Search Results

Search found 4482 results on 180 pages for 'mr bash'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 22/180 | < Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >

  • sum up value from textfile - bash

    - by user3493435
    I am trying to sum up the values in a textfile try.txt firstNumber,1 secondNumber,2 I tried with this script #!/bin/bash while IFS, read -r -a array; do printf "%s %s\n" "${array[0]} ${array[1]}" for n in "${array[1]}"; do ((total += n)) echo "total =" $total done done < try.txt and I landed up with this output firstNumber 1 total = 1 secondNumber 2 total = 3 expected output firstNumber 1 secondNumber 2 total = 3 Thanks in advance

    Read the article

  • Conecting bash script with a txt file

    - by cathy
    I have a txt file with 100+ lines called page1.txt; odd lines are urls and even lines are url names. I have a bash file already created that checks urls for completion. Except right now, the process is really manual because I have to modify the bash every time I need to check a url. So I need to connect the bash to the txt using the variable url. $url should get all the odd lines from page1.txt and check if the link is complete or not. Also, how would I write a variable called name that derives from the url the 7 digits? bash file manually: url=http://www.-------------/-/8200233/1/ name=8200233 lynx -dump $url > $name.txt I would prefer if the bash file could add "Complete/In-Complete " at the beginning of every even line in the page1.txt file but a new text file could be also created to keep track of the Completes/In-completes.

    Read the article

  • Bash Shell Scripting Errors: ./myDemo: 56: Syntax error: Unterminated quoted string [EDITED]

    - by ???
    Could someone take a look at this code and find out what's wrong with it? #!/bin/sh while : do echo " Select one of the following options:" echo " d or D) Display today's date and time" echo " l or L) List the contents of the present working directory" echo " w or W) See who is logged in" echo " p or P) Print the present working directory" echo " a or A) List the contents of a specified directory" echo " b or B) Create a backup copy of an ordinary file" echo " q or Q) Quit this program" echo " Enter your option and hit <Enter>: \c" read option case "$option" in d|D) date ;; l|L) ls $PWD ;; w|w) who ;; p|P) pwd ;; a|A) echo "Please specify the directory and hit <Enter>: \c" read directory if [ "$directory = "q" -o "Q" ] then exit 0 fi while [ ! -d "$directory" ] do echo "Usage: "$directory" must be a directory." echo "Re-enter the directory and hit <Enter>: \c" read directory if [ "$directory" = "q" -o "Q" ] then exit 0 fi done printf ls "$directory" ;; b|B) echo "Please specify the ordinary file for backup and hit <Enter>: \c" read file if [ "$file" = "q" -o "Q" ] then exit 0 fi while [ ! -f "$file" ] do echo "Usage: \"$file\" must be an ordinary file." echo "Re-enter the ordinary file for backup and hit <Enter>: \c" read file if [ "$file" = "q" -o "Q" ] then exit 0 fi done cp "$file" "$file.bkup" ;; q|Q) exit 0 ;; esac echo done exit 0 There are some syntax errors that I can't figure out. However I should note that on this unix system echo -e doesn't work (don't ask me why I don't know and I don't have any sort of permissions to change it and even if I wouldn't be allowed to) Bash Shell Scripting Error: "./myDemo ./myDemo: line 62: syntax error near unexpected token done' ./myDemo: line 62: " [Edited] EDIT: I fixed the while statement error, however now when I run the script some things still aren't working correctly. It seems that in the b|B) switch statement cp $file $file.bkup doesn't actually copy the file to file.bkup ? In the a|A) switch statement ls "$directory" doesn't print the directory listing for the user to see ? #!/bin/bash while $TRUE do echo " Select one of the following options:" echo " d or D) Display today's date and time" echo " l or L) List the contents of the present working directory" echo " w or W) See who is logged in" echo " p or P) Print the present working directory" echo " a or A) List the contents of a specified directory" echo " b or B) Create a backup copy of an ordinary file" echo " q or Q) Quit this program" echo " Enter your option and hit <Enter>: \c" read option case "$option" in d|D) date ;; l|L) ls pwd ;; w|w) who ;; p|P) pwd ;; a|A) echo "Please specify the directory and hit <Enter>: \c" read directory if [ ! -d "$directory" ] then while [ ! -d "$directory" ] do echo "Usage: "$directory" must be a directory." echo "Specify the directory and hit <Enter>: \c" read directory if [ "$directory" = "q" -o "Q" ] then exit 0 elif [ -d "$directory" ] then ls "$directory" else continue fi done fi ;; b|B) echo "Specify the ordinary file for backup and hit <Enter>: \c" read file if [ ! -f "$file" ] then while [ ! -f "$file" ] do echo "Usage: "$file" must be an ordinary file." echo "Specify the ordinary file for backup and hit <Enter>: \c" read file if [ "$file" = "q" -o "Q" ] then exit 0 elif [ -f "$file" ] then cp $file $file.bkup fi done fi ;; q|Q) exit 0 ;; esac echo done exit 0 Another thing... is there an editor that I can use to auto-parse code? I.e something similar to NetBeans?

