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  • How can I share data from a Samsung Wave Mobile phone with the Mac OS?

    - by M. Bedi
    This is driving me up the wall just a bit. I have a new Samsung Wave mobile phone. It is running the Bada OS. The mobile phone does not come with anyone software for the Mac. The Kies desktop interface is only available for Windows. I did try installing the Kies software in a VM with Parallels 5 but it did not detect the phone connected via USB. I tried using Bluetooth file exchange on the Mac; it lets me browse the file system on the Wave phone but not actually see any of the media files; I just get empty directory views. But I am able to access files using media sharing with the Wave phone and my PS3. So what would be a Mac desks top app that can be used a media sharing browser?

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  • Is there any program or way to make Mac OS X's ?-tab behave like Windows' alt-tab?

    - by J. Pablo Fernández
    Is there any program or way to make Mac OS X's ?(command)-tab behave like Windows' alt-tab? That is, instead of switching between applications, to switch between windows of all applications. I do know there's a way to switch between windows of the same application, but that's not what I want either. I'm not just trying to make Mac OS X behave like my recent former OS, I've been a Mac user for over two years and before that Ubuntu. After using Expose and ?-tab I think Windows' or Ubuntu's alt-tab is better.

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  • Parallels: How to see a Mac-hosted website from Windows?

    - by Jim Miller
    I'm traveling at the moment, and have moved one of the websites I'm working on to my MBP so I can work on it without a network connection. I've made an addition to the Mac's /etc/hosts file pointing the domain name to 127.0.0.1, and all's well. I now want to get into Parallels and check the site from Windows browsers. How do I get things so that the Windows browser will understand the domain name and access the site? The Windows image obviously doesn't recognize / can't find the Mac's /etc/hosts file, and references to 127.0.0.1 in the Windows hosts file just as obviously point to Windows, not the Mac. Any advice out there? Thanks!

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  • L'accessibilité des applications Qt évolue avec Qt 5.3, avec un meilleur support de VoiceOver pour Mac et de la lecture des menus sous Windows

    L'accessibilité des applications Qt évolue avec Qt 5.3 Un meilleur support de VoiceOver pour Mac et de la lecture des menus sous WindowsL'accessibilité des applications graphiques a toujours été un sujet de préoccupation de la part de l'équipe de Qt. En effet, une application doit être utilisable par tous, peu importe les différences entre chaque. Avec la publication de Qt 5.2, de nombreuses améliorations avaient été réalisées dans ce domaine. Une interface de programmation avait été rendue publique...

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  • Sending an Activation Email when a New User Registers

    - by John
    Hello, The code below is a login system that I am using. It is supposed to allow a new user to register and then send the new user an activation email. It is inserting the new user into the MySQL database, but it is not sending the activation email. Any ideas why it's not sending the activation email? Thanks in advance, John header.php: <?php //error_reporting(0); session_start(); require_once ('db_connect.inc.php'); require_once ("function.inc.php"); $seed="0dAfghRqSTgx"; $domain = "...com"; ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title>The Sandbox - <?php echo $domain; ?></title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> <link rel="stylesheet" type="text/css" href="sandbox.css"> <div class="hslogo"><a href="http://www...com/sandbox/"><img src="images/hslogo.png" alt="Example" border="0"/></a></div> </head> <body> login.php: <?php if (!isLoggedIn()) { // user is not logged in. if (isset($_POST['cmdlogin'])) { // retrieve the username and password sent from login form & check the login. if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { // User is not logged in and has not pressed the login button // so we show him the loginform show_loginform(); } } else { // The user is already loggedin, so we show the userbox. show_userbox(); } ?> function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php?'.$_SERVER['QUERY_STRING'].'"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; } register.php: <?php require_once "header.php"; if (isset($_POST['register'])){ if (registerNewUser($_POST['username'], $_POST['password'], $_POST['password2'], $_POST['email'])){ echo "<div class='registration'>Thank you for registering, an email has been sent to your inbox, Please activate your account. <a href='http://www...com/sandbox/index.php'>Click here to login.</a> </div>"; }else { echo "Registration failed! Please try again."; show_registration_form(); } } else { // has not pressed the register button show_registration_form(); } ?> New User Function: function registerNewUser($username, $password, $password2, $email) { global $seed; if (!valid_username($username) || !valid_password($password) || !valid_email($email) || $password != $password2 || user_exists($username)) { return false; } $code = generate_code(20); $sql = sprintf("insert into login (username,password,email,actcode) value ('%s','%s','%s','%s')", mysql_real_escape_string($username), mysql_real_escape_string(sha1($password . $seed)) , mysql_real_escape_string($email), mysql_real_escape_string($code)); if (mysql_query($sql)) { $id = mysql_insert_id(); if (sendActivationEmail($username, $password, $id, $email, $code)) { return true; } else { return false; } } else { return false; } return false; } Send Activation Email function: function sendActivationEmail($username, $password, $uid, $email, $actcode) { global $domain; $link = "http://www.$domain/sandbox/activate.php?uid=$uid&actcode=$actcode"; $message = " Thank you for registering on http://www.$domain/, Your account information: username: $username password: $password Please click the link below to activate your account. $link Regards $domain Administration "; if (sendMail($email, "Please activate your account.", $message, "no-reply@$domain")) { return true; } else { return false; } }

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  • Login or Register (Ruby on rails)

