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  • How to parse IP addresses with perl?

    - by Andrey Zentavr
    Hello! I have list of IPs: 238.51.208.96/28 238.51.209.180-199 238.51.209.100-109 238.51.213.2-254 ... How can I easily parse them? I need first and last IP from range. For First line I can use Net::Netmask CPAN module, but what can I do with others lines?

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  • UK IP address lookup API

    - by Phil Jackson
    Hi, im looking for a UK IP address lookup api ( or PHP script ) to find the location of a user. I want to produce more relevent results for a user when searching a directory. All the ones I have found just say 'UK' and dont get any more information than that. Can anyone point me in the right direction? Regards, Phil

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  • How to calculate an IPv6 IP Number?

    - by Bram
    I'm adding GeoIP tracking to WCF Web Service using MaxMinds' GeoIP Lite Country. All works well for their IPv4 database but they don't give any samples to calculate an IPv6 IP Number. I've contacted them and they said to use a search engine. Anyone have a sample they're willing to share? Any language will do.

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  • Redirect a specific IP address to a special page of my homepage with .htaccess

    - by Jim Knopf
    How can I use .htaccess to forward a visitor of a specific IP address to a webpage on my server? This example causes an infinite loop: RewriteCond %{REMOTE_ADDR} ^123\.\123\.123\.123$ RewriteRule ^(.*)$ /specialpage.php [R,L] I found this on the web but it just does not work: SetEnvIf REMOTE_ADDR 123.123.123.123 REDIR="redir" RewriteCond %{REDIR} redir RewriteRule ^(.*)$ /specialpage.php Note: My website consists of .htm, html and .php pages. Your help would be very much appreciated.

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  • VMWare Network bug in multiple VMWare Workstation versions if using a hardcoded IP address

    - by onyxruby
    I'm having a very tricky problem with some of my VM sessions being unable to reach the Internet or even ping the gateway. I have just set up a new VM Workstation (7) on a W2K8 64bit server (I'll be converting to ESXI 4 once I can find a decent book on it, so for the meanwhile I use workstation). I have imported a number of VM's and setup some new ones on the server.In short the problem with some of the VM's being unable to reach the Internet is that they can't reach the gateway. I've looking at a number of things and can pretty safely rule out the following: Switch, Router, DHCP Server, DNS, Client IP configuration, Routes and typos. The problem is that some of the new clients cannot reach the gateway if their IP address is hardcoded, they can't even ping it by IP address. That rules out DNS and DHCP. Now, if I allow them to get their IP address by DHCP they can reach the gateway and Internet without issue. The interesting thing on this, is that this behavior occurs even if I leave the DNS information hardcoded under TCP/IP settings. It doesn't work unless the IP and gateway are handed out by DHCP even though the same information IP info is being used by the host. Fundamentally from the standpoint of the clients, they are trying to reach the exact same gateway using the exact same IP information regardless of whether they are hardcoded or assigned by DHCP. Here's an example of one client. IP Address 192.168.7.66 - Subnet Mask 255.255.255.0 - Gateway 192.168.7.254 - DNS1 192.168.7.44 - DNS2 192.168.7.254. The issue occurs across six different microsoft operating systems, Windows 7 and Windows 2008 variants all have the issue. My W2K3, XP, Vista and W98 clients all work without issue with hardcoded IP addresses. I have tried things like rearranging the DNS order, flushing DNS and so on. It's not a routing or switch issue as the clients can work just fine if they get their IP by DHCP. It's not a paramater issue as the exact same paramaters are handed out by DHCP as I plug in by hand. It's not a DNS issue as clients cant reach other clients even with IP addresses only. I have run a tracert to the gateway by IP address and it times out on the very first hop before failing on hop3 with destination host unreachable. If I get the IP address by DHCP the tracert finds the gateway (and Internet) without issue. I have read a few other posts online in forums talking about this problem randomly occuring over the years in other VM versions as well, so I suspect some kind of long standing bug. Does anyone have any ideas on this? Is it possibly a bug with Windows 7 and W2K clients under VM?

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  • Benefits of sharing one IP, or prefarably assigning a new IP?

    - by Luis Yang
    I think I am lost but not found yet, please as regards this very topic; my issue was that I bought a new VPS using WHM optimised and it's just one domain meaning one IP. All I want to know is the benefit with sharing one IP to many domains I created for the users (remembering the IP is for the root) or is it of a disadvantage? Probably help me too with knowing if it's prefarable to create/assign a new IP to each new domain created for users?

