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  • How to use DAOs with hibernate/jpa?

    - by Ari
    Assuming the DAO structure and component interaction described below, how should DAOs be used with persistence layers like hibernate and toplink? What methods should/shouldn't they contain? Would it be bad practice to move the code from the DAO directly to the service? For example, let's say that for every model we have a DAO (that may or may not implement a base interface) that looks something like the following: public class BasicDao<T> { public List<T> list() { ... } public <T> retrieve() { ... } public void save() { ... } public void delete() { ... } } Component interaction pattern is -- service DAO model

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  • JPA/Hibernate query with class name?

    - by Petteri Hietavirta
    In this example com.test.Cat extends com.test.Animal and there is no field DB in CAT table of com.test.Cat explicitly defining its type (it wasn't me). When I query my animals from DB I get a collection of Animals. It is possible to sort them by class name: order by r.class but is there a way to use class name as a criteria? For example I would like to get all animals expect dogs. But no luck - even this does not work: where r.class = ? (String "ccc.test.Cat") as I get an exception: Caused by: java.lang.ClassCastException: java.lang.String cannot be cast to java.lang.Integer at org.hibernate.type.IntegerType.set(IntegerType.java:64) at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:154) at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:136) at org.hibernate.param.PositionalParameterSpecification.bind(PositionalParameterSpecification.java:62) at org.hibernate.loader.hql.QueryLoader.bindParameterValues(QueryLoader.java:514) at org.hibernate.loader.Loader.prepareQueryStatement(Loader.java:1589) at org.hibernate.loader.Loader.doQuery(Loader.java:696) at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:259) at org.hibernate.loader.Loader.doList(Loader.java:2228) at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2125) at org.hibernate.loader.Loader.list(Loader.java:2120) at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:401) at org.hibernate.hql.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:361) at org.hibernate.engine.query.HQLQueryPlan.performList(HQLQueryPlan.java:196) at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1148) at org.hibernate.impl.QueryImpl.list(QueryImpl.java:102) at org.hibernate.ejb.QueryImpl.getResultList(QueryImpl.java:67)

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  • app engine jpa N-way joins ?

    - by cometta
    may i know is the latest version of jgae support N-way joins? or still limit to 2-way join? reference: http://gae-java-persistence.blogspot.com/2010/03/executing-simple-joins-across-owned.html?showComment=1276491851890_AIe9_BEqp-CCn0bibiOUY8JUbbSFwFE02aF9d68baX0squIcfBnve8K3iIT3IEhPhpJxEBSZQLlz8tH-NMq1XGzOV0fAA8othN4f3zhR2B6xN0WzsTRpyEZJl2vPDonhVY38iUhJGe8Ot9URs3IjYk4HoH9LG41az7l0blTBNNnpJuyI-xl5CDJGoPLGk5jw4tLvtvsCYhq3n7XuiZwJIaBMWjHSDdy7-fB1NYszI0G4f9JRjZ5UdDM4at3o3tAhd-CYK2Af1dnG#c3679507832415682306

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  • How to handle choice field with JPA 2, Hibernate 3.5

    - by phmr
    I have an entity with Integer attributes that looks like this in proto code: class MyEntity: String name Integer frequency Integer type def getFrequency() def getType() get* accessors return strings according to this table. value(type) HumanReadableString(type) 1 BSD 2 Apache 3 GPL min frequency max frequency HumanReadableString(frequency) 0 1000 rare 1000 2000 frequent 2001 3000 sexy It should be possible to get all possible values that an attribute can take, example: getChoices(MyEntity, "type") returns ("rare", "frequent", "sexy") It should be possible to get the bound value from the string: getValue(MyEntity, "frequency", "sexy") returns (2000,3000)

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  • one to many jpa relationship

