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• Insert element into a tree from a list in Standard ML

  - by vichet

  I have just started to learn SML on my own and get stuck with a question from the tutorial. Let say I have: tree data type datatype node of (tree*int*tree) | null insert function fun insert (newItem, null) = node (null, newItem, null) | insert (newItem, node (left, oldItem, right)) = if (newItem <= oldItem) then node (insert(newItem,left),oldItem, right) else node (left, oldItem, insert(newItem, right) an integer list val intList = [19,23,21,100,2]; my question is how can I add write a function to loop through each element in the list and add to a tree? Your answer is really appreciated.

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• Sql Server - INSERT INTO SELECT to avoid duplicates

  - by Ashish Gupta

  I have following two tables:- Table1 ------------- ID Name 1 A 2 B 3 C Table2 -------- ID Name 1 Z I need to insert data from Table1 to Table2 and I can use following sytax for the same:- INSERT INTO Table2(Id, Name) SELECT Id, Name FROM Table1 However, In my case duplicate Ids might exist in Table2 (In my case Its Just "1") and I dont want to copy that again as that would throw an error. I can write something like this:- IF NOT EXISTS(SELECT 1 FROM Table2 WHERE Id=1) INSERT INTO Table2 (Id, name) SELECT Id, name FROM Table1 ELSE INSERT INTO Table2 (Id, name) SELECT Id, name FROM Table1 WHERE Table1.Id<>1 Is there a better way to do this without using IF - ELSE? I want to avoid two INSERT INTO-SELECT statements based on some condition. Any help is appreciated.

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• MySQL Insert not working with Date column

  - by Ian McCullough

  Hello All, I am having an issue with a simple insert query into a table. I have this PHP Code $T_MEMBER = "INSERT INTO T_MEMBER (MEMBER_IDENTIFIER,LAST_NAME,FIRST_NAME,BIRTH_DATE) VALUES ('$memberID','$last','$first','$birthdate')"; mysql_query($T_MEMBER) or die(mysql_error()); Here are a few examples of what the query looks like if i echo it: INSERT INTO T_MEMBER (MEMBER_IDENTIFIER,LAST_NAME,FIRST_NAME,BIRTH_DATE) VALUES ('2007','Hayes','Karin','1958-30-10') INSERT INTO T_MEMBER (MEMBER_IDENTIFIER,LAST_NAME,FIRST_NAME,BIRTH_DATE) VALUES ('2020','Long','Peggy','1968-29-5') INSERT INTO T_MEMBER (MEMBER_IDENTIFIER,LAST_NAME,FIRST_NAME,BIRTH_DATE) VALUES ('2021','Torres','Diane','1968-30-8') BIRTH_DATE is a date type column. The problem is, after i do any of these queries, the date shows up as 000-00-00!!!! I have been wracking my brain and i cannot seem to find the issue. Thanks, Ian

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• MySQL: Insert row on table2 if row in table1 exists

  - by Andrew M

  I'm trying to set up a MySQL query that will insert a row into table2 if a row in table1 exist already, otherwise it will just insert the row into table1. I need to find a way to adapt the following query into inserting a row into table2 with the existing row's id. INSERT INTO table1 (host, path) VALUES ('youtube.com', '/watch') IF NOT EXISTS ( SELECT * FROM table1 WHERE host='youtube.com' AND path='/watch' LIMIT 1); Something kind of like this: INSERT ... IF NOT EXISTS(..) ELSE INSERT INTO table2 (table1_id) VALUES(row.id); Except I don't know the syntax for this.

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• value of type 'string' cannot be converted to 'Devart.data.postgresql.PgSqlParameter'

