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  • How to access a named element in a control that inherits from a templated control

    - by Mrt
    Hello this is similar to http://stackoverflow.com/questions/2620165/how-to-access-a-named-element-of-a-derived-user-control-in-silverlight with the difference is inheriting from a templated control, not a user control. I have a templated control called MyBaseControl <Style TargetType="Problemo:MyBaseControl"> <Setter Property="Template"> <Setter.Value> <ControlTemplate TargetType="Problemo:MyBaseControl"> <Grid x:Name="LayoutRoot" Background="White"> <Border Name="HeaderControl" Background="Red" /> </Grid> </ControlTemplate> </Setter.Value> </Setter> </Style> public class MyBaseControl : Control { public UIElement Header { get; set; } public MyBaseControl() { DefaultStyleKey = typeof(MyBaseControl); } public override void OnApplyTemplate() { base.OnApplyTemplate(); var headerControl = GetTemplateChild("HeaderControl") as ContentPresenter; if (headerControl != null) headerControl.Content = Header; } } I have another control called myControl which inherits from MyBaseControl Control <me:MyBaseControl x:Class="Problemo.MyControl" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" mc:Ignorable="d" xmlns:me="clr-namespace:Problemo" d:DesignHeight="300" d:DesignWidth="400"> <me:MyBaseControl.Header> <TextBlock Name="xxx" /> </me:MyBaseControl.Header> </me:MyBaseControl> public partial class MyControl : MyBaseControl { public string Text { get; set; } public MyControl(string text) { InitializeComponent(); Text = text; Loaded += MyControl_Loaded; } void MyControl_Loaded(object sender, RoutedEventArgs e) { base.ApplyTemplate(); xxx.Text = Text; } } The issue is xxx is null. How do I access the xxx control in the code behind ?

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  • Using memorystream and DotNetZip in MVC gives "Cannot access a closed Stream"

    - by Frode Lillerud
    I'm trying to create a zipfile in a MVC method using the DotNetZip components. Here is my code: public FileResult DownloadImagefilesAsZip() { using (var memoryStream = new MemoryStream()) { using (var zip = new ZipFile()) { zip.AddDirectory(Server.MapPath("/Images/")); zip.Save(memoryStream); return File(memoryStream, "gzip", "images.zip"); } } } When I run it I get a "Cannot access a closed Stream" error, and I'm not sure why.

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  • How to create a bundle

    - by flohei
    Hi there, how do I create a bundle with resources like images and xibs to share it between apps? I saw that there's a way to do it when creating a new project, but there must be a way to do it based on a finished project, right? Thanks in advance –f

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  • Access denied when start sqlexpress from command line

    - by Brettski
    Windows 7 computer running SQL Server Express 2008. When I try to run net start mssql$sqlexpress I receive an error: System error 5 has occurred. Access is denied The SQL service is running under "Network Service" account The service starts fine if I use the services window. Could somebody help me figure out why I am receiving this error?

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  • XML based website - how to create?

    - by Aravind
    I would like to create an xml based website. I want to use xml files as datasources since it is a kind of online directory site. Can someone please give me a starting point? Are there any good online resources that I can refer to? I am pretty confortable with ASP and Javascript. Thank you in advance. Best regards, Aravind

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  • How To Create Per-Request Singleton in Pylons?

    - by dave mankoff
    In our Pylons based web-app, we're creating a class that essentially provides some logging functionality. We need a new instance of this class for each http request that comes in, but only one per request. What is the proper way to go about this? Should we just create the object in middleware and store in in request.environ? Is there a more appropriate way to go about this?

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  • #validate does not seem to work correctly with :on => :create/:update

    - by Tobias
    Greetings, I have a custom validation in my exemplary Movie model: class Movie < ActiveRecord::Base validate :it, :on => :create private def it self.errors.add 'foo', 'bar' end end This works on movie creation but also on updating an existing movie. :on => :update will also work for both. Might that be a bug or am I missing something? Best regards Tobias

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  • Trying to create tiny urls, getting redirect loop.

    - by Gary
    I'm trying to create tiny urls like this: site.com/abc123 goes to: site.com/index.php?token=abc123 but I keep getting redirect loops no matter what I try, or it tries to redirect to index.php?token=index.php.. Current .htaccess is: Options +FollowSymLinks Options -MultiViews RewriteEngine On RewriteRule ^([^/]*)$ /index.php?token=$1 [L]

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  • ASP MVC Access ViewData Array?

    - by Jacob Huggart
    I have some viewdata that is generated by going through my repository to the database to grab some scheduling info. When the information is stored in the Viewdata, I noticed that the viewdata is enumerated. How could I access the enumerated items and generate a table/list based on the viewdata? Most of the information just needs to be spit out into a table, but one item will have a link generated for it. Thanks!

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  • Create page break using OpenXml

    - by arek
    I use OpenXml to create Word document with simple text and some tables under this text. How can I force Paragraph with this text to show always on new page? Maybe this paragraph should be some Header but I'm not sure how to do this. Thanks

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  • how to access owl file inside jsp

    - by Udayanga
    hi, I'm trying to access owl file using jsp.I've successfully load the owl file and quering that using SPARQL.But still I couldn't success with JSP. I'm always getting error "java.lang.ClassNotFoundException: com.hp.hpl.jena.util.FileManager " help me! Thank in advance!

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  • How to create JPA EntityMananger in Spring Context?

    - by HDave
    I have a JPA/Spring application that uses Hibernate as the JPA provider. In one portion of the code, I have to manually create a DAO in my application with the new operator rather than use Spring DI. When I do this, the @PersistenceContext annotation is not processed by Spring. In my code where I create the DAO I have an EntityManagerFactory which I used to set the entityManager as follows: @PersistenceUnit private EntityManagerFactory entityManagerFactory; MyDAO dao = new MyDAOImpl(); dao.setEntityManager(entityManagerFactory.createEntityManager()); The problem is that when I do this, I get a Hibernate error: Could not find UserTransaction in JNDI [java:comp/UserTransaction] It's as if the HibernateEntityManager never received all the settings I've configured in Spring: <bean id="myAppTestLocalEmf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="persistenceUnitName" value="myapp-core" /> <property name="persistenceUnitPostProcessors"> <bean class="com.myapp.core.persist.util.JtaPersistenceUnitPostProcessor"> <property name="jtaDataSource" ref="myappPersistTestJdbcDataSource" /> </bean> </property> <property name="jpaProperties"> <props> <prop key="hibernate.transaction.factory_class">org.hibernate.transaction.JTATransactionFactory</prop> <prop key="hibernate.transaction.manager_lookup_class">com.atomikos.icatch.jta.hibernate3.TransactionManagerLookup</prop> </props> </property> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="showSql" value="true" /> <!-- The following use the PropertyPlaceholderConfigurer but it doesn't work in Eclipse --> <property name="database" value="$DS{hibernate.database}" /> <property name="databasePlatform" value="$DS{hibernate.dialect}" /> I am not sure, but I think the issue might be that I am not creating the entity manager correctly with the plain vanilla createEntityManager() call rather than passing in a map of properties. I say this because when Spring's LocalContainerEntityManagerFactoryBean proxy's the call to Hibernate's createEntityManager() all of the Spring configured options are missing. That is, there is no Map argument to the createEntityManager() call. Perhaps it is another problem entirely however....not sure!

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