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  • redirect user, then log his visit using php and mysql

    - by Bart van Heukelom
    I have a PHP redirect page to track clicks on links. Basically it does: - get url from $_GET - connect to database - create row for url, or update with 1 hit if it exists - redirect browser to url using Location: header I was wondering if it's possible to send the redirect to the client first, so it can get on with it's job, and then log the click. Would simply switching things around work?

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  • complex MySQL Order by not working

    - by Les Reynolds
    Here is the select statement I'm using. The problem happens with the sorting. When it is like below, it only sorts by t2.userdb_user_first_name, doesn't matter if I put that first or second. When I remove that, it sorts just fine by the displayorder field value pair. So I know that part is working, but somehow the combination of the two causes the first_name to override it. What I want is for the records to be sorted by displayorder first, and then first_name within that. SELECT t1.userdb_id FROM default_en_userdbelements as t1 INNER JOIN default_en_userdb AS t2 ON t1.userdb_id = t2.userdb_id WHERE t1.userdbelements_field_name = 'newproject' AND t1.userdbelements_field_value = 'no' AND t2.userdb_user_first_name!='Default' ORDER BY (t1.userdbelements_field_name = 'displayorder' AND t1.userdbelements_field_value), t2.userdb_user_first_name; Edit: here is what I want to accomplish. I want to list the users (that are not new projects) from the userdb table, along with the details about the users that is stored in userdbelements. And I want that to be sorted first by userdbelements.displayorder, then by userdb.first_name. I hope that makes sense? Thanks for the really quick help! Edit: Sorry for disappearing, here is some sample data userdbelements userdbelements_id userdbelements_field_name userdbelements_field_value userdb_id 647 heat 1 648 displayorder 1 - Sponsored 1 645 condofees 1 userdb userdb_id userdb_user_name userdb_emailaddress userdb_user_first_name userdb_user_last_name 10 harbourlights [email protected] Harbourlights 1237 Northshore Blvd, Burlington 11 harbourview [email protected] Harbourview 415 Locust Street, Burlington 12 thebalmoral [email protected] The Balmoral 2075 & 2085 Amherst Heights Drive, Burlington

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  • PHP + SQL Server or VB.NET + MySQL

    - by Muhammad Mussnoon
    Can someone suggest that out of the two mentioned (odd?) combinations, which is less odd, or in other words, is less trouble to work with + maintain. If it helps, the system is going to have two front-ends - one web application and one desktop application. The desktop application is going to be coded using VB.NET, and the web application in PHP. There's really no reason why the desktop application can't be replaced by a web application as well - except that one of the programmers seem to really want to code it in VB.... However, none of us have experience working with either of these pairs (you could easily call us n00bs), so we are a bit apprehensive to start. P.S. hosting service will be gotten from some provider and not be on the client's own server.

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  • PHP, MySQL: Receive email, auto search in DB & send email based on the results

    - by Devner
    Hi all, Visitors can contact staff by means of contact form (visitor needs to submit email as well). This will be stored in DB. Now considering that staff responds to this message, the reply from the staff would be sent to the visitors email directly. Say if the user wants to follow up on the message sent by the staff, I would like the visitor to just hit the reply button in his email service & send me his questions on the same topic, but just retain the ID in the Subject line. So when the visitor send this email, I would like to receive the email & at the same time, try to search in my DB if the ID that is present in the email subject, actually exists in the system. If yes, that would be sent back to the same staff member who handled the response previously or it would be assigned to a new staff member. That being said, I was thinking of how to do this. The part where I am really held up is when the staff receives the actual email from the visitors email, how can I check the DB? Say I am/staff is receiving emails at [email protected]. When visitor sends reply email, then it would be sent to [email protected]. How can I check to see if the ID in the subject line of the email that I received at [email protected], actually exists in my DB in my website? This is where I am really stuck. Looking forward for your replies. Thank you.

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  • MySQL problem: How to get desired rows.