  - by hector

  The following is my PostgreSQL table structure and the vb.net code to insert into the tables.Using Devart's Component For PostgreSQL Connect table gtab83 CREATE TABLE gtab83 ( orderid integer NOT NULL DEFAULT nextval('seq_gtab83_id'::regclass), acid integer, slno integer, orderdte date ) table gtab84 CREATE TABLE gtab84 ( orderdetid integer DEFAULT nextval('seq_gtab84_id'::regclass), productid integer, qty integer, orderid integer ) Code to insert into the above tables is below '1.)INSERT INTO gtab83(orderid,acid, slno, orderdte) VALUES (?, ?, ?); '2.)INSERT INTO gtab84(orderdetid,productid, qty, orderid) VALUES (?, ?, ?); Try Dim cmd As PgSqlCommand = New PgSqlCommand("", Myconnstr) cmd.CommandText = _ "INSERT INTO GTAB83(ACID,SLNO,ORDERDTE)" & _ "VALUES " & _ "(@acid,@slno,@orderdte);" Dim paramAcid As PgSqlParameter = New PgSqlParameter("@acid", PgSqlType.Int, 0) Dim paramSlno As PgSqlParameter = New PgSqlParameter("@slno", PgSqlType.Int, 0) Dim paramOrderdte As PgSqlParameter = New PgSqlParameter("@orderdte", PgSqlType.Date, 0) paramAcid = cboCust.SelectedValue paramSlno = txtOrderNO.Text #ERROR# paramOrderdte = (txtDate.Text, "yyyy-MM-dd") #ERROR# Catch ex As Exception End Try ERROR : value of type 'string' cannot be converted to 'Devart.data.postgresql.PgSqlParameter'

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• How to change Zend_Db_Table name within a Model to insert in multiple tables

  - by jwhat

  Using Zend Framework, I've created a Model to insert a record into a database. My question is, after $this->insert($data) how can I switch the active table so that I can insert a record into another table? Here's my code so far: class Model_DbTable_Foo extends Zend_Db_Table_Abstract { protected $_name = 'foo'; public function addFoo($params) { $data = array( 'foo' => $params['foo'], ); $this->insert($data); $foo_id = $this->getAdapter()->lastInsertId(); $data2 = array( 'bar' => $params['bar'] ); // I need to change the Db Table name here. $this->insert($data2); $bar_id = $this->getAdapter()->lastInsertId(); } }

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• How Serializable works with insert in SQL Server 2005

  - by Spence

  G'day I think I have a misunderstanding of serializable. I have two tables (data, transaction) which I insert information into in a serializable transaction (either they are both in, or both out, but not in limbo). SET TRANSACTION ISOLATION LEVEL SERIALIZABLE BEGIN TRANSACTION INSERT INTO dbo.data (ID, data) VALUES (@Id, data) INSERT INTO dbo.transactions(ID, info) VALUES (@ID, @info) COMMIT TRANSACTION I have a reconcile query which checks the data table for entries where there is no transaction at read committed isolation level. INSERT INTO reconciles (ReconcileID, DataID) SELECT Reconcile = @ReconcileID, ID FROM Data WHERE NOT EXISTS (SELECT 1 FROM TRANSACTIONS WHERE data.id = transactions.id) Note that the ID is actually a composite (2 column) key, so I can't use a NOT IN operator My understanding was that the second query would exclude any values written into data without their transaction as this insert was happening at serializable and the read was occurring at read committed. I have evidence that reconcile is picking up entries

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• INSERT SELECT Statement and Rollback SQL

  - by Juan Perez

  Im Working on a creation of a query who uses INSERT SELECT statement using MS SQL Server 2008: INSERT INTO TABLE1 (col1, col2) SELECT col1, col2 FROM TABLE2 Right now the excecution of this query is inside a transaction: Pseudocode: try { begin transaction; query; commit; } catch { rollback; } If TABLE2 has around 40m of rows, at the moment of making the insert on the TABLE1, if there is an error in the middle of the INSERT, will the INSERT SELECT statement make a rollback itself or I need to use a transaction to preserve data integrity? It is necessary to use a transaction? or SQL SERVER it self uses a transaction for this type of sentences.

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• Mistake in display and insert methods (double-ended queue)

