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  • Why don't DNS root servers answer?

    - by JustTrying
    If I try to query a root server with dig, I never receive an answer. For example the output for dig @b.root-servers.net www.ubuntu.com is ; << DiG 9.8.1-P1 << @b.root-servers.net www.ubuntu.com ; (1 server found) ;; global options: +cmd ;; connection timed out; no servers could be reached But if I query other servers (the one of my ISP, or 8.8.8.8), they answer correctly. Why?

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  • How to force programs out of swap file when a resources-intensive batch finishes?

    - by sharptooth
    We use employees' desktops for CPU-intensive simulation during the night. Desktops run Windows - usually Windows XP. Employees don't log off, they just lock the desktops, switch off their monitors and go. Every employee has a configuration file which he can edit to specify when he is most likely out of office. When that time comes a background program grabs data for simulation from the server, spawns worker processes, watches them, gets results and sends them to the server. When the time specified by the employee elapses simulation stops so that normal desktop usage is not interfered. The problem is that simuation consumes a lot of memory, so when the worker processes run they force other programs into the swap file. So when the employee comes all the programs he left are luggish and slow until he opens them one by one so that they are unswapped. Is there a way the program can force other programs out of swap file when it stops simulation so that they again run smoothly?

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  • Is ReaderWriterLockSlim.EnterUpgradeableReadLock() essentially the same as Monitor.Enter()?

    - by Neil Barnwell
    So I have a situation where I may have many, many reads and only the occasional write to a resource shared between multiple threads. A long time ago I read about ReaderWriterLock, and have read about ReaderWriterGate which attempts to mitigate the issue where many writes coming in trump reads and hurt performance. However, now I've become aware of ReaderWriterLockSlim... From the docs, I believe that there can only be one thread in "upgradeable mode" at any one time. In a situation where the only access I'm using is EnterUpgradeableReadLock() (which is appropriate for my scenario) then is there much difference to just sticking with lock(){}? Here's the excerpt: A thread that tries to enter upgradeable mode blocks if there is already a thread in upgradeable mode, if there are threads waiting to enter write mode, or if there is a single thread in write mode. Or, does the recursion policy make any difference to this?

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  • Need better Java application deployment strategy

    - by Jeff Post
    I have various Java Swing applications that are used by multiple users. My deployment strategy is to locate the .jar file on a network share, and users create shortcuts to that file. When the user launches an application, the file is copied to their machine and executed locally. This method allows for a single copy of the code and easy updating. The problem is that I can't update the file on the network share if any user is using the application at that time. I can't use Web Start because I don't have access to a cert for signing the jar. My current workaround is a separate application that copies the desired app to the user's local machine, launches the application, and then the launcher exits. There is a several second delay from when the launcher app exits and the user's app becomes visible. Can anyone suggest a better deployment method where I can easily update a central copy of the application, one where Windows XP won't maintain a lock on the file?

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  • [iptables] Why do 'iptables -A OUTPUT -j REJECT' at the end of the chain OUTPUT override the previous rules??

    - by Serge
    Those are my IPTABLES rules: iptables -A INPUT -m state --state ESTABLISHED,RELATED -j ACCEPT iptables -A OUTPUT -p tcp --dport 22 -j ACCEPT iptables -A OUTPUT -p udp --dport 22 -j ACCEPT iptables -A OUTPUT -p tcp --dport 80 -j ACCEPT iptables -A OUTPUT -p udp --dport 53 -j ACCEPT iptables -A OUTPUT -p tcp --dport 53 -j ACCEPT iptables -A INPUT -p tcp --dport 80 -j ACCEPT iptables -A INPUT -p tcp -m tcp --dport 22 -m state --state NEW -m recent --set --name DEFAULT --rsource iptables -A INPUT -p tcp -m tcp --dport 22 -m state --state NEW -m recent --update --seconds 180 --hitcount 4 --name DEFAULT --rsource -j DROP iptables -A INPUT -p tcp -m state --state NEW --dport 22 -j ACCEPT iptables -A OUTPUT -j REJECT iptables -A INPUT -j REJECT iptables -A FORWARD -j REJECT Im using a remote ssh conetion to set them up, but after i set: iptables -A OUTPUT -j REJECT My connection get lost. I have read all the documentation for Iptables and i can figure out anything, the global Rejects for INPUT work well because i can access to the web page but i get a timeout for ssh. Any idea? Thanks

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  • Is there a better way to serially submit multiple AJAX requests?

