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  • PHP create page as a string after PHP runs

    - by John
    I'm stuck on how to write the test.php page result (after php has run) to a string: testFunctions.php: <?php function htmlify($html, $format){ if ($format == "print"){ $html = str_replace("<", "&lt;", $html); $html = str_replace(">", "&gt;", $html); $html = str_replace("&nbsp;", "&amp;nbsp;", $html); $html = nl2br($html); return $html; } }; $input = <<<HTML <div style="background color:#959595; width:400px;"> &nbsp;<br> input <b>text</b> <br>&nbsp; </div> HTML; function content($input, $mode){ if ($mode =="display"){ return $input; } else if ($mode =="source"){ return htmlify($input, "print"); }; }; function pagePrint($page){ $a = array( 'file_get_contents' => array($page), 'htmlify' => array($page, "print") ); foreach($a as $func=>$args){ $x = call_user_func_array($func, $args); $page .= $x; } return $page; }; $file = "test.php"; ?> test.php: <?php include "testFunctions.php"; ?> <br><hr>here is the rendered html:<hr> <?php $a = content($input, "display"); echo $a; ?> <br><hr>here is the source code:<hr> <?php $a = content($input, "source"); echo $a; ?> <br><hr>here is the source code of the entire page after the php has been executed:<hr> <div style="margin-left:40px; background-color:#ebebeb;"> <?php $a = pagePrint($file); echo $a; ?> </div> I'd like to keep all the php in the testFunctions.php file, so I can place simple function calls into templates for html emails. Thanks!

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  • php cron jobs overlapping

    - by naveen gupta
    Hi I wrote few months back a script in perl for checking overlapping of jobs use Fcntl ':flock'; INIT { my $waitcount=12; # possible attemtps to run script my $waitseconds=300; # wait for $waitseconds each attempt my $lockstatus=0;#no lock was attained while ($waitcount > 0){ if (open LH, $0){ while ($waitcount > 0){ if (flock LH, LOCK_EX|LOCK_NB){ $waitcount=0;#signal end of waiting $lockstatus=1;#lock was attained } else{ --$waitcount;#decrement waitcount print "waiting to be able to lock $0\n"; sleep $waitseconds; }#end else }#end while }#end if else{ --$waitcount;#decrement waitcount print "waiting to be able to open $0\n"; sleep $waitseconds; }#end else }#end while if ($lockstatus == 0){ die "no lock was attained\n"; }#end if } I wanted to know if we can do similar thing in php .. How to integrate with your current php code which is running a part of php jobs?

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  • perl: added hash entry in a subroutine is lost

    - by hansi
    Why is the hash empty on the second call of printHash? my %hash = (); addToHash(\%hash); printHash(\%hash); sub addToHash { my %hash = %{$_[0]}; $hash{"test"} = "test"; printHash(\%hash); } sub printHash { print "printHash: \n"; my %hash = %{$_[0]}; foreach my $key (keys %hash) { print "key: $key, value: $hash{$key}\n"; } } Output: printHash: key: test, value: test printHash:

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  • Basic Python While loop compound conditional evaluation

    - by dbjohn
    In Python IDLE Shell it seems I cannot use a compound conditional expression and a while loop. I tried it within brackets too. k=0 m=0 while k<10 & m<10: print k k +=1 m+=1 If I write while k<10: print k k+=1 This does work. Is there a way I could achieve the first block of code with the "and" operator. I have done it in Java. Do I just need to put together "if" statements to achieve the same functionality in Python?

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  • AWK: how to reuse a result NR-times without removing END?

    - by HH
    How can I get all differences, not just one? I want to use the calculated result for each item in the third column. The dilemma is that if I remove END I can print $3 but cannot have ave. If I leave END I have ave but not all differences. awk '{sum+=$3} END {ave=sum/NR} END {print $3-ave}' coriolis_data -0.00964 // I want to see the rest differences, how? coriolis_data .105 0.005 0.9766 0.0001 0.595 0.005 .095 0.005 0.9963 0.0001 0.595 0.005 .115 0.005 0.9687 0.0001 0.595 0.005 .105 0.005 0.9693 0.0001 0.595 0.005 .095 0.005 0.9798 0.0001 0.595 0.005 .105 0.005 0.9798 0.0001 0.595 0.005 .095 0.005 0.9711 0.0001 0.595 0.005 .110 0.005 0.9640 0.0001 0.595 0.005 .105 0.005 0.9704 0.0001 0.595 0.005 .090 0.005 0.9644 0.0001 0.595 0.005

