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  • Alphabetically Ordering an array of words

    - by Genesis
    I'm studying C on my own in preparation for my upcoming semester of school and was wondering what I was doing wrong with my code so far. If Things look weird it is because this is part of a much bigger grab bag of sorting functions I'm creating to get a sense of how to sort numbers,letters,arrays,and the like! I'm basically having some troubles with the manipulation of strings in C currently. Also, I'm quite limited in my knowledge of C at the moment! My main Consists of this: #include <stdio.h> #include <stdio.h> #include <stdlib.h> int numbers[10]; int size; int main(void){ setvbuf(stdout,NULL,_IONBF,0); //This is magical code that allows me to input. int wordNumber; int lengthOfWord = 50; printf("How many words do you want to enter: "); scanf("%i", &wordNumber); printf("%i\n",wordNumber); char words[wordNumber][lengthOfWord]; printf("Enter %i words:",wordNumber); int i; for(i=0;i<wordNumber+1;i++){ //+1 is because my words[0] is blank. fgets(&words[i], 50, stdin); } for(i=1;i<wordNumber+1;i++){ // Same as the above comment! printf("%s", words[i]); //prints my words out! } alphabetize(words,wordNumber); //I want to sort these arrays with this function. } My sorting "method" I am trying to construct is below! This function is seriously flawed, but I'd thought I'd keep it all to show you where my mind was headed when writing this. void alphabetize(char a[][],int size){ // This wont fly. size = size+1; int wordNumber; int lengthOfWord; char sortedWords[wordNumber][lengthOfWord]; //In effort for the for loop int i; int j; for(i=1;i<size;i++){ //My effort to copy over this array for manipulation for(j=1;j<size;j++){ sortedWords[i][j] = a[i][j]; } } //This should be kinda what I want when ordering words alphabetically, right? for(i=1;i<size;i++){ for(j=2;j<size;j++){ if(strcmp(sortedWords[i],sortedWords[j]) > 0){ char* temp = sortedWords[i]; sortedWords[i] = sortedWords[j]; sortedWords[j] = temp; } } } for(i=1;i<size;i++){ printf("%s, ",sortedWords[i]); } } I guess I also have another question as well... When I use fgets() it's doing this thing where I get a null word for the first spot of the array. I have had other issues recently trying to scanf() char[] in certain ways specifically spacing my input word variables which "magically" gets rid of the first null space before the character. An example of this is using scanf() to write "Hello" and getting " Hello" or " ""Hello"... Appreciate any thoughts on this, I've got all summer to study up so this doesn't need to be answered with haste! Also, thank you stack overflow as a whole for being so helpful in the past. This may be my first post, but I have been a frequent visitor for the past couple of years and it's been one of the best places for helpful advice/tips.

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  • count specific values in a multidimensional array

