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  • Forwarding keypresses in GTK

    - by dguaraglia
    I'm writing a bit of code for a Gedit plugin. I'm using Python and the interface (obviously) is GTK. So, the issue I'm having is quite simple: I have a search box (a gtk.Entry) and right below I have a results box (a gtk.TreeView). Right after you type something in the search box you are presented a bunch of results, and I would like the user to be able to press the Up/Down keys to select one, Enter to choose it, and be done. Thing is, I can't seem to find a way to forward the Up/Down keypress to the TreeView. Currently I have this piece of code: def __onSearchKeyPress(self, widget, event): """ Forward up and down keys to the tree. """ if event.keyval in [gtk.keysyms.Up, gtk.keysyms.Down]: print "pressed up or down" e = gtk.gdk.Event(gtk.gdk.KEY_PRESS) e.keyval = event.keyval e.window = self.browser.window e.send_event = True self.browser.emit("key-press-event", e) return True I can clearly see I'm receiving the right kind of event, but the event I'm sending gets ignored by the TreeView. Any ideas? Thanks in advance people.

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  • Remote XP -> Win98 WMI Connection

    - by Logan Young
    I've asked this on Technet, but because Win98 is no longer supported, I can't get any decent information, I was hoping there might be some "old school" developers here who might be able to help me. There is an application that we use a lot at work. This application should run 8am-5pm with as little interruption as possible. Most of the computers where this application runs are using Win98, and we have no way to upgrade them because we can't buy new hardware at the moment. My computer is running WinXP, so I thought of a way to make sure that this application runs all the time: The idea I had was to develop a Windows Service that executes a VBScript file that contains a WMI query to get a list of processes from each computer. Each list is then examined, and, depending on whether or not the target application is running, it will either do nothing, or it will execute another VBScript file that contains a WMI query that will be used to start the target application remotely. I later found a way to do this all with 1 VBScript file (see code below) My problem is in the remote connection to the target computers. I've installed WMI Core 1.5 on them, but every time I try the remote connection, I get the following: The remote server is unavailable or does not exist: 'GetObject' VBScript runtime error 800A01CE I've done some research, and all I've found is info about DCOM Config and Windows Firewall, but Win98 doesn't have either of these. ' #### Variables and constants #### Const HIDDEN_WINDOW = 12 Dim T ' #### End Variables and constants #### Main() Sub Main() ' #### Get Process information from WMI Computer = "." Set WMI = GetObject("winmgmts:" & _ "{ImpersonationLevel=Impersonate}!\\" & Computer & "\root\cimv2") Set Settings = WMI.ExecQuery("SELECT * FROM Win32_Process") For Each Process In Settings ' #### If the application is found to be running, set a value to indicate this If Process.Name = "NOTEPAD.EXE" Then T = True End If Next ' #### T will only have a value if the application is not running. We therefore ' #### evaluate it to determine if it has a value or not. If not, start the application If Not T Then 'MsgBox("Application not found.") Set Startup = WMI.Get("Win32_ProcessStartup") Set Config = Startup.SpawnInstance_ Config.ShowWindow = HIDDEN_WINDOW Set Process = GetObject("winmgmts:root\cimv2:Win32_Process") errReturn = Process.Create(_ "C:\Windows\notepad.exe", null, Config, intProcessID) End If End Sub This uses WMI to get the list of processes from the local computer and, if the target application is running, it'll do nothing, otherwise it'll forcefully start the target application. The problem is that this works only if I specify the local comuter, if I target another computer, I get the error mentioned above. Does anyone have any ideas? Thanks in advance for the help!

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  • iPhone app not running on iPhone

    - by Jon
    I have my iPhone setup on my computer at home, with my developer account and provisioning profile. I'm trying to get it setup on my work computer so I can run work apps on it as well. My work has their own dev account. I created an app ID and privisioning profile on my personal account and downloaded it on my work computer but its not letting me compile and run on my iPhone. It says valid provisiong profile not found on executable.

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  • Please summarize how to implement node base licensing

    - by user294896
    Currently a user makes a purchase and then a license is generated and sent to that user, but the license isn't tied to a physical computer so there is nothing to prevent the user sharing the license with someone. I heard people talk about creating a license tied to the mac address of the computer, so the license only works on that computer. Now I know how to get the mac address in code but I dont understand how I can do this step when they first make the purchase on the web, so please what is the basic algorithm for node locked licenses ?

