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  • MapKit Annotations and User location

    - by teddafan
    Hi all, I followed this tutorial to make my first app: http://icodeblog.com/2009/12/21/introduction-to-mapkit-in-iphone-os-3-0/ I would really like to know how to sort the annotations in the Table in order of distance to the user (the nearest annotation is the first one on the table) How is it possible to do that? I understand that I must use the CLLocation to find the user's location but then I have no idea. Could any one help me? Cheers, Thank you in advance for your much appreciated help, teddafan

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  • Format fixed-format text file lines

    - by EugeneP
    there's a text file first second third 1 2 3 yes no ok hmmmmmmm yep_a_long_word_it_is ahahahahahahha what java functions /libs to use to align words so that they are looked like this (fixed width based on the longest column's length), let's say center align: first second third 1 2 3 yes no ok hmmmmmmm yep_a_long_word_it_is ahahahahahahha

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  • isPostBack as Query Parameter

    - by Steven
    I created an ASPX page with search controls to the left bound as controls for an AccessDataSource. I want the data grid to be blank on the first calling of the page, but show the results for subsequent page loads. I plan to achieve this by putting [pFirstRun] = False as my first WHERE condition with the parameter pFirstRun tied to the value isPostBack. How do I achieve this? Alternatively, is there a better way to achieve this goal?

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  • Android - Nesting ViewFlippers

    - by user286285
    Hi, I want to nest several viewflippers. is this possible? I have not been successful thus far. My first tier flips as required but when I flip to the first nested viewflipper its contents appear blank and I can't "flip" it my views are V1 V2 V3 - H1 , H2, H3 One I flip to V3 vertically ... H1 does not appear. where as H is my Horizontal flipper group. Neil

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  • C stdout printf problem

    - by silverbandit91
    I have a weird issue with printing data out. I use printf to print a char* string and then after that print another one. However part of the first string doesn't get printed and when I print the second string the missing part of the first one is pretended to that one. What is happening here?

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  • Mysql order by using two columns

    - by Krishna Priya
    Hi, I am using a table which has Createdon and Lastmodifiedon fields, I have to display first the newly added record based on createdon and then followed by lastmodifiedon records using mysql. I have tried adding "ORDER BY Createdon,Lastmodifiedon desc" at the end of the query;but sorting based on first column only occurs. Anyone please help in this issue Thanks.

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  • jQuery click(): overriding previously-bound click events

    - by JamesBrownIsDead
    When I use this code with an element whose id is "foobar": $("#foobar").click(function () { alert("first"); }); $("#foobar").click(function () { alert("second"); }); I get two alerts: "first" and "second" second. How do I specify a click event that also clears out any previous click events attached to the element? I want the last $("#foobar").click(...) to erase any previously bound events.

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  • Can I parse uri from resource?

    - by DYH1919
    // startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(getString(R.string.donate_url)))); startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.google.com"))); when I use the first,app will crash in emulator but the second run well, how can I fix the first? thanks for help

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  • mysql UNION query not working

    - by kalpaitch
    What am I doing wrong with this: $sql = "SELECT * FROM content WHERE threadName LIKE '%$filter%' ORDER BY lastUpdated desc UNION SELECT * FROM content WHERE threadName NOT LIKE '%$filter%' ORDER BY lastUpdated desc"; The first statement before the UNION works well on its own, but this one above returns: mysql_fetch_array() warning - supplied argument is not a valid MySQL result resource Am I right in believing that UNION will not return duplicate entries, in which case the second SELECT statement doesn't need to have the NOT LIKE but will just return everything that wasn't listed in the first statement.

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  • Can i pop to Specific ViewController?

    - by Ankit Vyas
    Hello!I am using Navigation Based Application.I push First ViewController to Second ViewController and From Second ViewController to Third ViewController Now I want to Pop From Third ViewController to First ViewController.I am Performing This task using the Below Code but i application get's Terminate.Please any body give me some proper Guidelines.I can't use pop to RootViewController because it's Different ViewController.Thanks in Advance... In Third ViewControler i have Written this: FirstViewCtr *x=[[FirstViewCtr alloc] initWithNibName:@"FirstViewCtr" bundle:nil]; [self.navigationController popToViewController:x animated:NO];

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  • Doing will_paginate pages calculation around a record

    - by Anderson De Andrade
    I'm displaying a list of events. I wanted displayed the page with the events for today by default. That was easy accomplished by: page = number_of_records_before_RECORD / number_of_pages + 1 Now I want to display the first item of today's events as the first item in that page. Maybe there is a way to generate page numbers around a record with negative values to get back.

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  • shell function and environment

    - by Michael
    How in Makefile export variable first then make another variable's expansion? somevar := apple export somevar update = $(shell perl -e 'print "$$ENV{somevar}"') all: @echo $(update) For some reason the expansion takes place first, then export. As a result the output is empty.

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  • What is the "opposite" of request serialization called?