    - by user1680701
    I have an odd set of arrays that I need to count how many times specific values show in the results. Currently I have this bit of code. $nested_arrays = shopp_orders( '2011-11-30 00:00:00', '2012-11-30 12:59:59', false, '', 2 ); print_r($nested_arrays); This code pulls multiple arrays (serialized data) from the database and outputs like this Array ( [30] => Purchase Object ( [purchased] => Array ( ) [columns] => Array ( ) [message] => Array ( ) [data] => Array ( ) [invoiced] => [authorized] => [captured] => [refunded] => [voided] => [balance] => 0 [downloads] => [shipable] => [shipped] => [stocked] => [_position:DatabaseObject:private] => 0 [_properties:DatabaseObject:private] => Array ( ) [_ignores:DatabaseObject:private] => Array ( [0] => _ ) [_map:protected] => Array ( ) [_table] => wp_shopp_demo_shopp_purchase [_key] => id [_datatypes] => Array ( [id] => int [customer] => int [shipping] => int [billing] => int [currency] => int [ip] => string [firstname] => string [lastname] => string [email] => string [phone] => string [company] => string [card] => string [cardtype] => string [cardexpires] => date [cardholder] => string [address] => string [xaddress] => string [city] => string [state] => string [country] => string [postcode] => string [shipname] => string [shipaddress] => string [shipxaddress] => string [shipcity] => string [shipstate] => string [shipcountry] => string [shippostcode] => string [geocode] => string [promos] => string [subtotal] => float [freight] => float [tax] => float [total] => float [discount] => float [fees] => float [taxing] => list [txnid] => string [txnstatus] => string [gateway] => string [paymethod] => string [shipmethod] => string [shipoption] => string [status] => int [data] => string [secured] => string [created] => date [modified] => date ) [_lists] => Array ( [taxing] => Array ( [0] => exclusive [1] => inclusive ) ) [id] => 30 [customer] => 12 [shipping] => 23 [billing] => 23 [currency] => 0 [ip] => 24.125.58.205 [firstname] => test [lastname] => test [email] => [email protected] [phone] => 1234567890 [company] => [card] => 1111 [cardtype] => Visa [cardexpires] => 1420070400 [cardholder] => test [address] => 123 Any Street [xaddress] => [city] => Danville [state] => VA [country] => US [postcode] => 24541 [shipname] => [shipaddress] => 123 Any Street [shipxaddress] => [shipcity] => Danville [shipstate] => VA [shipcountry] => US [shippostcode] => 24541 [geocode] => [promos] => Array ( ) [subtotal] => 49.37 [freight] => 9.98 [tax] => 9.874 [total] => 69.22 [discount] => 0 [fees] => 0 [taxing] => exclusive [txnid] => [txnstatus] => authed [gateway] => TestMode [paymethod] => credit-card-test-mode [shipmethod] => ItemRates-0 [shipoption] => Fast Shipping [status] => 0 [secured] => [created] => 1354096946 [modified] => 1354096946 ) [29] => Purchase Object ( [purchased] => Array ( ) [columns] => Array ( ) [message] => Array ( ) [data] => Array ( ) [invoiced] => [authorized] => [captured] => [refunded] => [voided] => [balance] => 0 [downloads] => [shipable] => [shipped] => [stocked] => [_position:DatabaseObject:private] => 0 [_properties:DatabaseObject:private] => Array ( ) [_ignores:DatabaseObject:private] => Array ( [0] => _ ) [_map:protected] => Array ( ) [_table] => wp_shopp_demo_shopp_purchase [_key] => id [_datatypes] => Array ( [id] => int [customer] => int [shipping] => int [billing] => int [currency] => int [ip] => string [firstname] => string [lastname] => string [email] => string [phone] => string [company] => string [card] => string [cardtype] => string [cardexpires] => date [cardholder] => string [address] => string [xaddress] => string [city] => string [state] => string [country] => string [postcode] => string [shipname] => string [shipaddress] => string [shipxaddress] => string [shipcity] => string [shipstate] => string [shipcountry] => string [shippostcode] => string [geocode] => string [promos] => string [subtotal] => float [freight] => float [tax] => float [total] => float [discount] => float [fees] => float [taxing] => list [txnid] => string [txnstatus] => string [gateway] => string [paymethod] => string [shipmethod] => string [shipoption] => string [status] => int [data] => string [secured] => string [created] => date [modified] => date ) [_lists] => Array ( [taxing] => Array ( [0] => exclusive [1] => inclusive ) ) [id] => 29 [customer] => 13 [shipping] => 26 [billing] => 25 [currency] => 0 [ip] => 70.176.223.40 [firstname] => Bryan [lastname] => Crawford [email] => [email protected] [phone] => 4802323049 [company] => ggg [card] => 1111 [cardtype] => Visa [cardexpires] => 1356998400 [cardholder] => ggg [address] => 1300 W Warner Rd [xaddress] => [city] => Gilbert [state] => AZ [country] => US [postcode] => 85224 [shipname] => [shipaddress] => 1300 W Warner Rd [shipxaddress] => [shipcity] => Gilbert [shipstate] => AZ [shipcountry] => US [shippostcode] => 85224 [geocode] => [promos] => Array ( ) [subtotal] => 29.95 [freight] => 9.98 [tax] => 0 [total] => 39.93 [discount] => 0 [fees] => 0 [taxing] => exclusive [txnid] => [txnstatus] => authed [gateway] => TestMode [paymethod] => credit-card-test-mode [shipmethod] => ItemRates-0 [shipoption] => Fast Shipping [status] => 0 [secured] => [created] => 1353538691 [modified] => 1353538691 ) ) This is order data from only two orders. I need to count how many times each state, each city, shipmethod, etc occur in the array. I tried the following but it only counted the 2 large arrays. function count_nested_array_keys(array &$a, array &$res=array()) { $i = 0; foreach ($a as $key=>$value) { if (is_array($value)) { $i += count_nested_array_keys($value, &$res); } else { if(!isset($res[$key])) $res[$key] = 0; $res[$key]++; $i++; } } return $i; } $total_item_count = count_nested_array_keys($nested_arrays, $count_per_key); echo "count per key: ", print_r($count_per_key), "\n"; If someone could show me how to count how many times each state value occurs, example, VA = 2 NC = 1 I can take it from there. Thank You.

