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  • redirect images to php script

    - by Jonathan
    I want to be able to redirect all requests to navigate to an image to a php script which will then show the image but with a nav bar at the top. However using rewrite (im using IIS btw) means that I can't embed those images. Any help will be greatly appreciated.

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  • how can I reset field after check it with php

    - by mjd
    Hi all, I have a html form that sends the data from 2 fields (memer no. , pw) via axaj (getElementById)to php file to check them with database info. . I did every thing well but I want to reset both fields if one of them is incorrect . How can I send reset order back to html form ? notice - I didn't use submit button just normal button to keep in same page. Thanks all

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  • php symantics of setting cookies and redirecting without getting header error

    - by salmane
    I would like to do the following in php : setcookie('name', $value, $Cookie_Expiration,'/'); then some action header("location:http://www.example.com") the problem is that I get : warning: Cannot modify header information - headers already sent by (...etc ) could you please let me know what i am doing wrong and if there is a way to do this? by the way , this code is before any output is made ...the cookie setting part works fine on its own and so does the redirection code....the combination fails thank you

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  • Undefined function in php

    - by Bidyut
    I wrote three methods in a class and one is calling another, but when I call the function outside through the object, it is showing an undefined function error for the second function. Here's my code: function resize_image(){ } function image_resize(){ $a = resize_image(); } When I run this, it shows resize_image() as undefined. Here's the error: Fatal error: Call to undefined function resize_image() in /home/vacayge/public_html/Major/Alpha1/classes/cUserImages.php on line 2090

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  • Submitting form in php file accessed by Ajax?

    - by dronnoc
    Hi people, I am trying to figure out how to submit a form in a page being accessed by Ajax? here are some code snippets to help demonstrate what i am trying to say. HTML BODY - THIS IS WHAT THE USER WILL SEE. <html> <head> <script language="javascript" src="linktoajaxfile.js"> </head> <body onLoad="gotoPage(0)"> <div id="fillThis"> </div> </body> </html> AJAX FILE var xmlhttp function gotoPage(phase) { xmlhttp=GetXmlHttpObject(); if (xmlhttp==null) { alert ("Your browser does not support AJAX!"); return; } var url="pageofstuffce.php"; url=url+"?stg="+phase; url=url+"&sid="+Math.random(); xmlhttp.onreadystatechange=stateChanged; xmlhttp.open("GET",url,true); xmlhttp.send(null); } function stateChanged() { if (xmlhttp.readyState==4) { document.getElementById("fillThis").innerHTML=xmlhttp.responseText; } } function GetXmlHttpObject() { if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari return new XMLHttpRequest(); } if (window.ActiveXObject) { // code for IE6, IE5 return new ActiveXObject("Microsoft.XMLHTTP"); } return null; } PAGE OF DATA <?php $stage = $_GET['stg']; if($stage == 0) { echo '<a onClick="gotoPage(1)">click me</a>'; } elseif($stage == 1) { <form> <input type="text" name="name"> <input type="submit" name="submit"> </form> } elseif(somehow can reach here) { show data from form. } ?> Can anyone perhaps help me get past the form and display the data in the same page? Also, i have looked around, and i don't think anything around has what i need... correct me if i'm wrong though :) Thanks in advance, and i hope i didn't put in too much detail :) Dronnoc EDIT Forgot to mention what I've tried; I have tried submitting the form to itself (same file) and that destroyed the ajax link, and opened the page. i have also tried just having the button move the page onto another step, but the $_POST variable is empty... i am at a loss, so does anyone else have any ideas?

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  • Get values from HTML in a multidimensional array and calculate values using PHP

    - by Frank Nwoko
    I have searched but could not get solution on this issue. I am working on an application which will generate unknown number of items and have users select the quantity from a drop down against each item. Eg. Item(s) | price | Select qty Rice 23 3 Beans 22 4 Eggs 52 5 ... ... ... unknown Please, how can I capture the above in an array and also calculate the total value for all selected items and corresponding fees? I have the following HTML code: <form id='form1' name='form1' method='post' action='item_calc.php'> <?php ..... while($t_row = mysql_fetch_assoc($get_items)) { echo "<p><label>$t_row['$item_name'] <input type='text' READONLY name='item_price[]' value='$t_row['$item_price']' /></label> <input type='text' READONLY name='item_fees[]' value='$t_row['$item_fee']' /> <select name="item_qty"> <option value="1"> <option value="2"> <option value="3"> <option value="4"> <option value="5"> </select> </p><p>"; } echo "<label><input type='submit' name='submit' value='Submit' /></label></p> </form>"; Please, how can I get item_price[] + item_fees[] * item_qty for all selected items? This is what I have tried: for ($i = 0; $i < count($_POST['item_price']); $i++) { // Do something here with $_POST['checkbx'][$i] foreach ($_POST['item_fees'] as $tkey => $tvalue) { //echo "Key: $tkey; Value: $tvalue<br>"; } foreach ($_POST['item_price'] as $pkey => $pvalue) { //echo "Key: $pkey; Value: $pvalue<br>"; } $total = $tvalue + $pvalue; } echo $total;

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  • Android : Connecting to MySQL using PHP

