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  • ASP.NET MVC Deployed Application Server Address

    - by Jacob Huggart
    I have an application that sends an email to a user so that they may access a web form. In the email there is just a link to the start page of this form. Currently, I have the value for the form location hardcoded. Once the app is deployed I know it is in inetpub/wwwroot/appName, which results in a URL of serverip:appPort/appName. What is the C# to get the serverip:appPort portion of the URL that I need? I think that server.mappath() might work, but for some reason I can't get to the method even though I have the necessary references.

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  • Show only one validation error-message using replaceWith

    - by timkl
    I am currently working with the jQuery validation plugin, and I want to show only one error-message before the form itself. Right now the validation shows all the error-messages on top of each others as they stack up, as you can see in my live example: http://timkjaerlange.com/foobar/stack-stuff/validate-test.html This is my jQuery: $(document).ready(function() { $("form").validate({ rules: { // bunch of rules here, left out to keep it simple }, messages: { // messages goes here }, errorElement: 'div', errorClass: 'error', errorPlacement: function(error, element) { error.insertBefore('form'); // this is what I've got $('div').replaceWith(error); // trying to replace the prev error } }); }); Anybody know how to this? Is this the best way to show only one error-message? Any help is highly appreciated.

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  • How to retrieve the value from Select html element using JS prototype in php?

    - by user309381
    <script type="text/javascript" src="prototype.js"></script> <script> function reload(form){ var val = $("seltab");alert(val); }</script> echo "<form method = post name = f1 action = '' >"; echo "<select id = seltab onchange = 'reload(this.form)'>"; $querysel = "SELECT title_id,author FROM authors NATURAL JOIN books"; $result1 = mysql_query($querysel) ; while($rowID = mysql_fetch_assoc($result1)) { $TitleID = $rowID['title_id']; $author = $rowID['author']; print "<option value =$TitleID>$author\n"; print "</option>"; } print "</select>";

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  • Re-binding an ajaxForm after content re-loads with ajax (jQuery 1.4.2)

    - by Cristian
    I'm trying to figure out why this is a problem when using jQuery 1.4.2 and not 1.3.2. This is my function: function prepare_logo_upload() { $("#logo-upload-form").ajaxForm({ //alert(responseText); success: function(responseText) { //alert(responseText); $('#profile .wrapper').html(responseText); prepare_logo_upload(); } }); } Every other live event works but can't use the .live() method because ajaxForm is a plugin. I have noticed this also for other types of binding (clicks) using the old form (re-binding after callback) Can you tell me if it is a way of solving this? This is a similar question, but due to my newbie reputation here, can't comment or ask a question there, so I'll ask a new one here. - http://stackoverflow.com/questions/2208880/jquery-bind-ajaxform-to-a-form-on-a-page-loaded-via-load Thank you!

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  • How JQuery data validation plugin works on the submit action

    - by kwokwai
    Hi all, I am learning how to use JQuery validation plugin, and came across some questions about the JQuery magic that works on the sumbit action. I got a simple HTML form which has got an input text field like this: <form class="cmxform" id="commentForm" method="get" action=""> <input id="cname" name="name" size="25" class="required" minlength="2" /> <input class="submit" type="submit" value="Submit"/> </form> The magic happened when I tried not to input any data into the field and pressed the submit button. I saw an error message in red pop up, and no matter how hard and how many times I pressed the submit button, nothing was submitted. It seemed that there was some scripts that disabled the submit action, but I just couldn't find which lines of codes in the JQuery Validatyion Plugin that did it.

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  • Extending existing Class in Symfony

    - by Dar Hamid
    I am new to symfony. I have created a registration form using the code: $user = new Register(); $form = $this->createForm(new RegisterType(), $user); In the RegisterType class i have 5 fields (for example).I store the values in database when the user registers with the system. Now I display the EDIT page using following code: $user = $em->getRepository('MysiteUserBundle:Register')->find($id); $form = $this->createForm(new RegisterType(), $user); The problem with the EDIT code however is that it displays me all of the fields mentioned in RegisterType class.Is it possible to display only some fields. If yes how can this be achieved. Any help will be appreciated

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  • How does struts 1.X ActionForm handle pure html checkbox list?

    - by BlueDolphin
    I am dealing with an old application which uses struts 1.2. And for some reason, we are using pure html form to submit to struts action. For example: for the content output of testAction.do, I try to submit to itself. item 1 item 2 Then I associate an form bean TestForm with testAction. I am not sure how to specify the properties in the form so that it take the value from myitem1 after user click "submit" I tried to add getMyitem1(), setMyitem1(String[] items), getSelectedMyitem1(), setSelectedMyitem1(String[] items) Those set methods are only called when page are loaded. I guess my understanding of ActionForm in struts 1.x must be wrong. Please advise, thanks.