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  • Ext.data.Store, Javascript Arrays and Ext.grid.ColumnModel

    - by Michael Wales
    I am using Ext.data.Store to call a PHP script which returns a JSON response with some metadata about fields that will be used in a query (unique name, table, field, and user-friendly title). I then loop through each of the Ext.data.Record objects, placing the data I need into an array (this_column), push that array onto the end of another array (columns), and eventually pass this to an Ext.grid.ColumnModel object. The problem I am having is - no matter which query I am testing against (I have a number of them, varying in size and complexity), the columns array always works as expected up to columns[15]. At columns[16], all indexes from that point and previous are filled with the value of columns[15]. This behavior continues until the loop reaches the end of the Ext.data.Store object, when the entire arrays consists of the same value. Here's some code: columns = []; this_column = []; var MetaData = Ext.data.Record.create([ {name: 'id'}, {name: 'table'}, {name: 'field'}, {name: 'title'} ]); // Query the server for metadata for the query we're about to run metaDataStore = new Ext.data.Store({ autoLoad: true, reader: new Ext.data.JsonReader({ totalProperty: 'results', root: 'fields', id: 'id' }, MetaData), proxy: new Ext.data.HttpProxy({ url: 'index.php/' + type + '/' + slug }), listeners: { 'load': function () { metaDataStore.each(function(r) { this_column['id'] = r.data['id']; this_column['header'] = r.data['title']; this_column['sortable'] = true; this_column['dataIndex'] = r.data['table'] + '.' + r.data['field']; // This display valid information, through the entire process console.info(this_column['id'] + ' : ' + this_column['header'] + ' : ' + this_column['sortable'] + ' : ' + this_column['dataIndex']); columns.push(this_column); }); // This goes nuts at columns[15] console.info(columns); gridColModel = new Ext.grid.ColumnModel({ columns: columns });

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  • Implementing arrays using a stack

    - by Zack
    My programming language has no arrays, no lists, no pointers, no eval and no variable variables. All it has: Ordinary variables like you know them from most programming languages: They all have an exact name and a value. One stack. Functions provided are: push (add element to top), pop (remove element from top, get value) and empty (check if stack is empty) My language is turing-complete. (Basic arithmetics, conditional jumps, etc implemented) That means, it must be possible to implement some sort of list or array, right? But I have no idea how... What I want to achieve: Create a function which can retrieve and/or change an element x of the stack. I could easily add this function in the implementation of my language, in the interpreter, but I want to do it in my programming language. "Solution" one (Accessing an element x, counting from the stack top) Create a loop. Pop off the element from the stack top x times. The last element popped of is element number x. I end up with a destroyed stack. Solution two: Do the same as above, but store all popped off values in a second stack. Then you could move all elements back after you are done. But you know what? I don't have a second stack!

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  • Having trouble with extension methods for byte arrays

    - by Dave
    I'm working with a device that sends back an image, and when I request an image, there is some undocumented information that comes before the image data. I was only able to realize this by looking through the binary data and identifying the image header information inside. I've been able to make everything work fine by writing a method that takes a byte[] and returns another byte[] with all of this preamble "stuff" removed. However, what I really want is an extension method so I can write image_buffer.RemoveUpToByteArray(new byte[] { 0x42, 0x4D }); instead of byte[] new_buffer = RemoveUpToByteArray( image_buffer, new byte[] { 0x42, 0x4D }); I first tried to write it like everywhere else I've seen online: public static class MyExtensionMethods { public static void RemoveUpToByteArray(this byte[] buffer, byte[] header) { ... } } but then I get an error complaining that there isn't an extension method where the first parameter is a System.Array. Weird, everyone else seems to do it this way, but okay: public static class MyExtensionMethods { public static void RemoveUpToByteArray(this Array buffer, byte[] header) { ... } } Great, that takes now, but still doesn't compile. It doesn't compile because Array is an abstract class and my existing code that gets called after calling RemoveUpToByteArray used to work on byte arrays. I could rewrite my subsequent code to work with Array, but I am curious -- what am I doing wrong that prevents me from just using byte[] as the first parameter in my extension method?

