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• How would I change the DocumenRoot on the version of Apache that came pre-installed on my Mac OS X s

  - by racl101

  OK, so I want to take advantage of the Apache server that comes installed on my Mac OS X system (which means, I would like not to have to install my own version of Apache since I might as well tryto use what comes bundled), and as such, I went to change some settings in the configuration file: /etc/apache2/httpd.conf Namely, I changed the these two lines: DocumentRoot "/Users/myusername/Sites" <Directory "/Users/myusername/Sites"> So that they initially pointed to a folder in my Dropbox folder (so I could have my docs sync to my Dropbox): DocumentRoot "/Users/myusername/Dropbox/public_html" <Directory "/Users/myusername/Dropbox/public_html"> That didn't work. So then I figured, ok maybe it was too much to ask to make folder in my Dropbox be my document root. So then I thought, what if I make the Document root another folder of my choosing like so: DocumentRoot "/Users/myusername/dev-sites/public_html" <Directory "/Users/myusername/dev-sites/public_html"> and that didn't work either. After looking within the httpd.conf file for clues it seems that only two directories appear to work as Document root paths for the Apache that comes bundled with Mac OS X: /Users/myusername/Sites (or ~/Sites) and /Library/WebServer/Documents/ But trying to use any other directories didn't seem to work. I would get 403 errors on my browser. I was wondering if there was some other settings to change on the httpd.conf file or any permissions to set to make this work. Any help would be appreciated and many thanks in advance.

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• How can I password protect & let cgi-bin to work?

  - by jaaaaaaax

  This is taken from sites-available directory. It's a virtual host setting for apache. Accessing myiphere/cgi-bin/ throws 403. The directory setting for /var/www2/ drwxrwxrwx 8 www-data www-data NameVirtualHost myiphere <VirtualHost myiphere> ServerAdmin webmaster@localhost DocumentRoot /var/www2/ <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www2/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined ServerSignature On Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory>

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• How to Access User Directory shared by Apache on OS X Mountain Lion?

  - by schluchc

  When trying to access the local user web page on localhost/~username, I get a "403 Forbidden". The system web page in /Library/WebServer/Documents is accessible on localhost/ though, so I assume Apache is working fine. I know that this problem has been discussed several times, also on superuser. I implemented and checked all I could find, but I still couldn't solve the problem and would be glad if someone had a suggestion for this particular case: sudo apachectl -t returns Syntax OK. I have a username.conf file in /etc/apache2/users/: <Directory "/Users/username/Sites/"> Options Indexes MultiViews FollowSymLinks AllowOverride AuthConfig Limit Order allow,deny Allow from all </Directory> as proposed here [SuperUser] and in several other tutorials. The permissions of the username.conf file are -rw-r--r-- root wheel, as they should be. The httpd.conf is unchanged and therefore contains the line Include /private/etc/apache2/extra/httpd-userdir.conf. That file in turn contains UserDir Sites Include /private/etc/apache2/users/*.conf <IfModule bonjour_module> RegisterUserSite customized-users </IfModule> So the httpd*.conf files should be ok. The permissions of /Users/username/Sites is drwxr-xr-x 10 username staff and -rw-r--r--@ 1 username staff for the index.html. In the error log I simply get a [Sun Nov 25 22:14:32 2012] [error] [client 127.0.0.1] (13)Permission denied: access to /~username/ denied. And yes, after each change I did the sudo apachectl restart. Any help no how to solve the problem or how to further analyze it would be highly appreciated!

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• Nginx Config - I can't access WordPress admin area

  - by WebDevDude

  I am a complete noob when it comes to Nginx, but I'm trying to make the switch over for my WordPress site. Everything works, even the permalink, but I can't access my WordPress admin directory (I get a 403 error). I have my WordPress install in a subfolder, so that complicates things a bit for me. Here is my Nginx config file: server { server_name mydomain.com; access_log /srv/www/mydomain.com/logs/access.log; error_log /srv/www/mydomain.com/logs/error.log; root /srv/www/mydomain.com/public_html; location / { index index.php; # This is cool because no php is touched for static content. # include the "?$args" part so non-default permalinks doesn't break when using query string try_files $uri $uri/ /index.php?$args; } location /myWordpressDir { try_files $uri $uri/ /myWordpressDir/index.php?$args; } location ~ \.php$ { include /etc/nginx/fastcgi_params; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME /srv/www/mydomain.com/public_html$fastcgi_script_name; fastcgi_split_path_info ^(/myWordpressDir)(/.*)$; } location ~* ^.+\.(ogg|ogv|svg|svgz|eot|otf|woff|mp4|ttf|rss|atom|jpg|jpeg|gif|png|ico|zip|tgz|gz|rar|bz2|doc|xls|exe|ppt|tar|mid|midi|wav|bmp|rtf)$ { access_log off; log_not_found off; expires max; } }