    - by Joonas Köppä
    I have been trying to solve this problem for 2 hours now but I cant understand the solutions others have given people with a similar problem. Ive seen some answers but can't apply it to my own needs. I have a table of users and their times in different sports events. I need to make a scoretable that shows the user with the best time, second best etc. The table before sorting and retrieving looks as follows: | Name | Time | Date | '''''''''''''''''''''''''''''''''''''''''''''' | Jack | 03:07:13 | 2010-12-01 | | Peter | 05:03:12 | 2010-12-03 | | Jack | 03:53:19 | 2010-12-04 | | Simon | 03:22:59 | 2010-12-02 | | Simon | 04:01:11 | 2010-12-09 | | Peter | 03:19:17 | 2010-12-06 | '''''''''''''''''''''''''''''''''''''''''''''' | Name | Time | Date | '''''''''''''''''''''''''''''''''''''''''' | Jack | 03:07:13 | 2010-12-01 | | Peter | 03:19:17 | 2010-12-06 | | Simon | 03:22:59 | 2010-12-02 | '''''''''''''''''''''''''''''''''''''''''' I know answers to this problem lie in another question asked on this very site: CLICK HERE I just have no idea how to apply it to fullfill my needs. Help is highly appreciated. Thank you -Joonas

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  • fast retrieval from MYSQL DB

    - by trojanwarrior3000
    I have a table of users - It contains around millions of rows (user-id is the primary key). I just want to retrieve user-id and their joining date. using "select user-id,joining date from table user" requires lot of time.Is there a fast way to query/retrieve the same data from this table?

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  • In python, changing MySQL query based on function variables

    - by ensnare
    I'd like to be able to add a restriction to the query if user_id != None ... for example: "AND user_id = 5" but I am not sure how to add this into the below function? Thank you. def get(id, user_id=None): query = """SELECT * FROM USERS WHERE text LIKE %s AND id = %s """ values = (search_text, id) results = DB.get(query, values) This way I can call: get(5) get(5,103524234) (contains user_id restriction)

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  • Fetch data from multiple MySQL tables

    - by Jon McIntosh
    My two tables look like this: TABLE1 TABLE2 +--------------------+ +--------------------+ |field1|field2|field3| and |field2|field4|field5| +--------------------+ +--------------------+ I am already running a SELECT query for TABLE1, and assorting all of the data into variables: $query = "SELECT * FROM TABLE1 WHERE field2 = 2"; $result = mysql_query($query); $num_rows = mysql_num_rows($result); if((!is_bool($result) || $result) && $num_rows) { while($row = mysql_fetch_array($result)) { $field1 = $row['field1']; $field2 = $row['field2']; $field3 = $row['field3']; } } What I want to do is get the data from 'field4' on TABLE2 and add it to my variables. I would want to get field4 WHERE field2 = 2

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  • Count Distinct With IF in MySQL?

    - by user1600801
    I need to do a query with count distinct and IF, but the results always are 0. What I need to do, is count the different users from a table in different months, using IF. My individual query, for one month is this: SELECT COUNT(DISTINCT(idUsers)) AS num_usuarios FROM table01 WHERE date1='201207' But I need to get the results by different months in the same query. What I'm trying to do is this: SELECT IF(date1=(201207), count(distinct(idUsers)), 0) as user30, IF(fecha1=(201206), count(distinct(idUsers)), 0) as user60, IF(fecha1=(201205), count(distinct(idUsers)), 0) as user90, IF(fecha1=(201204), count(distinct(idUsers)), 0) as user120, IF(fecha1=(201203), count(distinct(idUsers)), 0) as user150 FROM table01 But the all the results are always 0.

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  • Mysql data convert

    - by Sergio
    Is it possible to do DATE_SUB( ".$date." , INTERVAL 100 DAY ) if the type of the column where the date is stored is varchar(255) or I need to convert that column to "DATE" type?

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  • Collaborative filtering in MySQL ?

