Search Results

Search found 683 results on 28 pages for 'feb'.

Page 22/28 | < Previous Page | 18 19 20 21 22 23 24 25 26 27 28  | Next Page >

• Question about MySQLdb, OS X 10.5, and authentication

  - by timpone

  I'm a noob at Python and have been having problems with MySQLdb and OS X Leopard 10.5. I have a php app that is doing db access just fine with pdo but also want to access with Python. When I use the same credentials with MySQLdb as php, I get the following error: File "build/bdist.macosx-10.5-i386/egg/MySQLdb/connections.py", line 188, in __init__ _mysql_exceptions.OperationalError: (1045, "Access denied for user 'arc_db'@'localhost' (using password: YES)") The authentication piece works fine on my ubuntu server (installed via apt-get) implying that it is something specific to my OS X MySQLdb install. Looking at some postings, I thought it would be my local build of MySQLdb which seems to be problematic with OS X. But I am able to import fine: Python 2.5.1 (r251:54863, Feb 6 2009, 19:02:12) [GCC 4.0.1 (Apple Inc. build 5465)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> import MySQLdb >>> Also, wanting to create a positive, I am able to access and return results from a database tilted test_something (which presumably bypasses the MySQL's authtentication - not sure exactly how though). Trying to figure out a little more what is going on, I turn on logging for mysql and get the following (added my own comments): 100609 19:09:45 3 Connect Access denied for user 'arc_db'@'localhost' (using password: YES) //not worked 100609 19:10:02 4 Connect arc_db@localhost on arc_development //did work I'm not really sure what the 3 or 4 means but presumably a sucess or failue. So, I guess what would be the next step? Am I doing some obvious stupid python mistake (very likely)? Is there a better way for me to prove that this should / can be working? Is there any way to determine what MySQLdb is sending exactly in its authentication message to MySQL? thanks

  Read the article

• What Happens to Commit Logs on a Branch After Merging?

  - by Levi Hackwith

  Scenario: Programmer creates a branch for project 'foo' called 'my_foo' at revision 5 Programmer makes multiple changes to multiple files as he works on the 'my_foo' feature. At the end of each major step, say adding several new functions to class, the programmer does an svn commit on the appropriate files therefore committing them to the branch After several weeks and many commits later (each commit having a commit log describing what he did), the programmer merges the branch back into the trunk: #Assume the following is being done from inside a working copy of the trunk: svn merge -r 5:15 file:///path/to/repo/branches/my_foo Hazzah! he's merged all his changes back into trunk! There's much rejoicing and drinking of Mountain Dew. Now let's say another programmer comes along a week later and updates their working copy from revision 5 to revision 15. "Wow", they say. "I wonder what's changed since revision 5". The programmer then does an svn status on their working copy and they get something like this: ------------------------------------------------------------------------ r15 | programmer1 | 2010-03-20 21:27:04 -0400 (Sat, 20 Mar 2010) | 1 line Merging Version 2.0 Changes into trunk ------------------------------------------------------------------------ r5 | programmer2 | 2010-02-15 10:59:55 -0500 (Mon, 15 Feb 2010) | 1 line Added assets/images/tumblr_icon.png to trunk What the heck happened to all the notes that the other programmer put in with all of his commits in his branch? Do those not get pulled over during a merge? Am I crazy or just forgetting something?

  Read the article

• sorl-thumbnail unit tests fail by 1 pixel (!)

  - by stevejalim

  Hi I'm using sorl-thumbnail in a Django 1.2 (currently 1.2 RC) project and getting a surprising failure of four of sorl's built-in unit tests. Essentially, the resized images are all 1px shorter than the unit tests expect them to be. See below for details I'm developing on OSX 10.5.8 (not Snow Leopard) with Python 2.5.1 (r251:54863, Feb 6 2009, 19:02:12) and PIL 1.1.6. Any thoughts what might be up? Cheers Steve ====================================================================== FAIL: test_extension (sorl.thumbnail.tests.fields.FieldTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/local/django/myprojectnamehere/lib/sorl/thumbnail/tests/fields.py", line 66, in test_extension self.verify_thumbnail((50, 37), thumb, expected_filename) File "/usr/local/django/myprojectnamehere/lib/sorl/thumbnail/tests/base.py", line 92, in verify_thumbnail self.assertEqual(image.size, expected_size) AssertionError: (50, 38) != (50, 37) ====================================================================== FAIL: test_thumbnail (sorl.thumbnail.tests.fields.ImageWithThumbnailsFieldTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/local/django/myprojectnamehere/lib/sorl/thumbnail/tests/fields.py", line 111, in test_thumbnail self.verify_thumbnail((50, 37), thumb, expected_filename) File "/usr/local/django/myprojectnamehere/lib/sorl/thumbnail/tests/base.py", line 92, in verify_thumbnail self.assertEqual(image.size, expected_size) AssertionError: (50, 38) != (50, 37) ====================================================================== FAIL: testTag (sorl.thumbnail.tests.templatetags.ThumbnailTagTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/local/django/myprojectnamehere/lib/sorl/thumbnail/tests/templatetags.py", line 118, in testTag self.verify_thumbnail((90, 67), expected_filename=expected_fn) File "/usr/local/django/myprojectnamehere/lib/sorl/thumbnail/tests/base.py", line 92, in verify_thumbnail self.assertEqual(image.size, expected_size) AssertionError: (90, 68) != (90, 67)