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  • Problem Paging with Post Action in ASP.NET MVC

    - by Lukasz
    I have a page that takes a number of parameters on a form and posts them to an action. It returns a number of search results that need to be paged through. My pager uses ActionLink; <%= Html.ActionLink(i.ToString(), "Basic", new { page = (i - 1) })%> The results comeback as expected but when I click on page two it goes to the default Action, not the one marked with post. The form values do no get submitted again and the results that are shown for page two are the default results not filters with the parameters. I am not sure how to solve this problem? One way was to save the form values into the database on the post and reading them back on the default action but it seems overkill. Thank You!

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  • How to track different button clicks with Google Analytics and AJAX?

    - by citronas
    I have several pages, let's call them A, B and C. Each of these pages has a form where the user can type in some information and click a button to send those information to the server. This button click is performed in an UpdatePanel to prevent a full postback. A customer of ours now wants to know how many % of the using visiting each site (A, B and C have different URLs) use this form. (Meaning I need seperate values for A, B and C) How to I track this in Google Analytics? It seems that I have to create a conversion(??) for each page. Is that correct? How must I modify the existing web application to let Google Analytics know, that a user submitted the form. (without the need to redirect thank to xy amount of different thank you pages) The only piece of information I've found so far is this: http://www.google.com/support/googleanalytics/bin/answer.py?hl=en&answer=55519 Unfortunately, this FAQ entry does not cover my answer.

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  • jQuery not refreshing tabs content in IE

    - by iddimu
    Hi all! I have a page that is using jQuery tabs. Within one of my tabs I have a div that contains a form (initially hidden) that I want to use to add content to the tab. What I have works perfectly in Chrome, Firefox, and Safari. But, in IE 7 the tab will not refresh. The post works and the data gets added to the database, but it simply will not show the new content after submitting it. I don't think it matters - but, just for information I am using the Codeigniter PHP framework as well. Here is my javascript: <script type="text/javascript"> $(document).ready(function(){ // initialize the addChild form as hidden until user requests it open $('#addChild').hide(); // open the form $('#openDialog').click( function(){ $('#addChild').slideToggle(); return false; }); // close the form $('#closeDialog').click( function(){ $('#addChild').slideToggle(); return false; }); // submit the form $('#frmAddChild').submit( function(){ $('#addChild').slideToggle(); $.ajax({ url: '/children/add', type: 'POST', data: $('#frmAddChild').serialize() //cache: false }); //reload the children tab $('#tabs').tabs('load',3); return false; }); }); </script> And, here is my PHP/HTML: <?php // initialize the elements of the form $frmAddChild = array( 'name' => 'frmAddChild', 'id' => 'frmAddChild', 'method' => 'post' ); $child_name = array( 'name' => 'child_name', 'id' => 'child_name', ); $child_dob = array( 'name' => 'child_dob', 'id' => 'child_dob' ); $btnOpenDialog = array( 'name' => 'openDialog', 'id' => 'openDialog', 'value' => 'true', 'content' => 'Add Child' ); $btnCloseDialog = array( 'name' => 'closeDialog', 'id' => 'closeDialog', 'value' => 'true', 'content' => 'Cancel' ); // button that shows the drop down to add echo form_button($btnOpenDialog); ?> <div id="addChild" title="Add Child"> <?php echo form_open('children/add/',$frmAddChild); ?> <table> <tr> <td> <?php echo form_label('Child\'s Name', 'child_name'); ?>: </td> <td> <?php echo form_input($child_name); ?> </td> </tr> <tr> <td> <?php echo form_label('Date of Birth','child_dob'); ?>: </td> <td> <?php echo form_input($child_dob); ?> </td> </tr> <tr> <td colspan="2" align="right"> <?php echo form_submit('submit', 'Add'); ?> <?php echo form_button($btnCloseDialog); ?> </td> </tr> </table> <?php echo form_close(); ?> </div> Does anyone have any ideas how I can get this working correctly in IE? Also, if anyone has any comments about how I have things structured, please let me know. I'm new to Codeigniter and I am by no means a javascript or jQuery expert. Thanks for your help!

