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  • Rails Variable across all controller actions

    - by bob
    Hello, This should be a very simple rails question. I have a variable like the following. @administration = Administration.first I want this variable to be accessible through every controller action across all my controllers so for example if I have a Product controller and inside of it I have the usual CRUD actions, I want the @administration variable as defined above to be put into all the CRUD actions. (It would not be needed in destroy or create or update). I have many controllers throughout my project and I was wondering if there is an easier way than adding it manually through all of the actions that I want it in. I tried a global variable $administration = Administration.first but I run into an issue where it is not updated when I update the actual content of the Administration.first table. Also, I would like to avoid global variables. Any help would be much appreciated. Thanks! :)

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  • Play 2.0 javaToDo tutorial doesn't compile

    - by chsn
    I'm trying to follow the Play2.0 JavaToDO tutorial and for some reason it just doesn't want to work. Have looked through stackoverflow and other online resources, but haven't find an answer to this and it's driving me crazy. Attached code of the Application.java package controllers; import models.Task; import play.data.Form; import play.mvc.Controller; import play.mvc.Result; public class Application extends Controller { static Form<Task> taskForm = form(Task.class); public static Result index() { return redirect(routes.Application.tasks()); } public static Result tasks() { return ok( views.html.index.render(Task.all(), taskForm)); } public static Result newTask() { return TODO; } public static Result deleteTask(Long id) { return TODO; } } Attached code of the Task java package models; import java.util.List; import javax.persistence.Entity; import play.data.Form; import play.data.validation.Constraints.Required; import play.db.ebean.Model.Finder; import play.mvc.Result; import controllers.routes; @Entity public class Task { public Long id; @Required public String label; // search public static Finder<Long,Task> find = new Finder( Long.class, Task.class); // display tasks public static List<Task> all() { return find.all(); } // create task public static void create(Task task) { task.create(task); } // delete task public static void delete(Long id) { find.ref(id).delete(id); // find.ref(id).delete(); } // create new task public static Result newTask() { Form<Task> filledForm = taskForm.bindFromRequest(); if(filledForm.hasErrors()) { return badRequest( views.html.index.render(Task.all(), filledForm) ); } else { Task.create(filledForm.get()); return redirect(routes.Application.tasks()); } } } I get a compile error on Task.java on the line static Form<Task> taskForm = form(Task.class); As I'm working on eclipse (the project is eclipsified before import), it's telling me that taskForm cannot be resolved and it also underlines every play 2 command e.g. "render(), redirect(), bindFromRequest()" asking me to create a method for it. Any ideas how to solve the compilations error and also how to get Eclipse to recognize the play2 commands? EDIT: updated Application.java package controllers; import models.Task; import play.data.Form; import play.mvc.Controller; import play.mvc.Result; public class Application extends Controller { // create new task public static Result newTask() { Form<Task> filledForm = form(Task.class).bindFromRequest(); if(filledForm.hasErrors()) { return badRequest( views.html.index.render(Task.all(), filledForm) ); } else { Task.newTask(filledForm.get()); return redirect(routes.Application.tasks()); } } public static Result index() { return redirect(routes.Application.tasks()); } public static Result tasks() { return ok( views.html.index.render(Task.all(), taskForm)); } public static Result deleteTask(Long id) { return TODO; } } Updated task.java package models; import java.util.List; import javax.persistence.Entity; import play.data.Form; import play.data.validation.Constraints.Required; import play.db.ebean.Model; import play.db.ebean.Model.Finder; import play.mvc.Result; import controllers.routes; @Entity public class Task extends Model { public Long id; @Required public String label; // Define a taskForm static Form<Task> taskForm = form(Task.class); // search public static Finder<Long,Task> find = new Finder( Long.class, Task.class); // display tasks public static List<Task> all() { return find.all(); } // create new task public static Result newTask(Task newTask) { save(task); } // delete task public static void delete(Long id) { find.ref(id).delete(id); // find.ref(id).delete(); } }

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  • Teacher confused about MVC?