  Read the article

• virtualenv macosX --no-site-package ignored

  - by Tristram Gräbener

  Hello, I'm having problems with macOSX and virtualenv. It seems to ignore --no-site-package. Using exactly the same commands with linux (archlinux) it works. It it macOSX 10.5 with python 2.5 curl -o virtualenv.py 'http://bitbucket.org/ianb/virtualenv/raw/tip/virtualenv.py Create a new environment python virtualenv.py --no-site-packages foo New python executable in foo/bin/python Installing setuptools...........................done. Activate it source foo/bin/activate Try to install something in it. Despite virtualenv it looks for the system-wide install easy_install cherrypy Searching for cherrypy Best match: CherryPy 3.1.2 Adding CherryPy 3.1.2 to easy-install.pth file Using /Library/Python/2.5/site-packages Processing dependencies for cherrypy Finished processing dependencies for cherrypy Yet it doesn't find the module (foo)guidage-multimodal:~ tristram$ python Python 2.5.1 (r251:54863, Feb 6 2009, 19:02:12) [GCC 4.0.1 (Apple Inc. build 5465)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> import cherrypy Traceback (most recent call last): File "<stdin>", line 1, in <module> ImportError: No module named cherrypy I tried PIP after looking at http://stackoverflow.com/questions/1382925/virtualenv-no-site-packages-and-pip-still-finding-global-packages However it fails installing psycopg2 (some problems with gcc). Also I would like to be able to have a setup.py (from distribute) that does the whole woork

  Read the article

• MySQL - How do I inner join sorting the joined data

  - by Gary

  I'm trying to write a report which will join a person, their work, and their hourly wage at the time of work. I cannot seem to figure out the best way to join the person's cost when the date is less than the date of the work. Let's say a person cost $30 per hour at the start of the year then got a $10 raise o Feb 5 and another on Mar 1. 01/01/2010 $30.00 (per hour) 02/05/2010 $40.00 03/01/2010 $45.00 The person put in hours several days which span the rasies. 01/05/2010 10 hours (should be at $30/hr) 01/27/2010 5 hours (again at $30) 02/10/2010 10 hours (at $40/hr) 03/03/2010 5 hours (at $45/hr) I'm trying to write one SQL statement which will pull the hours, the cost per hour, and the hours*cost. The cost is the hourly rate last entered into the system so the cost date is less than the work date, ordered by cost date limit 1. SELECT person.id, person.name, work.hours, person_costs.value, work.hours * person_costs.value AS value FROM person INNER JOIN work ON (person.id = work.person_id) INNER JOIN person_costs ON (person.id = person_costs.person_id AND person_costs.date < work.date) WHERE person.id = 1234 ORDER BY work.date ASC The problem I'm having, the person_costs isn't ordered by date in descending order. It's pulling out "any" value (naturally sorted by record position) which matches the condition. How do I select the first person_cost value which is older than the work date? Thanks!

  Read the article

• python calendar to calculate month backwards

  - by Suhail

  Hi, we are trying to create a calendar function in python. we have created a small content management system, the requirement is, there will be a drop down list on the top right hand corner of the website, which will give the options - Months - 1 month, 2 months, 3 months and so on..., if the user selects 8 months then it should show the postscount for the last 8 months. the issue is we tried to write a small code which would do the month calculations, but the bug is that it does not consider the months beyond the current year, it shows the postscount only for months of the current year. for example: if the user selects 3 months, it will show the count for the l 3 months i.e present month and the previous 2 months, but if the user selects option more than 4 months, it does not consider the months from previous year, it still shows the month of the present year only. I am pasting the code below:- def __getSpecifiedMailCount__(request, value): dbconnector= DBConnector() CdateList= "select cdate from mail_records" DateNow= datetime.datetime.today() DateNow= DateNow.strftime("%Y-%m") DateYear= datetime.datetime.today() DateYear= DateYear.strftime("%Y") DateMonth= datetime.datetime.today() DateMonth= DateMonth.strftime("%m") #print DateMonth def getMonth(value): valueDic= {"01": "Jan", "02": "Feb", "03": "Mar", "04": "Apr", "05": "May", "06": "Jun", "07": "Jul", "08": "Aug", "09": "Sep", "10": "Oct", "11": "Nov", "12": "Dec"} return valueDic[value] def getMonthYearandCount(yearmonth): MailCount= "select count(*) as mailcount from mail_records where cdate like '%s%s'" % (yearmonth, "%") MailCountResult= MailCount[0]['mailcount'] return MailCountResult MailCountList= [] MCOUNT= getMonthYearandCount(DateNow) MONTH= getMonth(DateMonth) MailCountDict= {} MailCountDict['monthyear']= MONTH + ' ' + DateYear MailCountDict['mailcount']= MCOUNT var_monthyear= MONTH + ' ' + DateYear var_mailcount= MCOUNT MailCountList.append(MailCountDict) i=1 k= int(value) hereMONTH= int(DateMonth) while (i < k): hereMONTH= int(hereMONTH) - 1 if (hereMONTH < 10): hereMONTH = '0' + str(hereMONTH) if (hereMONTH == '00') or (hereMONTH == '0-1'): break else: PMONTH= getMonth(hereMONTH) hereDateNow= DateYear + '-' + PMONTH hereDateNowNum= DateYear + '-' + hereMONTH PMCOUNT= getMonthYearandCount(hereDateNowNum) MailCountDict= {} MailCountDict['monthyear']= PMONTH + ' ' + DateYear MailCountDict['mailcount']= PMCOUNT var_monthyear= PMONTH + ' ' + DateYear var_mailcount= PMCOUNT MailCountList.append(MailCountDict) i = i + 1 #print MailCountList MailCountDict= {'monthmailcount': MailCountList} reportdata = MailCountDict['monthmailcount'] #print reportdata return render_to_response('test.html', locals())

