Search Results

Search found 14079 results on 564 pages for 'folding at home'.

Page 223/564 | < Previous Page | 219 220 221 222 223 224 225 226 227 228 229 230  | Next Page >

  • popup with dynamic menuitems, each menuitem is another popup

    - by encryptor
    I am building an extension that has a pop up whose elements are constructed by a function call everytime the mouse hovers over the popup option. I am able to achieve this. Now I need to have a popup for each of the menu item (inside the original popup) which is not dynamic though. I have this code, but it does not work: for (var m=0; m < localpubliclist.length; m++) { var newItem = document.createElement("menu"); newItem.setAttribute("label", publicdisplayname[m]); newItem.setAttribute("id", "public" + m); myMenuPopup.appendChild(newItem); var newpopup = document.createElement("menupopup"); newpopup.setAttribute("id","publicpop" + m); newItem.appendChild(newpopup); var new1= document.createElement("menuitem"); new1.setAttribute("label", "Home"); new1.setAttribute("id", "publichome" + m); newpopup.appendChild(new1); } doing this forms the first popup where i can see all my menu with names publicdisplayname[m]. each of these is to be a popup which displays "Home". This does not work. the second popup (popup on publicdisplayname[m]) does not open. i have been stuck on this for quite some time and have tried various things cut it doesnt work. Can we do this at all? can we have double dynamic popups?

    Read the article

  • ASP.NET MVC 2 router matches correct area route but generates URL to the first registered area inste

    - by Sandor Drieënhuizen
    I'm working on a S#arpArchitecture 1.5 project, which uses ASP.NET MVC 2. I've been trying to get areas to work properly but I ran into a problem: The ASP.NET MVC 2 routing engine matches the correct route to my area but then it generates an URL that belongs to the first registered area instead. Here's my request URL: /Framework/Authentication/LogOn?ReturnUrl=%2fDefault.aspx I'm using the Route Tester from Phil Haack and it shows: Matched Route: Framework/{controller}/{action}/{id} Generated URL: /Data/Authentication/LogOn?ReturnUrl=%2FDefault.aspx using the route "Data/{controller}/{action}/{id}" That's clearly wrong, the URL should point to the Framework area, not the Data area. This is how I register my routes, nothing special there IMO. private static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); AreaRegistration.RegisterAllAreas(); routes.MapRoute( "default", "{controller}/{action}/{id}", new { controller = "Home", action = "Index", id = UrlParameter.Optional }); } The area registration classes all look like this. Again, nothing special. public class FrameworkAreaRegistration : AreaRegistration { public override string AreaName { get { return "Framework"; } } public override void RegisterArea(AreaRegistrationContext context) { context.MapRoute( "Framework_default", "Framework/{controller}/{action}/{id}", new { controller = "Home", action = "Index", id = UrlParameter.Optional }); } }

    Read the article

  • How to set up RPX widget and facebook app to be able to authenticate with rpx_now?

    - by Andrei
    Using the sample app for rpx_now gem ( http://github.com/grosser/rpx_now_example) on localhost:3000, I have successfully logged in via Google Accounts, myOpenID, Yahoo, but cannot make it via Facebook. In the RPX app/widget settings I have set my facebook-app key and secret. In my facebook app settings, the Connect URL is myappname.rpxnow.com. But when I try to connect, then I don't even see a facebook login page, just a number of redirects and I am back to my localhost with the following exception http://gist.github.com/386520 . Before I was successfully connecting with oauth2 gem, however, without fetching user data - only authentication. That time I set only key/secret and localhost as my Connect URL. Currently, I don't even ask for email etc., but still the same problem. Can it happen because rpx_now cannot get requested user data from facebook? Or it is a problem of facebook key/secret? May be I need to provide more settings of my facebook app? RPXNow::ApiError in UsersController#create Got error: Invalid parameter: token (code: 1), HTTP status: 200 RAILS_ROOT: /home/Andrei/rpx_now_example Application Trace | Framework Trace | Full Trace /usr/lib/ruby/gems/1.8/gems/rpx_now-0.6.20/lib/rpx_now/api.rb:71:in `parse_response' /usr/lib/ruby/gems/1.8/gems/rpx_now-0.6.20/lib/rpx_now/api.rb:21:in `call' /usr/lib/ruby/gems/1.8/gems/rpx_now-0.6.20/lib/rpx_now.rb:23:in `user_data' /home/Andrei/rpx_now_example/app/controllers/users_controller.rb:16:in `create' Request Parameters: None Show session dump Response Headers: {"Content-Type"="", "Cache-Control"="no-cache"}

    Read the article

  • Can the same ssh key be used to access two different users on the same server?