  - by MANAL

  1) My problem when i make remove from right or left program will be remove true but when i call diplay method the content wrong like this I insert 12 43 65 23 and when make remove from left program will remove 12 but when call display method show like this 12 43 65 and when make remove from right program will remove 23 but when call display method show like this 12 43 Why ?????? ); and when i try to make insert after remove write this Can not insert right because the queue is full . first remove right and then u can insert right where is the problem ?? Please Help me please 2) My code FIRST CLASS class dqueue { private int fullsize; //number of all cells private int item_num; // number of busy cells only private int front,rear; public int j; private double [] dqarr; //========================================== public dqueue(int s) //constructor { fullsize = s; front = 0; rear = -1; item_num = 0; dqarr = new double[fullsize]; } //========================================== public void insert(double data) { if (rear == fullsize-1) rear = -1; rear++; dqarr[rear] = data; item_num++; } public double removeLeft() // take item from front of queue { double temp = dqarr[front++]; // get value and incr front if(front == fullsize) front = 0; item_num --; // one less item return temp; } public double removeRight() // take item from rear of queue { double temp = dqarr[rear--]; // get value and decr rear if(rear == -1) // rear = item_num -1; item_num --; // one less item return temp; } //========================================= public void display () //display items { for (int j=0;j<item_num;j++) // for every element System.out.print(dqarr[j] +" " ); // display it System.out.println(""); } //========================================= public int size() //number of items in queue { return item_num; } //========================================== public boolean isEmpty() // true if queue is empty { return (item_num ==0); } } SECOND CLASS import java.util.Scanner; class dqueuetest { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println(" ***** Welcome here***** "); System.out.println(" ***** Mind Of Programming Group***** "); System.out.println(" _____________________________________________ "); System.out.println("enter size of your dqueue"); int size = input.nextInt(); dqueue mydq = new dqueue(size); System.out.println(""); System.out.println("enter your itemes"); //===================================== for(int i = 0;i<=size-1;i++) { System.out.printf("item %d:",i+1); double item = input.nextDouble(); mydq.insert(item); System.out.println(""); } //===================================== int queue =size ; int c = 0 ; while (c != 6) { System.out.println(""); System.out.println("************************************************"); System.out.println(" MAIN MENUE"); System.out.println("1- INSERT RIGHT "); System.out.println("2- REMOVE LEFT"); System.out.println("3- REMOVE RIGHT"); System.out.println("4- DISPLAY"); System.out.println("5- SIZE"); System.out.println("6- EXIT"); System.out.println("************************************************"); System.out.println("choose your operation by number(1-6)"); c = input.nextInt(); switch (c) { case 1: if (queue == size) System.out.print("Can not insert right because the queue is full . first remove right and then u can insert right "); else { System.out.print("enter your item: "); double item = input.nextDouble(); mydq.insert(item);} break; case 2: System.out.println("REMOVE FROM REAR :"); if( !mydq.isEmpty() ) { double item = mydq.removeLeft(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 3: System.out.println("REMOVE FROM FRONT :"); if( !mydq.isEmpty() ) { double item = mydq.removeRight(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 4: System.out.println("The items in Queue are :"); mydq.display(); break; case 5: System.out.println("The Size of the Queue is :"+mydq.size()); break; case 6: System.out.println("Good Bye"); break; default: System.out.println("wrong chiose enter again"); } //end switch } //end while } // end main }//end class

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• Repeating characters in VIM insert mode

  - by Cthutu

  Is there a way of repeating a character while in Vim's insert mode? For example, say I would like to insert 80 dashes, in something like emacs I would type: Ctrl+U 8 0 - The only way I know how to do it in VIM is to exit normal mode for the repeat argument, then go back into insert mode to type the dash, then exit to insert the actual dashes, AND then go back into insert mode to carry on typing. The sequence is a really long: <ESC> 8 0 a - <ESC> a It would be nice not to switch in and out of modes. Thanks

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• Insert into select and update in single query

  - by Ossi

  I have 4 tables: tempTBL, linksTBL and categoryTBL, extra on my tempTBL I have: ID, name, url, cat, isinserted columns on my linksTBL I have: ID, name, alias columns on my categoryTBL I have: cl_id, link_id,cat_id on my extraTBL I have: id, link_id, value How do I do a single query to select from tempTBL all items where isinsrted = 0 then insert them to linksTBL and for each record inserted, pickup ID (which is primary) and then insert that ID to categoryTBL with cat_id = 88. after that insert extraTBL ID for link_id and url for value. I know this is so confusing, put I'll post this anyhow... This is what I have so far: INSERT IGNORE INTO linksTBL (link_id,link_name,alias) VALUES(NULL,'tex2','hello'); # generate ID by inserting NULL INSERT INTO categoryTBL (link_id,cat_id) VALUES(LAST_INSERT_ID(),'88'); # use ID in second table I would like to add here somewhere that it only selects items where isinserted = 0 and iserts those records, and onse inserted, will change isinserted to 1, so when next time it runs, it will not add them again.

