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  • Problem with the way the Ajax Control Toolkit tab control sets the default submit button

    - by Colin
    We have a tab control containing some textboxes for doing a search. When you keypress inside one of the textboxes, the tab control sets the default button to be the button immediately following the tab control. This is fine because that's the search button. The problem occurs after the button is clicked and results returned. Now there is no default button, and keypress does nothing. Any suggestions?

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  • Disable button when clicked and make other buttons enabled

    - by tito11
    i have three buttons what is the best way to disable button when clicked and make other two button enabled <Button Name="initialzeButton" Width="50" Height="25" Margin="460,0,0,0" HorizontalAlignment="Left" VerticalAlignment="Center" Click="initialzeButton_Click" Content="Start" Cursor="Hand" /> <Button Name="uninitialzeButton" Width="50" Height="25" Margin="0,0,64,0" HorizontalAlignment="Right" VerticalAlignment="Center" Click="uninitialzeButton_Click" Content="Stop" Cursor="Hand" /> <Button Name="loadButton" Width="50" Height="25" Margin="0,0,9,0" HorizontalAlignment="Right" VerticalAlignment="Center" Click="loadButton_Click" Content="Load" Cursor="Hand" />

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  • How to click TinyMCE toolbar's button programmatically ?

    - by hongkildong
    I want to make preview button as usual form button next to submit button(as it made in most cases of "Post new topic" forms). How can I programmatically simulate toolbar's preview button click ? I tried $('#article_body_preview').click() but it didn't work. (I use jQuery lib and #article_body_preview is toolbar's preview button element )

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  • How to disable the delete button using if condition in Extjs

    - by sample
    How to disable the delete button using if condition in Extjs for ex;i want to disable the button if it satifies the given if condition else remain enabled. if(validAction(entityHash.get('entity.xyz'),actionHash.get('action.delete'))) This is the grid Delete button code. Ext.reg("gridheaderbar-inActive", Ad.GridInActiveButton,{ xtype: 'tbspacer', width: 5 }); Ad.GridCampDeleteButton = Ext.extend(Ext.Toolbar.Button, { //text: 'Delete', cls: 'ad-img-button', width:61, height:40, iconCls: 'ad-btn-icon', icon: '/webapp/resources/images/btn_del.png', handler:function(){ statusChange(this.parentBar.parentGrid, 'Delete') } });

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  • Encapsulating a Windows.Forms.Button

    - by devoured elysium
    I want to define a special kind of button that only allows two possible labels: "ON" and "OFF". I decided to inherit from a Windows.Forms.Button to implement this but now I don't know I how should enforce this rule. Should I just override the Text property like this? public override string Text { set { throw new InvalidOperationException("Invalid operation on StartStopButton!"); } } The problem I see with this is that I am breaking the contract that all buttons should have. If any code tries something like foreach (Button button in myForm) { button.Text = "123"; } they will get an Exception if I have any of my special buttons on the form, which is something that isn't expectable. First, because people think of properties just as "public" variables, not methods, second, because they are used to using and setting whatever they want to buttons without having to worry with Exceptions. Should I instead just make the set property do nothing? That could also lead to awkward results: myButton.Text = "abc"; MessageBox.Show(abc); //not "abc"! The general idea from the OO world is to in this kind of cases use Composition instead of inheritance. public class MySpecialButton : <Some class from System.Windows.Forms that already knows how to draw itself on forms> private Button button = new Button(); //I'd just draw this button on this class //and I'd then only show the fields I consider //relevant to the outside world. ... } But to make the Button "live" on a form it must inherit from some special class. I've looked on Control, but it seems to already have the Text property defined. I guess the ideal situation would be to inherit from some kind of class that wouldn't even have the Text property defined, but that'd have position, size, etc properties available. Upper in the hierarchy, after Control, we have Component, but that looks like a really raw class. Any clue about how to achieve this? I know this was a long post :( Thanks

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  • Java UIManager - What's the name of the area around a button