    - by DanielZ
    Hello stackoverflow, I'm working on an Ruby on Rails application (2.3.x) and i want to make a form that lets the user login or register. I want to do this in the same form. I have a JS function that replaces the form elements like this: Login form: <% form_for @user do |f| %> <div id="form"> <%= f.label :email, "E-mail" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.password_field :password %> <%= link_to "I don't have an account, "#", :id => "changeForm"%> <%= f.submit "Login" %> </div> <% end %> The id "changeForm" triggers a JS function that changes the form elements. So if you press the url the html looks like this: <% form_for @user do |f| %> <div id="form"> <%= f.label :name, "Name" %> <%= f.text_field :name %> <%= f.label :email, "E-mail" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.password_field :password %> <%= f.label :password_confirmation, "Password confirmation" %> <%= f.password_field :password_confirmation %> <%= link_to "I do have an account, "#", :id => "changeForm"%> <%= f.submit "Register" %> </div> <% end %> I added the neccesary validations to my user model: class User < ActiveRecord::Base attr_reader :password validates_presence_of :name, :email, :password validates_format_of :email, :with => /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})\Z/i validates_confirmation_of :password But what happens when you fill in the email / password you get the errors that the name is missing and that the password fields aren't confirmed. So i could do some nasty programming in my user model like this: #if password_conf or the name are present the user has tried to register... if params[:user][:password_confirmation].present? || params[:user][:name].present? #so we'll try to save the user if @user.save #if the user is saved authenticate the user current_session.user = User.authenticate(params[:user]) #if the user is logged in? if current_session.user.present? flash[:notice] = "succesvully logged redirect_to some_routes_path else #not logged in... flash[:notice] = "Not logged in" render :action => "new" end else #user not saved render :action => "new" end else #So if the params[:user][:password_confirmation] or [:user][:name] weren't present we geuss the user wants to login... current_session.user = User.authenticate(params[:user]) #are we logged_in? if current_session.user.present? flash[:notice] = "Succesvully logged in" redirect_to some_routes_path else #errors toevoegen @user.errors.add(:email, "The combination of email/password isn't valid") @user.errors.add(:password," ") render :action => "new" end end end Without validations this (imho dirty code and should not be in the controller) works. But i want to use the validates_presence_of methods and i don't want to slap the "conventions over configurations" in the face. So another thing i have tried is adding a hidden field to the form: #login form <%= f.hidden_field :login, :value => true %> # and ofcourse set it to false if we want to register. And then i wanted to use the method: before_validation before_validation_on_create do |user| if params[:user].login == true #throws an error i know... validates_presence_of :email, :password validates_format_of :email, :with => /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})\Z/i else validates_presence_of :name, :email, :password validates_format_of :email, :with => /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})\Z/i validates_confirmation_of :password end end But this doesn't work because i can't access the params. And login isn't a attribute for the user object. But i thought that in this way i could validate the email and password params if the user wants to login. And all the other attrs if the user want to register. So all i could think of doesn't work how i want it to work. So my main goal is this: 1 form for login/register with the use of the validation methods in the user model. So if we want to login but don't fill in any information = give validation errors. And if the user wants to login but the email/password combination doens't match give the "@user.errors.add(:email, "the combination wasn't found in the db...")". And the same goes for user register... Thanks in advance!

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  • How do I create a Linked Server in SQL Server 2005 to a password protected Access 95 database?

    - by Brad Knowles
    I need to create a linked server with SQL Server Management Studio 2005 to an Access 95 database, which happens to be password protected at the database level. User level security has not been implemented. I cannot convert the Access database to a newer version. It is being used by a 3rd party application; so modifying it, in any way, is not allowed. I've tried using the Jet 4.0 OLE DB Provider and the ODBC OLE DB Provider. The 3rd party application creates a System DSN (with the proper database password), but I've not had any luck in using either method. If I were using a standard connection string, I think it would look something like this: Provider=Microsoft.Jet.OLEDB.4.0;Data Source='C:\Test.mdb';Jet OLEDB:Database Password=####; I'm fairly certain I need to somehow incorporate Jet OLEDB:Database Password into the linked server setup, but haven't figured out how. I've posted the scripts I'm using along with the associated error messages below. Any help is greatly appreciated. I'll provide more details if needed, just ask. Thanks! Method #1 - Using the Jet 4.0 Provider When I try to run these statements to create the linked server: sp_dropserver 'Test', 'droplogins'; EXEC sp_addlinkedserver @server = N'Test', @provider = N'Microsoft.Jet.OLEDB.4.0', @srvproduct = N'Access DB', @datasrc = N'C:\Test.mdb' GO EXEC sp_addlinkedsrvlogin @rmtsrvname=N'Test', @useself=N'False',@locallogin=NULL, @rmtuser=N'Admin', @rmtpassword='####' GO I get this error when testing the connection: TITLE: Microsoft SQL Server Management Studio ------------------------------ "The test connection to the linked server failed." ------------------------------ ADDITIONAL INFORMATION: An exception occurred while executing a Transact-SQL statement or batch. (Microsoft.SqlServer.ConnectionInfo) ------------------------------ The OLE DB provider "Microsoft.Jet.OLEDB.4.0" for linked server "Test" reported an error. Authentication failed. Cannot initialize the data source object of OLE DB provider "Microsoft.Jet.OLEDB.4.0" for linked server "Test". OLE DB provider "Microsoft.Jet.OLEDB.4.0" for linked server "Test" returned message "Cannot start your application. The workgroup information file is missing or opened exclusively by another user.". (Microsoft SQL Server, Error: 7399) ------------------------------ Method #2 - Using the ODBC Provider... sp_dropserver 'Test', 'droplogins'; EXEC sp_addlinkedserver @server = N'Test', @provider = N'MSDASQL', @srvproduct = N'ODBC', @datasrc = N'Test:DSN' GO EXEC sp_addlinkedsrvlogin @rmtsrvname=N'Test', @useself=N'False',@locallogin=NULL, @rmtuser=N'Admin', @rmtpassword='####' GO I get this error: TITLE: Microsoft SQL Server Management Studio ------------------------------ "The test connection to the linked server failed." ------------------------------ ADDITIONAL INFORMATION: An exception occurred while executing a Transact-SQL statement or batch. (Microsoft.SqlServer.ConnectionInfo) ------------------------------ Cannot initialize the data source object of OLE DB provider "MSDASQL" for linked server "Test". OLE DB provider "MSDASQL" for linked server "Test" returned message "[Microsoft][ODBC Driver Manager] Driver's SQLSetConnectAttr failed". OLE DB provider "MSDASQL" for linked server "Test" returned message "[Microsoft][ODBC Driver Manager] Driver's SQLSetConnectAttr failed". OLE DB provider "MSDASQL" for linked server "Test" returned message "[Microsoft][ODBC Microsoft Access Driver] Cannot open database '(unknown)'. It may not be a database that your application recognizes, or the file may be corrupt.". (Microsoft SQL Server, Error: 7303)

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  • Windows 7, HTTPS WebDav: Asks for password twice and fails. Any workarounds?

    - by AutoDMC
    Howdy. I have a Dav server running with PHP SabreDav (code.google.com/p/sabredav/wiki/Windows) on Cherokee at an HTTPS secured URL. It's set to use https, and uses Digest Authentication. I can log in with multiple browsers and a few third party clients (BitKinex and Java AnyClient can connect and browse as well, caveats below). However, when attempting to log in with Windows 7 (surprise, surprise), it asks for my password twice, then tells me that my folder is invalid. I have verified that the server is using Digest authentication. I've verified multiple times that third party software can connect. I even went out and bought a GoDaddy SSL certificate so my SSL wouldn't be self signed anymore. I've applied the registry hacks here: support.microsoft.com/kb/943280 (Note that the article says the "fix" already exists for Windows 7, I just need magical registry hax to get it to work) I've applied the registry hacks here: support.microsoft.com/kb/941050 I've applied the registry hacks here: support.microsoft.com/kb/841215 (Supposedly allows Basic Auth, which shouldn't apply, but why not?) All to no avail; Windows continues to ask for my password twice, then state that "The folder you entered does not appear to be valid. Please choose another." Try the command line? Sure: I've attempted to access with NET USE "https://dav.example.com/" password /USER:me (System error 59) I've attempted to access with NET USE "https://dav.example.com/" (System error 1790) I've attempted to access with NET USE "https://dav.example.com/subdir/" password /USER:me (System error 59) I've attempted to access with NET USE "https://dav.example.com/subdir/" (System error 1790) For good luck: ping dav.example.com ... works. And again, web browsers can access the share just fine, so can third party tools. Best I can tell at this point is "HAHA, NO WEBDAV FOR YOU ON WINDOWS 7" which would be fine except everyone who will be using this application... uses Windows 7. And most are not as persistent or pugnacious as I am. I feel like I've burned through every random suggestion I've found anywhere in the first 10 pages of Google on every search term I can think of. Any ideas? I need it to be Webdav, I need it to be over HTTPS, and I really do need a method to access it from Windows 7. EXTRA DETAIL: However, the "third party" programs I've tried have either been buggy, incomplete, or have silly ... "glitches." For example, BitKinex seems to fixate on any http error codes sent, so if there's a glitch reading a directory, BAM, that directory is always listed empty. Long directory listings also show up as blank, even though the transfer panel shows that directory listing is still taking place. In any case, BitKinex is useless for development purposes for the reasons above. And besides, I'm building this for people other than myself, people who will want to get this dav share working "the regular way."