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  • CISCO 2911 Router configuration

    - by bala
    Device cisco 2911 router configuration support is required please. I have exchange server 2010 configured and working without any errors the problem is in cisco router configuration when exchange server sends emails out the receives WAN IP not the public ip. I have configured RDNS lookups with our MX record IP addesses that match the FQDN but all our emails are rejected because it does not match with the public ip. Receiving mails problem is not an problem all mails are coming through. i am sure i am missing something on the router configuration that does not sends the public ip, can any one help me to solve this issue. Note; I've got 1 WAN IP & 8 Public IP from ISP . Find below the running configuration. Building configuration... Current configuration : 2734 bytes ! ! Last configuration change at 06:32:13 UTC Tue Apr 3 2012 ! NVRAM config last updated at 06:32:14 UTC Tue Apr 3 2012 ! NVRAM config last updated at 06:32:14 UTC Tue Apr 3 2012 version 15.1 service timestamps debug datetime msec service timestamps log datetime msec service password-encryption ! hostname BSBG-LL ! boot-start-marker boot-end-marker ! ! enable secret 5 $x$xHrxxxxx5ox0 enable password 7 xx23xx5FxxE1xx044 ! no aaa new-model ! no ipv6 cef ip source-route ip cef ! ! ! ! ! ip flow-cache timeout active 1 ip domain name yourdomain.com ip name-server 213.42.20.20 ip name-server 195.229.241.222 multilink bundle-name authenticated ! ! crypto pki token default removal timeout 0 ! ! license udi pid CISCO2911/K9 ! ! username bsbg ! ! ! ! ! ! interface Embedded-Service-Engine0/0 no ip address shutdown ! interface GigabitEthernet0/0 ip address 192.168.0.9 255.255.255.0 ip flow ingress ip nat inside ip virtual-reassembly in duplex auto speed 100 no cdp enable ! interface GigabitEthernet0/1 ip address 213.42.xx.x2 255.255.255.252 ip nat outside ip virtual-reassembly in duplex auto speed auto no cdp enable ! interface GigabitEthernet0/2 no ip address shutdown duplex auto speed auto ! ip forward-protocol nd ! no ip http server no ip http secure-server ! ip nat inside source list 120 interface GigabitEthernet0/1 overload ip nat inside source static tcp 192.168.0.4 25 94.56.89.100 25 extendable ip nat inside source static tcp 192.168.0.4 53 94.56.89.100 53 extendable ip nat inside source static udp 192.168.0.4 53 94.56.89.100 53 extendable ip nat inside source static tcp 192.168.0.4 110 94.56.89.100 110 extendable ip nat inside source static tcp 192.168.0.4 443 94.56.89.100 443 extendable ip nat inside source static tcp 192.168.0.4 587 94.56.89.100 587 extendable ip nat inside source static tcp 192.168.0.4 995 94.56.89.100 995 extendable ip nat inside source static tcp 192.168.0.4 3389 94.56.89.100 3389 extendable ip nat inside source static tcp 192.168.0.4 443 94.56.89.101 443 extendable ip nat inside source static tcp 192.168.0.12 80 94.56.89.102 80 extendable ip nat inside source static tcp 192.168.0.12 443 94.56.89.102 443 extendable ip nat inside source static tcp 192.168.0.12 3389 94.56.89.102 3389 extendable ip route 0.0.0.0 0.0.0.0 213.42.69.41 ! access-list 120 permit ip 192.168.0.0 0.0.0.255 any ! ! ! control-plane ! ! ! line con 0 exec-timeout 5 0 line aux 0 line 2 no activation-character no exec transport preferred none transport input all transport output pad telnet rlogin lapb-ta mop udptn v120 ssh stopbits 1 line vty 0 4 password 7 xx64xxD530D26086Dxx login transport input all ! scheduler allocate 20000 1000 end

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  • Computer Networks UNISA - Chap 10 &ndash; In Depth TCP/IP Networking