    - by soulTower
    I'm using the Windows XP look and feel. On a panel containing a button there is a rectangular area around a button that looks like the area that a classic button would take up. That area is not adhering to the color of my panel. For example I'm setting my panel to blue but the area around the button is still white. What is the name of that area. I've tried button.shadow but that's not it. Thanks ST

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  • Click on button not taking to next Activity in android

    - by user1805266
    When i click on GO button its not taking to next Activity. I am using the following code.. can any one correct me where am i going wrong? final Button button = (Button) findViewById(R.id.button1); button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { // Perform action on click startActivity(new Intent(currentActivity.this, NextActivity.class)); } });

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  • Touchpad hardware button disables keyboard too

    - by jjg
    I have an old but nice Samsung X50 running MM which has a key between the touchpad buttons which disables the touchpad. Very nice, no-one like to brush against the touchpad while typing. It seems to be a hardware feature -- a BIOS style window appears at the top left of the screen when you press it saying "touchpad off"; and when you press it again it says "touchpad on", and so it is, but now the keyboard has no effect in X, I can type nothing except to meta-ctl F1 to the console. After a reboot the problem persists; and the only way I have found to fix it is to blow away .gconf are replace it with a copy I made in happier times. Deleting/modifying .gconf/desktop/gnome/peripherals/touchpad/%gconf.xml does not fix the problem. There is no way to turn off the switch in BIOS without losing the touchpad. I would prise the thing out with a screwdriver if I could, but it's a work machine. This button is the bane of my life, hanging over me like a sword of Damocles.

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  • Can't change settings for Mobile Broadband Dongle - Button is greyed out

    - by Ross LIndsey
    I was with VirginBroadband.com.au (Australia). My huawai 3G Dongle was working great on Ubuntu, However I have changed ISP's. I unlocked the modem, and put in the new SIM. I have tested this in my Windows PC and it connects to the new (Optus) Network A-OK and it all works. When I put this dongle (the same one that was working fine in Ubuntu) into that same Ubuntu Netbook it simply won't connect. When I try to go into the dialog to try and add or change settings the button to change or update settings is greyed out, I can't select it. Apparently since this dongle was already recognized the Broadband Setup Wizard won't start, and I have no idea how to get it to start (presuming it has the ability to configure an already recognized dongle). What do I have to do to either enable the ability to change the configuration for this setup, or to blow away the one that is set up so the Broadband Wizard will re-start and let me configure a new one. Can anyone provide simple instructions for doing this? I'm using Ubuntu with the Cinnamon Desktop

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  • Black Screen on pressing back button in libgdx

    - by user26384
    In my game when i touch on advertisements and press back button to return on game the i am getting a black screen. I referred this link. I tried to change IosGraphics.java but the change is not reflected in monotouch project. I did the following : Extracted nightly.zip and opened gdx-backend-iosmonotouch-sources From there I changed IosGraphicsjava. I then made a new jar file gdx-backend-iosmonotouch.jar and replaced it with original jar file in the nightly folder. Compressed all the files from nightly folder in .zip file. Used this .zip file to make a new project throuch gdx-setup-ui.jar. I tried to open my project in monotouch and from com-gdx-backendios.dll i found that the changes in IosGraphics are not being reflected. Am I missing something? How do I solve this? I even tried to open gdx-backend-iosmonotouch-sources.jar with winrar and edit IosGraphics.java and save it. Even this didn't work.