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• sub application and virtual directory file permissions

  - by Zeus

  I have a website setup in IIS7, exampledomain.com. Under the application exampledomain.com lives a sub application cms. In a rather convoluted way, we have content in our cms system in this sub-app, under cms\content\{generatedfoldername}. So to access an image in this content, the full URL would be http://www.exampledomain.com/cms/cms/content/{generatedfoldername}/image.jpg, (yes, cms twice...) and this works just fine. Now, we have a virtual directory under the parent website, called stuff which points at the content of the cms. So I should be able to get to the image using the url http://www.exampledomain.com/stuff/{generatedfoldername}/image.jpg. Unfortunately this gives a server 500 error "There is a problem with the resource you are looking for, and it cannot be displayed." Whilst you do have to log into the cms system to access any of the admin pages within, I don't think the image files are protected by login, or else the first example URL wouldn't work, right? Also it's a server 500 error, rather than a 403. I'm sure I must be missing something obvious here- will the virtual directory be using the permissions defined in the parent application, or the subapplication to which it is pointing? Or is there some other permissions I may have missed? Sorry, that was a bit long, thanks for reading all the way down here! (I also must point out that I'm pretty new to the server management stuff.) edit: also, we have <location path="." inheritInChildApplications="false"> specified in the webconfig of the parent app, so it's hopefully not the issue described in this config file hierarchy article.

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• Can't ssh from CentOS 6.5 to SUSE LINUX 10.1

  - by Pavel Tankov

  We have a quite old installation of SUSE LINUX 10.1 (i586) in the office. The problem shortly: I can successfully ssh to it from machines in the same LAN (192.168.1.0) and not from others (that are in 10.23.0.0). The SuSE has SSH server openssh-4.2p1-18.12. I have ruled out the firewall and hosts.allow and hosts.deny files. When my ssh login attempt fails, here is what the logs say: on the client: $ ssh -vvv 192.168.1.5 OpenSSH_5.3p1, OpenSSL 1.0.1e-fips 11 Feb 2013 debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug2: ssh_connect: needpriv 0 debug1: Connecting to 192.168.1.5 [192.168.1.5] port 22. debug1: Connection established. debug1: identity file /home/nbuild/.ssh/identity type -1 debug1: identity file /home/nbuild/.ssh/identity-cert type -1 debug1: identity file /home/nbuild/.ssh/id_rsa type -1 debug1: identity file /home/nbuild/.ssh/id_rsa-cert type -1 debug1: identity file /home/nbuild/.ssh/id_dsa type -1 debug1: identity file /home/nbuild/.ssh/id_dsa-cert type -1 on the server: Aug 21 16:34:25 serverhost sshd[20736]: debug3: fd 4 is not O_NONBLOCK Aug 21 16:34:25 serverhost sshd[20736]: debug1: Forked child 20739. Aug 21 16:34:25 serverhost sshd[20736]: debug3: send_rexec_state: entering fd = 7 config len 403 Aug 21 16:34:25 serverhost sshd[20736]: debug3: ssh_msg_send: type 0 Aug 21 16:34:25 serverhost sshd[20736]: debug3: send_rexec_state: done Aug 21 16:34:25 serverhost sshd[20739]: debug1: rexec start in 4 out 4 newsock 4 pipe 6 sock 7 Aug 21 16:34:25 serverhost sshd[20739]: debug1: inetd sockets after dupping: 3, 3 Aug 21 16:34:25 serverhost sshd[20739]: debug3: Normalising mapped IPv4 in IPv6 address Aug 21 16:34:25 serverhost sshd[20739]: Connection from 10.23.1.11 port 44340 The above log on the server is when I enable DEBUG3 log level. However, with the default log level (INFO), the only thing the server logs is this: Aug 21 16:38:32 serverhost sshd[20749]: Did not receive identification string from 10.23.1.11 Any hints? I feel I've tried everything already.

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• How do I setup an Alias on Apache with XAMPP on Linux ? (Permission problem)

  - by knarf

  XAMPP works fine but I want to have http://localhost/f to point to /home/knarf/prog/php/fwyxz. I've chmod -R 777 /home/knarf/prog/php/fwyxz I've added Alias /f /home/knarf/prog/php/fwyxz at the end of the httpd.conf And when I try to access it, I get a 403. From the apache error_log: [error] [client 127.0.0.1] (13)Permission denied: access to /f denied. I've already tried several solutions (userdir and symlinks) but they both failed with the same error. I've also tried to add this after the Alias: <Directory "/home/knarf/prog/php/fwyxz"> Order allow,deny Allow from all </Directory> But again, permission denied. Now if I change the User/Group under which apache runs from nobody to knarf, it seems to work (static files are ok) but PHP can't use/initialize sessions : [error] [client 127.0.0.1] PHP Warning: session_start() [function.session-start]: open(/tmp/sess_r5nrmu4ugqguqqe83rs53lq6k0, O_RDWR) failed: Permission denied (13) in /home/knarf/prog/php/fwyxz/index.php on line 3 [error] [client 127.0.0.1] PHP Warning: Unknown: open(/tmp/sess_r5nrmu4ugqguqqe83rs53lq6k0, O_RDWR) failed: Permission denied (13) in Unknown on line 0 [error] [client 127.0.0.1] PHP Warning: Unknown: Failed to write session data (files). Please verify that the current setting of session.save_path is correct () in Unknown on line 0 This is really frustrating.

