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  • Is there any way to add a MouseListener to a Graphic object ?

    - by Fahad
    Hi, Is there any way to add a MouseListener to a Graphic object. I have this simple GUI that draw an oval. What I want is handling the event when the user clicks on the oval import java.awt.*; import java.awt.event.MouseEvent; import java.awt.event.MouseListener; import javax.swing.*; public class Gui2 extends JFrame { JFrame frame = new JFrame(); MyDrawPanel drawpanel = new MyDrawPanel(); public static void main(String[] args) { Gui2 gui = new Gui2(); gui.go(); } public void go() { frame.getContentPane().add(drawpanel); // frame.addMouseListener(this); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setSize(300, 300); frame.setVisible(true); } } class MyDrawPanel extends JComponent implements MouseListener { public void paintComponent(Graphics g) { int red = (int) (Math.random() * 255); int green = (int) (Math.random() * 255); int blue = (int) (Math.random() * 255); Color startrandomColor = new Color(red, green, blue); red = (int) (Math.random() * 255); green = (int) (Math.random() * 255); blue = (int) (Math.random() * 255); Color endrandomColor = new Color(red, green, blue); Graphics2D g2d = (Graphics2D) g; this.addMouseListener(this); GradientPaint gradient = new GradientPaint(70, 70, startrandomColor, 150, 150, endrandomColor); g2d.setPaint(gradient); g2d.fillOval(70, 70, 100, 100); } @Override public void mouseClicked(MouseEvent e) { if ((e.getButton() == 1) && (e.getX() >= 70 && e.getX() <= 170 && e.getY() >= 70 && e .getY() <= 170)) { this.repaint(); // JOptionPane.showMessageDialog(null,e.getX()+ "\n" + e.getY()); } } @Override public void mouseEntered(MouseEvent e) { // TODO Auto-generated method stub } @Override public void mouseExited(MouseEvent e) { // TODO Auto-generated method stub } @Override public void mousePressed(MouseEvent e) { // TODO Auto-generated method stub } @Override public void mouseReleased(MouseEvent e) { // TODO Auto-generated method stub } } This Works Except it fires when the click is within a virtual box around the oval. Could anyone help me to have it fire when the click is EXACTLY on the oval. Thanks in advance.

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  • Detecting Markers Using OpenCV

    - by Hamza Yerlikaya
    I am trying to detect various objects containing colored markers, so a red blue green marker identifies object A, and a red blue red marker identifies object B. My problem is I can't use template matching cause objects can be rotated, currently I am thinking about check for each color then find the object by checking the distance between colors but it seems inefficient, so my question is there a better way to do this?

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  • Jquery toggle function that doesn't return false?

    - by Tom
    Hi, Is it possible to stop the automatic preventDefault() from applying in a simple Jquery toggle function? $(".mydiv").toggle( function () { $(this).addClass("blue"); }, function () { $(this).removeClass("blue"); } ); The above prevents elements inside the div from responding normally to the click. It doesn't have to be the toggle() function - anything that allows toggling a class on and off AND doesn't return false would be great. Thanks.

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  • How to add changebar in latex?

    - by Rabarberski
    In Latex, I've created a new command 'changedtext' to mark specifics parts in my document and make it appear blue: \newcommand{\changedtext}[1]{\textcolor{blue}{#1} } Is there any easy way to alter the command to have change bars appear next to the text in the resulting PDF? If not possible, any other suggestion for a visual markup (other than change bars) that would be clear on a black & white printout would be useful as well.

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  • How to get rid of box around linked image

    - by Earlz
    Hello, I know I've solved this problem before, but I can't remember or find the solution, so here I am... In Firefox 3.5 this code causes an undesirable blue border around the image. How do I get rid of this blue border? <a style="text-decoration: none;" href="index.html"> <img src="http://www.google.com/logos/stpatricksday10-hp.gif" /> </a> http://jsbin.com/umuzo3

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  • (Python) Converting a dictionary to a list?

    - by Daria Egelhoff
    So I have this dictionary: ScoreDict = {"Blue": {'R1': 89, 'R2': 80}, "Brown": {'R1': 61, 'R2': 77}, "Purple": {'R1': 60, 'R2': 98}, "Green": {'R1': 74, 'R2': 91}, "Red": {'R1': 87, 'Lon': 74}} Is there any way how I can convert this dictionary into a list like this: ScoreList = [['Blue', 89, 80], ['Brown', 61, 77], ['Purple', 60, 98], ['Green', 74, 91], ['Red', 87, 74]] I'm not too familiar with dictionaries, so I really need some help here. Thanks in advance!

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  • Displaying bitmaps in relative positions

    - by JonF
    I'd like to put a couple images on a surfaceview. I understand that the screen sizes of android devices can vary, so I don't think I can just use an x y position or I might end up placing it off different screens. Say I want to put two boxes in the center of the screen, a blue one and a red one. The blue one is to the left of the red one. How can I accomplish that while accounting for different screen sizes?

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  • Python: Comparing specific columns in two csv files

    - by coder999
    Say that I have two CSV files (file1 and file2) with contents as shown below: file1: fred,43,Male,"23,45",blue,"1, bedrock avenue" file2: fred,39,Male,"23,45",blue,"1, bedrock avenue" I would like to compare these two CSV records to see if columns 0,2,3,4, and 5 are the same. I don't care about column 1. What's the most pythonic way of doing this? EDIT: Some example code would be appreciated.

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  • Excelsheet query

    - by kunj
    Hi, Please tell me how can I find the last word from any particular cell in excel sheet if cell contains multiple words or instructions. For ex- The below string is in particular cell: C:\Documents and Settings\All Users\Documents\My Pictures\Sample Pictures\Blue hills.jpg My requirement is to search only last word in that cell i.e. Blue hills.jpg Your early response is highly appreciated!!!

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  • Air/Flex concatenating a variable with a property

    - by Deyon
    I have three text boxes on the stage id=red, blue, green same as the keys in my cars Object/Array public function carsToBox():void { var cars:Object={red:"300zx",blue:"Skyline",green:"Supra"}; for(var tempObj:String in cars) { tempObj.text= cars[tempObj];//this trows errors } } So I'm thinking "tempObj.text" would equal red.text but I can't stick "tempObj" with ".text" is there a way this can be done?

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  • iPod Touch (OS 3.0) bluetooth connection to non apple device

    - by Avi
    I need to know if I can programmatically connect my iPod Touch (OS 3.0) to a non apple blue tooth device, Using the Apple iPhone SDK. I know that I can connect to other iPhone using GameKit API, But can I connect to other non apple Bluetooth devices for example an measuring device that send out real time data over blue tooth?

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  • Line up swing components by edges

    - by rasen58
    Is it possible to line up swing components? The components are in separate panels which both use flow layout. These two panels are in another panel which is using a grid layout. As you can see there is a subtle difference and I find it annoying. I know that all of the jlabels [the rectangles in blue/purple all have the same size, so i think it might be because of the '+' and '*', but I'm not sure because the left sides of the first two boxes aren't lined up. the panels JPanel panel2 = new JPanel(new GridLayout(4, 1)); JPanel panel2a = new JPanel(new FlowLayout()); JPanel panel2b = new JPanel(new FlowLayout()); the first two rectangles (purple) add1 = new JLabel("", JLabel.CENTER); add1.setTransferHandler(new TransferHandler("text")); add1.setBorder(b2); add2 = new JLabel("", JLabel.CENTER); add2.setTransferHandler(new TransferHandler("text")); add2.setBorder(b2); the two blue rectangles textFieldA = new JTextField(); textFieldA.setHorizontalAlignment(JTextField.CENTER); textFieldA.setEditable(false); textFieldA.setBorder(new LineBorder(Color.blue)); textFieldM = new JTextField(); textFieldM.setHorizontalAlignment(JTextField.CENTER); textFieldM.setEditable(false); textFieldM.setBorder(new LineBorder(Color.blue)); the + and * opA = new JLabel("+", JLabel.CENTER); opS = new JLabel("*", JLabel.CENTER); Showing that the rectangles are the same size Dimension d = card1.getPreferredSize(); int width = d.width + 100; int height = d.height + 50; add1.setPreferredSize(new Dimension(width, height)); add2.setPreferredSize(new Dimension(width, height)); mult1.setPreferredSize(new Dimension(width, height)); mult2.setPreferredSize(new Dimension(width, height)); textFieldA.setPreferredSize(new Dimension(width, height)); textFieldM.setPreferredSize(new Dimension(width, height)); Adding to the panels panel2a.add(add1); panel2a.add(opA); panel2a.add(add2); panel2a.add(enterA); panel2a.add(textFieldA); panel2c.add(mult1); panel2c.add(opM); panel2c.add(mult2); panel2c.add(enterM); panel2c.add(textFieldM); panel2.add(panel2a); panel2.add(panel2c);

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  • CSS: a:link vs just a (without the :link part)

    - by Rob
    So we're required to use the following order for CSS anchor pseudo-classes a:link { color: red } a:visited { color: blue } a:hover { color: yellow } a:active { color: lime } But my question is why bother with the a:link part? Rather, is there any advantage to the above (other than perhaps clarity) over: a { color:red; } /* notice no :link part */ a:visited { color: blue; } etc.,etc.

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  • Drive Genius says: "Invalid catalog btree reverse link in node" is this fixable?

    - by bencnscp
    No obvious problems with my Mac OS X 10.5 system, but Drive Genius 1.5.1 says: "Invalid catalog btree reverse link in node" when doing a "Verify" The "repair" and "rebuild" options fail. I did some googling, and the consensus as: 1- Drive Genius is slightly better than Disk Warrior 2- This problem is likely not fixable. My assumed solution is that I should do a full backup and re-format.

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  • Which VPN-Software for Road-Worriors

    - by Phoibe
    Hello, I am using Unix (Debian) as my server platform and want to configure the following: A remote user can connect to a secure VPN server and use its IP to access the Internet, mostly for browsing and e-mail. I read a lot about OpenS/WAN+L2PT and OpenVPN but I am still confused how I should configure it. I would prefer IPSec+PPTP/L2PT since the road warrior doesn't have to install any extra software on iPhone/Windows7. Is there a good how-to for IPSec or what would you suggest?

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  • HTG Explains: Why Does Rebooting a Computer Fix So Many Problems?

    - by Chris Hoffman
    Ask a geek how to fix a problem you’ve having with your Windows computer and they’ll likely ask “Have you tried rebooting it?” This seems like a flippant response, but rebooting a computer can actually solve many problems. So what’s going on here? Why does resetting a device or restarting a program fix so many problems? And why don’t geeks try to identify and fix problems rather than use the blunt hammer of “reset it”? This Isn’t Just About Windows Bear in mind that this soltion isn’t just limited to Windows computers, but applies to all types of computing devices. You’ll find the advice “try resetting it” applied to wireless routers, iPads, Android phones, and more. This same advice even applies to software — is Firefox acting slow and consuming a lot of memory? Try closing it and reopening it! Some Problems Require a Restart To illustrate why rebooting can fix so many problems, let’s take a look at the ultimate software problem a Windows computer can face: Windows halts, showing a blue screen of death. The blue screen was caused by a low-level error, likely a problem with a hardware driver or a hardware malfunction. Windows reaches a state where it doesn’t know how to recover, so it halts, shows a blue-screen of death, gathers information about the problem, and automatically restarts the computer for you . This restart fixes the blue screen of death. Windows has gotten better at dealing with errors — for example, if your graphics driver crashes, Windows XP would have frozen. In Windows Vista and newer versions of Windows, the Windows desktop will lose its fancy graphical effects for a few moments before regaining them. Behind the scenes, Windows is restarting the malfunctioning graphics driver. But why doesn’t Windows simply fix the problem rather than restarting the driver or the computer itself?  Well, because it can’t — the code has encountered a problem and stopped working completely, so there’s no way for it to continue. By restarting, the code can start from square one and hopefully it won’t encounter the same problem again. Examples of Restarting Fixing Problems While certain problems require a complete restart because the operating system or a hardware driver has stopped working, not every problem does. Some problems may be fixable without a restart, though a restart may be the easiest option. Windows is Slow: Let’s say Windows is running very slowly. It’s possible that a misbehaving program is using 99% CPU and draining the computer’s resources. A geek could head to the task manager and look around, hoping to locate the misbehaving process an end it. If an average user encountered this same problem, they could simply reboot their computer to fix it rather than dig through their running processes. Firefox or Another Program is Using Too Much Memory: In the past, Firefox has been the poster child for memory leaks on average PCs. Over time, Firefox would often consume more and more memory, getting larger and larger and slowing down. Closing Firefox will cause it to relinquish all of its memory. When it starts again, it will start from a clean state without any leaked memory. This doesn’t just apply to Firefox, but applies to any software with memory leaks. Internet or Wi-Fi Network Problems: If you have a problem with your Wi-Fi or Internet connection, the software on your router or modem may have encountered a problem. Resetting the router — just by unplugging it from its power socket and then plugging it back in — is a common solution for connection problems. In all cases, a restart wipes away the current state of the software . Any code that’s stuck in a misbehaving state will be swept away, too. When you restart, the computer or device will bring the system up from scratch, restarting all the software from square one so it will work just as well as it was working before. “Soft Resets” vs. “Hard Resets” In the mobile device world, there are two types of “resets” you can perform. A “soft reset” is simply restarting a device normally — turning it off and then on again. A “hard reset” is resetting its software state back to its factory default state. When you think about it, both types of resets fix problems for a similar reason. For example, let’s say your Windows computer refuses to boot or becomes completely infected with malware. Simply restarting the computer won’t fix the problem, as the problem is with the files on the computer’s hard drive — it has corrupted files or malware that loads at startup on its hard drive. However, reinstalling Windows (performing a “Refresh or Reset your PC” operation in Windows 8 terms) will wipe away everything on the computer’s hard drive, restoring it to its formerly clean state. This is simpler than looking through the computer’s hard drive, trying to identify the exact reason for the problems or trying to ensure you’ve obliterated every last trace of malware. It’s much faster to simply start over from a known-good, clean state instead of trying to locate every possible problem and fix it. Ultimately, the answer is that “resetting a computer wipes away the current state of the software, including any problems that have developed, and allows it to start over from square one.” It’s easier and faster to start from a clean state than identify and fix any problems that may be occurring — in fact, in some cases, it may be impossible to fix problems without beginning from that clean state. Image Credit: Arria Belli on Flickr, DeclanTM on Flickr     

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  • Ubuntu 13.10 New keyboard stuff bugged wine games

    - by karapinha
    I have made recently a fresh install of ubuntu 13.10. Since the first day I have problems with keyboard probably because of the new ibus thing... My language is PT-PT. One of those problems is the wrong behaviours on wine. games I was running in ubuntu 13.04 (tomb-raider, Skyrim, Shadow Warrior and Dark Souls) installed in the new ubuntu 13.10 they started to get key stuck when there is a combination like W+D+R (Drifting right + reloading) and its not because of windows/wine problems because the prefixes are the same that I had in 13.04. The key stuck as already been reported on winehq for Skyrim for some one using Linux Mint that was based on the 13.10. Is there a way of making the keyboard work like I was in 13.04? Or can i change the input type? Or downgrade ibus or something like that?

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  • How to replace a div container with javascript

    - by Kovu
    Hi, I must have a little design in javascript. I have a menu with 5 entrys and only 1 HTML-page. So I will have a content-div and enabled and disabled different static content in it, each menu-entry is another content. I tried with 5 divs and disable 4 of them and enable 1, but the element under each other means every div is like a - enabled or not, so the "content" is moving then. Hope its understandable. Here is the code so far: <html><head><title>Des Einsame-Katerchen's kleine Homepage</title> <style type="text/css"> a:link { font-weight:bold; color:blue; text-decoration:none; } a:visited { font-weight:bold; color:blue; text-decoration:none; } a:focus { font-weight:bold; color:blue; text-decoration:none; } a:hover { font-weight:bold; color:blue; text-decoration:line-through; } a:active { font-weight:bold; color:blue; text-decoration:none; } h1:focus { background-color:red; } h1:hover { background-color:silver; } h1:active { background-color:green; } </style> <script> function an(id) { document.getElementById('start').style.visibility = 'hidden'; document.getElementById('start').style.height = '0px'; document.getElementById('me').style.visibility = 'hidden'; document.getElementById('me').style.height = '0px'; document.getElementById('rpg').style.visibility = 'hidden'; document.getElementById('rpg').style.height = '0px'; document.getElementById('musik').style.visibility = 'hidden'; document.getElementById('musik').style.height = '0px'; document.getElementById('screens').style.visibility = 'hidden'; document.getElementById('screens').style.height = '0px'; document.getElementById(id).style.visibility = 'visible'; document.getElementById(id).style.height = '500px'; } </script> </head> <body style=" " > <div style="width=100%; text-align:center; border: 1px red solid; height:40px;"> <div style="float:left; width:100px;"><a href="#" OnClick="an('start')" >Startseite</a></div> <div style="float:left; width:100px;"><a href="#" OnClick="an('me')" >Über mich</a></div> <div style="float:left; width:100px;"><a href="#" OnClick="an('rpg')" >RPG-Chars</a></div> <div style="float:left; width:100px;"><a href="#" OnClick="an('musik')" >Musik</a></div> <div style="float:left; width:150px;"><a href="#" OnClick="an('screens')" >Knuddels-Screens</a></div> </div> <br> <div id="start" style="border:1px red solid; width:500px; height:500px; overflow: visible; " > a </div> <div id="me" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > b </div> <div id="rpg" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > c </div> <div id="musik" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > d </div> <div id="screens" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > e </div> </body>

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  • creating a color coded time chart using colorbar and colormaps in python

    - by Rusty
    I'm trying to make a time tracking chart based on a daily time tracking file that I used. I wrote code that crawls through my files and generates a few lists. endTimes is a list of times that a particular activity ends in minutes going from 0 at midnight the first day of the month to however many minutes are in a month. labels is a list of labels for the times listed in endTimes. It is one shorter than endtimes since the trackers don't have any data about before 0 minute. Most labels are repeats. categories contains every unique value of labels in order of how well I regard that time. I want to create a colorbar or a stack of colorbars (1 for eachday) that will depict how I spend my time for a month and put a color associated with each label. Each value in categories will have a color associated. More blue for more good. More red for more bad. It is already in order for the jet colormap to be right, but I need to get desecrate color values evenly spaced out for each value in categories. Then I figure the next step would be to convert that to a listed colormap to use for the colorbar based on how the labels associated with the categories. I think this is the right way to do it, but I am not sure. I am not sure how to associate the labels with color values. Here is the last part of my code so far. I found one function to make a discrete colormaps. It does, but it isn't what I am looking for and I am not sure what is happening. Thanks for the help! # now I need to develop the graph import numpy as np from matplotlib import pyplot,mpl import matplotlib from scipy import interpolate from scipy import * def contains(thelist,name): # checks if the current list of categories contains the one just read for val in thelist: if val == name: return True return False def getCategories(lastFile): ''' must determine the colors to use I would like to make a gradient so that the better the task, the closer to blue bad labels will recieve colors closer to blue read the last file given for the information on how I feel the order should be then just keep them in the order of how good they are in the tracker use a color range and develop discrete values for each category by evenly spacing them out any time not found should assume to be sleep sleep should be white ''' tracker = open(lastFile+'.txt') # open the last file # find all the categories categories = [] for line in tracker: pos = line.find(':') # does it have a : or a ? if pos==-1: pos=line.find('?') if pos != -1: # ignore if no : or ? name = line[0:pos].strip() # split at the : or ? if contains(categories,name)==False: # if the category is new categories.append(name) # make a new one return categories # find good values in order of last day newlabels=[] for val in getCategories(lastDay): if contains(labels,val): newlabels.append(val) categories=newlabels # convert discrete colormap to listed colormap python for ii,val in enumerate(labels): if contains(categories,val)==False: labels[ii]='sleep' # create a figure fig = pyplot.figure() axes = [] for x in range(endTimes[-1]%(24*60)): ax = fig.add_axes([0.05, 0.65, 0.9, 0.15]) axes.append(ax) # figure out the colors to use # stole this function to make a discrete colormap # http://www.scipy.org/Cookbook/Matplotlib/ColormapTransformations def cmap_discretize(cmap, N): """Return a discrete colormap from the continuous colormap cmap. cmap: colormap instance, eg. cm.jet. N: Number of colors. Example x = resize(arange(100), (5,100)) djet = cmap_discretize(cm.jet, 5) imshow(x, cmap=djet) """ cdict = cmap._segmentdata.copy() # N colors colors_i = np.linspace(0,1.,N) # N+1 indices indices = np.linspace(0,1.,N+1) for key in ('red','green','blue'): # Find the N colors D = np.array(cdict[key]) I = interpolate.interp1d(D[:,0], D[:,1]) colors = I(colors_i) # Place these colors at the correct indices. A = zeros((N+1,3), float) A[:,0] = indices A[1:,1] = colors A[:-1,2] = colors # Create a tuple for the dictionary. L = [] for l in A: L.append(tuple(l)) cdict[key] = tuple(L) # Return colormap object. return matplotlib.colors.LinearSegmentedColormap('colormap',cdict,1024) # jet colormap goes from blue to red (good to bad) cmap = cmap_discretize(mpl.cm.jet, len(categories)) cmap.set_over('0.25') cmap.set_under('0.75') #norm = mpl.colors.Normalize(endTimes,cmap.N) print endTimes print labels # make a color list by matching labels to a picture #norm = mpl.colors.ListedColormap(colorList) cb1 = mpl.colorbar.ColorbarBase(axes[0],cmap=cmap ,orientation='horizontal' ,boundaries=endTimes ,ticks=endTimes ,spacing='proportional') pyplot.show()

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  • Problem when scaling game screen in Libgdx

    - by Nicolas Martel
    Currently, I'm able to scale the screen by applying this bit of code onto an OrthographicCamera Camera.setToOrtho(true, Gdx.graphics.getWidth() / 2, Gdx.graphics.getHeight() / 2); But something quite strange is happening with this solution, take a look at this picture of my game below Seems fine right? But upon further investigation, many components are rendered off by one pixels, and the tiles all are. Take a closer look I circled a couple of the errors. Note that the shadow of the warrior I circled appears fine for the other warriors. Also keep in mind that everything is rendered at pixel-perfect precision when I disable the scaling. I actually thought of a possible source for the problem as I'm writing this but I decided to still post this because I would assume somebody else might run into the same issue.

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