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• Last element not getting insert in Tree

  - by rdk1992

  So I was asked to make a Binary Tree in Haskell taking as input a list of Integers. Below is my code. My problem is that the last element of the list is not getting inserted in the Tree. For example [1,2,3,4] it only inserts to the tree until "3" and 4 is not inserted in the Tree. data ArbolBinario a = Node a (ArbolBinario a) (ArbolBinario a) | EmptyNode deriving(Show) insert(x) EmptyNode= insert(tail x) (Node (head x) EmptyNode EmptyNode) insert(x) (Node e izq der) |x == [] = EmptyNode --I added this line to fix the Prelude.Head Empty List error, after I added this line the last element started to be ignored and not inserted in the tree |head x == e = (Node e izq der) |head x < e = (Node e (insert x izq) der) |head x > e = (Node e izq (insert x der)) Any ideas on whats going on here? Help is much appreciated

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• Mistake in dispaly and insert method (double - ended queue)

  - by MANAL

  1) My problem when i make remove from right or left program will be remove true but when i call diplay method the content wrong like this I insert 12 43 65 23 and when make remove from left program will remove 12 but when call display method show like this 12 43 65 and when make remove from right program will remove 23 but when call display method show like this 12 43 Why ?????? ); and when i try to make insert after remove write this Can not insert right because the queue is full . first remove right and then u can insert right where is the problem ?? Please Help me please 2) My code FIRST CLASS class dqueue { private int fullsize; //number of all cells private int item_num; // number of busy cells only private int front,rear; public int j; private double [] dqarr; //========================================== public dqueue(int s) //constructor { fullsize = s; front = 0; rear = -1; item_num = 0; dqarr = new double[fullsize]; } //========================================== public void insert(double data) { if (rear == fullsize-1) rear = -1; rear++; dqarr[rear] = data; item_num++; } public double removeLeft() // take item from front of queue { double temp = dqarr[front++]; // get value and incr front if(front == fullsize) front = 0; item_num --; // one less item return temp; } public double removeRight() // take item from rear of queue { double temp = dqarr[rear--]; // get value and decr rear if(rear == -1) // rear = item_num -1; item_num --; // one less item return temp; } //========================================= public void display () //display items { for (int j=0;j //========================================= public int size() //number of items in queue { return item_num; } //========================================== public boolean isEmpty() // true if queue is empty { return (item_num ==0); } } SECOND CLASS import java.util.Scanner; class dqueuetest { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println(" Welcome here** "); System.out.println(" * Mind Of Programming Group*** "); System.out.println(" _________________________ "); System.out.println("enter size of your dqueue"); int size = input.nextInt(); dqueue mydq = new dqueue(size); System.out.println(""); System.out.println("enter your itemes"); //===================================== for(int i = 0;i<=size-1;i++) { System.out.printf("item %d:",i+1); double item = input.nextDouble(); mydq.insert(item); System.out.println(""); } //===================================== int queue =size ; int c = 0 ; while (c != 6) { System.out.println(""); System.out.println("**************************"); System.out.println(" MAIN MENUE"); System.out.println("1- INSERT RIGHT "); System.out.println("2- REMOVE LEFT"); System.out.println("3- REMOVE RIGHT"); System.out.println("4- DISPLAY"); System.out.println("5- SIZE"); System.out.println("6- EXIT"); System.out.println("**************************"); System.out.println("choose your operation by number(1-6)"); c = input.nextInt(); switch (c) { case 1: if (queue == size) System.out.print("Can not insert right because the queue is full . first remove right and then u can insert right "); else { System.out.print("enter your item: "); double item = input.nextDouble(); mydq.insert(item);} break; case 2: System.out.println("REMOVE FROM REAR :"); if( !mydq.isEmpty() ) { double item = mydq.removeLeft(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 3: System.out.println("REMOVE FROM FRONT :"); if( !mydq.isEmpty() ) { double item = mydq.removeRight(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 4: System.out.println("The items in Queue are :"); mydq.display(); break; case 5: System.out.println("The Size of the Queue is :"+mydq.size()); break; case 6: System.out.println("Good Bye"); break; default: System.out.println("wrong chiose enter again"); } //end switch } //end while } // end main }//end class

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• SQL SERVER – Maximize Database Performance with DB Optimizer – SQL in Sixty Seconds #054