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• Website and file/directory permissions

  - by mathiass

  I've been given a task to fix this one website. One of its issues is that on one page, the images have broken links - the images are not showing, and clicking on the image (i.e. direct link to the image file) results in a 403 (Forbidden) error. I am looking for some feedback on what could be the possible cause. The directory where the images are stored has the following permissions: drwxrws--- www "group" 10240 Aug 2008 "image directory name" I had to hide the names. I checked the page source code, and everything seems to be in place. The rest of the site, and other images outside that image directory are showing fine. I was told that recently there have been some changes to the server. I'm trying to assume that there is no fault in the source code, and the permissions are - or used to be - correct (since the site has been working before, and no recent changes to the site itself have been made). My only thoughts at the moment is that either: a) the directory permission should be: drwxrws--x (executable) for the other users, or b) there is a change in the server settings that I don't know of. Is there anything else I should check?

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• Apache directory access with virtual host [SOLVED]

  - by alexeygaidamaka

  I have a virtual host with a configuration like that. When i'm trying to get into foobar.com/dir providing valid username/password pair i get 403 forbidden page instead of that directory contents. www.foobar.com/dir has 777 rights, .httpaswd is chmoded 644. But i can't figure out why i am still not seeing contents. Please, give me a hint. ServerAdmin webmaster@localhost ServerName www.foobar.com ServerAlias www.foobar.com DocumentRoot /var/www/foobar <Directory /> Options FollowSymLinks AllowOverride All </Directory> <Directory /var/www/foobar> Options -Indexes FollowSymLinks AllowOverride All Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> <Directory /var/www/foobar/dir> AllowOverride AuthConfig AuthName "Authorize yourself, please!" AuthType Basic AuthUserFile /etc/apache2/.htpasswd AuthGroupFile /dev/null Allow from All Order Allow,Deny Options +Indexes<<- that one should be added Require valid-user you have to add the line Options +Indexes to see directory contents

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• Screen Scraping Twitter

  - by BRADINO

  I got an email today asking for help to scrape Twitter. In particular, to be able to login. So I am going to show everyone, NOT to encourage anyone to violate Twitters terms of use but as an educational blog post about how PHP and cURL can be used to post variables and store cookies. Again, I am using the cScrape class I wrote, which you can download. Step 1 First go to twitter.com and look at the source code of the login to get the form field names and the form post location. You will see that the form posts to https://twitter.com/session and the username and password fields are session[username_or_email] and session[password] respectively. Step 2 Now you are ready to login. So using the fetch function in the Scrape class you create an associative array to contain the form values you want to post. The other thing you will need to do is uncomment the lines for CURLOPT_COOKIEFILE and CURLOPT_COOKIEJAR. Cookies will be required to stay logged in and scrape around. The paths to the cookie files need to be writable by your app. Also you will need to uncomment the line about CURLOPT_FOLLOWLOCATION. $data = array('session[username_or_email]' => "bradino", 'session[password]' => "secret"); $scrape->fetch('https://twitter.com/sessions',$data); Step 1.5 Oops that didn't work. All I got back was 403 Forbidden: The server understood the request, but is refusing to fulfill it. Ahhh I see another variable called authenticity_token I bet Twitter was looking for that. So let's back up and first hit twitter.com to get the authenticity_token variable, and then make the login post request with that variable included in our array of parameters. $scrape->fetch('https://twitter.com'); $data = array('session[username_or_email]' => "bradino", 'session[password]' => "secret"); $data['authenticity_token'] = $scrape->fetchBetween('name="authenticity_token" type="hidden" value="','"',$scrape->result); $scrape->fetch('https://twitter.com/sessions',$data); echo $scrape->result; So that's basically it. Now you are logged in and can scrape around and request other pages as you normally would. Sorry it wasn't a longer post. I really do enjoy this kind of stuff so if anyone has a request, hit me up. Errors? 1) Make sure that you are properly parsing the token variable 2) Make sure that you uncommented the lines about CURLOPT_COOKIEFILE and CURLOPT_COOKIEJAR, those options need to be enabled and be sure the path set is writable by your application 3) Make sure that the path to the cookie file is writable and that it is getting data written to it 4) If you get a message about being redirected you need to uncomment the line about CURLOPT_FOLLOWLOCATION, that option needs to be enabled true