    Read the article

  • Transpose a file in bash

    - by Thrawn
    Hi all, I have a huge tab-separated file formatted like this X column1 column2 column3 row1 0 1 2 row2 3 4 5 row3 6 7 8 row4 9 10 11 I would like to transpose it in an efficient way using only using commands (I could write a ten or so lines Perl script to do that, but it should be slower to execute than the native bash functions). So the output should look like X row1 row2 row3 row4 column1 0 3 6 9 column2 1 4 7 10 column3 2 5 8 11 I thought of a solution like this cols=`head -n 1 input | wc -w` for (( i=1; i <= $cols; i++)) do cut -f $i input | tr $'\n' $'\t' | sed -e "s/\t$/\n/g" >> output done But it's slow and doesn't seem the most efficient solution. I've seen a solution for vi in this post, but it's still over-slow. Any thoughts/suggestions/brilliant ideas? :-)

    Read the article

  • Mixing regular expression and other conditional expression in a bash if statement

    - by Tassos
    I can't get around this for quite sometime now. As I read along manuals and tutorials I'm getting more confused. I want an if statement with the following logic: if [ -n $drupal_version ] && [[ "$drupal_version" =~ DRUPAL-[6-9]-[1-9][1-9] ]]; then but I can't get it to work properly. When the script is evaluated using the "bash -x ... " script construct, works ok but when is run as a regular script my expression is not evaluated (eventhough the above condition should be met the else part is run). Could you provide any help?

    Read the article

  • uppercase to lowercase in bash on a mac

    - by Mala
    Hi I'm writing a bash script which needs to convert a string to lowercase. The problem is I'm doing it on a mac so 'tr' is not available. How can I go about doing this on a mac? The problem I'm trying to tackle is that my script needs to recognize an if an extension is a .gif or a .jpg - and I don't want to have to check for .jpeg, .jPeg, .JPEG, .JPeg, etc etc etc... if there's a smarter way of doing this than just converting to lowercase and testing for gif, jpg and jpeg, i'm all ears :)

    Read the article

  • Editing history in bash

    - by nameanyone
    In bash, when I go back in history, edit some command and run it, this edited command is appended to history and the original one is left intact. But every once in a while I somehow manage to affect the original command, i.e. my edit replaces the original command back in history. I can't put my finger on how this happens. Can someone explain? My goal is to avoid this, so any edit to a previous command always gets appended to history and never replaces the original.

    Read the article

  • Mac OS X bash prompt bug?

    - by Memo
    I am trying to set my bash prompt to display the time and current directory in bold: export PS1="\[\e[1m\][\A] \w \$ \[\e[0m\]" This does apparently work, but when I use the command history (ctrl-r), after finding the command I was searching for and pressing enter, this line is not displayed correctly. Here is an example: [21:58] ~/Wyona/svn-repos/zwischengas $ (reverse-i-search)`ta': tail -F logs/log4j-cnode1.log becomes, after pressing enter: [21:58] ~/Wyona/svn-repos/zwischengas $ -F logs/log4j-cnode1.log Of course, this is not "really" a problem, since the command does work correctly, but it is still annoying. Does anybody know why this happens? And, more importantly, how to prevent/fix it? Thanks, Memo

    Read the article

  • Problem executing bash file

    - by sandelius
    HI there! I've run into some problem while learning to combine .sh files and PHP. I've create a file test.sh and in that file I call a PHP file called test.php. If I double click on the .sh file then it runs perfectly but when I try to run it from the terminal I get "command not found". I'm in the exact folder as my .sh file but it wont work. Here's my test.sh: #!/bin/bash LIB=${0/%cli/} exec php -q ${LIB}test.php one two three exit; When I doubleclick on the test.sh file then it returns the argv array like it suppost to. But why can't I run it from terminal?