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  • Why does the interpreted order seem different from what I expect?

    - by inspectorG4dget
    I have a problem that I have not faced before: It seems that the order of interpretation in my program is somehow different from what I expect. I have written a small Twitter client. It takes a few seconds for my program to actually post a tweet after I click the "GO" button (which can also be activated by hitting ENTER on the keyboard). I don't want to click multiple times within this time period thinking that I hadn't clicked it the first time. Therefore, when the button is clicked, I would like the label text to display something that tells me that the button has been clicked. I have implemented this message by altering the label text before I send the tweet across. However, for some reason, the message does not display until the tweet has been attempted. But since I have a confirmation message after the tweet, I never get to see this message and my original problem goes unsolved. I would really appreciate any help. Here is the relevant code: class SimpleTextBoxForm(Form): def __init__(self): # set window properties self.Text = "Tweeter" self.Width = 235 self.Height = 250 #tweet away self.label = Label() self.label.Text = "Tweet Away..." self.label.Location = Point(10, 10) self.label.Height = 25 self.label.Width = 200 #get the tweet self.tweetBox = TextBox() self.tweetBox.Location = Point(10, 45) self.tweetBox.Width = 200 self.tweetBox.Height = 60 self.tweetBox.Multiline = True self.tweetBox.WordWrap = True self.tweetBox.MaxLength = 140; #ask for the login ID self.askLogin = Label() self.askLogin.Text = "Login:" self.askLogin.Location = Point(10, 120) self.askLogin.Height = 20 self.askLogin.Width = 60 self.login = TextBox() self.login.Text= "" self.login.Location = Point(80, 120) self.login.Height = 40 self.login.Width = 100 #ask for the password self.askPass = Label() self.askPass.Text = "Password:" self.askPass.Location = Point(10, 150) self.askPass.Height = 20 self.askPass.Width = 60 # display password box with character hiding self.password = TextBox() self.password.Location = Point(80, 150) self.password.PasswordChar = "x" self.password.Height = 40 self.password.Width = 100 #submit button self.button1 = Button() self.button1.Text = 'Tweet' self.button1.Location = Point(10, 180) self.button1.Click += self.update self.AcceptButton = self.button1 #pack all the elements of the form self.Controls.Add(self.label) self.Controls.Add(self.tweetBox) self.Controls.Add(self.askLogin) self.Controls.Add(self.login) self.Controls.Add(self.askPass) self.Controls.Add(self.password) self.Controls.Add(self.button1) def update(self, sender, event): if not self.password.Text: self.label.Text = "You forgot to enter your password..." else: self.tweet(self.tweetBox.Text, self.login.Text, self.password.Text) def tweet(self, msg, login, password): self.label.Text = "Attempting Tweet..." # this should be executed before sending the tweet is attempted. But this seems to be executed only after the try block try: success = 'Tweet successfully completed... yay!\n' + 'At: ' + time.asctime().split()[3] ServicePointManager.Expect100Continue = False Twitter().UpdateAsXML(login, password, msg) except: error = 'Unhandled Exception. Tweet unsuccessful' self.label.Text = error else: self.label.Text = success self.tweetBox.Text = ""

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  • Why does the interpretted order seem different from what I expect?

    - by inspectorG4dget
    I have a problem that I have not faced before: It seems that the order of interpretation in my program is somehow different from what I expect. I have written a small Twitter client. It takes a few seconds for my program to actually post a tweet after I click the "GO" button (which can also be activated by hitting ENTER on the keyboard). I don't want to click multiple times within this time period thinking that I hadn't clicked it the first time. Therefore, when the button is clicked, I would like the label text to display something that tells me that the button has been clicked. I have implemented this message by altering the label text before I send the tweet across. However, for some reason, the message does not display until the tweet has been attempted. But since I have a confirmation message after the tweet, I never get to see this message and my original problem goes unsolved. I would really appreciate any help. Here is the relevant code: class SimpleTextBoxForm(Form): def init(self): # set window properties self.Text = "Tweeter" self.Width = 235 self.Height = 250 #tweet away self.label = Label() self.label.Text = "Tweet Away..." self.label.Location = Point(10, 10) self.label.Height = 25 self.label.Width = 200 #get the tweet self.tweetBox = TextBox() self.tweetBox.Location = Point(10, 45) self.tweetBox.Width = 200 self.tweetBox.Height = 60 self.tweetBox.Multiline = True self.tweetBox.WordWrap = True self.tweetBox.MaxLength = 140; #ask for the login ID self.askLogin = Label() self.askLogin.Text = "Login:" self.askLogin.Location = Point(10, 120) self.askLogin.Height = 20 self.askLogin.Width = 60 self.login = TextBox() self.login.Text= "" self.login.Location = Point(80, 120) self.login.Height = 40 self.login.Width = 100 #ask for the password self.askPass = Label() self.askPass.Text = "Password:" self.askPass.Location = Point(10, 150) self.askPass.Height = 20 self.askPass.Width = 60 # display password box with character hiding self.password = TextBox() self.password.Location = Point(80, 150) self.password.PasswordChar = "x" self.password.Height = 40 self.password.Width = 100 #submit button self.button1 = Button() self.button1.Text = 'Tweet' self.button1.Location = Point(10, 180) self.button1.Click += self.update self.AcceptButton = self.button1 #pack all the elements of the form self.Controls.Add(self.label) self.Controls.Add(self.tweetBox) self.Controls.Add(self.askLogin) self.Controls.Add(self.login) self.Controls.Add(self.askPass) self.Controls.Add(self.password) self.Controls.Add(self.button1) def update(self, sender, event): if not self.password.Text: self.label.Text = "You forgot to enter your password..." else: self.tweet(self.tweetBox.Text, self.login.Text, self.password.Text) def tweet(self, msg, login, password): self.label.Text = "Attempting Tweet..." # this should be executed before sending the tweet is attempted. But this seems to be executed only after the try block try: success = 'Tweet successfully completed... yay!\n' + 'At: ' + time.asctime().split()[3] ServicePointManager.Expect100Continue = False Twitter().UpdateAsXML(login, password, msg) except: error = 'Unhandled Exception. Tweet unsuccessful' self.label.Text = error else: self.label.Text = success self.tweetBox.Text = ""

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  • ImageMagick on Mac OSX Snow Leopard. Is there any way to get it to work?