    - by user1771128
    I followed the following article http://blog.sptechnolab.com/2011/02/10/android/android-connecting-to-mysql-using-php/ I am able to execute my php file. I executed it individually and its working fine. The problem is in the android execution part. Am posting the Log Cat for the error am facing. Tried putting in a List View with id "list" but the error stil 10-28 16:08:27.201: E/AndroidRuntime(664): **FATAL EXCEPTION: main** 10-28 16:08:27.201: E/AndroidRuntime(664): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.city/com.example.city.City}: java.lang.RuntimeException: Your content must have a ListView whose id attribute is 'android.R.id.list' 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1956) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:1981) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.access$600(ActivityThread.java:123) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1147) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.os.Handler.dispatchMessage(Handler.java:99) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.os.Looper.loop(Looper.java:137) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.main(ActivityThread.java:4424) 10-28 16:08:27.201: E/AndroidRuntime(664): at java.lang.reflect.Method.invokeNative(Native Method) 10-28 16:08:27.201: E/AndroidRuntime(664): at java.lang.reflect.Method.invoke(Method.java:511) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:784) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:551) 10-28 16:08:27.201: E/AndroidRuntime(664): at dalvik.system.NativeStart.main(Native Method) 10-28 16:08:27.201: E/AndroidRuntime(664): Caused by: java.lang.RuntimeException: Your content must have a ListView whose id attribute is 'android.R.id.list' 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ListActivity.onContentChanged(ListActivity.java:243) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.policy.impl.PhoneWindow.setContentView(PhoneWindow.java:254) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Activity.setContentView(Activity.java:1835) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.example.city.City.onCreate(City.java:35) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Activity.performCreate(Activity.java:4465) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1049) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1920) 10-28 16:08:27.201: E/AndroidRuntime(664): ... 11 more

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  • [php] call_user_func_array problems

    - by Knarf
    I have a class with this in self::$DB = new PDO("mysql:dbname=$dbname;host:=127.0.0.1" , 'root' , ''); and then this public static function __callStatic($name, $arguments) { return call_user_func_array(array('self::$DB', $name), $arguments); } How does I make it right/work? Warning: call_user_func_array() expects parameter 1 to be a valid callback, class 'self::$DB' not found in D:\Mine Dokumenter\My Dropbox\www\Framework 3\database.class.php on line 19

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  • php extracting complete url with variables

    - by salmane
    Hi there, Using Php I would like to extract the current Url of a page including all variables attached to it. $_SERVER['PHP_SELF'] only return the url without the variable . any idea what function I need. example : www.site.com/?v1=xyz&v2=123 using $_SERVER['PHP_SELF'] I get only : www.site.com as opposed to the whole url. using $_GET[] individually is not an opton since I am not sure what variable are attached to the URL. thank you

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  • Is there a simple PHP development server?

    - by pinchyfingers
    When writing web apps in Python, it brain dead easy to run a development server. Django and Google App Engine both ship with simple servers. The main feature I'm looking for is no configuration. I want something like the GAE dev server where you just pass the directory of the app as a parameter when the server is started. Is there a reason that this is more difficult with PHP?

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  • unserialize problem in php

    - by Kurt
    hi i'm using serialize/unserialize functions in php 5.2. the text to be stored is POSTed via a form. btw, no white-space before or after. if text contains " or ' it serializes successfully. the problem is it does not unserialize back. what i'm doing wrong?

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  • PHP class function.

    - by Jordan Pagaduan
    What is wrong with this code? <?php class users { var $user_id, $f_name, $l_name, $db_host, $db_user, $db_name, $db_table; function user_input() { $this->$db_host = 'localhost'; $this->$db_user = 'root'; $this->$db_name = 'input_oop'; $this->$db_table = 'users'; } function userInput($f_name, $l_name) { $dbc = mysql_connect($this->db_host , $this->db_user, "") or die ("Cannot connect to database : " .mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "insert into $this->db_table values (NULL, \"$f_name\", \"$l_name\")"; $result = mysql_query($query); if(!$result) die (mysql_error()); $this->userID = mysql_insert_id(); mysql_close($dbc); $this->first_name = $f_name; $this->last_name = $l_name; } function userUpdate($new_f_name, $new_l_name) { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "UPDATE $this->db_table set = \"$new_f_name\" , \"$new_l_name\" WHERE user_id = \"$this->user_id\""; $result = mysql_query($query); $this->f_name = $new_f_name; $this->l_name = $new_l_name; $this->user_id = $user_id; mysql_close($dbc); } function userDelete() { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "DELETE FROM $this->db_table WHERE $user_id = \"$this->user_id\""; mysql_close($dbc); } } ?> The error is: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\jordan_pagaduan\class.php on line 21 Cannot connect to database : Access denied for user 'ODBC'@'localhost' (using password: NO) The code cannot define this "$this->db_host" as "localhost".

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  • How do you create domain.com/?stringhere without a .php extension

    - by matt
    I want to create a link like the following: http://www.myurl.com/?IDHERE What i want to be able to do is be able to goto the above link, and then pull whats after the ? (in this case IDHERE) and be able to use that information to perform a MySQL lookup and return a page. Can anyone point me into the right direction? please know this is using PHP not ASP

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  • Return current web path in PHP

    - by BenTheDesigner
    Hi All Currently developing a PHP framework and have ran into my first problem. I need to be able to drop the framework into any folder on a server, no matter how many folders deep, and need to find that directory to use as a base URL. For example, it currently works if I put the framework in the root of the server (http://cms.dev/), but if I were to put it in http://cms.dev/folder/ it does not work. Please advise, any comments welcome. BenTheDesigner

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