    - by Gideon
    I have an assignment to create a game in java using MVC as a pattern. The thing is that stuff I read about MVC aren't really what the teacher is telling me. What I read is that the Model are the information objects, they are manipulated by the controllers. So in a game the controller mutates the placement of the objects and check if there is any collision etc. What my teacher told me is that I should put everything that is universal to the platform in the models and the controllers should only tell the model which input is given. That means the game loop will be in a model class, but also collision checks etc. So what I get from his story is that the View is the screen, the Controller is the unput handeler, and the Model is the rest. Can someone point me in the right direction?

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  • Widget_Controller for different types of data (MVC)

    - by steve-o
    Hello, I have a few widgets I need to show on a site - they are all relating to different types of data (e.g user, house). Each type of data and its relations is represented in specific models, but as far as a controller or helper is concerned, is it an ok plan to have a generic Widget controller/helper which generates the necessary widgets, even though each widget is dealing with distinct data? I don't really want to generate these widgets within the User and House controllers, as these controllers are dealing with different types of functionality. I'd imagine that the Widget_Controller could just contain static methods for generating these widgets, e.g: Widget_Controller::user_panel(); Does that make sense? Cheers!

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  • Zend Framework Autoloading in 3 modules

    - by haohan
    I am new to ZF and I am writing in Zend Framework 1.10 . Here is my application directory structure. APPLICATION_PATH` +-configs +-layouts +-modules +-admin ¦ +-controllers ¦ +-forms ¦ +-models ¦ +-views ¦ +-filters ¦ +-helpers ¦ +-scripts ¦ +-authentication ¦ +-cars ¦ +-index +-default +-controllers +-forms ¦ +-admin +-models ¦ +-DbTable +-plugins +-views +-helpers +-scripts +-about +-contact +-error +-index +-insurance +-used-cars I have 3 bootstrap.php files in APPLICATION_PATH, /default/ and /admin, i used AutoLoader to load models and forms $modelLoader = new Zend_Application_Module_Autoloader(array( 'namespace' => '', 'basePath' => APPLICATION_PATH . '/modules/default')); The code above will load all models and forms automatically in modules/default, and now, I have a problem to load forms and models in /modules/admin, Any solutions to solve this problem? How should I name the class name in /modules/admin Thanks.

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  • Where do you put non-controller classes in codeigniter?

    - by sprugman
    I've got a class Widgets. Widgets are made up of Doohickies. I'm never going to need to access Doohickies directly via url -- they're essentially a private class, only used by Widgets. Where do you put your code to define the Doohicky class? In /app/controllers/doohicky.php? in app/controllers/widget.php? somewhere else? Obviously, the former seems cleaner, but it's not obvious to me how to make the Doohicky class available to Widget.

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  • PrivateFontCollection fails on appharbor

    - by grennis
    I am trying to load a custom font (ttf file) and draw into an image with the Graphics object. This code runs fine locally: PrivateFontCollection fonts = new PrivateFontCollection(); string path = context.Server.MapPath("~/App_Data/Futura LT Bold.ttf"); if (!System.IO.File.Exists(path)) { throw new InvalidOperationException("Font file is not deployed: " + path); } fonts.AddFontFile(path); However when run on appharbor, the call to AddFontFile fails with the exception: System.ArgumentException: Font 'Futura LT Book' does not support style 'Regular'. at System.Drawing.Font.CreateNativeFont() at System.Drawing.Font.Initialize(FontFamily family, Single emSize, FontStyle style, GraphicsUnit unit, Byte gdiCharSet, Boolean gdiVerticalFont) at System.Drawing.Font..ctor(FontFamily family, Single emSize) at LumenboxWeb.Controllers.GalleryController.FontTest() in d:\temp\h5oqslma.udd\input\src\LumenboxWeb\Controllers\GalleryController.cs:line 59 at lambda_method(Closure , ControllerBase , Object[] ) at System.Web.Mvc.ActionMethodDispatcher.Execute(ControllerBase controller, Object[] parameters) at System.Web.Mvc.ReflectedActionDescriptor.Execute(ControllerContext controllerContext, IDictionary`2 parameters) I have tried different fonts, and they all work locally, but none work on appharbor. Is it possible to load fonts dynamically on appharbor?