    - by Nick
    I have an new ubuntu (hardy 8.04) server, it has two users, User1 and User2. User1 is listed in sudoers. I appended my public ssh key to authorized_keys in /home/user1/.ssh/authorized_keys, changed the permissions on user1/.ssh/ to 700 and user1/.ssh/authorized_keys to 600 and both file and folder are owned my User1. Then added I User1 to sshd_config (AllowUsers User1). This works and I can login into User1 debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from 86.141.61.197 I then copied the authorized_keys file to /home/user2/.shh/ and changed the permissions and ownership and added User2 to AllowUsers in sshd_config (AllowUsers User1 User2). Now when I try to login to User2 it will not authenticate the same public key. debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works? Thanks in advance, Nick

    Read the article

  • Jetty startup delay

    - by Tauren
    I'm trying to figure out what would be causing a 1 minute delay in the startup of Jetty. Is it a configuration problem, my application, or something else? I have Jetty 7 (jetty-7.0.1.v20091125 25 November 2009) installed on a server and I deploy a 45MB ROOT.war file into the webapps directory. This is the only webapp configured in Jetty. I then start Jetty with the command: java -DSTOP.PORT=8079 -DSTOP.KEY=mystopkey -Denv=stage -jar start.jar etc/jetty-logging.xml etc/jetty.xml & I get two lines of output right after doing this: 2010-03-07 14:20:06.642:INFO::Logging to StdErrLog::DEBUG=false via org.eclipse.jetty.util.log.StdErrLog 2010-03-07 14:20:06.710:INFO::Redirecting stderr/stdout to /home/zing/jetty-distribution-7.0.1.v20091125/logs/2010_03_07.stderrout.log When I press the enter key, I get my command prompt back. Looking at the log file (logs/2010_03_07.stderrout.log), I see the following at the beginning: 2010-03-07 14:08:50.396:INFO::jetty-7.0.1.v20091125 2010-03-07 14:08:50.495:INFO::Extract jar:file:/home/zing/jetty-distribution-7.0.1.v20091125/webapps/ROOT.war!/ to /tmp/Jetty_0_0_0_0_8080_ROOT.war___.8te0nm/webapp 2010-03-07 14:08:52.599:INFO::NO JSP Support for , did not find org.apache.jasper.servlet.JspServlet 2010-03-07 14:09:51.379:INFO::Set web app root system property: 'webapp.root' = [/tmp/Jetty_0_0_0_0_8080_ROOT.war___.8te0nm/webapp] 2010-03-07 14:09:51.585:INFO::Initializing Spring root WebApplicationContext INFO - ContextLoader - Root WebApplicationContext: initialization started INFO - XmlWebApplicationContext - Refreshing Root WebApplicationContext: startup date [Sun Mar 07 14:09:51 PST 2010]; root of context hierarchy ... Notice the 1 minute long pause between the 3rd and 4th lines. What is Jetty doing at this point? What other things could be going on? It doesn't even look like it has started my Spring initialization yet. Note that I checked my /tmp directory to see if it was simply the time to unpack my war file, but the file had been completely unpacked even at the start of this 1 minute delay.

    Read the article

  • move_uploaded_file() error

    - by James R.
    I have a website on free hosting - 000webhost.com and it allows you to upload images. However, when I try to upload an image, I get these errors: Warning: move_uploaded_file(images/SmallSmileyFace.jpg) [function.move-uploaded-file]: failed to open stream: Permission denied in /home/a6621074/public_html/m/write.php on line 76 Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move '/tmp/phpcmW3mo' to 'images/SmallSmileyFace.jpg' in /home/a6621074/public_html/m/write.php on line 76 This is the code: if (!empty($_FILES['fileImage']['name'])) { // check image type and size if ((($imagetype == 'image/gif') || ($imagetype == 'image/jpeg') || ($imagetype == 'image/pjpeg') || ($imagetype == 'image/png')) && ($imagesize > 0) && ($imagesize <= 32768)) { if ($_FILES['fileImage']['error'] == 0) { //move file $target = 'images/' . $image; if (move_uploaded_file($_FILES['fileImage']['tmp_name'], $target)) { $query = "INSERT INTO reviews (post_date, food_name, location, cafeteria, review, image, rating, user_id) VALUES (NOW(), '$foodname', '$location', '$cafeteria', '$review', '$image', $rate, $id)"; mysqli_query($dbc, $query); //confirm success echo '<p>Thank you for your submission!</p>'; } else { echo '<p class="errmsg">There was a problem uploading your image.</p>'; } } @unlink($_FILES['fileImage']['tmp_name']); } else { echo '<p class="errmsg">The screen shot must be a GIF, JPEG, or PNG image file no greater than 32KB in size.</p>'; } } Any ideas?