    - by user281434
    Hi I'm trying to develop a site that recommends items(fx. books) to users based on their preferences. So far, I've read O'Reilly's "Collective Intelligence" and numerous other online articles. They all, however, seem to deal with single instances of recommendation, for example if you like book A then you might like book B. What I'm trying to do is to create a set of 'preference-nodes' for each user on my site. Let's say a user likes book A,B and C. Then, when they add book D, I don't want the system to recommend other books based solely other users experience with book D. I wan't the system to look up similar 'preference-nodes' and recommend books based on that. Here's an example of 4 nodes: User1: 'book A'->'book B'->'book C' User2: 'book A'->'book B'->'book C'->'book D' user3: 'book X'->'book Y'->'book C'->'book Z' user4: 'book W'->'book Q'->'book C'->'book Z' So a recommendation system, as described in the material I've read, would recommend book Z to User 1, because there are two people who recommends Z in conjuction with liking C (ie. Z weighs more than D), even though a user with a similar 'preference-node', User2, would be more qualified to recommend book D because he has a more similar interest-pattern. So does any of you have any experience with this sort of thing? Is there some things I should try to read or does there exist any open source systems for this? Thanks for your time! Small edit: I think last.fm's algorithm is doing exactly what I my system to do. Using the preference-trees of people to recommmend music more personally to people. Instead of just saying "you might like B because you liked A"

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  • Select and copy to MySQL table PHP

    - by Liju
    Can insert the table1 value to Table2 like the follows.. based on Name Date. Table1 Id Date Name time 1 20/11/2010 Tom 08:00 2 20/11/2010 Tom 08:30 3 20/11/2010 Tom 09:00 4 20/11/2010 Tom 09:30 5 20/11/2010 Tom 10:00 6 20/11/2010 Tom 10:30 7 20/11/2010 Tom 11:30 8 20/11/2010 Tom 14:30 9 20/11/2010 John 08:10 10 20/11/2010 John 09:30 11 20/11/2010 John 11:00 12 20/11/2010 John 13:00 13 20/11/2010 John 14:30 14 20/11/2010 John 16:00 15 20/11/2010 John 17:30 16 20/11/2010 John 19:00 17 20/11/2010 Ram 08:05 18 20/11/2010 Ram 08:30 19 20/11/2010 Ram 09:00 20 20/11/2010 Ram 09:45 21 20/11/2010 Ram 12:00 22 20/11/2010 Ram 13:30 23 20/11/2010 Ram 15:00 Table2 Id Date Name Time In1 Time Out1 Time In1 Time Out1 Time In1 Time Out1 Time In4 Time Out4 1 20/11/2010 Tom 08:00 08:30 09:00 09:30 10:00 10:30 11:30 14:30 2 20/11/2011 John 08:10 09:30 11:00 13:00 14:30 16:00 17:30 19:00 3 20/11/2012 Ram 08:05 08:30 09:00 09:45 12:00 13:30 15:00 Null Help me Please... Liju

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  • MySQL GROUP BY and JOIN

    - by christian
    Guys what's wrong with this SQL query: $sql = "SELECT res.Age, res.Gender, answer.*, $get_sum, SUM(CASE WHEN res.Gender='Male' THEN 1 else 0 END) AS males, SUM(CASE WHEN res.Gender='Female' THEN 1 else 0 END) AS females FROM Respondents AS res INNER JOIN Answers as answer ON answer.RespondentID=res.RespondentID INNER JOIN Questions as question ON answer.Answer=question.id WHERE answer.Question='Q1' GROUP BY res.Age ORDER BY res.Age ASC"; the $get_sum is an array of sql statement derived from another table: $sum[]= "SUM(CASE WHEN answer.Answer=".$db->f("id")." THEN 1 else 0 END) AS item".$db->f("id"); $get_sum = implode(', ', $sum); the query above return these values: Age: 20 item1 0 item2 1 item3 1 item4 1 item5 0 item6 0 Subtotal for Age 20 3 Age: 24 item1 2 item2 2 item3 2 item4 2 item5 1 item6 0 Subtotal for Age 24 9 It should return: Subtotal for Age 20 1 Subtotal for Age 24 2 In my sample data there are 3 respondents 2 are 24 yrs of age and the other one is 20 years old.