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  • Cannot send e-mail with rails 2.3.4(I could with 2.3.2)

    - by Brian Roisentul
    I'm working with ruby on rails 2.3.4 and I yesterday I found out I cannot send emails any more. The email-related credentials are ok because I could send emails until I upgraded my rails version about two weeks ago. The error message I get is the following: ArgumentError in UsersController#create wrong # of arguments(3 for 2) D:/Proyectos/Cursometro/www/vendor/plugins/action_mailer_tls/lib/smtp_tls.rb:8:in `check_auth_args' D:/Proyectos/Cursometro/www/vendor/plugins/action_mailer_tls/lib/smtp_tls.rb:8:in `do_start' C:/Program Files (x86)/NetBeans 6.8/ruby2/jruby-1.4.0/lib/ruby/1.8/net/smtp.rb:525:in `start' C:/Program Files (x86)/NetBeans 6.8/ruby2/jruby-1.4.0/lib/ruby/gems/1.8/gems/actionmailer-2.3.4/lib/action_mailer/base.rb:682:in `perform_delivery_smtp' C:/Program Files (x86)/NetBeans 6.8/ruby2/jruby-1.4.0/lib/ruby/gems/1.8/gems/actionmailer-2.3.4/lib/action_mailer/base.rb:523:in `deliver!' C:/Program Files (x86)/NetBeans 6.8/ruby2/jruby-1.4.0/lib/ruby/gems/1.8/gems/actionmailer-2.3.4/lib/action_mailer/base.rb:395:in `method_missing' D:/Proyectos/Cursometro/www/app/models/user_observer.rb:3:in `after_create' D:/Proyectos/Cursometro/www/app/controllers/users_controller.rb:221:in `create_new_user' D:/Proyectos/Cursometro/www/app/controllers/users_controller.rb:101:in `create' Please, help!

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  • What is the most elegant way to access current_user from the models? or why is it a bad idea?

    - by TheLindyHop
    So, I've implemented some permissions between my users and the objects the users modify.. and I would like to lessen the coupling between the views/controllers with the models (calling said permissions). To do that, I had an idea: Implementing some of the permission functionality in the before_save / before_create / before_destroy callbacks. But since the permissions are tied to users (current_user.can_do_whatever?), I didn't know what to do. This idea may even increase coupling, as current_user is specifically controller-level. The reason why I initially wanted to do this is: All over my controllers, I'm having to check if a user has the ability to save / create / destroy. So, why not just return false upon save / create / destroy like rails' .save already does, and add an error to the model object and return false, just like rails' validations? Idk, is this good or bad? is there a better way to do this?

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  • Ruby On Rails CMS Framework

    - by stel
    Hi! I want to create a framework fo rails application. It will be a rails application but packed into gem (like a Radiant CMS). It must work like this: gem install cmsframework and then: cmsframework the_app After that we have a sceleton of rails app without any controllers etc.. - all controllers loaded from cmsframework gem. If I want to rewrite some files (for example public/styles.css) I must simply create it in my app (the_app). If I want new functions in my app I can create a plugin. But the main functionalities must be loaded from cmsframework gem. What is the best way to implement this?

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  • Conditional root_url (index)

    - by vise
    I'd like my application to display different data on the frontpage depending on whether the user has been logged in or not. def index if current_user # render another controllers action else # render another controllers action end end I can achieve this by using render_component. However it has been obsolete for some time. Although I can still use it as a plugin, I'm interested if anyone has a better approach. Just take in mind that rendering another controller's view directly is not an option. Thanks.

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  • How to pass some data to JQuery AJAX in CAKEPHP