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• edited and reversed changes on .htaccess - site starts redirecting to .comindex.php/

  - by Aurigae

  Site is a Joomla 2.5 site. I wanted to add a non www to www redirect to the htaccess file, did so, then the redirection went mad, reversed but still the site redirects. When i click view site in admin panel, i get linked to http://domain.comindex.php/ The website is http://www.domain.com Visiting the website URL works without www, but once you click on projects it acts mad too. Projects is managed with joomshopping extension. EDIT: the redirect also happens when rewrite is deactivated in admin panel. ## # @package Joomla # @copyright Copyright (C) 2005 - 2012 Open Source Matters. All rights reserved. # @license GNU General Public License version 2 or later; see LICENSE.txt ## ## # READ THIS COMPLETELY IF YOU CHOOSE TO USE THIS FILE! # # The line just below this section: 'Options +FollowSymLinks' may cause problems # with some server configurations. It is required for use of mod_rewrite, but may already # be set by your server administrator in a way that dissallows changing it in # your .htaccess file. If using it causes your server to error out, comment it out (add # to # beginning of line), reload your site in your browser and test your sef url's. If they work, # it has been set by your server administrator and you do not need it set here. ## ## Can be commented out if causes errors, see notes above. Options +FollowSymLinks ## Mod_rewrite in use. RewriteEngine On ## Begin - Rewrite rules to block out some common exploits. # If you experience problems on your site block out the operations listed below # This attempts to block the most common type of exploit `attempts` to Joomla! # # Block out any script trying to base64_encode data within the URL. RewriteCond %{QUERY_STRING} base64_encode[^(]*\([^)]*\) [OR] # Block out any script that includes a <script> tag in URL. RewriteCond %{QUERY_STRING} (<|%3C)([^s]*s)+cript.*(>|%3E) [NC,OR] # Block out any script trying to set a PHP GLOBALS variable via URL. RewriteCond %{QUERY_STRING} GLOBALS(=|\[|\%[0-9A-Z]{0,2}) [OR] # Block out any script trying to modify a _REQUEST variable via URL. RewriteCond %{QUERY_STRING} _REQUEST(=|\[|\%[0-9A-Z]{0,2}) # Return 403 Forbidden header and show the content of the root homepage RewriteRule .* index.php [F] # ## End - Rewrite rules to block out some common exploits. ## Begin - Custom redirects # # If you need to redirect some pages, or set a canonical non-www to # www redirect (or vice versa), place that code here. Ensure those # redirects use the correct RewriteRule syntax and the [R=301,L] flags. # ## End - Custom redirects ## # Uncomment following line if your webserver's URL # is not directly related to physical file paths. # Update Your Joomla! Directory (just / for root). ## # RewriteBase / ## Begin - Joomla! core SEF Section. # RewriteRule .* - [E=HTTP_AUTHORIZATION:%{HTTP:Authorization}] # # If the requested path and file is not /index.php and the request # has not already been internally rewritten to the index.php script RewriteCond %{REQUEST_URI} !^/index\.php # and the request is for something within the component folder, # or for the site root, or for an extensionless URL, or the # requested URL ends with one of the listed extensions RewriteCond %{REQUEST_URI} /component/|(/[^.]*|\.(php|html?|feed|pdf|vcf|raw))$ [NC] # and the requested path and file doesn't directly match a physical file RewriteCond %{REQUEST_FILENAME} !-f # and the requested path and file doesn't directly match a physical folder RewriteCond %{REQUEST_FILENAME} !-d # internally rewrite the request to the index.php script RewriteRule .* index.php [L] # ## End - Joomla! core SEF Section. Redirect 301 /index.html /index.php Redirect 301 /services /project Redirect 301 /projects/projects.html /project Redirect 301 /projects/project1.html /project Redirect 301 /projects/project2.html /project Redirect 301 /projects /project Redirect 301 /keypersonnel.html /about-agrin/keystaff Redirect 301 /cooperation.htm /about-agrin/intcoop Redirect 301 /member.html /about-agrin/memberships Redirect 301 /contact.html /contacts Redirect 301 /hr.htm /jobs Redirect 301 /index.php/404 /index.php

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• In Asp.Net MVC 2 is there a better way to return 401 status codes without getting an auth redirect

  - by Greg Roberts

  I have a portion of my site that has a lightweight xml/json REST API. Most of my site is behind forms auth but only some of my API actions require authentication. I have a custom AuthorizeAttribute for my API that I use to check for certain permissions and when it fails it results in a 401. All is good, except since I'm using forms auth, Asp.net conveniently converts that into a 302 redirect to my login page. I've seen some previous questions that seem a bit hackish to either return a 403 instead or to put some logic in the global.asax protected void Application_EndRequest() that will essentially convert 302 to 401 where it meets whatever criteria. Previous Question Previous Question 2 What I'm doing now is sort of like one of the questions, but instead of checking the Application_EndRequest() for a 302 I make my authorize attribute return 666 which indicates to me that I need to set this to a 401. Here is my code: protected void Application_EndRequest() { if (Context.Response.StatusCode == MyAuthAttribute.AUTHORIZATION_FAILED_STATUS) { //check for 666 - status code of hidden 401 Context.Response.StatusCode = 401; } } Even though this works, my question is there something in Asp.net MVC 2 that would prevent me from having to do this? Or, in general is there a better way? I would think this would come up a lot for anyone doing REST api's or just people that do ajax requests in their controllers. The last thing you want is to do a request and get the content of a login page instead of json.