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  • help with yes/no radio button for multiple questions pull from database

    - by Darlene
    hey guys i need a little help with this questionaire form. The tables currently using are: user userid| username answers aswerid|quesid|ans|userid|date ques quesid|ques The form below is what im using however i'm gettin errors for radio button.... could anyone offer advice? $query = mysql_query("SELECT * FROM ques", $con) or die("Cannot Access tblprequeations From Server"); echo"<div id='quesform' class='quesform'>"; echo"<form name='QForm' method='post' action='answers.php' onsubmit='return validateQForm(this);'>"; echo"<p>"; while($row = mysql_fetch_array($query)) { echo"<p>"; echo"<label>".$row['quesid']."</label>&nbsp; &nbsp;"; echo"<label>".$row['ques']."</label>&nbsp; &nbsp;"; echo"<input type='radio' name='ans' value='yes' if (isset($_POST['ans']) && $_POST['ans'] == 'yes') echo'checked'/>"; echo"<input type='radio' name='ans' value='no' if (isset($_POST['ans']) && $_POST['ans'] == 'no') echo'checked'/>"; echo"</p>"; } echo"</p>";

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  • Can I increase a buttons onclick-area programmatically?

    - by sandis
    Sometimes I have a button in my UI that it is so small that it is difficult to click. My solution so far has been to add a transparent border around the button in photoshop. Just increasing the padding on the button does not work, since this will also stretch the image. Since it is kind of a fuss to open photoshop each time I want to change the clickable surface, is there any way to do this programmatically? I have tried placing a framelayout behind the button and make it clickable, but then the button wont change appearance on touch as it should. Ofcourse I could also add a ontouchlistener on the framelayout which changes the buttons appearance, but then it quite some code if I have several of those buttons. Cheers,

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  • How to add Editext and Button to Efficent Adapter which has a Icon and text

    - by jayanthgande
    Hi, I want to create a layout in such a way that on top edittext and button should be there in one row. The search text I enter in editext and click on search button. Then I want to display a custom list view where each row contains image and text.(As per the API demos example list14 I have tried). But when I run the application, button and edittext are being added to each row (i.e., Each row contains a image, text, editext, button. Can Any one guide how to resolve this issue. Below is my xml file: <!-- <FrameLayout android:layout_width="wrap_content" android:layout_height="0dip" android:layout_weight="1"></FrameLayout> --> <ImageView android:id="@+id/icon" android:layout_width="48dip" android:layout_height="48dip" /> <TextView android:id="@+id/text" android:layout_gravity="center_vertical" android:layout_width="0dip" android:layout_weight="1.0" android:layout_height="wrap_content" /> <!-- <EditText android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/prdsearchtb" android:text="@string/tb_prd_search_lbl"></EditText> --> <!-- <TableLayout android:id="@+id/TableLayout01" android:layout_width="fill_parent" android:layout_height="wrap_content"> <TableRow> --> <Button android:id="@+id/prdsrcbutton" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="@string/btn_lbl_prd_search" android:layout_x="2px" android:layout_y="410px"></Button> <!