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  • Input not firing in jsp page

    - by GigaPr
    Hi, i have been using the spring mvc frameworks lately for a university project. Could you tell me why this work <FORM METHOD=POST ACTION="SaveName.jsp"> <input type="image" class="floatR marginTMinus10" src="images/delete.png" name="image" value="${rssItem.id}" alt="Delete"/> </FORM> while this not <input type="image" class="floatR marginTMinus10" src="images/delete.png" name="image" value="${rssItem.id}" alt="Delete"/> does it mean a button has to be in a form to work? Can i use a button? if yes how do i handle the event in the controller? thanks

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  • PHP, MySQL, jQuery, AJAX: json data returns correct response but frontend returns error

    - by Devner
    Hi all, I have a user registration form. I am doing server side validation on the fly via AJAX. The quick summary of my problem is that upon validating 2 fields, I get error for the second field validation. If I comment first field, then the 2nd field does not show any error. It has this weird behavior. More details below: The HTML, JS and Php code are below: HTML FORM: <form id="SignupForm" action=""> <fieldset> <legend>Free Signup</legend> <label for="username">Username</label> <input name="username" type="text" id="username" /><span id="status_username"></span><br /> <label for="email">Email</label> <input name="email" type="text" id="email" /><span id="status_email"></span><br /> <label for="confirm_email">Confirm Email</label> <input name="confirm_email" type="text" id="confirm_email" /><span id="status_confirm_email"></span><br /> </fieldset> <p> <input id="sbt" type="button" value="Submit form" /> </p> </form> JS: <script type="text/javascript"> $(document).ready(function() { $("#email").blur(function() { var email = $("#email").val(); var msgbox2 = $("#status_email"); if(email.length > 3) { $.ajax({ type: 'POST', url: 'check_ajax2.php', data: "email="+ email, dataType: 'json', cache: false, success: function(data) { if(data.success == 'y') { alert('Available'); } else { alert('Not Available'); } } }); } return false; }); $("#confirm_email").blur(function() { var confirm_email = $("#confirm_email").val(); var email = $("#email").val(); var msgbox3 = $("#status_confirm_email"); if(confirm_email.length > 3) { $.ajax({ type: 'POST', url: 'check_ajax2.php', data: 'confirm_email='+ confirm_email + '&email=' + email, dataType: 'json', cache: false, success: function(data) { if(data.success == 'y') { alert('Available'); } else { alert('Not Available'); } } , error: function (data) { alert('Some error'); } }); } return false; }); }); </script> PHP code: <?php //check_ajax2.php if(isset($_POST['email'])) { $email = $_POST['email']; $res = mysql_query("SELECT uid FROM members WHERE email = '$email' "); $i_exists = mysql_num_rows($res); if( 0 == $i_exists ) { $success = 'y'; $msg_email = 'Email available'; } else { $success = 'n'; $msg_email = 'Email is already in use.</font>'; } print json_encode(array('success' => $success, 'msg_email' => $msg_email)); } if(isset($_POST['confirm_email'])) { $confirm_email = $_POST['confirm_email']; $email = ( isset($_POST['email']) && trim($_POST['email']) != '' ? $_POST['email'] : '' ); $res = mysql_query("SELECT uid FROM members WHERE email = '$confirm_email' "); $i_exists = mysql_num_rows($res); if( 0 == $i_exists ) { if( isset($email) && isset($confirm_email) && $email == $confirm_email ) { $success = 'y'; $msg_confirm_email = 'Email available and match'; } else { $success = 'n'; $msg_confirm_email = 'Email and Confirm Email do NOT match.'; } } else { $success = 'n'; $msg_confirm_email = 'Email already exists.'; } print json_encode(array('success' => $success, 'msg_confirm_email' => $msg_confirm_email)); } ?> THE PROBLEM: As long as I am validating the $_POST['email'] as well as $_POST['confirm_email'] in the check_ajax2.php file, the validation for confirm_email field always returns an error. With my limited knowledge of Firebug, however, I did find out that the following were the responses when I entered email and confirm_email in the fields: RESPONSE 1: {"success":"y","msg_email":"Email available"} RESPONSE 2: {"success":"y","msg_email":"Email available"}{"success":"n","msg_confirm_email":"Email and Confirm Email do NOT match."} Although the RESPONSE 2 shows that we are receiving the correct message via msg_confirm_email, in the front end, the alert 'Some error' is popping up (I have enabled the alert for debugging). I have spent 48 hours trying to change every part of the code wherever possible, but with only little success. What is weird about this is that if I comment the validation for $_POST['email'] field completely, then the validation for $_POST['confirm_email'] field is displaying correctly without any errors. If I enable it back, it is validating email field correctly, but when it reaches the point of validating confirm_email field, it is again showing me the error. I have also tried renaming success variable in check_ajax2.php page to other different names for both $_POST['email'] and $_POST['confirm_email'] but no success. I will be adding more fields in the form and validating within the check_ajax2.php page. So I am not planning on using different ajax pages for validating each of those fields (and I don't think it's smart to do it that way). I am not a jquery or AJAX guru, so all help in resolving this issue is highly appreciated. Thank you in advance.