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• Passenger, Nginx, and Capistrano - Passenger not launching Rails app at all

  - by Throlkim

  Essentially, my route is working perfectly, Passenger seems to be loading - all is hunky-dory. Except that nothing Railsy happens. Here's my Nginx log from starting the server to the first request (ignore the different domain/route - it's because I haven't moved the new domain over yet, and it's returning a 403 error because there's no index file in the public folder): [ pid=24559 file=ext/nginx/HelperServer.cpp:826 time=2009-11-10 00:49:13.227 ]: Passenger helper server started on PID 24559 [ pid=24559 file=ext/nginx/HelperServer.cpp:831 time=2009-11-10 00:49:13.227 ]: Password received. 2009/11/10 00:49:53 [error] 24578#0: *1 directory index of "/var/www/***/current/public/" is forbidden, client: 188.221.195.27, server: ***, request: "GET / HTTP/1.1", host: "***" 2009/11/10 00:49:54 [error] 24578#0: *1 open() "/var/www/***/current/public/favicon.ico" failed (2: No such file or directory), client: 188.221.195.27, server: ***, request: "GET /favicon.ico HTTP/1.1", host: "***", referrer: "***" Someone on the RubyOnRails IRC channel suggested that it might be a webserver permissions problem. I had a suspicion that it might be a filesystem permission problem, but then Nginx runs as www-data and Passenger as root. I can load static files from within the public directory fine, but no Rails application is being launched. Does anyone have an idea? My head is gradually melting away figuring this one out! Edit: Here's the vhost file: server { listen 80; server_name ***; passenger_enabled on; location / { root /var/www/***/current/public; index index.html index.htm; } #error_page 404 /404.html; # redirect server error pages to the static page /50x.html # error_page 500 502 503 504 /50x.html; location = /50x.html { root html; } }

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• java.lang.NoSuchMethodError: org.w3c.dom.Document.setDocumentURI

  - by mike00000888

  I am getting a NoSuchMethodError error for org.w3c.dom.Document.setDocumentURI. This is strange, as I have rt.jar in the JAVA_HOME path. I am creating a web service using CXF, and the error seem to be coming out of CXF: java.lang.NoSuchMethodError: org.w3c.dom.Document.setDocumentURI(Ljava/lang/String;)V org.apache.cxf.staxutils.StaxUtils.read(StaxUtils.java:760) org.apache.cxf.wsdl11.WSDLManagerImpl.loadDefinition(WSDLManagerImpl.java:219) org.apache.cxf.wsdl11.WSDLManagerImpl.getDefinition(WSDLManagerImpl.java:179) org.apache.cxf.wsdl11.WSDLServiceFactory.(WSDLServiceFactory.java:91) org.apache.cxf.service.factory.ReflectionServiceFactoryBean.buildServiceFromWSDL(ReflectionServiceFactoryBean.java:403) org.apache.cxf.service.factory.ReflectionServiceFactoryBean.initializeServiceModel(ReflectionServiceFactoryBean.java:528) org.apache.cxf.service.factory.ReflectionServiceFactoryBean.create(ReflectionServiceFactoryBean.java:278) org.apache.cxf.jaxws.support.JaxWsServiceFactoryBean.create(JaxWsServiceFactoryBean.java:178) org.apache.cxf.frontend.AbstractWSDLBasedEndpointFactory.createEndpoint(AbstractWSDLBasedEndpointFactory.java:100) org.apache.cxf.frontend.ServerFactoryBean.create(ServerFactoryBean.java:105) org.apache.cxf.jaxws.JaxWsServerFactoryBean.create(JaxWsServerFactoryBean.java:167) org.apache.cxf.jaxws.EndpointImpl.getServer(EndpointImpl.java:349) org.apache.cxf.jaxws.EndpointImpl.doPublish(EndpointImpl.java:262) org.apache.cxf.jaxws.EndpointImpl.publish(EndpointImpl.java:212) org.apache.cxf.jaxws.EndpointImpl.publish(EndpointImpl.java:407) sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) java.lang.reflect.Method.invoke(Method.java:597) org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeCustomInitMethod(AbstractAutowireCapableBeanFactory.java:1414) org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1375) org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1335) org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:473) org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:409) java.security.AccessController.doPrivileged(Native Method) org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:380) org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:264) org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:261) org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:185) org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:164) org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:429) org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:728) org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:380) org.apache.cxf.transport.servlet.CXFServlet.loadAdditionalConfig(CXFServlet.java:171) org.apache.cxf.transport.servlet.CXFServlet.updateContext(CXFServlet.java:139) org.apache.cxf.transport.servlet.CXFServlet.loadSpringBus(CXFServlet.java:101) org.apache.cxf.transport.servlet.CXFServlet.loadBus(CXFServlet.java:70) org.apache.cxf.transport.servlet.AbstractCXFServlet.init(AbstractCXFServlet.java:78) org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:293) org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:849) org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:583) org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:454) java.lang.Thread.run(Thread.java:619) Can someone offer some advice? Much thanks