    - by user309944
    Hai I have created two table first table as student package com.crimson.rship; import javax.persistence.Basic; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.Id; import javax.persistence.OneToMany; @Entity(name="student") public class student { @Id private String stumailid; @Basic private String fathername; @Basic private String mothername; @Basic private String doa; @Basic private String dob; public student(String stumailid,String fathername,String mothername,String doa,String dob) { // TODO Auto-generated constructor stub this.stumailid=stumailid; this.fathername=fathername; this.mothername=mothername; this.doa=doa; this.dob=dob; } public void setStumailid(String stumailid) { this.stumailid = stumailid; } public String getStumailid() { return stumailid; } public void setFathername(String fathername) { this.fathername = fathername; } public String getFathername() { return fathername; } public void setMothername(String mothername) { this.mothername = mothername; } public String getMothername() { return mothername; } public void setDoa(String doa) { this.doa = doa; } public String getDoa() { return doa; } public void setDob(String dob) { this.dob = dob; } public String getDob() { return dob; } } Second table as mark package com.crimson.rship; import java.util.Collection; import javax.persistence.Basic; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.OneToMany; @Entity(name="mark") public class mark { @Id private String stumailid; @Basic private String fathername; @Basic private String mothername; @OneToMany(mappedBy="mark",targetEntity=student.class,fetch=FetchType.EAGER) private Collection orders; public mark(String stumailid,String fathername,String mothername) { // TODO Auto-generated constructor stub this.stumailid=stumailid; this.fathername=fathername; this.mothername=mothername; } public void setStumailid(String stumailid) { this.stumailid = stumailid; } public String getStumailid() { return stumailid; } public void setFathername(String fathername) { this.fathername = fathername; } public String getFathername() { return fathername; } public void setMothername(String mothername) { this.mothername = mothername; } public String getMothername() { return mothername; } public void setOrders(Collection orders) { this.orders = orders; } public Collection getOrders() { return orders; } } But this above coding working is not working correctly.can any one help me Thanks in advance

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  • The best JSF coding pattern for editing JPA entities using @RequestScoped only

    - by AlanObject
    I am in a project where I will write a lot of pages like this, so I want to use the most efficient (to write) coding pattern. Background: In the past I have used CODI's @ViewAccessScoped to preserve state between requests, and more recently I have started using flash scoped objects to save state. I can't use JSF @ViewScoped because I use CDI and they don't play well together. So I want to see if I can do this with only @RequestScoped backing beans. The page is designed like this (the p namespace is Primefaces): <f:metadata> <f:viewParam name="ID" value="#{backing.id}" /> </f:metadata> .... <h1>Edit Object Page</h1> <h:form id="formObj" rendered="#{backing.accessOK}"> <p:panelGrid columns="2"> <h:outputLabel value="Field #1:"/> <p:inputText value="#{backing.record.field1}" /> (more input fields) <h:outputLabel value="Action:" /> <h:panelGroup> <p:commandButton value="Save" action="#{backing.save}" /> <p:commandButton value="Cancel" action="backing.cancel" /> </h:panelGroup> </p:panelGrid> <p:messages showDetail="true" showSummary="true" /> </h:form> If the page is requested, the method accessOK() has the ability to keep the h:form from being rendered. Instead, the p:messages is shown with whatever FacesMessage(s) the accessOK() method cares to set. The pattern for the bean backing looks like this: @Named @RequestScoped public class Backing { private long id; private SomeJPAEntity record; private Boolean accessOK; public long getId() { return id; } public void setId(long value) { id = value; } public boolean accessOK() { if (accessOK != null) return accessOK; if (getRecord() == null) { // add a FacesMessage that explains the record // does not exist return accessOK = false; // note single = } // do any other access checks, such as write permissions return accessOK = true; } public SomeJPAEntity getRecord() { if (record != null) return record; if (getId() > 0) record = // get the record from DB else record = new SomeJPAEntity(); return record; } public String execute() { if (!accessOK()) return null; // bad edit // do other integrity checks here. If fail, set FacesMessages // and return null; if (getId() > 0) // merge the record back into the data base else // persist the record } } Here is what goes wrong with this model. When the Save button is clicked, a new instance of Backing is built, and then there are a lot of calls to the getRecord() getter before the setID() setter is called. So the logic in getRecord() breaks because it cannot rely on the id property being valid when it is called. When this was a @ViewAccessScoped (or ViewScoped) backing bean, then both the id and record properties are already set when the form is processed with the commandButton. Alternatively you can save those properties in flash storage but that has its own problems I want to avoid. So is there a way to make this programming model work within the specification?

