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  • jQuery UI problem centering a dialog

    - by marc
    I've got a jQuery dialog box that does display and respond to button clicks correctly. Unfortunately it's always positioned at 0, 0 in the browser window despite my attempts to convince it otherwise. Any ideas? var $dialog = $('<div></div>') .html('my message') .dialog({ autoOpen: false, title: 'my title', position: 'center', bgiframe: true }); $dialog.dialog('option', 'buttons', buttons); $dialog.dialog('option', 'position', "center"); $dialog.dialog("open");

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  • Autocomplete jQuery 1.8-UI JSON Format

    - by Kezzer
    I'm toying with the new autocomplete in jQuery 1.8-UI. I've provided data in the following format ["val1", "val2", "val3"] This is coming from a stored procedure but output as a string. For some reason this doesn't work at all, however, if I supply the same data using a javascript variable var data = ["val1", "val2", "val3"]; Then this works fine. <script type="text/javascript"> $(function() $("#txtClient").autocomplete({ source: "/intranet/common/scripts/IntranetLists.aspx?ListType=C" }); }); </script> I've got a page which supplies whatever data I want using query strings. It's more temporary, but it worked when I previously used bassistence's autocomplete. Any ideas?

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  • Fullscreen image with jquery on window resize?

    - by lauthiamkok
    I am trying to make fullscreen images with jquery when the window resize function is triggered. But I get this kind of result - where you can see a gap at the bottom of the image which I don't know how to fix it. the basic html, <!-- container --> <div id="container" class="container"> <div class="holder-supersize" id="supersize"> <ul class="background-supersize"> <li><a href="#"><img src="styles/images/IMG_0250.jpg" alt="" width="1000" height="667" /></a></li> <li><a href="#"><img src="styles/images/IMG_0255.jpg" alt="" width="667" height="1000" /></a></li> <li class="active"><a href="#"><img src="styles/images/IMG_0323.jpg" alt="" width="1158" height="772" /></a></li> </ul> </div> </div> <!-- container --> jquery for updating image size on window resize, $(document).ready(function(){ $(window).resize(function(){ $(".holder-supersize").each(function() { //Define image ratio & minimum dimensions var minwidth = .5*(640); var minheight = .5*(480); var ratio = 480/640; //Gather browser and current image size var imagewidth = $(this).width(); var imageheight = $(this).height(); var browserwidth = $(window).width(); var browserheight = $(window).height(); //Check for minimum dimensions if ((browserheight < minheight) && (browserwidth < minwidth)){ $(this).height(minheight); $(this).width(minwidth); } else { //When browser is taller if (browserheight > browserwidth){ imageheight = browserheight; $(this).height(browserheight); imagewidth = browserheight/ratio; $(this).width(imagewidth); if (browserwidth > imagewidth){ imagewidth = browserwidth; $(this).width(browserwidth); imageheight = browserwidth * ratio; $(this).height(imageheight); } } //When browser is wider if (browserwidth >= browserheight){ imagewidth = browserwidth; $(this).width(browserwidth); imageheight = browserwidth * ratio; $(this).height(imageheight); if (browserheight > imageheight){ imageheight = browserheight; $(this).height(browserheight); imagewidth = browserheight/ratio; $(this).width(imagewidth); } } } return false; }); }); }); CSS for supersize image /* Supersize -------------------------------------------*/ .holder-supersize { width:100%; height:100%; position:absolute; left:0; top:0; z-index:0; } .background-supersize { width:100%; height:100%; overflow:hidden; position:relative; } .background-supersize li { width:100%; height:100%; overflow:hidden; position:absolute; left:0; top:0; text-align:center; } .background-supersize li img { /* for image with height < width */ /**/ width:100%; height:auto; /* for image with height > width */ /* width:auto; height:100%; */ } .background-supersize li , .background-supersize a, .background-supersize img{ display:none; } .background-supersize .active, .background-supersize .active a, .background-supersize .active img{ display:inline; } This is the link at jsfiddle and this is the link to see the actual product. Any ideas what I have done wrong and how can I fix it?

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  • What does this JavaScript error mean?