  Read the article

• How do I get multimonth plugin of the jQuery datePicker to load with certain dates already selected?

  - by imHavoc

  well im using this script right here: http://www.kelvinluck.com/assets/jquery/datePicker/v2/demo/ and I have a multiMonth plugin and multiple select enabled. I want to be able to on load have certain dates already selected and those dates come from a database I found two possible clues to help me out, but since I have not strictly learned JS yet, I can not made heads or tails. http://www.kelvinluck.com/assets/jquery/datePicker/v2/demo/renderCalendarBankHolidays.html http://www.kelvinluck.com/assets/jquery/datePicker/v2/demo/datePickerDefaultToday.html here's the code right now im using: <script type="text/javascript" charset="utf-8"> jQuery(function() { jQuery('#multimonth').datePickerMultiMonth({ numMonths: 12, inline: true, selectMultiple: true, startDate: '01/09/2009', // DD/MM/YY month: 8, // 0=JAN 1=FEB ... year: 2009 }).bind( 'dpMonthChanged', function(event, displayedMonth, displayedYear) { //uncomment if you have firebug and want to confirm this works as expected... //console.log('dpMonthChanged', arguments); }).bind( 'dateSelected', function(event, date, jQuerytd, status) { //uncomment if you have firebug and want to confirm this works as expected... //console.log('dateSelected', arguments); }).val( new Date().asString()).trigger('change'); jQuery('#getSelected').bind( 'click', function(e) { alert(jQuery('#multimonth').dpmmGetSelected()); return false; }); }); </script> and this part is not being selected, I took it from the select todays date demo .val(new Date().asString()).trigger('change');

  Read the article

• How to append text in php

  - by user225269

  I have this form for inputting the birthday in html. But I only have a single column for storing it in wampserver(Column Birthday). <select title="- Select Month -" name="mm" id="mm" class="" > <option value="" SELECTED >Month</option> <option value="1" >Jan</option> <option value="2" >Feb</option> <option value="3" >Mar</option> <option value="4" >Apr</option> <option value="5" >May</option> <option value="6" >Jun</option> <option value="7" >Jul</option> <option value="8" >Aug</option> <option value="9" >Sep</option> <option value="10" >Oct</option> <option value="11" >Nov</option> <option value="12" >Dec</option> </select> <input title="Day" type="text" onkeypress="return isNumberKey(event)" name="dd" value="" size="1" maxlength="2" id='numbers'/ > <input title="Year" type="text" onkeypress="return isNumberKey(event)" name="yyyy" value="" size="1" maxlength="4" id='numbers'/> </td> Do you have any idea on how I can place those 3 values in the same column?Please help

  Read the article

• PHP strtotime() looks like it is expecting a Euro format

  - by Jason Rhodes

  I've been using PHP's strtotime() method to accept a date field on a form. I love how powerful it is, in how it will accept "Tomorrow", "Next Thursday", or (supposedly) any date representation and convert it to the Unix timestamp. It's been working great -- until yesterday. Someone entered "2-4-10" and instead of logging Feb 4th, 2010, it logged April 10, 2002! So it expected Y-M-D instead of M-D-Y. I thought maybe the problem was just using a 2-digit year, so we tried again with "2-4-2010". That logged April 2nd, 2010! At that point I just don't understand what strtotime() is doing. PHP.net says it expects a US English date format. Why then would it assume D-M-Y? Is there a way around this? Or do I have to stop using strtotime()? Note: I just now did a test. When you use slashes instead of hyphen/dashes, it works fine, even with 2/4/10. Why on earth does that matter? And if that's all it is, should I just run str_replace("-", "/", $input) on the form input before passing it to strtotime()?

  Read the article

• [Python] name 'OptionGroup' is not defined

  - by Cawas

  Ok, so I made this rookie mistake below, but in my defense I was led to it thanks to how the help about this subject is on python docs, which states how to use optparse. It is actually an error under the gigantic tutorial section. In contrast and to my offense, I may be one of the very few stupid people who can't read very well and pay close attention on what I do. But since this took me so long to discover, I wanted to "document" it here: Python 2.6.1 (r261:67515, Feb 11 2010, 00:51:29) >>> from optparse import OptionParser >>> outputGroup = OptionGroup(parser, 'Output handling') Traceback (most recent call last): File "<stdin>", line 1, in <module> NameError: name 'OptionGroup' is not defined This is strictly done with examples found on the docs, and you can't find anything about it anywhere, be it that long long docs page, google or stackoverflow. Plus, reading optparse.py shows OptionGroup is there, so that adds to the confusion. I bet it will take less than 1 minute for someone to spot my error. For that I'll only add proper tags and / or modify the title later on. :)