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• Creating ViewResults outside of Controllers in ASP.NET MVC

  - by Craig Walker

  Several of my controller actions have a standard set of failure-handling behavior. In general, I want to: Load an object based on the Route Data (IDs and the like) If the Route Data does not point to a valid object (ex: through URL hacking) then inform the user of the problem and return an HTTP 404 Not Found Validate that the current user has the proper permissions on the object If the user doesn't have permission, inform the user of the problem and return an HTTP 403 Forbidden If the above is successful, then do something with that object that's action-specific (ie: render it in a view). These steps are so standardized that I want to have reusable code to implement the behavior. My current plan of attack was to have a helper method to do something like this: public static ActionResult HandleMyObject(this Controller controller, Func<MyObject,ActionResult> onSuccess) { var myObject = MyObject.LoadFrom(controller.RouteData). if ( myObject == null ) return NotFound(controller); if ( myObject.IsNotAllowed(controller.User)) return NotAllowed(controller); return onSuccess(myObject); } # NotAllowed() is pretty much the same as this public static NotFound(Controller controller){ controller.HttpContext.Response.StatusCode = 404 # NotFound.aspx is a shared view. ViewResult result = controller.View("NotFound"); return result; } The problem here is that Controller.View() is a protected method and so is not accessible from a helper. I've looked at creating a new ViewResult instance explicitly, but there's enough properties to set that I'm wary about doing so without knowing the pitfalls first. What's the best way to create a ViewResult from outside a particular Controller?

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• Downloading attachments from Exchange with WebDAV

  - by arturito

  Hi there! I've been trying to retrive attachment from message in Exchange server using WebDAV.I don't know which version of Exchange the company is running. I'can successfully read messages and retrive list of attachments. However I am failing to save attachments. In both cases errors is: "The remote server returned an error: <403 Forbidden. Any idea what I'm doing wrong? My code: static void Main(string[] args) { HttpWebRequest Request; WebResponse Response; CredentialCache MyCredentialCache; string attachment = "http://mailserver/Exchange/Username/Inbox/Test.EML/Test.txt"; string strUserName = "username"; string strPassword = "password"; string strDomain = "domain"; try { // HttpWebRequest MyCredentialCache = new System.Net.CredentialCache(); MyCredentialCache.Add(new System.Uri(attachment), "NTLM", new NetworkCredential(strUserName, strPassword, strDomain)); Request = (HttpWebRequest)HttpWebRequest.Create(attachment); Request.Credentials = MyCredentialCache; Request.Method = "GET"; Response = (HttpWebResponse)Request.GetResponse(); } catch(Exception ex) { Console.WriteLine(ex.Message.ToString()); } try { //Web Client string downloadPath = "D:\\Downloads"; WebClient wcClient = new WebClient(); wcClient.Credentials = new NetworkCredential(strUserName, strPassword, strDomain); string file = Path.GetFileName(attachment); string filename = Path.Combine(downloadPath, file); wcClient.DownloadFile(attachment, filename); } catch (Exception ex) { Console.WriteLine(ex.Message.ToString()); } Console.ReadLine(); }

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• How can one detect if a server/script is accessing their site through cURL/file_get_contents()? (excluding user-agents and IP addresses)

  - by navnav

  I've come across a question where a user is having difficulties accessing an image through a script (using cURL/file_get_contents()): How to save an image from url using PHP? The image link seems to return a 403 error when using file_get_contents() to request it. But in cURL, a more detailed error is returned: You were denied access to the system. Turn off the engine or Surf Proxy, Fake IP if you really want to access. Proxy or not accepted from any Web tools Intrusion Prevention System. Binh Minh Online Data Services @ 2008 - 2012 I also failed to access the same image after fiddling around with a cURL request myself. I tried changing the user-agent to my exact browsers user-agent which can successfully access the image. I've also tried the script on my personal local server, which (obviously) uses the same IP address as my browser... So as far as I know, user-agents and IP addresses are out of the situation. How else can someone detect a script performing a request? BTW, this is not for anything crazy. I'm just curious xD

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• Cookies not present after using XMLHttpRequest