    - by Tommy
    Using the “Venkman” JavaScript debugger for Mozilla and getting the following error: XML Parsing Error: not well-formed Location: x-jsd:source?location=http%3A%2F%2F192.168.1.150%2Fscript.js&instance=337 Line Number 557, Column 50:<line><margin x='t'> - </margin><num> 554</num> ?? valid = false;</line> Functions works but I don't understand the error. Any help is appreciated. Thanks. function ValidateCheckBoxes() { var valid; $(document).ready(function(){ if($('input[@name=boxesA]:checked').size() == 0) {     valid = false; } else { valid = true; } }); return valid; }

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  • Fadeout a tiled background image in load using JQuery

    - by user346602
    Hi, I've used JQuery in the past to fade divs in and out successfully. However, I have encountered a situation I can't quite wrap my head around: I am coding a site for a designer who has based the formatting of all the elements on a grid pattern he's created. As he wants the pattern elements to be the same size independent of the browser window, I think I can only do this via a repeating background tiled image in CSS. Now he wants the background pattern (only) to come in dark and fade to very light, while not effecting any of the other elements. Am I right in thinking it's impossible to call a tiled background pattern using a CSS selector? Does anyone have any suggestions of a workaround to this problem?

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  • XML jQuery Problem

    - by Llamabomber
    This code for parsing my xml and appending via jquery seems to work great in every browser but Chrome (Mac only, the windows version of chrome works fine) and explorer. I'm not aware of any glaring issues in the code so I thought some fresh eyes might help. Anyone know what could be causing IE and Chrome on the mac to not append? <script type="text/javascript" charset="utf-8"> $(document).ready(function() { $.ajax({ type: "GET", url: "sitenav.xml", dataType: "xml", success: parseXml }); function parseXml(xml) { $(xml).find("GoogleAnalytics").each(function() { $("li#google_analytics").append('<ul><li>' + $(this).find("NavHeader").text() + '</li></ul>'); }); } }); </script>

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  • JQuery Validation using Remote posts empty data to webservice

    - by user319721
    I'm using the JQuery Validation plugin. I'm using the remote option to make a call to my webservice to check if a company name exists. The webservice only accepts JSON data. I pass the data to the webservice from the Company Input Field in my Form as follows: data: "{'company': '" + $('#Company').val() + "'}" But this always returns a blank value for company so the response is {'company':''} i.e. correct JSON but missing the Company Input Field value. Can anyone shed some light on why I always get a blank value here? Thanks for the help, Ciaran

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  • Select list value undefined in $(document).ready

    - by C. Ross
    I have the following code, which I want to load values on a selection change, and also do the selection load initially (since FF 'saves' the last value of the drop down under certain circumstances). The select part of the function works correctly, but for some reason when calling load2 directly the value of $('#select1').value is undefined, even though when I check the DOM in Firebug right after load select1.value has a value. How can I run the load2 function when select1.value is ready? $(document).ready(function() { //Setup change hook $('#select1').change(function(event) { //Remove the old options right away $('#select2').find('option').remove(); //Load the new options load2(this.value); }); //Do load for current value load2($('#select1').value); });

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  • Update options to jQuery slider via form

    - by Coughlin
    I have a jQuery Slider, and I am trying to make it more dynamic by adding three input fields: min max step I want to take those fields and then onblur update my slider options. I read that you can set options like this: $('.selector').slider('option', 'max', 7); And do the same for min,step, etc along with the other options. I tried playing with it yesterday, but I'm not sure how to get it to update. I am using a form with no submit button, so just change on blur. I know I would get the .val() of the input and set it to a variable then would it be: $('.selector').slider('option', 'max', var_here); Any thoughts?

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  • Auto submit form on clicking specific dropdown - jquery

    - by blasteralfred
    Hi, I have a form like below <form name="testform" id="testform" action="test.php" method="get"> <input name="field1" id="field1" type="text" value=""> <input name="field2" id="field2" type="text" value=""> <select name="dropdown" id="dropdown"> <option value="option1" selected="selected">option1</option> <option value="option2">option2</option> <option value="option3">option3</option> </select> <input type="submit" name="Submit" value="Submit" id="Submit"> </form> I want to submit the form automatically when someone click (or select) an option from the dropdown. How can I make this possible using jquery or something else or simple js. Thanks in advance... :) blasteralfred

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  • JQuery Syntax Problem?

    - by Michael Smith
    I am using JQuery to insert divs into a page but i cant seem to get the quotation marks correctly setup. For example the code below works fine: var newDiv_1 = '<div id="event_1"><b>Hello World 01</b></div>'; $('#mon_Events').append(newDiv_1); But when i try to use variable in place of the normal text, i doesnt seem to work: var eventname = 1; var newDiv_1 = '<div id="event_' . eventName . '"><b>Hello World 01</b></div>'; $('#mon_Events').append(newDiv_1); How do i use variable inside this statement?