    Read the article

  • jqGrid - edit function never getting called

    - by dcp
    I'm having a problem with JQGrid using ASP.NET MVC. I'm trying to follow this example (after you go to that link, over on the left side of the page please click Live Data Manipulation, then Edit Row), but my edit function is never getting called (i.e. it's never getting into the $("#bedata").click(function(). Does anyone know what could be the problem? <script type="text/javascript"> var lastsel2; jQuery(document).ready(function() { jQuery("#editgrid").jqGrid({ url: '/Home/GetMovieData/', datatype: 'json', mtype: 'GET', colNames: ['id', 'Movie Name', 'Directed By', 'Release Date', 'IMDB Rating', 'Plot', 'ImageURL'], colModel: [ { name: 'id', index: 'Id', width: 55, sortable: false, hidden: true, editable: false, editoptions: { readonly: true, size: 10} }, { name: 'Movie Name', index: 'Name', width: 250, editable: true, editoptions: { size: 10} }, { name: 'Directed By', index: 'Director', width: 250, align: 'right', editable: true, editoptions: { size: 10} }, { name: 'Release Date', index: 'ReleaseDate', width: 100, align: 'right', editable: true, editoptions: { size: 10} }, { name: 'IMDB Rating', index: 'IMDBUserRating', width: 100, align: 'right', editable: true, editoptions: { size: 10} }, { name: 'Plot', index: 'Plot', width: 150, hidden: false, editable: true, editoptions: { size: 30} }, { name: 'ImageURL', index: 'ImageURL', width: 55, hidden: true, editable: false, editoptions: { readonly: true, size: 10} } ], pager: jQuery('#pager'), rowNum: 5, rowList: [5, 10, 20], sortname: 'id', sortorder: "desc", height: '100%', width: '100%', viewrecords: true, imgpath: '/Content/jqGridCss/redmond/images', caption: 'Movies from 2008', editurl: '/Home/EditMovieData/', caption: 'Movie List' }); }); $("#bedata").click(function() { var gr = jQuery("#editgrid").jqGrid('getGridParam', 'selrow'); if (gr != null) jQuery("#editgrid").jqGrid('editGridRow', gr, { height: 280, reloadAfterSubmit: false }); else alert("Hey dork, please select a row"); }); </script> The relevant HTML is here: <table id="editgrid"> </table> <div id="pager" style="text-align: center;"> </div> <input type="button" id="bedata" value="Edit Selected" />

    Read the article

  • Source Control - XCode - Visual Studio 2005/2008 / 2010

    - by Mick Walker
    My apologies if this has been asked before, I wasnt quite sure if this question should be asked on a programming forum, as it more relates to programming environment than a particular technology, so please accept my (double) appologies if I am posting this in the wrong place, my logic in this case was if it effects the code I write, then this is the place for it. At home, I do a lot of my development on a Mac Pro, I do development for the Mac, iPhone and Windows on this machine (Xcode & Visual Studio - (multiple versions installed in bootcamp, but generally I run it via Parallels)). When visiting a client, I have a similar setup, but on my MacBook Pro. What I want is a source control solution to install on the Mac Pro, that will support both XCode and multiple versions of visual studio, so that when I visit a client, I can simply grab the latest copy from source control via the MacBook Pro. Whilst visiting the client, he / she may suggest changes, and minor ones I would tend to make on site, so I need the ability to merge any modified code back into the trunk of the project / solution when I return home. At the moment, I am using no source control at all, and rely on simply coping folders and overwriting them when I return from a client- thats my 'merge'!!! I was wondering if anyone had any ideas of a source provider I could use, which would support both Windows and Mac development environments, and is cheap (free would be better).

    Read the article

  • Automatically support new changes with Python.

    - by Zachary Brown
    I was working on a program,that I need to support new additions. Hmmm. Let me give you some background on the program. It is an educational software program that has quizzes for the user to take, just to gain odd knowledge. Now, It currently supports 6 subjects, all organized with directores on the HDD ( i.e. the Science directory is called science. ) and the way you launch the subject to see what quizzes you have to take is by pushing a button on the home screen. This sort of thing prevents easy subject additions. I want to be able to add a subject later on without having to recode the home screen and re organize all the buttons. I would use a Listbox and os.listdir(...), but I was kind of wanting something prettier than a Listbox. I am using Tkinter on Windows. The Python version I am using is 2.6 Is there a "fancy" listbox sort of thing that can be styled to work with the background?

    Read the article

  • MVC Areas - View not found

    - by user314827
    Hi, I have a project that is using MVC areas. The area has the entire project in it while the main "Views/Controllers/Models" folders outside the Areas are empty barring a dispatch controller I have setup that routes default incoming requests to the Home Controller in my area. This controller has one method as follows:- public ActionResult Index(string id) { return RedirectToAction("Index", "Home", new {area = "xyz"}); } I also have a default route setup to use this controller as follows:- routes.MapRoute( "Default", // Default route "{controller}/{action}/{id}", new { controller = "Dispatch", action = "Index", id = UrlParameter.Optional } ); Any default requests to my site are appropriately routed to the relevant area. The Area's "RegisterArea" method has a single route:- context.MapRoute( "xyz_default", "xyz/{controller}/{action}/{id}", new { action = "Index", id = UrlParameter.Optional } My area has multiple controllers with a lot of views. Any call to a specific view in these controller methods like "return View("blah"); renders the correct view. However whenever I try and return a view along with a model object passed in as a parameter I get the following error:- Server Error in '/DeveloperPortal' Application. The view 'blah' or its master was not found. The following locations were searched: ~/Views/Profile/blah.aspx ~/Views/Profile/blah.ascx ~/Views/Shared/blah.aspx ~/Views/Shared/blah.ascx It looks like whenever a model object is passed in as a param. to the "View()" method [e.g. return View("blah",obj) ] it searches for the view in the root of the project instead of in the area specific view folder. What am I missing here ? Thanks in advance.

