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• The configuration in win 7 for Apache 2.2 + php 5.2

  - by user312079

  Every time I start apache , it always fails. The problem is in loadmodulephp5... The error log:[warn] pid file C:/windows/Apache2/logs/httpd.pid overwritten — Unclean shutdown of previous Apache run? I tried to delete this file and then start apache.But this file had been created again. Any solution?

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• Django template context not working with imported class

  - by Andy Hume

  I'm using Django's templating on appengine, and am having a problem whereby a class I'm importing from another package is not correctly being made available to the template context. Broadly speaking, this is the code. The prop1 is not available in the template in the first example below, but is in the second. MyClass is identical in both cases. This does not work: from module import MyClass context = MyClass() self.response.out.write(template.render(path, context)) This does: class MyClass(object): def __init__(self): self.prop1 = "prop1" context = MyClass() self.response.out.write(template.render(path, context)) If I log the context in the above code I get: <module.MyClass object at 0x107b1e450> when it's imported, and: <__main__.MyClass object at 0x103759390> when it's defined in the same file. Any clues as to what might cause this kind of behaviour?

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• mb_internal_encoding() not available though configured?

  - by Jonas Byström

  I'm having problem with mbstring in my Apache2.2/Win7/PHP5.3 setup, though I think it's correctly configured in my php.ini: extension_dir = "ext" extension=php_mbstring.dll I get the following: Fatal error: Call to undefined function mb_internal_encoding() in ... I did a manual installation (by the book) using the VC6 .zip. I'm running out of ideas of what to try.

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• Exception message (Python 2.6)

  - by TurboJupi

  If I want to open binary file (in Python 2.6), that doesn't exists, program exits with an error and prints this: Traceback (most recent call last): File "C:\Python_tests\Exception_Handling\src\exception_handling.py", line 4, in <module> pkl_file = open('monitor.dat', 'rb') IOError: [Errno 2] No such file or directory: 'monitor.dat' I can handle this with 'try-except', like: try: pkl_file = open('monitor.dat', 'rb') monitoring_pickle = pickle.load(pkl_file) pkl_file.close() except Exception: print 'No such file or directory' Does anybody know, how could I, in caught Exception, print the following line? File "C:\Python_tests\Exception_Handling\src\exception_handling.py", line 11, in <module> pkl_file = open('monitor.dat', 'rb') So, program would not exits, and I would have useful information.

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• MVC way of handling data input

  - by korki

  I have a data input module where I add the information of my product and its sub information like: product basic info product price info product price details price info and price details are related to product and are lists In my web forms approach I would store my main product object on the view state and I would populate it's pricing info and details while doing ajax postbacks. This way I can create a compact module that is very user friendly in terms of defining a lot of data from one place without the need to enter these data from seperate modules. And when I am done I would do one product.save() and that would persist all the data to the respective tables on db. Now I am building similar app on .net mvc framework and pondering on what would be the good way of handling this on mvc. I don't resonate towards storing all this on client side till I click save. And saving to the db after each action makes me remember the days I was coding on asp. Will appreciate your inputs on ways to approach this on mvc framework

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• OpenERP model tracking external resource, hooking into parent's copy() or copy_data()

  - by CB.

  I have added a new model (call it crm_lead_external) that is linked via a new one2many on crm_lead. Thus, my module has two models defined: an updated crm_lead (with _name=crm_lead) and a new crm_lead_external. This external model tracks a file and as such has a 'filename' field. I also created a unique SQL index on this filename field. This is part of my module: def copy(self, cr, uid, id, default=None, context=None): if not default: default = {} default.update({ 'state': 'new', 'filename': '', }) ret = super(crm_lead_external, self).copy(cr, uid, id, default, context=context) #do file copy return ret The intent here is to allow an external entity to be duplicated, but to retarget the file path. Now, if I click duplicate on the Lead, I get an IntegrityError on my unique constraint. Is there a particular reason why copy() isn't being called? Should I add this logic to copy_data()? Myst I really override copy() for the lead? Thanks in advance.

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• Possible to view PHP code of a website?

  - by Camran

  Is it possible to somehow view another websites php files/codes? Or to rephrase the question, Can my php codes be viewed by anybody except for those who have access to the file? If so, how cant I best prevent this? Thanks Ps: Server OS is Ubuntu 9.10 and PHP version is 5+ (Apache2)

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• Drupal menu permissions question

  - by Luke

  I'm creating an admin module for my client that gives then access to some administration functionality concerning their content. I'm starting off my adding some permissions in my module by implementing hook_perm: function mymodule_perm() { return array( 'manage projects', ); } I can then create my menu by adding to the admin section that already exists: function mymodule_menu() { $items['admin/projects'] = array( 'title' => 'Projects', 'description' => 'Manage your projects.', 'page callback' => 'manage_projects_overview', 'access callback' => 'user_access', 'access arguments' => array('manage projects'), 'type' => MENU_NORMAL_ITEM, 'weight' => -100, ); $items['admin/projects/add'] = array( 'title' => 'Add project', 'access arguments' => array('manage projects'), 'page callback' => 'mymodule_projects_add', 'type' => MENU_NORMAL_ITEM, 'weight' => 1, ); return $items; } This will add a Projects section to the Administration area with an Add project sub section. All good. The behavior I want is that my client can only see the Projects section when they log in. I've accomplished this by ticking the "manage projects" permission for authenticated users. Now to give my client actual access to the Administration area I also need to tick "access administration pages" under the "system module" in the users permissions section. This works great, when I log in as my client I can only see the Projects section in the Administration area. There is one thing though, I my Navigation menu shown in the left column I can see the following items: - Administer - Projects - Content management - Site building - Site configuration - User management I was expecting only the see Administer and Projects, not the other ones. When I click e.g. Content Management I get a Content Management titled page with no options. Same for Site Building, Site Configuration and User Management. What's really odd is that Reports is not being shown which is also a top level Administration section. Why are these other items, besides my Projects section, being shown and how can I make them stop from appearing if I'm not logged in as administrator?

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• How to have CVS files in different directory than source files in NetBeans?

  - by Ondrej Slinták

  I have a project in NetBeans which haven't used CVS until now. Let's say the directory with source files is called /www/source_files and directory with project files /www/project_files. Module in repository is called differently than source files directory. When I'm trying to check out CVS, it forces me to create a directory called exactly how module is called, which is fine by me in fact. Straight after it asks me if I wanted to create new project. And here the problem begins. I don't want to do that and I have no idea how to link newly created directory with CVS and checked out files with my project. I'd like to end up with following structure: /www /source_files /project_files /cvs_files Any ideas how to do this? I'm using NetBeans 6.8.

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• Passing parameters in VBA for Access

  - by Newbie

  In Access 2007 I have created a form with a textbox and a button. At the moment, when I press the button, I load a query with the textbox data passed as a parameter to the query criteria. I would like to change this so that all (manually input) options appear in a combobox (in place of the textbox). I would then like to pass the combobox text to a VBA module upon pressing the button. How do I do this? Similarly, I hope to output a different string from this module, and I hope to use this as the query criteria. How do I do this?

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• Rails: Creating subfolders in model?

  - by keruilin

  I'm going to have a ton of subclasses, so want to organize them under a subfolder called stream. I added the following line to the environment.rb so that all classes in the subfolder would be loaded: Rails::Initializer.run do |config| ... config.load_paths += Dir["#{RAILS_ROOT}/app/models/*"].find_all { |f| File.stat(f).directory? } ... end I thought this would solve the issue in which by convention the model class is namespaced into an according module. However, when I try to call one of the classes called stream in the stream folder, I get the following error: NoMethodError: undefined method `new' for Stream:Module from (irb):28 from /usr/local/bin/irb:12:in `<main>' Here's the model for the parent and one child: class Stream end class EventStream < Stream end Any idea what the issue is?

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• What is the best way to handle dynamic content_type in Sinatra

  - by lusis

  I'm currently doing the following but it feels "kludgy": module Sinatra module DynFormat def dform(data,ct) if ct == 'xml';return data.to_xml;end if ct == 'json';return data.to_json;end end end helpers DynFormat end My goal is to plan ahead. Right now we're only working with XML for this particular web service but we want to move over to JSON as soon as all the components in our stack support it. Here's a sample route: get '/api/people/named/:name/:format' do format = params[:format] h = {'xml' => 'text/xml','json' => 'application/json'} content_type h[format], :charset => 'utf-8' person = params[:name] salesperson = Salespeople.find(:all, :conditions => ['name LIKE ?', "%#{person}%"]) "#{dform(salesperson,format)}" end It just feels like I'm not doing it the best way possible.

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• In PLT scheme, can I export functions after another function has been called?

  - by Jason Baker

  I'm trying to create a binding to libpython using scheme's FFI. To do this, I have to get the location of python, create the ffi-lib, and then create functions from it. So for instance I could do this: (module pyscheme scheme (require foreign) (unsafe!) (define (link-python [lib "/usr/lib/libpython2.6.so"]) (ffi-lib lib)) This is all well and good, but I can't think of a way to export functions. For instance, I could do something like this: (define Py_Initialize (get-ffi-obj "Py_Initialize" libpython (_fun -> _void))) ...but then I'd have to store a reference to libpython (created by link-python) globally somehow. Is there any way to export these functions once link-python is called? In other words, I'd like someone using the module to be able to do this: (require pyscheme) (link-python) (Py_Initialize) ...or this: (require pyscheme) (link-python "/weird/location/for/libpython.so") (Py_Initialize) ...but have this give an error: (require pyscheme) (Py_Initialize) How can I do this?

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• android localization: Is it a good practice to have only needed resource to put in localized folder?

  - by MobileDev123

  Hi, My application has 4 languages in it. However only one module needs to be localized out of 5, This module has 4 layout files and some images, remaining files can be there in default layout folder and drawable folders. My question is : is it good practice to put only needed files in localization folders, if I leave other files in its respective folders and don't copy them in translation folders, does my application throw NullPointerException when my application runs in other language? and Does android market have any size limit? (Also being a BB developer,AFAIK they do not allow OTA, if the application size grows more than 3 mb) [In case i need to copy the layout and image files]. Note about NullPointerException : it throws in string if you omit some string in localization and application runs in that particular locale. Thanks

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• How to access the calling source line from interactive shell

  - by TJD

  I want to make a function that can determine the source code of how it was called. I'm aware of how to do this generally with the inspect module. For example, this question, works well and provides my desired output in the lines variable as shown below: def hello(x): frame,filename,line_number,function_name,lines,index=\ inspect.getouterframes(inspect.currentframe())[1] print(frame,filename,line_number,function_name,lines,index) The problem is that this solution doesn't work in an interactive command line session. For example, from a command line, the result looks like: >>> y = hello(7) (<frame object at 0x01ECA9E8>, '<stdin>', 1, '<module>', None, None) The problem is that the source file is '<stdin>', so the lines variable is None. How can I access the calling line to find the result containing the string y = hello(7) during an interactive session?

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• Prevent Apache from chunking gzipped content

  - by Bear

  When using mod_deflate in Apache2, Apache will chunk gzipped content, setting the Transfer-encoding: chunked header. While this results in a faster download time, I cannot display a progress bar. If I handle the compression myself in PHP, I can gzip it completely first and set the Content-length header, so that I can display a progress bar to the user. Is there any way to change Apache's behavior, and have Apache set a Content-length header instead of chunking the response, so that I don't have to handle the compression myself?

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• powershell folder stats

  - by huppy_doodoo

  Hi all, I keep all modules of our system in one dir (e.g. All\ModuleA; All\ModuleB). I want to see what types of files are most numerous and take up the most space, by module. So, I'd like output along the lines of: ModName,java-count,java-size,xml-count,xml-size,png-count,png-size... ModuleA,30,0.2,100,2.3,0,0,... ModuleB,21,0.1,20,0.7,1,1.2 Not all modules have files of all types, so this will only work if I list all types for all module (with lots of zeros). I have something that almost works, but it's hideous, verbose and inefficient. I'm sure someone can help me see the light :-) (which, by the way, can be a piece of freeware software that does this out of the box; I only chose to do this in powershell out of interest). thanks

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• How do you extend python with C++?

  - by superjoe30

  I've successfully extended python with C, thanks to this handy skeleton module. But I can't find one for C++, and I have circular dependency trouble when trying to fix the errors that C++ gives when I compile this skeleton module. How do you extend Python with C++? I'd rather not depend on Boost (or SWIP or other libraries) if I don't have to. Dependencies are a pain in the butt. Best case scenario, I find a skeleton file that already compiles with C++.

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• Can drupal router handle PUT requests ?

  - by redben

  I have a module that will be using some restfulness and i'd like to know if drupal's menu router handles PUT requests without problem...?

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• Zend Framework 2 without MVC

  - by Luke

  I'm currently using Zend Framework 2 for all my web tier development using the MVC module that's shipped with the framework. However, I want to implement my business logic in a separate layer, call it the business tier which is a non HTTP layer and expose it through AMQP, and I'd like to reuse my knowledge of PHP for implementing this. Since there is a lot of "stuff" that I need in this business layer such as configuration, a service manager, database access, etc, etc, I'd like to use all the goodies shipped with Zend Framework 2 for this. Are there any examples or tutorials out there on how to build a Zend Framework 2 application that is not build for the web tier and doesn't require the MVC module?

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• How do I detect the directory a php file is in

  - by Eric

  I have a PHP file that I need it to detect it's directory it's in. In my case I want it to return C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\ I think that this is pretty straightforward but if there is something you don't understand just comment

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• ruby confusing -- local variable or instance_method ?

  - by boblu

  I have the following program. module C def self.included(base) base.extend(ClassMethods) end module ClassMethods def test_for class_eval <<-DEFINECLASSMETHODS def self.my_method(param_a) puts "SELF is: #{self.inspect}" puts param_a puts "#{param_a}" end DEFINECLASSMETHODS end end end class A include C end class B < A test_for end when I run B.new.my_method("aaa"), I got this error NameError: undefined local variable or method `param_a' for B:Class I am quite confused. I define param_a as a local variable in class method my_method, puts param_a runs good, and will output the "aaa". however, puts "#{param_a}" output that error. why? Can anyone explain this?

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• Rails 2.3.5: How does one access code inside of lib/directory/file.rb?

  - by randombits

  I created a file so I can share a method amongst many models in lib/foo/bar_woo.rb. Inside of bar_woo.rb I defined the following: module BarWoo def hello puts "hello" end end Then in my model I'm doing something like: def MyModel < ActiveRecord::Base include Foo::BarWoo def some_method Foo::BarWoo.hello end end The interpreter is complaining that it expected bar_woo.rb to define Foo::BarWoo. The Agile Web Development with Rails book states that if files contain classes or modules and the files are named using the lowercase form of the class or module name, then Rails will load the file automatically. I didn't require it because of this.

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• trying to show a variable in my layout

  - by user1400

  hi i have a simple question where is my code wrong ? in index controller and index action i put $this->view->username="user1"; and when i try in my layout i use echo $this->username; i got fllowing error or null value Notice: Trying to get property of non-object in D:\Zend\Apache2\htdocs\test\application\layouts\layout.phtml on line 115 thanks

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• How to define a new type (class) in Python using C API?

  - by ~mech

  Hi, I am trying to use the Python C API to define a new class inside a module that would expose certain functionality written in C to Python code. I specifically want to have it in the form of a class and not a set of module functions. However, I can't find anything regarding this particular task in the official documentation. The closest I could find is PyClass_New function (in the Python.h header) but it is not mentioned anywhere in the official docs, so I assume it is not supposed to be used. So, what is the proper way to define a new Python class from C code? Thanks.

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