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  • Sending JSON(jQuery) to PHP and decoding it

    - by dscher
    I can't for the life of me figure out what I'm doing wrong. It seems like it should be simple because I can't find anyone else with this issue but I can't figure out to send basic data via javascript(jQuery) to PHP and decode it. For the sake of simplicity, this is what I have: JAVASCRIPT var json_data = { "name" : "john doe" }; $.ajax({ type: "POST", url: "../bin/process.php", dataType: "json", data: json_data }); and my PHP FILE $arr = json_decode("json_data", true); $fp = fopen('data.txt', "w"); fwrite($fp, $arr['name']); fclose($fp); The file I'm writing ends up with nothing in it. If I do an: fwrite($fp, 'test'); I get a file with the word test in it but no matter what I do I don't get the json data I sent. Can someone please share a thorough example of A to Z. Thanks for any help.

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  • Jquery code working in all browsers apart from FF

    - by alan
    Hi, I have written the following jquery sitting in the head tags of my HTML It is supposed to bring the image that is being hovered over to full opacity and slide another image over it from the right, then return when un-hovered. <script type="text/javascript"> $(function() { $('ul#img-nav li').css({ "opacity": .5 }); $('ul#img-nav li').hover(function() { $(this).stop(true).animate({"opacity":1}); $(this).children('.overlay').stop(true).animate({"left" : "18px" }); }, function() { $(this).stop(true).animate({"opacity":.5}); $(this).children('.overlay').stop(true).animate({"left" : "180px" }); }); }); This works fine in Safari, Chrome, IE (7,8) but not in FF 3.6. Any suggestions why this might be? Many thanks

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  • jquery: how to append elements to emtpy object

    - by John
    I want to create a set of options, that will be appended to every select in grid column <option> option 1 </option> <option> option 2 </option> ... <option> option N </option> but I don't know how to create a set of elements without parent element. appending to an empty jquery object doesn't work var options = $(''); options.append('<option></option>')

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  • Morphing content based on window part focus

    - by Adrian A.
    What I'm trying to achieve is basically have a code that will morph ( move around the page ) based on the part of the window which is currently viewed. Scenario : - actual page height : 2000px - actual screen height( pc, laptop whatever ) : 800px - 1 image of 600px - 3 div's or virtual boxes ( just to prove what I want to do ) Workflow When you open the page, you'd see the first part of the page with the image loaded in the first div. What I want and need to achieve is when scrolling the page, and the focus would be on the second div ( or the image simply gets out of focus - you can't see it no more ), the image would move ( disappear from the first box ) and appear in the second one, which is currently visible. The idea might seem pretty easy but I'm not Javascript savvy. Ideally, the answer should include a way to load a Javascript instead of that image.

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  • Grab only 2 items from Jquery Loop

    - by Bry4n
    Here is my Jquery $th.each(function(idx) { var notSelected = $(this).text(); if ((notSelected.indexOf(to) != -1) || (notSelected.indexOf(from) != -1)) { if (idx < 10) { $(this).show(); // and show its corresponding td $td.eq(idx).show(); } } }); It is part of a tableFilter type function for a HTML table. However I want it to only display only 2 of the results. I tried instantiating some kind of index counter but I was unsuccessful. Any help or thoughts would be appreciated.

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  • Hiding Options of a Select with JQuery

    - by Syed Abdul Rahman
    Okay, let's start with an example. Keep in mind, this is only an example. <select id = "selection1">     <option value = "1" id = "1">Number 1</option>     <option value = "2" id = "2">Number 2</option>     <option value = "3" id = "3">Number 3</option> </select> Now from here, we have a dropdown with 3 options. What I want to do now is to hide an option. Adding style = "display:none" will not help. The option would not appear in the dropdownlist, but using the arrow keys, you can still select it. Essentially, it does exactly what the code says. It isn't displayed, and it stops there. A JQuery function of $("#1").hide() will not work. Plus, I don't only want to hide the option, I want to completely remove it. Any possibility on doing so? Do I have to use parent/sibling/child elements? If so, I'm still not sure how. Any help on this would be greatly appreciated. Thanks.           Another question - It's related Ok, so I found out that there is a .remove() available in JQuery. Works well. But what if I want to bring it back? if(condition)     {     $(this).remove();     } I can loops this. Shouldn't be complicated. But the thing of which I am trying to do is this: Maximum Capacity of Class: (Input field here) Select Room: (Dropdown here) What I'd like for it to do is to update is Dropdown using a function such as .change() or .keyup. I could create the dropdown only after something is typed. At a change or a keyup, execute the dropdown accordingly. But what I am doing is this: $roomarray = mysql_query("SELECT *     FROM         (         SELECT *,         CASE         WHEN type = 'Classroom' THEN 1         WHEN type = 'Computer laboratory' THEN 2         WHEN type = 'Lecture Hall' THEN 3         WHEN type = 'Auditorium' THEN 4         END AS ClassTypeValue         FROM rooms         ) t     ORDER BY ClassTypeValue, maxppl, roomID"); echo "<select id = \"room\">"; while ($rooms = mysql_fetch_array($roomarray)) { ?> <option value=<?php echo $rooms['roomID']; ?> id=<?php echo $rooms['roomID']; ?>><?php echo $rooms['type']; echo "&nbsp;"; echo $rooms['roomID']; echo "&nbsp;("; echo $rooms['maxppl']; echo ")"; ?></option> <?php } echo "</select>"; Yes, I know it is very messy. I plan to change it later on. But the issue now is this: Can I toggle the removal of the options according to what has been typed? Is it possible to do so with a dropdown made from a loop? Because I sure as hell can't keep executing SQL Queries. Or is that even an option? Because if it's possible, I still think it's a bad one.