  Read the article

• Poor execution plans when using a filter and CONTAINSTABLE in a query

  - by Paul McLoughlin

  We have an interesting problem that I was hoping someone could help to shed some light on. At a high level the problem is as below: The following query executes quickly (1 second): SELECT SA.* FROM cg.SEARCHSERVER_ACTYS AS SA JOIN CONTAINSTABLE(CG.SEARCHSERVER_ACTYS, NOTE, 'reports') AS T1 ON T1.[Key]=SA.UNIQUE_ID but if we add a filter to the query, then it takes approximately 2 minutes to return: SELECT SA.* FROM cg.SEARCHSERVER_ACTYS AS SA JOIN CONTAINSTABLE(CG.SEARCHSERVER_ACTYS, NOTE, 'reports') AS T1 ON T1.[Key]=SA.UNIQUE_ID WHERE SA.CHG_DATE'19 Feb 2010' Looking at the execution plan for the two queries, I can see that in the second case there are two places where there are huge differences between the actual and estimated number of rows, these being: 1) For the FulltextMatch table valued function where the estimate is approx 22,000 rows and the actual is 29 million rows (which are then filtered down to 1670 rows before the join) and 2) For the index seek on the full text index, where the estimate is 1 row and the actual is 13,000 rows As a result of the estimates, the optimiser is choosing to use a nested loops join (since it assumes a small number of rows) hence the plan is inefficient. We can work around the problem by either (a) parameterising the query and adding an OPTION (OPTIMIZE FOR UNKNOWN) to the query or (b) by forcing a HASH JOIN to be used. In both of these cases the query returns in sub 1 second and the estimates appear reasonable. My question really is 'why are the estimates being used in the poorly performing case so wildly inaccurate and what can be done to improve them'? Statistics are up to date on the indexes on the indexed view being used here. Any help greatly appreciated.

  Read the article

• Schema design: many to many plus additional one to many

  - by chrisj

  Hi, I have this scenario and I'm not sure exactly how it should be modeled in the database. The objects I'm trying to model are: teams, players, the team-player membership, and a list of fees due for each player on a given team. So, the fees depend on both the team and the player. So, my current approach is the following: **teams** id name **players** id name **team_players** id player_id team_id **team_player_fees** id team_players_id amount send_reminder_on Schema layout ERD In this schema, team_players is the junction table for teams and players. And the table team_player_fees has records that belong to records to the junction table. For example, playerA is on teamA and has the fees of $10 and $20 due in Aug and Feb. PlayerA is also on teamB and has the fees of $25 and $25 due in May and June. Each player/team combination can have a different set of fees. Questions: Are there better ways to handle such a scenario? Is there a term for this type of relationship? (so I can google it) Or know of any references with similar structures?

  Read the article

• Web application date time localization best practice at 201x

  - by Hieu Lam

  Hi all, I have worked for various web projects but correct date time localization have not been done and considered throroughly so I want to ask this very typical problem here and I want to hear comments from expert in this problem What is the correct strategy for storing a date/time value from client from server As I understand, because of locale and timezone so we have to do the conversion, I have heard about GMT or UTC time and after do some search it seems that UTC is more accurate ? so we will convert from client time - UTC+0 when saving and when we read the value from server to client, we convert from server time back to client time again ? However, I see in some website, at the bottom have the sentence "All times are in UTC", "All times are in GMT" and also "All times are in your local time". So maybe not all the sites do the convertion back and forth ? And in that case the user has to manually do the date/time conversion ? How to display the date/time convenient to user based on his locale and region How to provide personalization on date/time value ? I had one time depends on vbscript to do the display and the format is read from windows regional and format settings automatically. But without vbscript how can we determine a date/time pattern for a user of a specific locale. Do we have to store a mapping between a locale and pattern somewhere and do the conversion at the server side ? Although date/time conversion is needed in most case, there's situation where only date matter for example if my birthday is 2 Feb 1980, it should be the same for all locale and no conversion should be done. How can we address this issue.

  Read the article

• Save PyML.classifiers.multi.OneAgainstRest(SVM()) object?

  - by Michael Aaron Safyan

  I'm using PYML to construct a multiclass linear support vector machine (SVM). After training the SVM, I would like to be able to save the classifier, so that on subsequent runs I can use the classifier right away without retraining. Unfortunately, the .save() function is not implemented for that classifier, and attempting to pickle it (both with standard pickle and cPickle) yield the following error message: pickle.PicklingError: Can't pickle : it's not found as __builtin__.PySwigObject Does anyone know of a way around this or of an alternative library without this problem? Thanks. Edit/Update I am now training and attempting to save the classifier with the following code: mc = multi.OneAgainstRest(SVM()); mc.train(dataset_pyml,saveSpace=False); for i, classifier in enumerate(mc.classifiers): filename=os.path.join(prefix,labels[i]+".svm"); classifier.save(filename); Notice that I am now saving with the PyML save mechanism rather than with pickling, and that I have passed "saveSpace=False" to the training function. However, I am still gettting an error: ValueError: in order to save a dataset you need to train as: s.train(data, saveSpace = False) However, I am passing saveSpace=False... so, how do I save the classifier(s)? P.S. The project I am using this in is pyimgattr, in case you would like a complete testable example... the program is run with "./pyimgattr.py train"... that will get you this error. Also, a note on version information: [michaelsafyan@codemage /Volumes/Storage/classes/cse559/pyimgattr]$ python Python 2.6.1 (r261:67515, Feb 11 2010, 00:51:29) [GCC 4.2.1 (Apple Inc. build 5646)] on darwin Type "help", "copyright", "credits" or "license" for more information. import PyML print PyML.__version__ 0.7.0

