safari

    - by user564816
    I'm trying to get a demo working that was used in J. Stark's webinar on Safari Books Online (still available for viewing). I think I've followed the code example correctly, but the class="back" objects used to return from the "blog", "contacts", "settings" and "about" panels do not work, though the correct address shows in the nav area at the base of the browser window when I hover the mouse over the respective link. The panels-- which should slide in and out when called by their respective class"arrow" elements-- appear on the main page, nor do they animate correctly. Browser is Safari 5.0.3(6533.19.4); jquery-1.3.2; jqtouch freshly downloaded from the jqt website. Obviously I'm missing something simple. I'd sincerely appreciate anyone's help who sees what I'm doing wrong. Thanks for considering my question. View the app and source code (use view source in your browser) here. Sat 8 January 2011: 1 48 AM UPDATE in response to JS's comments: Most humble thanks for your note. Didn't want to impose on your server, so the URL for jqtouch.min.css points to a version on my server @ fastermac.net. There's something further amiss, I believe. On load, page still shows the elements that should be invisible until called by clicking class="arrow" elements. Animations not yet wiggling. Did get them to wiggle at one point, but "flip," for instance, landed then on a black page-- not the targeted panel. Probably something obvious, but I'm missing it after some considerable due diligence. Again, thanks for your note. Any further illumination would be sincerely appreciated.

    Read the article

  • Is this a safe way to release resources in Java?

    - by palto
    Usually when code needs some resource that needs to be released I see it done like this: InputStream in = null; try{ in = new FileInputStream("myfile.txt"); doSomethingWithStream(in); }finally{ if(in != null){ in.close(); } } What I don't like is that you have to initialize the variable to null and after that set it to another value and in the finally block check if the resource was initialized by checking if it is null. If it is not null, it needs to be released. I know I'm nitpicking, but I feel like this could be done cleaner. What I would like to do is this: InputStream in = new FileInputStream("myfile.txt"); try{ doSomethingWithStream(in); }finally{ in.close(); } To my eyes this looks almost as safe as the previous one. If resource initialization fails and it throws an exception, there's nothing to be done(since I didn't get the resource) so it doesn't have to be inside the try block. The only thing I'm worried is if there is some way(I'm not Java certified) that an exception or error can be thrown between operations? Even simpler example: Inputstream in = new FileInputStream("myfile.txt"); in.close(); Is there any way the stream would be left open that a try-finally block would prevent?

    Read the article

  • Division of text follow the cursor via Javascript/Jquery

    - by webzide
    Dear experts, I wanted have a dynamic division of content follow you with the cursor in the web browser space. I am not a pro at JS so I spent 2 hours to finally debugged a very stupid way to accomplish this. $(document).ready(function () { function func(evt) { var evt = (evt) ? evt : event; var div = document.createElement('div'); div.style.position = "absolute"; div.style.left = evt.clientX + "px"; div.style.top = evt.clientY + "px"; $(div).attr("id", "current") div.innerHTML = "CURSOR FOLLOW TEXT"; $(this).append($(div)); $(this).unbind() $(this).bind('mousemove', function () { $('div').remove("#current"); }); $(this).bind('mousemove', func); } $("body").bind('mousemove', func) }); As you can see this is pretty much Brute force and it slows down the browser quite a bit. I often experience a lag on the browser as a drag my mouse from one place to another. Is there a way to accomplish this easier and faster and more intuitive. I know you can use the cursor image technique but thats something I'm looking to avoid. Thanks in advance.

    Read the article

  • programs hangs during socket interaction

    - by herrturtur
    I have two programs, sendfile.py and recvfile.py that are supposed to interact to send a file across the network. They communicate over TCP sockets. The communication is supposed to go something like this: sender =====filename=====> receiver sender <===== 'ok' ======= receiver or sender <===== 'no' ======= receiver if ok: sender ====== file ======> receiver I've got The sender and receiver code is here: Sender: import sys from jmm_sockets import * if len(sys.argv) != 4: print "Usage:", sys.argv[0], "<host> <port> <filename>" sys.exit(1) s = getClientSocket(sys.argv[1], int(sys.argv[2])) try: f = open(sys.argv[3]) except IOError, msg: print "couldn't open file" sys.exit(1) # send filename s.send(sys.argv[3]) # receive 'ok' buffer = None response = str() while 1: buffer = s.recv(1) if buffer == '': break else: response = response + buffer if response == 'ok': print 'receiver acknowledged receipt of filename' # send file s.send(f.read()) elif response == 'no': print "receiver doesn't want the file" # cleanup f.close() s.close() Receiver: from jmm_sockets import * s = getServerSocket(None, 16001) conn, addr = s.accept() buffer = None filename = str() # receive filename while 1: buffer = conn.recv(1) if buffer == '': break else: filename = filename + buffer print "sender wants to send", filename, "is that ok?" user_choice = raw_input("ok/no: ") if user_choice == 'ok': # send ok conn.send('ok') #receive file data = str() while 1: buffer = conn.recv(1) if buffer=='': break else: data = data + buffer print data else: conn.send('no') conn.close() I'm sure I'm missing something here in the sorts of a deadlock, but don't know what it is.

    Read the article

< Previous Page | 208 209 210 211 212 213 214 215 216 217 218 219  | Next Page >