    Read the article

  • ejb lookup failing with NamingException

    - by Drake
    I've added the following in my web.xml: <ejb-ref> <ejb-ref-name>ejb/userManagerBean</ejb-ref-name> <ejb-ref-type>Session</ejb-ref-type> <home>gha.ywk.name.entry.ejb.usermanager.UserManagerHome</home> <remote>what should go here??</remote> </ejb-ref> The following java code is giving me NamingException: public UserManager getUserManager () throws HUDException { String ROLE_JNDI_NAME = "ejb/userManagerBean"; try { Properties props = System.getProperties(); Context ctx = new InitialContext(props); UserManagerHome userHome = (UserManagerHome) ctx.lookup(ROLE_JNDI_NAME); UserManager userManager = userHome.create(); WASSSecurity user = userManager.getUserProfile("user101", null); return userManager; } catch (NamingException e) { log.error("Error Occured while getting EJB UserManager" + e); return null; } catch (RemoteException ex) { log.error("Error Occured while getting EJB UserManager" + ex); return null; } catch (CreateException ex) { log.error("Error Occured while getting EJB UserManager" + ex); return null; } } The code is used inside the container. By that I mean that the .WAR is deployed on the server (Sun Application Server). StackTrace (after jsight's suggestion): >Exception occurred in target VM: com.sun.enterprise.naming.java.javaURLContext.<init>(Ljava/util/Hashtable;Lcom/sun/enterprise/naming/NamingManagerImpl;)V java.lang.NoSuchMethodError: com.sun.enterprise.naming.java.javaURLContext.<init>(Ljava/util/Hashtable;Lcom/sun/enterprise/naming/NamingManagerImpl;)V at com.sun.enterprise.naming.java.javaURLContextFactory.getObjectInstance(javaURLContextFactory.java:32) at javax.naming.spi.NamingManager.getURLObject(NamingManager.java:584) at javax.naming.spi.NamingManager.getURLContext(NamingManager.java:533) at javax.naming.InitialContext.getURLOrDefaultInitCtx(InitialContext.java:279) at javax.naming.InitialContext.lookup(InitialContext.java:351) at gov.hud.pih.eiv.web.EjbClient.EjbClient.getUserManager(EjbClient.java:34)

    Read the article

  • inbound/outbound url routing in asp.net MVC

    - by Stephane
    The routing I need is quite simple, I must be missing something there. As code example I put the simpler situation where I can reproduce my behavior. You have this ActionMethod : public ActionResult Index(string provider) { ViewData["Message"] = provider; return View("Index"); } And you have this route : routes.MapRoute( null, "{controller}/{action}/{provider}", new { controller = "Home", action = "Index", provider = "Default" } ); // Parameter defaults You can call /Home/Index/Custom and provider will take the value "Custom" What Route would I need if I want the url /?provider=Custom to map the provider to the parameter. I thought that would just work, because the default controller and the default action would be used, and the provider from the querystring would be used instead of the default one. but the querystring is just ignored here. That's a problem in my situation as I have a form using HTTP GET method. The form action has to be Html.BeginForm(c=c.Index(null)) which is resolved as / and the value of my form are added in the querystring. (the provider being a dropdown in the form) So the url built by the form is /?abc=value&cde=value...

    Read the article

  • SHA function issues

    - by Damian James
    I have this php code from my login.php if (isset($_POST['logIn'])) { $errmsg = ""; $logname = mysqli_real_escape_string($dbc, trim($_POST['usernameIn'])); $logpassword = mysqli_real_escape_string($dbc, trim($_POST['passwordIn'])); $query = "SELECT user_id, username FROM members WHERE username = '$logname' AND password = SHA('$logpassword')"; $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { $row = mysqli_fetch_array($data); setcookie('user_id', $row['user_id'], time() + (60 * 60 * 24 * 30)); //expires after 30 days setcookie('username', $row['username'], time() + (60 * 60 * 24 * 30)); $home = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']) . '/index.php'; header('Location: ' . $home); } else { $errmsg = '<p class="errormsg">Username or password is incorrect.</p>'; } } And for some reason, it always ends up setting $errmsg in the else statement. I am sure that I'm entering information (username,password) that is correct and exists in the database. I insert my values (from a signup script) using this query: $query = "INSERT INTO members (username, password, email) VALUES ('$username', SHA('$password'), '$email')"; Anyone see the problem with this script? Thanks!

    Read the article

  • Render a Form from an XSLT file

    - by Russ Clark
    I've generated the following XSLT file, and have created a Form that will post to an ASP.Net MVC action called Home/ProcessRequest: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html> <body> <xsl:value-of select="Employee/Name"/> <br /> <xsl:value-of select="Employee/ID"/> <form method="post" action="/Home/ProcessRequest?id=42"> <input id="Action" name="Action" type="radio" value="Approved"></input> Approved <br /> <input id="Action" name="Action" type="radio" value="Rejected"></input> Rejected <br /> <input type="submit" value="Submit"></input> </form> </body> </html> Here is my XML File: <Employee xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Name>Russ</Name> <ID>42</ID> </Employee> This works fine the way it is, but I need to change the id parameter in my from from a hard coded integer, to use the ID element from my XML file. Does anyone know how to do this?