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  • jQuery each function, getting the data out of it

    - by Ankur
    I am trying to use the jQuery each function (line 5) to display the results of an AJAX call. when I write resultObj.value on line 6 how come I am not getting any data? Am I making a syntax error (I am pretty sure that I must be)? success : function(resultObj) { count = count+1; $(".objHolder").filter("#"+id).append("<table border='1' cellspacing='4' cellpadding='4' class='preTable' id='"+id+"' level='"+count+"'><tr><td class='preItem' id='"+id+"' level='"+count+"'><img src='images/right.jpg' width='16' height='10' /></td><td class='preList'>&nbsp;</td><td class='preHolder' level='"+count+"'>&nbsp;</td></tr></table>"); isClicked[level]="yes"; $.each(resultObj, function(index, value){ $(".preHolder").filter("#"+id).append(resultObj.value); }); } });

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  • Jquery Ajaxform with input type=file and multifile

    - by crunchingnumbers
    Im using ajax form with multifile. However ajaxform just seems to quietly die and does not do anything if using multifile. Multifile is just a jquery plugin that builds a list of input type=file so that you can upload multiple files at once, before which you can add/delete your file upload list. I've looked at multifile and made one change to ensure that it generated a unique name as well as id which it didn't do before and i've checked the form elements multifile is building which all appear to be correct. From looking at ajaxform, it seems that it shoulld just generate the iframe as normal and post the multiple input type=file but it does nothing. Has anyone else experienced problems with multiple input type=file uploads

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  • Using JQuery Ajax to call a php function

    - by Stevie Jenowski
    Hello! First and foremost thank you for checking out my problem, and for any help you may give! Okay, so like the title says I'm in need of calling a php function from my index page, which adds a new record in my database as a vote, using JQuery Ajax. This function will return one integer, which will then be printed inside the form button in which it was called from. Anyone have an idea on how I would accomplish this? Any guidance is appreciated!

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  • jquery to php (wait for php script until result/finish)

    - by user354051
    Hi, I am executing a php call from javascript(jQuery), php sript is sending result back. The problem is that these php scripts are taking some time (milliseconds), and java script is not waiting for them to finish, thus variables are not getting initialized with correct values. The code is simple: $.get("php/validation.php",{'email':email},function(data){ // valid_email now contains true/false alert(data); if(data=="true"){ var valid_email = true;} }); The "alert" is printing true but value of valid_mail is recognized as "false" in the code below. Is there any other better way to call php scripts and wait for until they are not finished? Prashant

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  • How to read from CSS files with jQuery

    - by Neurofluxation
    Ok, I have a HTML page with jQuery included. I have a CSS file with a good load of lines in, I would like to read all styles for a given element from the external CSS file... Not the inline styles... I have the following code (which looks like it should work...): var styleProperties= {}; var getCssProperties = ['width', 'margin', 'height']; for (c=0;i<=returnStyleProps.length;c++) { styleProperties[returnStyleProps[c]] = $('div#container').css(returnStyleProps[c]); alert(styleProperties); } alert(styleProperties); But this only seems to alert: "[Object Object]" Any ideas you clever people?

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  • Get a CSS value from external style sheet with Javascript/jQuery

    - by Acorn
    Is it possible to get a value from the external CSS of a page if the element that the style refers to has not been generated yet? (the element is to be generated dynamically). The jQuery method I've seen is $('element').css('property','value');, but this relies on element being on the page. Is there a way of finding out what the property is set to within the CSS rather than the computed style of an element? Will I have to do something ugly like add a hidden copy of the element to my page so that I can access its style attributes?

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  • jQuery UI get the sorted position of LI element in UL

    - by PeterBZ
    I'm using jQuery UI's sortable for my UL list. Each time the user sorts the list, I want each li element to update it's "position" attribute to it's position in the list. <ul> <li position="1">a</li> <li position="2">b</li> <li position="3">c</li> </ul> So when a user swaps c with a, the position will also update. I tried to use .each but it seems that javascript doesn't follow the order of how the LI elements are displayed but the order of the element's creation.

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