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  • Mysql maven jpa skeleton

    - by coubeatczech
    Hi, is there a skeleton for a project using mysql, some eclipse/top link with RESOURCE_LOCAL as connection type? Preferably using maven. I'm searching for it for hours and can't get running even the sipmlest exaple. So if you had it ready and running, please, post :-). Even something as simple as these two classes only. @Entity public class Message implements Serializable{ public Message() {} public Message(String s){ this.s = s; } @Id String s; public String getS(){ return s; } } public class App { static private EntityManagerFactory emf; static private EntityManager em; public static void main( String[] args ) { emf = Persistence.createEntityManagerFactory("persistence"); em = emf.createEntityManager(); Message m = new Message("abc"); em.persist(m); } }

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  • Hibernate (JPA) Entity with Static collection as a member

    - by Kyle Partridge
    Is it possible to have a static collection as a member of a hibernate entity? Say I have an object Question: public class Question { private String category; ... } Would it be possible to populate a static Set<String> that is a distinct set of all categories in the Database? I know I could just query this, but I was wondering if there was a more elegant solution, as it seems like something that other people may have come across.

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  • Java EE 7 support in Eclipse 4.3

    - by arungupta
    Eclipse Kepler (4.3) features 71 different open source projects and over 58 million LOC. One of the main themes of the release is the support for Java EE 7. Kepler specifically added support for the features mentioned below: Create Java EE 7 Eclipse projects or using Maven New facets for JPA 2.1, JSF 2.2, Servlet 3.1, JAX-RS 2.0, EJB 3.2 Schemas and descriptors updated for Java EE 7 standards (web.xml, application.xml, ejb-jar.xml, etc) Tolerance for JPA 2.1 such as features can be used without causing invalidation and content assist for UI (JPA 2.1) Support for NamedStoredProcedureQuery (JPA 2.1) Schema generation configuration in persistence.xml (JPA 2.1) Updates to persistence.xml editor with the new JPA 2.1 properties Existing features support EE7 (Web Page Editor, Palette, EL content assist, annotations, JSF tags, Facelets, etc) Code generation wizards tolerant of EE7 (New EJB, Servlet, JSP, etc.) A comprehensive list of features added in this release is available in Web Tools Platform 3.5 - New and Noteworthy. Download Eclipse 4.3 and Java EE 7 SDK and start playing with Java EE 7! Oracle Enterprise Pack for Eclipse was released recently that uses Eclipse Kepler RC3 but will be refreshed soon to include the final bits.

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  • JPQL IN clause: Java-Arrays (or Lists, Sets...)?

    - by Bernd Haug
    I would like to load all objects that have a textual tag set to any of a small but arbitrary number of values from our database. The logical way to go about this in SQL would be to build an "IN" clause. JPQL allows for IN, but it seems to require me to specify every single parameter to IN directly (as in, "in (:in1, :in2, :in3)"). Is there some way to specify an array, or a list (or some other container) that should be unrolled to the values of an IN clause?

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  • No Persistence provider for EntityManager named ...

    - by Robert A Henru
    I have my persistence.xml with the same name, using toplink, under META-INF directory. Then I have my code calling it with... EntityManagerFactory emfdb = Persistence.createEntityManagerFactory("agisdb"); Yet, I got the following error message 2009-07-21 09:22:41,018 [main] ERROR - No Persistence provider for EntityManager named agisdb javax.persistence.PersistenceException: No Persistence provider for EntityManager named agisdb at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:89) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:60) Here is the persistence.xml... <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" version="1.0"> <persistence-unit name="agisdb"> <class>com.agis.livedb.domain.AddressEntity</class> <class>com.agis.livedb.domain.TrafficCameraEntity</class> <class>com.agis.livedb.domain.TrafficPhotoEntity</class> <class>com.agis.livedb.domain.TrafficReportEntity</class> <properties> <property name="toplink.jdbc.url" value="jdbc:mysql://localhost:3306/agisdb"/> <property name="toplink.jdbc.driver" value="com.mysql.jdbc.Driver"/> <property name="toplink.jdbc.user" value="root"/> <property name="toplink.jdbc.password" value="password"/> </properties> </persistence-unit> </persistence> It should have been in the classpath... Yet, I got the above error... Really appreciate any help... Thanks

