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  • INSERT SELECT Statement and Rollback SQL

    - by Juan Perez
    Im Working on a creation of a query who uses INSERT SELECT statement using MS SQL Server 2008: INSERT INTO TABLE1 (col1, col2) SELECT col1, col2 FROM TABLE2 Right now the excecution of this query is inside a transaction: Pseudocode: try { begin transaction; query; commit; } catch { rollback; } If TABLE2 has around 40m of rows, at the moment of making the insert on the TABLE1, if there is an error in the middle of the INSERT, will the INSERT SELECT statement make a rollback itself or I need to use a transaction to preserve data integrity? It is necessary to use a transaction? or SQL SERVER it self uses a transaction for this type of sentences.

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  • Which of the two ways should I use to insert tags into mysql?

    - by ggfan
    For each ad, I allow users to choose up to 5 tags. Right now, in my database, I have it like... Posting_id TagID 5 1 5 2 5 3 6 5 6 1 But i was thinking if I should make it like... Posting_id TagID 5 1 2 3 6 5 1 Then first option is much easier to insert and retrieve data. But if I have 100 posts with 3 tags each, that's 300 rows...so ALOT more rows The second option requires using explode() impode(), etc but it is much cleaner. Which option should I do and why? thanks!

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  • Mistake in display and insert methods (double-ended queue)

    - by MANAL
    1) My problem when i make remove from right or left program will be remove true but when i call diplay method the content wrong like this I insert 12 43 65 23 and when make remove from left program will remove 12 but when call display method show like this 12 43 65 and when make remove from right program will remove 23 but when call display method show like this 12 43 Why ?????? ); and when i try to make insert after remove write this Can not insert right because the queue is full . first remove right and then u can insert right where is the problem ?? Please Help me please 2) My code FIRST CLASS class dqueue { private int fullsize; //number of all cells private int item_num; // number of busy cells only private int front,rear; public int j; private double [] dqarr; //========================================== public dqueue(int s) //constructor { fullsize = s; front = 0; rear = -1; item_num = 0; dqarr = new double[fullsize]; } //========================================== public void insert(double data) { if (rear == fullsize-1) rear = -1; rear++; dqarr[rear] = data; item_num++; } public double removeLeft() // take item from front of queue { double temp = dqarr[front++]; // get value and incr front if(front == fullsize) front = 0; item_num --; // one less item return temp; } public double removeRight() // take item from rear of queue { double temp = dqarr[rear--]; // get value and decr rear if(rear == -1) // rear = item_num -1; item_num --; // one less item return temp; } //========================================= public void display () //display items { for (int j=0;j<item_num;j++) // for every element System.out.print(dqarr[j] +" " ); // display it System.out.println(""); } //========================================= public int size() //number of items in queue { return item_num; } //========================================== public boolean isEmpty() // true if queue is empty { return (item_num ==0); } } SECOND CLASS import java.util.Scanner; class dqueuetest { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println(" ***** Welcome here***** "); System.out.println(" ***** Mind Of Programming Group***** "); System.out.println(" _____________________________________________ "); System.out.println("enter size of your dqueue"); int size = input.nextInt(); dqueue mydq = new dqueue(size); System.out.println(""); System.out.println("enter your itemes"); //===================================== for(int i = 0;i<=size-1;i++) { System.out.printf("item %d:",i+1); double item = input.nextDouble(); mydq.insert(item); System.out.println(""); } //===================================== int queue =size ; int c = 0 ; while (c != 6) { System.out.println(""); System.out.println("************************************************"); System.out.println(" MAIN MENUE"); System.out.println("1- INSERT RIGHT "); System.out.println("2- REMOVE LEFT"); System.out.println("3- REMOVE RIGHT"); System.out.println("4- DISPLAY"); System.out.println("5- SIZE"); System.out.println("6- EXIT"); System.out.println("************************************************"); System.out.println("choose your operation by number(1-6)"); c = input.nextInt(); switch (c) { case 1: if (queue == size) System.out.print("Can not insert right because the queue is full . first remove right and then u can insert right "); else { System.out.print("enter your item: "); double item = input.nextDouble(); mydq.insert(item);} break; case 2: System.out.println("REMOVE FROM REAR :"); if( !mydq.isEmpty() ) { double item = mydq.removeLeft(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 3: System.out.println("REMOVE FROM FRONT :"); if( !mydq.isEmpty() ) { double item = mydq.removeRight(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 4: System.out.println("The items in Queue are :"); mydq.display(); break; case 5: System.out.println("The Size of the Queue is :"+mydq.size()); break; case 6: System.out.println("Good Bye"); break; default: System.out.println("wrong chiose enter again"); } //end switch } //end while } // end main }//end class