    - by kwokwai
    Hi all, I am learning how to use JQuery to help check data availability. To start with it, I wrote a few lines of codes using cakePHP. I have written a function in a Controller for checking data input, and the URL is like this: http://www.mywebsite.com/controllers/action/avariable I was trying to pass the value in a Input TextBox field using the JQuery Ajax to the URL above,but I don't know why it is not working in passing a variable to the Controller's action. Could you help me out please? <Script language="javascript"> //<!-- $(document).ready(function(){ $(document).change(function() { var usr = $("#data\\[User\\]\\[name\\]").val(); if(usr.length >= 3){ $("#username").append('<span><img align="absmiddle" src="loader.gif" />Checking</span>'); $.ajax({ type: "POST", url: "http://www.mywebsite.com/controllers/action/", data: usr, success: function(msg){ if(msg == 'OK') { $("#username").append('<span><img align="absmiddle" src="accepted.png"/></span>'); } else { $("#username").append('<span>'+msg+'</span>'); } } }); } else { $("#username").append('<span>The username should have at least 3 characters.</span>'); } }); }); //--> </Script> <form name="adduser" id="adduser" method="post" action="/controllers/action2"> <table border=0 width="100%"> <tr> <td>Username</td> <td> <div id="username"> <input type=text name="data[User][name]" id="data[User][name]"> </div> </td> </tr> <tr> <td> <input type="submit" value="Send"> </td> </tr> </table> </form>

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  • Why do we need Web-Api? [closed]

    - by user437973
    I was just wondering what the deal is with Asp.net Web-Api. Why did we need a separate type of controller in order to facilitate varying content types for action results? Why wasn't this capability just baked into the ASP.Net MVC base controller? Anyway, I was just wondering if there was a compelling reason to use both types of controllers within the same project, assuming that the project was being freshly created, or if this project structure was due to an inherent technical limitation. Would it be possible to have ApiControllers fulfill the purpose of an MVC Controller in all cases by just serving HTML when that is the specified accept type? It just seems to me like a lot of unnecessary repetition to have to re-implement the same types of actions using both types of controllers if you want those actions to be available to your web application through the API and through the web interface.

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  • Handling Model Inheritance in ASP.NET MVC2

    - by enth
    I've gotten myself stuck on how to handle inheritance in my model when it comes to my controllers/views. Basic Model: public class Procedure : Entity { public Procedure() { } public int Id { get; set; } public DateTime ProcedureDate { get; set; } public ProcedureType Type { get; set; } } public ProcedureA : Procedure { public double VariableA { get; set; } public int VariableB { get; set; } public int Total { get; set; } } public ProcedureB : Procedure { public int Score { get; set; } } etc... many of different procedures eventually. So, I do things like list all the procedures: public class ProcedureController : Controller { public virtual ActionResult List() { IEnumerable<Procedure> procedures = _repository.GetAll(); return View(procedures); } } but now I'm kinda stuck. Basically, from the list page, I need to link to pages where the specific subclass details can be viewed/edited and I'm not sure what the best strategy is. I thought I could add an action on the ProcedureController that would conjure up the right subclass by dynamically figuring out what repository to use and loading the subclass to pass to the view. I had to store the class in the ProcedureType object. I had to create/implement a non-generic IRepository since I can't dynamically cast to a generic one. public virtual ActionResult Details(int procedureID) { Procedure procedure = _repository.GetById(procedureID, false); string className = procedure.Type.Class; Type type = Type.GetType(className, true); Type repositoryType = typeof (IRepository<>).MakeGenericType(type); var repository = (IRepository)DependencyRegistrar.Resolve(repositoryType); Entity procedure = repository.GetById(procedureID, false); return View(procedure); } I haven't even started sorting out how the view is going to determine which partial to load to display the subclass details. I'm wondering if this is a good approach? This makes determining the URL easy. It makes reusing the Procedure display code easy. Another approach is specific controllers for each subclass. It simplifies the controller code, but also means many simple controllers for the many procedure subclasses. Can work out the shared Procedure details with a partial view. How to get to construct the URL to get to the controller/action in the first place? Time to not think about it. Hopefully someone can show me the light. Thanks in advance.

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  • How to add Exception to route with :any in CodeIgniter?

    - by aslamdoctor
    In my project, have setup an admin panel under a folder inside controllers folder like this controllers/admin_panel/dashboard.php And when we open it like this, it loads dashboard controller default http://www.mysite.com/admin_panel Now I have added a page controller on root level to load the page content from database. So here I have some a setup of kind of CMS. To load the page controller, I have added a condition in routes as below $route[':any'] = "page"; But what it is doing now is, when I try to open admin_panel, it loads the page controller. So I want to add a kind of exception condition here like route any except admin_panel Any suggestions how can I achieve this ? Thanks in advance.