    Read the article

  • Proper way to set PYTHONPATH (including precedence)

    - by Wells
    In .bashrc I have: export PYTHONPATH=/home/wells/py-mlb I've verified this is actually being set. so, in this directory is another directory called 'py_mlb'- the actual module. So I go python -v and then import py_mlb but it does: >>> import py_mlb import py_mlb # directory /usr/local/lib/python2.6/dist-packages/py_mlb Then I do import sys and print sys.path and I see: >>> print sys.path ['', '/usr/local/lib/python2.6/dist-packages/python_memcached-1.44-py2.6.egg', '/usr/local/lib/python2.6/dist-packages/pymc-2.1alpha-py2.6-linux-i686.egg', '/usr/local/lib/python2.6/dist-packages/nose-0.11.1-py2.6.egg', '/home/wells/py-mlb', '/usr/lib/python2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk', '/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/usr/lib/python2.6/dist-packages', '/usr/local/lib/python2.6/dev-packages', '/usr/lib/pymodules/python2.6', '/usr/lib/pymodules/python2.6/gtk-2.0', '/usr/local/lib/python2.6/dist-packages'] So my path from .bashrc IS in there, and from the look of it it's even before dist-packages but it's importing the module from dist-packages. How can I finagle this so the PYTHONPATH as defined by .bashrc takes precedence? Thanks!

    Read the article

  • issue in property file

    - by devuser
    I want to load the property file when tomcat is starting.so I'm using servletContextListener to do that and i can get values of property file to my web application. But i want to keep the same value after changing the property file once log into web application.But when i change the value of property file and log into system again it change the value to new one.I want to keep the same value that loaded when tomcat was starting.how can i implement this? My coding is as below import javax.servlet.*; import java.io.IOException; import java.util.Properties; import java.util.logging.Level; import java.util.logging.Logger; import java.io.*; import java.util.ResourceBundle; public final class sysProperties implements javax.servlet.ServletContextListener { private static Properties props = new Properties(); private static String file_name = "com/util/contact.properties"; public addSystemProperties() { } public void contextInitialized(ServletContextEvent servletContextEvent) { // Get the context ServletContext servletContext = servletContextEvent.getServletContext(); // Set a context attribute try { // props.load(servletContext.getResourceAsStream(file_name)); props.load(getClass().getClassLoader().getResourceAsStream(file_name)); System.out.println(" Application X is starting"); servletContext.setAttribute("h1",props.getProperty("home.h1")); servletContext.setAttribute("h2",props.getProperty("home.h2")); System.out.println("h1"+servletContext.getAttribute("h1")); System.out.println("h2"+ servletContext.getAttribute("h2")); ; } catch (Exception e) { System.out.println(" Error setting context attribute: " + e.getMessage()); } } public void contextDestroyed(ServletContextEvent servletContextEvent) { // Get the context ServletContext servletContext = servletContextEvent.getServletContext(); // Output the context variable we set earlier System.out.println(" Application X is shutting down"); System.out.println(" Value of h1 is: " + servletContext.getAttribute("h1")); System.out.println(" Value of h2 is: " + servletContext.getAttribute("h2")); // Clean up (not really necessary as the context is being destroyed, but let's be neat) servletContext.removeAttribute(props.getProperty("h1")); servletContext.removeAttribute(props.getProperty("h2")); } }

    Read the article

  • emberjs on symfony2 dev enviroment dont work propertly

    - by rkmax
    I've builded a app with symfony2 the app expose an REST Api. now i build a simple client for consuming app.coffee - app.js App = Em.Application.create ready: -> @.entradas.load() Entrada: Em.Object.extend() entradas: Em.ArrayController.create content: [] load: -> url = 'http://localhost/api/1/entrada' me = @ $.ajax( url: url, method: 'GET', success: (data) -> me.set('content', []) for entrada in data.data.objects me.pushObject DBPlus.Entrada.create(entrada) ) MyBundle:Home:index.html.twig <script type="text/x-handlebars" src="{{ asset('js/templates/entradas.hbs') }}"></script> <script src="{{ asset('js/libs/jquery-1.7.2.min.js') }}"></script> <script src="{{ asset('js/libs/handlebars-1.0.0.beta.6.js') }}"></script> <script src="{{ asset('js/libs/ember-1.0.pre.min.js') }}"></script> <script src="{{ asset('js/app.js') }}"></script> the problem here is when i run on dev enviroment and link the template like <script type="text/x-handlebars" src="{{...}}"> the app dont work, nothing show but works fine over prod enviroment. he only way that works on dev enviroment is inline template MyBundle:Home:index.html.twig <script type="text/x-handlebars"> {% raw %} <ul class="entradas"> {{#each App.entradas}} <li class="entrada">{{nombre}}</li> {{/each}} </ul> {% endraw %} </script> can explain why this behavoir? Note: I disabled the debug profiler toolbar, and nothing