    - by ?????
    It seems that I have more trouble getting standard Unix things to run on Snow Leopard than any other platform--including Windows cygwin For the past couple of days, I've been trying to get ImageMagick to run on Snow Leopard. The most obvious way, Mac Ports, fails: tppllc-Mac-Pro:ImageMagick-sl swirsky$ sudo port install imagemagick ---> Computing dependencies for p5-locale-gettext ---> Configuring p5-locale-gettext Error: Target org.macports.configure returned: configure failure: shell command " cd "/opt/local/var/macports/build/_opt_local_var_macports_sources_rsync.macports.org_release_ports_perl_p5-locale-gettext/work/gettext-1.05" && /opt/local/bin/perl Makefile.PL INSTALLDIRS=vendor " returned error 2 Command output: checking for gettext... no checking for gettext in -I/opt/local/include -arch i386 -L/opt/local/lib -lintl...gettext function not found. Please install libintl at Makefile.PL line 18. no Error: Unable to upgrade port: 1 Error: Unable to execute port: upgrade xorg-libXt failed Before reporting a bug, first run the command again with the -d flag to get complete output. tppllc-Mac-Pro:ImageMagick-sl swirsky$ Not wanting to spend another two days figuring out why my libintl doesn't have a "gettext" function, I tried a different route: the script mentioned here: http://github.com/masterkain/ImageMagick-sl This script downloads and installs an ImageMagic independently of MacPorts issues tppllc-Mac-Pro:ImageMagick-sl swirsky$ /usr/local/bin/convert dyld: Library not loaded: /opt/local/lib/libiconv.2.dylib Referenced from: /opt/local/lib/libfontconfig.1.dylib Reason: Incompatible library version: libfontconfig.1.dylib requires version 8.0.0 or later, but libiconv.2.dylib provides version 7.0.0 Trace/BPT trap It downloads everything and compiles fine, but fails when I try to run it, with the message above. So now I'm two steps away from ImageMagick, trying to get a newer libiconv on my machine. I downloaded the latest libiconv, compiled and built it. I put the resulting library in /opt/local/lib, and I still get the same error message: tppllc-Mac-Pro:.libs swirsky$ sudo mv libiconv.2.dylib /opt/local/lib/libiconv.2.dylib tppllc-Mac-Pro:.libs swirsky$ convert dyld: Library not loaded: /opt/local/lib/libiconv.2.dylib Referenced from: /opt/local/lib/libfontconfig.1.dylib Reason: Incompatible library version: libfontconfig.1.dylib requires version 8.0.0 or later, but libiconv.2.dylib provides version 7.0.0 Trace/BPT trap So here's my question: Is it possible to get ImageMagick to run on OSX Snow Leopard? Are there any binary distributions that have static libraries baked in so I don't have to worry about these issue/

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  • How can I set up a git repository on windows, and then push to/pull from it on Mac OSX

    - by Eric S.
    I'm trying to set up a Windows-based web server, but do the development work on Mac OSX. I installed freeSSHd and msysGit on the Windows server, and set up a repository where I want it. I also have git on my Mac and set up a repo there too. When I try to clone, pull from, or push to the windows repo via SSH, it gives me an error, "fatal: protocol error: bad line length character" It doesn't matter what I set the remote to in my client (Mac OSX) machine - I can point it to a folder that doesn't exist and it still gives me that error. I also tried this on a Linux box I have sitting around and it works perfectly, so it's not my Mac. I have a couple ideas: Maybe freeSSHd isn't behaving correctly (as suggested here) so I could get a different SSH server for Windows - perhaps OpenSSH Perhaps I'm typing the code that combines Mac and Windows file paths incorrectly. I tried: sudo git clone ssh://[email protected]/C:/Users/[my_username]/[remote_repo_name]/.git [destination] and sudo git clone ssh://[email protected]/C:\Users\[my_username]\[remote_repo_name]\.git [destination] I'm getting the same error with both of these. Does anybody know what's going wrong? Better yet, is there anybody out there that has managed to do what I want to do (push to and pull from a windows repository via SSH)? Thanks!

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  • Weird javascript problem...

    - by Silvio Iannone
    Hi there, i'm building a page that is dinamically loaded with ajax. This is what the '$.get' jQuery function calls (this is located on an external HTML page): <script type="text/javascript"> $(function() { $('button').sb_animateButton(); $('input').sb_animateInput(); $('#settings_security_error').hide(); }); function check_passwords(password, password_confirm) { $('#settings_security_error').show(); alert('I\'m in funcion!'); // This works... if(password.length < 4) // ... this doesn't { $('#settings_security_error').innerHTML = 'Password too short'; } else { password = hex_md5(password); password_confirm = hex_md5(password_confirm); $.get('/engine/ajax/check_password.php?password=' + password + '$password_confirm=' + password_confirm, {language: "php", version: 5}, function(result) { $('#settings_security_error').innerHTML = result; }, 'html'); } } </script> <div class="title">Security</div> <table class="sub_container"> <tr> <td><label>Old password</label></td> <td class="td_input"><input type="password" name="old_password"/></td> </tr> <tr> <td><label>New password</label></td> <td class="td_input"><input type="password" name="new_password" id="settings_security_new_password" onkeyup="check_passwords(this.value, getElementById('settings_security_password_confirm').value)"/></td> </tr> <tr> <td><label>Confirm password</label></td> <td class="td_input"><input type="password" name="new_password_confirm" id="settings_security_password_confirm" onkeyup="check_passwords(getElementById('settings_security_new_password').value, this.value)"/></td> </tr> <tr> <td class="td_error" id="settings_security_error"></td> </tr> </table> And this is where the external HTML is placed...: <div id="settings_appearance"> </div> ... from this javascript snippet: function get_page_content(page, target_id) { $.get('engine/ajax/get_page_content.php?page=' + page, null, function(result) { $("#"+target_id).html(result); // Or whatever you need to insert the result }, 'html'); } Well... the problem is that the javascript in the first snippet is executed when it's loaded by the $.get function, but i still can't understand the reason why when i type into the input boxes nothing happen. It should write the output of the javascript function check_passwords(password, password_confirm) in <td class="td_error" id="settings_security_error"></td>. Thanks for helping. Silvio

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  • iPhone - How do I find the MAC address of the connected WiFi access point?

    - by Ciaran
    Without using the private APIs, is it possible to programatically determine the MAC address of the access point that the iPhone is connected to? I understand that this should be doable using the core BSD libraries, but we are new to this, so it would be great if someone can point us to some starter code. Note: we're trying to determine the MAC address of the remote device - not the MAC address of the iPhone.