    - by friedo
    I have a page with multiple forms that I submit via Ajax POSTs serially. At first, I tried using synchronous XHR requests, but this causes the browser to lock up for the duration of the request, and breaks my DOM-manipulation effects, which is unacceptable. So the pattern I ended up using is basically this: var fcount = 0; // incremented for each form to be submitted function submit_form( num ) { var fdata = { ... }; // data from form # num $.ajax( { async: true, url: '/index.cgi', data: fdata, type: 'POST', success: function() { if ( num < fcount ) { submit_form( ++num ); } } } ); } $( '#submit_form_btn' ).click( function() { submit_form( 1 ) } ); The recursion strikes me as a bit of an ugly solution to what is essentially an iterative problem. Is there a cleaner or more elegant way that this could be handled?

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  • Debugging in visual studio 2008 freezes entire system

    - by mat690
    Any time i try to debug in visual studio 2008 my entire system will freeze whenever a breakpoint is hit. I can move the mouse around and that remains responsive but nothing i click on does anything, I can bring up the task manager but can't do anything with it and i am able to lock/unlock the machine. I tried a fix that i found via google that suggested i disable advanced text services but it didn't work. I am using visual studio 2008 with SP1 running on Windows XP Pro, asking here is my last hope before formating/reinstalling so i hope someone can help me out. I debug by running the application in debug mode, the freeze happens no matter what the project size and it seems as if it is just the entire GUI that freezes, the computer carries on working just fine i just can't do anything with it because the GUI is totaly unresponsive.

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  • Exception error in Erlang

    - by Jim
    So I've been using Erlang for the last eight hours, and I've spent two of those banging my head against the keyboard trying to figure out the exception error my console keeps returning. I'm writing a dice program to learn erlang. I want it to be able to call from the console through the erlang interpreter. The program accepts a number of dice, and is supposed to generate a list of values. Each value is supposed to be between one and six. I won't bore you with the dozens of individual micro-changes I made to try and fix the problem (random engineering) but I'll post my code and the error. The Source: -module(dice2). -export([d6/1]). d6(1) - random:uniform(6); d6(Numdice) - Result = [], d6(Numdice, [Result]). d6(0, [Finalresult]) - {ok, [Finalresult]}; d6(Numdice, [Result]) - d6(Numdice - 1, [random:uniform(6) | Result]). When I run the program from my console like so... dice2:d6(1). ...I get a random number between one and six like expected. However when I run the same function with any number higher than one as an argument I get the following exception... **exception error: no function clause matching dice2:d6(1, [4|3]) ... I know I I don't have a function with matching arguments but I don't know how to write a function with variable arguments, and a variable number of arguments. I tried modifying the function in question like so.... d6(Numdice, [Result]) - Newresult = [random:uniform(6) | Result], d6(Numdice - 1, Newresult). ... but I got essentially the same error. Anyone know what is going on here?

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  • Is this ISession handled by the SessionScope - Castle ActiveRecord

    - by oillio
    Can I do this? I have the following in my code: public class ARClass : ActiveRecordBase<ARClass> { ---SNIP--- public void DoStuff() { using (new SessionScope()) { holder.CreateSession(typeof(ARClass)).Lock(this, LockMode.None); ...Do some work... } } } So, as I'm sure you can guess, I am doing this so that I can access lazy loaded references in the object. It works great, however I am worried about creating an ISession like this and just dropping it. Does it get properly registered with the SessionScope and will the scope properly tare my ISession down when it is disposed of? Or do I need to do more to manage it myself?