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  • Repeating characters in VIM insert mode

    - by Cthutu
    Is there a way of repeating a character while in Vim's insert mode? For example, say I would like to insert 80 dashes, in something like emacs I would type: Ctrl+U 8 0 - The only way I know how to do it in VIM is to exit normal mode for the repeat argument, then go back into insert mode to type the dash, then exit to insert the actual dashes, AND then go back into insert mode to carry on typing. The sequence is a really long: <ESC> 8 0 a - <ESC> a It would be nice not to switch in and out of modes. Thanks

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  • Can't INSERT INTO SELECT into a table with identity column

    - by Eran Goldin
    In SQL server, I'm using a table variable and when done manipulating it I want to insert its values into a real table that has an identity column which is also the PK. The table variable I'm making has two columns; the physical table has four, the first of which is the identity column, an integer IK. The data types for the columns I want to insert are the same as the target columns' data types. INSERT INTO [dbo].[Message] ([Name], [Type]) SELECT DISTINCT [Code],[MessageType] FROM @TempTableVariable END This fails with Cannot insert duplicate key row in object 'dbo.Message' with unique index 'IX_Message_Id'. The duplicate key value is (ApplicationSelection). But when trying to insert just Values (...) it works ok. How do I get it right?

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  • NHibernate will insert but not update after move to host with shared server running mysql.

    - by Andy LifeBrixx
    Hi, I have a site running MVC and Nhibernate (not fluent) using standard session per request in an http module, runs fine locally (also with mysql) but after a move to a hosting provider no update statements are being issued. I can insert but not update, no exceptions are raised, I have the 'show_sql' option switched on which locally shows the update statements being issued but on the server no update statements are logged. I don't think NHProf is an option for me as I can only run asp.net apps on my shared server, are there any other methods of diagnosing NH issues like this ? Anyone had a similar issue ? Cheers, A

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  • Mistake in dispaly and insert method (double - ended queue)

    - by MANAL
    1) My problem when i make remove from right or left program will be remove true but when i call diplay method the content wrong like this I insert 12 43 65 23 and when make remove from left program will remove 12 but when call display method show like this 12 43 65 and when make remove from right program will remove 23 but when call display method show like this 12 43 Why ?????? ); and when i try to make insert after remove write this Can not insert right because the queue is full . first remove right and then u can insert right where is the problem ?? Please Help me please 2) My code FIRST CLASS class dqueue { private int fullsize; //number of all cells private int item_num; // number of busy cells only private int front,rear; public int j; private double [] dqarr; //========================================== public dqueue(int s) //constructor { fullsize = s; front = 0; rear = -1; item_num = 0; dqarr = new double[fullsize]; } //========================================== public void insert(double data) { if (rear == fullsize-1) rear = -1; rear++; dqarr[rear] = data; item_num++; } public double removeLeft() // take item from front of queue { double temp = dqarr[front++]; // get value and incr front if(front == fullsize) front = 0; item_num --; // one less item return temp; } public double removeRight() // take item from rear of queue { double temp = dqarr[rear--]; // get value and decr rear if(rear == -1) // rear = item_num -1; item_num --; // one less item return temp; } //========================================= public void display () //display items { for (int j=0;j //========================================= public int size() //number of items in queue { return item_num; } //========================================== public boolean isEmpty() // true if queue is empty { return (item_num ==0); } } SECOND CLASS import java.util.Scanner; class dqueuetest { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println(" Welcome here** "); System.out.println(" * Mind Of Programming Group*** "); System.out.println(" _________________________ "); System.out.println("enter size of your dqueue"); int size = input.nextInt(); dqueue mydq = new dqueue(size); System.out.println(""); System.out.println("enter your itemes"); //===================================== for(int i = 0;i<=size-1;i++) { System.out.printf("item %d:",i+1); double item = input.nextDouble(); mydq.insert(item); System.out.println(""); } //===================================== int queue =size ; int c = 0 ; while (c != 6) { System.out.println(""); System.out.println("**************************"); System.out.println(" MAIN MENUE"); System.out.println("1- INSERT RIGHT "); System.out.println("2- REMOVE LEFT"); System.out.println("3- REMOVE RIGHT"); System.out.println("4- DISPLAY"); System.out.println("5- SIZE"); System.out.println("6- EXIT"); System.out.println("**************************"); System.out.println("choose your operation by number(1-6)"); c = input.nextInt(); switch (c) { case 1: if (queue == size) System.out.print("Can not insert right because the queue is full . first remove right and then u can insert right "); else { System.out.print("enter your item: "); double item = input.nextDouble(); mydq.insert(item);} break; case 2: System.out.println("REMOVE FROM REAR :"); if( !mydq.isEmpty() ) { double item = mydq.removeLeft(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 3: System.out.println("REMOVE FROM FRONT :"); if( !mydq.isEmpty() ) { double item = mydq.removeRight(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 4: System.out.println("The items in Queue are :"); mydq.display(); break; case 5: System.out.println("The Size of the Queue is :"+mydq.size()); break; case 6: System.out.println("Good Bye"); break; default: System.out.println("wrong chiose enter again"); } //end switch } //end while } // end main }//end class