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  • Is it possible to create a Mac OS specific CSS to fix font difference ?

    - by Gabriel
    I'm working on a project with a designer and he insisted on using some specific font for titles and various elements in the page. So we're using a font kit to embed with @font-face. It's working perfectly on PC (Firefox, IE 7 and 8, Chrome, Safari) but on Mac OS (Safari and Firefox) the fonts are not vertically aligned the same way. After looking on the Web, I didn't find any solution for this except "there always been differences between browsers and platforms, live with it". I know that fonts are never rendered exactly the same across platforms, but this time it's not something like the font looks more bold or something like that. The font looks as if it's baseline is completely different between Windows and Mac OS X. On Mac OS, the font, at a size of 16px is 3px higher than on PC. So I'm looking for a backup solution : is there a way to create a CSS specifically for Mac OS users? I do not want to target only Safari because Safari PC is ok, and Firefox Mac is not ok. Or if you have a solution to fix the baseline difference that does not require a specific CSS file, I'd be happy to hear it. Thanks!

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  • VirtualBox: How to connect to Internet via wi-fi on Mac?

    - by Paul Riedel
    I installed VirtualBox with a Win XP VM on my Mac running OS 10.7.5. My Mac only has a wi-fi connection to the internet. On the settings for the virtual host, I set: Attached to: Bridged Adapter Name: en1: Wi-Fi (AirPort) Adapter Type: Intel PRO/1000 MT Desktop (82540EM) Promiscuous Mode: Deny Mac Address: Cable Connected: true Those are the settings I see around the internet as being correct, but I still can't ping anything. On my Mac I have internet sharing via Ethernet enabled (not sure if that matters). When I start up my WinXP VM, it asks me to install a bunch of hardware which I don't have any drivers to. Do I need to install any ethernet card drivers in order for the internet to work? Thank you!!

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  • Scripting out Contained Database Users

    - by Argenis
      Today’s blog post comes from a Twitter thread on which @SQLSoldier, @sqlstudent144 and @SQLTaiob were discussing the internals of contained database users. Unless you have been living under a rock, you’ve heard about the concept of contained users within a SQL Server database (hit the link if you have not). In this article I’d like to show you that you can, indeed, script out contained database users and recreate them on another database, as either contained users or as good old fashioned logins/server principals as well. Why would this be useful? Well, because you would not need to know the password for the user in order to recreate it on another instance. I know there is a limited number of scenarios where this would be necessary, but nonetheless I figured I’d throw this blog post to show how it can be done. A more obscure use case: with the password hash (which I’m about to show you how to obtain) you could also crack the password using a utility like hashcat, as highlighted on this SQLServerCentral article. The Investigation SQL Server uses System Base Tables to save the password hashes of logins and contained database users. For logins it uses sys.sysxlgns, whereas for contained database users it leverages sys.sysowners. I’ll show you what I do to figure this stuff out: I create a login/contained user, and then I immediately browse the transaction log with, for example, fn_dblog. It’s pretty obvious that only two base tables touched by the operation are sys.sysxlgns, and also sys.sysprivs – the latter is used to track permissions. If I connect to the DAC on my instance, I can query for the password hash of this login I’ve just created. A few interesting things about this hash. This was taken on my laptop, and I happen to be running SQL Server 2014 RTM CU2, which is the latest public build of SQL Server 2014 as of time of writing. In 2008 R2 and prior versions (back to 2000), the password hashes would start with 0x0100. The reason why this changed is because starting with SQL Server 2012 password hashes are kept using a SHA512 algorithm, as opposed to SHA-1 (used since 2000) or Snefru (used in 6.5 and 7.0). SHA-1 is nowadays deemed unsafe and is very easy to crack. For regular SQL logins, this information is exposed through the sys.sql_logins catalog view, so there is really no need to connect to the DAC to grab an SID/password hash pair. For contained database users, there is (currently) no method of obtaining SID or password hashes without connecting to the DAC. If we create a contained database user, this is what we get from the transaction log: Note that the System Base Table used in this case is sys.sysowners. sys.sysprivs is used as well, and again this is to track permissions. To query sys.sysowners, you would have to connect to the DAC, as I mentioned previously. And this is what you would get: There are other ways to figure out what SQL Server uses under the hood to store contained database user password hashes, like looking at the execution plan for a query to sys.dm_db_uncontained_entities (Thanks, Robert Davis!) SIDs, Logins, Contained Users, and Why You Care…Or Not. One of the reasons behind the existence of Contained Users was the concept of portability of databases: it is really painful to maintain Server Principals (Logins) synced across most shared-nothing SQL Server HA/DR technologies (Mirroring, Availability Groups, and Log Shipping). Often times you would need the Security Identifier (SID) of these logins to match across instances, and that meant that you had to fetch whatever SID was assigned to the login on the principal instance so you could recreate it on a secondary. With contained users you normally wouldn’t care about SIDs, as the users are always available (and synced, as long as synchronization takes place) across instances. Now you might be presented some particular requirement that might specify that SIDs synced between logins on certain instances and contained database users on other databases. How would you go about creating a contained database user with a specific SID? The answer is that you can’t do it directly, but there’s a little trick that would allow you to do it. Create a login with a specified SID and password hash, create a user for that server principal on a partially contained database, then migrate that user to contained using the system stored procedure sp_user_migrate_to_contained, then drop the login. CREATE LOGIN <login_name> WITH PASSWORD = <password_hash> HASHED, SID = <sid> ; GO USE <partially_contained_db>; GO CREATE USER <user_name> FROM LOGIN <login_name>; GO EXEC sp_migrate_user_to_contained @username = <user_name>, @rename = N’keep_name’, @disablelogin = N‘disable_login’; GO DROP LOGIN <login_name>; GO Here’s how this skeleton would look like in action: And now I have a contained user with a specified SID and password hash. In my example above, I renamed the user after migrated it to contained so that it is, hopefully, easier to understand. Enjoy!