  Read the article

• calculating offer period for subscription

  - by TheVillageIdiot

  I'm maintaining a web application which deals with some kind of subscriptions. Users can to renew their subscriptions from 2 months before expiry (not earlier than that). Sometimes user does not renew before expiry and get grace period which is of 3 months. Now he can renew in these 3 months of grace period. Now the problem part. In the previous transactions of renew requests I have to show what was the offer period for that particular request (subscription start and subscription end period if renew was granted). Things are pretty simple if user renews before expiry, but I'm not able to get things straight if there is grace period specially when the subscriptions is expiring in last months of the year. Also there sometimes calculations go haywire when subscription is ending in jan or feb. All this is happening because offer period is not saved with the application anywhere (I don't know why). so if subscription is ending in 20 October 2008 and renew application is submitted in 16 January 2009 (because of grace period) the offer period should be 21 October 2008 to 20 October 2009.

  Read the article

• How to sort a date array in PHP

  - by Click Upvote

  I have an array in this format: Array ( [0] => Array ( [28th February, 2009] => 'bla' ) [1] => Array ( [19th March, 2009] => 'bla' ) [2] => Array ( [5th April, 2009] => 'bla' ) [3] => Array ( [19th April, 2009] => 'bla' ) [4] => Array ( [2nd May, 2009] => 'bla' ) ) I want to sort them out in the ascending order of the dates (based on the month, day, and year). What's the best way to do that? Originally the emails are being fetched in the MySQL date format, so its possible for me to get the array in this state: Array [ ['2008-02-28']='some text', ['2008-03-06']='some text' ] Perhaps when its in this format, I can loop through them, remove all the '-' (hyphen) marks so they are left as integars, sort them using array_sort() and loop through them yet again to sort them? Would prefer if there was another way as I'd be doing 3 loops with this per user. Thanks. Edit: I could also do this: $array[$index]=array('human'=>'28 Feb, 2009', 'db'=>'20080228', 'description'=>'Some text here'); But using this, would there be any way to sort the array based on the 'db' element alone? Edit 2: Updated initial var_dump

  Read the article

• "ImportError: cannot import name Exchange" when using Celery w/ Kombu installed

  - by alukach

  I'm trying to create a Celery worker node on an Amazon EC2 Windows2008 R2 instance. Due to a plugin we require for another Python module, we are required to user Python3. I've installed Python3.2 and necessary modules and run Celery, but for some reason it states that it can't import Exchange and Queue from Kombu, despite the face that Kombu is installed and can be imported by python. Microsoft Windows [Version 6.1.7601] Copyright (c) 2009 Microsoft Corporation. All rights reserved. C:\Users\Administrator>celery Traceback (most recent call last): File "C:\Python32\Scripts\celery-script.py", line 9, in <module> load_entry_point('celery==3.0.11', 'console_scripts', 'celery')() File "C:\Python32\lib\site-packages\celery\__main__.py", line 13, in main from celery.bin.celery import main File "C:\Python32\lib\site-packages\celery\bin\celery.py", line 21, in <module> from celery.utils import term File "C:\Python32\lib\site-packages\celery\utils\__init__.py", line 22, in <module> from kombu import Exchange, Queue ImportError: cannot import name Exchange C:\Users\Administrator>python Python 3.2 (r32:88445, Feb 20 2011, 21:29:02) [MSC v.1500 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> from kombu import Exchange, Queue >>> print('WTF?!?') WTF?!? >>> This problem seems similar to this and this, but I have not been able to remedy the issue. Any ideas?

  Read the article

• How do I improve my performance with this singly linked list struct within my program?