  - by Pinal Dave

  Performance tuning is an interesting concept and everybody evaluates it differently. Every developer and DBA have different opinion about how one can do performance tuning. I personally believe performance tuning is a three step process Understanding the Query Identifying the Bottleneck Implementing the Fix While, we are working with large database application and it suddenly starts to slow down. We are all under stress about how we can get back the database back to normal speed. Most of the time we do not have enough time to do deep analysis of what is going wrong as well what will fix the problem. Our primary goal at that time is to just fix the database problem as fast as we can. However, here is one very important thing which we need to keep in our mind is that when we do quick fix, it should not create any further issue with other parts of the system. When time is essence and we want to do deep analysis of our system to give us the best solution we often tend to make mistakes. Sometimes we make mistakes as we do not have proper time to analysis the entire system. Here is what I do when I face such a situation – I take the help of DB Optimizer. It is a fantastic tool and does superlative performance tuning of the system. Everytime when I talk about performance tuning tool, the initial reaction of the people is that they do not want to try this as they believe it requires lots of the learning of the tool before they use it. It is absolutely not true with the case of the DB optimizer. It is a very easy to use and self intuitive tool. Once can get going with the product, in no time. Here is a quick video I have build where I demonstrate how we can identify what index is missing for query and how we can quickly create the index. Entire three steps of the query tuning are completed in less than 60 seconds. If you are into performance tuning and query optimization you should download DB Optimizer and give it a go. Let us see the same concept in following SQL in Sixty Seconds Video: You can Download DB Optimizer and reproduce the same Sixty Seconds experience. Related Tips in SQL in Sixty Seconds: Performance Tuning – Part 1 of 2 – Getting Started and Configuration Performance Tuning – Part 2 of 2 – Analysis, Detection, Tuning and Optimizing What would you like to see in the next SQL in Sixty Seconds video? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Database, Pinal Dave, PostADay, SQL, SQL Authority, SQL in Sixty Seconds, SQL Interview Questions and Answers, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology, Video Tagged: Identity

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• PostgreSQL insert on primary key failing with contention, even at serializable level

  - by Steven Schlansker

  I'm trying to insert or update data in a PostgreSQL db. The simplest case is a key-value pairing (the actual data is more complicated, but this is the smallest clear example) When you set a value, I'd like it to insert if the key is not there, otherwise update. Sadly Postgres does not have an insert or update statement, so I have to emulate it myself. I've been working with the idea of basically SELECTing whether the key exists, and then running the appropriate INSERT or UPDATE. Now clearly this needs to be be in a transaction or all manner of bad things could happen. However, this is not working exactly how I'd like it to - I understand that there are limitations to serializable transactions, but I'm not sure how to work around this one. Here's the situation - ab: => set transaction isolation level serializable; a: => select count(1) from table where id=1; --> 0 b: => select count(1) from table where id=1; --> 0 a: => insert into table values(1); --> 1 b: => insert into table values(1); --> ERROR: duplicate key value violates unique constraint "serial_test_pkey" Now I would expect it to throw the usual "couldn't commit due to concurrent update" but I'm guessing since the inserts are different "rows" this does not happen. Is there an easy way to work around this?

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• value of Identity column returning null when retrieved by value in dataGridView

  - by Raven Dreamer

  Greetings. I'm working on a windows forms application that interacts with a previously created SQL database. Specifically, I'm working on implementing an "UPDATE" query. for (int i = 0; i < dataGridView1.RowCount; i++) { string firstName = (string)dataGridView1.Rows[i].Cells[0].Value; string lastName = (string)dataGridView1.Rows[i].Cells[1].Value; string phoneNo = (string)dataGridView1.Rows[i].Cells[2].Value; short idVal = (short)dataGridView1.Rows[i].Cells[3].Value; this.contactInfoTableAdapter.UpdateQuery(firstName, lastName, phoneNo, idVal); } The dataGridView has 4 columns, First Name, Last Name, Phone Number, and ID (which was created as an identity column when I initially formed the table in SQL). When I try to run this code, the three strings are returned properly, but dataGridView1.Rows[i].Cells[3].Value is returning "null". I'm guessing this is because it was created as an identity column rather than a normal column. What's a better way to retrieve the relevant ID value for my UpdateQuery?