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  • App-Engine (Java) File Upload

    - by Manjoor
    I managged to upload files on app-engine by using the following example http://stackoverflow.com/questions/1513603/how-to-upload-and-store-an-image-with-google-app-engine-java and http://www.mail-archive.com/[email protected]/msg08090.html The problem is, I am sumitting other fields along with file field as listed below <form action="index.jsp" method="post" enctype="multipart/form-data"> <input name="name" type="text" value=""> <br/> <input name="imageField" type="file" size="30"> <br/> <input name="Submit" type="submit" value="Sumbit"> </form> In my servlet I am getting null when querying name = request.getParameter("name"); Why it is so? Is there a way to retrieve text field value?

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  • jQuery if checkbox is checked to toggle classes

    - by Lynx
    I am needed to change my jQuery code up. Instead of the label toggling the class and showing the icon I need it to where if the checkbox is checked to show to toggle those classes. I have tried prop and is but I couldn't get them to work properly. The reason for the change is I want to preload data into the form and if it's going to be checked those toggles need to reflect that change. http://jsfiddle.net/70fbLooL/2/ EDIT Seems to be confusion as to exactly what I am trying to do. The fiddle I provided works perfectly fine. The problem is if I want to call the form from server-side and pre-populate the form the checkbox toggles will not show that they are checked because it's based on the clicked function. I need it to be based on if the checkbox equal true or checked. That way if the value equals true from the server-side call it will toggle those classes and look like it's checked.

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  • What causes my borderless C++ app to crash when overriding WndProc?

    - by Ste
    I use a form with border NONE. I need to override WndProc for resize and move form. However, using this code, my app crashes! static const int WM_NCHITTEST = 0x0084; static const int HTCLIENT = 1; static const int HTCAPTION = 2; protected: virtual void Form1::WndProc(System::Windows::Forms::Message %m) override { switch (m.Msg) { case WM_NCHITTEST: if (m.Result == IntPtr(HTCLIENT)) { m.Result = IntPtr(HTCAPTION); } break; } Form1::WndProc(m); } virtual System::Windows::Forms::CreateParams^ get() override { System::Windows::Forms::CreateParams^ cp = __super::CreateParams; cp->Style |= 0x40000; return cp; } How can I fix my code not to crash but still allow my form to be moved and resized?

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  • Jquery - check if atleast one checkbox is checked

    - by Vincent
    All, I have the following HTML form and it can have many checkboxes. When the submit button is clicked, I want the user to get a javascript alert to check atleast one checkbox if none are checked. Is there an easy way to do this using Jquery? <form name = "frmTest" id="frmTest"> <input type="checkbox" value="true" checked="true" name="chk[120]"> <input type="checkbox" value="true" checked="true" name="chk[128]"> <input type="checkbox" name="chk[130]"> <input type="checkbox" name="chk[143]"> <input type="submit" name="btnsubmit" value="Submit"> </form> Thanks

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  • Why isnt php reading my cookie?

    - by Jason94
    at index.php i have a form to fill out some settings. the form posts to setsettings.php at setsettings.php it uses the form data and sets some cookies and redirect back to index.php. if i print_r($_COOKIE) at setsettings.php all is well. but nothing comes up at index.php, the $_COOKIE array is empty :( Does somebody know how i go about solving this? I set det setting by (setsettings.php): /* Write new cookie */ $expire = 60 * 60 * 24 * 60 + time(); // ~2 months setcookie("user_var_001", $_POST['selection'], $expire); and in index.php print_r($_COOKIE) turns up blank;

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  • Help getting ActiveScaffold to work properly

    - by x3ro
    Hey there I was curious about the ActiveScaffold Rails plugin, but somehow I can't get it to work properly. I've followed the steps which are described on http://activescaffold.com/tutorials/ . The table and everything shows up and when I click on "Create new", the dialog pops up. However, when I fill out the form and click "Create", I just get "500 Internal server error". In the server log, it says "NameError (wrong constant name ###):", with ### being what I entered in the first form field. If I don't enter anything in the form, it says "NoMethodError (undefined method `new_record?' for #):"... So what am I doing wrong here? Thanks in advance for your help :)

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  • Better explanation of $this-> in this example please

