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  • Ways to prevent multiple email notification with php&mysql

    - by Louis Loudog Trottier
    My 1st post, but i got many great answers and tips from stackoverflow so far. This one was a close call- How does facebook, gmail send the real time notification? but not exactly, so let brainstorm this together. I have CMS system with mail notification when a change is made on the site. Everything wotk very well but i want to prevent multiple notification if somene make another quick change to, let say, fix a typo. Using php mail(), obviously. I've tough of 2 ways, one simple, and one.... let just say, pretty heavy... cough. the 3rd one was inspired by Implementing Email Notification but really doesn't look appealing to me to send bunch of email at once. Use a timestamp to check if another change was made in the 'let say' last 5 minutes. Record the last change, and compare it to the new one. Could be usefull for backup at the same time since i'll have to save the change somewhere, but text can be long and making an sql search would be painfull. Wouldn't it? Use cron to send changes every x minutes... convince me if you ythink it is a suitable solution. Any ideas, comment or suggestion of your own? Looking forward for your inputs, and since i now registered, i'll do my best to help around. Cheers, all llt

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  • Incrementing through mysql PHP

    - by Rawdon
    I am looking at try to increment and decrement by three records through a table and present those records. Say if the id '4' is currently active. I want the to be display the ID's and category of 3.2.1 and 5.6.7 from an increment and decrement So far I have: $stmt = $db->query("SELECT id, category FROM test"); $stmt->execute(); while ($results = $stmt->fetch(PDO::FETCH_ASSOC)) { $current = $results['id']; $category = $results['category']; $next = array(array('slide_no' => $current, 'category' => $category)); } print_r($next); Now with this, I am getting back every row in the table. I'm now getting confused on how I could increment and decrement the records by 3 and make sure that the category will also increment correctly. Thank you very much.

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  • MySQL Group Results by day using timestamp

    - by Webnet
    I need to take the following query and pull the total order counts and sum of the orders grouped by day. I'm storing everything using timestamps. SELECT COUNT(id) as order_count, SUM(price + shipping_price) as order_sum, DAY(FROM_UNIXTIME(created)) as day FROM `order` WHERE '.implode(' AND ', $where).' I need to group by DAY but when I do for this past weekend's sales it takes my order_count and makes it 1 instead of 3. How can I pull the above values grouped by day? NOTE: The implode is used ONLY to define the time period (WHERE created = TIMESTAMP AND <= TIMESTAMP)

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  • PHP/MySQL Problem

    - by Scott
    Why does this only print the sites specific content under the first site, and doesn't do it for the other 2? <?php echo 'NPSIN Data will be here soon!'; // connect to DB $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = 'root'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to DB'); $dbname = 'npsin'; mysql_select_db($dbname); // get number of sites $query = 'select count(*) from sites'; $result = mysql_query($query) or die ('Query failed: ' . mysql_error()); $resultArray = mysql_fetch_array($result); $numSites = $resultArray[0]; echo "<br><br>"; // get all sites $query = 'select site_name from sites'; $result = mysql_query($query); // get site content $query2 = 'select content_name, site_id from content'; $result2 = mysql_query($query2); // get site files // print info $count = 1; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { echo "Site $count: "; echo "$row[0]"; echo "<br>"; $contentCount = 1; while ($row2 = mysql_fetch_array($result2, MYSQL_NUM)) { $id = $row2[1]; if ($id == ($count - 1)) { echo "Content $contentCount: "; echo "$row2[0]"; echo "<br>"; } $contentCount++; } $count++; } ?>

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  • Validation library for PHP/mysql

    - by Industrial
    Hi! Is there any lightweight validation library available for PHP that easily can check if a specific string or value is valid for a known database type - Something like this: if (is_MEDIUMINT($var)) { $this->db->insert($anothervar); } Thanks!