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• SQL Server INSERT ... SELECT Statement won't parse

  - by Jim Barnett

  I am getting the following error message with SQL Server 2005 Msg 120, Level 15, State 1, Procedure usp_AttributeActivitiesForDateRange, Line 18 The select list for the INSERT statement contains fewer items than the insert list. The number of SELECT values must match the number of INSERT columns. I have copy and pasted the select list and insert list into excel and verified there are the same number of items in each list. Both tables an additional primary key field with is not listed in either the insert statement or select list. I am not sure if that is relevant, but suspicious it may be. Here is the source for my stored procedure: CREATE PROCEDURE [dbo].[usp_AttributeActivitiesForDateRange] ( @dtmFrom DATETIME, @dtmTo DATETIME ) AS BEGIN SET NOCOUNT ON; DECLARE @dtmToWithTime DATETIME SET @dtmToWithTime = DATEADD(hh, 23, DATEADD(mi, 59, DATEADD(s, 59, @dtmTo))); -- Get uncontested DC activities INSERT INTO AttributedDoubleClickActivities ([Time], [User-ID], [IP], [Advertiser-ID], [Buy-ID], [Ad-ID], [Ad-Jumpto], [Creative-ID], [Creative-Version], [Creative-Size-ID], [Site-ID], [Page-ID], [Country-ID], [State Province], [Areacode], [OS-ID], [Domain-ID], [Keyword], [Local-User-ID], [Activity-Type], [Activity-Sub-Type], [Quantity], [Revenue], [Transaction-ID], [Other-Data], Ordinal, [Click-Time], [Event-ID]) SELECT [Time], [User-ID], [IP], [Advertiser-ID], [Buy-ID], [Ad-ID], [Ad-Jumpto], [Creative-ID], [Creative-Version], [Creative-Size-ID], [Site-ID], [Page-ID], [Country-ID], [State Province], [Areacode], [OS-ID], [Domain-ID], [Keyword], [Local-User-ID] [Activity-Type], [Activity-Sub-Type], [Quantity], [Revenue], [Transaction-ID], [Other-Data], REPLACE(Ordinal, '?', '') AS Ordinal, [Click-Time], [Event-ID] FROM Activity_Reports WHERE [Time] BETWEEN @dtmFrom AND @dtmTo AND REPLACE(Ordinal, '?', '') IN (SELECT REPLACE(Ordinal, '?', '') FROM Activity_Reports WHERE [Time] BETWEEN @dtmFrom AND @dtmTo EXCEPT SELECT CONVERT(VARCHAR, TripID) FROM VisualSciencesActivities WHERE [Time] BETWEEN @dtmFrom AND @dtmTo); END GO

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• Not able to insert data in the database from a form in php

  - by Prashant Baid

  I am not able to insert data into my data, i dont know what the problem is. Here is the code: mysql_select_db("mitestore", $con); */ if ((isset($_POST['product_name'])) && (strlen(trim($_POST['product_name'])) 0)) { $product_name = stripslashes(strip_tags($_POST['product_name'])); $sql="INSERT INTO sell (product_name) VALUE ('$_POST[product_name]')"; } else {$product_name = 'Please enter the product name.';} if ((isset($_POST[''])) && (strlen(trim($_POST['how_old'])) 0)) { $how_old = stripslashes(strip_tags($_POST['how_old'])); $sql="INSERT INTO sell (how_old) VALUE ('$_POST[how_old]')"; } else {$how_old = 'Please enter how old your product is';} if ((isset($_POST['which_block'])) && (strlen(trim($_POST['which_block'])) 0)) { $which_block = stripslashes(strip_tags($_POST['which_block'])); $sql="INSERT INTO sell (which_block) VALUE ('$_POST[which_block]')"; } else {$which_block = 'Please enter which block are you from';} if ((isset($_POST['room_no'])) && (strlen(trim($_POST['room_no'])) 0)) { $room_no = stripslashes(strip_tags($_POST['room_no'])); $sql="INSERT INTO sell (room_no) VALUE ('$_POST[room_no]')"; } else {$room_no = 'Please enter the room no:';} if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Success!"; mysql_close($con) ? Initially i had this code and it worked for me. mysql_select_db("database", $con); $sql="INSERT INTO sell ( product_name, how_old , selling_price, negotiable, which_block, room_no) VALUES ('$_POST[product_name]','$_POST[how_old]','$_POST[selling_price]','$_POST[negotiable]','$_POST[which_block]','$_POST[room_no]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Your product is added."; mysql_close($con) ? But i don't know how to validate each field individually.