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  • Database Rebuild

    - by Robert May
    I promised I’d have a simpler mechanism for rebuilding the database.  Below is a complete MSBuild targets file for rebuilding the database from scratch.  I don’t know if I’ve explained the rational for this.  The reason why you’d WANT to do this is so that each developer has a clean version of the database on their local machine.  This also includes the continuous integration environment.  Basically, you can do whatever you want to the database without fear, and in a minute or two, have a completely rebuilt database structure. DBDeploy (including the KTSC build task for dbdeploy) is used in this script to do change tracking on the database itself.  The MSBuild ExtensionPack is used in this target file.  You can get an MSBuild DBDeploy task here. There are two database scripts that you’ll see below.  First is the task for creating an admin (dbo) user in the system.  This script looks like the following: USE [master] GO If not Exists (select Name from sys.sql_logins where name = '$(User)') BEGIN CREATE LOGIN [$(User)] WITH PASSWORD=N'$(Password)', DEFAULT_DATABASE=[$(DatabaseName)], CHECK_EXPIRATION=OFF, CHECK_POLICY=OFF END GO EXEC master..sp_addsrvrolemember @loginame = N'$(User)', @rolename = N'sysadmin' GO USE [$(DatabaseName)] GO CREATE USER [$(User)] FOR LOGIN [$(User)] GO ALTER USER [$(User)] WITH DEFAULT_SCHEMA=[dbo] GO EXEC sp_addrolemember N'db_owner', N'$(User)' GO The second creates the changelog table.  This script can also be found in the dbdeploy.net install\scripts directory. CREATE TABLE changelog ( change_number INTEGER NOT NULL, delta_set VARCHAR(10) NOT NULL, start_dt DATETIME NOT NULL, complete_dt DATETIME NULL, applied_by VARCHAR(100) NOT NULL, description VARCHAR(500) NOT NULL ) GO ALTER TABLE changelog ADD CONSTRAINT Pkchangelog PRIMARY KEY (change_number, delta_set) GO Finally, Here’s the targets file. <Projectxmlns="http://schemas.microsoft.com/developer/msbuild/2003" ToolsVersion="4.0" DefaultTargets="Update">   <PropertyGroup>     <DatabaseName>TestDatabase</DatabaseName>     <Server>localhost</Server>     <ScriptDirectory>.\Scripts</ScriptDirectory>     <RebuildDirectory>.\Rebuild</RebuildDirectory>     <TestDataDirectory>.\TestData</TestDataDirectory>     <DbDeploy>.\DBDeploy</DbDeploy>     <User>TestUser</User>     <Password>TestPassword</Password>     <BCP>bcp</BCP>     <BCPOptions>-S$(Server) -U$(User) -P$(Password) -N -E -k</BCPOptions>     <OutputFileName>dbDeploy-output.sql</OutputFileName>     <UndoFileName>dbDeploy-output-undo.sql</UndoFileName>     <LastChangeToApply>99999</LastChangeToApply>   </PropertyGroup>     <ImportProject="$(MSBuildExtensionsPath)\ExtensionPack\4.0\MSBuild.ExtensionPack.tasks"/>   <UsingTask TaskName="Ktsc.Build.DBDeploy" AssemblyFile="$(DbDeploy)\Ktsc.Build.dll"/>   <ItemGroup>     <VariableInclude="DatabaseName">       <Value>$(DatabaseName)</Value>     </Variable>     <VariableInclude="Server">       <Value>$(Server)</Value>     </Variable>     <VariableInclude="User">       <Value>$(User)</Value>     </Variable>     <VariableInclude="Password">       <Value>$(Password)</Value>     </Variable>   </ItemGroup>     <TargetName="Rebuild">     <!--Take the database offline to disconnect any users. Requires that the current user is an admin of the sql server machine.-->     <MSBuild.ExtensionPack.SqlServer.SqlCmd Variables="@(Variable)" Database="$(DatabaseName)" TaskAction="Execute" CommandLineQuery ="ALTER DATABASE $(DatabaseName) SET OFFLINE WITH ROLLBACK IMMEDIATE"/>         <!--Bring it back online.  If you don't, the database files won't be deleted.-->     <MSBuild.ExtensionPack.Sql2008.DatabaseTaskAction="SetOnline" DatabaseItem="$(DatabaseName)"/>     <!--Delete the database, removing the existing files.-->     <MSBuild.ExtensionPack.Sql2008.DatabaseTaskAction="Delete" DatabaseItem="$(DatabaseName)"/>     <!--Create the new database in the default database path location.-->     <MSBuild.ExtensionPack.Sql2008.DatabaseTaskAction="Create" DatabaseItem="$(DatabaseName)" Force="True"/>         <!--Create admin user-->     <MSBuild.ExtensionPack.SqlServer.SqlCmd TaskAction="Execute" Server="(local)" Database="$(DatabaseName)" InputFiles="$(RebuildDirectory)\0002 Create Admin User.sql" Variables="@(Variable)" />     <!--Create the dbdeploy changelog.-->     <MSBuild.ExtensionPack.SqlServer.SqlCmd TaskAction="Execute" Server="(local)" Database="$(DatabaseName)" LogOn="$(User)" Password="$(Password)" InputFiles="$(RebuildDirectory)\0003 Create Changelog.sql" Variables="@(Variable)" />     <CallTarget Targets="Update;ImportData"/>     </Target>    <TargetName="Update" DependsOnTargets="CreateUpdateScript">     <MSBuild.ExtensionPack.SqlServer.SqlCmd TaskAction="Execute" Server="(local)" Database="$(DatabaseName)" LogOn="$(User)" Password="$(Password)" InputFiles="$(OutputFileName)" Variables="@(Variable)" />   </Target>   <TargetName="CreateUpdateScript">     <ktsc.Build.DBDeploy DbType="mssql"                                        DbConnection="User=$(User);Password=$(Password);Data Source=$(Server);Initial Catalog=$(DatabaseName);"                                        Dir="$(ScriptDirectory)"                                        OutputFile="..\$(OutputFileName)"                                        UndoOutputFile="..\$(UndoFileName)"                                        LastChangeToApply="$(LastChangeToApply)"/>   </Target>     <TargetName="ImportData">     <ItemGroup>       <TestData Include="$(TestDataDirectory)\*.dat"/>     </ItemGroup>     <ExecCommand="$(BCP) $(DatabaseName).dbo.%(TestData.Filename) in&quot;%(TestData.Identity)&quot;$(BCPOptions)"/>   </Target> </Project> Technorati Tags: MSBuild

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  • Enterprise Manager Database Control Configuration - Recovering From Errors Due to CA Expiry on Oracle Database 10.2.0.4 or 10.2.0.5 from 31-Dec-2010 onwards

