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• How can I mix command line arguments and filenames for <> in Perl?

  - by Jimmeh

  Consider the following silly Perl program: $firstarg = $ARGV[0]; print $firstarg; $input = <>; print $input; I run it from a terminal like: perl myprog.pl sample_argument And get this error: Can't open sample_argument: No such file or directory at myprog.pl line 5. Any ideas why this is? When it gets to the < is it trying to read from the (non-existent) file, "sample_argument" or something? And why?

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• Optimizing sparse dot-product in C#

  - by Haggai

  Hello. I'm trying to calculate the dot-product of two very sparse associative arrays. The arrays contain an ID and a value, so the calculation should be done only on those IDs that are common to both arrays, e.g. <(1, 0.5), (3, 0.7), (12, 1.3) * <(2, 0.4), (3, 2.3), (12, 4.7) = 0.7*2.3 + 1.3*4.7 . My implementation (call it dict) currently uses Dictionaries, but it is too slow to my taste. double dot_product(IDictionary<int, double> arr1, IDictionary<int, double> arr2) { double res = 0; double val2; foreach (KeyValuePair<int, double> p in arr1) if (arr2.TryGetValue(p.Key, out val2)) res += p.Value * val2; return res; } The full arrays have about 500,000 entries each, while the sparse ones are only tens to hundreds entries each. I did some experiments with toy versions of dot products. First I tried to multiply just two double arrays to see the ultimate speed I can get (let's call this "flat"). Then I tried to change the implementation of the associative array multiplication using an int[] ID array and a double[] values array, walking together on both ID arrays and multiplying when they are equal (let's call this "double"). I then tried to run all three versions with debug or release, with F5 or Ctrl-F5. The results are as follows: debug F5: dict: 5.29s double: 4.18s (79% of dict) flat: 0.99s (19% of dict, 24% of double) debug ^F5: dict: 5.23s double: 4.19s (80% of dict) flat: 0.98s (19% of dict, 23% of double) release F5: dict: 5.29s double: 3.08s (58% of dict) flat: 0.81s (15% of dict, 26% of double) release ^F5: dict: 4.62s double: 1.22s (26% of dict) flat: 0.29s ( 6% of dict, 24% of double) I don't understand these results. Why isn't the dictionary version optimized in release F5 as do the double and flat versions? Why is it only slightly optimized in the release ^F5 version while the other two are heavily optimized? Also, since converting my code into the "double" scheme would mean lots of work - do you have any suggestions how to optimize the dictionary one? Thanks! Haggai

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• Get previous element in IObservable without re-evaluating the sequence

  - by dcstraw

  In an IObservable sequence (in Reactive Extensions for .NET), I'd like to get the value of the previous and current elements so that I can compare them. I found an example online similar to below which accomplishes the task: sequence.Zip(sequence.Skip(1), (prev, cur) => new { Previous = prev, Current = cur }) It works fine except that it evaluates the sequence twice, which I would like to avoid. You can see that it is being evaluated twice with this code: var debugSequence = sequence.Do(item => Debug.WriteLine("Retrieved an element from sequence")); debugSequence.Zip(debugSequence.Skip(1), (prev, cur) => new { Previous = prev, Current = cur }).Subscribe(); The output shows twice as many of the debug lines as there are elements in the sequence. I understand why this happens, but so far I haven't found an alternative that doesn't evaluate the sequence twice. How can I combine the previous and current with only one sequence evaluation?

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• size of structures in .NET

  - by redpaladin

  My problem is very simple. My problem is to send a structure between a program in C to a C# program. I made a struct in C#: public struct NetPoint { public float lat; // 4 bytes public float lon; // 4 bytes public int alt; // 4 bytes public long time; // 8 bytes } Total size of the struct must be 20 bytes. When I do a sizeof() of this struct: System.Diagnostics.Debug.WriteLine("SizeOf(NetPoint)=" + System.Runtime.InteropServices.Marshal.SizeOf(new NetPoint())); The debug console shows: SizeOf(NetPoint)=24 But I expected to have 20 bytes. Why do I see a difference?