  - by Joe B

  I'm trying to make a bookmarklet to download videos off of YouTube, but I've come across a little problem. To detect the highest quality video available, I use a sort of brute force method, in which I make requests using the XMLHttpRequest object until a 404 isn't returned (I can't do it until a 200 ok is returned because YouTube redirects to a different server if the video is available, and the cross-domain policy won't allow me to access any of that data). Once a working URL is found, I simply set window.location to the URL and the download should start, right? Wrong. A request is made, but for reasons unknown to me, the cookies are stripped and YouTube returns a 403 access denied. This does not happen if the XML requests aren't made before it, i.e. if I just set the window.location to the URL everything works fine, it's when I do the XMLHttpRequest that the cookies aren't sent. It's hard to explain so here's the script: var formats = ["37", "22", "35", "34", "18", ""]; var url = "/get_video?video_id=" + yt.getConfig('SWF_ARGS')['video_id'] + "&t=" + (unescape(yt.getConfig('SWF_ARGS')['t'])) + "&fmt="; for (var i = 0; i < formats.length; i++) { xmlhttp = new XMLHttpRequest; xmlhttp.open("HEAD", url + formats[i], false); xmlhttp.send(null); if (xmlhttp.status != 404) { document.location = url + formats[i]; break } } That script does not send the cookies after setting the document.location and thus does not work. However, simply doing this: document.location = /get_video?video_id=" + yt.getConfig('SWF_ARGS')['video_id'] + "&t=" + (unescape(yt.getConfig('SWF_ARGS')['t'])) DOES send the cookies along with the request, and does work. The only downside is I can't automatically detect the highest quality, I just have to try every "fmt" parameter manually until I get it right. So my question is: why is the XMLHttpRequest object removing cookies from subsequent requests? This is the first time I've ever done anything in JS by the way, so please, go easy on me. ;)

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• Why is Django/FastCGI/Apache logging HTTP status code 200 for every request, even 404s?

  - by jl6

  Edit: I have now discovered that the status code is returned correctly, it just isn't recorded correctly in Apache's access.log. Title amended. This is still a problem. Any ideas? Original question follows. Hi all. I run the following stack: Django(svn) on WSGI on FastCGI on Apache on Dreamhost. Every page served by Django returns HTTP status code 200, even those resulting from statements such as raise Http404 There is a .htaccess file which directs most pages to Django, via my dispatch.fcgi file, and other pages elsewhere. The other pages return correct status codes, e.g. trying to access /.htaccess itself results in status code 403. When I run my Django project on a local development server (Apache, not Django's built-in development server), I get correct status codes, so I don't think this is caused by my Django code. My current thinking is that the problem lies somewhere in how the FastCGI/WSGI interface is configured, but I'm not sure how to proceed debugging this. Any tips on how I can find out what's causing this?

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• What is the best way to send structs containing enum values via sockets in C.

  - by Axel

  I've lots of different structs containing enum members that I have to transmit via TCP/IP. While the communication endpoints are on different operating systems (Windows XP and Linux) meaning different compilers (gcc 4.x.x and MSVC 2008) both program parts share the same header files with type declarations. For performance reasons, the structures should be transmitted directly (see code sample below) without expensively serializing or streaming the members inside. So the question is how to ensure that both compilers use the same internal memory representation for the enumeration members (i.e. both use 32-bit unsigned integers). Or if there is a better way to solve this problem... //type and enum declaration typedef enum { A = 1, B = 2, C = 3 } eParameter; typedef enum { READY = 400, RUNNING = 401, BLOCKED = 402 FINISHED = 403 } eState; #pragma pack(push,1) typedef struct { eParameter mParameter; eState mState; int32_t miSomeValue; uint8_t miAnotherValue; ... } tStateMessage; #pragma pack(pop) //... send via socket tStateMessage msg; send(iSocketFD,(void*)(&msg),sizeof(tStateMessage)); //... receive message on the other side tStateMessage msg_received; recv(iSocketFD,(void*)(&msg_received),sizeof(tStateMessage)); Additionally... Since both endpoints are little endian maschines, endianess is not a problem here. And the pack #pragma solves alignment issues satisfactorily. Thx for your answers, Axel

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• safely hosting a django project over apache using centos

  - by tipu

  Error can be seen at: http://djaffry.selfip.com:8080/ I had a project working great, but I had all the files under /var/www/ and with my limited understanding it's bad, according to django's site: "If your background is in PHP, you’re probably used to putting code under the Web server’s document root (in a place such as /var/www). With Django, you don’t do that. It’s not a good idea to put any of this Python code within your Web server’s document root, because it risks the possibility that people may be able to view your code over the Web. That’s not good for security. Put your code in some directory outside of the document root, such as /home/mycode." So I went to /home/tipu/stuff/ and executed django-admin.py startproject twingle. Then I went to apache and did <VirtualHost *:8080> ServerName tweet_search_engine DocumentRoot /home/tipu/stuff/twingle/ </VirtualHost> <Directory /home/tipu/stuff/twingle> SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE settings PythonOption django.root /home/tipu/stuff/twingle PythonDebug On PythonPath "['/home/tipu/stuff/', '/home/tipu/stuff/twingle/'] + sys.path" </Directory> Now I am getting a 403 Forbidden error.. any idea what I'm doing wrong? I'm newer to Linux (CentOS) and django, so I could be over looking some very simple things.