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  • Service haproxy error

    - by user128296
    I want to configure Haproxy for outgoing mail load balancing. my configuration file /etc/haproxy.cfg is. global maxconn 4096 # Total Max Connections. This is dependent on ulimit daemon nbproc 4 # Number of processing cores. Dual Dual-core Opteron is 4 cores for example. defaults mode tcp listen smtp_proxy 199.83.95.71:25 mode tcp option tcplog balance roundrobin # Load Balancing algorithm ## Define your servers to balance server r23.lbsmtp.org 74.117.x.x:25 weight 1 maxconn 512 check server r15.lbsmtp.org 199.71.x.x:25 weight 1 maxconn 512 check And when i start service haproxy i get this error. Starting HAproxy: [ALERT] 244/172148 (7354) : cannot bind socket for proxy smtp_proxy. Aborting. Please tell me where i am doing mistake.help will appreciated.

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  • Mongodb using db.help() on a particular db command

    - by user1325696
    When I type db.help() It returns DB methods: db.addUser(username, password[, readOnly=false]) db.auth(username, password) ... ... db.printShardingStatus() ... ... db.fsyncLock() flush data to disk and lock server for backups db.fsyncUnock() unlocks server following a db.fsyncLock() I'd like to find out how to get more detailed help for the particular command. The problem was with the printShardingStatus as it returned "too many chunks to print, use verbose if you want to print" mongos> db.printShardingStatus() --- Sharding Status --- sharding version: { "_id" : 1, "version" : 3 } shards: { "_id" : "shard0000", "host" : "localhost:10001" } { "_id" : "shard0001", "host" : "localhost:10002" } databases: { "_id" : "admin", "partitioned" : false, "primary" : "config" } { "_id" : "dbTest", "partitioned" : true, "primary" : "shard0000" } dbTest.things chunks: shard0001 12 shard0000 19 too many chunks to print, use verbose if you want to for ce print I found that for that particular command I can specify boolean parameter db.printShardingStatus(true) which wasn't shown using db.help().

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  • Help me write my LISP :) LISP environments, Ruby Hashes...

    - by MikeC8
    I'm implementing a rudimentary version of LISP in Ruby just in order to familiarize myself with some concepts. I'm basing my implementation off of Peter Norvig's Lispy (http://norvig.com/lispy.html). There's something I'm missing here though, and I'd appreciate some help... He subclasses Python's dict as follows: class Env(dict): "An environment: a dict of {'var':val} pairs, with an outer Env." def __init__(self, parms=(), args=(), outer=None): self.update(zip(parms,args)) self.outer = outer def find(self, var): "Find the innermost Env where var appears." return self if var in self else self.outer.find(var) He then goes on to explain why he does this rather than just using a dict. However, for some reason, his explanation keeps passing in through my eyes and out through the back of my head. Why not use a dict, and then inside the eval function, when a new "sub-environment" needs to be created, just take the existing dict and update the key/value pairs that need to be updated, and pass that new dict into the next eval? Won't the Python interpreter keep track of the previous "outer" envs? And won't the nature of the recursion ensure that the values are pulled out from "inner" to "outer"? I'm using Ruby, and I tried to implement things this way. Something's not working though, and it might be because of this, or perhaps not. Here's my eval function, env being a regular Hash: def eval(x, env = $global_env) ........ elsif x[0] == "lambda" then ->(*args) { eval(x[2], env.merge(Hash[*x[1].zip(args).flatten(1)])) } ........ end The line that matters of course is the "lambda" one. If there is a difference, what's importantly different between what I'm doing here and what Norvig did with his Env class? If there's no difference, then perhaps someone can enlighten me as to why Norvig uses the Env class. Thanks :)