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• How to calculate median of a Map<Int,Int>?

  - by Chris

  For a map where the key represents a number of a sequence and the value the count how often this number appeared in the squence, how would an implementation of an algorithm in java look like to calculate the median? For example: 1,1,2,2,2,2,3,3,3,4,5,6,6,6,7,7 in a map: Map<Int,Int> map = ... map.put(1,2) map.put(2,4) map.put(3,3) map.put(4,1) map.put(5,1) map.put(6,3) map.put(7,2) double median = calculateMedian(map); print(median); would result in: > print(median); 3 > So what i am looking for is a java implementation of calculateMedian.

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• Why are these strings escaping from my regular expression in python?

  - by dohkoxar

  In my code, I load up an entire folder into a list and then try to get rid of every file in the list except the .mp3 files. import os import re path = '/home/user/mp3/' dirList = os.listdir(path) dirList.sort() i = 0 for names in dirList: match = re.search(r'\.mp3', names) if match: i = i+1 else: dirList.remove(names) print dirList print i After I run the file, the code does get rid of some files in the list but keeps these two especifically: ['00. Various Artists - Indie Rock Playlist October 2008.m3u', '00. Various Artists - Indie Rock Playlist October 2008.pls'] I can't understand what's going on, why are those two specifically escaping my search.

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• Windows Service Printing Behaviour

  - by Andre

  Alright, I was tasked to develop a Windows Service that listens to a directory for files that are dropped in it, read them, delete them and print out a report. I installed the service on my work laptop (Win 7 x86) and a test machine (XP x86) under a User account at first. It would do everything as it should except the print the report. No errors, nothing. Then I made it run under Local System and it produced a "No printers found" exception. Converting the app to a Console Application and running on these machines gave the desired result. OK, so now I was assuming that there are security "stuff" involved. Then I installed the service on a Server 2008 x64 machine (under Local System) and it just worked. Can anybody explain to me why this is happening? Why does the service allow printing from Server OS but not from a Desktop OS or am I missing something very obvious?

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• AWK: how to reuse a result NR-times without removing END?

  - by HH

  How can I get all differences, not just one? I want to use the calculated result for each item in the third column. The dilemma is that if I remove END I can print $3 but cannot have ave. If I leave END I have ave but not all differences. awk '{sum+=$3} END {ave=sum/NR} END {print $3-ave}' coriolis_data -0.00964 // I want to see the rest differences, how? coriolis_data .105 0.005 0.9766 0.0001 0.595 0.005 .095 0.005 0.9963 0.0001 0.595 0.005 .115 0.005 0.9687 0.0001 0.595 0.005 .105 0.005 0.9693 0.0001 0.595 0.005 .095 0.005 0.9798 0.0001 0.595 0.005 .105 0.005 0.9798 0.0001 0.595 0.005 .095 0.005 0.9711 0.0001 0.595 0.005 .110 0.005 0.9640 0.0001 0.595 0.005 .105 0.005 0.9704 0.0001 0.595 0.005 .090 0.005 0.9644 0.0001 0.595 0.005

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• SQL Server float datatype

  - by Martin Smith

  The documentation for SQL Server Float says Approximate-number data types for use with floating point numeric data. Floating point data is approximate; therefore, not all values in the data type range can be represented exactly. Which is what I expected it to say. If that is the case though why does the following return 'Yes' in SQL Server DECLARE @D float DECLARE @E float set @D = 0.1 set @E = 0.5 IF ((@D + @D + @D + @D +@D) = @E) BEGIN PRINT 'YES' END ELSE BEGIN PRINT 'NO' END but the equivalent C++ program returns "No"? #include <iostream> using namespace std; int main() { float d = 0.1F; float e = 0.5F; if((d+d+d+d+d) == e) { cout << "Yes"; } else { cout << "No"; } }

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• Will an optimizing compiler remove calls to a method whose result will be multiplied by zero?