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  • Last element not getting insert in Tree

    - by rdk1992
    So I was asked to make a Binary Tree in Haskell taking as input a list of Integers. Below is my code. My problem is that the last element of the list is not getting inserted in the Tree. For example [1,2,3,4] it only inserts to the tree until "3" and 4 is not inserted in the Tree. data ArbolBinario a = Node a (ArbolBinario a) (ArbolBinario a) | EmptyNode deriving(Show) insert(x) EmptyNode= insert(tail x) (Node (head x) EmptyNode EmptyNode) insert(x) (Node e izq der) |x == [] = EmptyNode --I added this line to fix the Prelude.Head Empty List error, after I added this line the last element started to be ignored and not inserted in the tree |head x == e = (Node e izq der) |head x < e = (Node e (insert x izq) der) |head x > e = (Node e izq (insert x der)) Any ideas on whats going on here? Help is much appreciated

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  • Dynamically change MYSQL query within a PHP file using jQuery .post?

    - by John
    Hi, Been trying this for quite a while now and I need help. Basically I have a PHP file that queries database and I want to change the query based on a logged in users name. What happens on my site is that a user logs on with Twitter Oauth and I can display their details (twitter username etc.). I have a database which the user has added information to and I what I would like to happen is when the user logs in with Twitter Oauth, I could use jQuery to take the users username and update the mysql query to show only the results where the user_name = that particular users name. At the moment the mysql query is: "SELECT * FROM markers WHERE user_name = 'dave'" I've tried something like: "SELECT * FROM markers WHERE user_name = '$user_name'" And elsewhere in the PHP file I have $user_name = $_POST['user_name'];. In a separate file (the one in which the user is redirected to after they log in through Twitter) I have some jQuery like this: $(document).ready(function(){ $.post('phpsqlinfo_resultb.php',{user_name:"<?PHP echo $profile_name?>"})}); $profile_name has been defined earlier on that page. I know i'm clearly doing something wrong, i'm still learning. Is there a way to achieve what I want using jQuery to post the users username to the PHP file to change the mysql query to display only the results related to the user that is logged in. I've included the PHP file with the query below: <?php // create a new XML document //$doc = domxml_new_doc('1.0'); $doc = new DomDocument('1.0'); //$root = $doc->create_element('markers'); //$root = $doc->append_child($root); $root = $doc->createElement('markers'); $root = $doc->appendChild($root); $table_id = 'marker'; $user_name = $_POST['user_name']; // Make a MySQL Connection include("phpsqlinfo_addrow.php"); $result = mysql_query("SELECT * FROM markers WHERE user_name = '$user_name'") or die(mysql_error()); // process one row at a time //header("Content-type: text/xml"); header('Content-type: text/xml; charset=utf-8'); while($row = mysql_fetch_assoc($result)) { // add node for each row $occ = $doc->createElement($table_id); $occ = $root->appendChild($occ); $occ->setAttribute('lat', $row['lat']); $occ->setAttribute('lng', $row['lng']); $occ->setAttribute('type', $row['type']); $occ->setAttribute('user_name', utf8_encode($row['user_name'])); $occ->setAttribute('name', utf8_encode($row['name'])); $occ->setAttribute('tweet', utf8_encode($row['tweet'])); $occ->setAttribute('image', utf8_encode($row['image'])); } // while $xml_string = $doc->saveXML(); $user_name2->response; echo $xml_string; ?> This is for use with a google map mashup im trying to do. Many thanks if you can help me. If my question isn't clear enough, please say and i'll try to clarify for you. I'm sure this is a simple fix, i'm just relatively inexperienced to do it. Been at this for two days and i'm running out of time unfortunately.