    Read the article

  • Bash: Extract Range with Regular Expressioin (maybe sed?)

    - by sixtyfootersdude
    I have a file that is similar to this: <many lines of stuff> SUMMARY: <some lines of stuff> END OF SUMMARY I want to extract just the stuff between SUMMARY and END OF SUMMARY. I suspect I can do this with sed but I am not sure how. I know I can modify the stuff in between with this: sed "/SUMMARY/,/END OF SUMMARY/ s/replace/with/" fileName (But not sure how to just extract that stuff). I am Bash on Solaris.

    Read the article

  • Filtering Filenames with bash

    - by Stefan Liebenberg
    I have a directory full of log files in the form ${name}.log.${year}{month}${day} such that they look like this: logs/ production.log.20100314 production.log.20100321 production.log.20100328 production.log.20100403 production.log.20100410 ... production.log.20100314 production.log.old I'd like to use a bash script to filter out all the logs older than x amount of month's and dump it into *.log.old X=6 #months LIST=*.log.*; for file in LIST; do is_older = file_is_older_than_months( ${file}, ${X} ); if is_older; then cat ${c} >> production.log.old; rm ${c}; fi done; How can I get all the files older than x months? and... How can I avoid that *.log.old file is included in the LIST attribute? Thank you Stefan

    Read the article

  • Importing Python module from the Bash

    - by Morlock
    I am launching a Python script from the command line (Bash) under Linux. I need to open Python, import a module, and then have lines of code interpreted. The console must then remain in Python (not quit it). How do I do that? I have tried an alias like this one: alias program="cd /home/myname/programs/; python; import module; line_of_code" But this only starts python and the commands are not executed (no module import, no line of code treated). What is the proper way of doing this, provided I need to keep Python open (not quit it) after the script is executed? Many thanks.

    Read the article

  • SIMPLE BASH Programming.

    - by atif089
    I am a newbie to BASH so please dont mind my stupid questions because I am not able to get any good sources to learn that. I want to create a script to display filename and its size. This is what the code is like filename=$1 if [ -f $filename ]; then filesize=`du -b $1` echo "The name of file is $1" echo "Its size is $filesize" else echo "The file specified doesnot exists" fi The output is like this $ ./filesize.sh aa The name of file is aa Its size is 88 aa But in the last line I dont want to show the name of the file. How do I do that ? I want to do the same thing using wc as well.

    Read the article

  • List the names of existing directories from .tgz file in a bash variable

    - by Tom
    I would like to find all the directories that are in a .tgz file and that already exist on the system and put the result in a bash variable. I have tried this: EXISTING=`for f in \`tar tzf $ARCHIVE\`; do if [ -d "/tmp/unpacked-data/\$f" ]; then echo \$f; fi; done` with no luck. If I echo the value of $f before the if in the loop, I get all the files, ie this works: EXISTING=`for f in \`tar tzf $ARCHIVE\`; do echo \$f; done` Can someone tell me why the \$f doesn't work in the if statement? Thanks, Tom

    Read the article

  • Remove first element from $@ in bash

    - by Herms
    I'm writing a bash script that needs to loop over the arguments passed into the script. However, the first argument shouldn't be looped over, and instead needs to be checked before the loop. If I didn't have to remove that first element I could just do: for item in "$@" ; do #process item done I could modify the loop to check if it's in its first iteration and change the behavior, but that seems way too hackish. There's got to be a simple way to extract the first argument out and then loop over the rest, but I wasn't able to find it.

    Read the article

  • Sed not working inside bash script

    - by Isabelle
    Hello. I believe this may be a simple question, but I've looked everywhere and tried some workarounds, but I still haven't solved the problem. Problem description: I have to replace a character inside a file and I can do it easily using the command line: sed -e 's/pattern1/pattern2/g' full_path_to_file/file But when I use the same line inside a bash script I can't seem to be able to replace it, and I don't get an error message, just the file contents without the substitution. #!/bin/sh VAR1="patter1" VAR2="patter2" VAR3="full_path_to_file" sed -e 's/${VAR1}/${VAR2}/g' ${VAR3} Any help would be appreciated. Thank you very much for your time.