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  • [MySQL] Optimize Query

    - by bordeux
    Hello. I have problem with optimize this query: SET @SEARCH = "dokumentalne"; SELECT SQL_NO_CACHE `AA`.`version` AS `Version` , `AA`.`contents` AS `Contents` , `AA`.`idarticle` AS `AdressInSQL` , `AA` .`topic` AS `Topic` , MATCH (`AA`.`topic` , `AA`.`contents`) AGAINST (@SEARCH) AS `Relevance` , `IA`.`url` AS `URL` FROM `xv_article` AS `AA` INNER JOIN `xv_articleindex` AS `IA` ON ( `AA`.`idarticle` = `IA`.`adressinsql` ) INNER JOIN ( SELECT `idarticle` , MAX( `version` ) AS `version` FROM `xv_article` WHERE MATCH (`topic` , `contents`) AGAINST (@SEARCH) GROUP BY `idarticle` ) AS `MG` ON ( `AA`.`idarticle` = `MG`.`idarticle` ) WHERE `IA`.`accepted` = "yes" AND `AA`.`version` = `MG`.`version` ORDER BY `Relevance` DESC LIMIT 0 , 30 Now, this query using ^ 20 seconds. How to optimize this? EXPLAIN gives this: 1 PRIMARY AA ALL NULL NULL NULL NULL 11169 Using temporary; Using filesort 1 PRIMARY ALL NULL NULL NULL NULL 681 Using where 1 PRIMARY IA ALL accepted NULL NULL NULL 11967 Using where 2 DERIVED xv_article fulltext topic topic 0 1 Using where; Using temporary; Using filesort This is example server with my data: user: bordeux_4prog password: 4prog phpmyadmin: http://phpmyadmin.bordeux.net/ chive: http://chive.bordeux.net/

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  • How to Download my MYSQL Backup?

    - by NiCk Newman
    Okay I use this script here to make a backup of my database: mysqldump -u root -h localhost -pPASSWORD forums | gzip -9 > backup-$(date +%Y-%m-%d).sql.gz This is used in a cron daily. But I need to download this remotely or through a ftp program every day as well so I have a physical copy of it on my home hard drive, is this possible? I know it is, can anyone tell me a quick way to do it?

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  • Mysql SELECT with an OR across 2 columns

    - by Haroldo
    I'm creating a 'similar items' link table. i have a 2 column table. both columns contains product ids. The table is showing that these items are similar. However ids in the left column are more valuable. Say i want to select similar items to product '125b'. i only want 3 similar items to 125b. If there are any instances of 125b in col1 I would prefer these to finding 125b in col2. so i need a select statement along the lines of SELECT * FROM similar_items WHERE col_1={$id} OR col_2={$id} ORDER BY column(?) LIMIT 3 i do not want to do 2 separate queries ( ie query 2 if count(query1) <3 )

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  • Mysql - Join matches and non-matches

    - by jwzk
    This is related to my other question: http://stackoverflow.com/questions/2579249/managing-foreign-keys I am trying to join the table of matches and non-matches. So I have a list of interests, a list of users, and a list of user interests. I want the query to return all interests, whether the user has the interest or not (should be null in that case), only where the user = x. Every time I get the query working its only matching interests that the user specifically has, instead of all interests whether they have it or not.

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  • MySQL - JOINS (excepts)

    - by user2529899
    I'm trying to find 2 different result via JOINS. Table look like; SELECT id,member_id,registered_year FROM records; I can listing which members registered in 2012 and also in 2013 with; SELECT member_id FROM records a INNER JOIN records b ON a.member_id=b.member_id WHERE a.registered_year='2013' AND b.registered_year='2012'; But I can't list revers of It. How can I list which members were registered in 2012 but not in 2013? Thnx in advance.

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  • mysql query trouble

    - by Bharanikumar
    Hi , in my database i have phone numbers with country code , which look somthing like 0044-123456 0044-123456 0014-123456 0014-123456 0024-123456 0024-123456 0034-123456 0044-123456 0044-123456 0024-123456 0034-123456 084-123456 084-123456 i want to total up the numbers by country, something like this output 0044 (2) 0024 (2) 0034 (1) 084 (2) 064 (5) Is it possible to do this with a SQL query?

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  • MYSQL sum() for distinct rows

    - by makeee
    I'm looking for help using sum() in my SQL query (not posting full query since the scenario is fairly simple). I have COUNT(DISTINCT conversions.id) in my query. I use DISTINCT because I'm doing "group by" for multiple columns and this ensures the same row is not counted more than once. Now I want to add: SUM(conversions.value) as conversion_value The problem is that the "value" for each row is counted more than once (due to the multiple group bys) I basically want to do SUM(conversions.value) for each DISTINCT conversions.id. Is that possible?

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  • mysql_num_rows(): supplied argument is not a valid MySQL result resource

    - by php-b-grader
    I am getting this error when I pass an invalid SQL string... I spent the last hour trying to find the problem assuming - It's not my SQL it must be the db handle... ANyway, I've now figured out that it was bad SQL... What I want to do is test the result of the mysql_query() for a valid resultset. I am simply using empty($result)... Is this the most effective test? Is there a more widely accepted method of testing a resultset for a valid result?

