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  • MySQL look for missing ratings

    - by Dustin
    Hopefully I can ask this without being confusing. I am a photographer and I am having some of our clients rate pictures that we have taken. We have hundreds of pictures in our portfolio that they may be rating. What I want to do is ask our clients to rate pictures again, but only show them the pictures they haven't yet rated. I currently have three tables: one that stores the actual ratings, one that stores the pictures (or location of each picture), and one that stores the information about the rater. I'm using codeigniter for my db management, if that helps at all. What I have so far is this: "SELECT * FROM ratings LEFT JOIN portfolio ON ratings.portfolioid = portfolio.portfolioid" This will give me a row for each rating, but won't show me where a rating is missing for a picture. Thanks in advance!

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  • mysql table creation problem..

    - by pradeep
    Hi, I have a small problem. I am creating an appointment table where in the foreign key is patient id which is referenced from patient table.This table is for all registered patients. there will be unregistered patients also, who will be seeking appointments.SO i just need to store the name,phone and few details. I don't want to make these 2 as different tables. So is there a way to skip the integrity check of foreign key when i ma inserting unregistered patient data

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  • MySQL: optimization of table (indexing, foreign key) with no primary keys

    - by Haradzieniec
    Each member has 0 or more orders. Each order contains at least 1 item. memberid - varchar, not integer - that's OK (please do not mention that's not very good, I can't change it). So, thera 3 tables: members, orders and order_items. Orders and order_items are below: CREATE TABLE `orders` ( `orderid` INT(11) UNSIGNED NOT NULL AUTO_INCREMENT, `memberid` VARCHAR( 20 ), `Time` TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP , `info` VARCHAR( 3200 ) NULL , PRIMARY KEY (orderid) , FOREIGN KEY (memberid) REFERENCES members(memberid) ) ENGINE = InnoDB; CREATE TABLE `order_items` ( `orderid` INT(11) UNSIGNED NOT NULL, `item_number_in_cart` tinyint(1) NOT NULL , --- 5 items in cart= 5 rows `price` DECIMAL (6,2) NOT NULL, FOREIGN KEY (orderid) REFERENCES orders(orderid) ) ENGINE = InnoDB; So, order_items table looks like: orderid - item_number_in_cart - price: ... 1000456 - 1 - 24.99 1000456 - 2 - 39.99 1000456 - 3 - 4.99 1000456 - 4 - 17.97 1000457 - 1 - 20.00 1000458 - 1 - 99.99 1000459 - 1 - 2.99 1000459 - 2 - 69.99 1000460 - 1 - 4.99 ... As you see, order_items table has no primary keys (and I think there is no sense to create an auto_increment id for this table, because once we want to extract data, we always extract it as WHERE orderid='1000456' order by item_number_in_card asc - the whole block, id woudn't be helpful in queries). Once data is inserted into order_items, it's not UPDATEd, just SELECTed. The questions are: I think it's a good idea to put index on item_number_in_cart. Could anybody please confirm that? Is there anything else I have to do with order_items to increase the performance, or that looks pretty good? I could miss something because I'm a newbie. Thank you in advance.

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  • php mysql error beginner

    - by Marcelo
    Hi, I'm trying to print some values on the screen from a table but I having a problem, I don't know much about string, vector and array but I think that my problem is related to them. I'm getting this on the screen Fatal error: Cannot use [] for reading ... My code $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql) or trigger_error(mysql_error().$sql); while($row = mysql_fetch_array($result)){ $DATA = $row[]; } //line with probelm mysql_close(); //html part <table> <? foreach($DATA as $row): ?> <tr> <td><?=$row['id']?></td> //more stuff </tr> <? endforeach ?> </table> What I'm trying to do is print somevalues form a database. But I'm getting this error. I'm sorry for any mistake in English, and thanks in advance for any help.