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  • JPQL cross tab query

    - by Phil
    Hi can anyone tell me if its possible to write a cross tab query in JPQL? (I'm using eclipse link JPA2) An example of a cross tab query in SQL can found here http://onlamp.com/pub/a/onlamp/2003/12/04/crosstabs.html SELECT dept, COUNT(CASE WHEN gender = 'm' THEN id ELSE NULL END) AS m, COUNT(CASE WHEN gender = 'f' THEN id ELSE NULL END) AS f, COUNT(*) AS total FROM person GROUP BY dept How can I do the same thing as a single query in JPQL? Looking at the spec it doesn't seem to look like CASE is valid in COUNT Is there any other way?

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  • Can't get running JPA2 with Hibernate and Maven

    - by erlord
    Have been trying the whole day long and googled the ** out of the web ... in vain. You are my last hope: Here's my code: The Entity: package sas.test.model; import javax.persistence.Entity; import javax.persistence.Id; @Entity public class Employee { @Id private int id; private String name; private long salary; public Employee() {} public Employee(int id) { this.id = id; } public int getId() { return id; } public void setId(int id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } public long getSalary() { return salary; } public void setSalary (long salary) { this.salary = salary; } } The service class: package sas.test.dao; import sas.test.model.Employee; import javax.persistence.*; import java.util.List; public class EmployeeService { protected EntityManager em; public EmployeeService(EntityManager em) { this.em = em; } public Employee createEmployee(int id, String name, long salary) { Employee emp = new Employee(id); emp.setName(name); emp.setSalary(salary); em.persist(emp); return emp; } public void removeEmployee(int id) { Employee emp = findEmployee(id); if (emp != null) { em.remove(emp); } } public Employee raiseEmployeeSalary(int id, long raise) { Employee emp = em.find(Employee.class, id); if (emp != null) { emp.setSalary(emp.getSalary() + raise); } return emp; } public Employee findEmployee(int id) { return em.find(Employee.class, id); } } And the main class: package sas.test.main; import javax.persistence.*; import java.util.List; import sas.test.model.Employee; import sas.test.dao.EmployeeService; public class ExecuteMe { public static void main(String[] args) { EntityManagerFactory emf = Persistence.createEntityManagerFactory("EmployeeService"); EntityManager em = emf.createEntityManager(); EmployeeService service = new EmployeeService(em); // create and persist an employee em.getTransaction().begin(); Employee emp = service.createEmployee(158, "John Doe", 45000); em.getTransaction().commit(); System.out.println("Persisted " + emp); // find a specific employee emp = service.findEmployee(158); System.out.println("Found " + emp); // find all employees // List<Employee> emps = service.findAllEmployees(); // for (Employee e : emps) // System.out.println("Found employee: " + e); // update the employee em.getTransaction().begin(); emp = service.raiseEmployeeSalary(158, 1000); em.getTransaction().commit(); System.out.println("Updated " + emp); // remove an employee em.getTransaction().begin(); service.removeEmployee(158); em.getTransaction().commit(); System.out.println("Removed Employee 158"); // close the EM and EMF when done em.close(); emf.close(); } } Finally my confs. pom.xml: <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>Test_JPA_CRUD</groupId> <artifactId>Test_JPA_CRUD</artifactId> <packaging>jar</packaging> <version>1.0</version> <name>Test_JPA_CRUD</name> <url>http://maven.apache.org</url> <repositories> <repository> <id>maven2-repository.dev.java.net</id> <name>Java.net Repository for Maven</name> <url>http://download.java.net/maven/2/ </url> <layout>default</layout> </repository> <repository> <id>maven.org</id> <name>maven.org Repository</name> <url>http://repo1.maven.org/maven2</url> <releases> <enabled>true</enabled> </releases> <snapshots> <enabled>true</enabled> </snapshots> </repository> </repositories> <dependencies> <dependency> <groupId>junit</groupId> <artifactId>junit</artifactId> <version>4.8.1</version> <scope>test</scope> </dependency> <!-- <dependency> <groupId>javax</groupId> <artifactId>javaee-api</artifactId> <version>6.0</version> </dependency> --> <!-- <dependency> <groupId>javax.persistence</groupId> <artifactId>persistence-api</artifactId> <version>1.0</version> </dependency> --> <!