  - by Tim R.

  Suppose you have a computationally expensive method, Compute(p), which returns some float, and another method, Falloff(p), which returns another float from zero to one. If you compute Falloff(p) * Compute(p), will Compute(p) still run when Falloff(p) returns zero? Or would you need to write a special case to prevent Compute(p) from running unnecessarily? Theoretically, an optimizing compiler could determine that omitting Compute when Falloff returns zero would have no effect on the program. However, this is kind of hard to test, since if you have Compute output some debug data to determine whether it is running, the compiler would know not to omit it because of that debug info, resulting in sort of a Schrodinger's cat situation. I know the safe solution to this problem is just to add the special case, but I'm just curious.

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• Python 3: Recursivley find if number is even

  - by pythonhack

  I am writing a program that must find if a number is even or not. It needs to follow this template. I can get it to find if a number is even or not recursively (call function and subtract 2, base case zero), but I am having a hard time following this template, based on how the isEven function is called in the main function. Any help would be greatly appreciated. Write a recursive function called isEven that finds whether a number is even or not: def isEven() #recursivley determine whether number is even or not def main(): number=int(input(“Enter a number : “)) if (isEven(number)): print(“Number is even”) else: print(“Number is not even”) main() Thank you! Appreciate it.

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• Globals across modules

  - by Coder1

  Wow, this seems so basic, but I can't get it to work. All I need to do is store a global dict which can be accessed and modified from other modules & threads. What's the "best practices" way of achieving this? test.py import testmodule class MyClassA(): def __init__(self, id): self.id = id if __name__ == '__main__': global classa_dict classa_dict = {} classa_dict[1] = MyClassA(1) classa_dict[2] = MyClassA(2) testing = testmodule.TestModule() testmodule.py class TestModule(): def __init__(self): global classa_dict print classa_dict[2] output $ python test.py Traceback (most recent call last): File "test.py", line 13, in <module> testing = testmodule.TestModule() File "/path/to/project/testmodule.py", line 4, in __init__ print classa_dict[2] NameError: global name 'classa_dict' is not defined

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• iPhone Application crashing upon loading a new Detail View

  - by Jeb Sears

  Hi, My problem is when trying to load a detail view through a table cell, the application constantly crashes. The error that comes up when running through debug is "__TERMINATING_DUE_TO_UNCAUGHT_EXCEPTION___" objc exception thrown. If anyone can help me it would be greatly appreciated. Here is a screenshot for the debug, I am not sure if I am interpreting it right http://img43.imageshack.us/img43/2143/errorud.png Here is my code where I beleive the error is happening: - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { NSInteger row = [indexPath row]; if(self.moreDetailView == nil){ DetailViewController *dvController = [[DetailViewController alloc] initWithNibName:@"DetailViewController" bundle:[NSBundle mainBundle]]; self.moreDetailView = dvController; [dvController release]; } else{} moreDetailView.title = [NSString stringWithFormat:@"%@", [listOfItems objectAtIndex:row]]; goHerdv2AppDelegate *delegate = [[UIApplication sharedApplication] delegate]; [delegate.detailView pushViewController:moreDetailView animated:YES];}

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• can i changed for loop index variable inside the loop in Matlab???

  - by shawana

  hi every one. i need to change my loop variable inside the iterationa as ihave to acces array elements in the loop which is changing w.r.t size inside the loop. ashort piece of code is that: que=[]; que=[2,3,4]; global len; len=size(que,2) x=4; for i=1:len if x<=10 que(x)= 5; len=size(que,2) x=x+1; end end que array should print like: 2 3 4 5 5 5 5 5 5 5 but it is printed in such a way: 2 3 4 5 5 5. how shuould it be accomplished in matlab? in visual c++ it happen correctly and print whole array of 10 elements which increases at run time plz reply me if have any ideaabout this as i m new into matlab

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• What is Java Message Service (JMS) for?