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  • Beginner problems with references to arrays in python 3.1.1

    - by Protean
    As part of the last assignment in a beginner python programing class, I have been assigned a traveling sales man problem. I settled on a recursive function to find each permutation and the sum of the distances between the destinations, however, I am have a lot of problems with references. Arrays in different instances of the Permute and Main functions of TSP seem to be pointing to the same reference. from math import sqrt class TSP: def __init__(self): self.CartisianCoordinates = [['A',[1,1]], ['B',[2,2]], ['C',[2,1]], ['D',[1,2]], ['E',[3,3]]] self.Array = [] self.Max = 0 self.StoredList = ['',0] def Distance(self, i1, i2): x1 = self.CartisianCoordinates[i1][1][0] y1 = self.CartisianCoordinates[i1][1][1] x2 = self.CartisianCoordinates[i2][1][0] y2 = self.CartisianCoordinates[i2][1][1] return sqrt(pow((x2 - x1), 2) + pow((y2 - y1), 2)) def Evaluate(self): temparray = [] Data = [] for i in range(len(self.CartisianCoordinates)): Data.append([]) for i1 in range(len(self.CartisianCoordinates)): for i2 in range(len(self.CartisianCoordinates)): if i1 != i2: temparray.append(self.Distance(i1, i2)) else: temparray.append('X') Data[i1] = temparray temparray = [] self.Array = Data self.Max = len(Data) def Permute(self,varray,index,vcarry,mcarry): #Problem Class array = varray[:] carry = vcarry[:] for i in range(self.Max): print ('ARRAY:', array) print (index,i,carry,array[index][i]) if array[index][i] != 'X': carry[0] += self.CartisianCoordinates[i][0] carry[1] += array[index][i] if len(carry) != self.Max: temparray = array[:] for j in range(self.Max):temparray[j][i] = 'X' index = i mcarry += self.Permute(temparray,index,carry,mcarry) else: return mcarry print ('pass',mcarry) return mcarry def Main(self): out = [] self.Evaluate() for i in range(self.Max): array = self.Array[:] #array appears to maintain the same reference after each copy, resulting in an incorrect array being passed to Permute after the first iteration. print (self.Array[:]) for j in range(self.Max):array[j][i] = 'X' print('I:', i, array) out.append(self.Permute(array,i,[str(self.CartisianCoordinates[i][0]),0],[])) return out SalesPerson = TSP() print(SalesPerson.Main()) It would be greatly appreciated if you could provide me with help in solving the reference problems I am having. Thank you.

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  • PHP - Counting matching arrays in array

    - by Sergio
    hi there, I have an array structure that looks like this: Array ( [0] => Array ( [type] => image [data] => Array ( [id] => 1 [alias] => test [caption] => no caption [width] => 200 [height] => 200 ) ) [1] => Array ( [type] => image [data] => Array ( [id] => 2 [alias] => test2 [caption] => hello there [width] => 150 [height] => 150 ) ) ) My question is, how can I get a count of the number of embedded arrays that have their type set as image (or anything else for that matter)? In practise this value can vary. So, the above array would give me an answer of 2. Thanks

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  • Storing arrays in NSUserDefaultsController

    - by neoneye
    Currently I use NSUserDefaults and I'm interested in using NSUserDefaultsController, so that I get notifications when things change. Below is my current code. items = /* NSArray of MYItem's */; NSData* data = [NSKeyedArchiver archivedDataWithRootObject:items]; [[NSUserDefaults standardUserDefaults] setObject:data forKey:kMYItems]; How should I rework my code to store items in NSUserDefaultsController ? Is NSKeyedArchiver the smartest way to store arrays? @interface MYItem : NSObject <NSCoding> { NSString* name; NSString* path; } @property (copy) NSString* name; @property (copy) NSString* path; @end @implementation MYItem @synthesize name, path; -(void)encodeWithCoder:(NSCoder*)coder { [coder encodeObject:name forKey:@"name"]; [coder encodeObject:path forKey:@"path"]; } -(id)initWithCoder:(NSCoder*)coder { [super init]; [self setName:[coder decodeObjectForKey:@"name"]]; [self setPath:[coder decodeObjectForKey:@"path"]]; return self; } @end

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  • AutoMapper and flattening nested arrays

    - by Bryan Slatner
    I'm trying to use AutoMapper to flatten multiple levels of arrays. Consider the following source classes: class X { public string A { get; set; } public Y[] B { get; set; } } class Y { public string C { get; set; } public Z[] D { get; set; } } class Z { public string E { get; set; } public string F { get; set; } } And the following destination: class Destination { public string A { get; set; } public string C { get; set; } public string E { get; set; } public string F { get; set; } } What I'd like to be able to do is get a List from one or more X, e.g.: Mapper.Map<IEnumerable<X>, IEnumerable<Destination>>(arrayOfX); I'm unable to figure out what sort of mapping configuration to use to achieve this. MapFrom seems like the way to go for 1:1 compositions, but doesn't seem to be able to handle the array (or other enumerable) unless I use AutoMapper's destination naming convention. Any insights on how to achieve this?