-- </TableRow> </TableLayout> -- and Java File: /** * */ package org.techdata.activity; import android.app.AlertDialog; import android.app.ListActivity; import android.content.Context; import android.content.Intent; import android.graphics.Bitmap; import android.graphics.BitmapFactory; import android.os.Bundle; import android.util.Log; import android.view.LayoutInflater; import android.view.View; import android.view.ViewGroup; import android.widget.BaseAdapter; import android.widget.Button; import android.widget.EditText; import android.widget.ImageView; import android.widget.ListView; import android.widget.TextView; /** * @author jayanthg * */ public class ProductSearch extends ListActivity { private static class ProductSearchAdapter extends BaseAdapter { private LayoutInflater mInflater; private Bitmap mIcon1; private Bitmap mIcon2; public ProductSearchAdapter(Context context) { mInflater = LayoutInflater.from(context); // Icons bound to the rows. mIcon1 = BitmapFactory.decodeResource(context.getResources(), R.drawable.icon48x48_1); mIcon2 = BitmapFactory.decodeResource(context.getResources(), R.drawable.icon48x48_2); } @Override public int getCount() { return DATA.length; } @Override public Object getItem(int position) { return position; } @Override public long getItemId(int position) { return position; } @Override public View getView(final int position, View convertView, ViewGroup parent) { ViewHolder holder; Button btn=null; if (convertView == null) { convertView = mInflater.inflate(R.layout.productsearch, null); // Creates a ViewHolder and store references to the two children // views // we want to bind data to. holder = new ViewHolder(); holder.text = (TextView) convertView.findViewById(R.id.text); holder.icon = (ImageView) convertView.findViewById(R.id.icon); btn=(Button)convertView.findViewById(R.id.prdsrcbutton); convertView.setTag(holder); } else { // Get the ViewHolder back to get fast access to the TextView // and the ImageView. holder = (ViewHolder) convertView.getTag(); } // Bind the data efficiently with the holder. holder.text.setText(DATA[position]); holder.icon.setImageBitmap((position & 1) == 1 ? mIcon1 : mIcon2); holder.icon.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Log.i("image", " u clicked on icon Position" + position); } }); holder.text.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Log.i("Text", " u clicked on text Position" + position); } }); btn.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Log.i("Button","U clicked on button"); } }); return convertView; } static class ViewHolder { TextView text; ImageView icon; } private static final String[] DATA = { "Abbaye de Belloc", "Abbaye du Mont des Cats" }; } ListView product_search_list; Button srch_btn; EditText srch_text; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setListAdapter(new ProductSearchAdapter(this)); // setContentView(R.layout.productsearch); // getListView().setEmptyView(findViewById(R.id.text)); // srch_text = (EditText)findViewById(R.id.prdsearchtb); // srch_btn = (Button) findViewById(R.id.prdsearchtb); // srch_btn.setOnClickListener(new View.OnClickListener() { // // @Override // public void onClick(View v) { // callProductSearchAdapter(); // // } // }); } void callProductSearchAdapter() { setListAdapter(new ProductSearchAdapter(this)); } private void createDialog(String title, String text, final Intent i) { if (i == null) { AlertDialog ad = new AlertDialog.Builder(this).setIcon( R.drawable.alert_dialog_icon).setPositiveButton("Ok", null) .setTitle(title).setMessage(text).create(); ad.show(); } } } Regards: Jayanth