    - by Adam Lindberg
    For example, if a request is made to a resource and another identical request is made before the first has returned a result, the server returns the result of the first request for the second request as well. This to avoid unnecessary processing on the resource. This is not the same thing as caching/memoization since it only concerns identical requests ongoing in parallel. Is there a term for the reuse of results for currently ongoing requests to a resource for the purpose of minimizing processing?

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  • Core data, sorting one-to-many child objects

    - by Shizam
    So if I have a store of parents children and the parent has a one to many relationship to children (parent.children) and they all have first names. Now, on the initial fetch for parents I can specify a sort descriptor to get them back in order of first name but how can I request the children in order? If I do a [parent.children allObjects] it just gives them back in a jumble and I'd have to sort after the fact, every time. Thanks, Sam

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  • stored as array understanding mongoid

    - by Gagan
    Hello frens, This is not a problem, but I just want to know stored as array of Mongoid better. I have following code in my model. class Company include Mongoid::Document include Mongoid::Timestamps references_many :people, :stored_as => :array, :inverse_of => :companies end class Person include Mongoid::Document include Sunspot::Mongoid references_many :companies, :stored_as => :array, :inverse_of => :people end Now in Company object we get person_ids as a result of stored_as array and company_ids in Person object. Now initially I inserted lots of person in company and the ids in person_ids fields is huge. Now I deleted most of person from company down to 8 people. Now I don't get why person_ids fields of Company object storing all the deleted ids of person. My console snapshot is follwing ruby-1.9.2-head Company.first.person_ids = [BSON::ObjectId('4d12d2907adf350695000025'), BSON::ObjectId('4d12d2907adf35069500002c'), BSON::ObjectId('4d12d2907adf350695000035'), BSON::ObjectId('4d12d2907adf35069500003f'), BSON::ObjectId('4d12d2907adf350695000048'), BSON::ObjectId('4d12d2907adf350695000052'), BSON::ObjectId('4d12d2907adf350695000059'), BSON::ObjectId('4d12d2907adf350695000062'), BSON::ObjectId('4d12d4017adf35069500008d'), BSON::ObjectId('4d12d4017adf350695000094'), BSON::ObjectId('4d12d4017adf35069500009d'), BSON::ObjectId('4d12d4017adf3506950000a7'), BSON::ObjectId('4d12d4017adf3506950000b0'), BSON::ObjectId('4d12d4017adf3506950000ba'), BSON::ObjectId('4d12d4017adf3506950000c1'), BSON::ObjectId('4d12d4017adf3506950000ca'), BSON::ObjectId('4d12d48a7adf3506950000f5'), BSON::ObjectId('4d12d48a7adf3506950000fc'), BSON::ObjectId('4d12d48a7adf350695000108'), BSON::ObjectId('4d12d48b7adf350695000115'), BSON::ObjectId('4d12d48b7adf350695000121'), BSON::ObjectId('4d12d48b7adf35069500012e'), BSON::ObjectId('4d12d48b7adf350695000135'), BSON::ObjectId('4d12d48b7adf350695000141'), BSON::ObjectId('4d12d53e7adf35069500016f'), BSON::ObjectId('4d12d53e7adf350695000176'), BSON::ObjectId('4d12d53e7adf350695000182'), BSON::ObjectId('4d12d53e7adf35069500018f'), BSON::ObjectId('4d12d53e7adf35069500019b'), BSON::ObjectId('4d12d53f7adf3506950001a8'), BSON::ObjectId('4d12d53f7adf3506950001af'), BSON::ObjectId('4d12d53f7adf3506950001bb'), BSON::ObjectId('4d12d8587adf3506950001e9'), BSON::ObjectId('4d12d8587adf3506950001f0'), BSON::ObjectId('4d12d8587adf3506950001ff'), BSON::ObjectId('4d12d8597adf35069500020f'), BSON::ObjectId('4d12d8597adf35069500021e'), BSON::ObjectId('4d12d8597adf35069500022e'), BSON::ObjectId('4d12d8597adf350695000235'), BSON::ObjectId('4d12d85a7adf350695000244'), BSON::ObjectId('4d12d9587adf35069500025b'), BSON::ObjectId('4d12db8b7adf35069500026a'), BSON::ObjectId('4d12de6f7adf3509c9000024'), BSON::ObjectId('4d12de6f7adf3509c900002b'), BSON::ObjectId('4d12de6f7adf3509c900003a'), BSON::ObjectId('4d12de707adf3509c900004a'), BSON::ObjectId('4d12de707adf3509c9000059'), BSON::ObjectId('4d12de707adf3509c9000069'), BSON::ObjectId('4d12de707adf3509c9000070'), BSON::ObjectId('4d12de717adf3509c900007f'), BSON::ObjectId('4d12e7f27adf350bd2000009'), BSON::ObjectId('4d12e81f7adf350bd2000015'), BSON::ObjectId('4d12e87f7adf350bd2000024'), BSON::ObjectId('4d12e8b87adf350bd200004c'), BSON::ObjectId('4d12e8b97adf350bd2000053'), BSON::ObjectId('4d12e8b97adf350bd200005c'), BSON::ObjectId('4d12e8b97adf350bd2000066'), BSON::ObjectId('4d12e8b97adf350bd200006f'), BSON::ObjectId('4d12e8b97adf350bd2000079'), BSON::ObjectId('4d12e8ba7adf350bd2000080'), BSON::ObjectId('4d12e8ba7adf350bd2000089'), BSON::ObjectId('4d12ee6b7adf350bd2000198'), BSON::ObjectId('4d12ee6b7adf350bd200019f'), BSON::ObjectId('4d12ee6c7adf350bd20001a5'), BSON::ObjectId('4d12ee6c7adf350bd20001ac'), BSON::ObjectId('4d12ee6c7adf350bd20001b2'), BSON::ObjectId('4d12ee6c7adf350bd20001b9'), BSON::ObjectId('4d12ee6c7adf350bd20001c0'), BSON::ObjectId('4d12ee6c7adf350bd20001c6'), BSON::ObjectId('4d141ca57adf35033e00006e'), BSON::ObjectId('4d141ca57adf35033e000075'), BSON::ObjectId('4d1420aa7adf350705000003'), BSON::ObjectId('4d1420aa7adf35070500000a'), BSON::ObjectId('4d1420f47adf350705000011'), BSON::ObjectId('4d1420f57adf350705000015'), BSON::ObjectId('4d1420f57adf350705000018'), BSON::ObjectId('4d1420f57adf35070500001c'), BSON::ObjectId('4d1420f57adf350705000023'), BSON::ObjectId('4d1420f57adf350705000026'), BSON::ObjectId('4d14215f7adf35070500004b'), BSON::ObjectId('4d14215f7adf350705000052'), BSON::ObjectId('4d14215f7adf350705000055'), BSON::ObjectId('4d14215f7adf350705000059'), BSON::ObjectId('4d14215f7adf35070500005c'), BSON::ObjectId('4d14215f7adf350705000060'), BSON::ObjectId('4d14215f7adf350705000067'), BSON::ObjectId('4d14215f7adf35070500006a')] Company.first.people.collect(&:id) = [BSON::ObjectId('4d14215f7adf35070500004b'), BSON::ObjectId('4d14215f7adf350705000052'), BSON::ObjectId('4d14215f7adf350705000055'), BSON::ObjectId('4d14215f7adf350705000059'), BSON::ObjectId('4d14215f7adf35070500005c'), BSON::ObjectId('4d14215f7adf350705000060'), BSON::ObjectId('4d14215f7adf350705000067'), BSON::ObjectId('4d14215f7adf35070500006a')] Isn't the Company.first.person_ids array be only storing the ids shown by Company.first.people.collect(&:id) It would be helpful if some one tell me when to best use stored_as = :array method. Do stored_as = :array increase querying performance? Thanks