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  • nginx+mysql5 loadtesting configuration strangeness

    - by genseric
    i am trying to setup a new server running on debian6 and trying to make it work smooth under load. i ve used a wordpress site as a test object, and tried the configurations on http://blitz.io. when i increase the mysql max_connections from 50 to 200 lots of timeouts start to occur. but on 50 , no timeouts and pretty well response times. nginx configuration is fine , i tuned the config so i dont see errors. so i presume it's related to the other configuration options of my.cnf . i read some about options but still cant find what max_connections problem is all about. btw, the server has 16gb of ram and a fine i7 cpu. here is the current my.cnf [client] port = 3306 socket = /var/run/mysqld/mysqld.sock [mysqld_safe] socket = /var/run/mysqld/mysqld.sock nice = 0 [mysqld] wait_timeout=60 connect_timeout=10 interactive_timeout=120 user = mysql pid-file = /var/run/mysqld/mysqld.pid socket = /var/run/mysqld/mysqld.sock port = 3306 basedir = /usr datadir = /var/lib/mysql tmpdir = /tmp language = /usr/share/mysql/english skip-external-locking bind-address = 127.0.0.1 key_buffer = 384M max_allowed_packet = 16M thread_stack = 192K thread_cache_size = 20 myisam-recover = BACKUP max_connections = 50 table_cache = 1024 thread_concurrency = 8 query_cache_limit = 2M query_cache_size = 128M expire_logs_days = 10 max_binlog_size = 100M [mysqldump] quick quote-names max_allowed_packet = 16M [mysql] #no-auto-rehash # faster start of mysql but no tab completition [isamchk] key_buffer = 16M thanks in advance. i asked this question on SO but it's closed as off topic so i believe this is a SF question.

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  • fatal error 'stdio.h' Python 2.7 on Mc OS X 10.7.5 [closed]

    - by DjangoRocks
    I have this weird issue on my Mac OS X 10.7.5 /Library/Frameworks/Python.framework/Versions/2.7/include/python2.7/Python.h:33:10: fatal error: 'stdio.h' file not found What caused the above error? This error has been bugging me and i can't install mysql-python as i'm stuck with this step. I'm using Python 2.7.3. Things like Google App Engine ( python ), python script, tornado generally works on my mac. But not mysql-python. I've install MySQL using the dmg image and have copied the mysql folder to /usr/local/ How do i fix this? ======UPDATE====== I've ran the command, and tried to install mysql-python by running sudo python setup.py install. But received the following: running install running bdist_egg running egg_info writing MySQL_python.egg-info/PKG-INFO writing top-level names to MySQL_python.egg-info/top_level.txt writing dependency_links to MySQL_python.egg-info/dependency_links.txt writing MySQL_python.egg-info/PKG-INFO writing top-level names to MySQL_python.egg-info/top_level.txt writing dependency_links to MySQL_python.egg-info/dependency_links.txt reading manifest file 'MySQL_python.egg-info/SOURCES.txt' reading manifest template 'MANIFEST.in' writing manifest file 'MySQL_python.egg-info/SOURCES.txt' installing library code to build/bdist.macosx-10.6-intel/egg running install_lib running build_py copying MySQLdb/release.py -> build/lib.macosx-10.6-intel-2.7/MySQLdb running build_ext gcc-4.2 not found, using clang instead building '_mysql' extension clang -fno-strict-aliasing -fno-common -dynamic -g -O2 -DNDEBUG -g -O3 -Dversion_info=(1,2,4,'rc',5) -D__version__=1.2.4c1 -I/usr/local/mysql/include -I/Library/Frameworks/Python.framework/Versions/2.7/include/python2.7 -c _mysql.c -o build/temp.macosx-10.6-intel-2.7/_mysql.o -Os -g -fno-common -fno-strict-aliasing -arch x86_64 In file included from _mysql.c:29: /Library/Frameworks/Python.framework/Versions/2.7/include/python2.7/Python.h:33:10: fatal error: 'stdio.h' file not found #include <stdio.h> ^ 1 error generated. error: command 'clang' failed with exit status 1 What other possible ways can i fix it? thanks! Best Regards.