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  • Reordering Variadic Parameters

    - by void-pointer
    I have come across the need to reorder a variadic list of parameters that is supplied to the constructor of a struct. After being reordered based on their types, the parameters will be stored as a tuple. My question is how this can be done so that a modern C++ compiler (e.g. g++-4.7) will not generate unnecessary load or store instructions. That is, when the constructor is invoked with a list of parameters of variable size, it efficiently pushes each parameter into place based on an ordering over the parameters' types. Here is a concrete example. Assume that the base type of every parameter (without references, rvalue references, pointers, or qualifiers) is either char, int, or float. How can I make it so that all the parameters of base type char appear first, followed by all of those of base type int (which leaves the parameters of base type float last). The relative order in which the parameters were given should not be violated within sublists of homogeneous base type. Example: foo::foo() is called with arguments float a, char&& b, const float& c, int&& d, char e. The tuple tupe is std::tuple<char, char, int, float, float>, and it is constructed like so: tuple_type{std::move(b), e, std::move(d), a, c}. Consider the struct defined below, and assume that the metafunction deduce_reordered_tuple_type is already implemented. How would you write the constructor so that it works as intended? If you think that the code for deduce_reodered_tuple_type, would be useful to you, I can provide it; it's a little long. template <class... Args> struct foo { // Assume that the metafunction deduce_reordered_tuple_type is defined. typedef typename deduce_reordered_tuple_type<Args...>::type tuple_type; tuple_type t_; foo(Args&&... args) : t_{reorder_and_forward_parameters<Args>(args)...} {} }; Edit 1 The technique I describe above does have applications in mathematical frameworks that make heavy use of expression templates, variadic templates, and metaprogramming in order to perform aggressive inlining. Suppose that you wish to define an operator that takes the product of several expressions, each of which may be passed by reference, reference to const, or rvalue reference. (In my case, the expressions are conditional probability tables and the operation is the factor product, but something like matrix multiplication works suitably as well.) You need access to the data provided by each expression in order to evaluate the product. Consequently, you must move the expressions passed as rvalue references, copy the expressions passed by reference to const, and take the addresses of expressions passed by reference. Using the technique I describe above now poses several benefits. Other expressions can use uniform syntax to access data elements from this expression, since all of the heavy-lifting metaprogramming work is done beforehand, within the class. We can save stack space by grouping the pointers together and storing the larger expressions towards the end of the tuple. Implementing certain types of queries becomes much easier (e.g. check whether any of the pointers stored in the tuple aliases a given pointer). Thank you very much for your help!

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  • can i changed for loop index variable inside the loop in Matlab???

    - by shawana
    hi every one. i need to change my loop variable inside the iterationa as ihave to acces array elements in the loop which is changing w.r.t size inside the loop. ashort piece of code is that: que=[]; que=[2,3,4]; global len; len=size(que,2) x=4; for i=1:len if x<=10 que(x)= 5; len=size(que,2) x=x+1; end end que array should print like: 2 3 4 5 5 5 5 5 5 5 but it is printed in such a way: 2 3 4 5 5 5. how shuould it be accomplished in matlab? in visual c++ it happen correctly and print whole array of 10 elements which increases at run time plz reply me if have any ideaabout this as i m new into matlab

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  • kmeans based on mapreduce by python

    - by user3616059
    I am going to write a mapper and reducer for the kmeans algorithm, I think the best course of action to do is putting the distance calculator in mapper and sending to reducer with the cluster id as key and coordinates of row as value. In reducer, updating the centroids would be performed. I am writing this by python. As you know, I have to use Hadoop streaming to transfer data between STDIN and STOUT. according to my knowledge, when we print (key + "\t"+value), it will be sent to reducer. Reducer will receive data and it calculates the new centroids but when we print new centroids, I think it does not send them to mapper to calculate new clusters and it just send it to STDOUT and as you know, kmeans is a iterative program. So, my questions is whether Hadoop streaming suffers of doing iterative programs and we should employ MRJOB for iterative programs?