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  • Printing Arrays from Structs

    - by Carlll
    I've been stumped for a few hours on an exercise where I must use functions to build up an array inside a struct and print it. In my current program, it compiles but crashes upon running. #define LIM 10 typedef char letters[LIM]; typedef struct { int counter; letters words[LIM]; } foo; int main(int argc, char **argv){ foo apara; structtest(apara, LIM); print_struct(apara); } int structtest(foo *p, int limit){ p->counter = 0; int i =0; for(i; i< limit ;i++){ strcpy(p->words[p->counter], "x"); //only filling arrays with 'x' as an example p->counter ++; } return; I do believe it's due to my incorrect usage/combination of pointers. I've tried adjusting them, but either an 'incompatible types' error is produced, or the array is seemingly blank } void print_struct(foo p){ printf(p.words); } I haven't made it successfully up to the print_struct stage, but I'm unsure whether p.words is the correct item to be calling. In the output, I would expect the function to return an array of x's. I apologize in advance if I've made some sort of grievous "I should already know this" C mistake. Thanks for your help.

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  • Rewrite arrays using collections

    - by owca
    I have a task, which I was able to do with the use of simplest methods - arrays. Now I'd like to go further and redo it using some more complicated java features like collections, but I've never used anything more complicated than 2d matrix. What should I look at and how to start with it. Should Tower become a Collection ? And here's the task : We have two classes - Tower and Block. Towers are built from Blocks. Ande here's sample code for testing: Block k1=new Block("yellow",1,5,4); Block k2=new Block("blue",2,2,6); Block k3=new Block("green",3,4,2); Block k4=new Block("yellow",1,5,4); Tower tower=new Tower(); tower.add(k1,k2,k3); "Added 3 blocks." System.out.println(tower); "block: green, base: 4cm x 3cm, thicknes: 2 cm block: blue, base: 6cm x 2cm, thicknes: 2 cm block: yellow, base: 5cm x 4cm, thicknes: 1 cm" tower.add(k2); "Tower already contains this block." tower.add(k4); "Added 1 block." System.out.println(tower); "block: green, base: 4cm x 3cm, thicknes: 2 cm block: blue, base: 6cm x 2cm, thicknes: 2 cm block: yellow, base: 5cm x 4cm, thicknes: 1 cm block: yellow, base: 5cm x 4cm, thicknes: 1 cm" tower.delete(k1); "Deleted 1 block" tower.delete(k1); "Block not in tower" System.out.println(tower); "block: blue, base: 6cm x 2cm, thicknes: 2 cm block: yellow, base: 5cm x 4cm, thicknes: 1 cm block: yellow, base: 5cm x 4cm, thicknes: 1 cm" Let's say I will treat Tower as a collection of blocks. How to perform search for specific block among whole collection ? Or should I use other interface ?

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  • Java OutOfMemoryError message changes when trying to create Arrays of different sizes

    - by Gordon
    In the question by DKSRathore How to simulate the Out Of memory : Requested array size exceeds VM limit some odd behavior was noted when creating an arrays. When creating an array of size Integer.MAX_VALUE an exception with the error java.lang.OutOfMemoryError Requested array size exceeds VM limit was thrown. However when an array was created with a size less than the max but still above the virtual machine memory limit the error message read java.lang.OutOfMemoryError: Java heap space. Testing further I managed to narrow down where the error messages changes. long[] l = new long[2147483645]; exceptions message reads - Requested array size exceeds VM limit long[] l = new long[2147483644]; exceptions message reads - Java heap space errors I increased my virtual machine memory and still produced the same result. Has anyone any idea why this happens? Some extra info: Integer.MAX_VALUE = 2147483647. Edit: Here's the code I used to find the value, might be helpful. int max = Integer.MAX_VALUE; boolean done = false; while (!done) { try { max--; // Throws an error long[] l = new long[max]; // Exit if an error is no longer thrown done = true; } catch (OutOfMemoryError e) { if (!e.getMessage().contains("Requested array size exceeds VM limit")) { System.out.println("Message changes at " + max); done = true; } } }

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  • joining / merging two arrays