-- JPA2 provider --> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-entitymanager</artifactId> <version>3.4.0.GA</version> </dependency> <!-- JDBC driver --> <dependency> <groupId>org.apache.derby</groupId> <artifactId>derby</artifactId> <version>10.5.3.0_1</version> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-core</artifactId> <version>3.3.2.GA</version> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>ejb3-persistence</artifactId> <version>3.3.2.Beta1</version> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-annotations</artifactId> <version>3.4.0.GA</version> </dependency> <dependency> <groupId>org.slf4j</groupId> <artifactId>slf4j-log4j12</artifactId> <version>1.5.2</version> </dependency> <dependency> <groupId>log4j</groupId> <artifactId>log4j</artifactId> <version>1.2.14</version> </dependency> </dependencies> <build> <plugins> <!-- compile with mvn assembly:assembly --> <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-jar-plugin</artifactId> <version>2.2</version> </plugin> <!-- compile with mvn assembly:assembly --> <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-assembly-plugin</artifactId> <version>2.2-beta-2</version> <configuration> <descriptorRefs> <descriptorRef>jar-with-dependencies</descriptorRef> </descriptorRefs> <archive> <manifest> <mainClass>sas.test.main.ExecuteMe</mainClass> </manifest> </archive> </configuration> <executions> <execution> <phase>package</phase> </execution> </executions> </plugin> <plugin> <!-- Force UTF-8 & Java-Version 1.6 --> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-compiler-plugin</artifactId> <configuration> <source>1.6</source> <target>1.6</target> <!--<encoding>utf-8</encoding>--> </configuration> </plugin> </plugins> </build> </project> and the persistence.xml, which, I promise, is in the classpath of the target: <?xml version="1.0" encoding="UTF-8"?> <persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd http://java.sun.com/xml/ns/persistence "> <persistence-unit name="EmployeeService" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <class>sas.test.model.Employee</class> <properties> <property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.EmbeddedDriver"/> <property name="hibernate.dialect" value="org.hibernate.dialect.DerbyDialect"/> <property name="hibernate.show_sql" value="true"/> <property name="javax.persistence.jdbc.url" value="jdbc:derby:webdb;create=true"/> </properties> </persistence-unit> </persistence> As you may have noticed from some commented code, I tried both, the Hibernate and the J2EE 6 implementation of JPA2.0, however, both failed. The above-mentioned code ends up with following error: log4j:WARN No appenders could be found for logger (org.hibernate.cfg.annotations.Version). log4j:WARN Please initialize the log4j system properly. Exception in thread "main" java.lang.UnsupportedOperationException: The user must supply a JDBC connection at org.hibernate.connection.UserSuppliedConnectionProvider.getConnection(UserSuppliedConnectionProvider.java:54) at org.hibernate.jdbc.ConnectionManager.openConnection(ConnectionManager.java:446) at org.hibernate.jdbc.ConnectionManager.getConnection(ConnectionManager.java:167) at org.hibernate.jdbc.JDBCContext.connection(JDBCContext.java:142) Any idea what's going wrong? Any "Hello World" maven/JPA2 demo that actually runs? I couldn't get any of those provided by google's search running. Thanx in advance.

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  • specify query timeout when using toplink essential query hint

    - by yhzs8
    Hi, For glassfish v2, I have searched through the web and I cannot find anyway to specify query timeout when using TopLink essential query hint. We have another option to migrate to EclipseLink but that is not feasible. have tried the solution in http://forums.oracle.com/forums/thread.jspa?threadID=974732&tstart=-1 but it seems the DatabaseQuery which one could set a timeout value is actually for Toplink, not TopLink essential. Do we have some other way to instruct the JDBC driver for this timeout value other than the query hint? I need to do it on query-basis and not system-basis (which is just to change the value of DISTRIBUTED_LOCK_TIMEOUT)

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  • Hibernate: "Field 'id' doesn't have a default value"