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  • Can't login to phpMyAdmin on a WAMP server running Windows 2008

    - by Richard West
    I am setting up a new server. I have installed Apache 2.2.17, PHP 5.3.3, MySQL 5.1.53 and phpMyAdmin 3.3.8 running on a Windows 2008 (32 bit) OS. I have configured Apache and PHP so they appear to be working fine. I have created the standard test php page with the following code and everything appears to be working fine. <?php //index.php phpinfo(); ?> I also see the mySQL and mySQLi section in the above webpage, so it appears that that I have the proper extensions loaded for mySQL access. The problem that I am having centeres around myPHPAdmin. I have this installed and I can access to the login screen at http://localhost/pma I login using "root" and the password I have setup for root. After a delay of 30 seconds or so the web page goes to a blank screen, and the url is now http://localhost/pma/index.php?token= No error is ever displayed - however nothing usable is either. I have confirmed that mySQL is running by going to the command line and logging into mySQL from there. I have double checked my configuration but I am not having any luck getting this to work. I have also disabled the Windows firewall, but that did not change anything. I installed mySQL using the standard port 3306. Any advice would be greatly appreciated.

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  • PhpMyAdmin import/export - strange character encoding issues.

    - by John Hunt
    Hello, I'm migrating a site to a new host, and there are a couple of databases on there. There's no SSH access so I'm stuck with phpmyadmin. The issue is that certain characters (namely just whitespace) seems to being corrupt on the new site (same html, and apache doesn't seem to be messing with any encodings - you can see the strange characters have changed when I use less on my linux machine after downloading a table dump from both servers.) The issue isn't as bad if I import into the new database as utf-8 - whitespace characters only have one funny A type symbol instead of two. I've been trying various combinations of character encoding etc to no avail. Exporting from: phpMyAdmin 2.6.2 MySQL 4.1.20 MySQL connection collation: utf8_general_ci MySQL charset: UTF-8 Unicode (utf8) Collation on tables and their fields is: latin1_swedish_ci Importing to: phpMyAdmin - 2.11.9.2 MySQL client version: 5.0.45 MySQL charset: UTF-8 Unicode (utf8) MySQL connection collation: utf8_general_ci The import sql has this kind of thing in it: ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=192 ; I get the impression this is actually a bug or something with mysqldump as nothing seems to work.. does anyone have any insight into this? Cheers, John.

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  • mysqldump isn't able to export a specific database, phpMyAdmin crashes

    - by Devils Child
    I'm experiencing problems with a database on my server (Note: All other databases work fine). Once I try to export it with mysqldump I get this error: # mysqldump -u root -pXXXXXXXXX databasename > /root/databasename.sql mysqldump: Couldn't execute 'show table status like 'apps'': Lost connection to MySQL server during query (2013) Also, phpMyAdmin throws an error when selecting this database and immediately logs out. However, the web site which uses this database works fine. I can also execute SELECT statements on the table named "apps" from the MySQL shell. I tried restarting the MySQL daemon as well as REPAIR DATABASE and REPAIR TABLE but the problem still persists. I had this problem before, then it disappeared somehow without me doing anything to resolve the issue. Now, the problem is back and I'm simply unable to create a backup of this database. Used software Debian 6.0.7 x64 MySQL 5.1.66-0 MySQL Version: mysql> SHOW VARIABLES LIKE "%version%"; +-------------------------+-------------------+ | Variable_name | Value | +-------------------------+-------------------+ | protocol_version | 10 | | version | 5.1.66-0+squeeze1 | | version_comment | (Debian) | | version_compile_machine | x86_64 | | version_compile_os | debian-linux-gnu | +-------------------------+-------------------+

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  • PostgreSQL insert on primary key failing with contention, even at serializable level