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  • Connecting SceneBuilder edited FXML to Java code

    - by daniel
    Recently I had to answer several questions regarding how to connect an UI built with the JavaFX SceneBuilder 1.0 Developer Preview to Java Code. So I figured out that a short overview might be helpful. But first, let me state the obvious. What is FXML? To make it short, FXML is an XML based declaration format for JavaFX. JavaFX provides an FXML loader which will parse FXML files and from that construct a graph of Java object. It may sound complex when stated like that but it is actually quite simple. Here is an example of FXML file, which instantiate a StackPane and puts a Button inside it: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml"> <children> <Button mnemonicParsing="false" text="Button" /> </children> </StackPane> ... and here is the code I would have had to write if I had chosen to do the same thing programatically: import javafx.scene.control.*; import javafx.scene.layout.*; ... final Button button = new Button("Button"); button.setMnemonicParsing(false); final StackPane stackPane = new StackPane(); stackPane.setPrefWidth(200.0); stackPane.setPrefHeight(150.0); stacPane.getChildren().add(button); As you can see - FXML is rather simple to understand - as it is quite close to the JavaFX API. So OK FXML is simple, but why would I use it?Well, there are several answers to that - but my own favorite is: because you can make it with SceneBuilder. What is SceneBuilder? In short SceneBuilder is a layout tool that will let you graphically build JavaFX user interfaces by dragging and dropping JavaFX components from a library, and save it as an FXML file. SceneBuilder can also be used to load and modify JavaFX scenegraphs declared in FXML. Here is how I made the small FXML file above: Start the JavaFX SceneBuilder 1.0 Developer Preview In the Library on the left hand side, click on 'StackPane' and drag it on the content view (the white rectangle) In the Library, select a Button and drag it onto the StackPane on the content view. In the Hierarchy Panel on the left hand side - select the StackPane component, then invoke 'Edit > Trim To Selected' from the menubar That's it - you can now save, and you will obtain the small FXML file shown above. Of course this is only a trivial sample, made for the sake of the example - and SceneBuilder will let you create much more complex UIs. So, I have now an FXML file. But what do I do with it? How do I include it in my program? How do I write my main class? Loading an FXML file with JavaFX Well, that's the easy part - because the piece of code you need to write never changes. You can download and look at the SceneBuilder samples if you need to get convinced, but here is the short version: Create a Java class (let's call it 'Main.java') which extends javafx.application.Application In the same directory copy/save the FXML file you just created using SceneBuilder. Let's name it "simple.fxml" Now here is the Java code for the Main class, which simply loads the FXML file and puts it as root in a stage's scene. /* * Copyright (c) 2012, Oracle and/or its affiliates. All rights reserved. */ package simple; import java.util.logging.Level; import java.util.logging.Logger; import javafx.application.Application; import javafx.fxml.FXMLLoader; import javafx.scene.Scene; import javafx.scene.layout.StackPane; import javafx.stage.Stage; public class Main extends Application { /** * @param args the command line arguments */ public static void main(String[] args) { Application.launch(Main.class, (java.lang.String[])null); } @Override public void start(Stage primaryStage) { try { StackPane page = (StackPane) FXMLLoader.load(Main.class.getResource("simple.fxml")); Scene scene = new Scene(page); primaryStage.setScene(scene); primaryStage.setTitle("FXML is Simple"); primaryStage.show(); } catch (Exception ex) { Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex); } } } Great! Now I only have to use my favorite IDE to compile the class and run it. But... wait... what does it do? Well nothing. It just displays a button in the middle of a window. There's no logic attached to it. So how do we do that? How can I connect this button to my application logic? Here is how: Connection to code First let's define our application logic. Since this post is only intended to give a very brief overview - let's keep things simple. Let's say that the only thing I want to do is print a message on System.out when the user clicks on my button. To do that, I'll need to register an action handler with my button. And to do that, I'll need to somehow get a handle on my button. I'll need some kind of controller logic that will get my button and add my action handler to it. So how do I get a handle to my button and pass it to my controller? Once again - this is easy: I just need to write a controller class for my FXML. With each FXML file, it is possible to associate a controller class defined for that FXML. That controller class will make the link between the UI (the objects defined in the FXML) and the application logic. To each object defined in FXML we can associate an fx:id. The value of the id must be unique within the scope of the FXML, and is the name of an instance