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  • Cannot connect to Github?

    - by user2973438
    so I tried to push some updates onto my repo on github via terminal on Mac OSX 10.8.4 and it doesn't work. I've been getting the same error many times: Lillys-MacBook-Air:Yuewei Lilly$ git push origin master error: Failed connect to github.com:443; Operation timed out while accessing https://github.com/lillybeans/Yuewei.git/info/refs?service=git-receive-pack fatal: HTTP request failed Some background: I've pushed many projects onto github before using terminal (when I was in Canada). I am currently in Shanghai, China, could it be the GFW? But when I was in Beijing, I was able to push projects onto github still. when I do ping github.com: Lillys-MacBook-Air:Yuewei Lilly$ ping github.com PING github.com (192.30.252.131): 56 data bytes Request timeout for icmp_seq 0 Request timeout for icmp_seq 1 ping: sendto: No route to host Request timeout for icmp_seq 2 ping: sendto: Host is down Request timeout for icmp_seq 3 ping: sendto: Host is down Request timeout for icmp_seq 4 ping: sendto: Host is down Request timeout for icmp_seq 5 ping: sendto: Host is down Request timeout for icmp_seq 6 ping: sendto: Host is down Request timeout for icmp_seq 7 ^C --- github.com ping statistics --- 9 packets transmitted, 0 packets received, 100.0% packet loss Lillys-MacBook-Air:Yuewei Lilly$ I have ShadowSocks (proxy) turned on. Without it I can't access github.com via browser, with it, I can. also when I do "git remote -v" I see both my pull and push remote repos correctly listed. Thank you in advance!

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  • Repeat over files in a File > Open dialog with Applescript

    - by GotNoSugarBaby
    In the below script I use an Application other than Finder to launch an "Open" browser and perform a search in it. I've got the window into the state I want, but whatever I try can't access the list of files to repeat over. If anyone can help by adding the code to repeat over that file list and log out the file path of each file it'd be a huge help. Thanks a lot. tell application "Preview" -- start the app activate -- let it boot up delay 3 -- ensure it still has focus activate end tell tell application "System Events" tell process "Preview" -- spawn "Open" window keystroke "o" using {command down} delay 0.5 -- spawn "Go to" window keystroke "g" using {command down, shift down} delay 0.5 -- expand scope of search to all of this mac keystroke "/" keystroke return delay 0.5 -- spawn search field keystroke "f" using {command down} delay 0.5 -- perform search keystroke ".jpg OR .jpeg" keystroke return end tell end tell

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  • Capturing network traffic on Linux

    - by Quandary
    Question: I have one Windows laptop, one Linux laptop and a wireless router. Now I want to "investigate" the hotmail/windows live protocol. What I want to do is route network traffic from the windows laptop via ethernet to the linux laptop, capture it on the Linux computer, forward it wirelessly to the router, receive the hotmail response from the router on the linux computer and forward it to the windows computer. How do I do that? In essence, switching the Linux laptop between the Windows laptop and the router, to capture network traffic ? Which program is best for capturing/analysing ? Please note that for whatever reason, packet capturing with winpcap on the windows computer doesn't work...

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  • JSON onFailure issue

    - by Mikey1980
    I’m having trouble getting a AJAX/JSON function to work correctly. I had this function grabbing value from a drop down box but now I want to use an anchor tag to set it's value. I thought it would be easy to just use the onClick event to pass string to the function I was using for the drop down box but I get the alert in JSON onFailure event even though data gets added to MySQL. I tried removing the alert from onFailure event but then it doesn't add the data. The drop down still continues work work fine, no alerts. (I should note that removing the alert also broke my drop down box) 1st I add an onClick event… <a href="<?php echo Settings::get('app.webroot'); ?>?view=schedule&action=questions" onmouseout="MM_swapImgRestore();" onmouseover="MM_swapImage('bre','','template/images/schedule/bre_f2.gif',1)" onclick="assignCallType('testing')";> 2nd I check main.js.php function assignCallType(type) { alert(type); new Request.JSON({ url: "ajax.php", onSuccess: function(rtndata,txt){ if (rtndata['STATUS'] != 'OK') alert('Status was not okay'); }, onFailure : function () { alert("onFailure") } }).get({ 'action': 'assignCallType', 'call_type': type }); } 3rd Ajax.php: the variable is back in PHP and values get added to MySQL but I get the Alert in the JSON onFailure event if ($_GET['action'] == "assignCallType") { if ($USER->isInsideSales()) { $call_type = $_GET['call_type']; $_SESSION['callinfo']->setCallType($call_type); $_SESSION['callinfo']->save($callid); echo json_encode(array('STATUS'=>'OK')); } else { echo json_encode(array('STATUS'=>'DENIED')); } } Any idea where I am going wrong. The only difference between this and the working drop down is how the function was called, I used onchange="assignCallType(this.value)".