  - by Daniel

  I am currently evaluating JMS and I don't get what I could use it for. Currently, I believe this would be a Usecase: I want to create a SalesInvoice PDF and print it when an SalesOrder leaves the Warehouse, so during the Delivery transaction I could send a transactional print request which just begins when the SalesOrder transaction completes successfully. Now I found out most JMS products are standalone server. Why would a need a Standalone Server for Message Processing, vs. e.g. some simple inproc processing with Quartz scheduler? How does it interact with my application? Isn't it much too slow? What are Usecases you already implemented successfully?

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• Assistance with regular expressions in Python

  - by da5id

  I am still learning REGEX, and I've run into an issue ... I am trying to separate a string that is composed of a mixture of letters and numbers that are in decimal format: AB0.500CD1.05EF2.29 Into something like this: list1 = AB,CD,EF list2 = 0.500,1.05,2.29 A complication to all this is that I also have strings that look like this: AB1CD2EF3 Which I'd also like to separate into this: list1 = AB,CD,EF list2 = 1,2,3 A previous inquiry yielded the following snippet, import re pattern = re.compile(r'([a-zA-Z]+)([0-9]+)') for (letters, numbers) in re.findall(pattern,cmpnd): print numbers print letters This example works fine for strings of the 2nd kind, but only "finds" the leading digit in the numbers that contain decimal places in the strings of the first kind. I've attempted an approach using the following line: pattern = re.compile(r'([a-zA-Z]+)([0-9]+(\.[0-9]))') But this results in an error: "ValueError: too many values to unpack" Thanks for any and all assistance!

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• C++ performance, optimizing compiler, empty function in .cpp

  - by Dodo

  I've a very basic class, name it Basic, used in nearly all other files in a bigger project. In some cases, there needs to be debug output, but in release mode, this should not be enabled and be a NOOP. Currently there is a define in the header, which switches a makro on or off, depending on the setting. So this is definetely a NOOP, when switched off. I'm wondering, if I have the following code, if a compiler (MSVS / gcc) is able to optimize out the function call, so that it is again a NOOP. (By doing that, the switch could be in the .cpp and switching will be much faster, compile/link time wise). --Header-- void printDebug(const Basic* p); class Basic { Basic() { simpleSetupCode; // this should be a NOOP in release, // but constructor could be inlined printDebug(this); } }; --Source-- // PRINT_DEBUG defined somewhere else or here #if PRINT_DEBUG void printDebug(const Basic* p) { // Lengthy debug print } #else void printDebug(const Basic* p) {} #endif

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• Issue using Python to solve the Coin problem [closed]

  - by challarao

  I'm attempting to solve a problem commonly known as the Coin problem, but using McNuggets. McNuggets come in boxes containing either 6, 9, or 20 nuggets. I want to write a python script that uses Diophantine equations to determine if a given number of McNuggets n can be exactly purchased in these groupings. For example: 26 McNuggets -- Possible: 1 6-pack, 0 9-packs, 1 20-pack 27 McNuggets -- Possible: 0 6-packs, 3 9-packs, 0 20-packs 28 McNuggets -- Not possible This is my current attempt at writing the solution in Python, but the output is incorrect and I'm not sure what's wrong. n=input("Enter the no.of McNuggets:") a,b,c=0,0,0 count=0 for a in range(n): if 6*a+9*b+20*c==n: count=count+1 break else: for b in range(n): if 6*a+9*b+20*c==n: count=count+1 break else: for c in range(n): if 6*a+9*b+20*c==n: count=count+1 break if count>0: print "It is possible to buy exactly",n,"packs of McNuggetss",a,b,c else: print "It is not possible to buy"

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• Define new Drupal theme region inside a block