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  • directx audio video error message in debugmode

    - by clamp
    I have a c#/winforms application that uses directx to play some video and audio. whenever i start my application in debugmode i get this annoying message. i can click "continue" and everything seems to work fine. but i still want to get rid of this message. it does not show up in releasemode. Managed Debugging Assistant 'LoaderLock' has detected a problem in 'C:\pathtoexe.exe'. Additional Information: DLL 'C:\WINDOWS\assembly\GAC\Microsoft.DirectX.AudioVideoPlayback\1.0.2902.0__31bf3856ad364e35\Microsoft.DirectX.AudioVideoPlayback.dll' is attempting managed execution inside OS Loader lock. Do not attempt to run managed code inside a DllMain or image initialization function since doing so can cause the application to hang.

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  • TSQL ID generation

    - by Markus
    Hi. I have a question regarding locking in TSQL. Suppose I have a the following table: A(int id, varchar name), where id is the primary key, but is NOT an identity column. I want to use the following pseudocode to insert a value into this table: lock (A) uniqueID = GenerateUniqueID() insert into A values (uniqueID, somename) unlock(A) How can this be accomplished in terms of TSQL? The computation of the next id should be done with the table A locked in order to avoid other sessions to do the same operation at the same time and get the same id.

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  • Does Windows 7 have a Kiosk Mode?

    - by Jordan
    I'm writing a Kiosk on a Windows 7 computer. The Kiosk is on a touch screen computer, that will not have a keyboard. The application is a WPF application running the .NET Framework version 3.5. I'm having problems with the progress bar task bar showing up (blinking) at the bottom of the screen. This unfortunately gives the user access to the background operating system. Is there someway to lock a full screen application window into the front of the screen without using it on-top-of-everything mode. Some sort of Kiosk mode, or some tool that was designed for this.

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  • PostgreSQL pgdb driver raises "can't rollback" exception

    - by David Parunakian
    Hello, for some reason I'm experiencing the Operational Error with "can't rollback" message when I attempt to roll back my transaction in the following context: try: cursors[instance].execute("lock revision, app, timeout IN SHARE MODE") cursors[instance].execute("insert into app (type, active, active_revision, contents, z) values ('session', true, %s, %s, 0) returning id", (cRevision, sessionId)) sAppId = cursors[instance].fetchone()[0] cursors[instance].execute("insert into revision (app_id, type) values (%s, 'active')", (sAppId,)) cursors[instance].execute("insert into timeout (app_id, last_seen) values (%s, now())", (sAppId,)) connections[instance].commit() except pgdb.DatabaseError, e: connections[instance].rollback() return "{status: 'error', errno:4, errmsg: \"%s\"}"%(str(e).replace('\"', '\\"').replace('\n', '\\n').replace('\r', '\\r')) The driver in use is PGDB. What is fundamentally wrong here?

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  • Firefox, prevent rendering between javascript statements.

    - by Erik
    I'm trying to create some kind of zoom around the mouse cursor feature on my website which ultimately runs these two lines (+ the same for height/scrollTop). canvas.style.width = someValue; canvas.parentNode.scrollLeft = someOtherValue; The problem is that in firefox(3.6) the page is re-rendered directly after the first row has been executed and since the view is depending on both values this means that every time i recalculate the view firefox will will render an invalid view before the correct one, in other words creating flicker. I've tried swapping the two rows but get the same problem. In chrome, opera and IE this doesn't happen. Both lines are executed before any rendering is done. Is there any way to lock the rendering manually, maybe something like this? document.disableRendering(); //fantasy function canvas.style.width = someValue; canvas.parentNode.scrollLeft = someOtherValue; document.enableRendering(); //fantasy function

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  • Plotting an Arc in Discrete Steps