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  • Wait until a webpage finished loading to load the next one in a list

    - by envy
    Hi! I'm using PyQT webView to visit some webpages I have stored on a dictionary the code is something like this: def loadLink(self, url): manager = QNetworkAccessManager() request = QNetworkRequest(QUrl(url)) self.ui.webView.load(QUrl(visitar)) def readUnreadLinks(self): print "Links to read: " + str(len(self.unreadLinks)) for link in self.unreadLinks: print "link-> " + str(link) self.loadLink(link) the problem is it doesn't wait until finished loading the web page and starts loading the next one. I want to load a webpage, wait until it finished loading and then load the next one. Thanks, this is driving me crazy :)

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  • How can I mix command line arguments and filenames for <> in Perl?

    - by Jimmeh
    Consider the following silly Perl program: $firstarg = $ARGV[0]; print $firstarg; $input = <>; print $input; I run it from a terminal like: perl myprog.pl sample_argument And get this error: Can't open sample_argument: No such file or directory at myprog.pl line 5. Any ideas why this is? When it gets to the < is it trying to read from the (non-existent) file, "sample_argument" or something? And why?

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  • Replacing backslashes in Python strings

    - by user323659
    I have some code to encrypt some strings in Python. Encrypted text is used as a parameter in some urls, but after encrypting, there comes backslashes in string and I cannot use single backslash in urllib2.urlopen. I cannot replace single backslash with double. For example: print cipherText '\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb' print cipherText.replace('\\','\\\\') '\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb' Also putting r in front of \ in replace statement did not worked. All I want to do is calling that kind of url: http://awebsite.me/main?param="\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb" And also this url can be successfully called: http://awebsite.me/main?param="\\t3-@\\xab7+\\xc7\\x93H\\xdc\\xd1\\x13G\\xe1\\xfb" Any idea will be appreciated.

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  • Windows Service Printing Behaviour

    - by Andre
    Alright, I was tasked to develop a Windows Service that listens to a directory for files that are dropped in it, read them, delete them and print out a report. I installed the service on my work laptop (Win 7 x86) and a test machine (XP x86) under a User account at first. It would do everything as it should except the print the report. No errors, nothing. Then I made it run under Local System and it produced a "No printers found" exception. Converting the app to a Console Application and running on these machines gave the desired result. OK, so now I was assuming that there are security "stuff" involved. Then I installed the service on a Server 2008 x64 machine (under Local System) and it just worked. Can anybody explain to me why this is happening? Why does the service allow printing from Server OS but not from a Desktop OS or am I missing something very obvious?

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  • Using methods on 2 input files - 2nd is printing multiple times - Java