    - by MarkPearl
    After reading this section you should be able to Understand methods of network design unique to TCP/IP networks, including subnetting, CIDR, and address translation Explain the differences between public and private TCP/IP networks Describe protocols used between mail clients and mail servers, including SMTP, POP3, and IMAP4 Employ multiple TCP/IP utilities for network discovery and troubleshooting Designing TCP/IP-Based Networks The following sections explain how network and host information in an IPv4 address can be manipulated to subdivide networks into smaller segments. Subnetting Subnetting separates a network into multiple logically defined segments, or subnets. Networks are commonly subnetted according to geographic locations, departmental boundaries, or technology types. A network administrator might separate traffic to accomplish the following… Enhance security Improve performance Simplify troubleshooting The challenges of Classful Addressing in IPv4 (No subnetting) The simplest type of IPv4 is known as classful addressing (which was the Class A, Class B & Class C network addresses). Classful addressing has the following limitations. Restriction in the number of usable IPv4 addresses (class C would be limited to 254 addresses) Difficult to separate traffic from various parts of a network Because of the above reasons, subnetting was introduced. IPv4 Subnet Masks Subnetting depends on the use of subnet masks to identify how a network is subdivided. A subnet mask indicates where network information is located in an IPv4 address. The 1 in a subnet mask indicates that corresponding bits in the IPv4 address contain network information (likewise 0 indicates the opposite) Each network class is associated with a default subnet mask… Class A = 255.0.0.0 Class B = 255.255.0.0 Class C = 255.255.255.0 An example of calculating  the network ID for a particular device with a subnet mask is shown below.. IP Address = 199.34.89.127 Subnet Mask = 255.255.255.0 Resultant Network ID = 199.34.89.0 IPv4 Subnetting Techniques Subnetting breaks the rules of classful IPv4 addressing. Read page 490 for a detailed explanation Calculating IPv4 Subnets Read page 491 – 494 for an explanation Important… Subnetting only applies to the devices internal to your network. Everything external looks at the class of the IP address instead of the subnet network ID. This way, traffic directed to your network externally still knows where to go, and once it has entered your internal network it can then be prioritized and segmented. CIDR (classless Interdomain Routing) CIDR is also known as classless routing or supernetting. In CIDR conventional network class distinctions do not exist, a subnet boundary can move to the left, therefore generating more usable IP addresses on your network. A subnet created by moving the subnet boundary to the left is known as a supernet. With CIDR also came new shorthand for denoting the position of subnet boundaries known as CIDR notation or slash notation. CIDR notation takes the form of the network ID followed by a forward slash (/) followed by the number of bits that are used for the extended network prefix. To take advantage of classless routing, your networks routers must be able to interpret IP addresses that don;t adhere to conventional network class parameters. Routers that rely on older routing protocols (i.e. RIP) are not capable of interpreting classless IP addresses. Internet Gateways Gateways are a combination of software and hardware that enable two different network segments to exchange data. A gateway facilitates communication between different networks or subnets. Because on device cannot send data directly to a device on another subnet, a gateway must intercede and hand off the information. Every device on a TCP/IP based network has a default gateway (a gateway that first interprets its outbound requests to other subnets, and then interprets its inbound requests from other subnets). The internet contains a vast number of routers and gateways. If each gateway had to track addressing information for every other gateway on the Internet, it would be overtaxed. Instead, each handles only a relatively small amount of addressing information, which it uses to forward data to another gateway that knows more about the data’s destination. The gateways that make up the internet backbone are called core gateways. Address Translation An organizations default gateway can also be used to “hide” the organizations internal IP addresses and keep them from being recognized on a public network. A public network is one that any user may access with little or no restrictions. On private networks, hiding IP addresses allows network managers more flexibility in assigning addresses. Clients behind a gateway may use any IP addressing scheme, regardless of whether it is recognized as legitimate by the Internet authorities but as soon as those devices need to go on the internet, they must have legitimate IP addresses to exchange data. When a clients transmission reaches the default gateway, the gateway opens the IP datagram and replaces the client’s private IP address with an Internet recognized IP address. This process is known as NAT (Network Address Translation). TCP/IP Mail Services All Internet mail services rely on the same principles of mail delivery, storage, and pickup, though they may use different types of software to accomplish these functions. Email servers and clients communicate through special TCP/IP application layer protocols. These protocols, all of which operate on a variety of operating systems are discussed below… SMTP (Simple Mail transfer Protocol) The protocol responsible for moving messages from one mail server to another over TCP/IP based networks. SMTP belongs to the application layer of the ODI model and relies on TCP as its transport protocol. Operates from port 25 on the SMTP server Simple sub-protocol, incapable of doing anything more than transporting mail or holding it in a queue MIME (Multipurpose Internet Mail Extensions) The standard message format specified by SMTP allows for lines that contain no more than 1000 ascii characters meaning if you relied solely on SMTP you would have very short messages and nothing like pictures included in an email. MIME us a standard for encoding and interpreting binary files, images, video, and non-ascii character sets within an email message. MIME identifies each element of a mail message according to content type. MIME does not replace SMTP but works in conjunction with it. Most modern email clients and servers support MIME POP (Post Office Protocol) POP is an application layer protocol used to retrieve messages from a mail server POP3 relies on TCP and operates over port 110 With POP3 mail is delivered and stored on a mail server until it is downloaded by a user Disadvantage of POP3 is that it typically does not allow users to save their messages on the server because of this IMAP is sometimes used IMAP (Internet Message Access Protocol) IMAP is a retrieval protocol that was developed as a more sophisticated alternative to POP3 The single biggest advantage IMAP4 has over POP3 is that users can store messages on the mail server, rather than having to continually download them Users can retrieve all or only a portion of any mail message Users can review their messages and delete them while the messages remain on the server Users can create sophisticated methods of organizing messages on the server Users can share a mailbox in a central location Disadvantages of IMAP are typically related to the fact that it requires more storage space on the server. Additional TCP/IP Utilities Nearly all TCP/IP utilities can be accessed from the command prompt on any type of server or client running TCP/IP. The syntaxt may differ depending on the OS of the client. Below is a list of additional TCP/IP utilities – research their use on your own! Ipconfig (Windows) & Ifconfig (Linux) Netstat Nbtstat Hostname, Host & Nslookup Dig (Linux) Whois (Linux) Traceroute (Tracert) Mtr (my traceroute) Route