    - by Shishant
    I have two arrays like this, actually this is mysql data retrieved from two different servers: $array1 = array ( 0 => array ( 'id' => 1, 'name' => 'somename') , 1 => array ( 'id' => 2, 'name' => 'somename2') ); $array2 = array ( 0 => array ( 'thdl_id' => 1, 'otherdate' => 'spmethings') , 1 => array ( 'thdl_id' => 2, 'otherdate' => 'spmethings22') ); how can i join / merge array so it looks like this $new_array = array ( 0 => array ( 'id' => 1, 'name' => 'somename', 'otherdate' => 'spmethings') , 1 => array ( 'id' => 2, 'name' => 'somename2', 'otherdate' => 'spmethings22') );

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  • Algorithm to produce Cartesian product of arrays in depth-first order

    - by Yuri Gadow
    I'm looking for an example of how, in Ruby, a C like language, or pseudo code, to create the Cartesian product of a variable number of arrays of integers, each of differing length, and step through the results in a particular order: So given, [1,2,3],[1,2,3],[1,2,3]: [1, 1, 1] [2, 1, 1] [1, 2, 1] [1, 1, 2] [2, 2, 1] [1, 2, 2] [2, 1, 2] [2, 2, 2] [3, 1, 1] [1, 3, 1] etc. Instead of the typical result I've seen (including the example I give below): [1, 1, 1] [2, 1, 1] [3, 1, 1] [1, 2, 1] [2, 2, 1] [3, 2, 1] [1, 3, 1] [2, 3, 1] etc. The problem with this example is that the third position isn't explored at all until all combinations of of the first two are tried. In the code that uses this, that means even though the right answer is generally (the much larger equivalent of) 1,1,2 it will examine a few million possibilities instead of just a few thousand before finding it. I'm dealing with result sets of one million to hundreds of millions, so generating them and then sorting isn't doable here and would defeat the reason for ordering them in the first example, which is to find the correct answer sooner and so break out of the cartesian product generation earlier. Just in case it helps clarify any of the above, here's how I do this now (this has correct results and right performance, but not the order I want, i.e., it creates results as in the second listing above): def cartesian(a_of_a) a_of_a_len = a_of_a.size result = Array.new(a_of_a_len) j, k, a2, a2_len = nil, nil, nil, nil i = 0 while 1 do j, k = i, 0 while k < a_of_a_len a2 = a_of_a[k] a2_len = a2.size result[k] = a2[j % a2_len] j /= a2_len k += 1 end return if j > 0 yield result i += 1 end end UPDATE: I didn't make it very clear that I'm after a solution where all the combinations of 1,2 are examined before 3 is added in, then all 3 and 1, then all 3, 2 and 1, then all 3,2. In other words, explore all earlier combinations "horizontally" before "vertically." The precise order in which those possibilities are explored, i.e., 1,1,2 or 2,1,1, doesn't matter, just that all 2 and 1 are explored before mixing in 3 and so on.

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  • Wrappers of primitive types in arraylist vs arrays

    - by ismail marmoush
    Hi, In "Core java 1" I've read CAUTION: An ArrayList is far less efficient than an int[] array because each value is separately wrapped inside an object. You would only want to use this construct for small collections when programmer convenience is more important than efficiency. But in my software I've already used Arraylist instead of normal arrays due to some requirements, though "The software is supposed to have high performance and after I've read the quoted text I started to panic!" one thing I can change is changing double variables to Double so as to prevent auto boxing and I don't know if that is worth it or not, in next sample algorithm public void multiply(final double val) { final int rows = getSize1(); final int cols = getSize2(); for (int i = 0; i < rows; i++) { for (int j = 0; j < cols; j++) { this.get(i).set(j, this.get(i).get(j) * val); } } } My question is does changing double to Double makes a difference ? or that's a micro optimizing that won't affect anything ? keep in mind I might be using large matrices.2nd Should I consider redesigning the whole program again ?

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  • PHP: visual difference between 2 arrays

    - by Paulo Freitas
    I've these arrays: <?php // New $array1 = array( array( 'g_id' => '1', 'g_title' => 'Root Admin', 'g_perm_id' => '1', 'g_bitoptions' => '0' ), array( 'g_id' => '2', 'g_title' => 'Member', 'g_perm_id' => '2', 'g_bitoptions' => '32' ), array( 'g_id' => '3', 'g_title' => 'Banned', 'g_perm_id' => '3', 'g_bitoptions' => '0' ) ); // Old $array2 = array( array( 'g_id' => '1', 'g_title' => 'Admin', 'g_perm_id' => '1', 'g_bitoptions' => '0' ), array( 'g_id' => '2', 'g_title' => 'User', 'g_perm_id' => '2', 'g_bitoptions' => '0' ), array( 'g_id' => '4', 'g_title' => 'Validating', 'g_perm_id' => '4', 'g_bitoptions' => '0' ) ); What I'm want is an HTML visual difference between them, like this picture: http://img519.imageshack.us/i/diffe.png/ Anyone here knows any 3rd party class that do this? I've been looking at some but none of them had it. =/ Thank you in advance.