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  • How to make a single line systabcontrol32 that scrolls but doesn't show a scrollbar

    - by TheNewbie
    Hi I'm creating a systabcontrol32 control with the TCS_SINGLELINE style when I resize my window so the tab won't fit an up-down control appears that should allow me to scroll so I can see all the tabs. The thing is that the up-down buttons don't seem to work unless I add a the WS_HSCROLL property to the tab control witch makes it ugly as hell. It could be cool if the up-down could scroll the tabs without need to add the scrollbar (even more since the scroll bar doesn't seem to work, it just sits there and I can't click it).

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  • Synchronizing time between two Windows 7 machines connected with a LAN cable

    - by Markus Roth
    I have a number laptops that run our application while connected to each other in pairs with an ethernet cable, but not connected to any external network or the internet. T I need the connected pair to synchronize their system times, but since every computer needs to be able to synch with any other computer, I can't define one computer to be a time-server and the other to be a client. Is there a way to do this with NTP? Or some other way?

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  • Attribute Address getting displayed instead of Attribute Value

    - by Manish
    I am try to create the following. I want to have one drop down menu. Depending on the option selected in the first drop down menu, options in second drop down menu will be displayed. The options in 2nd drop down menu is supposed by dynamic, i.e., options change with the change of values in first menu. Here, instead of getting the drop down menus, I am getting the following Choose your Option1: Choose your Option2: Note: I strictly don't want to use javascript. home_form.py class HomeForm(forms.Form): def __init__(self, *args, **kwargs): var_filter_con = kwargs.pop('filter_con', None) super(HomeForm, self).__init__(*args, **kwargs) if var_filter_con == '***': var_empty_label = None else: var_empty_label = ' ' self.option2 = forms.ModelChoiceField(queryset = db_option2.objects.filter(option1_id = var_filter_con).order_by("name"), empty_label = var_empty_label, widget = forms.Select(attrs={"onChange":'this.form.submit();'}) ) self.option1 = forms.ModelChoiceField(queryset = db_option1.objects.all().order_by("name"), empty_label=None, widget=forms.Select(attrs={"onChange":'this.form.submit();'}) ) view.py def option_view(request): if request.method == 'POST': form = HomeForm(request.POST) if form.is_valid(): cd = form.cleaned_data if cd.has_key('option1'): f = HomeForm(filter_con = cd.get('option1')) return render_to_response('homepage.html', {'home_form':f,}, context_instance=RequestContext(request)) return render_to_response('invalid_data.html', {'form':form,}, context_instance=RequestContext(request)) else: f = HomeForm(filter_con = '***') return render_to_response('homepage.html', {'home_form':f,}, context_instance=RequestContext(request)) homepage.html <!DOCTYPE HTML> <head> <title>Nivaaran</title> </head> <body> <form method="post" name = 'choose_opt' action=""> {% csrf_token %} Choose your Option1: {{ home_form.option1 }} <br/> Choose your Option2: {{ home_form.option2 }} </form> </body>

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  • Using a dropdown on a static webpage as a DataSource in C#.net

    - by Matt
    I know this is a terrible way of doing things, but it's for an internal app where security is no issue. Basically, an old group created a php page with a drop down and this drop down is populated with entries from a DB. The DB owner is currently absent and for the sake of time, I would just need something that turns the entries in that drop down, always at the same url with the same ID every load into a List. Is there a quick, painless way to do this in .NET?