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  • Oracle Coherence?UCOM?IP???????SIP?????????????

    - by Norihito Yachita
    ?????????Oracle Coherence???????????????????????UCOM?IP???????SIP(Session Initiation Protocol)?????????????????????????????????? UCOM?????????????????????????????????????????IP????????????????????????????????????ISP?????????????????????????????????????????????????????????????????????????????????????????SOHO??????????????????????? UCOM??IP???????????????????SIP??????????????????????????????IP???????????????????????????Oracle Coherence??2011?2????????????????????????????????????????????????????????????????????????????????????????·????????2????????? 11?30?(?)??????????·??????·????? 2011?(??:??????)??UCOM??Oracle Coherence?????????????????????:?UCOM ????????????????????????

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  • Mutually beneficial IP/copyright clauses for contract-based freelance work

    - by Nathan de Vries
    I have a copyright section in the contract I give to my clients stating that I retain copyright on any works produced during my work for them as an independent contractor. This is most definitely not intended to place arbitrary restrictions on my clients, but rather to maintain my ability to decide on how the software I create is licensed and distributed. Almost every project I work on results in at least one part of it being released as open source. Every project I work on makes use of third-party software released in the same fashion, so returning the favour is something I would like to continue doing. Unfortunately, the contract is not so clear when it comes to defining the rights of the client in the use of said software. I mention that the code will be licensed to them, but do not mention specifics about exclusivity, ability to produce derivatives etc. As such, a client has raised concerns about the copyright section of my contract, and has suggested that I reword it such that all copyrights are transferred entirely to the client on final payment for the project. This will almost certainly reduce my ability to distribute the software I have created; I would much prefer to find a more mutually beneficial agreement where both our concerns are appeased. Are there any tried and true approaches to licensing software in this kind of situation? To summarise: I want to maintain the ability to license (parts of) the software under my own terms, independently of my relationship with the client; with some guarantee to the client that no trade-secrets or critical business logic will be shared; giving them the ability to re-use my code in their future projects; but not necessarily letting them sell it (I'm not sure about this, though...what happens if they sell their business and the software along with it?) I realise that everyone's feedback is going to be prefixed with "IANAL", however I appreciate any thoughts you might have on the matter.

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  • How to tell endianness from this output?