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• F# insert/remove item from list

  - by Timothy

  How should I go about removing a given element from a list? As an example, say I have list ['A'; 'B'; 'C'; 'D'; 'E'] and want to remove the element at index 2 to produce the list ['A'; 'B'; 'D'; 'E']? I've already written the following code which accomplishes the task, but it seems rather inefficient to traverse the start of the list when I already know the index. let remove lst i = let rec remove lst lst' = match lst with | [] -> lst' | h::t -> if List.length lst = i then lst' @ t else remove t (lst' @ [h]) remove lst [] let myList = ['A'; 'B'; 'C'; 'D'; 'E'] let newList = remove myList 2 Alternatively, how should I insert an element at a given position? My code is similar to the above approach and most likely inefficient as well. let insert lst i x = let rec insert lst lst' = match lst with | [] -> lst' | h::t -> if List.length lst = i then lst' @ [x] @ lst else insert t (lst' @ [h]) insert lst [] let myList = ['A'; 'B'; 'D'; 'E'] let newList = insert myList 2 'C'

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• BYOD is not a fashion statement; it’s an architectural shift - by Indus Khaitan

  - by Greg Jensen

  Ten years ago, if you asked a CIO, “how mobile is your enterprise?”. The answer would be, “100%, we give Blackberry to all our employees.”Few things have changed since then: 1.    Smartphone form-factors have matured, especially after the launch of iPhone. 2.    Rapid growth of productivity applications and services that enable creation and consumption of digital content 3.    Pervasive mobile data connectivityThere are two threads emerging from the change. Users are rapidly mingling their personas of an individual as well as an employee. In the first second, posting a picture of a fancy dinner on Facebook, to creating an expense report for the same meal on the mobile device. Irrespective of the dual persona, a user’s personal and corporate lives intermingle freely on a single hardware and more often than not, it’s an employees personal smartphone being used for everything. A BYOD program enables IT to “control” an employee owned device, while enabling productivity. More often than not the objective of BYOD programs are financial; instead of the organization, an employee pays for it.  More than a fancy device, BYOD initiatives have become sort of fashion statement, of corporate productivity, of letting employees be in-charge and a show of corporate empathy to not force an archaic form-factor in a world of new device launches every month. BYOD is no longer a means of effectively moving expense dollars and support costs. It does not matter who owns the device, it has to be protected.  BYOD brings an architectural shift.  BYOD is an architecture, which assumes that every device is vulnerable, not just what your employees have brought but what organizations have purchased for their employees. It's an architecture, which forces us to rethink how to provide productivity without comprising security.Why assume that every device is vulnerable? Mobile operating systems are rapidly evolving with leading upgrade announcement every other month. It is impossible for IT to catch-up. More than that, user’s are savvier than earlier.  While IT could install locks at the doors to prevent intruders, it may degrade productivity—which incentivizes user’s to bypass restrictions. A rapidly evolving mobile ecosystem have moving parts which are vulnerable. Hence, creating a mobile security platform, which uses the fundamental blocks of BYOD architecture such as identity defragmentation, IT control and data isolation, ensures that the sprawl of corporate data is contained. In the next post, we’ll dig deeper into the BYOD architecture. Normal 0 false false false EN-US JA X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:12.0pt; font-family:"Cambria","serif"; mso-ascii-font-family:Cambria; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Cambria; mso-hansi-theme-font:minor-latin;}

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• Insert a newline in a perl -e statement?

  - by lydonchandra

  If I do this in bash perl -e '$x; $y' How can I insert a newline between the character ; and $y? I don't want to re-type the whole line, I just want to move my cursor to the position and then insert a newline. Is this possible? Many thanks.

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• insert newline in perl -e statement

  - by lydonchandra

  Hi If I do this in bash perl -e '$x; $y' How can I insert a new line between the character ; and $y? I don't want to re-type the whole line, I just want to move my cursor to the position and then insert a newline ? Is this possible? Many thanks

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• how to spoof compelte browser identity

  - by Greenleader

  I found question on how to spoof user agent. I dont' want to spoof only user agent. I want to spoof everything from user agent, to Accept headers to http headers and also the information javascript can tell about browser - screen resolution and depth, class cpu, platform, device name, etc. Do you know of a way to achieve this in any browser out there ? I don't want 10 plugins to achieve this. I'd like unified way.