    - by Steven Schlansker
    I'm trying to insert or update data in a PostgreSQL db. The simplest case is a key-value pairing (the actual data is more complicated, but this is the smallest clear example) When you set a value, I'd like it to insert if the key is not there, otherwise update. Sadly Postgres does not have an insert or update statement, so I have to emulate it myself. I've been working with the idea of basically SELECTing whether the key exists, and then running the appropriate INSERT or UPDATE. Now clearly this needs to be be in a transaction or all manner of bad things could happen. However, this is not working exactly how I'd like it to - I understand that there are limitations to serializable transactions, but I'm not sure how to work around this one. Here's the situation - ab: => set transaction isolation level serializable; a: => select count(1) from table where id=1; --> 0 b: => select count(1) from table where id=1; --> 0 a: => insert into table values(1); --> 1 b: => insert into table values(1); --> ERROR: duplicate key value violates unique constraint "serial_test_pkey" Now I would expect it to throw the usual "couldn't commit due to concurrent update" but I'm guessing since the inserts are different "rows" this does not happen. Is there an easy way to work around this?

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  • Using OUTPUT/INTO within instead of insert trigger invalidates 'inserted' table

    - by Dan
    I have a problem using a table with an instead of insert trigger. The table I created contains an identity column. I need to use an instead of insert trigger on this table. I also need to see the value of the newly inserted identity from within my trigger which requires the use of OUTPUT/INTO within the trigger. The problem is then that clients that perform INSERTs cannot see the inserted values. For example, I create a simple table: CREATE TABLE [MyTable]( [MyID] [int] IDENTITY(1,1) NOT NULL, [MyBit] [bit] NOT NULL, CONSTRAINT [PK_MyTable_MyID] PRIMARY KEY NONCLUSTERED ( [MyID] ASC )) Next I create a simple instead of trigger: create trigger [trMyTableInsert] on [MyTable] instead of insert as BEGIN DECLARE @InsertedRows table( MyID int, MyBit bit); INSERT INTO [MyTable] ([MyBit]) OUTPUT inserted.MyID, inserted.MyBit INTO @InsertedRows SELECT inserted.MyBit FROM inserted; -- LOGIC NOT SHOWN HERE THAT USES @InsertedRows END; Lastly, I attempt to perform an insert and retrieve the inserted values: DECLARE @tbl TABLE (myID INT) insert into MyTable (MyBit) OUTPUT inserted.MyID INTO @tbl VALUES (1) SELECT * from @tbl The issue is all I ever get back is zero. I can see the row was correctly inserted into the table. I also know that if I remove the OUTPUT/INTO from within the trigger this problem goes away. Any thoughts as to what I'm doing wrong? Or is how I want to do things not feasible? Thanks.

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  • SQL Server INSERT ... SELECT Statement won't parse

    - by Jim Barnett
    I am getting the following error message with SQL Server 2005 Msg 120, Level 15, State 1, Procedure usp_AttributeActivitiesForDateRange, Line 18 The select list for the INSERT statement contains fewer items than the insert list. The number of SELECT values must match the number of INSERT columns. I have copy and pasted the select list and insert list into excel and verified there are the same number of items in each list. Both tables an additional primary key field with is not listed in either the insert statement or select list. I am not sure if that is relevant, but suspicious it may be. Here is the source for my stored procedure: CREATE PROCEDURE [dbo].[usp_AttributeActivitiesForDateRange] ( @dtmFrom DATETIME, @dtmTo DATETIME ) AS BEGIN SET NOCOUNT ON; DECLARE @dtmToWithTime DATETIME SET @dtmToWithTime = DATEADD(hh, 23, DATEADD(mi, 59, DATEADD(s, 59, @dtmTo))); -- Get uncontested DC activities INSERT INTO AttributedDoubleClickActivities ([Time], [User-ID], [IP], [Advertiser-ID], [Buy-ID], [Ad-ID], [Ad-Jumpto], [Creative-ID], [Creative-Version], [Creative-Size-ID], [Site-ID], [Page-ID], [Country-ID], [State Province], [Areacode], [OS-ID], [Domain-ID], [Keyword], [Local-User-ID], [Activity-Type], [Activity-Sub-Type], [Quantity], [Revenue], [Transaction-ID], [Other-Data], Ordinal, [Click-Time], [Event-ID]) SELECT [Time], [User-ID], [IP], [Advertiser-ID], [Buy-ID], [Ad-ID], [Ad-Jumpto], [Creative-ID], [Creative-Version], [Creative-Size-ID], [Site-ID], [Page-ID], [Country-ID], [State Province], [Areacode], [OS-ID], [Domain-ID], [Keyword], [Local-User-ID] [Activity-Type], [Activity-Sub-Type], [Quantity], [Revenue], [Transaction-ID], [Other-Data], REPLACE(Ordinal, '?', '') AS Ordinal, [Click-Time], [Event-ID] FROM Activity_Reports WHERE [Time] BETWEEN @dtmFrom AND @dtmTo AND REPLACE(Ordinal, '?', '') IN (SELECT REPLACE(Ordinal, '?', '') FROM Activity_Reports WHERE [Time] BETWEEN @dtmFrom AND @dtmTo EXCEPT SELECT CONVERT(VARCHAR, TripID) FROM VisualSciencesActivities WHERE [Time] BETWEEN @dtmFrom AND @dtmTo); END GO

