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  • Convert a list of strings [ '3', '1' , '2'] to a list of sorted integers [ 1, 2, 3] in Python, how?

    - by Shamim
    I have: L1 = ['11', '10', '13', '12', '15', '14', '1', '3', '2', '5', '4', '7', '6', '9', '8'] this is a list of strings, right? I need to make it a list of integers as follows: L2 = [11, 10, 13, 12, 15, 14, 1, 3, 2, 5, 4, 7, 6, 9, 8] finally I will sort it like below: L3 = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15] by L2.sort() please let me know how I can get to L3 from L1

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  • The best way to use dictionary items as we use the advantages of List

    - by blgnklc
    I want to get use of dictionary items like I do in List generic class, e.g; foreach(item in ItemList) { item.BlaBla; } but in dictionary there s no chance, like e method above... Dictionary<string, HtmlInputImage> smartPenImageDictionary; I mean I got to know the key item for the dictionary item.. but what I want, I want to travel from beginning of the list till the end..

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  • searching a list of tuples in python

    - by hdx
    So I have a list of tuple like: [(1,"juca"),(22,"james"),(53,"xuxa"),(44,"delicia")] I want this list for a tuple whose number value is equal to something. So that if I do search(53) it will return 2 Is is an easy way to do that?

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  • Remove duplicates from a list

    - by Mercer
    Hello i want to remove duplicates from a list i do this but not working List<Customer> listCustomer = new ArrayList<Customer>(); for (Customer customer: tmpListCustomer) { if (!listCustomer.contains(customer)) { listCustomer.add(customer); } }

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  • Java - Adding a Node in a doubly-linked list.

    - by jacobnlsn
    Hi, I am working on some code were I need to add a Node into a doubly linked-list, this is the code I have so far: Node tempNext = cursor.getNext(); temp = new Node(item, null, cursor, tempNext); tempNext.setPrev(temp); cursor is the Node that is right before the new added Node should go.

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  • Erlang : flattening a list of strings

    - by ErJab
    I have a list like this: [["str1","str2"],["str3","str4"],["str5","str6"]] And I need to convert it to ["str1", "str2", "str3", "str4", "str5", "str6"] How do I do this? The problem is that I'm dealing with lists of strings, so when I do lists:flatten([["str1","str2"],["str3","str4"],["str5","str6"]]) I get "str1str2str3str4str5str6" However, if the elements of the original list where just atoms, then lists:flatten would have given me what I needed. How do I achieve the same with strings?

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  • Sikuli List of Functions & Operators

    - by PPTim
    Hello, I've just discovered Sikuli, and would like to see a comprehensive functions list without digging through the online-examples and demos. Has anyone found such a list? Furthermore, apparently Sikuli supports more complex loops and function calls as well, and seems to be based in Python(!!). Examples would be great. Thanks.

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  • has any simply way to delete a value in list of python

    - by zjm1126
    a=[1,2,3,4] b=a.index(6) del a[b] print a it show error: Traceback (most recent call last): File "D:\zjm_code\a.py", line 6, in <module> b=a.index(6) ValueError: list.index(x): x not in list so i have to do this : a=[1,2,3,4] try: b=a.index(6) del a[b] except: pass print a but this is not simple,has any simply way ? thanks

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  • RegEx to reverse order of list?

    - by quantomcat
    Is there a singular regular expression that can be used in, say, a text editor's search/replace dialog to reverse the order of the items in a list? For instance, take this list: First item Second item Third item Select it in a text editor like EditPad, bring up the search and replace box, apply a regex (run as a loop or not) and turn it into: Third item Second item First item Can this be done?

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  • c# array vs generic list

    - by L G
    Hi, i basically want to know the differences or advantages in using a generic list instead of an array in the below mentioned scenario Class Employee { private _empName; Public EmpName { get{return _empName;} set{_empName = value;} } } 1. Employee[] emp 2. List<Employee> emp can anyone please tell me the advantages or disadvaatges and which one to prefer

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  • Ensuring the contacts in a Distribution List are displayed with both name and email address

    - by hawbsl
    How can I ensure the contacts I add to an Outlook distribution list are displayed with both name and email address? These contacts may not exist in any other address book, just the distribution list. Currently they show up just as an email address (in both columns). Here's roughly the VBA we're using: Do Until RS.EOF //here's where we want to inject RS!FirstName, RS!Surname etc objRecipients.Add RS!Email objRecipients.Resolve RS.MoveNext Loop Set objDistList = contactsFolder.Items.Add("IPM.DistList") objDistList.DLName = "Whatever" objDistList.AddMembers objRecipients objDistList.Save etc

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  • asp.net mvc2 - update list of objects

    - by ile
    I want to display list of objects from database, and on the same page have option to edit them. When submitting, I'd like to submit changes to all of them. I found this link: http://haacked.com/archive/2008/10/23/model-binding-to-a-list.aspx and http://www.hanselman.com/blog/ASPNETWireFormatForModelBindingToArraysListsCollectionsDictionaries.aspx but there is no description how to handle posted data in controller. Thanks in advance!

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  • How to determine whether a linked list contains a loop?

    - by ET
    During a preparation for a job interview, I encountered the following question: How can you determine whether a linked list (of any type) contains a loop, using additional space complexity of O(1)? You cannot assume that the loop starts at the first node (and of course, the loop doesn't have to contain all nodes). I couldn't find the answer, though I have the feeling it's quite simple...

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  • Returning all "positions" of a list

    - by Daymor
    I Have a list with "a" and "b" and the "b"'s are somewhat of a path and "a"'s are walls. Im writing a program to make a graph of all the possible moves. I got the code running to check the first "b" for possible moves, but i have NO Idea how im going to find all "b"'s , even less check them all without repeating. Major issue im having is getting the tuple coordinates of the "b"'s out of the list. Any pointers/tips?

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  • Query a SharePoint List from InfoPath web form in code

    - by dawsonweb
    I'm writing an InfoPath web form, using C# code behind. The form is a holiday request, after the user inputs the start and end dates I want the code to query a bank-holiday sharepoint list and count occurrences between the dates. I've added the sharepoint list as a second datasource however I'm now stuck. Any ideas?

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  • Convert list of dicts to string

    - by John
    I'm very new to Python, so forgive me if this is easier than it seems to me. I'm being presented with a list of dicts as follows: [{'directMember': 'true', 'memberType': 'User', 'memberId': '[email protected]'}, {'directMember': 'true', 'memberType': 'User', 'memberId': '[email protected]'}, {'directMember': 'true', 'memberType': 'User', 'memberId': '[email protected]'}] I would like to generate a simple string of memberIds, such as [email protected], [email protected], [email protected] but every method of converting a list to a string that I have tried fails because dicts are involved. Any advice?

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  • Linked Measure Groups and Local Dimensions

    - by ekoner
    Mulling over something I've been reading up on. According to Chris Webb, A linked measure group can only be used with dimensions from the same database as the source measure group. So I took this to mean as long as two cubes share a database, a linked measure group can be used with a dimension. So I created a new cube and added a local measure group, a local dimension and a linked measure group. However, I can't create a relationship between the linked measure group and the local dimension even though they are within the same database. I get the message below: Regular relationships in the current database between non-linked (local) dimensions and linked measure groups cannot be edited. These relationship can only be created through the wizard. This dialog can be used to delete these relationships. I see that I can go to the original cube and add the dimension there, but does the message below mean I have an alternative? I just know it's going to be something simple and trivial! Thanks for reading.

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