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  • MYSQL CASE WHEN PROBLEM

    - by user305270
    SELECT `profiles`.* FROM `profiles` INNER JOIN `friendships` ON `profiles`.id = `friendships`.(CASE WHEN friendships.profile_id = 1 THEN`friend_id` ELSE `profile_id` END) How can i make the inner join like profile.id = friendships.(here will select the one key that is needed) but it doesnt work. please help :P it cant be: `profiles`.id = (CASE WHEN friendships.profile_id = 1 THEN `friendships`.`friend_id` ELSE `friendships`.`profile_id` END)

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  • MYSQL Select and group by date

    - by Gil
    I'm not sure how create a right query to get the result I'm looking for. What I have is 2 tables. first has ID, Name columns and second has date and adminID, which is referenced from table 1 column ID. Now, what I want to get is basically number of times each admin loged in per day during the month. From structure like this one I want to get per day and month data so result would be similar to 1, 2, 2 march total 5 for admin 4. ID | Date ------------------ 4 | 2010/03/01 4 | 2010/03/04 4 | 2010/03/04 4 | 2010/03/05 4 | 2010/03/05

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  • Tricky string transformation (hopefully) in LINQ

    - by Larsenal
    I'm hoping for a concise way to perform the following transformation. I want to transform song lyrics. The input will look something like this: Verse 1 lyrics line 1 Verse 1 lyrics line 2 Verse 1 lyrics line 3 Verse 1 lyrics line 4 Verse 2 lyrics line 1 Verse 2 lyrics line 2 Verse 2 lyrics line 3 Verse 2 lyrics line 4 And I want to transform them so the first line of each verse is grouped together as in: Verse 1 lyrics line 1 Verse 2 lyrics line 1 Verse 1 lyrics line 2 Verse 2 lyrics line 2 Verse 1 lyrics line 3 Verse 2 lyrics line 3 Verse 1 lyrics line 4 Verse 2 lyrics line 4 Lyrics will obviously be unknown, but the blank line marks a division between verses in the input.

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  • MySQL top count({column}) with a limit

    - by Josh K
    I have a table with an ip address column. I would like to find the top five addresses which are listed. Right now I'm planning it out the following: Select all distinct ip addresses Loop through them all saying count(id) where IP='{ip}' and storing the count List the top five counts. Downsides include what if I have 500 ip addresses. That's 500 queries I have to run to figure out what are the top five. I'd like to build a query like so select ip from table where 1 order by count({distinct ip}) asc limit 5

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  • How to optimize this mysql query - explain output included

