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  • Touchpad hardware button disables keyboard too

    - by jjg
    I have an old but nice Samsung X50 running MM which has a key between the touchpad buttons which disables the touchpad. Very nice, no-one like to brush against the touchpad while typing. It seems to be a hardware feature -- a BIOS style window appears at the top left of the screen when you press it saying "touchpad off"; and when you press it again it says "touchpad on", and so it is, but now the keyboard has no effect in X, I can type nothing except to meta-ctl F1 to the console. After a reboot the problem persists; and the only way I have found to fix it is to blow away .gconf are replace it with a copy I made in happier times. Deleting/modifying .gconf/desktop/gnome/peripherals/touchpad/%gconf.xml does not fix the problem. There is no way to turn off the switch in BIOS without losing the touchpad. I would prise the thing out with a screwdriver if I could, but it's a work machine. This button is the bane of my life, hanging over me like a sword of Damocles.

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  • Can't change settings for Mobile Broadband Dongle - Button is greyed out

    - by Ross LIndsey
    I was with VirginBroadband.com.au (Australia). My huawai 3G Dongle was working great on Ubuntu, However I have changed ISP's. I unlocked the modem, and put in the new SIM. I have tested this in my Windows PC and it connects to the new (Optus) Network A-OK and it all works. When I put this dongle (the same one that was working fine in Ubuntu) into that same Ubuntu Netbook it simply won't connect. When I try to go into the dialog to try and add or change settings the button to change or update settings is greyed out, I can't select it. Apparently since this dongle was already recognized the Broadband Setup Wizard won't start, and I have no idea how to get it to start (presuming it has the ability to configure an already recognized dongle). What do I have to do to either enable the ability to change the configuration for this setup, or to blow away the one that is set up so the Broadband Wizard will re-start and let me configure a new one. Can anyone provide simple instructions for doing this? I'm using Ubuntu with the Cinnamon Desktop

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  • Black Screen on pressing back button in libgdx

    - by user26384
    In my game when i touch on advertisements and press back button to return on game the i am getting a black screen. I referred this link. I tried to change IosGraphics.java but the change is not reflected in monotouch project. I did the following : Extracted nightly.zip and opened gdx-backend-iosmonotouch-sources From there I changed IosGraphicsjava. I then made a new jar file gdx-backend-iosmonotouch.jar and replaced it with original jar file in the nightly folder. Compressed all the files from nightly folder in .zip file. Used this .zip file to make a new project throuch gdx-setup-ui.jar. I tried to open my project in monotouch and from com-gdx-backendios.dll i found that the changes in IosGraphics are not being reflected. Am I missing something? How do I solve this? I even tried to open gdx-backend-iosmonotouch-sources.jar with winrar and edit IosGraphics.java and save it. Even this didn't work.

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  • help with yes/no radio button for multiple questions pull from database

    - by Darlene
    hey guys i need a little help with this questionaire form. The tables currently using are: user userid| username answers aswerid|quesid|ans|userid|date ques quesid|ques The form below is what im using however i'm gettin errors for radio button.... could anyone offer advice? $query = mysql_query("SELECT * FROM ques", $con) or die("Cannot Access tblprequeations From Server"); echo"<div id='quesform' class='quesform'>"; echo"<form name='QForm' method='post' action='answers.php' onsubmit='return validateQForm(this);'>"; echo"<p>"; while($row = mysql_fetch_array($query)) { echo"<p>"; echo"<label>".$row['quesid']."</label>&nbsp; &nbsp;"; echo"<label>".$row['ques']."</label>&nbsp; &nbsp;"; echo"<input type='radio' name='ans' value='yes' if (isset($_POST['ans']) && $_POST['ans'] == 'yes') echo'checked'/>"; echo"<input type='radio' name='ans' value='no' if (isset($_POST['ans']) && $_POST['ans'] == 'no') echo'checked'/>"; echo"</p>"; } echo"</p>";

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  • Can I increase a buttons onclick-area programmatically?