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  • Animate and form rows, arrays, AS3

    - by VideoDnd
    Question How can I animate and form rows together? Explanation One 'for loop' is for animation, the other 'for loop' is for making rows. I want to understand how to use arrays and create a row of sprite animations. 'for loop' for animation //FRAMES ARRAY //THIS SETS UP MY ANIMATION FOR TIMER EVENT var frames:Array = [ new Frame1(), new Frame2(), new Frame3(), new Frame4(), new Frame5(), new Frame6(), new Frame7(), new Frame8(), new Frame9(), new Frame0(), ]; for each (var frame:Sprite in frames) { addChild(frame); } 'for loop' for rows //THIS MAKES A ROW OF DISPLAY OBJECTS var numberOfClips:Number = 11; var xStart:Number = 0; var yStart:Number = 0; var xVal:Number = xStart; var xOffset:Number = 2; for (var $:Number=0; $<numberOfClips; $++) { //DUDE ARRAY var dude:Array = frames; dude.y = yStart +11; dude.x = xVal +55; xVal = dude.x + dude.width + this.xOffset; } timer var timer:Timer = new Timer(100); timer.addEventListener(TimerEvent.TIMER, countdown); function countdown(event:TimerEvent) { var currentFrame:int = timer.currentCount % frames.length; for (var i:int = 0; i < frames.length; ++i) { frames[i].visible = (i == currentFrame); } } timer.start(); counter experiment My new class I'm working on loops through 10 different display objects that are numbers. For those following, I'm trying to make something like NumbersView.

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  • str_replace() and strpos() for arrays?

    - by Josh
    I'm working with an array of data that I've changed the names of some array keys, but I want the data to stay the same basically... Basically I want to be able to keep the data that's in the array stored in the DB, but I want to update the array key names associated with it. Previously the array would have looked like this: $var_opts['services'] = array('foo-1', 'foo-2', 'foo-3', 'foo-4'); Now the array keys are no longer prefixed with "foo", but rather with "bar" instead. So how can I update the array variable to get rid of the "foos" and replace with "bars" instead? Like so: $var_opts['services'] = array('bar-1', 'bar-2', 'bar-3', 'bar-4'); I'm already using if(isset($var_opts['services']['foo-1'])) { unset($var_opts['services']['foo-1']); } to get rid of the foos... I just need to figure out how to replace each foo with a bar. I thought I would use str_replace on the whole array, but to my dismay it only works on strings (go figure, heh) and not arrays.

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  • How to combine these two PHP arrays ?

    - by Annan
    I have two arrays in php that are part of an image management system. weighted_images A multidimensional array. Each sub array is an associative array with keys of 'weight' (for ordering by) and 'id' (the id of the image). array( 156 => array('weight'=>1, 'id'=>156), 784 => array('weight'=>-2, 'id'=>784), ) images This array is user input. It's an array of image ids. array(784, 346, 748) I want to combine them in to a single array of ids ordered by the weight of the image. If an image doesn't have a weight append to the end. It's not a particularly hard problem however my solution is far from elegant and can't help thinking that there must be a better way to do this. $t_images = array(); foreach ($weighted_images as $wi) { if ( in_array($wi['id'], $images) ) { $t_images[$wi['weight']] = $wi['id']; } } foreach ($images as $image) { if ( !$weighted_images[$image] ) { $t_images[] = $image; } } $images = $t_images; Question: Is there a better way to do this?

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  • Ruby 1.9: turn these 4 arrays into hash of key/value pairs

    - by randombits
    I have four arrays that are coming in from the client. Let's say that there is an array of names, birth dates, favorite color and location. The idea is I want a hash later where each name will have a hash with respective attributes: Example date coming from the client: [name0, name1, name2, name3] [loc0, loc1] [favcololor0, favcolor1] [bd0, bd1, bd2, bd3, bd4, bd5] Output I'd like to achieve: name0 => { location => loc0, favcolor => favcolor0, bd => bd0 } name1 => { location => loc1, favcolor => favcolor1, bd => bd1 } name2 => { location => nil, favcolor => nil, bd => bd2 } name3 => { location => nil, favcolor => nil, bd => bd3 } I want to have an array at the end of the day where I can iterate and work on each particular person hash. There need not be an equivalent number of values in each array. Meaning, names are required.. and I might receive 5 of them, but I only might receive 3 birth dates, 2 favorite colors and 1 location. Every missing value will result in a nil. How does one make that kind of data structure with Ruby 1.9?