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  • Not able to insert data in the database from a form in php

    - by Prashant Baid
    I am not able to insert data into my data, i dont know what the problem is. Here is the code: mysql_select_db("mitestore", $con); */ if ((isset($_POST['product_name'])) && (strlen(trim($_POST['product_name'])) 0)) { $product_name = stripslashes(strip_tags($_POST['product_name'])); $sql="INSERT INTO sell (product_name) VALUE ('$_POST[product_name]')"; } else {$product_name = 'Please enter the product name.';} if ((isset($_POST[''])) && (strlen(trim($_POST['how_old'])) 0)) { $how_old = stripslashes(strip_tags($_POST['how_old'])); $sql="INSERT INTO sell (how_old) VALUE ('$_POST[how_old]')"; } else {$how_old = 'Please enter how old your product is';} if ((isset($_POST['which_block'])) && (strlen(trim($_POST['which_block'])) 0)) { $which_block = stripslashes(strip_tags($_POST['which_block'])); $sql="INSERT INTO sell (which_block) VALUE ('$_POST[which_block]')"; } else {$which_block = 'Please enter which block are you from';} if ((isset($_POST['room_no'])) && (strlen(trim($_POST['room_no'])) 0)) { $room_no = stripslashes(strip_tags($_POST['room_no'])); $sql="INSERT INTO sell (room_no) VALUE ('$_POST[room_no]')"; } else {$room_no = 'Please enter the room no:';} if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Success!"; mysql_close($con) ? Initially i had this code and it worked for me. mysql_select_db("database", $con); $sql="INSERT INTO sell ( product_name, how_old , selling_price, negotiable, which_block, room_no) VALUES ('$_POST[product_name]','$_POST[how_old]','$_POST[selling_price]','$_POST[negotiable]','$_POST[which_block]','$_POST[room_no]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Your product is added."; mysql_close($con) ? But i don't know how to validate each field individually.

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  • INSERT..ON DUPLICATE KEY UPDATE - but NOT using the duplicate key to compare.

    - by calumbrodie
    I am trying to solve a problem I have inherited with poor treatment of different data sources. I have a user table that contains BOTH good and evil users. create table `users`( `user_id` int(13) NOT NULL AUTO_INCREMENT , `email` varchar(255) , `name` varchar(255) , PRIMARY KEY (`user_id`) ); In this table the primary key is currently set to be user_id. I have another table ('users_evil') which contains ONLY the evil users (all the users from this table are included in the first table) - the user_id's on this table do NOT correspond to those in the first table. I want to have all my users in one table, and simply flag which are good and which are evil. What I want to do is alter the user table and add a column ('evil') which defaults to 0. I then want to dump the data from my 'users_evil') table and then run an INSERT..ON DUPLICATE KEY UPDATE with this data into the first table (setting 'evil'=1 where the emails match) The problem is that the 'PK' is set to the user_id and not the 'email'. Any suggestions, or even another strategy to successfully achive this. Can I run this statement but treat another column as PK only for the duration of the statement.