    - by sandis
    Sometimes I have a button in my UI that it is so small that it is difficult to click. My solution so far has been to add a transparent border around the button in photoshop. Just increasing the padding on the button does not work, since this will also stretch the image. Since it is kind of a fuss to open photoshop each time I want to change the clickable surface, is there any way to do this programmatically? I have tried placing a framelayout behind the button and make it clickable, but then the button wont change appearance on touch as it should. Ofcourse I could also add a ontouchlistener on the framelayout which changes the buttons appearance, but then it quite some code if I have several of those buttons. Cheers,

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  • How to add Editext and Button to Efficent Adapter which has a Icon and text

    - by jayanthgande
    Hi, I want to create a layout in such a way that on top edittext and button should be there in one row. The search text I enter in editext and click on search button. Then I want to display a custom list view where each row contains image and text.(As per the API demos example list14 I have tried). But when I run the application, button and edittext are being added to each row (i.e., Each row contains a image, text, editext, button. Can Any one guide how to resolve this issue. Below is my xml file: <!-- <FrameLayout android:layout_width="wrap_content" android:layout_height="0dip" android:layout_weight="1"></FrameLayout> --> <ImageView android:id="@+id/icon" android:layout_width="48dip" android:layout_height="48dip" /> <TextView android:id="@+id/text" android:layout_gravity="center_vertical" android:layout_width="0dip" android:layout_weight="1.0" android:layout_height="wrap_content" /> <!-- <EditText android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/prdsearchtb" android:text="@string/tb_prd_search_lbl"></EditText> --> <!-- <TableLayout android:id="@+id/TableLayout01" android:layout_width="fill_parent" android:layout_height="wrap_content"> <TableRow> --> <Button android:id="@+id/prdsrcbutton" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="@string/btn_lbl_prd_search" android:layout_x="2px" android:layout_y="410px"></Button> <!-- </TableRow> </TableLayout> -- and Java File: /** * */ package org.techdata.activity; import android.app.AlertDialog; import android.app.ListActivity; import android.content.Context; import android.content.Intent; import android.graphics.Bitmap; import android.graphics.BitmapFactory; import android.os.Bundle; import android.util.Log; import android.view.LayoutInflater; import android.view.View; import android.view.ViewGroup; import android.widget.BaseAdapter; import android.widget.Button; import android.widget.EditText; import android.widget.ImageView; import android.widget.ListView; import android.widget.TextView; /** * @author jayanthg * */ public class ProductSearch extends ListActivity { private static class ProductSearchAdapter extends BaseAdapter { private LayoutInflater mInflater; private Bitmap mIcon1; private Bitmap mIcon2; public ProductSearchAdapter(Context context) { mInflater = LayoutInflater.from(context); // Icons bound to the rows. mIcon1 = BitmapFactory.decodeResource(context.getResources(), R.drawable.icon48x48_1); mIcon2 = BitmapFactory.decodeResource(context.getResources(), R.drawable.icon48x48_2); } @Override public int getCount() { return DATA.length; } @Override public Object getItem(int position) { return position; } @Override public long getItemId(int position) { return position; } @Override public View getView(final int position, View convertView, ViewGroup parent) { ViewHolder holder; Button btn=null; if (convertView == null) { convertView = mInflater.inflate(R.layout.productsearch, null); // Creates a ViewHolder and store references to the two children // views // we want to bind data to. holder = new ViewHolder(); holder.text = (TextView) convertView.findViewById(R.id.text); holder.icon = (ImageView) convertView.findViewById(R.id.icon); btn=(Button)convertView.findViewById(R.id.prdsrcbutton); convertView.setTag(holder); } else { // Get the ViewHolder back to get fast access to the TextView // and the ImageView. holder = (ViewHolder) convertView.getTag(); } // Bind the data efficiently with the holder. holder.text.setText(DATA[position]); holder.icon.setImageBitmap((position & 1) == 1 ? mIcon1 : mIcon2); holder.icon.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Log.i("image", " u clicked on icon Position" + position); } }); holder.text.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Log.i("Text", " u clicked on text Position" + position); } }); btn.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Log.i("Button","U clicked on button"); } }); return convertView; } static class ViewHolder { TextView text; ImageView icon; } private static final String[] DATA = { "Abbaye de Belloc", "Abbaye du Mont des Cats" }; } ListView product_search_list; Button srch_btn; EditText srch_text; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setListAdapter(new ProductSearchAdapter(this)); // setContentView(R.layout.productsearch); // getListView().setEmptyView(findViewById(R.id.text)); // srch_text = (EditText)findViewById(R.id.prdsearchtb); // srch_btn = (Button) findViewById(R.id.prdsearchtb); // srch_btn.setOnClickListener(new View.OnClickListener() { // // @Override // public void onClick(View v) { // callProductSearchAdapter(); // // } // }); } void callProductSearchAdapter() { setListAdapter(new ProductSearchAdapter(this)); } private void createDialog(String title, String text, final Intent i) { if (i == null) { AlertDialog ad = new AlertDialog.Builder(this).setIcon( R.drawable.alert_dialog_icon).setPositiveButton("Ok", null) .setTitle(title).setMessage(text).create(); ad.show(); } } } Regards: Jayanth