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  • Intelligent Merge of two Arrays (3-way-kindof)

    - by simon.oberhammer
    I have to Arrays, each represents a list of Stories. Two users can concurrently modify the order, add or remove Stories, and I want those changes merged. An example should make this clearer Orignial 1,2,3,4,5 UserA (mine) 3,1,2,4,5 (moved story 3 to start) UserB (theirs) 1,2,3,5,4 (moved story 5 forward) The result of the above should be Merge (result) 3,1,2,5,4 In case of conflicts, UserA should always win. I came pretty far with this simple approach. First i deleted whatever mine says i should deleted (that part of the code is not shown, it's trivial), then I iterate of mine, inserting and moving from theirs what is needed (mstories = mine, tstories = theirs): var offset = 0; for (var idx=0;idx<mstories.length;idx++) { var storyId = mstories[idx]; // new story in theirs if (mstories.indexOf(tstories[idx]) == -1) { mstories.splice(idx+1, 0, tstories[idx]); idx--; continue; } // new story in mine? if (tstories.indexOf(storyId) == -1) { tstories.splice(idx+offset, 0, storyId); offset += 1; // story moved } else if (tstories.indexOf(storyId) != idx + offset) { tstories.splice(tstories.indexOf(storyId), 1); tstories.splice(idx+offset, 0, storyId); } } It's close, but it gets confused when too many Stories are moved to the front / back with Stories in between, which the other User touched. I have an extended version which does checks on the original and is smarter - holding 2 offsets, etc - , but I feel like this is a problem that must have a) a name b) a perfect solution and i don't want to re-invent it.

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  • Arrays (toString) not output correctly

    - by DiscoDude
    Hello, Actually this tread is continuing from the other one. There wasn't enough characters to continue there. Anyway. the problem is that the output is "1(10) 2(23) 3(29)". Even though I could return string for the array values (10,23,29) and used string reference as 1, 2 and 3. My question is it possible to return index values 1,2,3 and as well as array values. Am I making an sense. Here is what I have done... // int[] groups = {10, 23, 29}; in the constructor String tempA = ""; String tempB = " "; int[] temp = new int[4]; int length = groups.length; for (int j = 0; j < length; j++) { temp[j] = groups[j]; tempB = tempB + "("+goups+")"; } groups = temp; Arrays.sort(coingroups); for(int i = 1; i < groups.length;i++) { tempA = tempA+" "+(i)+ "("+groups[i]+")"; } return tempA;

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  • Language-agnostic term for typed things that need memory

    - by FredOverflow
    Is there an accepted general term that subsumes the concepts of variables, class instances and arrays? Basically "any typed thing that needs memory". In C++, such a thing is called an object, but I'm looking for a more language-agnostic term. § 1.8 The C++ object model 1 The constructs in a C++ program create, destroy, refer to, access, and manipulate objects. An object is a region of storage. [...] An object can have a name (Clause 3). An object has a storage duration (3.7) which influences its lifetime (3.8). An object has a type (3.9).

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  • Return a pointer to a char array in C

    - by snitko
    I've seen a lot of questions on that on StackOverflow, but reading the answers did not clear that up for me, probably because I'm a total newbie in C programming. Here's the code: #include <stdio.h> char* squeeze(char s[], char c); main() { printf("%s", squeeze("hello", 'o')); } char* squeeze(char s[], char c) { int i, j; for(i = j = 0; s[i] != '\0'; i++) if(s[i] != c) s[j++] = s[i]; s[j] = '\0'; return s; } It compiles and I get segmentation fault when I run it. I've read this faq about about returning arrays and tried the 'static' technique that is suggested there, but still could not get the program working. Could anyone point out exactly what's wrong with it and what should I be paying attention in the future?

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  • How do I create an empty array/matrix in NumPy?

    - by Ben
    I'm sure I must be being very dumb, but I can't figure out how to use an array or matrix in the way that I would normally use a list. I.e., I want to create an empty array (or matrix) and then add one column (or row) to it at a time. At the moment the only way I can find to do this is like: mat = None for col in columns: if mat is None: mat = col else: mat = hstack((mat, col)) Whereas if it were a list, I'd do something like this: list = [] for item in data: list.append(item) Is there a way to use that kind of notation for NumPy arrays or matrices? (Or a better way -- I'm still pretty new to python!)

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