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  • update record only works when there is no auto_increment

    - by every_answer_gets_a_point
    i am accessing a mysql table through an odbc connection in excel here is how i am updating the table: With rs .AddNew ' create a new record ' add values to each field in the record .Fields("datapath") = dpath .Fields("analysistime") = atime .Fields("reporttime") = rtime .Fields("lastcalib") = lcalib .Fields("analystname") = aname .Fields("reportname") = rname .Fields("batchstate") = "bstate" .Fields("instrument") = "NA" .Update ' stores the new record End With when the schema of the table is this, updating it works: create table batchinfo(datapath text,analysistime text,reporttime text,lastcalib text,analystname text, reportname text, batchstate text, instrument text); but when i have auto_increment in there it does not work: CREATE TABLE batchinfo ( rowid int(11) NOT NULL AUTO_INCREMENT, datapath text, analysistime text, reporttime text, lastcalib text, analystname text, reportname text, batchstate text, instrument text, PRIMARY KEY (rowid) ) ENGINE=InnoDB AUTO_INCREMENT=67 DEFAULT CHARSET=latin1 has anyone experienced a problem like this where updating does not work when there is an auto_increment field involved? connection string: Private Sub ConnectDB() Set oConn = New ADODB.Connection oConn.Open "DRIVER={MySQL ODBC 5.1 Driver};" & _ "SERVER=localhost;" & _ "DATABASE=employees;" & _ "USER=root;" & _ "PASSWORD=pas;" & _ "Option=3" End Sub also here's the rs.open: rs.Open "batchinfo", oConn, adOpenKeyset, adLockOptimistic, adCmdTable

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  • PHP Dropdown menu [closed]

    - by rShetty
    <br><h2>Select a Tag</h2></br> <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("portal", $con); $query = "SELECT tag_name FROM tags"; $result = mysql_query($query); ?> <select name="tag_name" id="abc"> <option size=30 selected>Select</option> <?php while($array = mysql_fetch_assoc($result)){ ?> <option value ="<?php echo $array['tag_name'];?>"><?php echo $array['tag_name'];?> </option> <?php } ?> </select> <br><br> This is a snippet of code for getting the dropdown menu in the page. I have a database named portal and table named tags with tag_name as the attribute. Do help me to find the error in the program. I am not getting the tag_names in the dropdown menu

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  • How would i output a message that says "values inserted to table" ?

    - by ranlo
    <?php error_reporting(0); $con=mysql_connect("localhost","root",""); if (!$con) { die('could not connect:'.mysql_error()); } mysql_select_db("final?orgdocs",$con); $org_name = $_POST["org_name"]; $org_type = $_POST["org_type"]; $org_code = $_POST["org_code"]; $description = $_POST["description"]; $stmt = "INSERT INTO organization VALUES('".$org_name."','".$org_type."','".$org_code."','".$description."')"; $result = mysql_query("SELECT * FROM organization WHERE org_name = '$org_name' "); echo '<TABLE BORDER = "1">'; $result1 = $result; while ($row = mysql_fetch_array($result1)){ echo '<TR>'.'<TD>'.'Organization Name'.'</TD>'.'<TD>'.'Organization Type'.'</TD>'.'<TD>'.'Organization Code'.'</TD>'.'<TD>'.'Description'.'</TD>'.'<TD>'.'Constitution'.'</TD>'; echo '</TR>'; echo '<TR>'.'<TD>'.$row['org_name'].'</TD>'.'<TD>'.$row['org_type'].'</TD>'; echo '<TD>'.$row['org_code'].'</TD>'.'<TD>'.$row['description'].'</TD>'.'<TD>'; echo '</TR>'; } echo '</TABLE>'; ?>

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  • Preserve name of file using cURL to transfer files