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  • Connecting SceneBuilder edited FXML to Java code

    - by daniel
    Recently I had to answer several questions regarding how to connect an UI built with the JavaFX SceneBuilder 1.0 Developer Preview to Java Code. So I figured out that a short overview might be helpful. But first, let me state the obvious. What is FXML? To make it short, FXML is an XML based declaration format for JavaFX. JavaFX provides an FXML loader which will parse FXML files and from that construct a graph of Java object. It may sound complex when stated like that but it is actually quite simple. Here is an example of FXML file, which instantiate a StackPane and puts a Button inside it: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml"> <children> <Button mnemonicParsing="false" text="Button" /> </children> </StackPane> ... and here is the code I would have had to write if I had chosen to do the same thing programatically: import javafx.scene.control.*; import javafx.scene.layout.*; ... final Button button = new Button("Button"); button.setMnemonicParsing(false); final StackPane stackPane = new StackPane(); stackPane.setPrefWidth(200.0); stackPane.setPrefHeight(150.0); stacPane.getChildren().add(button); As you can see - FXML is rather simple to understand - as it is quite close to the JavaFX API. So OK FXML is simple, but why would I use it?Well, there are several answers to that - but my own favorite is: because you can make it with SceneBuilder. What is SceneBuilder? In short SceneBuilder is a layout tool that will let you graphically build JavaFX user interfaces by dragging and dropping JavaFX components from a library, and save it as an FXML file. SceneBuilder can also be used to load and modify JavaFX scenegraphs declared in FXML. Here is how I made the small FXML file above: Start the JavaFX SceneBuilder 1.0 Developer Preview In the Library on the left hand side, click on 'StackPane' and drag it on the content view (the white rectangle) In the Library, select a Button and drag it onto the StackPane on the content view. In the Hierarchy Panel on the left hand side - select the StackPane component, then invoke 'Edit > Trim To Selected' from the menubar That's it - you can now save, and you will obtain the small FXML file shown above. Of course this is only a trivial sample, made for the sake of the example - and SceneBuilder will let you create much more complex UIs. So, I have now an FXML file. But what do I do with it? How do I include it in my program? How do I write my main class? Loading an FXML file with JavaFX Well, that's the easy part - because the piece of code you need to write never changes. You can download and look at the SceneBuilder samples if you need to get convinced, but here is the short version: Create a Java class (let's call it 'Main.java') which extends javafx.application.Application In the same directory copy/save the FXML file you just created using SceneBuilder. Let's name it "simple.fxml" Now here is the Java code for the Main class, which simply loads the FXML file and puts it as root in a stage's scene. /* * Copyright (c) 2012, Oracle and/or its affiliates. All rights reserved. */ package simple; import java.util.logging.Level; import java.util.logging.Logger; import javafx.application.Application; import javafx.fxml.FXMLLoader; import javafx.scene.Scene; import javafx.scene.layout.StackPane; import javafx.stage.Stage; public class Main extends Application { /** * @param args the command line arguments */ public static void main(String[] args) { Application.launch(Main.class, (java.lang.String[])null); } @Override public void start(Stage primaryStage) { try { StackPane page = (StackPane) FXMLLoader.load(Main.class.getResource("simple.fxml")); Scene scene = new Scene(page); primaryStage.setScene(scene); primaryStage.setTitle("FXML is Simple"); primaryStage.show(); } catch (Exception ex) { Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex); } } } Great! Now I only have to use my favorite IDE to compile the class and run it. But... wait... what does it do? Well nothing. It just displays a button in the middle of a window. There's no logic attached to it. So how do we do that? How can I connect this button to my application logic? Here is how: Connection to code First let's define our application logic. Since this post is only intended to give a very brief overview - let's keep things simple. Let's say that the only thing I want to do is print a message on System.out when the user clicks on my button. To do that, I'll need to register an action handler with my button. And to do that, I'll need to somehow get a handle on my button. I'll need some kind of controller logic that will get my button and add my action handler to it. So how do I get a handle to my button and pass it to my controller? Once again - this is easy: I just need to write a controller class for my FXML. With each FXML file, it is possible to associate a controller class defined for that FXML. That controller class will make the link between the UI (the objects defined in the FXML) and the application logic. To each object defined in FXML we can associate an fx:id. The value of the id must be unique within the scope of the FXML, and is the name of an instance variable inside the controller class, in which the object will be injected. Since I want to have access to my button, I will need to add an fx:id to my button in FXML, and declare an @FXML variable in my controller class with the same name. In other words - I will need to add fx:id="myButton" to my button in FXML: -- <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> and declare @FXML private Button myButton in my controller class @FXML private Button myButton; // value will be injected by the FXMLLoader Let's see how to do this. Add an fx:id to the Button object Load "simple.fxml" in SceneBuilder - if not already done In the hierarchy panel (bottom left), or directly on the content view, select the Button object. Open the Properties sections of the inspector (right panel) for the button object At the top of the section, you will see a text field labelled fx:id. Enter myButton in that field and validate. Associate a controller class with the FXML file Still in SceneBuilder, select the top root object (in our case, that's the StackPane), and open the Code section of the inspector (right hand side) At the top of the section you should see a text field labelled Controller Class. In the field, type simple.SimpleController. This is the name of the class we're going to create manually. If you save at this point, the FXML will look like this: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml" fx:controller="simple.SimpleController"> <children> <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> </children> </StackPane> As you can see, the name of the controller class has been added to the root object: fx:controller="simple.SimpleController" Coding the controller class In your favorite IDE, create an empty SimpleController.java class. Now what does a controller class looks like? What should we put inside? Well - SceneBuilder will help you there: it will show you an example of controller skeleton tailored for your FXML. In the menu bar, invoke View > Show Sample Controller Skeleton. A popup appears, displaying a suggestion for the controller skeleton: copy the code displayed there, and paste it into your SimpleController.java: /** * Sample Skeleton for "simple.fxml" Controller Class * Use copy/paste to copy paste this code into your favorite IDE **/ package simple; import java.net.URL; import java.util.ResourceBundle; import javafx.fxml.FXML; import javafx.fxml.Initializable; import javafx.scene.control.Button; public class SimpleController implements Initializable { @FXML // fx:id="myButton" private Button myButton; // Value injected by FXMLLoader @Override // This method is called by the FXMLLoader when initialization is complete public void initialize(URL fxmlFileLocation, ResourceBundle resources) { assert myButton != null : "fx:id=\"myButton\" was not injected: check your FXML file 'simple.fxml'."; // initialize your logic here: all @FXML variables will have been injected } } Note that the code displayed by SceneBuilder is there only for educational purpose: SceneBuilder does not create and does not modify Java files. This is simply a hint of what you can use, given the fx:id present in your FXML file. You are free to copy all or part of the displayed code and paste it into your own Java class. Now at this point, there only remains to add our logic to the controller class. Quite easy: in the initialize method, I will register an action handler with my button: () { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... -- ... // initialize your logic here: all @FXML variables will have been injected myButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... That's it - if you now compile everything in your IDE, and run your application, clicking on the button should print a message on the console! Summary What happens is that in Main.java, the FXMLLoader will load simple.fxml from the jar/classpath, as specified by 'FXMLLoader.load(Main.class.getResource("simple.fxml"))'. When loading simple.fxml, the loader will find the name of the controller class, as specified by 'fx:controller="simple.SimpleController"' in the FXML. Upon finding the name of the controller class, the loader will create an instance of that class, in which it will try to inject all the objects that have an fx:id in the FXML. Thus, after having created '<Button fx:id="myButton" ... />', the FXMLLoader will inject the button instance into the '@FXML private Button myButton;' instance variable found on the controller instance. This is because The instance variable has an @FXML annotation, The name of the variable exactly matches the value of the fx:id Finally, when the whole FXML has been loaded, the FXMLLoader will call the controller's initialize method, and our code that registers an action handler with the button will be executed. For a complete example, take a look at the HelloWorld SceneBuilder sample. Also make sure to follow the SceneBuilder Get Started guide, which will guide you through a much more complete example. Of course, there are more elegant ways to set up an Event Handler using FXML and SceneBuilder. There are also many different ways to work with the FXMLLoader. But since it's starting to be very late here, I think it will have to wait for another post. I hope you have enjoyed the tour! --daniel