    - by André Neves
    Hi, all. I'm facing what I think is a simple problem with Hibernate, but can't get over it (Hibernate forums being unreachable certainly doesn't help). I have a simple class I'd like to persist, but keep getting: SEVERE: Field 'id' doesn't have a default value Exception in thread "main" org.hibernate.exception.GenericJDBCException: could not insert: [hibtest.model.Mensagem] at org.hibernate.exception.SQLStateConverter.handledNonSpecificException(SQLStateConverter.java:103) at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:91) [ a bunch more ] Caused by: java.sql.SQLException: Field 'id' doesn't have a default value [ a bunch more ] The relevant code for the persisted class is: package hibtest.model; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Inheritance; import javax.persistence.InheritanceType; @Entity @Inheritance(strategy = InheritanceType.JOINED) public class Mensagem { protected Long id; protected Mensagem() { } @Id @GeneratedValue public Long getId() { return id; } public Mensagem setId(Long id) { this.id = id; return this; } } And the actual running code is just plain: SessionFactory factory = new AnnotationConfiguration() .configure() .buildSessionFactory(); { Session session = factory.openSession(); Transaction tx = session.beginTransaction(); Mensagem msg = new Mensagem("YARR!"); session.save(msg); tx.commit(); session.close(); } I tried some "strategies" within the GeneratedValue annotation but it just doesn't seem to work. Initializing id doesn't help either! (eg Long id = 20L). Could anyone shed some light? EDIT 2: confirmed: messing with@GeneratedValue(strategy = GenerationType.XXX) doesn't solve it SOLVED: recreating the database solved the problem

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  • EJB3 - @Column(insertable="false") question

    - by WhiteTigerK
    Hi All, I'm building a J2SE application with EJB3 and an Oracle Express Edition DB. My problem is like that - I set an EntityBean in my project which matches a table in the DB. The table contains a column which is not nullable and has a default value. All I want is that when persisting a new data to this table using the EJB, the column's value will get its default value. This is how I set it in the project: //holds user's first name @Basic(optional = true) @Column(name = "FIRST_NAME", insertable = false, updatable = true, nullable = false) private String m_firstName; I also set it in the ORM.XML file: <basic name="firstName"> <column name="FIRST_NAME" insertable="false" updatable="true" nullable="false"/> </basic> But for some reason, when creating a new EntityBean and not setting the first name field, and then trying to persist it, i get the following exception: Exception [TOPLINK-4002] (Oracle TopLink Essentials - 2.1 (Build b60e-fcs (12/23/2008))): oracle.toplink.essentials.exceptions.DatabaseException Internal Exception: java.sql.SQLException: ORA-01400: cannot insert NULL into ("TSDB"."USERS"."FIRST_NAME") Which means that the persistence manager tries to insert the first name field although I told it not to. Am I doing something wrong here ? Thanks!

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  • use of EntityManagerFactory causing duplicate primary key exceptions

    - by bradd
    Hey guys, my goal is create an EntityManager using properties dependent on which database is in use. I've seen something like this done in all my Google searches(I made the code more basic for the purpose of this question): @PersistenceUnit private EntityManagerFactory emf; private EntityManager em; private Properties props; @PostConstruct public void createEntityManager(){ //if oracle set oracle properties else set postgres properties emf = Persistence.createEntityManagerFactory("app-x"); em = emf.createEntityManager(props); } This works and I can load Oracle or Postgres properties successfully and I can Select from either database. HOWEVER, I am running into issues when doing INSERT statements. Whenever an INSERT is done I get a duplicate primary key exception.. every time! Can anyone shed some light on why this may be happening? Thanks -Brad

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  • Help with JPQL query

    - by Robert
    I have to query a Message that is in a provided list of Groups and has not been Deactivated by the current user. Here is some pseudo code to illustrate the properties and entities: class Message { private int messageId; private String messageText; } class Group { private String groupId; private int messageId; } class Deactivated { private String userId; private int messageId; } Here is an idea of what I need to query for, it's the last AND clause that I don't know how to do (I made up the compound NOT IN expression). Filtering the deactivated messages by userId can result in multiple messageIds, how can I check if that subset of rows does not contain the messageId? SELECT msg FROM Message msg, Group group, Deactivated unactive WHERE group.messageId = msg.messageId AND (group.groupId = 'groupA' OR group.groupId = 'groupB' OR ...) AND ('someUserId', msg.messageId) NOT IN (unactive.userId, unactive.messageId) I don't know the number of groupIds ahead of time -- I receive them as a Collection<String> so I'll need to traverse them and add them to the JPQL dynamically.