    - by phobos51594
    Good afternoon, Background My question relates to the plotting of an arbitrary arc in space using discrete steps. It is unique, however, in that I am not drawing to a canvas in the typical sense. The firmware I am designing is for a gcode interpreter for a CNC mill that will translate commands into stepper motor movements. Now, I have already found a similar question on this very site, but the methodology suggested (Bresenham's Algorithm) appears to be incompatable for moving an object in space, as it only relies on the calculation of one octant of a circle which is then mirrored about the remaining axes of symmetry. Furthermore, the prescribed method of calculation an arc between two arbitrary angles relies on trigonometry (I am implementing on a microcontroller and would like to avoid costly trig functions, if possible) and simply not taking the steps that are out of the range. Finally, the algorithm only is designed to work in one rotational direction (e.g. counterclockwise). Question So, on to the actual question: Does anyone know of a general-purpose algorithm that can be used to "draw" an arbitrary arc in discrete steps while still giving respect to angular direction (CW / CCW)? The final implementation will be done in C, but the language for the purpose of the question is irrelevant. Thank you in advance. References S.O post on drawing a simple circle using Bresenham's Algorithm: "Drawing" an arc in discrete x-y steps Wiki page describing Bresenham's Algorithm for a circle http://en.wikipedia.org/wiki/Midpoint_circle_algorithm Gcode instructions to be implemented (see. G2 and G3) http://linuxcnc.org/docs/html/gcode.html

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  • FreeBSD 8 and Samba 3.3 smb_panic

    - by scraft3613
    What is causing samba to crash? Need help diagnosing ... [2010/06/14 16:11:42, 0] lib/fault.c:fault_report(40) =============================================================== [2010/06/14 16:11:42, 0] lib/fault.c:fault_report(41) INTERNAL ERROR: Signal 11 in pid 951 (3.3.8) Please read the Trouble-Shooting section of the Samba3-HOWTO [2010/06/14 16:11:42, 0] lib/fault.c:fault_report(43) From: http://www.samba.org/samba/docs/Samba3-HOWTO.pdf [2010/06/14 16:11:42, 0] lib/fault.c:fault_report(44) =============================================================== [2010/06/14 16:11:42, 0] lib/util.c:smb_panic(1673) PANIC (pid 951): internal error [2010/06/14 16:53:40, 0] smbd/server.c:main(1274) Edit: A bit more info -- log.smbd: [2010/06/14 15:59:02, 0] smbd/server.c:main(1274) smbd version 3.3.8 started. Copyright Andrew Tridgell and the Samba Team 1992-2009 [2010/06/14 15:59:02, 0] printing/print_cups.c:cups_connect(103) Unable to connect to CUPS server localhost:631 - Connection refused [2010/06/14 15:59:02, 0] printing/print_cups.c:cups_connect(103) Unable to connect to CUPS server localhost:631 - Connection refused smb.conf [global] workgroup = WASH netbios name = PROD1 [media] path = /jon/media read only = no guest ok = yes

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  • Why ping another inet machine from MacBook get netgate's ip address?

    - by Xinwang
    I have three machine in my home network connected by a wireless router. One is server installed linux at 192.168.1.1, another is Thinkpad with MS Windows XP at 192.168.1.2, last one is MacBook Pro with Mac OS X 10.6.3 at 192.168.1.3. When I ping the Linux Server from Thinkpad (MS Windows XP) I can get the correct ip address, but when I ping it from Mac I get the global address of my router, like 61.135.181.175. Could you tell me why this happen? And how do I get same ping result on Mac and Windows. Thanks

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  • Likeliness of obtaining same IP address after restarting a router

    - by ?affael
    My actual objective is to simulate logged IPs of web-site users who are all assumed to use dynamically assigned IPs. There will be two kinds of users: good users who only change IP when the ISP assignes a new one bad users who will restart their router to obtain a new IP So what I would like to understand is what assignment mechanics are usually at work here deciding from what pool of IPs one is chosen and whether the probability is uniformly distributed. I know there is no definite and global answer as this process can be adjusted be the ISP but maybe there is something like a technological frame and common process that allows some plausible assumptions. UPDATE: A bad user will restart the router as often as possible if necessary. So here the central question is how many IP changes on average are necessary to end up with a previously used IP.