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  • Lenovo Mini Wireless Keyboard N5901: Remap orange "My Computer" button

    - by Jon Schneider
    I have a Lenovo Mini Wireless Keyboard N5901 (a.k.a. Part No. 57Y6336) that I'm using with an HTPC running Windows 7. The remote comes with an orange button in the top-left corner that by default, when pressed, opens the Windows "My Computer" window. I would like to remap / reprogram this button to act like the green "Windows Media Center" button instead on a Windows Media Center (WMC) remote; that is, open Windows Media Center if it isn't already open, or go to the WMC homepage if WMC is already open. I've tried several keyboard-remapping utilities (as recommended in other, more general "how to remap keyboard key?" SuperUser.com questions) including SharpKeys, Key Mapper, and KeyTweak, with no luck so far. None of these utilities recognize the orange button -- they all do recognize that some key was pressed, but display a value for the key of "unsupported" or something similar. I was able to use a utility called Keyboard Scan Code Generator to determine that a press of the orange button has a KeyData value of 16777217 (0x1000001), and a "Virtual Code" value of 182. (The other "media" buttons on the N5901 have the same KeyData value, but different Virtual Code values). I'm not sure at this point where in Windows this keystroke is being interpreted as a command to open "My Computer." There is no special software / driver for this device; it worked out of the box with Windows 7, no special driver install necessary. Is there any way to accomplish this? Thanks in advance for any suggestions!