    - by Toby
    I'm transferring files from an existing http request using cURL like so... $postargs = array( 'nonfilefield' =>'nonfilevalue', 'fileentry' => '@'.$_FILES['thefile']['tmp_name'][0] ); $ch = curl_init('http://localhost/curl/rec.php'); curl_setopt($ch,CURLOPT_USERAGENT, "Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)"); curl_setopt($ch,CURLOPT_RETURNTRANSFER, true); curl_setopt($ch,CURLOPT_POST,TRUE); curl_setopt($ch,CURLOPT_POSTFIELDS,$postargs); curl_exec($ch); curl_close($ch); The only way I can get this to work is using the tmp_name, without this it won't send. However, I then lose the name value for when I want to name the file later. Is there some way to do this preserving the $_FILES array as it normally would be without curl? I'm also using an array of file fields in my script, so at the moment I have to convert my multidimensional array into a single dimension for this to work

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  • Strange bug with PHP on Windows 7

    - by chessweb
    This is the configuration: Windows 7 Home Premium, XAMPP 1.7.3 (Apache 2.2.14 , PHP 5.3.1), Firefox 3.6 This is the PHP-code in a file named 'test.php' in htdocs: <?php echo('04556-8978765'); ?> On http://localhost/test.php I would expect to see the string 04556-8978765 in the browser. This is not what happens, though. The string appears for a short time and then it disappears altogether. Firebug shows an empty body-tag. However, when I look at page source, the string is there alright. When I change the string in the echo-statement to e.g. 4556-8978765, everything is fine. Internet Explorer 8 does not show this strange behavior. I could not reproduce this with the same Apache/PHP/Firefox configuration on Windows XP. '04556-8978765' is by no means unique. The couple '02065-96047' and '02065-9604' behave exactly the same. Can anybody reproduce this and offer an explanation as to what is going on? PS: If you can not see the string '04556-8978765' in the echo-statement above, look at this post with IE8.

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  • Properly handling NSURLConnection errors

    - by Cal S
    Hi, I have a simple form interface set up that send username and password information to a server: (working) NSString *postData = [NSString stringWithFormat:@"user=%@&pass=%@",[self urlEncodeValue:sysUsername],[self urlEncodeValue:password]]; NSLog(@"Post data -> %@", postData); /// NSData* postVariables = [postData dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; NSMutableURLRequest* request = [[[NSMutableURLRequest alloc] init] autorelease]; NSString* postLength = [NSString stringWithFormat:@"%d", [postVariables length]]; NSURL* postUrl = [NSURL URLWithString:@"http://localhost/~csmith/cocoa/test.php"]; [request setURL:postUrl]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody: postVariables]; NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:NULL error:NULL]; NSLog(@"Post data SENT & returned -> %@", returnData); How do I handle connection errors such as no internet connection, firewall, etc. Also, does this method use the system-wide proxy settings? Many of my users are behind a proxy. Thanks a lot!

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  • best way to avoid sql injection

    - by aauser
    I got similar domain model 1) User. Every user got many cities. @OneToMany(targetEntity=adv.domain.City.class...) 2) City. Every city got many districts @OneToMany(targetEntity=adv.domain.Distinct.class) 3) Distintc My goal is to delete distinct when user press delete button in browser. After that controller get id of distinct and pass it to bussiness layer. Where method DistinctService.deleteDistinct(Long distinctId) should delegate deliting to DAO layer. So my question is where to put security restrictions and what is the best way to accomplish it. I want to be sure that i delete distinct of the real user, that is the real owner of city, and city is the real owner of distinct. So nobody exept the owner can't delete ditinct using simple url like localhost/deleteDistinct/5. I can get user from httpSession in my controller and pass it to bussiness layer. After that i can get all cities of this user and itrate over them to be sure, that of the citie.id == distinct.city_id and then delete distinct. But it's rather ridiculous in my opinion. Also i can write sql query like this ... delete from t_distinct where t_distinct.city_id in (select t_city.id from t_city left join t_user on t_user.id = t_city.owner_id where t_user.id = ?) and t_distinct.id = ? So what is the best practice to add restrictions like this. I'm using Hibernate, Spring, Spring MVC by the way.. Thank you

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  • Delay PHP execution until JavaScript cookie set?