    Read the article

  • error in implementing static files in django

    - by POOJA GUPTA
    my settings.py file:- STATIC_ROOT = '/home/pooja/Desktop/static/' # URL prefix for static files. STATIC_URL = '/static/' # Additional locations of static files STATICFILES_DIRS = ( '/home/pooja/Desktop/mysite/search/static', ) my urls.py file:- from django.conf.urls import patterns, include, url from django.contrib.staticfiles.urls import staticfiles_urlpatterns from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', url(r'^search/$','search.views.front_page'), url(r'^admin/', include(admin.site.urls)), ) urlpatterns += staticfiles_urlpatterns() I have created an app using django which seraches the keywords in 10 xml documents and then return their frequency count displayed as graphical representation and list of filenames and their respective counts.Now the list has filenames hyperlinked, I want to display them on the django server when user clicks them , for that I have used static files provision in django. Hyperlinking has been done in this manner: <ul> {% for l in list1 %} <li><a href="{{STATIC_URL}}static/{{l.file_name}}">{{l.file_name}}</a{{l.frequency_count</li> {% endfor %} </ul> Now when I run my app on the server, everything is running fine but as soon as I click on the filename, it gives me this error : Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order: ^search/$ ^admin/ ^static\/(?P<path>.*)$ The current URL, search/static/books.xml, didn't match any of these. I don't know why this error is coming, because I have followed the steps required to achieve this. I have posted my urls.py file and it is showing error in that only. I'm new to django , so Please help

    Read the article

  • Error when running rake db:create

    - by Amy
    Hi, I am trying to setup an ror app but I keep getting this error. Any ideas as to what may be causing the problem? /usr/lib/ruby/site_ruby/1.8/rubygems/custom_require.rb:31:in `gem_original_require' /usr/lib/ruby/site_ruby/1.8/rubygems/custom_require.rb:31:in `require' /usr/lib/ruby/gems/1.8/gems/activesupport-2.3.5/lib/active_support/dependencies.rb:156:in `require' /usr/lib/ruby/gems/1.8/gems/activesupport-2.3.5/lib/active_support/dependencies.rb:521:in `new_constants_in' /usr/lib/ruby/gems/1.8/gems/activesupport-2.3.5/lib/active_support/dependencies.rb:156:in `require' /home/projects/testproject/lib/tasks/more_tasks.rake:3 /usr/lib/ruby/gems/1.8/gems/activesupport-2.3.5/lib/active_support/dependencies.rb:145:in `load_without_new_constant_marking' /usr/lib/ruby/gems/1.8/gems/activesupport-2.3.5/lib/active_support/dependencies.rb:145:in `load' /usr/lib/ruby/gems/1.8/gems/activesupport-2.3.5/lib/active_support/dependencies.rb:521:in `new_constants_in' /usr/lib/ruby/gems/1.8/gems/activesupport-2.3.5/lib/active_support/dependencies.rb:145:in `load' /usr/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/tasks/rails.rb:9 /usr/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/tasks/rails.rb:9:in `each' /usr/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/tasks/rails.rb:9 /usr/lib/ruby/site_ruby/1.8/rubygems/custom_require.rb:31:in `gem_original_require' /usr/lib/ruby/site_ruby/1.8/rubygems/custom_require.rb:31:in `require' /home/projects/testproject/Rakefile:10 /usr/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2383:in `load' /usr/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2383:in `raw_load_rakefile' /usr/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2017:in `load_rakefile' /usr/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2068:in `standard_exception_handling' /usr/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2016:in `load_rakefile' /usr/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2000:in `run' /usr/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2068:in `standard_exception_handling' /usr/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:1998:in `run' /usr/lib/ruby/gems/1.8/gems/rake-0.8.7/bin/rake:31 /usr/bin/rake:19:in `load' /usr/bin/rake:19

    Read the article

  • Hudson plugin, Java error "... disagree on InnerClasses attribute"

    - by StackedCrooked
    I am trying to be able to step through the code of a Hudson plugin called SVNPublisher. I checked out the code for SVNPublisher, used Netbeans to open the project, and clicked "Debug Main project". This results in a Firefox window opening address http://localhost:8080 which shows the Hudson main page. Clicking the "New Job" link results in an error page: HTTP ERROR: 500 jar:file:/home/francis/svn/svnpublisher/target/work/webapp/WEB-INF/lib/hudson-core-1.319.jar!/lib/hudson/newFromList/form.jelly:43:47: <j:forEach> hudson.scm.SubversionTagAction and hudson.scm.SubversionTagAction$DescriptorImpl disagree on InnerClasses attribute RequestURI=/newJob Caused by: org.apache.commons.jelly.JellyTagException: jar:file:/home/francis/svn/svnpublisher/target/work/webapp/WEB-INF/lib/hudson-core-1.319.jar!/lib/hudson/newFromList/form.jelly:43:47: hudson.scm.SubversionTagAction and hudson.scm.SubversionTagAction$DescriptorImpl disagree on InnerClasses attribute at org.apache.commons.jelly.impl.TagScript.handleException(TagScript.java:713) at org.apache.commons.jelly.impl.TagScript.run(TagScript.java:282) at org.apache.commons.jelly.impl.ScriptBlock.run(ScriptBlock.java:95) ... I am very new to Hudson and not very experienced with Java so I'm pretty much clueless on the meaning of this error. Can anyone help?