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  • get-wmiobject sql join in powershell - trying to find physical memory vs. virtual memory of remote s

    - by Willy
    get-wmiobject -query "Select TotalPhysicalMemory from Win32_LogicalMemoryConfiguration" -computer COMPUTERNAME output.csv get-wmiobject -query "Select TotalPageFileSpace from Win32_LogicalMemoryConfiguration" -computer COMPUTERNAME output.csv I am trying to complete this script with an output as such: Computer Physical Memory Virtual Memory server1 4096mb 8000mb server2 2048mb 4000mb

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  • Jquery animate negative top and back to 0 - starts messing up after 3rd click

    - by Daniel Takyi
    The site in question is this one: http://www.pickmixmagazine.com/wordpress/ When you click on one of the posts (any of the boxes) an iframe will slide down from the top with the content in it. Once the "Home" button in the top left hand corner of the iframe is clicked, the iframe slides back up. This works perfectly the first 2 times, on the 3rd click on of a post, the content will slide down, but when the home button is clicked, the content slides back up normally but once it has slid all the way up to the position it should be in, the iframe drops straight back down to where it was before the home button was clicked, I click it again and then it works. Here is the code I've used for both sliding up and sliding down functions: /* slide down function */ var $div = $('iframe.primary'); var height = $div.height(); var width = parseInt($div.width()); $div.css({ height : height }); $div.css('top', -($div.width())); $('.post').click(function () { $('iframe.primary').load(function(){ $div.animate({ top: 0 }, { duration: 1000 }); }) return false; }); /* slide Up function */ var elm = parent.document.getElementsByTagName('iframe')[0]; var jelm = $(elm);//convert to jQuery Element var htmlElm = jelm[0];//convert to HTML Element $('.homebtn').click(function(){ $(elm).animate({ top: -height }, { duration: 1000 }); return false; })

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  • How to I get raw 'mouse' events with touch screens on Windows Vista/7?

    - by Emil
    Does anyone have a clue how to completely disable the touch/tablet 'magic' introduced in Windows Vista? When I follow the steps on http://msdn.microsoft.com/en-us/library/bb969148(VS.85).aspx (both SetProp disable and WM_TABLET_QUERYSYSTEMGESTURESTATUS override) I succeed in stopping windows from treating press-and-hold as a right-click (it correctly gives me a WM_LBUTTONDOWN), but it also gives me a premature WM_LBUTTONUP (before I really let go of the screen). And there is also another problem: a click followed by a drag (down, up, down, move) is treated as a double-click (down, up, down, up, move). These issues occur with two very different touch screens (so it is not a hardware problem), and it never used to happen with Windows XP. This really bugs me. I would much rather have the raw input events like you have for normal mouse clicks. Any ideas?

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  • Tree iterator, can you optimize this any further?

    - by Ron
    As a follow up to my original question about a small piece of this code I decided to ask a follow up to see if you can do better then what we came up with so far. The code below iterates over a binary tree (left/right = child/next ). I do believe there is room for one less conditional in here (the down boolean). The fastest answer wins! The cnt statement can be multiple statements so lets make sure this appears only once The child() and next() member functions are about 30x as slow as the hasChild() and hasNext() operations. Keep it iterative <-- dropped this requirement as the recursive solution presented was faster. This is C++ code visit order of the nodes must stay as they are in the example below. ( hit parents first then the children then the 'next' nodes). BaseNodePtr is a boost::shared_ptr as thus assignments are slow, avoid any temporary BaseNodePtr variables. Currently this code takes 5897ms to visit 62200000 nodes in a test tree, calling this function 200,000 times. void processTree (BaseNodePtr current, unsigned int & cnt ) { bool down = true; while ( true ) { if ( down ) { while (true) { cnt++; // this can/will be multiple statesments if (!current->hasChild()) break; current = current->child(); } } if ( current->hasNext() ) { down = true; current = current->next(); } else { down = false; current = current->parent(); if (!current) return; // done. } } }

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  • How does Software/Code actually communicate with Harware?

    - by AbyJames
    My question is: When I press the "Shut down" button in Windows/Linux,the computer shutdowns.How did the command "Shut down" actually make the computer Physically shutdown? To make my point clear: When we kick a ball,there is physical contact between the ball and our leg,for the ball to move.So how is the physical connection achieved between softwares and hardwares?How does plain text of codes make the computer do what it does? (Noob question,I know but it has been irritating me for quite sometime now) -Aby

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  • clearTimeout not working as expected

    - by user543314
    Javascript sliding menu stay open. clearTimeout not working as expected -can you help me please <html> <head> <style> #Menu1 {position:absolute; top:-190px; left:150px; font-size:15px;visibility:visible; background-color:#D0BCFE; width:114px;z-index:0;border-style:solid; } #Menu2 {position:absolute; top:-190px; left:580px; font-size:15px;visibility:visible; background-color:#D0BCFE; width:114px;z-index:0;border-style:solid; } #Menu3 {position:absolute; top:-190px; left:1005px; font-size:15px;visibility:visible; background-color:#D0BCFE; width:114px;z-index:0;border-style:solid; } TD.TDHREFMENUS{font-size:20;color:red;position:relative;z-index:0;background-color:#C4ABFE;border-style:solid;width:114px;} </style> <script> var stopUp=null; var stopDown=null; var mov=-143; var on; function down(id){ if (!on){ on=true; clearTimeout(stopUp) stopUp=null; } var obj=document.getElementById(id) obj.style.top=mov +"px"; if (mov <=27){ mov+=2; stopDown=setTimeout(function (){ down(id) }, 20) } } function up(id){ if (on){ on=false; clearTimeout(stopDown) stopDown=null; } var obj=document.getElementById(id) obj.style.top=mov +"px"; if (mov >=-143){ mov-=2; stopUp=setTimeout(function(){ up(id)}, 20); } } </script> </head> <body leftmargin=0 marginwidth=0 topmargin=0 marginheight=0> <div id="Menu1" onmouseover="down('Menu1')" onmouseout="up('Menu1')"> URL 1<br> URL 2<br> URL 3<br> URL 4<br> URL 5<br> URL 6<br> URL 7<br> URL 8<br> </div> </div> <div id="Menu2" onmouseover="down('Menu2')" onmouseout="up('Menu2')"> URL 1<br> URL 2<br> URL 3<br> URL 4<br> URL 5<br> URL 6<br> URL 7<br> URL 8<br> </div> </div> <div id="Menu3" onmouseover="down('Menu3')" onmouseout="up('Menu3')"> URL 1<br> URL 2<br> URL 3<br> URL 4<br> URL 5<br> URL 6<br> URL 7<br> URL 8<br> </div> </div> <TABLE cellSpacing=0 cellPadding=0 BORDER=1 WIDTH=100%> <TBODY> <TR> <TD align=middle CLASS="TDHREFMENUS"><span onmouseover="down('Menu1')" onmouseout="up('Menu1')">MENU 1</span> </TD> <TD align=middle CLASS="TDHREFMENUS"><span onmouseover="down('Menu2')" onmouseout="up('Menu2')">MENU 2</span> </TD> <TD align=middle CLASS="TDHREFMENUS"><span onmouseover="down('Menu3')" onmouseout="up('Menu3')">MENU 3</span> </TD> </TR> </TBODY> </TABLE> <br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br> <html> <head>

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  • Help with running crontab from root

    - by user242065
    Im using OSX and having trouble getting a cron job to run. I type the following: $ sudo -i $ crontab -e I then enter: * * * * * root ifconfig en0 down > /dev/null 0 19 * * * root ifconfig en0 down > /dev/null 0 7 * * * root ifconfig en0 up > /dev/null and no success, the first line is for testing. I want it to shut off my internet. The next two lines I plan to leave in, once I get this working. If I type this in to the terminal the internet goes off ifconfig en0 down Why is my cron job not shutting down the internet? FYI: This is a follow up question from http://stackoverflow.com/questions/3027362/how-can-i-write-a-cron-job-that-will-block-my-internet-from-7pm-to-7am-so-i-can most of the comments there are people making fun of me. And a few attempts to solve the problem with out cron jobs.

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  • Solve a maze using multicores?

    - by acidzombie24
    This question is messy, i dont need a working solution, i need some psuedo code. How would i solve this maze? This is a homework question. I have to get from point green to red. At every fork i need to 'spawn a thread' and go that direction. I need to figure out how to get to red but i am unsure how to avoid paths i already have taken (finishing with any path is ok, i am just not allowed to go in circles). Heres an example of my problem, i start by moving down and i see a fork so one goes right and one goes down (or this thread can take it, it doesnt matter). Now lets ignore the rest of the forks and say the one going right hits the wall, goes down, hits the wall and goes left, then goes up. The other thread goes down, hits the wall then goes all the way right. The bottom path has been taken twice, by starting at different sides. How do i mark this path has been taken? Do i need a lock? Is this the only way? Is there a lockless solution? Implementation wise i was thinking i could have the maze something like this. I dont like the solution because there is a LOT of locking (assuming i lock before each read and write of the haveTraverse member). I dont need to use the MazeSegment class below, i just wrote it up as an example. I am allowed to construct the maze however i want. I was thinking maybe the solution requires no connecting paths and thats hassling me. Maybe i could split the map up instead of using the format below (which is easy to read and understand). But if i knew how to split it up i would know how to walk it thus the problem. How do i walk this maze efficiently? The only hint i receive was dont try to conserve memory by reusing it, make copies. However that was related to a problem with ordering a list and i dont think the hint was a hint for this. class MazeSegment { enum Direction { up, down, left, right} List<Pair<Direction, MazeSegment*>> ConnectingPaths; int line_length; bool haveTraverse; } MazeSegment root; class MazeSegment { enum Direction { up, down, left, right} List<Pair<Direction, MazeSegment*>> ConnectingPaths; bool haveTraverse; } void WalkPath(MazeSegment segment) { if(segment.haveTraverse) return; segment.haveTraverse = true; foreach(var v in segment) { if(v.haveTraverse == false) spawn_thread(v); } } WalkPath(root);

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  • How can I call an executable to run on a separate machine within a program on my own machine (win xp

    - by Mr. H.
    My objective is to write a program which will call another executable on a separate computer(all with win xp) with parameters determined at run-time, then repeat for several more computers, and then collect the results. In short, I'm working on a grid-computing project. The algorithm itself being used is already coded in FORTRAN, but we are looking for an efficient way to run it on many computers at once. I suppose one way to accomplish this would be to upload a script to each computer and then run said script on each computer, all automatically and dependent on my own parameters. But how can I write a program which will write to, upload, and run a script on a separate computer? I had considered GridGain, but the algorithm is already coded and in a different language, so that is ruled out. My current guess at accomplishing this task is using Expect (wiki/Expect), but I have no knowledge of the tool. Any advice appreciated.

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  • Creating New Object of Other Class dynamicly ?

    - by Meko
    I am trying to create new object of other class in a for loop. like for(int i =0;i<10;i++){ Computer p1=new Computer(10,20); } and when I try anywhere to reach p1.someAction(); it say you must declare p1. But if I declare it on top of program how can I create again in loop? I also try only Computer p1; but it gave exeption ..

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  • How to make a transition in flex 4 on a fill that contains a linear gradient?

    - by Totty
    <?xml version="1.0" encoding="utf-8"?> <s:Rect id="background" top="0" right="0" bottom="0" left="0" height="30"> <s:fill> <s:SolidColor color="#000000"/> </s:fill> <s:fill.over> <s:LinearGradient rotation="90"> <s:GradientEntry color="#FF5800" alpha="1.0" ratio="0"/> <s:GradientEntry color="#EE0202" alpha="1.0" ratio="1"/> </s:LinearGradient> </s:fill.over> <s:fill.down> <s:LinearGradient rotation="90"> <s:GradientEntry color="#EE0202" alpha="1.0" ratio="0"/> <s:GradientEntry color="#AF0000" alpha="1.0" ratio="1"/> </s:LinearGradient> </s:fill.down> </s:Rect> <s:RichText id="labelDisplay" paddingLeft="10" paddingRight="10" textAlign="center" fontFamily="Myriad Pro" fontSize="16" tabStops="S0 S50 S100 S150" color="#FFFFFF" y="8" color.over="#000000" tabStops.over="S0 S50 S100 S150" color.down="#000000" tabStops.down="S0 S50 S100 S150" color.disabled="#EE0202" tabStops.disabled="S0 S50 S100 S150" color.up="#EE0202" tabStops.up="S0 S50 S100 S150"> <s:filters> <s:DropShadowFilter includeIn="over" blurX="0" blurY="0" distance="1" hideObject="false" inner="false" color="#FFFFFF" strength="1" alpha="1" quality="2" knockout="false" angle="45.0"/> <s:DropShadowFilter includeIn="down" blurX="0" blurY="0" distance="1" hideObject="false" inner="false" color="#CCCCCC" strength="1" alpha="1" quality="2" knockout="false" angle="45.0"/> <s:BlurFilter includeIn="disabled" blurX="4.0" blurY="4.0" quality="2"/> </s:filters> </s:RichText> here is the code, I would like to make a smooth transition when enters the "over" state. any help?

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