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  • How can two threads access a common array of buffers with minimal blocking ? (c#)

    - by Jelly Amma
    Hello, I'm working on an image processing application where I have two threads on top of my main thread: 1 - CameraThread that captures images from the webcam and writes them into a buffer 2 - ImageProcessingThread that takes the latest image from that buffer for filtering. The reason why this is multithreaded is because speed is critical and I need to have CameraThread to keep grabbing pictures and making the latest capture ready to pick up by ImageProcessingThread while it's still processing the previous image. My problem is about finding a fast and thread-safe way to access that common buffer and I've figured that, ideally, it should be a triple buffer (image[3]) so that if ImageProcessingThread is slow, then CameraThread can keep on writing on the two other images and vice versa. What sort of locking mechanism would be the most appropriate for this to be thread-safe ? I looked at the lock statement but it seems like it would make a thread block-waiting for another one to be finished and that would be against the point of triple buffering. Thanks in advance for any idea or advice. J.

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  • unique constraint (w/o Trigger) on "one-to-many" relation

    - by elgcom
    To illustrate the problem, I make an example: A tag_bundle consists of one or more than one tags. A unique tag combination can map to a unique tag_bundle, vice versa. tag_bundle tag tag_bundle_relation +---------------+ +--------+ +---------------+--------+ | tag_bundle_id | | tag_id | | tag_bundle_id | tag_id | +---------------+ +--------+ +---------------+--------+ | 1 | | 100 | | 1 | 100 | +---------------+ +--------+ +---------------+--------+ | 101 | | 1 | 101 | +--------+ +---------------+--------+ There can't be another tag_bundle having the combination from tag 100 and tag 101. How can I ensure such unique constraint when executing SQL "concurrently"!! that is, to prevent concurrently adding two bundles with the same tag combination Adding a simple unique constraint on any table does not work, Is there any solution other than Trigger or explicit lock. I come to only this simple way: make tag combination into string, and let it be unique. tag_bundle (unique on tags) tag tag_bundle_relation +---------------+--------+ +--------+ +---------------+--------+ | tag_bundle_id | tags | | tag_id | | tag_bundle_id | tag_id | +---------------+--------+ +--------+ +---------------+--------+ | 1 | 100,101| | 100 | | 1 | 100 | +---------------+--------+ +--------+ +---------------+--------+ | 101 | | 1 | 101 | +--------+ +---------------+--------+ but it seems not a good way :(

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  • Locking down multiple sites in Sitecore

    - by adam
    Hi I have two sites running under one Sitecore 6 installation. The home nodes of the sites are as such: /sitecore/content/Home /sitecore/content/Careers Assuming the primary site is at domain.com, the careers site can be accessed at careers.domain.com. My problem is that, by prefixing the uri with /sitecore/content/, any sitecore item can be accessed by either (sub)domain. For example, I can get to: http://domain.com/sitecore/content/careers.aspx (should be under careers.domain.com) http://careers.domain.com/sitecore/content/home/destinations.aspx (should be under domain.com). I know I can redirect these urls (using IIS7 Redirects or ISAPIRewrite) but is there any way to 'lock' Sitecore down to only serve items under the configured home node for that domain? Thanks, Adam

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  • How to get coordinates when iPhone is locked/sleeping?

    - by lionfly
    For normal situations, the didUpdateToLocation (of CLLocationManager) does not work any more when the lock/sleep button is pushed, and your app cannot get further newLocation coordinates during the locked period. However, some apps CAN track during the locked period, and they will show the correct route when you unlocked and see the Mapview. Obviously there are ways to get the coordinates during the locked period. How to get the coordinates when the iPhone is locked/sleeping? Who has hints and further info, please post. Thanks.

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