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  • Excel 2007 - Closing Using The Close Button When Using Personal.xlsb To Store Marcos

    - by XXXXXXXXXXXXXXXXX
    When I create and store macros in Excel 2007 using the Personal file in the XLstart folder then open and go to close Excel using the close buttom in the upper right hand corner I now have to click it twice to completely close Excel however if I use the Excel Exit button by clicking on the Office 2007 button first Excel will close on one. Is there away I can store macros for use with all workbooks I open with Excel and be able to close on one from the close button in the upper right hand corner after saving the current workbook I have be working on?

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  • WPF Image change source when button is disabled

    - by Taylor
    Hi, I'm trying to show a different image when the button is disabled. Should be easy with triggers, right?! For some reason, I have not been able to get the images to switch. I've tried setting triggers on both the image and button. What is wrong with what I have below? How can I change the image source when the button is enabled/disabled? Thanks! <Button x:Name="rleft" Command="{Binding Path=Operation}" CommandParameter="{x:Static vm:Ops.OpA}"> <Button.Content> <StackPanel> <Image Width="24" Height="24" RenderOptions.BitmapScalingMode="NearestNeighbor" SnapsToDevicePixels="True" Source="/MyAssembly;component/images/enabled.png"> <Image.Style> <Style> <Style.Triggers> <DataTrigger Binding="{Binding ElementName=rleft, Path=Button.IsEnabled}" Value="False"> <Setter Property="Image.Source" Value="/MyAssembly;component/images/disabled.png" /> </DataTrigger> </Style.Triggers> </Style> </Image.Style> </Image> </StackPanel> </Button.Content> </Button>

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  • How to disable "back" button on my mouse?

    - by Sergiy Byelozyorov
    I have bought Microsoft Bluetooth Notebook Mouse 5000. It's working just as I want it except that "back" button on the right side. I constantly hit it with the thumb and browser goes back. I am not used to this behavior, since my older mouse didn't have such a button. I just want to get rid of it -- disable the button once and forever, so if I clicked it -- nothing should happen.

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  • Button Visibility Converter

    - by developer
    Hi All, I have a requirement wherein I need to display on a User form, a Create Button if that user has doesnt have a profile and a Edit Button if he does have a profile. I am using a converter to change the visibility of the button. Below is my code, <StackPanel Orientation="Horizontal"> <Button Content="Create Profile" Visibility="{Binding Profile,Converter={StaticResource ButtonVisibilityConverter}, ConverterParameter='Create'}" Command="local:LaunchEditor" CommandParameter="{Binding}"/> <Button Content="Edit Profile" Visibility="{Binding Profile,Converter={StaticResource ButtonVisibilityConverter}, ConverterParameter='Edit'}" Command="local:LaunchEditor" CommandParameter="{Binding}"/> </StackPanel> Below is my converter code public class ButtonVisibilityConverter : IValueConverter { public object Convert(object value, Type targetType, object parameter, CultureInfo culture) { string btName = null; btName = (string)parameter; if ((value==null)&&(btName=="Create")) { return Visibility.Visible; } else if ((value != null) && (btName=="Edit")) { return Visibility.Visible; } else { return Visibility.Collapsed; } } public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture) { throw new NotImplementedException(); } } Everything works fine initially, but the moment I click on the Create Profile window, and it is the constructor that loads the profile window, after that even if I close that window without doing anything, the Create button turns to edit. My guess is that, it is because the constructor would have create the profile object and so even though the object is empty it shows me edit button instead of create. Is there any other way I could display button visibility??