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  • UISplitViewController Common View

    - by saikamesh
    is it possible to have a common view for both master and detail view controllers. What if I need to add a header image(at top, the very first view) common for both the master and detail view controllers. When the device is in the portrait mode the width of the header image view has to shrink to fit to the detail view controller's view and when the orientation changes to landscape the width of the same header image view has to be expanded that is the width of it has to be 1024. Please tell me whether doing this is possible. or any workaround for this?

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  • Notice Undefined index url

    - by user1906992
    I'm doing youtube mvc tutorial http://www.youtube.com/watch?v=Aw28-krO7ZM and have stopped on the best first step: my index.php file: <?php $url = $_GET['url']; require 'controllers/' . $url . '.php'; My .htaccess file: RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-l RewriteRule ^(.+)$ index.php?url=$1 [QSA,L] so, the question is next: when i go on any other url except 'index' it works good. So what's wrong with 'index' url? Notice: Undefined index: url in /var/www/sadman/index.php on line 2 Warning: require(controllers/.php) [function.require]: failed to open stream: No such file or directory in /var/www/sadman/index.php on line 4 Btw, i have LAMP, and i think my settings are wright.

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  • Play 2.0 framework - POST parameters

    - by user1452715
    I'm trying to POST parameters to Action, and wrote in the routes: Home page GET / controllers.Application.index() POST /login/name:/password: controllers.Application.login(name, password) and I have an Action public static Result login(String name, String password) { return ok(name + " " + password); } my form is <form action="/login" method="post"> <input name="name" type="text" id="name"> <input name="password" type="password" id="password"> <input type="submit" value="Login"> </form> and it doesn't work For request 'POST /login' [Missing parameter: name] what am i doing wrong?

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  • php calling classes functions in separate pages

    - by sys_debug
    I've worked with J2EE recently and like the idea of struts.xml where I can handle the redirection to pages based on return string from action classes. In PHP, in my new under-development site, I am trying to follow the MVC standards without an MVC framework used from the internet. So I create the controllers, models and views (empty now). The only thing I am really stuck at is when I submit the form in view (insert_product.php) then I will need to create another php page to handle the post data and pass them to controllers. Anyway of avoiding creating those pages and maybe having something like struts.xml? Even if I can post data directly to controller class, that would be good. Thanks,

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  • Maintaining shared service in ASP.NET MVC Application