    - by Aaa
    I have the following code to read in text, store in a hashmap as bigrams (with other methods to sort them by frequency and do v. v. basic additive smoothing. I had it working great for one language input file (english) and then I want to expand it for the second language input file (japanese - doens;t matter what it is I suppose) using the same methods but the Japanese bigram hashmap is printing out 3 times in a row with diff. values. I've tried using diff text in the input file, making sure there are no gaps in text etc. I've also put print statements at certain places in the Japanese part of the code to see if I can get any clues but all the print statements are printing each time so I can't work out if it is looping at a certain place. I have gone through it with a fine toothcomb but am obviously missing something and slowly going crazy here - any help would be appreciated. thanks in advance... package languagerecognition2; import java.lang.String; import java.io.InputStreamReader; import java.util.*; import java.util.Iterator; import java.util.List.*; import java.util.ArrayList; import java.util.AbstractMap.*; import java.lang.Object; import java.io.*; import java.util.Enumeration; import java.util.Arrays; import java.lang.Math; public class Main { /** public static void main(String[] args) { //training English ----------------------------------------------------------------- File file = new File("english1.txt"); StringBuffer contents = new StringBuffer(); BufferedReader reader = null; try { reader = new BufferedReader(new FileReader(file)); String test = null; //test = reader.readLine(); // repeat until all lines are read while ((test = reader.readLine()) != null) { test = test.toLowerCase(); char[] charArrayEng = test.toCharArray(); HashMap<String, Integer> hashMapEng = new HashMap<String, Integer>(bigrams(charArrayEng)); LinkedHashMap<String, Integer> sortedListEng = new LinkedHashMap<String, Integer>(sort(hashMapEng)); int sizeEng=sortedListEng.size(); System.out.println("Total count of English bigrams is " + sizeEng); LinkedHashMap<String, Integer> smoothedListEng = new LinkedHashMap<String, Integer>(smooth(sortedListEng, sizeEng)); //print linkedHashMap to check values Set set= smoothedListEng.entrySet(); Iterator iter = set.iterator ( ) ; System.out.println("Beginning English"); while ( iter.hasNext()) { Map.Entry entry = ( Map.Entry ) iter.next ( ) ; Object key = entry.getKey ( ) ; Object value = entry.getValue ( ) ; System.out.println( key+" : " + value); } System.out.println("End English"); }//end while }//end try catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { try { if (reader != null) { reader.close(); } } catch (IOException e) { e.printStackTrace(); } } //End training English----------------------------------------------------------- //Training japanese-------------------------------------------------------------- File file2 = new File("japanese1.txt"); StringBuffer contents2 = new StringBuffer(); BufferedReader reader2 = null; try { reader2 = new BufferedReader(new FileReader(file2)); String test2 = null; //repeat until all lines are read while ((test2 = reader2.readLine()) != null) { test2 = test2.toLowerCase(); char[] charArrayJap = test2.toCharArray(); HashMap<String, Integer> hashMapJap = new HashMap<String, Integer>(bigrams(charArrayJap)); //System.out.println( "bigrams stage"); LinkedHashMap<String, Integer> sortedListJap = new LinkedHashMap<String, Integer>(sort(hashMapJap)); //System.out.println( "sort stage"); int sizeJap=sortedListJap.size(); //System.out.println("Total count of Japanese bigrams is " + sizeJap); LinkedHashMap<String, Integer> smoothedListJap = new LinkedHashMap<String, Integer>(smooth(sortedListJap, sizeJap)); System.out.println( "smooth stage"); //print linkedHashMap to check values Set set2= smoothedListJap.entrySet(); Iterator iter2 = set2.iterator(); System.out.println("Beginning Japanese"); while ( iter2.hasNext()) { Map.Entry entry2 = ( Map.Entry ) iter2.next ( ) ; Object key = entry2.getKey ( ) ; Object value = entry2.getValue ( ) ; System.out.println( key+" : " + value); }//end while System.out.println("End Japanese"); }//end while }//end try catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { try { if (reader2 != null) { reader2.close(); } } catch (IOException e) { e.printStackTrace(); } } //end training Japanese--------------------------------------------------------- } //end main (inner)

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  • How to calculate median of a Map<Int,Int>?

    - by Chris
    For a map where the key represents a number of a sequence and the value the count how often this number appeared in the squence, how would an implementation of an algorithm in java look like to calculate the median? For example: 1,1,2,2,2,2,3,3,3,4,5,6,6,6,7,7 in a map: Map<Int,Int> map = ... map.put(1,2) map.put(2,4) map.put(3,3) map.put(4,1) map.put(5,1) map.put(6,3) map.put(7,2) double median = calculateMedian(map); print(median); would result in: > print(median); 3 > So what i am looking for is a java implementation of calculateMedian.

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  • how could it works if function is called before it is defined in python?

    - by user2131316
    I was wondering what does if __name__ == "__main__": really do in python, I have the following code in python3: def main(): test(); def test(): print("hello world " + __name__); if __name__ == "__main__": main(); we know that we have to declare a function before we use it, so function call inside of if part works fine, the main() is defined before it is called inside of if statement, but what about the test() function, it is defined after it is called and there is no errors: def main(): test(); def test(): print("hello world " + __name__); so how could it works if the test() function is defined after it is called?

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  • Assistance with regular expressions in Python

    - by da5id
    I am still learning REGEX, and I've run into an issue ... I am trying to separate a string that is composed of a mixture of letters and numbers that are in decimal format: AB0.500CD1.05EF2.29 Into something like this: list1 = AB,CD,EF list2 = 0.500,1.05,2.29 A complication to all this is that I also have strings that look like this: AB1CD2EF3 Which I'd also like to separate into this: list1 = AB,CD,EF list2 = 1,2,3 A previous inquiry yielded the following snippet, import re pattern = re.compile(r'([a-zA-Z]+)([0-9]+)') for (letters, numbers) in re.findall(pattern,cmpnd): print numbers print letters This example works fine for strings of the 2nd kind, but only "finds" the leading digit in the numbers that contain decimal places in the strings of the first kind. I've attempted an approach using the following line: pattern = re.compile(r'([a-zA-Z]+)([0-9]+(\.[0-9]))') But this results in an error: "ValueError: too many values to unpack" Thanks for any and all assistance!