    - by Adam184
    I am trying to delay PHP execution until a cookie is set through JavaScript. The code is below, I trimmed the createCookie JavaScript function for simplicity (I've tested the function itself and it works). <?php if(!isset($_COOKIE["test"])) { ?> <script type="text/javascript"> $(function() { // createCookie script createCookie("test", 1, 3600); }); </script> <?php // Reload the page to ensure cookie was set if(!isset($_COOKIE["test"])) { header("Location: http://localhost/asdf.php/"); } } ?> At first I had no idea why this didn't work, however after using microtime() I figured out that the PHP after the <script> was executing before the jQuery ready function. I reduced my code significantly to show a simple version that is answerable, I am well aware that I am able to use setcookie() in PHP, the requirements for the cookie are client-side. I understand mixing PHP and JavaScript is incorrect, but any help on how to make this work (is there a PHP delay? - I tried sleep(), didn't work and didn't think it would work, since the scripts would be delayed as well) would be greatly appreciated.

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  • Exception thrown when creating database

    - by Bob
    For some reason, I can't get embedded firebird sql to work on Windows using C#/.NET. Here's my code: string BuildConnectionString() { FbConnectionStringBuilder builder = new FbConnectionStringBuilder(); builder.DataSource = "localhost"; builder.UserID = "SYSDBA"; builder.Password = "masterkey"; builder.Database = "database.fdb"; builder.ServerType = FbServerType.Embedded; return builder.ConnectionString; } private void OnConnectClicked(object sender, EventArgs e) { string cString = BuildConnectionString(); FbConnection.CreateDatabase( cString ); FbConnection connection = new FbConnection( cString ); connection.Open(); //CreateTable(); //FillListView(); connection.Close(); } When I call FbConnection.CreateDatabase, I get the following exception: An attempt was made to load a program with an incorrect format. (Exception from HRESULT: 0x8007000B) I'm very new to SQL and Firebird in general, so I'm not sure how to resolve this issue. Anyone?

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  • How to append query parametr @runtime using jquery

    - by Wondering
    Hi All, Through javascript I am appending one query parameter to the page url and I am facing one strange behaiviour <div> <a href="Default3.aspx?id=2">Click me</a> </div> $(function () { window.location.href = window.location.href + "&q=" + "aa"; }); Now I am appending &q in default3.aspx and in this page the &q is getting added continuously I mean the url become http://localhost:1112/WebSite2/Default3.aspx?id=2&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa&q=aa one would say just pass it like <a href="Default3.aspx?id=2&q=aa">Click me</a> but I cant do that , value of this query parameter is actually value of an html element which is in default3.aspx..I have to add it in run time. what are the ways to achieve this. Thanks.

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  • problem after uploading file to web host

    - by Alexander
    I have a .xml file in my App_Data folder, I can access it fine in my localhost, however after uploading it to my webhost I got the following: ASP.NET is not authorized to access the requested resource. Consider granting access rights to the resource to the ASP.NET request identity. ASP.NET has a base process identity (typically {MACHINE}\ASPNET on IIS 5 or Network Service on IIS 6) that is used if the application is not impersonating. If the application is impersonating via , the identity will be the anonymous user (typically IUSR_MACHINENAME) or the authenticated request user. To grant ASP.NET access to a file, right-click the file in Explorer, choose "Properties" and select the Security tab. Click "Add" to add the appropriate user or group. Highlight the ASP.NET account, and check the boxes for the desired access. So who should I grant access to read? There's 3 user in my web host and all seems to have read access set to them.. one is NETWORK_SERVICE, IUSR_MACHINENAME and my user. So what is wrong?

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  • Difficulty Inserting from HTML form into MySQL (created in Workbench)

    - by Chaya Cooper
    I created a MySQL database in Workbench 5.2.35 for purposes of storing and using information submitted in html forms but I'm having difficulty inserting records from the html form. The relevant SQL script was saved as Demo2.sql, the schema is C2F, and the table is customer_info. I wasn't sure if that was the problem, so I tried replacing the database name (Demo2) with the schema name, but that didn't work either. My html file includes: form action="insert.php" method="post" The insert.php file states: ?php $con = mysql_connect("localhost","root","****"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Demo2", $con); $sql="INSERT INTO customer_info(fname, lname, user, password, reminder, answer) VALUES ('$_POST[fname]','$_POST[lname]','$_POST[user]','$_POST[password]','$_POST[reminder]','$_POST[answer]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con) ? I've also tried INSERT INTO c2f.customer_info(fname, lname, etc. and INSERT INTO 'c2f'.'customer_info'

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  • Python client / server question

    - by AustinM
    I'm working on a bit of a project in python. I have a client and a server. The server listens for connections and once a connection is received it waits for input from the client. The idea is that the client can connect to the server and execute system commands such as ls and cat. This is my server code: import sys, os, socket host = '' port = 50105 s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.bind((host, port)) print("Server started on port: ", port) s.listen(5) print("Server listening\n") conn, addr = s.accept() print 'New connection from ', addr while (1): rc = conn.recv(5) pipe = os.popen(rc) rl = pipe.readlines() file = conn.makefile('w', 0) file.writelines(rl[:-1]) file.close() conn.close() And this is my client code: import sys, socket s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) host = 'localhost' port = input('Port: ') s.connect((host, port)) cmd = raw_input('$ ') s.send(cmd) file = s.makefile('r', 0) sys.stdout.writelines(file.readlines()) When I start the server I get the right output, saying the server is listening. But when I connect with my client and type a command the server exits with this error: Traceback (most recent call last): File "server.py", line 21, in <module> rc = conn.recv(2) File "/usr/lib/python2.6/socket.py", line 165, in _dummy raise error(EBADF, 'Bad file descriptor') socket.error: [Errno 9] Bad file descriptor On the client side, I get the output of ls but the server gets screwed up.

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  • Cannot connect to mysql via servlet

    - by JBoy
    Hi all I have been since 2 days trying to figure out why my servlet does not connect to the database MySql. I have mysql installed and working properly and eclipse. Whenever i try to etabilish a connection i get the ClassNotFoundException for the com.mysql.jdbc.Driver, which is actually properly imported, the connector i'm using is the mysql-connector-java5.1.14 added properly as external jar so everything seems fine. here's my code protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String dbUrl="jdbc:mysql://localhost:3306/test"; String username="root"; String password=""; try { Class.forName("com.mysql.jdbc.Driver").newInstance(); conn=DriverManager.getConnection(dbUrl); System.out.println("Connected!"); } catch (SQLException e) { e.printStackTrace(); System.out.println("not connected"); } catch(ClassNotFoundException x){ x.printStackTrace(); } catch(Exception e){ e.printStackTrace(); } } The stacktrace(part of): java.lang.ClassNotFoundException: com.mysql.jdbc.Driver at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1645) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1491) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:375) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:164) i'm following the connection steps from a published java book and also in forums and tutorials i just see the same code, cannot figure out why that Exception comes. On a normal application which does not run on the server the Exception isn't thrown and the connection (in the exact same way) its successfull. Do you have any advice?

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  • PHP Error Form - Leave Contents of Form on Redirect

    - by user1371500
    I have a simple login form in which if an error occurs such as wrong password, I need it to be able to remember the username which was entered. Would I Go about doing this PHP or Javascript as I am not allowed to use JQuery. My current PHP - (Not Including the HTML Form) <?php //MySQl Connection mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("clubresults") or die(mysql_error()); //Initiates New Session - Cookie session_start(); // Start a new session // Get the data passed from the form $username = $_POST['username']; $password = md5($_POST['pass']); // Do some basic sanitizing $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); //Performs SQL Query to retrieve Login Details from DB $sql = "select * from admin_passwords where username = '$username' and password = '$password'"; $result = mysql_query($sql) or die ( mysql_error() ); //Assigns a Variable Count to 0 $count = 0; //Exectues a loop to increment on Successful Login while ($line = mysql_fetch_assoc($result)) { $count++; } //If count is equal to 1 Redirect user to the Members Page and Set Cookie if ($count == 1) { $_SESSION['loggedIn'] = "true"; header("Location: members.php"); // This is wherever you want to redirect the user to } else { //Else Echo that login was a failure. die('Login Failed. <a href=login.php>Click Here to Try Again</a>'); } ?> Any help would be appreciated. Cheers

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  • Javascript ( jQuery ) Error: SyntaxError: missing ) after argument list

    - by Obmerk Kronen
    I have the simplest function : jQuery(document).ajaxSuccess(function(e, xhr, settings) { var widget_id_base = '099_cf_samurai_widget'; if(settings.data.search('action=save-widget') != -1 && settings.data.search('id_base=' + widget_id_base) != -1) { // alert(\'yay!'\); my_function_chosen_099(); } }); function my_function_chosen_099(){ jQuery(".chzn-select").chosen(); } which works just fine , but When I add the width Parameter like so : function my_function_chosen_k99(){ jQuery(".chzn-select").chosen(width:'95%'); } it gives me an error of: Error: SyntaxError: missing ) after argument list Source File: http://localhost/my-path/js/o99.chosen.init.js?ver=k99 Line: 20, Column: 41 Source Code: jQuery(".chzn-select").chosen(width:"95%"); .............................................| I have tried escaping: jQuery(".chzn-select").chosen(width:\"95%"\); and even double jQuery(".chzn-select").chosen(width:\\"95%"\\); and in my desperation, even jQuery(".chzn-select").chosen( width:"95%" ); I checked and rechecked the closing of brackets , and also tried with single quotes ' - but nothing . There appear to be a lot of similar questions here , but all I saw was escaping problems, ANd I have tried all that I know .. What is wrong here ?? I assume it is not a simple syntax error - or is it ? ( one which I can not find .. )

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  • I'm new on Angularjs and i have this error ReferenceError: _ is not defined at h.$scope.setSelectedClient?

    - by user3381078
    Here is my controller.js . var animateApp = angular.module('animateApp'); animateApp.controller('portofolioController', ['$scope', function ($scope) { $scope.selectedCategory = []; $scope.categoryList = [{ id: 1, name: 'webdesign' }, { id: 2, name: 'webdevelop' }, { id: 3, name: 'logo' }]; $scope.clients = [{ name: '1', designation: 'descriere', category: { id: 1, name: 'webdesign' } }, { name: '2', designation: 'descriere', category: { id: 2, name: 'wendevelop' } }, { name: '3', designation: 'descriere', category: { id: 3, name: 'logo' } }, { name: '4', designation: 'descriere', category: { id: 4, name: 'webdesign' } }, { name: '5', designation: 'descriere', category: { id: 5, name: 'webdevelop' } }]; $scope.setSelectedClient = function () { var id = this.category.id; if (_.contains($scope.selectedCategory, id)) { $scope.selectedCategory = _.without($scope.selectedCategory, id); } else { $scope.selectedCategory.push(id); } return false; }; }]); And this is in my html file, is a button and when it pressed, the list i have is sort by category. I have a filter in filter.js who show just the fields in this category. <li data-ng-repeat="category in categoryList"> <a data-ng-click="setSelectedClient()" class="btn">{{category.name}}</a></li> I'm receving an error when i click on click on button. I'm looking posts like that but i can't find anything. ReferenceError: _ is not defined at h.$scope.setSelectedClient (http://localhost/Portofolio2/js/controllers.js:60:13)

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  • How to reslove mysql_fetch_assoc(): problems!

    - by sky
    When i use the code below, im getting this error: Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource when returning the data, anyone can fix it? Thanks! <?php $mysql_server_name="localhost"; $mysql_username=""; $mysql_password=""; $mysql_database=""; $conn=mysql_connect($mysql_server_name, $mysql_username, $mysql_password); ?> <?php $result = mysql_query("SELECT * FROM users"); $arrays = array(); while ($row = mysql_fetch_assoc($result)) { foreach ($row as $key => $val) { if (!array_contains_key($key)) { $arrays[$key] = array(); } $arrays[$key][] = $val; } } ?> <script type="text/javascript"> <?php foreach ($arrays as $key => $val) { print 'var ' . $key . ' = ' . json_encode($val) . ";\r\n"; } ?> </script>

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  • rails route question

    - by badnaam
    I am trying to build a search functionality which at a high level works like this. 1 - I have a Search model, controller with a search_set action and search views/partial to render the search. 2 - At the home page a serach form is loaded with an empty search object or a search object initialized with session[:search] (which contains user search preferences, zip code, proximity, sort order, per page etc). This form has a post(:put) action to search_set. 3 - When a registered user performs a set the params of the search form are collected and a search record is saved against that user. If a unregistered user performs a search then the search set action simply stores the params in the session[:search]. In either case, the search is executed with the given params and the results are displayed. At this point the url of in the location bar is something like.. http://localhost:3000/searches/search_set?stype=1 At this point if the user simply hits enter on the location bar, I get an error that says "No action responded to show" I am guessing because the URL contains search_set which uses a put method and even though I have a search_show (:get) action (which simply reruns the search in the session or saved in the database) does not get called. How can I handle this situation where I can route a user hitting enter into the location bar to a get method? If this does not explain the problem , please let me know I can share more details/code etc. Thanks!

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  • Error in inserting data into database

    - by Matthew
    When I try to run this code it will not insert the data into the database? <?php class Database { private $dsn; function __construct($dbname, $host, $user, $password, $enckey) { $this->dsn = "mysql:dbname=" . $dbname . ';host=' . $host; $this->user = $user; $this->password = $password; } private function createDSN() { return $this->dsn; } public function createConnection() { try { $dbh = new PDO(self::createDSN(), $this->user, $this->password); } catch (PDOException $e) { echo 'Connection failed: ' . $e->getMessage(); } return $dbh; } } $db = new Database('mytest', 'localhost', 'root', 'hashedpassword', null); $dbh = $db->createConnection(); $sql = $dbh->prepare("INSERT INTO contacts (firstname, lastname) VALUES (?,?)"); $sql->execute(array("abc", "xyz")); ?>

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  • PHP login, getting wrong count value from query / fetch array

    - by Chris
    Hello, *EDIT*Thanks to the comments below it has been figured out that the problem lies with the md5, without everything works as it should. But how do i implent the md5 then? I am having some troubles with the following code below to login. The database and register system are already working. The problem lies that it does not find any result at all in the query. IF the count is 0 it should redirect the user to a secured page. But this only works if i write count = 0, but this should be 0 , only if the user name and password is found he should be directed to the secure (startpage) of the site after login. For example root (username) root (password) already exists but i cannot seem to properly login with it. <?php session_start(); if (!empty($_POST["send"])) { $username = ($_POST["username"]); $password = (md5($_POST["password"])); $count = 0; $con = mysql_connect("localhost" , "root", ""); mysql_select_db("testdb", $con); $result = mysql_query("SELECT name, password FROM user WHERE name = '".$username."' AND password = '".$password."' ") or die("Error select statement"); $count = mysql_num_rows($result); if($count > 0) // always goes the to else, only works with >=0 but then the data is not found in the database, hence incorrect { $row = mysql_fetch_array($result); $_SESSION["username"] = $row["name"]; header("Location: StartPage.php"); } else { echo "Wrong login data, please try again"; } mysql_close($con); } ?>

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  • Debugging a local SQL Server 2008 stored proceedure from Visual studio 2008

    - by Ricibob
    Hi all, There are a few posts about this question around but most concern remote debugging - here everything is on same machine. Visual studio 2008. I have a data connection to localhost SQL Server 2008 using Windows authentication with an admin account - this account is a member of sysadmin in SQL server. I double click stored proc and add a break point. I right click and select "Step into stored proceedure". I get the loathed and feared "Canceled by user." in output window. Does anyone know whats doing? Further - right clicking on the data connection shows both "Application debugging" and "Allow SQL/CLR Debugging". I have checked "Enable SQL Server debugging" on the properties of the C# client app. If run that in debug and try to step in to stored proc code "command.ExecuteNonQuery()" then the break points in the stored proc become disabled and are not pulled. After doing this once the right click on stored proc "Execute" and "Step into stored proceedure" are greyed/disabled. To get them back I have to restart visual studio (refresh connection doesn't do it). Any help much appreciated!! Cheers.

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  • How to do something when AVQueuePlayer finishes the last playeritem

    - by user1634529
    I've got an AVQueuePlayer which I'm creating from an array of 4 AVPlayerItems, and it all plays fine. I want to do something when the last item in the queue finishes playing, I've looked a load of answers on here and this is the one that looks most promising for what I want: The best way to execute code AFTER a sound has finished playing In my button handler i have this code: static const NSString *ItemStatusContext; [thePlayerItemA addObserver:self forKeyPath:@"status" options:0 context:&ItemStatusContext]; [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(playerItemDidReachEnd) name:AVPlayerItemDidPlayToEndTimeNotification object:thePlayerItemA]; theQueuePlayer = [AVQueuePlayer playerWithPlayerItem:thePlayerItemA]; [theQueuePlayer play]; and then I have a function to handle playerItemDidReachEnd: - (void)playerItemDidReachEnd:(NSNotification *)notification { // Do stuff here NSLog(@"IT REACHED THE END"); } But when I run this I get an Internal Inconsistency Exception: An -observeValueForKeyPath:ofObject:change:context: message was received but not handled. Key path: status Observed object: <AVPlayerItem: 0x735a130, asset = <AVURLAsset: 0x73559c0, URL = file://localhost/Users/mike/Library/Application%20Support/iPhone%20Simulator/5.0/Applications/A0DBEC13-2DA6-4887-B29D-B43A78E173B8/Phonics%2001.app/yes.mp3>> Change: { kind = 1; } What am I doing wrong?

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  • jQuery .ajax method executing but not firing error (or success)

    - by John Swaringen
    I'm having a very strange situation. I have a .NET Web Service (.asmx) that I'm trying to call via jQuery ajax to populate some <select></select>'s. The service is running System.Web.Services like it's supposed to and should be returning a JSON list. At least that's the way I understand that it will in .NET 3.5/4.0. The main problem is that the .ajax() function (below) seems to execute but the internal callbacks aren't executing. I know it's executing because I can do something before and after the function and both execute, so JavaScript isn't blowing up. $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: 'http://localhost:59191/AFEDropDownService/Service.asmx/GetAVP', data: "{}", dataType: "jsonp", crossDomain: true, success: function(list) { console.log(list); console.log("success!!"); }, error: function(msg) { console.log("error: " + msg.text); } }); If you need more of the code let me know. Or if you know a better way as I'm trying to build cascading <select></select's.

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  • curl run out very slowly.

    - by sabuj
    here is my code bellow: $url = "http://localhost/Test/post_output.php"; $post_data = array ( "foo" => "bar", "query" => "Nettuts", "action" => "Submit" ); $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // we are doing a POST request curl_setopt($ch, CURLOPT_POST, 1); // adding the post variables to the request curl_setopt($ch, CURLOPT_POSTFIELDS, $post_data); curl_setopt($ch, CURLINFO_HEADER_OUT, true); curl_setopt($ch, CURLOPT_VERBOSE, true); // some output will go to stderr / error_log curl_setopt($ch, CURLOPT_TIMEOUT, 10); curl_setopt(CURLOPT_CONNECTTIMEOUT, 5); $output = curl_exec($ch); $errStr = curl_error($ch); $errNum = curl_errno($ch); $head = curl_getinfo($ch, CURLINFO_HEADER_OUT); $ci = curl_getinfo($ch); print_r(array($head, $errStr, $errNum, $ci)); exit; curl_close($ch); echo $output; This script outputs very slowly. Even outputs nothing... can anyone help out this. Thanks...

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