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• The Unintended Consequences of Sound Security Policy

  - by Tanu Sood

  v\:* {behavior:url(#default#VML);} o\:* {behavior:url(#default#VML);} w\:* {behavior:url(#default#VML);} .shape {behavior:url(#default#VML);} Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Calibri","sans-serif"; mso-bidi-font-family:"Times New Roman";} Author: Kevin Moulton, CISSP, CISM Meet the Author: Kevin Moulton, Senior Sales Consulting Manager, Oracle Kevin Moulton, CISSP, CISM, has been in the security space for more than 25 years, and with Oracle for 7 years. He manages the East Enterprise Security Sales Consulting Team. He is also a Distinguished Toastmaster. Follow Kevin on Twitter at twitter.com/kevin_moulton, where he sometimes tweets about security, but might also tweet about running, beer, food, baseball, football, good books, or whatever else grabs his attention. Kevin will be a regular contributor to this blog so stay tuned for more posts from him. When I speak to a room of IT administrators, I like to begin by asking them if they have implemented a complex password policy. Generally, they all nod their heads enthusiastically. I ask them if that password policy requires long passwords. More nodding. I ask if that policy requires upper and lower case letters – faster nodding – numbers – even faster – special characters – enthusiastic nodding all around! I then ask them if their policy also includes a requirement for users to regularly change their passwords. Now we have smiles with the nodding! I ask them if the users have different IDs and passwords on the many systems that they have access to. Of course! I then ask them if, when they walk around the building, they see something like this: Thanks to Jake Ludington for the nice example. Can these administrators be faulted for their policies? Probably not but, in the end, end-users will find a way to get their job done efficiently. Post-It Notes to the rescue! I was visiting a business in New York City one day which was a perfect example of this problem. First I walked up to the security desk and told them where I was headed. They asked me if they should call upstairs to have someone escort me. Is that my call? Is that policy? I said that I knew where I was going, so they let me go. Having the conference room number handy, I wandered around the place in a search of my destination. As I walked around, unescorted, I noticed the post-it note problem in abundance. Had I been so inclined, I could have logged in on almost any machine and into any number of systems. When I reached my intended conference room, I mentioned my post-it note observation to the two gentlemen with whom I was meeting. One of them said, “You mean like this,” and he produced a post it note full of login IDs and passwords from his breast pocket! I gave him kudos for not hanging the list on his monitor. We then talked for the rest of the meeting about the difficulties faced by the employees due to the security policies. These policies, although well-intended, made life very difficult for the end-users. Most users had access to 8 to 12 systems, and the passwords for each expired at a different times. The post-it note solution was understandable. Who could remember even half of them? What could this customer have done differently? I am a fan of using a provisioning system, such as Oracle Identity Manager, to manage all of the target systems. With OIM, and email could be automatically sent to all users when it was time to change their password. The end-users would follow a link to change their password on a web page, and then OIM would propagate that password out to all of the systems that the user had access to, even if the login IDs were different. Another option would be an Enterprise Single-Sign On Solution. With Oracle eSSO, all of a user’s credentials would be stored in a central, encrypted credential store. The end-user would only have to login to their machine each morning and then, as they moved to each new system, Oracle eSSO would supply the credentials. Good-bye post-it notes! 3M may be disappointed, but your end users will thank you. I hear people say that this post-it note problem is not a big deal, because the only people who would see the passwords are fellow employees. Do you really know who is walking around your building? What are the password policies in your business? How do the end-users respond?

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• Simulating an identity column within an insert trigger

  - by William Jens

  I have a table for logging that needs a log ID but I can't use an identity column because the log ID is part of a combo key. create table StuffLogs { StuffID int LogID int Note varchar(255) } There is a combo key for StuffID & LogID. I want to build an insert trigger that computes the next LogID when inserting log records. I can do it for one record at a time (see below to see how LogID is computed), but that's not really effective, and I'm hoping there's a way to do this without cursors. select @NextLogID = isnull(max(LogID),0)+1 from StuffLogs where StuffID = (select StuffID from inserted) The net result should allow me to insert any number of records into StuffLogs with the LogID column auto computed. StuffID LogID Note 123 1 foo 123 2 bar 456 1 boo 789 1 hoo Inserting another record using StuffID: 123, Note: bop will result in the following record: StuffID LogID Note 123 3 bop

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