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  • F# insert/remove item from list

    - by Timothy
    How should I go about removing a given element from a list? As an example, say I have list ['A'; 'B'; 'C'; 'D'; 'E'] and want to remove the element at index 2 to produce the list ['A'; 'B'; 'D'; 'E']? I've already written the following code which accomplishes the task, but it seems rather inefficient to traverse the start of the list when I already know the index. let remove lst i = let rec remove lst lst' = match lst with | [] -> lst' | h::t -> if List.length lst = i then lst' @ t else remove t (lst' @ [h]) remove lst [] let myList = ['A'; 'B'; 'C'; 'D'; 'E'] let newList = remove myList 2 Alternatively, how should I insert an element at a given position? My code is similar to the above approach and most likely inefficient as well. let insert lst i x = let rec insert lst lst' = match lst with | [] -> lst' | h::t -> if List.length lst = i then lst' @ [x] @ lst else insert t (lst' @ [h]) insert lst [] let myList = ['A'; 'B'; 'D'; 'E'] let newList = insert myList 2 'C'

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  • How do you fix a MySQL “Incorrect key file” error when you can’t repair the table?

    - by Wayne M
    I'm trying to run a rather large query that is supposed to run nightly to populate a table. I'm getting an error saying Incorrect key file for table '/var/tmp/#sql_201e_0.MYI'; try to repair it but the storage engine I'm using (whatever the default is, I guess?) doesn't support repairing tables. how do I fix this so I can run the query? We are under pressure to get this table loaded for a client.

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  • can 'Percona MySQL Data Recovery' be used to recover dropped tables if the datadir filesystem is mounted as /

    - by Tom Geee
    according to Percona: Unmount the filesystem or make it read-only if... You have filesystem corruption OR You have dropped tables in innodb_file_per_table format If I have innodb_file_per_table enabled, and accidently dropped a table, while the datadir is mounted as within the / partition , can data still be recovered? Obviously you can't work with an unmounted root filesystem. Our VPS host has a defaulted filesystem table which we cannot customize. I was wondering in case of any future scenario. edit: would mounting the / filesystem through NFS onto another system as read-only be a workaround? TIA.

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  • insert newline in perl -e statement

    - by lydonchandra
    Hi If I do this in bash perl -e '$x; $y' How can I insert a new line between the character ; and $y? I don't want to re-type the whole line, I just want to move my cursor to the position and then insert a newline ? Is this possible? Many thanks

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  • PHPMyAdmin works with https Only (not http)

    - by 01010011
    Hi I've been having a problem getting phpmyadmin to work consistently on my XP desktop and laptop computers for months now. When I type into Chrome's browser on both machines, localhost/phpmyadmin, I kept getting Error #1045 Access Denied for user at root@localhost (using password yes). Eventually, I realized that I had two (2) versions of mysql installed (XAMPP and MySQL Server 5.1) on both machines. So I uninstalled the MySQL Server 5.1I from the desktop and phpmyadmin worked. But when I uninstalled MySQL Server 5.1 from my laptop, it did not work. But I realized I could still get into MySQL Commandline Client using my password and that my databases were still intact. So I uninstalled and reinstalled XAMPP on the laptop and phpmyadmin worked after that. Now I have a new problem. On phpMyAdmin's home page has a message at the bottom: Your configuration file contains settings (root with no password) that correspond to the default MySQL privileged account. Your MySQL server is running with this default, is open to intrusion, and you really should fix this security hole by setting a password for user 'root'. So I located the following lines in config.inc.php file: /* Authentication type and info */ $cfg['Servers'][$i]['auth_type'] = 'config'; $cfg['Servers'][$i]['user'] = 'root'; $cfg['Servers'][$i]['password'] = ''; $cfg['Servers'][$i]['AllowNoPassword'] = true; and I just changed the last 2 lines as follows: $cfg['Servers'][$i]['password'] = 'mypassword'; $cfg['Servers'][$i]['AllowNoPassword'] = false; As soon as I did that and I tried to access phpmyadmin again, I got the Error #1045 message again, but when I tried https://localhost/phpmyadmin/ I got a red page saying this sites certificate is not trusted would you like to proceed anyway. And now it only works using https. I would really like to settle all my phpmyadmin problems once and for all so here are my questions: 1. Why does my laptop only access phpmyadmin via https? 2. How do I change my password in my configuration file? Also, if you have any other tips regarding phpMyAdmin, they are very welcome. Thanks in advance

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