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  • MySQL Casting in C#

    - by user798080
    Okay, so I'm attempting to print out the contents of a table in a comma-separated file. using (OdbcCommand com = new OdbcCommand("SELECT * FROM pie_data WHERE Pie_ID = ?", con)) { com.Parameters.AddWithValue("", Request.Form["pie_id"]); com.ExecuteNonQuery(); using (OdbcDataReader reader = com.ExecuteReader()) { string finalstring = ""; while (reader.Read()) { finalstring = reader.GetString(9) + ","; for (int i = 0; i <= 8; i = i + 1) { finalstring = finalstring + reader.GetString(i) + ","; } } } Response.Write(finalstring); noredirect = 1; } My table layout is: CREATE TABLE `rent_data` ( `Pies` INT(10) UNSIGNED NOT NULL, `Name` VARCHAR(85) NOT NULL, `Email` VARCHAR(85) NOT NULL, `Pie_Rent` DATE NOT NULL, `Rent_To` DATE NOT NULL, `Returned_Date` DATE NULL DEFAULT NULL, `Place` VARCHAR(100) NOT NULL, `Purpose` MEDIUMTEXT NOT NULL, `Comments` MEDIUMTEXT NULL, `Pie_ID` SMALLINT(5) UNSIGNED ZEROFILL NOT NULL, INDEX `Pie_ID` (`Equipment_ID`) ) The error I'm getting is this: Exception Details: System.InvalidCastException: Unable to cast object of type 'System.Int64' to type 'System.String'. On the line: finalstring = finalstring + reader.GetString(i) + ",";

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  • Mysql Query is not working, why?

    - by Furkan Kadioglu
    Im using this example: www.jtable.org Now i download to jtable php version. And i edited script. Jtable simple version is working but my edition is doesnt working. I can do list, but i cant do add a row; this codes having problem. But php doesnt giving any error. else if($_GET["action"] == "create") { //Insert record into database $result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'"); //Get last inserted record (to return to jTable) $result = mysql_query("SELECT * FROM veriler WHERE id = LAST_INSERT_ID();"); $row = mysql_fetch_array($result); //Return result to jTable $jTableResult = array(); $jTableResult['Result'] = "OK"; $jTableResult['Record'] = $row; print json_encode($jTableResult); } if you doesnt understand, please ask me question. Where is the problem?

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  • My MYSQL & PHP while code is out of memory, when there is only one row

    - by Sam
    Hey all, why is this code throwing an out of memory error, when there is only 1 row in the database.. $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); $request = mysql_fetch_array( $request_db ); echo "<table border=\"1\" align=\"center\">"; while ( $request['haveplayed'] == "0" ) { echo "<tr><td>"; echo $request['SongName']; echo "</td><td>"; echo "<tr><td>"; echo $request['Artist']; echo "</td><td>"; echo "<tr><td>"; echo $request['DedicatedTo']; echo "</td><td>"; } echo "</table>"; Thanks.

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  • Selecting data from mysql table and related data from another to join them

    - by knittledan
    Ive looked at other questions and answers but still dont understand which brings me here. I have one data base two tables. lets say table1 and table2 from database. I'm looking to grab all the information from table1 and only one column from table2 that coincides with the correct row in table1. Example which I know is wrong: SELECT table1.*, table2.time_stamp FROM table1, table2 WHERE table1.ticket_id=$var AND table1.user_id = table2.user_id Basically select data from table1 then use a value from the selected table to grab the related data from table2 and join them to output them as one mysql_query. Im sure its simple and has been asked before. edit: I dont receive an error. SQL just returns noting. log form of this would be: $sqlResults = mysql_query("SELECT table1.* FROM table1 WHERE table1.ticket_id=$var") while($rowResult = mysql_fetch_array( $sqlResults )) { $userID = $rowResult['user_id']; $sqlResults2 = mysql_query("SELECT table2.time_stamp FROM table2 WHERE table2.user_id=$userID") } I want to combine that into one sql statement so i dont have to hit table2 for every row table1 has

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  • How to change data structure in mysql using mysqldump without deleting files

    - by Don Quixote
    Essentially what I'm trying to do is sync a production server with a sandbox server, but only the table structures and stored procedures. The procedures aren't any problem since they can be overriden, but the problem is the tables. I want to sync and alter their structures on the production server using mysqldump (or any other way that you can propose) without altering any existing data. If it helps, I only want to add more columns, not remove any existing ones. Also, I am using mysqlyog. Is there any way to do this?