    - by Sandeepan Nath
    This is the query (a search query basically, based on tags):- select SUM(DISTINCT(ttagrels.id_tag in (2105,2120,2151,2026,2046) )) as key_1_total_matches, td.*, u.* from Tutors_Tag_Relations AS ttagrels Join Tutor_Details AS td ON td.id_tutor = ttagrels.id_tutor JOIN Users as u on u.id_user = td.id_user where (ttagrels.id_tag in (2105,2120,2151,2026,2046)) group by td.id_tutor HAVING key_1_total_matches = 1 And following is the database dump needed to execute this query:- CREATE TABLE IF NOT EXISTS `Users` ( `id_user` int(10) unsigned NOT NULL auto_increment, `id_group` int(11) NOT NULL default '0', PRIMARY KEY (`id_user`), KEY `Users_FKIndex1` (`id_group`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=730 ; INSERT INTO `Users` (`id_user`, `id_group`) VALUES (303, 1); CREATE TABLE IF NOT EXISTS `Tutor_Details` ( `id_tutor` int(10) unsigned NOT NULL auto_increment, `id_user` int(10) NOT NULL default '0', PRIMARY KEY (`id_tutor`), KEY `Users_FKIndex1` (`id_user`), KEY `id_user` (`id_user`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=58 ; INSERT INTO `Tutor_Details` (`id_tutor`, `id_user`) VALUES (26, 303); CREATE TABLE IF NOT EXISTS `Tags` ( `id_tag` int(10) unsigned NOT NULL auto_increment, `tag` varchar(255) default NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`), KEY `tag_4` (`tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=2957 ; INSERT INTO `Tags` (`id_tag`, `tag`) VALUES (2026, 'Brendan.\nIn'), (2046, 'Brendan.'), (2105, 'Brendan'), (2120, 'Brendan''s'), (2151, 'Brendan)'); CREATE TABLE IF NOT EXISTS `Tutors_Tag_Relations` ( `id_tag` int(10) unsigned NOT NULL default '0', `id_tutor` int(10) unsigned default NULL, `tutor_field` varchar(255) default NULL, `cdate` timestamp NOT NULL default CURRENT_TIMESTAMP, `udate` timestamp NULL default NULL, KEY `Tutors_Tag_Relations` (`id_tag`), KEY `id_tutor` (`id_tutor`), KEY `id_tag` (`id_tag`), KEY `id_tutor_2` (`id_tutor`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `Tutors_Tag_Relations` (`id_tag`, `id_tutor`, `tutor_field`, `cdate`, `udate`) VALUES (2105, 26, 'firstname', '2010-06-17 17:08:45', NULL); ALTER TABLE `Tutors_Tag_Relations` ADD CONSTRAINT `Tutors_Tag_Relations_ibfk_2` FOREIGN KEY (`id_tutor`) REFERENCES `Tutor_Details` (`id_tutor`) ON DELETE NO ACTION ON UPDATE NO ACTION, ADD CONSTRAINT `Tutors_Tag_Relations_ibfk_1` FOREIGN KEY (`id_tag`) REFERENCES `Tags` (`id_tag`) ON DELETE NO ACTION ON UPDATE NO ACTION; What the query does? This query actually searches tutors which contain "Brendan"(as their name or biography or something). The id_tags 2105,2120,2151,2026,2046 are nothing but the tags which are LIKE "%Brendan%". My question is :- 1.In the explain of this query, the reference column shows NULL for ttagrels, but there are possible keys (Tutors_Tag_Relations,id_tutor,id_tag,id_tutor_2). So, why is no key being taken. How to make the query take references. Is it possible at all? 2. The other two tables td and u are using references. Any indexing needed in those? I think not. Check the explain query output here http://www.test.examvillage.com/explain.png

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  • Simple javascript string problem in ie6 and ie7

    - by Jeff Lamb
    I have a very simple function that takes a list of comma separated (x,y) points and imports them into a graph. I have FF, Chrome and IE8 installed. I use IETester to test for IE6 and IE7. // Import Data this.Import = function(data) { alert("Data in: "+data); var d; // Make sure the first and the last are start/ending parenthesis if ( (data[0] != '(') || (data[data.length-1] != ')') ) { alert("After if: "+data[0]+" "+data[data.length-1]); return false; } ... In Chrome, FF and IE8, I don't see the "After if:" alert. In IE6 and IE7, I see the following two alerts: Data in: (52,16),(100,90) After if: undefined undefined The "Data in" alert matches in all browsers. Any ideas?

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  • Single specific string replace method Objective C

    - by Sam
    Hi guys, I wanted to know if theres a single method or way that will help me replace strings for specific characters. like MALE - M FEMALE - F CHILD - P The longer way out is this.. [str stringByreplacingOccurencesOfString:@"MALE" withString:@"M"]; [str stringByreplacingOccurencesOfString:@"FEMALE" withString:@"F"]; [str stringByreplacingOccurencesOfString:@"CHILD" withString:@"P"]; I was wondering if theres another way in which i can reduce lines of code here, specially when there are alots of things to replace. thanks. this is for iPhone OS.

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  • mysql table marked as crashed

    - by Phil Jackson
    I recently created a ajax based instant messaging application and after running for a while I got an error [table] is marked as crashed and should be repaired. How could this have happened and how do I go about preventing it happening again?

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