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  • How to test a regex password in Python?

    - by jCuga
    Using a regex in Python, how can I verify that a user's password is: At least 8 characters Must be restricted to, though does not specifically require any of: uppercase letters: A-Z lowercase letters: a-z numbers: 0-9 any of the special characters: @#$%^&+= Note, all the letter/number/special chars are optional. I only want to verify that the password is at least 8 chars in length and is restricted to a letter/number/special char. It's up to the user to pick a stronger / weaker password if they so choose. So far what I have is: import re pattern = "^.*(?=.{8,})(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%^&+=]).*$" password = raw_input("Enter string to test: ") result = re.findall(pattern, password) if (result): print "Valid password" else: print "Password not valid"

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  • Does template class/function specialization improves compilation/linker speed?

    - by Stormenet
    Suppose the following template class is heavily used in a project with mostly int as typename and linker speed is noticeably slower since the introduction of this class. template <typename T> class MyClass { void Print() { std::cout << m_tValue << std::endl;; } T m_tValue; } Will defining a class specialization benefit compilation speed? eg. void MyClass<int>::Print() { std::cout << m_tValue << std::endl; }

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  • im writing this code so the user would enter his/her name and followed by his/her marks to get the a

    - by WM
    What if the user wanted to enter his/her grades in the following way: Will 23, 34, 45, 45 how would i get rid of the commas public class StudentAverage { public static void main(String[] args) { int markSum = 0; double average = 0; Scanner input1 = new Scanner(System.in); System.out.print("Enter student record : "); String name = input1.next(); Scanner input2 = new Scanner(input1.nextLine()); int countTotal = 0; while (input2.hasNextInt()) { countTotal++; markSum += input2.nextInt(); } average = markSum / countTotal; // to calculate the total average System.out.print( name + " " + average ); } }

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  • How to Replace only Part of the Variable using #define

    - by mahesh
    #define C_TX_ TX_ #define C_RX_ RX_ enum Test { C_TX_MAC 0x0100, // Pre-Processor should replace C_TX_ to TX_ C_RX_MAC 0x0101 // But Not Working. }; int main(int argc, char *argv[]) { cout << TX_MAC; // HOW TO PRINT ? cout << RX_MAC; // HOW TO PRINT ? return true; } Please Help. Thanks in Advance

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  • set arraylist element as null

    - by Jessy
    The first index is set to null (empty), but it doesn't print the right output, why? //set the first index as null and the rest as "High" String a []= {null,"High","High","High","High","High"}; //add array to arraylist ArrayList<Object> choice = new ArrayList<Object>(Arrays.asList(a)); for(int i=0; i<choice.size(); i++){ if(i==0){ if(choice.get(0).equals(null)) System.out.println("I am empty"); //it doesn't print this output } }

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  • File::Find and $_ in nested subroutines.

    - by zedoo
    When running the following code, the filenames of all files below C:\Test are printed. Why doesn't it print just Hello (n times, depending on how many files are processed)? Does this imply that I cannot rely on shift to reliably assign to $_? Imagine a coworker implements the wtf function and doesn't know that it's called from a File::Find wanted sub. I run this code with Strawberry Perl 5.12 use strict; use warnings; use File::Find; find(\&wanted, "C:\\test"); sub wanted{ wtf("Hello"); } sub wtf { shift; print; #expecting Hello }

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  • SQL Server float datatype

    - by Martin Smith
    The documentation for SQL Server Float says Approximate-number data types for use with floating point numeric data. Floating point data is approximate; therefore, not all values in the data type range can be represented exactly. Which is what I expected it to say. If that is the case though why does the following return 'Yes' in SQL Server DECLARE @D float DECLARE @E float set @D = 0.1 set @E = 0.5 IF ((@D + @D + @D + @D +@D) = @E) BEGIN PRINT 'YES' END ELSE BEGIN PRINT 'NO' END but the equivalent C++ program returns "No"? #include <iostream> using namespace std; int main() { float d = 0.1F; float e = 0.5F; if((d+d+d+d+d) == e) { cout << "Yes"; } else { cout << "No"; } }

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