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  • select similar value from MySQL and order the result

    - by mathew
    how do I order this result?? $range = 5; // you'll be selecting around this range. $min = $rank - $range; $max = $rank + $range; $limit = 10; // max number of results you want. $result = mysql_query("select * from table where rank between $min and $max limit $limit"); while($row = mysql_fetch_array($result)) { echo $row['name']."&nbsp;-&nbsp;".$row['rank']."<br>"; }

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  • What data actually gets cached in InnoDB/MySQL?

    - by ming yeow
    Hi folks, i am trying to optimize performance for my database. My question is - what get cached in the db memory? For example: (table with 2 columns: key (indexed), data (not indexed) updated (not indexed) Select * where updated=20100202 (the db will do a scan - will the scanned rows be kept in memory?) Select * where key = 20 (the db will refer to the index - will the identified rows be kept in memory?)

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  • significance of index name in creating an index (mySQL)

    - by Will
    I've done something like this in order to use on duplicate key update: CREATE UNIQUE INDEX blah on mytable(my_col_to_make_an_index); and its worked just fine. I'm just not sure what the purpose of the index name is -- in this case 'blah'. The stuff I've read says to use one but I can't fathom why. It doesn't seem to be used in queries, although I can see it if I export the schema. So ... what purpose does the index name serve? If it helps the line in the CREATE TABLE ends up looking like: UNIQUE KEY `clothID` (`clothID`)

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  • Mysql insert into 2 tables

    - by Spidfire
    I want to make a insert into 2 tables visits: visit_id int | card_id int registration: registration_id int | type enum('in','out') | timestamp int | visit_id int i want something like: INSERT INTO `visits` as v ,`registration` as v (v.`visit_id`,v.`card_id`,r.`registration_id`, r.`type`, r.`timestamp`, r.`visit_id`) VALUES (NULL, 12131141,NULL, UNIX_TIMESTAMP(), v.`visit_id`); I wonder if its possible

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  • Help with MySQL Query?

    - by Devyn
    I have two tables rooms and users. I want to get only rooms.room_id, users.user_name with user_id = 1. I can get the result of all users with following sql... select rooms.room_id, rooms.user_id, users.user_name from rooms LEFT JOIN users ON rooms.user_id = users.user_id When I do like this to filter the result with user_id = 1 ... I got error. select rooms.room_id, rooms.user_id, users.user_name from rooms where rooms.user_id = 1 LEFT JOIN users ON rooms.user_id = users.user_id What should I do?

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  • MySQL foreign key constraint disappearing

    - by Bramjam
    This is my table: /* oefenreeks leerplan */ CREATE TABLE leerplan_oefenreeks ( leerplan_oefenreeks_id INT PRIMARY KEY AUTO_INCREMENT NOT NULL, leerplan_id INT NOT NULL, oefenreeks_id INT NOT NULL, plaats INT NOT NULL ); /* fk */ ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT fk_leerp_oefenr_leerplan FOREIGN KEY(leerplan_id) REFERENCES leerplan (leerplan_id) ON DELETE CASCADE; ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT fk_leerp_oefenr_oefenreeks FOREIGN KEY(oefenreeks_id) REFERENCES oefenreeks (oefenreeks_id) ON DELETE CASCADE; /* when I execute the nexline, my fk_leerp_oefenr_leerplan constraint vanishes/disappears*/ ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT un_leerp_oefenr UNIQUE(leerplan_id, oefenreeks_id); ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT un_leerp_oefenr_plaats UNIQUE(leerplan_id, plaats); When I go and check only 3 constraints exist. fk_leerp_oefenr_leerplan disappears. I don't understand why this happens.