    - by jayatheertha.rao(at)oracle.com
    Description What is the Issue? In Enterprise Manager Database Control with Oracle Database 10.2.0.4 and 10.2.0.5, the root certificate used to secure communications via the Secure Socket Layer (SSL) protocol will expire on 31-Dec-2010 00:00:00. The certificate expiration will cause errors if you attempt to configure Database Control on or after 31-Dec-2010. Existing Database Control configurations are not affected by this issue. Likelihood of Occurrence What Versions Are Affected? The issue impacts configuration of Database Control with Oracle Database 10.2.0.4 and 10.2.0.5 only. It does not impact database creation or upgrade. The issue does not impact existing Database Control configurations. What Happens During Database Control Configuration Failure? Database Configuration Assistant (DBCA) and Database Upgrade Assistant (DBUA) Errors Database Configuration Assistant (DBCA) and Database Upgrade Assistant (DBUA) will report the following error in the console: Could not complete the Enterprise Manager configuration.Enterprise manager configuration failed due to the following error -Error starting Database Control Enterprise Manager Configuration Assistant (EMCA) Errors Enterprise Manager Configuration Assistant (EMCA) will write errors similar to those below to the emca.log file: CONFIG: Securing Database Control completed successfully .Jan 2, 2011 7:22:47 PM oracle.sysman.emcp.ParamsManager getParamCONFIG: No value was set for the parameter ORACLE_HOSTNAME.Jan 2, 2011 7:22:47 PM oracle.sysman.emcp.util.DBControlUtil startOMSINFO: Starting Database Control (this may take a while) ...Jan 2, 2011 7:22:47 PM oracle.sysman.emcp.util.PlatformInterface addEnvVarToListCONFIG: Value for env var 'ORACLE_HOSTNAME' is '', discarding the sameCONFIG: Returning env array from cacheJan 2, 2011 7:22:47 PM oracle.sysman.emcp.util.PlatformInterface executeCommandCONFIG: Starting execution: /myhost/bin/emctl start dbconsoleJan 2, 2011 7:27:26 PM oracle.sysman.emcp.util.PlatformInterface executeCommandCONFIG: Exit value of 1Jan 2, 2011 7:27:26 PM oracle.sysman.emcp.util.PlatformInterface executeCommandCONFIG: Oracle Enterprise Manager 10g Database Control Release 10.2.0.4.0Copyright (c) 1996, 2007 Oracle Corporation. All rights reserved.https://myhost:5501/em/console/aboutApplicationStarting Oracle Enterprise Manager 10g Database Control............................................................................................. failed.------------------------------------------------------------------Logs are generated in directory /myhost/sysman/logJan 2, 2011 7:27:26 PM oracle.sysman.emcp.util.PlatformInterface executeCommandWARNING: Error executing /myhost/bin/emctl start dbconsoleJan 2, 2011 7:27:26 PM oracle.sysman.emcp.EMConfig performSEVERE: Error starting Database ControlRefer to the log file at /myhost/dbua/d4/upgrade/emConfig.log for more details.Jan 2, 2011 7:27:26 PM oracle.sysman.emcp.EMConfig performCONFIG: Stack Trace:oracle.sysman.emcp.exception.EMConfigException: Error starting Database Controlat oracle.sysman.emcp.EMDBPostConfig.performUpgrade(EMDBPostConfig.java:763)at oracle.sysman.emcp.EMDBPostConfig.invoke(EMDBPostConfig.java:232)at oracle.sysman.emcp.EMDBPostConfig.invoke(EMDBPostConfig.java:193)at oracle.sysman.emcp.EMConfig.perform(EMConfig.java:184)at oracle.sysman.assistants.util.em.EMConfiguration.run(EMConfiguration.java:436)at oracle.sysman.assistants.util.em.EMConfigStep.executeImpl(EMConfigStep.java:140)at oracle.sysman.assistants.util.step.BasicStep.execute(BasicStep.java:210)at oracle.sysman.assistants.util.step.BasicStep.callStep(BasicStep.java:251)at oracle.sysman.assistants.dbma.backend.EMConfigStep.executeStepImpl(EMConfigStep.java:104)at oracle.sysman.assistants.dbma.backend.SummarizableStep.executeImpl(SummarizableStep.java:175)at oracle.sysman.assistants.util.step.BasicStep.execute(BasicStep.java:210)at oracle.sysman.assistants.util.step.Step.execute(Step.java:140)at oracle.sysman.assistants.util.step.StepContext$ModeRunner.run(StepContext.java:2488)at java.lang.Thread.run(Thread.java:534) The EMCA console will display output similar to the following: aime@myhost09 db_1]$ bin/emca -config dbcontrol db -repos recreate -clusterSTARTED EMCA at Jan 11, 2011 4:11:01 PMEM Configuration Assistant, Version 10.2.0.1.0 ProductionCopyright (c) 2003, 2005, Oracle. All rights reserved.Enter the following information:Database unique name: catestDatabase Control is already configured for the database catestYou have chosen to configure Database Control for managing the database catestThis will remove the existing configuration and the default settings and perform a fresh configurationDo you wish to continue? [yes(Y)/no(N)]: YListener port number: 1521Cluster name: myclusterPassword for SYS user:Password for DBSNMP user:Password for SYSMAN user:Email address for notifications (optional):Outgoing Mail (SMTP) server for notifications (optional):........Jan 11, 2011 4:18:05 PM oracle.sysman.emcp.util.DBControlUtil secureDBConsoleINFO: Securing Database Control (this may take a while) ...Jan 11, 2011 4:19:31 PM oracle.sysman.emcp.util.DBControlUtil startOMSINFO: Starting Database Control (this may take a while) ...Jan 11, 2011 4:28:38 PM oracle.sysman.emcp.EMConfig performSEVERE: Error starting Database ControlRefer to the log file at /myhost/oracle/product/10.2.0/db_1/cfgtoollogs/emca/catest/emca_2011-01-11_04-11-01-PM.log for more details.Could not complete the configuration. Refer to the log file at /myhost/oracle/product/10.2.0/db_1/cfgtoollogs/emca/catest/emca_2011-01-11_04-11-01-PM.log for more details. At the end of the database installation on non-Windows platforms, both Database Control and the Management Agent will be up and running, even though the status of both components will be shown as not running, because EMCTL will be unable to connect to the dbconsole process. In addition, Database Control will fail to connect to the Agent. Note for Windows Platform Only:On Windows, the dbconsole process will be stopped after the failed configuration attempt. Note that the tool used to perform Database Control configuration (DBUA, DBCA or EMCA) will also wait for 15 minutes for Database Control to start, then time out. The output of the "emctl status dbconsole" command incorrectly returns the status of Database Control, as shown below: $ ./emctl status dbconsoleOracle Enterprise Manager 10g Database Control Release 10.2.0.1.0Copyright (c) 1996, 2005 Oracle Corporation. All rights reserved.https://myhost:1158/em/console/aboutApplicationOracle Enterprise Manager 10g is not running. The output of the "emctl status agent" command incorrectly returns the status of the Agent, as shownbelow: $ ./emctl status agentOracle Enterprise Manager 10g Database Control Release 10.2.0.1.0Copyright (c) 1996, 2005 Oracle Corporation. All rights reserved.---------------------------------------------------------------Agent is Not Running   For Solution, refer to Note: 1222603.1 Note: 1217493.1

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  • How does browser know when to prompt user to save password?