variable inside the controller class, in which the object will be injected. Since I want to have access to my button, I will need to add an fx:id to my button in FXML, and declare an @FXML variable in my controller class with the same name. In other words - I will need to add fx:id="myButton" to my button in FXML: -- <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> and declare @FXML private Button myButton in my controller class @FXML private Button myButton; // value will be injected by the FXMLLoader Let's see how to do this. Add an fx:id to the Button object Load "simple.fxml" in SceneBuilder - if not already done In the hierarchy panel (bottom left), or directly on the content view, select the Button object. Open the Properties sections of the inspector (right panel) for the button object At the top of the section, you will see a text field labelled fx:id. Enter myButton in that field and validate. Associate a controller class with the FXML file Still in SceneBuilder, select the top root object (in our case, that's the StackPane), and open the Code section of the inspector (right hand side) At the top of the section you should see a text field labelled Controller Class. In the field, type simple.SimpleController. This is the name of the class we're going to create manually. If you save at this point, the FXML will look like this: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml" fx:controller="simple.SimpleController"> <children> <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> </children> </StackPane> As you can see, the name of the controller class has been added to the root object: fx:controller="simple.SimpleController" Coding the controller class In your favorite IDE, create an empty SimpleController.java class. Now what does a controller class looks like? What should we put inside? Well - SceneBuilder will help you there: it will show you an example of controller skeleton tailored for your FXML. In the menu bar, invoke View > Show Sample Controller Skeleton. A popup appears, displaying a suggestion for the controller skeleton: copy the code displayed there, and paste it into your SimpleController.java: /** * Sample Skeleton for "simple.fxml" Controller Class * Use copy/paste to copy paste this code into your favorite IDE **/ package simple; import java.net.URL; import java.util.ResourceBundle; import javafx.fxml.FXML; import javafx.fxml.Initializable; import javafx.scene.control.Button; public class SimpleController implements Initializable { @FXML // fx:id="myButton" private Button myButton; // Value injected by FXMLLoader @Override // This method is called by the FXMLLoader when initialization is complete public void initialize(URL fxmlFileLocation, ResourceBundle resources) { assert myButton != null : "fx:id=\"myButton\" was not injected: check your FXML file 'simple.fxml'."; // initialize your logic here: all @FXML variables will have been injected } } Note that the code displayed by SceneBuilder is there only for educational purpose: SceneBuilder does not create and does not modify Java files. This is simply a hint of what you can use, given the fx:id present in your FXML file. You are free to copy all or part of the displayed code and paste it into your own Java class. Now at this point, there only remains to add our logic to the controller class. Quite easy: in the initialize method, I will register an action handler with my button: () { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... -- ... // initialize your logic here: all @FXML variables will have been injected myButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... That's it - if you now compile everything in your IDE, and run your application, clicking on the button should print a message on the console! Summary What happens is that in Main.java, the FXMLLoader will load simple.fxml from the jar/classpath, as specified by 'FXMLLoader.load(Main.class.getResource("simple.fxml"))'. When loading simple.fxml, the loader will find the name of the controller class, as specified by 'fx:controller="simple.SimpleController"' in the FXML. Upon finding the name of the controller class, the loader will create an instance of that class, in which it will try to inject all the objects that have an fx:id in the FXML. Thus, after having created '<Button fx:id="myButton" ... />', the FXMLLoader will inject the button instance into the '@FXML private Button myButton;' instance variable found on the controller instance. This is because The instance variable has an @FXML annotation, The name of the variable exactly matches the value of the fx:id Finally, when the whole FXML has been loaded, the FXMLLoader will call the controller's initialize method, and our code that registers an action handler with the button will be executed. For a complete example, take a look at the HelloWorld SceneBuilder sample. Also make sure to follow the SceneBuilder Get Started guide, which will guide you through a much more complete example. Of course, there are more elegant ways to set up an Event Handler using FXML and SceneBuilder. There are also many different ways to work with the FXMLLoader. But since it's starting to be very late here, I think it will have to wait for another post. I hope you have enjoyed the tour! --daniel