  - by Jesus

  Hey guys, I have a program that does operations of sets of strings. We have to implement functions such as addition and subtraction of two sets of strings. We are suppose to get it down to the point where performance if of O(N+M), where N,M are sets of strings. Right now, I believe my performance is at O(N*M), since I for each element of N, I go through every element of M. I'm particularly focused on getting the subtraction to the proper performance, as if I can get that down to proper performance, I believe I can carry that knowledge over to the rest of things I have to implement. The '-' operator is suppose to work like this, for example. Declare set1 to be an empty set. Declare set2 to be a set with { a b c } elements Declare set3 to be a set with ( b c d } elements set1 = set2 - set3 And now set1 is suppose to equal { a }. So basically, just remove any element from set3, that is also in set2. For the addition implementation (overloaded '+' operator), I also do the sorting of the strings (since we have to). All the functions work right now btw. So I was wondering if anyone could a) Confirm that currently I'm doing O(N*M) performance b) Give me some ideas/implementations on how to improve the performance to O(N+M) Note: I cannot add any member variables or functions to the class strSet or to the node structure. The implementation of the main program isn't very important, but I will post the code for my class definition and the implementation of the member functions: strSet2.h (Implementation of my class and struct) // Class to implement sets of strings // Implements operators for union, intersection, subtraction, // etc. for sets of strings // V1.1 15 Feb 2011 Added guard (#ifndef), deleted using namespace RCH #ifndef _STRSET_ #define _STRSET_ #include <iostream> #include <vector> #include <string> // Deleted: using namespace std; 15 Feb 2011 RCH struct node { std::string s1; node * next; }; class strSet { private: node * first; public: strSet (); // Create empty set strSet (std::string s); // Create singleton set strSet (const strSet &copy); // Copy constructor ~strSet (); // Destructor int SIZE() const; bool isMember (std::string s) const; strSet operator + (const strSet& rtSide); // Union strSet operator - (const strSet& rtSide); // Set subtraction strSet& operator = (const strSet& rtSide); // Assignment }; // End of strSet class #endif // _STRSET_ strSet2.cpp (implementation of member functions) #include <iostream> #include <vector> #include <string> #include "strset2.h" using namespace std; strSet::strSet() { first = NULL; } strSet::strSet(string s) { node *temp; temp = new node; temp->s1 = s; temp->next = NULL; first = temp; } strSet::strSet(const strSet& copy) { if(copy.first == NULL) { first = NULL; } else { node *n = copy.first; node *prev = NULL; while (n) { node *newNode = new node; newNode->s1 = n->s1; newNode->next = NULL; if (prev) { prev->next = newNode; } else { first = newNode; } prev = newNode; n = n->next; } } } strSet::~strSet() { if(first != NULL) { while(first->next != NULL) { node *nextNode = first->next; first->next = nextNode->next; delete nextNode; } } } int strSet::SIZE() const { int size = 0; node *temp = first; while(temp!=NULL) { size++; temp=temp->next; } return size; } bool strSet::isMember(string s) const { node *temp = first; while(temp != NULL) { if(temp->s1 == s) { return true; } temp = temp->next; } return false; } strSet strSet::operator + (const strSet& rtSide) { strSet newSet; newSet = *this; node *temp = rtSide.first; while(temp != NULL) { string newEle = temp->s1; if(!isMember(newEle)) { if(newSet.first==NULL) { node *newNode; newNode = new node; newNode->s1 = newEle; newNode->next = NULL; newSet.first = newNode; } else if(newSet.SIZE() == 1) { if(newEle < newSet.first->s1) { node *tempNext = newSet.first; node *newNode; newNode = new node; newNode->s1 = newEle; newNode->next = tempNext; newSet.first = newNode; } else { node *newNode; newNode = new node; newNode->s1 = newEle; newNode->next = NULL; newSet.first->next = newNode; } } else { node *prev = NULL; node *curr = newSet.first; while(curr != NULL) { if(newEle < curr->s1) { if(prev == NULL) { node *newNode; newNode = new node; newNode->s1 = newEle; newNode->next = curr; newSet.first = newNode; break; } else { node *newNode; newNode = new node; newNode->s1 = newEle; newNode->next = curr; prev->next = newNode; break; } } if(curr->next == NULL) { node *newNode; newNode = new node; newNode->s1 = newEle; newNode->next = NULL; curr->next = newNode; break; } prev = curr; curr = curr->next; } } } temp = temp->next; } return newSet; } strSet strSet::operator - (const strSet& rtSide) { strSet newSet; newSet = *this; node *temp = rtSide.first; while(temp != NULL) { string element = temp->s1; node *prev = NULL; node *curr = newSet.first; while(curr != NULL) { if( element < curr->s1 ) break; if( curr->s1 == element ) { if( prev == NULL) { node *duplicate = curr; newSet.first = newSet.first->next; delete duplicate; break; } else { node *duplicate = curr; prev->next = curr->next; delete duplicate; break; } } prev = curr; curr = curr->next; } temp = temp->next; } return newSet; } strSet& strSet::operator = (const strSet& rtSide) { if(this != &rtSide) { if(first != NULL) { while(first->next != NULL) { node *nextNode = first->next; first->next = nextNode->next; delete nextNode; } } if(rtSide.first == NULL) { first = NULL; } else { node *n = rtSide.first; node *prev = NULL; while (n) { node *newNode = new node; newNode->s1 = n->s1; newNode->next = NULL; if (prev) { prev->next = newNode; } else { first = newNode; } prev = newNode; n = n->next; } } } return *this; }

  Read the article

• using switch in strings

  - by xtemer

  guys me trying to use switch in strings by first coverting string into char and then apply switch but still didnt done it....here is my code..help me out.. import javax.swing.*; import java.io.*; class HappyBirthday { public static void main(String[] args) throws IOException { String Month; char[] Months = Month.toCharArray(); BufferedReader dataIn= new BufferedReader(new InputStreamReader(System.in)); System.out.println("Please enter your month."); Month = JOptionPane.showInputDialog("enter month"); String month1={"January","feb"}; char[] month2 = month1.toCharArray(); // String s=month1.equals(Month); //System.out.print(month2Array[0]); switch (month2) { case 0: System.out.println("kool"); break; case 1: System.out.println("not kool"); break; default: }}} /** if (month1[1].equals(Month)) System.out.println("kool"); else if(month1[0].equals(Month)) System.out.println("kooooooooooooool"); else System.out.println("Big kooooool"); **/