    - by Eric
    This is related to the question I asked here: http://stackoverflow.com/questions/2382329/how-can-i-get-browser-to-prompt-to-save-password This is the problem: I CAN'T get my browser to prompt me to save the password for the site I'm developing. (I'm talking about the bar that appears sometimes when you submit a form on Firefox, that says "Remember the password for yoursite.com? Yes / Not now / Never") This is super frustrating because this feature of Firefox (and most other modern browsers, which I hope work in a similar fashion) seems to be a mystery. It's like a magic trick the browser does, where it looks at your code, or what you submit, or something, and if it "looks" like a login form with a username (or email address) field and a password field, it offers to save. Except in this case, where it's not offering my users that option after they use my login form, and it's making me nuts. :-) (I checked my Firefox settings-- I have NOT told the browser "never" for this site. It should be prompting.) My question: exactly what the heuristics are that Firefox (or any other modern browser) uses to know when it should prompt the user to save? This shouldn't be too difficult to answer, since it's right there in the Mozilla source (I don't know where to look or else I'd try to dig it out myself). You'd think there would be a blog post or some other similar developer note from the Mozilla developers about this but I can't find that either. (* Note that if your answer to me has anything to do with cookies, encryption or anything else that is about how I'm storing the user's passwords in the database, you've probably misread my question. :-)

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  • PHP/MySQL allowing current user to edit there account information

    - by user1837896
    i have created 2 pages update.php edit.php we start on edit.php so here is edit.php's script <?php session_start(); $id = $_SESSION["id"]; $username = $_POST["username"]; $fname = $_POST["fname"]; $password = $_POST["password"]; $email = $_POST["email"]; mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); echo "MySQL Connection Established! <br>"; mysql_select_db("a2670376_Pass") or die(mysql_error()); echo "Database Found! <br>"; $query = "UPDATE members SET username = '$username', fname = '$fname', password = '$password' WHERE id = '$id'"; $res = mysql_query($query); if ($res) echo "<p>Record Updated<p>"; else echo "Problem updating record. MySQL Error: " . mysql_error(); ?> <form action="update.php" method="post"> <input type="hidden" name="id" value="<?=$id;?>"> ScreenName:<br> <input type='text' name='username' id='username' maxlength='25' style='width:247px' name="username" value="<?=$username;?>"/><br> FullName:<br> <input type='text' name='fname' id='fname' maxlength='20' style='width:248px' name="ud_img" value="<?=$fname;?>"/><br> Email:<br> <input type='text' name='email' id='email' maxlength='50' style='width:250px' name="ud_img" value="<?=$email;?>"/><br> Password:<br> <input type='text' name='password' id='password' maxlength='25' style='width:251px' value="<?=$password;?>"/><br> <input type="Submit"> </form> now here is the update.php page where i am having the MAJOR problem <?php session_start(); mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); mysql_select_db("a2670376_Pass") or die(mysql_error()); $id = (int)$_SESSION["id"]; $username = mysql_real_escape_string($_POST["username"]); $fname = mysql_real_escape_string($_POST["fname"]); $email = mysql_real_escape_string($_POST["email"]); $password = mysql_real_escape_string($_POST["password"]); $query="UPDATE members SET username = '$username', fname = '$fname', email = '$email', password = '$password' WHERE id='$id'"; mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ echo "<p>($id) Record Updated<p>"; }else{ echo "<p>($id) Not Updated<p>"; } ?> now on edit.php i fill out the form to edit the account "test" while i am logged into it now once the form if filled out i click on |Submit!| button and it takes me to update.php and it returns this (0) Not Updated (0) <= id of user logged in Not Updated <= MySql Error from mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ i want it to update the user logged in and if i am not mistaken in this script it says $id = (int)$_SESSION["id"]; witch updates the user with the id of the person who is logged in but it isnt updating its saying that no tables were effected if it helps heres my MySql Database picture just click here http://i50.tinypic.com/21juqfq.png if this could possibly be any help to find the solution i have 2 more files delete.php and delete_ac.php they have can remove users from my sql database and they show the user id and it works there are no bugs in this script at all PLEASE DO NOT MAKE SUGGESTIONS FOR THE SCRIPTS BELOW delete.php first <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="PASSWORD"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // select record from mysql $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); ?> <table border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" style="bgcolor: #FFFFFF"><strong><img src="http://i47.tinypic.com/u6ihk.png" height="30" widht="30">Delete data in mysql</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>UserName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>FullName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Password</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Date</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Ip</strong></td> <td align="center" bgcolor="#FFFFFF">&nbsp;</td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['username']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['fname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['password']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['date']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['ip']; ?></td> <td bgcolor="#FFFFFF"><a href="delete_ac.php?id=<? echo $rows['id']; ?>">delete</a></td> </tr> <?php // close while loop } ?> </table> <?php // close connection; sql_close(); ?> and now delete_ac.php <table width="500" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" bgcolor="#FFFFFF"><strong><img src="http://t2.gstatic.com/images? q=tbn:ANd9GcS_kwpNSSt3UuBHxq5zhkJQAlPnaXyePaw07R652f4StmvIQAAf6g" height="30" widht="30">Removal Of Account</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"> <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="javascript00"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['id']; // Delete data in mysql from row that has this id $sql="DELETE FROM $tbl_name WHERE id='$id'"; $result=mysql_query($sql); // if successfully deleted if($result){ echo "Deleted Successfully"; echo "<BR>"; echo "<a href='delete.php'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?> </td> </tr> </table>

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  • Account Lockout with pam_tally2 in RHEL6

    - by Aaron Copley
    I am using pam_tally2 to lockout accounts after 3 failed logins per policy, however, the connecting user does not receive the error indicating pam_tally2's action. (Via SSH.) I expect to see on the 4th attempt: Account locked due to 3 failed logins No combination of required or requisite or the order in the file seems to help. This is under Red Hat 6, and I am using /etc/pam.d/password-auth. The lockout does work as expected but the user does not receive the error described above. This causes a lot of confusion and frustration as they have no way of knowing why authentication fails when they are sure they are using the correct password. Implementation follows NSA's Guide to the Secure Conguration of Red Hat Enterprise Linux 5. (pg.45) It's my understanding that that only thing changed in PAM is that /etc/pam.d/sshd now includes /etc/pam.d/password-auth instead of system-auth. If locking out accounts after a number of incorrect login attempts is required by your security policy, implement use of pam_tally2.so. To enforce password lockout, add the following to /etc/pam.d/system-auth. First, add to the top of the auth lines: auth required pam_tally2.so deny=5 onerr=fail unlock_time=900 Second, add to the top of the account lines: account required pam_tally2.so EDIT: I get the error message by resetting pam_tally2 during one of the login attempts. user@localhost's password: (bad password) Permission denied, please try again. user@localhost's password: (bad password) Permission denied, please try again. (reset pam_tally2 from another shell) user@localhost's password: (good password) Account locked due to ... Account locked due to ... Last login: ... [user@localhost ~]$

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  • Is there a client for Google Talk, for Mac, that allows phone calls?

    - by xtraorange
    I'm having no luck finding a client for Google Talk that is both for Mac (OSX) and that allows phone calls (not just chatting with other Google Talk users). If I leave the browser page open to gmail, it will ring when I receive a call to my Google Voice number, and I can call out from my Google Voice number, but I don't want to use the browser. Is there any sort of client, for Mac, that will allow calls through Google Talk?

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