    - by Doug
    Referring to this question: http://stackoverflow.com/questions/2035449/why-is-oop-hard-for-me class Form { protected $inputs = array(); public function makeInput($type, $name) { echo '<input type="'.$type.'" name="'.$name.'">'; } public function addInput($type, $name) { $this->inputs[] = array("type" => $type, "name" => $name); } public function run() { foreach($this->inputs as $array) { $this->makeInput($array['type'], $array['name']; } } } $form = new form(); $this->addInput("text", "username"); $this->addInput("text", "password");** Can I get a better explanation of what the $this->input[] is doing in this part: public function addInput($type, $name) { $this->inputs[] = array("type" => $type, "name" => $name); }

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  • PHP code not working on IE

    - by Michael Frey
    I have a website with a flag. If it is clicked, the language of the website changes. Here is the code displaying the flag, which is a form with post event: <?php $pagename = $_SERVER['REQUEST_URI']; echo '<form action="'.$pagename.'" method="post"> <input name="formlanguage" type="image" '; if ($_SESSION['lang'] == 0) { echo 'alt="English" src="images/en.png" value="1" '; } else { echo 'alt="Deutsch" src="images/de.png" value="0" '; } echo '/></form>'; ?> Here is the response to that, and this part always fails on IE: if (isset($_POST['formlanguage'])) { $_SESSION['lang']=$_POST['formlanguage']; } I can not figure out why it works on Chrome but not IE. I assume that it might be a setting of IE. But what could that be?

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  • File upload using HTML file type.

    - by vaibhav
    I want to upload a file on my aspx page. I am using <form id="frmId" method="post" enctype="Multipart/form-data"> <input type="file" id="file1"/> <input type="submit" id="btnsubmit"/> </form> and in code behind I am trying to get this file. Its not letting me to get the file until I use server side input file control. I don't want to use runat="server" attribute with my file control. Do anyone know how to do this.

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  • notications pop up in user side

    - by user2931015
    i try to show notification as a pop up. like when admin login and through his account he send notification to user i add this html in admin form like this.. <asp:Button ID="notic" runat="server" Text="Send" onclick="Button1_Click" /> <br /> <input class="add_message" type="text" value="type your message" name="add_message"></input> <input type="button" value="add message" onclick="sNotify.addToQueue($('.add_message').attr('value'))"/> Then when admin click on button then notification send to users account like when any user login then he/she able to see pop ups in user form I call this java script in page load like this .. ClientScript.RegisterStartupScript(GetType(), "Javascript", "javascript:sNotify.addToQueue($('.add_message').attr('value'))();", true); it works like when i login as a admin and click on button then notification in his own page .. but i want to show this notifications in user form. so how to solve it?

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  • Pass Value between MDI Child in WinForm using C#

    - by abhilashca
    I have an MDI Parent, containing a MenuStrip. When I click on one of the Menu, two Child Forms are displayed simultaneoulsy. I have a TextBox and a Send Button on one of my ChildForm. When I type-in something in that TextBox and Click the Send Button, I need to show that value in the TextBox of my Second Child Form. What I had done is, I wrote a Public Function in the Second Child Form and tried to invoke it by creating an object of Second Form, on the Send Button click event. When I put break points, in that Public Function, I find that the control is flowing through that Public function on cliking the Send button. But the passed value is not displayed. And, I know that is not the standard way to do that. Any sample script for help? Thanks.

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  • How to get the values from post method to the codehind file

    - by SmartestVEGA
    I have created a Webpage which will post as "post" method..not as "get" method. <html> <head> </head> <body> <FORM action="RetrieveData_Post.asp" id=form1 method=post name=form1> First Name: <br> <INPUT id="txtFirstName" name="txtFirstName" > <br> Last Name: <br> <INPUT id="txtLastName" name="txtLastName" > <br> <INPUT type="submit" value="Submit"> </FORM> </body> </html> i want to retieve the values in the textboxes in the code behind of another form. Please help me.

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  • html post issue

    - by Amarsh
    i have the following html code : <FORM name=frmmail> <input id="dochtmlContent" type="hidden" name="dochtmlContent" value="oldValue"/> <script>document.dochtmlContent="newValue"</script> </FORM> and later on in a javascrip function (which is called upn submit): alert(document.dochtmlContent); document.frmmail.method = "post"; document.frmmail.ENCTYPE = "application/x-www-form-urlencoded"; document.frmmail.action = "/myServlet"; document.frmmail.submit(); Basically, I am declaring a hiden variable, changing its value and submitting it. The issue is, while I see an alert box displaying "newValue", when I submit it, my servlet recieves the "oldValue" for the dochtmlContent parameter. Can someone suggest whats wrong here.

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