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  • How to remap "Dashboard" key to show the Desktop on OSX [Snow] Leopard?

    - by Mike
    I use my Desktop far more often than I use my Dashboard. However, my MacBook Pro comes with a dedicated key for Dashboard but it doesn't come with one for Desktop. Using this article, I was able to remap my Dashboard key to show the desktop by changing the values for keys 62 and 63 ("Dashboard") to the same values used by keys 36 and 37 ("Show Desktop"). Specifically, I changed the value for both array index #1s to 111. This worked great for my external (kinesis freestyle) keyboard. But when I went back to my internal macbook keyboard, I discovered that the Dashboard key still mapped to the Dashboard rather than the Desktop. How can I complete this mapping for all of my keyboards? The Kinesis Freestyle, my internal MacBook Pro keyboard, and my external Apple Aluminum Bluetooth keyboard? Update: I'm definitely not looking for a solution that involves using the Function keys instead of the special keys. I wish to keep using my Function keys as function keys as they're indispensable for other applications.

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  • Conditional hotkey or include in AutoHotKey

    - by Bowen
    Is there a way to define a Hotkey conditionally in AutoHotKey? I want to do different keyboard mappings for different machines with different physical keyboards. This is what I want to do: RegRead, ComputerName, HKEY_LOCAL_MACHINE, System\CurrentControlSet\Control\ComputerName, ComputerName If ( ComputerName = BDWELLE-DIM8300 ) { #Include %A_ScriptDir%\Mappings-BDWELLE-DIM8300.ahk } OR RegRead, ComputerName, HKEY_LOCAL_MACHINE, System\CurrentControlSet\Control\ComputerName, ComputerName If ( ComputerName = BDWELLE-DIM8300 ) { LWin::LAlt [more hotkey definitions that only apply to this machine] } but since AHK parses Hotkey definitions and #Include statements BEFORE interpreting If statements, the Hotkeys definitions (whether buried in an #Include or not) do not respect the If condition. Thanks for pointing me to AutoHotKey_L! Do you have a specific example of how to conditionally define a hotkey? The syntax is very confusing. Here's what I'm trying (after having installed AutoHotKey_L.exe in place of AutoHotKey.exe): RegRead, ComputerName, HKEY_LOCAL_MACHINE, System\CurrentControlSet\Control\ComputerName, ComputerName #If ( ComputerName = BDWELLE-DIM8300 ) LWin::LAlt but that doesn't seem to work...

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  • Excel 2007 - Closing Using The Close Button When Using Personal.xlsb To Store Marcos

    - by XXXXXXXXXXXXXXXXX
    When I create and store macros in Excel 2007 using the Personal file in the XLstart folder then open and go to close Excel using the close buttom in the upper right hand corner I now have to click it twice to completely close Excel however if I use the Excel Exit button by clicking on the Office 2007 button first Excel will close on one. Is there away I can store macros for use with all workbooks I open with Excel and be able to close on one from the close button in the upper right hand corner after saving the current workbook I have be working on?

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  • How to remap CAPSLOCK to ESC in Linux Mint 12

    - by imcoddy
    I would like to remap the CAPSLOCK key to ESC as this is easier to use in Vim. I can make it in Ubuntu 11.04 as there's an option for this in Keyborad configuration. But recently I switched to use Linux Mint and found that there's no such option. I don't know whether it is the gnome3 that makes this happen, as there are only some basic features to customize. Hoping someone can help me remap the key, thanks in advance. found this article, but the options are not found in Mint 12

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  • WPF Image change source when button is disabled

    - by Taylor
    Hi, I'm trying to show a different image when the button is disabled. Should be easy with triggers, right?! For some reason, I have not been able to get the images to switch. I've tried setting triggers on both the image and button. What is wrong with what I have below? How can I change the image source when the button is enabled/disabled? Thanks! <Button x:Name="rleft" Command="{Binding Path=Operation}" CommandParameter="{x:Static vm:Ops.OpA}"> <Button.Content> <StackPanel> <Image Width="24" Height="24" RenderOptions.BitmapScalingMode="NearestNeighbor" SnapsToDevicePixels="True" Source="/MyAssembly;component/images/enabled.png"> <Image.Style> <Style> <Style.Triggers> <DataTrigger Binding="{Binding ElementName=rleft, Path=Button.IsEnabled}" Value="False"> <Setter Property="Image.Source" Value="/MyAssembly;component/images/disabled.png" /> </DataTrigger> </Style.Triggers> </Style> </Image.Style> </Image> </StackPanel> </Button.Content> </Button>

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  • How to disable "back" button on my mouse?

    - by Sergiy Byelozyorov
    I have bought Microsoft Bluetooth Notebook Mouse 5000. It's working just as I want it except that "back" button on the right side. I constantly hit it with the thumb and browser goes back. I am not used to this behavior, since my older mouse didn't have such a button. I just want to get rid of it -- disable the button once and forever, so if I clicked it -- nothing should happen.