    - by kazimanzurrashid
    Depending on the application sometimes we have to maintain some shared service throughout our application. Let’s say you are developing a multi-blog supported blog engine where both the controller and view must know the currently visiting blog, it’s setting , user information and url generation service. In this post, I will show you how you can handle this kind of case in most convenient way. First, let see the most basic way, we can create our PostController in the following way: public class PostController : Controller { public PostController(dependencies...) { } public ActionResult Index(string blogName, int? page) { BlogInfo blog = blogSerivce.FindByName(blogName); if (blog == null) { return new NotFoundResult(); } IEnumerable<PostInfo> posts = postService.FindPublished(blog.Id, PagingCalculator.StartIndex(page, blog.PostPerPage), blog.PostPerPage); int count = postService.GetPublishedCount(blog.Id); UserInfo user = null; if (HttpContext.User.Identity.IsAuthenticated) { user = userService.FindByName(HttpContext.User.Identity.Name); } return View(new IndexViewModel(urlResolver, user, blog, posts, count, page)); } public ActionResult Archive(string blogName, int? page, ArchiveDate archiveDate) { BlogInfo blog = blogSerivce.FindByName(blogName); if (blog == null) { return new NotFoundResult(); } IEnumerable<PostInfo> posts = postService.FindArchived(blog.Id, archiveDate, PagingCalculator.StartIndex(page, blog.PostPerPage), blog.PostPerPage); int count = postService.GetArchivedCount(blog.Id, archiveDate); UserInfo user = null; if (HttpContext.User.Identity.IsAuthenticated) { user = userService.FindByName(HttpContext.User.Identity.Name); } return View(new ArchiveViewModel(urlResolver, user, blog, posts, count, page, achiveDate)); } public ActionResult Tag(string blogName, string tagSlug, int? page) { BlogInfo blog = blogSerivce.FindByName(blogName); if (blog == null) { return new NotFoundResult(); } TagInfo tag = tagService.FindBySlug(blog.Id, tagSlug); if (tag == null) { return new NotFoundResult(); } IEnumerable<PostInfo> posts = postService.FindPublishedByTag(blog.Id, tag.Id, PagingCalculator.StartIndex(page, blog.PostPerPage), blog.PostPerPage); int count = postService.GetPublishedCountByTag(tag.Id); UserInfo user = null; if (HttpContext.User.Identity.IsAuthenticated) { user = userService.FindByName(HttpContext.User.Identity.Name); } return View(new TagViewModel(urlResolver, user, blog, posts, count, page, tag)); } } As you can see the above code heavily depends upon the current blog and the blog retrieval code is duplicated in all of the action methods, once the blog is retrieved the same blog is passed in the view model. Other than the blog the view also needs the current user and url resolver to render it properly. One way to remove the duplicate blog retrieval code is to create a custom model binder which converts the blog from a blog name and use the blog a parameter in the action methods instead of the string blog name, but it only helps the first half in the above scenario, the action methods still have to pass the blog, user and url resolver etc in the view model. Now lets try to improve the the above code, first lets create a new class which would contain the shared services, lets name it as BlogContext: public class BlogContext { public BlogInfo Blog { get; set; } public UserInfo User { get; set; } public IUrlResolver UrlResolver { get; set; } } Next, we will create an interface, IContextAwareService: public interface IContextAwareService { BlogContext Context { get; set; } } The idea is, whoever needs these shared services needs to implement this interface, in our case both the controller and the view model, now we will create an action filter which will be responsible for populating the context: public class PopulateBlogContextAttribute : FilterAttribute, IActionFilter { private static string blogNameRouteParameter = "blogName"; private readonly IBlogService blogService; private readonly IUserService userService; private readonly BlogContext context; public PopulateBlogContextAttribute(IBlogService blogService, IUserService userService, IUrlResolver urlResolver) { Invariant.IsNotNull(blogService, "blogService"); Invariant.IsNotNull(userService, "userService"); Invariant.IsNotNull(urlResolver, "urlResolver"); this.blogService = blogService; this.userService = userService; context = new BlogContext { UrlResolver = urlResolver }; } public static string BlogNameRouteParameter { [DebuggerStepThrough] get { return blogNameRouteParameter; } [DebuggerStepThrough] set { blogNameRouteParameter = value; } } public void OnActionExecuting(ActionExecutingContext filterContext) { string blogName = (string) filterContext.Controller.ValueProvider.GetValue(BlogNameRouteParameter).ConvertTo(typeof(string), Culture.Current); if (!string.IsNullOrWhiteSpace(blogName)) { context.Blog = blogService.FindByName(blogName); } if (context.Blog == null) { filterContext.Result = new NotFoundResult(); return; } if (filterContext.HttpContext.User.Identity.IsAuthenticated) { context.User = userService.FindByName(filterContext.HttpContext.User.Identity.Name); } IContextAwareService controller = filterContext.Controller as IContextAwareService; if (controller != null) { controller.Context = context; } } public void OnActionExecuted(ActionExecutedContext filterContext) { Invariant.IsNotNull(filterContext, "filterContext"); if ((filterContext.Exception == null) || filterContext.ExceptionHandled) { IContextAwareService model = filterContext.Controller.ViewData.Model as IContextAwareService; if (model != null) { model.Context = context; } } } } As you can see we are populating the context in the OnActionExecuting, which executes just before the controllers action methods executes, so by the time our action methods executes the context is already populated, next we are are assigning the same context in the view model in OnActionExecuted method which executes just after we set the  model and return the view in our action methods. Now, lets change the view models so that it implements this interface: public class IndexViewModel : IContextAwareService { // More Codes } public class ArchiveViewModel : IContextAwareService { // More Codes } public class TagViewModel : IContextAwareService { // More Codes } and the controller: public class PostController : Controller, IContextAwareService { public PostController(dependencies...) { } public BlogContext Context { get; set; } public ActionResult Index(int? page) { IEnumerable<PostInfo> posts = postService.FindPublished(Context.Blog.Id, PagingCalculator.StartIndex(page, Context.Blog.PostPerPage), Context.Blog.PostPerPage); int count = postService.GetPublishedCount(Context.Blog.Id); return View(new IndexViewModel(posts, count, page)); } public ActionResult Archive(int? page, ArchiveDate archiveDate) { IEnumerable<PostInfo> posts = postService.FindArchived(Context.Blog.Id, archiveDate, PagingCalculator.StartIndex(page, Context.Blog.PostPerPage), Context.Blog.PostPerPage); int count = postService.GetArchivedCount(Context.Blog.Id, archiveDate); return View(new ArchiveViewModel(posts, count, page, achiveDate)); } public ActionResult Tag(string blogName, string tagSlug, int? page) { TagInfo tag = tagService.FindBySlug(Context.Blog.Id, tagSlug); if (tag == null) { return new NotFoundResult(); } IEnumerable<PostInfo> posts = postService.FindPublishedByTag(Context.Blog.Id, tag.Id, PagingCalculator.StartIndex(page, Context.Blog.PostPerPage), Context.Blog.PostPerPage); int count = postService.GetPublishedCountByTag(tag.Id); return View(new TagViewModel(posts, count, page, tag)); } } Now, the last thing where we have to glue everything, I will be using the AspNetMvcExtensibility to register the action filter (as there is no better way to inject the dependencies in action filters). public class RegisterFilters : RegisterFiltersBase { private static readonly Type controllerType = typeof(Controller); private static readonly Type contextAwareType = typeof(IContextAwareService); protected override void Register(IFilterRegistry registry) { TypeCatalog controllers = new TypeCatalogBuilder() .Add(GetType().Assembly) .Include(type => controllerType.IsAssignableFrom(type) && contextAwareType.IsAssignableFrom(type)); registry.Register<PopulateBlogContextAttribute>(controllers); } } Thoughts and Comments?