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  • Creating CFArray from MySQL Result Array

    - by Andrew
    Is there an easy way to dump an array returned from mysql_fetch_row into a CFArray? (part of the PHP implementation of CFPropertyList) I'm bummed by the lack of documentation on CFPropertyList for PHP. Iterating through each item in the array seems inefficient. I'm open to using a different mysql_fetch_... command. I'd like to just say: $NewArray = new CFArray( $ResultArray ) But that deosn't seem to work. This is my current code: $plist = new CFPropertyList(); $ResultRow = mysqli_fetch_row( $result ); $plist-add( $TableRow = new CFArray() ); foreach ( $ResultRow as $Item ){ $TableRow-add( new CFString( $Item ) ); }

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  • MySQL some columns Distinct

    - by Adam
    I have the following query that works well. SELECT DISTINCT city,region1,region2 from static_geo_world where country='AU' AND (city LIKE '%geel%' OR region1 LIKE '%geel%' OR region2 LIKE '%geel%' OR region3 LIKE '%geel%' OR zip LIKE 'geel%') ORDER BY city; I need to also extract a column named 'id' but this messes up the DISTINCT as each ID is different. How can I get the same UNIQUE set of records as above but also get the 'id' for each record? Note: sometimes I can return a few thousand records so a query for each record isn't possible. Any ideas would be very welcome...

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  • MySQL -- How to do this better?

    - by Andrew
    $activeQuery = mysql_query("SELECT count(`status`) AS `active` FROM `assignments` WHERE `user` = $user_id AND `status` = 0"); $active = mysql_fetch_assoc($activeQuery); $failedQuery = mysql_query("SELECT count(`status`) AS `failed` FROM `assignments` WHERE `user` = $user_id AND `status` = 1"); $failed = mysql_fetch_assoc($failedQuery); $completedQuery = mysql_query("SELECT count(`status`) AS `completed` FROM `assignments` WHERE `user` = $user_id AND `status` = 2"); $completed = mysql_fetch_assoc($completedQuery); There has to be a better way to do that, right? I don't know how much I need to elaborate as you can see what I'm trying to do, but is there any way to do all of that in one query? I need to be able to output the active, failed, and completed assignments, preferably in one query.

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  • MySQL: group by and IF statement

    - by notset
    By default, parent_id = 0. I want to select all records with parent_id = 0 and only the last ones with parent_id 0. I tried this, but it didn't work: SELECT * FROM `articles` IF `parent_id` > 0 THEN GROUP BY `parent_id` HAVING COUNT(`parent_id`) >= 1 END; ORDER BY `time` DESC What could be the solution?

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  • how to remove mysql root password

    - by nectar
    I want to remove password for user root in localhost how can I do that?by mistake I have set the password of root user thats why phpmyadmin is giving error- #1045 - Access denied for user 'root'@'localhost' (using password: NO)

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  • mySQL JOIN wont return results with 0 count

    - by MPC
    SELECT categories.*, COUNT(categoryID) AS kritCount FROM categories AS categories LEFT JOIN krits ON categories.id = categoryID WHERE (krits.approved = '1') GROUP BY categories.id So this works great except that it does not return a category that has a 0 count of krits in the category. It will if I remove the WHERE statement but I need the WHERE to only select the krits where the field approved = 1

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  • Adding up row number and displaying total using COUNT (PHP MySQL)

    - by Yvonne
    I'm attempting to run a query that adds up the total number of subjects in a class. A class has many subjects. There is a 'teachersclasses' table between teachers (the user table) and classes. The principles sounds pretty simple but I'm having some trouble in getting my page to display the number of subjects for each class (directly associated with the teacher) This is what I have so far, trying to make use of the COUNT with a nested SELECT: SELECT (SELECT count(*) FROM subjects WHERE subjects.classid = class.classid) AS total_subjects, class.classname, class.classid FROM class Then I am calling up 'num_subjects' to present the total within a while loop: <?php echo $row['total_subjects']?> From the above, I am receiving the total subjects for a class, but within the same table row (for one class) and my other while loop doesnt run anymore, which returns all of the classes associated with a teacher :( ... Bit of a mess now! I know to return the classes for a particular teacher, I can do an additional WHERE clause on the session of 'teacherid' but I think my query is getting too complicated for me that errors are popping up everywhere. Anyone have a quick fix for this! Thanks very much

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