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  • How to Get Specific Button pressed in a repeater when using ModalPopupExtender

    - by MemphisDeveloper
    I have buttons contained within a repeater. A ModalPopupExtender is used to confirm event for each button. I create standard panels outside of the repeater and I attach each button in the repeater to these panels from inside the repeater. The problem is once the button is pressed in the popup I can't figure out how to determine which row of the repeater to edit as I can't figure out how to identify which button was pressed. Panel: <asp:Panel ID="pnlRemoveAlert" runat="server" > <h1 align="center">Remove Phone</h1> <asp:Button ID="butRemove" runat="server" OnCommand="Handle_Click" CommandName="Remove" Text="Continue"/> <asp:Button ID="butRemoveCancel" runat="server" Text="Cancel"/> </asp:Panel> Repeater: <asp:Repeater ID="repPhoneNumbers" runat="server" OnItemDataBound="setButtonModals"> <ItemTemplate> ... <asp:Button ID="btnStatus" runat="server"/> <asp:Button ID="dummybutton" runat="Server" Visible="false" /> <ajaxToolkit:ModalPopupExtender ID="mpeEnable" runat="server" TargetControlID = "btnStatus CancelControlID="butEnableCancel" PopupControlID="pnlEnableAlert"/> ... Event Handle: Protected Sub Handle_Click(ByVal sender As Object, ByVal e As CommandEventArgs) 'I need to know which row of the repeater to deal with here End Sub

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  • Stopping and Play button for Audio (Android)

    - by James Rattray
    I have this problem, I have some audio I wish to play... And I have two buttons for it, 'Play' and 'Stop'... Problem is, after I press the stop button, and then press the Play button, nothing happens. -The stop button stops the song, but I want the Play button to play the song again (from the start) Here is my code: final MediaPlayer mp = MediaPlayer.create(this, R.raw.megadeth); And then the two public onclicks: (For playing...) button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { // Perform action on click button.setText("Playing!"); try { mp.prepare(); } catch (IllegalStateException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } mp.start(); // } }); And for stopping the track... final Button button2 = (Button) findViewById(R.id.cancel); button2.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { mp.stop(); mp.reset(); } }); Can anyone see the problem with this? If so could you please fix it... (For suggest) Thanks alot... James

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  • python tkinter gui

    - by Lewis Townsend
    I'm wanting to make a small python program for yearly temperatures. I can get nearly everything working in the standard console but I'm wanting to implement it into a GUI. The program opens a csv file reads it into lists, works out the average, and min & max temps. Then on closing the application will save a summary to a new text file. I am wanting the default start up screen to show All Years. When a button is clicked it just shows that year's data. Here is a what I want it to look like. Pretty simple layout with just the 5 buttons and the out puts for each. I can make up the buttons for the top fine with: Code: class App: def __init__(self, master): frame = Frame(master) frame.pack() self.hi_there = Button(frame, text="All Years", command=self.All) self.hi_there.pack(side=LEFT) self.hi_there = Button(frame, text="2011", command=self.Y1) self.hi_there.pack(side=LEFT) self.hi_there = Button(frame, text="2012", command=self.Y2) self.hi_there.pack(side=LEFT) self.hi_there = Button(frame, text="2013", command=self.Y3) self.hi_there.pack(side=LEFT) self.hi_there = Button(frame, text="Save & Exit", command=self.Exit) self.hi_there.pack(side=LEFT) I'm not sure as to how to make the other elements, such as the title & table. I was going to post the code of the small program but decided not to. Once I have the structure/framework I think I can populate the fields & I might learn better this way. Using Python 2.7.3

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  • Having trouble hiding keyboard using invisible button which sits on top of uiscrollview

    - by phil
    I have 3 items in play... 1) UIView sits at the base of the hierarchy and contains the UIScrollview. 2) UIScrollview that is presenting a lengthy user form. 3) An invisible button on the UIScrollview that I'm using to provide "hide the keyboard" features. Notice in the code below that I'm registering to be notified when the keyboard is going to appear and again when it's going to disappear. These are working great. My problem is seemingly one of "layers". See below where I insert the button into the view atIndex:0. This causes the button to be activated and "stuffed" behind the scrollview so that when you click on it, the scrollview grabs the touch and the button is unaware. There is no way to "reach" the button and suppress the keyboard. However, if I insert atIndex:1, the button gets super imposed on top of the text entry fields and so any touch at all is acted upon by the button, which immediately suppresses the keyboard and then disappears. How do I insert the button on top of the UIScrollview but behind the UITextfields that sit there? other logistics: I have a -(void) hidekeyboard function that I have setup with the UIButtion as an IBAction(). And I have the UIButton connected to "files owner" via a ctrl-drag/drop. (Do I need both of those conventions?) This code in ViewDidLoad()... [[NSNotificationCenter defaultCenter] addObserverForName:UIKeyboardWillShowNotification object:nil queue:nil usingBlock:^(NSNotification *notification){ [self.view insertSubview:self.keyboardDismissalButton atIndex:0]; }];