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  • SQL Server Select Distinct

    - by homam
    I want to write a query like this: For a table that has these columns: ColA ColB ColC, ColD select first(ColA, ColB, ColC, ColD) distinct(ColB, ColC) from table order by ColD The query is supposed to order the table by ColD, then group the results by the combination of ColB and ColC (they may have different data types) and returns the first rows (with all the columns of the table) in the groups. How is it possible in MS SQL Server 2005?

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  • Codeigniter: Checklist for new users & logistics of app

    - by Kevin Brown
    I'm developing my first web-app, and I'm working through logistics. New users (At first login) need to complete a few things before they can use the app fully. For example, they need to complete their profile before they can move on to step 2, which is taking a test. What's the best way to go about creating a "new-user" checklist? I want it to be as simple as possible, coding wise, and as easy as possible for the user.

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  • I don't find the sql request

    - by user301089
    Hi everybody, Here it's my problem I've a list of the following measure : src1 dst2 24th december 2009 src1 dst3 22th december 2009 src1 dst2 18th december 2009 I would like to have just the latest measures with a sql request - 2 first lines in my case because the pairs(src and dst) aren't the same. I try to use DISTINCT but I have just the 2 first columns and I will all columns. I try too GROUP BY but I hadn't success. Anyone can help me ? Thx Narglix

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  • VB.net Reading from ListViews with Multiple Columns

    - by xzerox
    Alright. So I was able to find out how to read from the first column but I need to read from both of them. I am using full row select which I need on there. Here is the code I am using to get it for the first column. Dim I As Integer For I = 0 To ListView1.SelectedItems.Count - 1 MsgBox(ListView1.SelectedItems(I).Text) Next MessageBox.Show(ListView1.Columns(0).Text)

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  • How to label each equation in align environment?

    - by Tim
    Hi, I wonder how to label each equation in align environment? For example \begin{align} \label{eq:lnnonspbb} \lambda_i + \mu_i = 0 \\ \mu_i \xi_i = 0 \\ \lambda_i [y_i( w^T x_i + b) - 1 + \xi_i] = 0 \end{align} only label the first equation and only the first equation can be referred later. Thanks and regards!

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