    Read the article

  • Listing time every second as a Bash script

    - by Caleb
    Hello all, first time here as I've finally started to learn programming. Anyway, I'm just trying to print the time in nanoseconds every second here, and I have this: #!/usr/bin/env bash while true; do date=(date +%N) ; echo $date ; sleep 1 ; done Now, that simply yields a string of date's, which isn't what I want. My learning has been rather messy, so I hope you'll excuse me for this if it's really simple. Also, I did manage to fine this, that worked on the prompt: while true ; do date +%N ; sleep 1 ; done But that obviously doesn't work as a script.

    Read the article

  • Use a grepped file as an included source in bash

    - by Andrew
    I'm on a shared webhost where I don't have permission to edit the global bash configuration file at /ect/bashrc. Unfortunately there is one line in the global file, mesg y, which puts the terminal in tty mode and makes scp and similar commands unavailable. My local ~./bashrc includes the global file as a source, like so: # Source global definitions if [ -f /etc/bashrc ]; then . /etc/bashrc fi My current workaround uses grep to output the global file, sans offending line, into a local file and use that as a source. # Source global definitions if [ -f /etc/bashrc ]; then grep -v mesg /etc/bashrc > ~/.bash_global . ~/.bash_global fi Is there a way to do include a grepped file like this without the intermediate step of creating an actual file? Something like this? . grep -v mesg /etc/bashrc > ~/.bash_global

    Read the article

  • cURL: from PHP to BASH

    - by flienteen
    Hi.. I've never done any curl before so am in need of some help. php: <?php $ch = curl_init(); $data = array( 'uptype'=>'file', 'file'=>'@'.$argv[1], ); curl_setopt($ch, CURLOPT_URL, 'http://my_site_ex/up.php'); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $data); curl_exec($ch); curl_close($ch); ?> how to make the same script in BASH?

    Read the article

  • mkdir error in bash script

    - by Don
    Hi, The following is a fragment of a bash script that I'm running under cygwin on Windows: deployDir=/cygdrive/c/Temp/deploy timestamp=`date +%Y-%m-%d_%H:%M:%S` deployDir=${deployDir}/$timestamp if [ ! -d "$deployDir" ]; then echo "making dir $deployDir" mkdir -p $deploydir fi This produces output such as: making dir /cygdrive/c/Temp/deploy/2010-04-30_11:47:58 mkdir: missing operand Try `mkdir --help' for more information. However, if I type /cygdrive/c/Temp/deploy/2010-04-30_11:47:58 on the command-line it succeeds, why does the same command not work in the script? Thanks, Don

    Read the article

  • Automatic exit from bash shell script on error

    - by radman
    Hi, I've been writing some shell script and I would find it useful if there was the ability to halt the execution of said shell script if any of the commands failed. See below for an example: #!/bin/bash cd some_dir ./configure --some-flags make make install So in this case if the script can't change to the indicated directory then it would certainly not want to do a ./configure afterward it fails. Now I'm well aware that I could have an if check for each command (which I think is a hopeless solution), but is there a global setting to make the script exit if one of the commands fails?

    Read the article

  • bash command history update before execution of command

    - by Jon
    Hi, Bash's command history is great, especially it is useful when adding the history -a command to the COMMAND_PROMPT. However, I'm wondering if there is a way to log the commands to a file as soon as the Return key is pressed, e.g. before starting the command and not on completion of the command (using the COMMAND_PROMPT option would save the command once the prompt is there again). I read about auditing programs like snoopy and session recorder like script but I thought they're already too complex for the simple question I have. I guess that deactivating that script logs all the output of the command would lead already in the right direction but isn't there a quicker way to solve that probelm? Thanks, Jon

    Read the article

  • Parsing getopts in bash

    - by ABach
    I've got a bash function that I'm trying to use getopts with and am having some trouble. The function is designed to be called by itself (getch), with an optional -s flag (getch -s), or with an optional string argument afterward (so getch master and getch -s master are both valid). The snippet below is where my problem lies - it isn't the entire function, but it's what I'm focusing on: getch() { if [ "$#" -gt 2 ] || [ "$1" = "-h" ] || [ "$1" = "--help" ]; then echo "Usage: $0 [-s] [branch-name]" >&2 return 1 fi while getopts "s" opt; do echo $opt # This line is here to test how many times we go through the loop case $opt in s) squash=true shift ;; *) ;; esac done } The getch -s master case is where the strangeness happens. The above should spit out s once, but instead, I get this: [user@host:git-repositories/temp]$ getch -s master s s [user@host:git-repositories/temp]$ Why is it parsing the -s opt twice?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >