Search Results

Search found 10433 results on 418 pages for 'session replication'.

Page 228/418 | < Previous Page | 224 225 226 227 228 229 230 231 232 233 234 235  | Next Page >

• MySQL developer here -- Nesting with select * finicky in Oracle 10g?

  - by John Sullivan

  I'm writing a simple diagnostic query then attempting to execute it in the Oracle 10g SQL Scratchpad. EDIT: It will not be used in code. I'm nesting a simple "Select *" and it's giving me errors. In the SQL Scratchpad for Oracle 10g Enterprise Manager Console, this statement runs fine. SELECT * FROM v$session sess, v$sql sql WHERE sql.sql_id(+) = sess.sql_id and sql.sql_text <> ' ' If I try to wrap that up in Select * from () tb2 I get an error, "ORA-00918: Column Ambiguously Defined". I didn't think that could ever happen with this kind of statement so I am a bit confused. select * from (SELECT * FROM v$session sess, v$sql sql WHERE sql.sql_id(+) = sess.sql_id and sql.sql_text <> ' ') tb2 You should always be able to select * from the result set of another select * statement using this structure as far as I'm aware... right? Is Oracle/10g/the scratchpad trying to force me to accept a certain syntactic structure to prevent excessive nesting? Is this a bug in scratchpad or something about how oracle works?

  Read the article

• Get Nhibernate entity and complete it from a web service.

  - by Nour Sabouny

  Hi every one. let's say that i have an order system. each "Order" references a "Customer" Object. when i fill the orders list in Data Access Layer, the customer object should be brought from a Customer Web Service "WCF". so i didn't map the Customer property in the Order mapping class, Id(o => o.OrderID).GeneratedBy.Identity(); //References(o => o.Customer).Not.Nullable().Column("CustomerID"); HasMany(o => o.Details).KeyColumn("OrderID").Cascade.AllDeleteOrphan(); Map(c => c.CustomerID).Not.Nullable(); and asked the nhibernate session to get me the orders list. and tried to loop on every order in the list to fill it's customer property, doe's any body have a good idea for this ???? IList<Order> lst = Session.CreateCriteria<Order>().List<Order>(); foreach (Order order in lst) order.Customer = serviceProxy.GetCustomerByID(order.CustomerID);

  Read the article

• Sending mail through PHP

  - by Angeline Aarthi

  I'm trying to sends mails in PHP. The code I used for sending a mail in CakePHP is given below. I get the message 'Simple Email Sent' in my web page but the mail is not delivered to my inbox. Am I missing something? The values in the to, subject and link fields are set with the values entered in the user interface. $this->set('to',$this->params['form']['to']); $this->set('subject',$this->params['form']['subject']); $this->set('link',$this->params['form']['link']); $this->Email->to = to; $this->Email->subject = subject; $this->Email->from = '[email protected]'; $this->Email->delivery= 'mail'; $this->Email->sendAs='text'; $this->Email->template = 'simple_message'; //$this->Email->send(link); if ( $this->Email->send(link) ) { $this->Session->setFlash('Simple email sent'); } else { $this->Session->setFlash('Simple email not sent'); }

  Read the article

• How do you submit an authenticated HTML form using XUL (Firefox extension) Javascript?

  - by machineghost

  I am working on a Firefox extension, and in that extension I am trying to use AJAX to submit a form on a webpage. I am using: var request = Components.classes["@mozilla.org/xmlextras/xmlhttprequest;1"].createInstance(Components.interfaces.nsIXMLHttpRequest); request.onload = loadHandler; request.open("POST", url, true); request.send(values); to make the request, and it works ... mostly. The one problem is that the form has an authentication token on it, and I need to submit that token with my POST. I tried doing a GET separately to get this token, but by the time I made my second (POST) request my session had (evidently) changed, and the authenticity token was considered invalid. Does anyone know of a way to use the XUL/Chrome Javscript to maintain a constant session across multiple requests (all "behind the scenes") for something this? I'm still a XUL n00b, so there may be a totally obvious alternative that I'm missing (eg. hidden IFRAME; I tried that briefly but couldn't get it to work).

  Read the article

• Passing a outside variable into a <asp:sqldatasource> tag. ASP.NET 2.0

  - by MadMAxJr

  I'm designing some VB based ASP.NET 2.0, and I am trying to make more use of the various ASP tags that visual studio provides, rather than hand writing everything in the code-behind. I want to pass in an outside variable from the Session to identify who the user is for the query. <asp:sqldatasource id="DataStores" runat="server" connectionstring="<%$ ConnectionStrings:MY_CONNECTION %>" providername="<%$ ConnectionStrings:MY_CONNECTION.ProviderName %>" selectcommand="SELECT THING1, THING2 FROM DATA_TABLE WHERE (THING2 IN (SELECT THING2 FROM RELATED_DATA_TABLE WHERE (USERNAME = @user)))" onselecting="Data_Stores_Selecting"> <SelectParameters> <asp:parameter name="user" defaultvalue ="" /> </SelectParameters> </asp:sqldatasource> And on my code behind I have: Protected Sub Data_Stores_Selecting(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.SqlDataSourceSelectingEventArgs) Handles Data_Stores.Selecting e.Command.Parameters("user").Value = Session("userid") End Sub Oracle squaks at me with ORA-01036, illegal variable name. Am I declaring the variable wrong in the query? I thought external variables share the same name with a @ prefixed. from what I understand, this should be placing the value I want into the query when it executes the select. EDIT: Okay, thanks for the advice so far, first error was corrected, I need to use : and not @ for the variable declaration in the query. Now it generates an ORA-01745 invalid host/bind variable name. EDIT AGAIN: Okay, looks like user was a reserved word. It works now! Thanks for other points of view on this one. I hadn't thought of that approach.

  Read the article

• persist values/variables from page to page

  - by Todd

  Hello, I'm wondering if there's another solution to my problem, that's considered more the Sharepoint way. FIrstly, my site is an Internet site, not Intranet. The problem is, all I'm trying to do is save values/variables from page to page in Sharepoint. I know the issue with Session Variables, but this seems to be the only way I can see to accomplish this. I know there are webparts that can store this value, but am I wrong in thinking this won't be persisted from page to page? Basically, I'll be extending the Content Query Web Part to dynamically filter it's results based off of a variable/value. The user chooses their 'area' from a dropdown, and the CQWP in the site will change and query results based off of this value (It will be a provincial structure as it is a Canadian site, so if someone chooses the province 'Ontario', this value is saved in a global variable, and these extended CQWP that are throughout the site, will get this value, and query lists flagged as Ontario). Is Session variables the only solution? Thanks everyone!

  Read the article

• how to redirect user depending on user type at time of login (codeignitor)

  - by Anam Tahir

  im facing problem while redirecting my user according to its type. how can do it here's my code plz suggest how to do it. <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class VerifyLogin extends CI_Controller { function __construct() { parent::__construct(); } function index() { $this->load->model('user','',TRUE); //This method will have the credentials validation $this->load->library('form_validation'); $this->load->library('session'); $this->form_validation->set_rules('username', 'Username','trim|required|xss_clean'); $this->form_validation->set_rules('password', 'Password' 'trim|required|xss_clean|callback_check_database'); if($this->form_validation->run() == FALSE) { //Field validation failed.&nbsp; User redirected to login page validation_errors(); $this->load->view('error'); } else { //Go to private area basically here i want to redirect if user is admin then redirect to admin page else redirect to home how can i do this ??? redirect('home', 'refresh'); } } function check_database($password) { //Field validation succeeded.&nbsp; Validate against database $username = $this->input->post('username'); //query the database $result = $this->user->login($username, $password); if($result) { $sess_array = array(); foreach($result as $row) { $sess_array = array( 'id' => $row->id, 'username' => $row->username ); $this->session->set_userdata('logged_in', $sess_array); } return TRUE; } else { $this->form_validation->set_message('check_database', 'Invalid username or password'); return false; } } } ?>

  Read the article

• Hibernate Exception Fixed By Alt+Tab

  - by Lee Theobald

  Hi all, I've got a very curious problem in Hibernate that I would like some opinions on. In my code if I do the following: Go to page A Click a link on page A to be taken to page B Click on data item on page B Exception thrown I get an error telling me: failed to lazily initialize a collection of role: XYZ, no session or session was closed Fair enough. But when I do the same thing but add an alt+tab in the middle, everything is fine. E.g. Go to page A Click a link on page A to be taken to page B Hit ALt+Tab to switch to another application Hit ALt+Tab to switch back to the web browser Click on data item on page B Everything is fine. I'm a little confused as to how switching focus from my application makes it act as I want it to. Does anyone have any light to shine on the subject? I don't think it's a locking issue as even if I do the second set of steps quicker than the first, still no error. It's a Seam application using Hibernate 3.3.2.GA & 3.4.0.GA.

  Read the article

• What's the best technique to protect my framework from visitors who are not logged in?

  - by Hermet

  First of all, I would like to say that I have used the search box looking for a similar question and was unsuccessful, maybe because of my poor english skills. I have a a 'homemade' framework. I have certain PHP files that must only be visible for the admin. The way I currently do this is check within every single page to see if a session has been opened. If not, the user gets redirected to a 404 page, to seem like the file which has been requested doesn't exist. I really don't know if this is guaranteed to work or if there's a better and more safe way because I'm currently working with kind of confidential data that should never become public. Could you give me some tips? Or leave a link where I could find some? Thank you very much, and again excuse me for kicking the dictionary. EDIT What I usually write in the top of each file is something like this <?php include("sesion.php"); $rs=comprueba(); //'check' if ($rs==1) { ?> And then, at the end <?php } ?> Is it such a butched job, isn't it? EDIT Let's say I have a customers list in a file named customers.php That file may be currently on http://www.mydomain.com/admin/customers.php and it must only be visible for the admin user. Once the admin user has been logged in, I create a session variable. That variable is what I check on the top of each page, and if it exists, the customers list is shown. If not, the user gets redirected to the 404 page. Thank you for your patience. I really appreciate.

  Read the article

• [nHibernate] casting string to bool using nHibernate Criteria

  - by code-zoop

  I have an nHibernate query using Criteria, and I am trying to cast a string to bool in the query itself. I have done the same with casting a string to int, and that works well (the "DataField" property is "1" as a string): var result = Session .CreateCriteria<Car>() .Add(Restrictions.Eq((Projections.Cast(NHibernateUtil.Int32, Projections.Property("DataField"), 1)) .List<Car>(); tx.Commit(); But I am trying to do the same with bool, but I do not get the expected result: var result = Session .CreateCriteria<Car>() .Add(Restrictions.Eq((Projections.Cast(NHibernateUtil.bool, Projections.Property("DataField"), true)) .List<Car>(); tx.Commit(); "DataField" is the string "True", but the result in an empty list, where it should contain 100 elements with the "DataField" property string set to "True". I have tried with the string "true", and "1", but the result is still an empty List. [EDIT] As Commented below, I could check for the string "True" or "False", but I would say this is a more general question than just for the Boolean. Note that the idea is to have some sort of key value representation of the data, where the value can be different data types. I need the value table to contain all data, so storing the data as string seems like the cleanest solution! I have been able to use the method above to store both int and double as string, and to the cast in the query, but I have not succeeded using the same method for DateDime and Boolean. And for DateTime it is crucial to have the actual DateTime object. How can I make the cast from string to bool, and string to DateTime work in the queries? Thanks

  Read the article

• Looking for Simplified Overview of EJB3

  - by sdoca

  Hi I'm looking for a simplified overview of EJB3 components. I seem to understand most of the pieces of the puzzle, but can't quite get them to fit together in my brain as a full picture. I've developed numerous web applications (wars) that have been deployed on Tomcat before, but not a full-fledged EE application (ear). I would like the overview to be as generic as possible. I'm not looking for a tutorial on how to set up EJB3 on Glassfish built in NetBeans or some other vendor specific tutorial that's more about the IDE than the technology. I keep reading about Java, ejb-jar, web and ear modules but am not clear on what these different modules contain and how to use them to put together my app. In my case, I want to write a simple database CRUD web application. The first step is simple; create entity classes that model the database tables my app will be using. I plan on using annotations. Should I create a jar that contains just these enity classes? Is this the ejb-jar module (sometimes referred to as the Java module)? Next, I'll need some business logic classes that make use of the entity classes. These are the session beans (stateless or stateful) correct? Should these be packaged in the same jar as the entity classes or a separate jar? Finally, I'll need some sort of web interface (I'll be creating a JSF portlet) application that makes use of the both the session and entity beans. Together with the above jar(s), this will be my war? Assuming the above to be correct, what is involved in creating an ear? Forgive me if this post is vague, but I'm having a hard time defining what it is I don't understand. Thanks for any help!

  Read the article

• How do I implement Hibernate Pagination using a cursor (so the results stay consistent, despite new

  - by hunterae

  Hey all, Is there any way to maintain a database cursor using Hibernate between web requests? Basically, I'm trying to implement pagination, but the data that is being paged is consistently changing (i.e. new records are added into the database). We are trying to set it up such that when you do your initial search (returning a maximum of 5000 results), and you page through the results, those same records always appear on the same page (i.e. we're not continuously running the query each time next and previous page buttons are clicked). The way we're currently implementing this is by merely selecting 5000 (at most) primary keys from the table we're paging, storing those keys in memory, and then just using 20 primary keys at a time to fetch their details from the database. However, we want to get away from having to store these keys in memory and would much prefer a database cursor that we just keep going back to and moving backwards and forwards over the cursor to generate pages. I tried doing this with Hibernate's ScrollableResults but found that I could not call methods like next() and previous() would cause an exception if you within a different web request / Hibernate session (no surprise there). Is there any way to reattach a ScrollableResults object to a Session, much the same way you would reattach a detached database object to make it persistent? Are there any other approaches to implement this data paging with consistent paging results without caching the primary keys?

  Read the article

• What might be causing this Rails method error?

  - by Trip

  My error: Notice the undefined method '-@' . This is for a sort by. All sorts on one page break, but all the sorts on other pages use the same helper and do not break. Does it allude to something obvious? Processing OrganizationsController#search (for ::1 at 2010-05-13 15:42:01) [GET] Parameters: {"action"=>"search", "controller"=>"organizations", "direction"=>"desc", "_"=>"1273779721464", "order_by"=>"published_at"} SQL (0.5ms) SHOW TABLES Organization Columns (2.2ms) SHOW FIELDS FROM `organizations` NoMethodError (undefined method `-@' for #<Array:0x2f88cc8>): app/controllers/organizations_controller.rb:190:in `search' sunspot (1.0.5) lib/sunspot/util.rb:84:in `call' sunspot (1.0.5) lib/sunspot/util.rb:84:in `instance_eval_or_call' sunspot (1.0.5) lib/sunspot/search.rb:200:in `build' sunspot (1.0.5) lib/sunspot/session.rb:45:in `new_search' sunspot (1.0.5) lib/sunspot/session.rb:53:in `search' sunspot (1.0.5) lib/sunspot/session_proxy/abstract_session_proxy.rb:11:in `search' sunspot (1.0.5) lib/sunspot.rb:323:in `search' app/controllers/organizations_controller.rb:183:in `search' haml (2.2.2) [v] rails/./lib/sass/plugin/rails.rb:19:in `process' lib/flash_session_cookie_middleware.rb:14:in `call' vendor/gems/hoptoad_notifier-2.2.2/lib/hoptoad_notifier/rack.rb:27:in `call' /usr/local/lib/ruby/1.8/webrick/httpserver.rb:104:in `service' /usr/local/lib/ruby/1.8/webrick/httpserver.rb:65:in `run' /usr/local/lib/ruby/1.8/webrick/server.rb:173:in `start_thread' /usr/local/lib/ruby/1.8/webrick/server.rb:162:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:162:in `start_thread' /usr/local/lib/ruby/1.8/webrick/server.rb:95:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:92:in `each' /usr/local/lib/ruby/1.8/webrick/server.rb:92:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:23:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:82:in `start' Rendered rescues/_trace (68.5ms) Rendered rescues/_request_and_response (0.6ms) Rendering rescues/layout (internal_server_error)

  Read the article

• How to read the birthday_date from the Facebook API

  - by Steve

  I have been chasing my tail on this! And it should be so simple!! I have an app in FaceBook that is working fine. However, I need to get the user's birth date. I have successfully got the request for extended permissions, but cannot get the birthday_date out and into a variable/store in database. <?php require_once('facebook.php'); $facebook = new Facebook(array( 'appId' => 'xxxxx', 'secret' => 'yyyyyyy', 'cookie' => true )); if ($facebook->getSession()) { $uid = $facebook->getUser(); $fbme = $facebook->api('/me'); } else { $params = array( 'fbconnect'=>0, 'canvas'=>1, 'req_perms'=>'publish_stream','email','user_location','user_birthday' ); $loginUrl = $facebook->getLoginUrl($params); print "<script type='text/javascript'>top.location.href = '$loginUrl';</script>"; } $session = $facebook->getSession(); $token = $session['access_token']; I would be very grateful if someone could show me the PHP code that reads the extended permissions and places the results into variables. Thanks Steve

  Read the article

• Quick and easy flood protection?

  - by James P

  I have a site where a user submits a message using AJAX to a file called like.php. In this file the users message is submitted to a database and it then sends a link back to the user. In my Javascript code I disabled the text box the user types into when they submit the AJAX request. The only problem is, a malicious user can just constantly send POST requests to like.php and flood my database. So I would like to implement simple flood protection. I don't really want the hassle of another database table logging users IPs and such... as if they are flooding my site there will be a lot of database read/writes slowing it down. I thought about using sessions, like have a session that contains a timestamp that gets checked every time they send data to like.php, and if the current time is before the timestamp let them add data to the database, otherwise send out an error and block them. If they are allowed to enter something into the database, update their session with a new timestamp. What do you think? Would this be the best way to go about it or are there easier alternatives? Thanks for any help. :)

  Read the article

• Showing the URL of the view in the address bar, instead of the one of the action

  - by aditya

  @RequestMapping(value = "updatePatient", method = RequestMethod.POST) public ModelAndView postUpdatePatientById( @ModelAttribute("patient") PatientForm patientForm, HttpSession session) { Long id = (Long) session.getAttribute("refId"); if (id != 0 || id != null) { Patient patient1 = HospitalPatientHelper .getPatientFrom_PatientForm(patientForm); patientService.updatePatient(patient1, id); PatientService patientService) { Patient patient = patientService.getPatientById(id); ModelAndView mv; PatientForm patientForm = HospitalPatientHelper .getPatientForm_FromPatient(patient); List<Weight> weights = patientService.viewLast10RecordedWeight(patient); WeightTable weightTable = new WeightTable(); List<WeightSummaryTable> summaryWeights = weightTable.summary(weights, patient.getHeight()); mv = new ModelAndView("patient1/patientDetail"); mv.addObject("patient", patientForm); mv.addObject("summaries", summaryWeights); mv.addObject("lastWeight", summaryWeights.get(0).getWeight()); mv.addObject("bmi", summaryWeights.get(0).getBmi()); return mv; } else { return new ModelAndView("patient1/patientDetail"); } } the page shown sucessfully, but the url dosn't change, means the url is not showing the address www.url.com/patient1/patientDetail.htm and i want that the returning view address should also be shown in the url too. please help me

  Read the article

• Re-authentication required for registered-path links (to ASP.NET site) coming to IE from PowerPoint

  - by Daniel Halsey

  We're using URL routing based on Phil Haack's example, with config modifications based on MSDN Library article #CC668202, to provide "shareable" links for a ASP.NET forms site, and have run into a strange issue: For users attempting to open links from PowerPoint presentations, and who have IE set as their default browser, using one of these links forces (forms-based) re-authentication, even in the same browser instance with a live session. Info: We know the session is still alive. (Page returns information for the currently logged-in user; confirmed via debug watches) This doesn't happen with other browsers (FF, Chrome) or with other programs (Notepad++) as the URL source. We do not have a default path set, as this caused issues with root path handling at initial login. This primarily happens with PowerPoint, but will also happen in Word and OCS. On some machines, even after changing the default browser, Office apps will continue to use IE for these links, forcing this error. (A potential registry fix for this failed, but even if it had worked, we can't control default browser choice for our users.) We can't figure out if this is an Office oddity or is being caused by our decision to use app-level URL routing (rather than IIS rewriting). Has anyone else encountered this and found a solution?

  Read the article

• em.createQuery keeps returning null

  - by Developer106

  I have this application which i use JSF 2.0 and EclipseLink, i have entities created for a database made in MySQL, Created these entities using netbeans 7.1.2, it gets created automaticly. Then i use session beans to work with these entities, the thing is the em.createQuery always returns a null, though I checked NamedQueries in the entities and they perfectly match a sample from the entities named queries:- @NamedQueries({ @NamedQuery(name = "Users.findAll", query = "SELECT u FROM Users u"), @NamedQuery(name = "Users.findByUserId", query = "SELECT u FROM Users u WHERE u.userId = :userId"), @NamedQuery(name = "Users.findByUsername", query = "SELECT u FROM Users u WHERE u.username = :username"), @NamedQuery(name = "Users.findByEmail", query = "SELECT u FROM Users u WHERE u.email = :email"), notice how i use this findByEmail query in the session bean :- public Users findByEmail(String email){ em.getTransaction().begin(); String find = "Users.findByEmail"; Query query = em.createNamedQuery(find); query.setParameter("email", email); Users user = (Users) query.getSingleResult(); but it always returns null from this em.createNamedQuery, i tried using .createQuery first but it also was no good. the stacktrace of the exception Caused by: java.lang.NullPointerException at com.readme.entities.sessionBeans.UsersFacade.findByEmail(UsersFacade.java:48) at com.readme.user.signup.SignupBean.checkAvailability(SignupBean.java:137) at com.readme.user.signup.SignupBean.save(SignupBean.java:146) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:601) What Seems To Be The Problem Here ?

  Read the article

• SQL developer here -- Nesting with select * finicky in Oracle 10g?

  - by John Sullivan

  I am writing a simple diagnostic query I will execute in my Oracle 10g scratchpad. I am trying to do this as part of a step to build the query. In the SQL Scratchpad for Oracle 10g Enterprise Manager Console, this statement runs fine. SELECT * FROM v$session sess, v$sql sql WHERE sql.sql_id(+) = sess.sql_id and sql.sql_text <> ' ' If I try to wrap that up in Select * from () tb2 I get an error, "ORA-00918: Column Ambiguously Defined". I didn't think that could ever happen with this kind of statement so I am a bit confused. select * from (SELECT * FROM v$session sess, v$sql sql WHERE sql.sql_id(+) = sess.sql_id and sql.sql_text <> ' ') tb2 You should always be able to select * from the result set of another select * statement using this structure as far as I'm aware... right? Is Oracle/10g/the scratchpad trying to force me to accept a certain syntactic structure to prevent excessive nesting? Is this a bug in scratchpad or something about how oracle works?

  Read the article

• jsf annotations

  - by Andrew Bucknell

  I've created an address bean and I want to use it twice - once for street address and once for mailing address. I can achieve this using faces config as per the below, but I'm wondering if I can do this via annotations. e.g. put @ManagedBean(name="StreetAddress") and @ManagedBean(name="MailingAddress") on the same class? I feel like I am missing something obvious here but I'm not sure what. <managed-bean> <managed-bean-name>MailingAddress</managed-bean-name> <managed-bean-class>com.leetb.jsf_ex1.model.AddressBean</managed-bean-class> <managed-bean-scope>session</managed-bean-scope> <map-entries/> </managed-bean> <managed-bean> <managed-bean-name>StreetAddress</managed-bean-name> <managed-bean-class>com.leetb.jsf_ex1.model.AddressBean</managed-bean-class> <managed-bean-scope>session</managed-bean-scope> <map-entries/> </managed-bean> public class AddressBean { private String line_one; private String line_two; private String suburb; private String state; private String postcode; /* getters and setters snipped */ }

  Read the article

• Can this line of code really throw an IndexOutOfRange exception?

  - by Jonathan M

  I am getting an IndexOutOfRange exception on the following line of code: var searchLastCriteria = (SearchCriteria)Session.GetSafely(WebConstants.KeyNames.SEARCH_LAST_CRITERIA); I'll explain the above here: SearchCriteria is an Enum with only two values Session is the HttpSessionState GetSafely is an extension method that looks like this: public static object GetSafely(this HttpSessionState source, string key) { try { return source[key]; } catch (Exception exc) { log.Info(exc); return null; } } WebConstants.KeyNames.SEARCH_LAST_CRITERIA is simply a constant I've tried everything to replicate this error, but I cannot reproduce it. I am beginning to think the stack trace is wrong. I thought perhaps the exception was actually coming from the GetSafely call, but it is swallowing the exceptions, so that can't be the case, and even if it was, it should show up in the stack trace. Is there anything in the line of code above that could possible throw an IndexOutOfRange exception? I know the line will throw an NullReferenceException if GetSafely returns null, and it will also throw an InvalidCastException if it returns anything that cannot be cast to SearchCriteria, but an IndexOutOfRange exception? I'm scratching my head here. Here is the stack trace: $LOG--> 2010-06-11 07:01:33,814 [ERROR] SERVERA (14) Web.Global - Index was outside the bounds of the array. System.Web.HttpUnhandledException: Exception of type 'System.Web.HttpUnhandledException' was thrown. ---> System.IndexOutOfRangeException: Index was outside the bounds of the array. at IterateSearchResult(Boolean next) in C:\Projects\Web\UserControls\AccountHeader.ascx.cs:line 242 at nextAccountLink_Click(Object sender, EventArgs e) in C:\Projects\Web\UserControls\AccountHeader.ascx.cs:line 232

  Read the article

• What would be a better implementation of shared variable among subclass

  - by Churk

  So currently I have a spring unit testing application. And it requires me to get a session cookie from a foreign authentication source. Problem what that is, this authentication process is fairly expensive and time consuming, and I am trying to create a structure where I am authenticate once, by any subclass, and any subsequent subclass is created, it will reuse this session cookie without hitting the authentication process again. My problem right now is, the static cookie is null each time another subclass is created. And I been reading that using static as a global variable is a bad idea, but I couldn't think of another way to do this because of Spring framework setting things during run time and how I would set the cookie so that all other classes can use it. Another piece of information. The variable is being use, but is change able during run time. It is not a single user being signed in and used across the board. But more like a Sub1 would call login, and we have a cookie. Then multiple test will be using that login until SubX will come in and say, I am using different credential, so I need to login as something else. And repeats. Here is a outline of my code: public class Parent implements InitializingBean { protected static String BASE_URL; public static Cookie cookie; ... All default InitializingBean methods ... afterPropertiesSet() { cookie = // login process returns a cookie } } public class Sub1 extends Parent { @resource public String baseURL; @PostConstruct public void init() { // set parents with my baseURL; BASE_URL = baseURL; } public void doSomething() { // Do something with cookie, because it should have been set by parent class } } public class Sub2 extends Parent { @resource public String baseURL; @PostConstruct public void init() { // set parents with my baseURL; BASE_URL = baseURL; } public void doSomethingElse() { // Do something with cookie, because it should have been set by parent class } }

  Read the article

• How to differentiate between exceptions i can show the user, and ones i can't?

  - by Ian Boyd

  i have some business logic that traps some logically invalid situations, e.g. trying to reverse a transaction that was already reversed. In this case the correct action is to inform the user: Transaction already reversed or Cannot reverse a reversing transaction or You do not have permission to reverse transactions or This transaction is on a session that has already been closed or This transaction is too old to be reversed The question is, how do i communicate these exceptional cases back to the calling code, so they can show the user? Do i create a separate exception for each case: catch (ETransactionAlreadyReversedException) MessageBox.Show('Transaction already reversed') catch (EReversingAReversingTransactionException) MessageBox.Show('Cannot reverse a reversing transaction') catch (ENoPermissionToReverseTranasctionException) MessageBox.Show('You do not have permission to reverse transactions') catch (ECannotReverseTransactionOnAlredyClosedSessionException) MessageBox.Show('This transaction is on a session that has already been closed') catch (ECannotReverseTooOldTransactionException) MessageBox.Show('This transaction is too old to be reversed') Downside for this is that when there's a new logical case to show the user: Tranasctions created by NSL cannot be reversed i don't simply show the user a message, and instead it leaks out as an unhandled excpetion, when really it should be handled with another MessageBox. The alternative is to create a single exception class: `EReverseTransactionException` With the understanding that any exception of this type is a logical check, that should be handled with a message box: catch (EReverseTransactionException) But it's still understood that any other exceptions, ones that involve, for example, an memory ECC parity error, continue unhandled. In other words, i don't convert all errors that can be thrown by the ReverseTransaction() method into EReverseTransactionException, only ones that are logically invalid cause of the user.

  Read the article

• How to avoid notice in php when one of the conditions is not true

  - by user225269

  I've notice that when one of the two conditions in a php if statement is not true. You get an undefined index notice for the statement that is not true. And the result in my case is a distorted web page. For example, this code: <?php session_start(); if (!isset($_SESSION['loginAdmin']) && ($_SESSION['loginAdmin'] != '')) { header ("Location: loginam.php"); } else { include('head2.php'); } if (!isset($_SESSION['login']) && ($_SESSION['login'] != '')) { header ("Location: login.php"); } else { include('head3.php'); } ?> If one of the if statements is not true. The one that is not true will give you a notice that it is undefined. In my case it says that the session 'login' is not defined. If session 'LoginAdmin' is used. What can you recommend that I would do in order to avoid these undefined index notice.

  Read the article

• Android EVO4G SenseUI Flash Lite 4 cookie problem

  - by cmurray

  Got the EVO4G today, watching it run Actionscript3 out of the box was EXTREMELY cool. Ran into a problem though. When I connect to a server which creates an HTTP session and hands a cookie to my application, subsequent calls from my client to the server do not have the cookie attached to the HTTP request. That causes the server to invalidate the session and my user is logged out. This appears to be a bug between the Flash Lite 4 player and the SenseUI/browser running in Android 2.1 for the EVO4G. This same application works on other platforms, including the HTC HERO if compiled for flash lite 2. If I hardcode my HTTP requests in the browser address bar, the cookies work, so I know cookies are working on the phone. But when my application is running in the Flash Player, the cookies are not working. I realize this may not be the best forum for this question, so if you cant answer or help me, if you could give me some more appropriate forums to ask on, I would appreciate that. Thanks!

  Read the article

< Previous Page | 224 225 226 227 228 229 230 231 232 233 234 235  | Next Page >