    - by Nick Rosencrantz
    I'm running this example program and I'm suppossed to be able to tell from the output what machine type it is. I'm certain it's from inspecting one or two values but how should I perform this inspection? /* pointers.c - Test pointers * Written 2012 by F Lundevall * Copyright abandoned. This file is in the public domain. * * To make this program work on as many systems as possible, * addresses are converted to unsigned long when printed. * The 'l' in formatting-codes %ld and %lx means a long operand. */ #include <stdio.h> #include <stdlib.h> int * ip; /* Declare a pointer to int, a.k.a. int pointer. */ char * cp; /* Pointer to char, a.k.a. char pointer. */ /* Declare fp as a pointer to function, where that function * has one parameter of type int and returns an int. * Use cdecl to get the syntax right, http://cdecl.org/ */ int ( *fp )( int ); int val1 = 111111; int val2 = 222222; int ia[ 17 ]; /* Declare an array of 17 ints, numbered 0 through 16. */ char ca[ 17 ]; /* Declare an array of 17 chars. */ int fun( int parm ) { printf( "Function fun called with parameter %d\n", parm ); return( parm + 1 ); } /* Main function. */ int main() { printf( "Message PT.01 from pointers.c: Hello, pointy World!\n" ); /* Do some assignments. */ ip = &val1; cp = &val2; /* The compiler should warn you about this. */ fp = fun; ia[ 0 ] = 11; /* First element. */ ia[ 1 ] = 17; ia[ 2 ] = 3; ia[ 16 ] = 58; /* Last element. */ ca[ 0 ] = 11; /* First element. */ ca[ 1 ] = 17; ca[ 2 ] = 3; ca[ 16 ] = 58; /* Last element. */ printf( "PT.02: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); printf( "PT.03: val2: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val2, val2, val2 ); printf( "PT.04: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.05: Dereference pointer ip and we find: %d \n", *ip ); printf( "PT.06: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.07: Dereference pointer cp and we find: %d \n", *cp ); *ip = 1234; printf( "\nPT.08: Executed *ip = 1234; \n" ); printf( "PT.09: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); printf( "PT.10: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.11: Dereference pointer ip and we find: %d \n", *ip ); printf( "PT.12: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); *cp = 1234; /* The compiler should warn you about this. */ printf( "\nPT.13: Executed *cp = 1234; \n" ); printf( "PT.14: val2: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val2, val2, val2 ); printf( "PT.15: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.16: Dereference pointer cp and we find: %d \n", *cp ); printf( "PT.17: val2: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val2, val2, val2 ); ip = ia; printf( "\nPT.18: Executed ip = ia; \n" ); printf( "PT.19: ia[0]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ia[0], ia[0], ia[0] ); printf( "PT.20: ia[1]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ia[1], ia[1], ia[1] ); printf( "PT.21: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.22: Dereference pointer ip and we find: %d \n", *ip ); ip = ip + 1; /* add 1 to pointer */ printf( "\nPT.23: Executed ip = ip + 1; \n" ); printf( "PT.24: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.25: Dereference pointer ip and we find: %d \n", *ip ); cp = ca; printf( "\nPT.26: Executed cp = ca; \n" ); printf( "PT.27: ca[0]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[0], ca[0], ca[0] ); printf( "PT.28: ca[1]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[1], ca[1], ca[1] ); printf( "PT.29: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.30: Dereference pointer cp and we find: %d \n", *cp ); cp = cp + 1; /* add 1 to pointer */ printf( "\nPT.31: Executed cp = cp + 1; \n" ); printf( "PT.32: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.33: Dereference pointer cp and we find: %d \n", *cp ); ip = ca; /* The compiler should warn you about this. */ printf( "\nPT.34: Executed ip = ca; \n" ); printf( "PT.35: ca[0]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[0], ca[0], ca[0] ); printf( "PT.36: ca[1]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[1], ca[1], ca[1] ); printf( "PT.37: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.38: Dereference pointer ip and we find: %d \n", *ip ); cp = ia; /* The compiler should warn you about this. */ printf( "\nPT.39: Executed cp = ia; \n" ); printf( "PT.40: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.41: Dereference pointer cp and we find: %d \n", *cp ); printf( "\nPT.42: fp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &fp, (long) fp, (long) fp ); printf( "PT.43: Dereference fp and see what happens.\n" ); val1 = (*fp)(42); printf( "PT.44: Executed val1 = (*fp)(42); \n" ); printf( "PT.45: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); return( 0 ); } Output Message PT.01 from pointers.c: Hello, pointy World! PT.02: val1: stored at 21e50 (hex); value is 111111 (dec), 1b207 (hex) PT.03: val2: stored at 21e54 (hex); value is 222222 (dec), 3640e (hex) PT.04: ip: stored at 21eb8 (hex); value is 138832 (dec), 21e50 (hex) PT.05: Dereference pointer ip and we find: 111111 PT.06: cp: stored at 21e6c (hex); value is 138836 (dec), 21e54 (hex) PT.07: Dereference pointer cp and we find: 0 PT.08: Executed *ip = 1234; PT.09: val1: stored at 21e50 (hex); value is 1234 (dec), 4d2 (hex) PT.10: ip: stored at 21eb8 (hex); value is 138832 (dec), 21e50 (hex) PT.11: Dereference pointer ip and we find: 1234 PT.12: val1: stored at 21e50 (hex); value is 1234 (dec), 4d2 (hex) PT.13: Executed *cp = 1234; PT.14: val2: stored at 21e54 (hex); value is -771529714 (dec), d203640e (hex) PT.15: cp: stored at 21e6c (hex); value is 138836 (dec), 21e54 (hex) PT.16: Dereference pointer cp and we find: -46 PT.17: val2: stored at 21e54 (hex); value is -771529714 (dec), d203640e (hex) PT.18: Executed ip = ia; PT.19: ia[0]: stored at 21e74 (hex); value is 11 (dec), b (hex) PT.20: ia[1]: stored at 21e78 (hex); value is 17 (dec), 11 (hex) PT.21: ip: stored at 21eb8 (hex); value is 138868 (dec), 21e74 (hex) PT.22: Dereference pointer ip and we find: 11 PT.23: Executed ip = ip + 1; PT.24: ip: stored at 21eb8 (hex); value is 138872 (dec), 21e78 (hex) PT.25: Dereference pointer ip and we find: 17 PT.26: Executed cp = ca; PT.27: ca[0]: stored at 21e58 (hex); value is 11 (dec), b (hex) PT.28: ca[1]: stored at 21e59 (hex); value is 17 (dec), 11 (hex) PT.29: cp: stored at 21e6c (hex); value is 138840 (dec), 21e58 (hex) PT.30: Dereference pointer cp and we find: 11 PT.31: Executed cp = cp + 1; PT.32: cp: stored at 21e6c (hex); value is 138841 (dec), 21e59 (hex) PT.33: Dereference pointer cp and we find: 17 PT.34: Executed ip = ca; PT.35: ca[0]: stored at 21e58 (hex); value is 11 (dec), b (hex) PT.36: ca[1]: stored at 21e59 (hex); value is 17 (dec), 11 (hex) PT.37: ip: stored at 21eb8 (hex); value is 138840 (dec), 21e58 (hex) PT.38: Dereference pointer ip and we find: 185664256 PT.39: Executed cp = ia; PT.40: cp: stored at 21e6c (hex); value is 138868 (dec), 21e74 (hex) PT.41: Dereference pointer cp and we find: 0 PT.42: fp: stored at 21e70 (hex); value is 69288 (dec), 10ea8 (hex) PT.43: Dereference fp and see what happens. Function fun called with parameter 42 PT.44: Executed val1 = (*fp)(42); PT.45: val1: stored at 21e50 (hex); value is 43 (dec), 2b (hex)