    Read the article

  • Apache rewrite rules redux

    - by AlexanderJohannesen
    I've got a REST framework that when plopped into any directory should Just Work(TM), and it seems to work fine when I've got projects in subdirectories, but not if it's in root. So, given a few example directories; / /project1 /bingo/project2 /hoopla/doopla/minor/project3 All of these works fine, except I'm getting "funnies"* when the project runs in the root directory (bit hard to explain, I suppose, but the second level rewrites are not working properly). Here's my attempt at a generic .htaccess file: RewriteEngine On RewriteRule ^static/ - [L] RewriteCond %{REQUEST_URI} ^$ RewriteRule .* ./ [R,L] RewriteRule ^index.php - [L] RewriteRule (.*) index.php?q=$1 [QSA,PT] (And yes, all projects have a subdirectory ./static which is ignored by rewrites) What I'm trying to achieve is a set of rewrite rules that work for most cases (which is, again, plonking the project in a directory the webserver serves). I'm not a rewrite rules wiz by a long shot, and any good advice and gotchas would be appreciated (and yes, I've gone through too many introductory articles. I need some serious juice.) More info on the funnies; my webserver has docroot in one spot (under /usr/share/apache2/default-site/), but a set of rules that says that /projects is pulled in from somewhere else that's not a subdirectory of docroot (/home/user/Projects/). When I go there, I get a list of /projects subdirectories, and if one of those subdirectories gets called (restmapp) with the proposed rewrite rules, I get ; The requested URL /home/user/Projects/restmapp/index.php was not found on this server.

    Read the article

  • Lotus Notes - Export emails to plain text file

    - by mbeckish
    I am setting up a Lotus Notes account to accept emails from a client, and automatically save each email as a plain text file to be processed by another application. So, I'm trying to create my very first Agent in Lotus to automatically export the emails to text. Is there a standard, best practices way to do this? I've created a LotusScript Agent that pretty much works. However, there is a bug - once the Body of the memo exceeds 32K characters, it starts inserting extra CR/LF pairs. I am using Lotus Notes 7.0.3. Here is my script: Sub Initialize On Error Goto ErrorCleanup Dim session As New NotesSession Dim db As NotesDatabase Dim doc As NotesDocument Dim uniqueID As Variant Dim curView As NotesView Dim docCount As Integer Dim notesInputFolder As String Dim notesValidOutputFolder As String Dim notesErrorOutputFolder As String Dim outputFolder As String Dim fileNum As Integer Dim bodyRichText As NotesRichTextItem Dim bodyUnformattedText As String Dim subjectText As NotesItem ''''''''''''''''''''''''''''''''''''''''''''''''''''''' 'INPUT OUTPUT LOCATIONS outputFolder = "\\PASCRIA\CignaDFS\CUser1\Home\mikebec\MyDocuments\" notesInputFolder = "IBEmails" notesValidOutputFolder = "IBEmailsDone" notesErrorOutputFolder="IBEmailsError" ''''''''''''''''''''''''''''''''''''''''''''''''''''''' Set db = session.CurrentDatabase Set curview = db.GetView(notesInputFolder ) docCount = curview.EntryCount Print "NUMBER OF DOCS " & docCount fileNum = 1 While (docCount > 0) 'set current doc to Set doc = curview.GetNthDocument(docCount) Set bodyRichText = doc.GetFirstItem( "Body" ) bodyUnformattedText = bodyRichText.GetUnformattedText() Set subjectText = doc.GetFirstItem("Subject") If subjectText.Text = "LotusAgentTest" Then uniqueID = Evaluate("@Unique") Open "\\PASCRIA\CignaDFS\CUser1\Home\mikebec\MyDocuments\email_" & uniqueID(0) & ".txt" For Output As fileNum Print #fileNum, "Subject:" & subjectText.Text Print #fileNum, "Date:" & Now Print #fileNum, bodyUnformattedText Close fileNum fileNum = fileNum + 1 Call doc.PutInFolder(notesValidOutputFolder) Call doc.RemoveFromFolder(notesInputFolder) End If doccount = doccount-1 Wend Exit Sub ErrorCleanup: Call sendErrorEmail(db,doc.GetItemValue("From")(0)) Call doc.PutInFolder(notesErrorOutputFolder) Call doc.RemoveFromFolder(notesInputFolder) End Sub Update Apparently the 32KB issue isn't consistent - so far, it's just one document that starts getting extra carriage returns after 32K.

    Read the article

  • Has Twisted changed its dependencies?

    - by cdecker
    Hi all, I'm currently working on a Python/Twisted project which is to be distributed and tested on Planetlab. For some reason my code was working on friday and now that I wanted to test a minor change it refuses to work at all: Traceback (most recent call last): File "acn_a4/src/node.py", line 6, in <module> from twisted.internet.protocol import DatagramProtocol File "/usr/lib/python2.5/site-packages/Twisted-10.0.0-py2.5-linux-i686.egg/twisted/__init__.py", line 18, in <module> from twisted.python import compat File "/usr/lib/python2.5/site-packages/Twisted-10.0.0-py2.5-linux-i686.egg/twisted/python/compat.py", line 146, in <module> import operator File "/home/cdecker/dev/acn/acn_a4/src/operator.py", line 7, in <module> File "/home/cdecker/acn_a4/src/node.py", line 6, in <module> from twisted.internet.protocol import DatagramProtocol File "/usr/lib/python2.5/site-packages/Twisted-10.0.0-py2.5-linux-i686.egg/twisted/internet/protocol.py", line 20, in <module> from twisted.python import log, failure, components File "/usr/lib/python2.5/site-packages/Twisted-10.0.0-py2.5-linux-i686.egg/twisted/python/log.py", line 19, in <module> from twisted.python import util, context, reflect File "/usr/lib/python2.5/site-packages/Twisted-10.0.0-py2.5-linux-i686.egg/twisted/python/util.py", line 5, in <module> import os, sys, hmac, errno, new, inspect, warnings File "/usr/lib/python2.5/inspect.py", line 32, in <module> from operator import attrgetter ImportError: cannot import name attrgetter And since I'm pretty new to python I have no idea what could have caused this problem. All suggestions are welcome :-)