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  • Complex MySQL table select/join with pre-condition

    - by Howard
    Hello, I have the schema below CREATE TABLE `vocabulary` ( `vid` int(10) unsigned NOT NULL auto_increment, `name` varchar(255), PRIMARY KEY vid (`vid`) ); CREATE TABLE `term` ( `tid` int(10) unsigned NOT NULL auto_increment, `vid` int(10) unsigned NOT NULL default '0', `name` varchar(255), PRIMARY KEY tid (`tid`) ); CREATE TABLE `article` ( `aid` int(10) unsigned NOT NULL auto_increment, `body` text, PRIMARY KEY aid (`aid`) ); CREATE TABLE `article_index` ( `nid` int(10) unsigned NOT NULL default '0', `tid` int(10) unsigned NOT NULL default '0' ) INSERT INTO `vocabulary` values (1, 'vocabulary 1'); INSERT INTO `vocabulary` values (2, 'vocabulary 2'); INSERT INTO `term` values (1, 1, 'term v1 t1'); INSERT INTO `term` values (2, 1, 'term v1 t2 '); INSERT INTO `term` values (3, 2, 'term v2 t3'); INSERT INTO `term` values (4, 2, 'term v2 t4'); INSERT INTO `term` values (5, 2, 'term v2 t5'); INSERT INTO `article` values (1, ""); INSERT INTO `article` values (2, ""); INSERT INTO `article` values (3, ""); INSERT INTO `article` values (4, ""); INSERT INTO `article` values (5, ""); INSERT INTO `article_index` values (1, 1); INSERT INTO `article_index` values (1, 3); INSERT INTO `article_index` values (2, 2); INSERT INTO `article_index` values (3, 1); INSERT INTO `article_index` values (3, 3); INSERT INTO `article_index` values (4, 3); INSERT INTO `article_index` values (5, 3); INSERT INTO `article_index` values (5, 4); Example. Select term of a defiend vocabulary (with non-zero article index), e.g. vid=2 select a.tid, count(*) as article_count from term t JOIN article_index a ON t.tid = a.tid where t.vid = 2 group by t.tid; +-----+---------------+ | tid | article_count | +-----+---------------+ | 3 | 4 | | 4 | 1 | +-----+------------ Question: Select terms a. of a defiend vocabulary (with non-zero article index, e.g. vid=1 = term {1,2}) b. given that those terms are linked with articles which are linked with terms under vid=2, e.g. = {1}, term with tid=2 is excluded since no linkage to terms under vid=2 SQL: Any idea? Expected result: +-----+---------------+ | tid | article_count | +-----+---------------+ | 1 | 2 | +-----+---------------+

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  • Foreign keys and NULL in mySQL

    - by Industrial
    Hi everyone, Can I have a column in my values table (value) referenced as a foreign key to knownValues table, and let it be NULL whenever needed, like in the example: Table: values product type value freevalue 0 1 NULL 100 1 2 NULL 25 3 3 1 NULL Table: types id name prefix 0 length cm 1 weight kg 2 fruit NULL Table: knownValues id Type name 0 2 banana Note: The types in the table values & knownValues are of course referenced into the types table. Thanks!

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  • Help creating a SQL Query

    - by Wes
    Somewhat new to SQL queries and I need a little help with my join. I am supplied with gid For each of these I need to grab name from table wp_ngg_gallery then join in table wp_ngg_pictures and grab field filename limit 1 order DESC by field imagedate Anyone able to help?

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  • retrive data from mysql using php and jquery

    - by user313835
    i have a menu, it contains multiple items, each menu item will retrieve data from the database. i want to do it without the page refresh, i want like an area that will change when the user clicks on the menu link. How should i send data to the php script and how should i get it from there and preview it on the page. if you can send me any information, references or examples that will be great Thanks in advance.

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  • After 30 seconds, update MYSQL databse

    - by Sam
    Hello everyone! I've been looking around here on SO and Googling, however I can't find anything that fits my description. What I want to do is update the database if the page has not been refreshed after 30 seconds. I want to email a person with the contents of a form {submitted by a different user} (I can do that) IF the person has NOT visited the page (I can do that) within the last 30 seconds. What I've tried to do is make the page that should be visited refresh every 30 seconds, and so I figured if I did something like after 31 seconds, edit the database (so if the refreshed page was not refreshed, the database editing would run). I'm sorry if this sounds complicated, there's probably a better way to do this, but I'm not sure how. The bigger picture is I'm trying to make a 'on-duty' sort of thing, so that if the person is not actively looking at the page, they will get emailed with whatever the contents of the form is. The page will contain a table of all the entered form results.

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