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  • Link Button on asp.net user control not firing

    - by andyriome
    Hi I have a user control, which is added to another user control. The nested user control is built up of a gridview, an image button and a link button. The nested user control is added to the outer control as a collection object based upon the results bound to the gridview. The problem that I have is that my link button doesn't work. I click on it and the event doesn't fire. Even adding a break point was not reached. As the nested user control is added a number of times, I have set image button to have unique ids and also the link button. Whilst image button works correctly with its java script. The link button needs to fire an event in the code behind, but despite all my efforts, I can't make it work. I am adding the link button to the control dynamically. Below is the relevant code that I am using: public partial class ucCustomerDetails : System.Web.UI.UserControl { protected override void CreateChildControls( ) { base.CreateChildControls( ); string strUniqueID = lnkShowAllCust.UniqueID; strUniqueID = strUniqueID.Replace('$','_'); this.lnkShowAllCust.ID = strUniqueID; this.lnkShowAllCust.Click += new EventHandler(this.lnkShowAllCust_Click); this.Controls.Add(lnkShowAllCust); } protected override void OnInit (EventArgs e) { CreateChildControls( ); base.OnInit(e); } protected override void OnLoad(EventArgs e) { base.EnsureChildControls( ); } protected void Page_Load(object sender, EventArgs e) { if (IsPostBack) { CreateChildControls( ); } } protected void lnkShowAllCust_Click(object sender, EventArgs e) { this.OnCustShowAllClicked(new EventArgs ( )); } protected virtual void OnCustShowAllClicked(EventArgs args) { if (this.ViewAllClicked != null) { this.ViewAllClicked(this, args); } } public event EventHandler ViewAllClicked; } I have been stuggling with this problem for the last 3 days and have had no success with it, and I really do need some help. Can anyone please help me?

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  • PHP Form multiple buttons

    - by Ken
    I have a form with 2 buttons, that depending on which is selected will either be deleted or edited from the database. Those are each individual pages using SQL statements (questionedit and questiondelete). However, when i press a button, nothing happens...Any Ideas Here is my javascript <script type="text/javascript"> function SelectedButton(button) { if(button == 'edit') { document.testedit_questionform.action ="testedit_questionedit.php"; } else if(button == 'delete') { document.testedit_questionform.action ="testedit_questiondelete.php"; } document.forms[].testedit_questionform.submit(); } </script> Here is my form (being echoed from a loop) <form name=\"testedit_questionform\" action=\"SelectedButton\" method=\"POST\"> <span class=\"grid_11 prefix_1\" id=\"\" > Question:<input type=\"text\" name=\"QuestionText\" style=\"width:588px; margin-left:10px;\" value=\"$row[0]\"/> <input type=\"button\" value=\"Edit\" name=\"Operation\"onclick=\"submitForm(\'edit\')\" /> <input type=\"button\" value=\"Delete\" name=\"Operation\"onclick=\"submitForm(\'delete\')\" /> <input type=\"hidden\" name=\"QId\" value=\"$row[3]\" /><br />"); </form>

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  • Wired USB mouse left button stops working

    - by InNeedOfHelp
    My wired USB mouse's left button stops working properly after being plugged into the computer for about five minutes. The mouse button will become sticky and not allow me to select things or the left button is completely unresponsive. The mouse driver is up to date. I am running Windows Vista Home Premium with the Service Pack 2 on a Sony Viao laptop (Model number (VGN-NW125J). If anybody knows how to fix this your help would be greatly appreciated.

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  • How to copy a button with shadow effect from PSD to PNG

    - by Alex
    I got a web site design in PSD file from a web-designer. All element s there snap to guides, which is handy when I make a selection to copy an element of design to a PNG file: guides make my selection precise. One button there has two states: normal and hover. Both states contains of several layers. So I am trying to copy both states as PNG files in order to make a nice button in html. The problem is that both states have shadow effects, which go beyond the layers' edges, i.e. when I try to select a button my selection (snapped to guides) does not include an outer part of the shadow. How do I make a precise selection of the button state in such situation?