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• IdHTTP XML, getting xml, help please

  - by user1748535

  Already some day I can not solve the problem. Help than you can. I'm using Delphi 2010, and I can not get through IdHTTP XML document from the site. I always had the answer 403 / HTTP 1.1 and text/html (need text/xml) When using MSXML all well and getting XML file. But I need a proxy, so need idhtop. When using the synapse does not change. Work with msxml: CoInitialize(nil); GetXML:={$IFDEF VER210}CoXMLHTTP{$ELSE}CoXMLHTTPRequest{$ENDIF}.Create; GetXML.open('POST', '***************', false, EmptyParam, EmptyParam); GetXML.setRequestHeader('Host', '***************'); GetXML.setRequestHeader('User-Agent', 'Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.2.13) Gecko/20101203 Firefox/3.6.13'); GetXML.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded'); GamesBody:='***************'; GetXML.send(GamesBody); Form1.Memo2.Lines.Text:=GetXML.responseText; ResultPage:=GetXML.responseText; if Pos('error code', ResultPage)=0 then begin CoUninitialize; how to set up IdHTTP? All settings have changed 100 times Or a connection to a proxy MSXML?

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• Apache Not Accepting a Path in My Home Folder

  - by Promather

  I have trying to set up an Apache site to use a folder in my home folder without any success. I exactly followed the steps in this page: https://help.ubuntu.com/community/ApacheMySQLPHP yet I did not succeed; I keep getting error 403, which says that the server doesn't have permission to access the requested page. I searched forums and many suggested changing the permission of the folder. I went straight away and set the permission to 777, but that didn't solve the problem. I made another search and somebody gave me a clue, which is that it could be because my home folder is encrypted. I believe this could be the problem, but: What is the relation between encryption and Apache? I suppose Apache server is requesting the file from the system, rather than trying to access the file bytes! Is there anyway to solve this problem? I don't want to move the folder to /var/www because I am using this Apache for testing, so I want whatever change I make to be immediately reflected, rather than having to copy files which is error prone.

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• asp.net MVC HandleError

  - by boris callens

  How do I go about the [HandleError] filter in asp.net MVC Preview 5? I set the customErrors in my web.config file <customErrors mode="On" defaultRedirect="Error.aspx"> <error statusCode="403" redirect="NoAccess.htm"/> <error statusCode="404" redirect="FileNotFound.htm"/> </customErrors> and put [HandleError] above my Controller Class like this: [HandleError] public class DSWebsiteController: Controller{ [snip] public ActionResult CrashTest() { throw new Exception("Oh Noes!"); } } Then I let my controllers inherit from this class and call CrashTest() on them. Visual studio halts at the error and after pressing f5 to continue, I get rerouted to Error.aspx?aspxerrorpath=/sxi.mvc/CrashTest (where sxi is the name of the used controller. Off course the path cannot be found and I get "Server Error in '/' Application." 404. This site was ported from preview 3 to 5. Everything runs (wasn't that much work to port) except the error handling. When I create a complete new project the error handling seems to work. Ideas? --Note-- Since this question has over 3K views now, I thought it would be beneficial to put in what I'm currently (asp.net mvc 1.0) using. In the mvc contrib project there is a brilliant attribute called "RescueAttribute" You should probably check it out too ;)

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• Getting Google results in Java? Need help!

  - by Cris Carter

  Hello. Right now, I'm trying to get the results from Google in Java, by searching for a term. I'm using a desktop program, not an applet. That in itself isn't complicated. but then Google gave me a 403 error. Anyways, I added referrer and User Agent and then it worked. Now, my problem is that I don't get the results page from Google. Instead, I get their script which gets the results page. My code right now simply uses a GET request on "http://www.google.com/search?q=" + Dork; Then it outputs each line. Here is what I get when I run my program: <.!doctype html<.head<.titledork - Google Search<./title<.scriptwindow.google={kEI:"9myaS-Date).getTime()}}};try{}catch(u){}window.google.jsrt_kill=1; align:center}#logo{display:block;overflow:hidden;position:relative;width:103px;height:37px; <./ script<./div Lots of stuff like that. I shortened it (A LOT) and put in dots to fit it here. So my big question is: How do I turn this whole mess into the nice results page I get when searching Google with a browser? Any help would be seriously appreciated, and I really need the answer fast. Also, please keep in mind that I do NOT want to use Google's API for this. Thanks in advance!

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