  Read the article

• Loop a formula in excel VBA

  - by CEMG

  I am trying to loop a formula in Column "D" until Column "B" doesn't have any more data. The formula I am adding to Column "D" is : IF(ISNUMBER(C5),C5,IF(C5A5/3+OFFSET(C5,-1,0)) ,IF(C5<C6,((OFFSET(C5,1,0)-OFFSET(C5,-2,0))(A5/3)+OFFSET(C5,-2,0)),""))) So the result I want in Column "D" once the macro is run is this: A B C D 3 May-10 78.0000 78.00000 1 Jun-10 52.06667 2 Jul-10 26.13333 3 Aug-10 0.2000 0.20000 1 Sep-10 0.21393 2 Oct-10 0.22786 3 Nov-10 0.2418 0.24179 1 Dec-10 0.26640 2 Jan-11 0.29102 3 Feb-11 0.3156 0.31563 1 Mar-11 0.34821 2 Apr-11 0.38080 3 May-11 0.4134 0.41338 1 Jun-11 0.44992 2 Jul-11 0.48646 3 Aug-11 0.5230 0.52300 1 Sep-11 0.56440 2 Oct-11 0.60580 3 Nov-11 0.6472 0.64720 1 Dec-11 0.43147 If someone can help me at what I am doing wrong with the VBA codes I would greatly appreciated. My CODES are the following: Sub IsNumeric() // first logic: IF(ISNUMBER(C6),C6 // If Application.IsNumber(Range("c5").Value) Then Range("d5").Value = Range("C5").Value // second logic: IF(C6 ElseIf Range("c6").Value < Range("c5").Value Then Range("d6").Value = Range("c6").Offset(2, 0).Value - Range("c6").Offset(-1, 0).Value * (Range("a6").Value / 3) + Range("c6").Offset(-1, 0).Value // third logic: IF(C6<C7,((OFFSET(C6,1,0)-OFFSET(C6,-2,0))*(A6/3)+OFFSET(C6,-2,0)),""))) // ElseIf Range("c6").Value < Range("c7").Value Then Range("d6").Value = (Range("c6").Offset(1, 0).Select) - Range("c6").Offset(-2, 0).Select * (Range("a6").Select / 3) + Range("c6").Offset(-2, 0).Select Else Range("d6").Value = "" End If End Sub

  Read the article

• Need to get 3 record for database on current date using sqlite

  - by Umaid

  SELECT rowid, Day, Advice from MainCategory where ((Day = ((cast(strftime('%d',date('now','-1 day')) as Integer)))) and (Month = (strftime('%m',date('now'))))) and ((Day = ((cast(strftime('%d',date('now')) as Integer)))) and (Month = (strftime('%m',date('now'))))) , ((Day = ((cast(strftime('%d',date('now','+1 day')) as Integer)))) and (Month = (strftime('%m',date('now',+1 month))))); What if i make my Month column in Integer data type then it would be. SELECT rowid, Month, Day, Advice from MainCategory where ((Day = ((cast(strftime('%d',date('now','-1 day')) as Integer)))) and (Month = (strftime('%m',date('now'))))) and ((Day = ((cast(strftime('%d',date('now')) as Integer)))) and (Month = (strftime('%m',date('now'))))) , ((Day = ((cast(strftime('%d',date('now','+1 day')) as Integer)))) and (Month = (strftime('%m',date('now',+1 month))))); Please note that I have over this scenerio when I am in middle of month but below query returns 2 records and 1 from begining from all 11 months as (feb is exclusive) then record will be 33 but i need three 3 records from the table and increment it on next button. Please write 3 querys one which return all three record on current date, next all 3 records must be incremented by 1 on every next button click finally all 3 records must be decremented by 1 on every previous button click keep last day and begining date on the month in minds else i have also achieved for middle of month. Running query but returns 33 records instead of 3. SELECT rowid,Month, Day, Advice from MainCategory where Day in ((cast(strftime('%d',date('now','-1 day')) as Integer)),(cast(strftime('%d',date('now')) as Integer)),(cast(strftime('%d',date('now','+1 day')) as Integer)));

  Read the article

• Returning an array of culture formatted dates C# MVC3

  - by user1875797

  I'm new to programming and trying to do an exercise that formats a date to the Thai culture in a variety of formats this is what I have for my code so far: public String[] FormatAsSpecified(DateTime theDate, String theCulture, String[] formats) { String[] dateResults = new String[formats.Length]; CultureInfo culture = CultureInfo.GetCultureInfo(theCulture); for (int i = 0; i < formats.Length; i++) { String culture_formatted_date = theDate.ToString(formats[i], culture); dateResults[i] = culture_formatted_date; } return dateResults; } This is the test method that goes with it: [TestMethod] public void FormatAsSpecifiedReturnsDateLiteralsInSpecifiedFormatForAllStandardFormatStrings() { //Arrange var controller = new DateController(); var theDate = new DateTime(2014, 2, 14, 9, 15, 32, 376); String theCulture = "th-TH"; // Array of all supported standard date and time format specifiers. String[] formats = { "d", "D", "f", "F", "g", "G", "m", "o", "r", "s", "t", "T", "u", "U", "Y" }; //Corresponding date literals for the standard Thai regional settings String[] expectedResults = {"14/2/2557" , "14 ?????????? 2557" , "14 ?????????? 2557 9:15" , "14 ?????????? 2557 9:15:32" , "14/2/2557 9:15" , "14/2/2557 9:15:32" , "14 ??????????" , "2014-02-14T09:15:32.3760000" , "Fri, 14 Feb 2014 09:15:32 GMT" , "2014-02-14T09:15:32" , "9:15" , "9:15:32" , "2014-02-14 09:15:32Z" , "??????????? 14 ?????????? 2014 9:15:32" , "?????????? 2557"}; //Act String[] actualResults = new String[15]; for (int i = 0; i < formats.Length; i++) { actualResults[i] = controller.FormatAsSpecified(theDate, theCulture, formats[i]); } //Assert CollectionAssert.AreEqual(expectedResults, actualResults); } I get an error in the test method at 'controller.FormatAsSpecified(theDate, theCulture, formats[i]);' that says "Argument 3, cannot convert from 'string' to 'string[]'" What am I doing wrong?