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  • Returning a Value from a jQuery Dialog Button Instead of Running a Function

    - by kamera
    I'm working on an admin UI and I can't wrap my head around how to get a specific kind of modal behaviour. I'm using jQuery. I already have a system for modal dialogs in place, where an openModal(settings) function opens a modal. Based on the settings, it will show/hide or sometimes inject various dialogs. I also have a generic confirmation dialog and this is the one I'm not sure how to make work. The layout is simple: <div id="confirmation-dialog"> <h2>Are you sure?</h2> <button class="button.yes">Yes</button> <button class="button.no">No</button> </div> I could just hard-code each button to do what I need it to do but I would like this to be more generic. Ideally, I would like it to function like this: (I know this doesn't work) function deleteImportantThing() { if (confirmThis() == true) { // Delete the thing } else { // Do nothing, close dialog } } function confirmThis() { openModal({kind: "confirm"}); // Check which button is clicked, then return true or false } I guess I just don't know enough JavaScript to get this to work, or to even figure out where to look. Any advice? I know there are modal dialog plug-ins out there but I'd have to change how the rest of my modals work to integrate them, and I'd like to do this myself if at all possible.

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  • Using jQuery .find() with multiple conditions at the same time?

    - by fuzzybabybunny
    I know that there are other ways of grabbing radio button values, but I want to know how to do this with .find(). I only want to log the value of the selected radio button, so it requires finding by two conditions at the same time: The button with name=area The button with selected=selected <div class="radio"> <label> <input class="track-order-change" type="radio" name="area" id="area1" value="area1" checked="checked"> Area 1 </label> </div> <div class="radio"> <label> <input class="track-order-change" type="radio" name="area" id="area2" value="area2"> Area 2 </label> </div> <div class="radio"> <label> <input class="track-order-change" type="radio" name="area" id="area3" value="area3"> Area 3 </label> </div> When anything with the class track-order-change changes, it will run the function UpdateOrderSubmission. $('.track-order-change').on('change', function() { updateOrderSubmission() }); I want the updateOrderSubmission function to console log the value of the radio button that is selected. var updateOrderSubmission = function() { var orderSubmission = { area: $('#submit-initial-form').find('[name=area],[checked=checked]').this.val() } console.log(orderSubmission) }; The code above doesn't work. How do I grab the value of the selected radio button? I need to do .find() with two conditions (name and checked), not just one condition.

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  • html button elemenents and onserverclick attribute in asp.net

    - by Adrian Adkison
    I have been experiencing some very strange behavior using html buttons with the onserverclick attribute. What I am trying to do is use jQuery to designate the default button on the page. By default button I mean the button that is "clicked" when a user hits enter. In testing, I would hit enter while in an input field and sometimes the intended "default" button was clicked and the server side method defined in the corresponding onserverclick attribute was hit. Other times a post back was made without hitting the server method. In order to isolate the issue I created a minimal test case and found some very interesting results. client side: <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title>Untitled Page</title> <script type="text/javascript" src="/scripts/jquery-1.4.min.js"></script> </head> <body> <form id="form1" runat="server"> <asp:Label ID="_response" runat="server"></asp:Label> <input id="input1" type="text" /> <input id="input2" type="text" /> <button id="first" type="button" class="defaultBtn" runat="server" onserverclick="ServerMethod1">test1</button> <button id="second" type="button" runat="server" onserverclick="ServerMethod2">test2</button> </form> <script type="text/javascript"> jQuery('form input').keyup( function(e) { if ((e.which && e.which == 13) || (e.keyCode && e.keyCode == 13)) { $('button.defaultBtn').click(); return true; } } ); </script> </body> </html> server side: public partial class admin_spikes_ButtonSubmitTest : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { } protected void ServerMethod1(object sender, EventArgs e) { _response.Text = "server method1 was hit"; } protected void ServerMethod2(object sender, EventArgs e) { _response.Text = "server method2 was hit"; } } What I found was that everything worked as expected with this code except when I removed one of the input elements. In Firefox 3.6 and IE 8 when only one input exists on the page, hitting enter does not trigger the onserverclick, it makes a post back without even being jQuery "clicked" or actually "clicked". You can test this by starting with two inputs and clicking "test2". This will output "server method2 was hit". Then just hit enter and the output will be "server method1 was hit. Now take away an input and run the same test. Click "test2" see the results, then hit enter and you will see that nothing will change because the "test1" method was never hit. Does anyone know what is going on? Thanks p.s. Chrome worked as expected

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  • Button layed out using layout_toLeftOf in a RelativeLayout does not show up

    - by rodion
    Hello all, I am trying to layout a Button to the left of a TextView that is centered on the screen. My layout looks like this: <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:gravity="center"> <TextView android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="foo" android:id="@+id/center" /> <Button android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="Left button" android:layout_toLeftOf="@id/center" /> </RelativeLayout> Unfortunately, the button just does not appear. I get the following result: As you see, the button doesn't show up. It works if I use layout_toRightOf, then the button appears to the right of the TextView, just as expected. Any ideas what I am doing wrong here?

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