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  • Getting some French-Canadian keyboard strokes to work on English keyboard

    - by Gradient
    I'm trying to use some of the French-Canadian keyboard stokes I'm used to on an English keyboard. I would like to change the behaviour of some keys. I was able to implement these changes in Vim, but I would like them to be applied system-wide (for Windows and Ubuntu). Here's what I want to implement : If I press [a, the character printed is â. When I press [r, something that's supposed to stay normal, the characters printed are [r. If I hold [ for 3 seconds, [ is printed. I want this delay to be applied to all my modified keys. I want to map < to ' and the characters 'e to è. The complex problem here is that I only want the ' beside the ; key to produce the è character, NOT when I press the < (remapped to ') then e. I'll show you a .vimrc file that implements this, now I want this behavior system-wide: set timeout timeoutlen=3000 ttimeoutlen=100 inoremap [a â inoremap [A Â inoremap [e ê inoremap [E Ê inoremap [i î inoremap [I Î inoremap [o ô inoremap [O Ô inoremap [u û inoremap [U Û inoremap 'a à inoremap 'A À inoremap 'e è inoremap 'E È inoremap 'u ù inoremap 'U Ù inoremap }e ë inoremap }E Ë inoremap }i ï inoremap }I Ï inoremap }u ü inoremap }U Ü inoremap ]c ç inoremap ]C Ç inoremap / é inoremap < '

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  • Button Visibility Converter

    - by developer
    Hi All, I have a requirement wherein I need to display on a User form, a Create Button if that user has doesnt have a profile and a Edit Button if he does have a profile. I am using a converter to change the visibility of the button. Below is my code, <StackPanel Orientation="Horizontal"> <Button Content="Create Profile" Visibility="{Binding Profile,Converter={StaticResource ButtonVisibilityConverter}, ConverterParameter='Create'}" Command="local:LaunchEditor" CommandParameter="{Binding}"/> <Button Content="Edit Profile" Visibility="{Binding Profile,Converter={StaticResource ButtonVisibilityConverter}, ConverterParameter='Edit'}" Command="local:LaunchEditor" CommandParameter="{Binding}"/> </StackPanel> Below is my converter code public class ButtonVisibilityConverter : IValueConverter { public object Convert(object value, Type targetType, object parameter, CultureInfo culture) { string btName = null; btName = (string)parameter; if ((value==null)&&(btName=="Create")) { return Visibility.Visible; } else if ((value != null) && (btName=="Edit")) { return Visibility.Visible; } else { return Visibility.Collapsed; } } public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture) { throw new NotImplementedException(); } } Everything works fine initially, but the moment I click on the Create Profile window, and it is the constructor that loads the profile window, after that even if I close that window without doing anything, the Create button turns to edit. My guess is that, it is because the constructor would have create the profile object and so even though the object is empty it shows me edit button instead of create. Is there any other way I could display button visibility??

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  • How to Get Specific Button pressed in a repeater when using ModalPopupExtender

    - by MemphisDeveloper
    I have buttons contained within a repeater. A ModalPopupExtender is used to confirm event for each button. I create standard panels outside of the repeater and I attach each button in the repeater to these panels from inside the repeater. The problem is once the button is pressed in the popup I can't figure out how to determine which row of the repeater to edit as I can't figure out how to identify which button was pressed. Panel: <asp:Panel ID="pnlRemoveAlert" runat="server" > <h1 align="center">Remove Phone</h1> <asp:Button ID="butRemove" runat="server" OnCommand="Handle_Click" CommandName="Remove" Text="Continue"/> <asp:Button ID="butRemoveCancel" runat="server" Text="Cancel"/> </asp:Panel> Repeater: <asp:Repeater ID="repPhoneNumbers" runat="server" OnItemDataBound="setButtonModals"> <ItemTemplate> ... <asp:Button ID="btnStatus" runat="server"/> <asp:Button ID="dummybutton" runat="Server" Visible="false" /> <ajaxToolkit:ModalPopupExtender ID="mpeEnable" runat="server" TargetControlID = "btnStatus CancelControlID="butEnableCancel" PopupControlID="pnlEnableAlert"/> ... Event Handle: Protected Sub Handle_Click(ByVal sender As Object, ByVal e As CommandEventArgs) 'I need to know which row of the repeater to deal with here End Sub

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