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  • How do I use ffmpeg with live streaming from an IP camera

    - by Murali Hariharan
    My question is very basic because I am a newbie to all these technologies. I have an IP camera connected to my internal network. - "http://192.168.1.20/videostream.cgi?user=admin&pwd=" gives a live streaming view in Firefox or Internet Explorer. Now I want to record the live stream into a video. The parameters to be supplied are begin_time, end_time, format of video etc. How do I accomplish this? I appreciate any guidance. Thanks Murali

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  • Determine if IP Address is Cellular IP Address

    - by CJCraft.com
    In .NET Compact Framework a device can have several IP Addresses I want to find one that is NOT coming from the Cellular connection. Goal is for WiFi or Ethernet connection. Is there a way to do this? Seems like State and Notification Broker would have a way to do this but didn't see a way.

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  • cPanel/WHM IP Ban - How to Unban IP

    - by Loren
    We are using htaccess basic authentication on one of our sites. One of our clients tried accessing the site and failed logging in multiple times. Now when visiting our site they simply get a "Can't Display Webpage" error. I believe I've had this before and I believe there IP's got banned after so many failures. I'm not sure where to go in WHM/cPanel to unban them - appreciate any assistance!! Thanks Loren

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  • One google IP address is failing. Is there a way to force a switch to different one?

    - by vaccano
    The google ip address 74.125.53.100 is failing. I know no one would believe this so I did an online ping: As this image shows one of the IP addresses for Google is failing. But there are others. If I type them in then I can get to Google just fine. But when I try to search, Google reverts back to the broken IP. Is there any way for me to say "I want to do a search with one of the working IP addresses"?

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  • Saving an IP adddress to DB

    - by Mark
    I want to save a user's IP address to my database just in case any legal issues come up and we need to track down who performed what action. Since I highly doubt I will ever actually need to use this data (well, maybe for counting unique hits or something) do you think I can just dump the REMOTE_ADDR into a field? If so, what should the length of that field be? 39 chars should fit an IPv6 address, no? I don't know if I'll ever get any of those, but just in case...

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