  Read the article

• Output array of XML to plain XML

  - by danit

  I have a script which collects 4 URL's (XML) using CURL and returns an array with 4 items each ocntaining the results of the URL's. Here is the array: array(3) { [0]=> string(41772) "<?xml version="1.0" encoding="UTF-8"?> <statuses type="array"> <status> <created_at>Tue Mar 30 20:58:53 +0000 2010</created_at> <id>11328253513</id> <text>...</text> <source...</source> <truncated>false</truncated> <in_reply_to_status_id></in_reply_to_status_id> <in_reply_to_user_id></in_reply_to_user_id> <favorited>true</favorited> <in_reply_to_screen_name></in_reply_to_screen_name> <user> <id>1...</id> <name>....</name> </status> </statuses> " [1]=> string(20630) "<?xml version="1.0" encoding="UTF-8"?> <statuses type="array"> <status> <created_at>Sun Feb 28 14:12:30 +0000 2010</created_at> <id>...</id> <text>...</text> <source>&lt;a etc... How can I easily output the XML from the array? I also need to combine the 3 XML structures into one where begins and ends in between each array.

  Read the article

• I need to Loop an a formula with the Offset function until the cell is blank

  - by CEMG

  I need to Loop the formula below until Column "B" which contains dates is empty. I am stuck and I just can't seem to write the VBA Code to do the Loop until there is no more Dates in Column "B". The formula is smoothing out the yields by using those dates that have a yield. I hope anyone would be able to help me. Thanks in advance A B C D 5 Factor Date Yield Input 6 3 May-10 .25 7 1 Jun-10 8 2 Jul-10 9 3 Aug-10 0.2000 10 1 Sep-10 11 2 Oct-10 12 3 Nov-10 0.2418 13 1 Dec-10 14 2 Jan-11 15 3 Feb-11 0.3156 16 1 Mar-11 17 2 Apr-11 . Sub IsNumeric() 'IF(ISNUMBER(C6),C6, If Application.IsNumber(range("c6").Value) Then range("d6").Value = range("c6") 'IF(C6<C5,((OFFSET(C6,2,0)-OFFSET(C6,-1,0))*A6/3+OFFSET(C6,-1,0)), If range("c6").Select < range("c5").Select Then range("d6").Value = range("c6").Offset(2, 0).Select - range("c6").Offset(-1, 0).Select * (range("a6").Select / 3) + range("c6").Offset(-1, 0).Select 'IF(C6<>C7,((OFFSET(C6,1,0)-OFFSET(C6,-2,0))*(A6/3)+OFFSET(C6,-2,0)),""))) If range("c6").Select <> range("c7").Select Then range("d6").Value = (range("c6").Offset(1, 0).Select) - range("c6").Offset(-2, 0).Select * (range("a6").Select / 3) + range("c6").Offset(-2, 0).Select Else range("d6").Value = "" End If End If End If End Sub

  Read the article

• Boost Date_Time problem compiling a simple program

  - by Andry

  Hello! I'm writing a very stupid program using Boost Date_Time library. int main(int srgc, char** argv) { using namespace boost::posix_time; date d(2002,Feb,1); //an arbitrary date ptime t1(d, hours(5)+nanosec(100)); //date + time of day offset ptime t2 = t1 - minutes(4)+seconds(2); ptime now = second_clock::local_time(); //use the clock date today = now.date(); //Get the date part out of the time } Well I cannot compile it, compiler does not recognize a type... Well I used many features of Boost libs like serialization and more... I correctly built them and, looking in my /usr/local/lib folder I can see that libboost_date_time.so is there (a good sign which means I was able to build that library) When I compile I write the following: g++ -lboost_date_time main.cpp But the errors it showed me when I specify the lib are the same of those ones where I do not specify any lib. What is this? Anyone knows? The error is main.cpp: In function ‘int main(int, char**)’: main.cpp:9: error: ‘date’ was not declared in this scope main.cpp:9: error: expected ‘;’ before ‘d’ main.cpp:10: error: ‘d’ was not declared in this scope main.cpp:10: error: ‘nanosec’ was not declared in this scope main.cpp:13: error: expected ‘;’ before ‘today’

  Read the article

< Previous Page | 18 19 20 21 22 23 24 25 26 27 28  | Next Page >