    Read the article

  • How to ellipsize center-aligned textview beside a right-aligned button when screen width is small

    - by simplymoody
    ------------------------------------ | LONG_TITL... |button| | |------------------------------------| | | I have an app header which consists of the app title and a button. The button should be fixed on the right side but I want the title to be in the middle and ellipsize when the screen is too small. Problem is the title just won't ellipsize even though the button is nearly beside it. Here's what I have so far: <RelativeLayout android:id="@+id/headr" android:layout_width="match_parent" android:layout_height="wrap_content" android:gravity="center"> <ImageView android:id="@+id/bar_orange" android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_alignParentTop="true" android:minHeight="40dp" android:scaleType="centerCrop" android:src="@drawable/bar_orange"/> <TextView android:id="@+id/Title" android:layout_marginLeft="20dp" android:layout_marginRight="20dp" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_centerInParent="true" android:gravity="center" android:text="@string/bcd" android:textColor="#FFFFFF" android:ellipsize="marquee" android:singleLine="true" android:textSize="18sp" android:textStyle="bold"/> <Button android:padding="5dp" android:id="@+id/home" android:textColor="#ffffff" android:layout_marginRight="10dp" android:layout_marginLeft="10dp" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignParentRight="true" android:layout_centerVertical="true" android:singleLine="true" android:background="@drawable/button_home" android:text="@string/home"/> </RelativeLayout> Is there a way to do this with just RelativeLayout?

    Read the article

  • Hadoop streaming with Python and python subprocess

    - by Ganesh
    I have established a basic hadoop master slave cluster setup and able to run mapreduce programs (including python) on the cluster. Now I am trying to run a python code which accesses a C binary and so I am using the subprocess module. I am able to use the hadoop streaming for a normal python code but when I include the subprocess module to access a binary, the job is getting failed. As you can see in the below logs, the hello executable is recognised to be used for the packaging, but still not able to run the code. . . packageJobJar: [/tmp/hello/hello, /app/hadoop/tmp/hadoop-unjar5030080067721998885/] [] /tmp/streamjob7446402517274720868.jar tmpDir=null JarBuilder.addNamedStream hello . . 12/03/07 22:31:32 INFO mapred.FileInputFormat: Total input paths to process : 1 12/03/07 22:31:32 INFO streaming.StreamJob: getLocalDirs(): [/app/hadoop/tmp/mapred/local] 12/03/07 22:31:32 INFO streaming.StreamJob: Running job: job_201203062329_0057 12/03/07 22:31:32 INFO streaming.StreamJob: To kill this job, run: 12/03/07 22:31:32 INFO streaming.StreamJob: /usr/local/hadoop/bin/../bin/hadoop job -Dmapred.job.tracker=master:54311 -kill job_201203062329_0057 12/03/07 22:31:32 INFO streaming.StreamJob: Tracking URL: http://master:50030/jobdetails.jsp?jobid=job_201203062329_0057 12/03/07 22:31:33 INFO streaming.StreamJob: map 0% reduce 0% 12/03/07 22:32:05 INFO streaming.StreamJob: map 100% reduce 100% 12/03/07 22:32:05 INFO streaming.StreamJob: To kill this job, run: 12/03/07 22:32:05 INFO streaming.StreamJob: /usr/local/hadoop/bin/../bin/hadoop job -Dmapred.job.tracker=master:54311 -kill job_201203062329_0057 12/03/07 22:32:05 INFO streaming.StreamJob: Tracking URL: http://master:50030/jobdetails.jsp?jobid=job_201203062329_0057 12/03/07 22:32:05 ERROR streaming.StreamJob: Job not Successful! 12/03/07 22:32:05 INFO streaming.StreamJob: killJob... Streaming Job Failed! Command I am trying is : hadoop jar contrib/streaming/hadoop-*streaming*.jar -mapper /home/hduser/MARS.py -reducer /home/hduser/MARS_red.py -input /user/hduser/mars_inputt -output /user/hduser/mars-output -file /tmp/hello/hello -verbose where hello is the C executable. It is a simple helloworld program which I am using to check the basic functioning. My Python code is : #!/usr/bin/env python import subprocess subprocess.call(["./hello"]) Any help with how to get the executable run with Python in hadoop streaming or help with debugging this will get me forward in this. Thanks, Ganesh

    Read the article

< Previous Page | 219 220 221 222 223 224 225 226 227 228 229 230  | Next Page >