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  • Daily tech links for .net and related technologies - Mar 18-21, 2010

    - by SanjeevAgarwal
    Daily tech links for .net and related technologies - Mar 18-21, 2010 Web Development TDD kata for ASP.NET MVC controllers (part 2) -David Take Control Of Web Control ClientID Values in ASP.NET 4.0 - Scott Mitchell Inside the ASP.NET MVC Controller Factory - Dino Esposito Microsoft, jQuery, and Templating - stephen walther Cross Domain AJAX Request with YQL and jQuery - Jeffrey Way T4MVC Add-In to auto run template -Wayne Web Design Website Content Planning The Right Way - Kristin Wemmer Microsoft...(read more)

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  • Are there any libraries similar to Three20? [closed]

    - by GoldFire
    Are there any libraries similar to Three20? Three20 does not work for me on iOS 5; it gives me warnings. Three20 provides powerful view controllers such as the Launcher, the popular Photo Browser, and internet-aware tables. The library is modular, meaning you choose which elements of the library to include in your app. This modular design allows Three20 to be one of the only Objective-C frameworks that encourages what are called 'extensions' from the community.

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  • Storage Configuration

    - by jchang
    Storage performance is not inherently complicated subject. The concepts are relatively simple. In fact, scaling storage performance is far easier compared with the difficulties encounters in scaling processor performance in NUMA systems. Storage performance is achieved by properly distributing IO over: 1) multiple independent PCI-E ports (system memory and IO bandwith is key) 2) multiple RAID controllers or host bus adapters (HBAs) 3) multiple storage IO channels (SAS or FC, complete path) most importantly,...(read more)

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  • Storage Configuration

    - by jchang
    Storage performance is not inherently complicated subject. The concepts are relatively simple. In fact, scaling storage performance is far easier compared with the difficulties encounters in scaling processor performance in NUMA systems. Storage performance is achieved by properly distributing IO over: 1) multiple independent PCI-E ports (system memory and IO bandwith is key) 2) multiple RAID controllers or host bus adapters (HBAs) 3) multiple storage IO channels (SAS or FC, complete path) most importantly,...(read more)

    Read the article

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