  - by oalo

  I have a footer block, and I need to print a block inside that block. So i have defined the new region inside my theme.info file, cleared caches, enabled PHP code input, and written this code inside the footer block: <div class="grid-4 suffix-4 omega"> <?php if ($footer-right): ?> <div id="footer-right"> <?php print $footer-right; ?> </div> </div> I have configured a block to appear inside the new region (which appears in the blocks admin page), but it doesnt show. Any idea about what may be happening? Thank you

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• making a programming language

  - by None

  I was wondering which way would create a faster programming language, because I have tried both. Writing code that takes the text, splits it by whitespace or newlines or something, then processes each line and has a dictionary for variables. Or writing code that takes text and converts it to another programming language. This is an example of how a very simple version of the first way would be programmed in python: def run(code): text = code.split(";") for t in text: if t == "hello": print "hi" second: def run(code): rcode = "" text = code.split(";") for t in text: if t == "hello": rcode += "print 'hi'"

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• how do you release code like a static library in windows

  - by djones2010

  I had a question with regards doing an official release of code. Its my first time using VS2008 so bear with me. I have my header file that has the api's which grant them access to the lib. now there is a debug and a release version that is talked about. how do i give these to my client? do i need to give them both folders or just the lib file along with the header file for that lib. The lib is ready for use directly. but i am a little confused between debug vs release. thanks

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• kmeans based on mapreduce by python

  - by user3616059

  I am going to write a mapper and reducer for the kmeans algorithm, I think the best course of action to do is putting the distance calculator in mapper and sending to reducer with the cluster id as key and coordinates of row as value. In reducer, updating the centroids would be performed. I am writing this by python. As you know, I have to use Hadoop streaming to transfer data between STDIN and STOUT. according to my knowledge, when we print (key + "\t"+value), it will be sent to reducer. Reducer will receive data and it calculates the new centroids but when we print new centroids, I think it does not send them to mapper to calculate new clusters and it just send it to STDOUT and as you know, kmeans is a iterative program. So, my questions is whether Hadoop streaming suffers of doing iterative programs and we should employ MRJOB for iterative programs?

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• How to Replace only Part of the Variable using #define

  - by mahesh

  #define C_TX_ TX_ #define C_RX_ RX_ enum Test { C_TX_MAC 0x0100, // Pre-Processor should replace C_TX_ to TX_ C_RX_MAC 0x0101 // But Not Working. }; int main(int argc, char *argv[]) { cout << TX_MAC; // HOW TO PRINT ? cout << RX_MAC; // HOW TO PRINT ? return true; } Please Help. Thanks in Advance

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• Django model class and custom property

  - by dArignac

  Howdy - today a weird problem occured to me: I have a modle class in Django and added a custom property to it that shall not be saved into the database and therefore is not represent in the models structure: class Category(models.Model): groups = models.ManyToManyField(Group) title = defaultdict() Now, when I'm within the shell or writing a test and I do the following: c1 = Category.objects.create() c1.title['de'] = 'german title' print c1.title['de'] # prints "german title" c2 = Category.objects.create() print c2.title['de'] # prints "german title" <-- WTF? It seems that 'title' is kind of global. If I change title to a simple string it works as expected, so it has to do something with the dict? I also tried setting title as a property: title = property(_title) But that did not work, too. So, how can I solve this? Thank you in advance! enter code here

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• How to test a regex password in Python?

  - by jCuga

  Using a regex in Python, how can I verify that a user's password is: At least 8 characters Must be restricted to, though does not specifically require any of: uppercase letters: A-Z lowercase letters: a-z numbers: 0-9 any of the special characters: @#$%^&+= Note, all the letter/number/special chars are optional. I only want to verify that the password is at least 8 chars in length and is restricted to a letter/number/special char. It's up to the user to pick a stronger / weaker password if they so choose. So far what I have is: import re pattern = "^.*(?=.{8,})(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%^&+=]).*$" password = raw_input("Enter string to test: ") result = re.findall(pattern, password) if (result): print "Valid password" else: print "Password not valid"

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