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  • Interfaces with hibernate annotations

    - by molleman
    Hello i am wondering how i would be able to annotate an interface @Entity @Table(name = "FOLDER_TABLE") public class Folder implements Serializable, Hierarchy { @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "folder_id", updatable = false, nullable = false) private int fId; @Column(name = "folder_name") private String folderName; @OneToMany(cascade = CascadeType.ALL) @JoinTable(name = "FOLDER_JOIN_FILE_INFORMATION_TABLE", joinColumns = { @JoinColumn(name = "folder_id") }, inverseJoinColumns = { @JoinColumn(name = "file_information_id") }) private List< Hierarchy > fileInformation = new ArrayList< Hierarchy >(); above and below are 2 classes that implement an interface called Hierarchy, the folder class has a list of Hierarchyies being a folder or a fileinformation class @Entity @Table(name = "FILE_INFORMATION_TABLE") public class FileInformation implements Serializable, Hierarchy { @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "file_information_id", updatable = false, nullable = false) private int ieId; @Column (name = "location") private String location; i have serached the web for someway to annotate or a workaround but i cannot map the interface which is simply this public interface Hierarchy { } i get a mapping exeception on the List of hierarchyies with a folder but i dont know how to map the class correctly

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  • How to handle EntityExistsException properly?

    - by Ivan Yatskevich
    I have two entities: Question and FavoritesCounter. FavoritesCounter should be created when the question is added to favorites for the first time. Consider a use case when two users tries to add a question to favorites simultaneously - this will cause EntityExistsException when entityManager.persist(counter) is called for the second user. But the code below doesn't work, because when EntityExistsException is thrown, container marks transaction as rollback only and attempt to return getFavoritesCounter(question) fails with javax.resource.ResourceException: Transaction is not active @Stateless public class FavoritesServiceBean implements FavoritesService { ... public void addToFavorites(Question question) { FavoritesCounter counter = getCounter(question); if (counter == null) { counter = createCounter(question); } //increase counter } private FavoritesCounter createCounter(Question question) { try { FavoritesCounter counter = new FavoritesCounter(); counter.setQuestion(question); entityManager.persist(counter); entityManager.flush(); return counter; } catch (EntityExistsException e) { return getFavoritesCounter(question); } } private FavoritesCounter getFavoritesCounter(Question question) { Query counterQuery = entityManager.createQery("SELECT counter FROM FavoritesCounter counter WHERE counter.question = :question"); counterQuery.setParameter("question", question); List<FavoritesCounter> result = counterQuery.getResultList(); if (result.isEmpty()) return null; return result.get(0); } } Question @Entity public class Question implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //getter and setter for id } FavoritesCounter @Entity public class FavoritesCounter implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; @OneToOne @Column(unique = true) private Question question; //getter and setter } What is the best way to handle such a situation - return already created entity after EntityExistsException?

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  • persistence.xml ignores Hibernate and chooses DataNucleus

    - by iNPUTmice
    Hi, I'm toying around with GWT (dunno if this matters) and Hibernate. I've created a a file persistence.xml in META-INF with (amoung) other configuration the line: org.hibernate.ejb.HibernatePersistence But when I startup the EntityManager it chooses DataNucleus instead of Hibernate (which later fails because it isnt installed (jar are not in the class path)) Java Code is: EntityManagerFactory factory = Persistence.createEntityManagerFactory("gwt"); EntityManager em =factory.createEntityManager(); EntityTransaction transacation = em.getTransaction(); transacation.begin(); Campaign campaign = new Campaign(); campaign.setName("Test"); em.persist(campaign); transacation.commit(); config file contains: <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="gwt" transaction-type="JTA"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <jta-data-source>java:/DefaultDS</jta-data-source> <properties> ...

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