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  • Apply a recursive CTE on grouped table rows (SQL server 2005).

    - by Evan V.
    Hi all, I have a table (ROOMUSAGE) containing the times people check in and out of rooms grouped by PERSONKEY and ROOMKEY. It looks like this: PERSONKEY | ROOMKEY | CHECKIN | CHECKOUT | ROW ---------------------------------------------------------------- 1 | 8 | 13-4-2010 10:00 | 13-4-2010 11:00 | 1 1 | 8 | 13-4-2010 08:00 | 13-4-2010 09:00 | 2 1 | 1 | 13-4-2010 15:00 | 13-4-2010 16:00 | 1 1 | 1 | 13-4-2010 14:00 | 13-4-2010 15:00 | 2 1 | 1 | 13-4-2010 13:00 | 13-4-2010 14:00 | 3 13 | 2 | 13-4-2010 15:00 | 13-4-2010 16:00 | 1 13 | 2 | 13-4-2010 15:00 | 13-4-2010 16:00 | 2 I want to select just the consecutive rows for each PERSONKEY, ROOMKEY grouping. So the desired resulting table is: PERSONKEY | ROOMKEY | CHECKIN | CHECKOUT | ROW ---------------------------------------------------------------- 1 | 8 | 13-4-2010 10:00 | 13-4-2010 11:00 | 1 1 | 1 | 13-4-2010 15:00 | 13-4-2010 16:00 | 1 1 | 1 | 13-4-2010 14:00 | 13-4-2010 15:00 | 2 1 | 1 | 13-4-2010 13:00 | 13-4-2010 14:00 | 3 13 | 2 | 13-4-2010 15:00 | 13-4-2010 16:00 | 1 I want to avoid using cursors so I thought I would use a recursive CTE. Here is what I came up with: ;with CTE (PERSONKEY, ROOMKEY, CHECKIN, CHECKOUT, ROW) as (select RU.PERSONKEY, RU.ROOMKEY, RU.CHECKIN, RU.CHECKOUT, RU.ROW from ROOMUSAGE RU where RU.ROW = 1 union all select RU.PERSONKEY, RU.ROOMKEY, RU.CHECKIN, RU.CHECKOUT, RU.ROW from ROOMUSAGE RU inner join CTE on RU.ROWNUM = CTE.ROWNUM + 1 where CTE.CHECKIN = RU.CHECKOUT and CTE.PERSONKEY = RU.PERSONKEY and CTE.ROOMKEY = RU.ROOMKEY) This worked OK for very small datasets (under 100 records) but it's unusable on large datasets. I'm thinking that I should somehow apply the cte recursevely on each PERSONKEY, ROOMKEY grouping on my ROOMUSAGE table but I am not sure how to do that. Any help would be much appreciated, Cheers!

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  • diskpart on RDM's ...

    - by karnash
    HI, We have ESXi cluster which is attached to clariion CX4 We have windows 2008 R2 as the guest OS. Attahed to this vm is 2 x 1.95T RDM's I select disk 1 create partition primary size=1 (1MB) then list partition Partition ### Type Size Offset * Partition 1 Primary 1024 KB 1024 KB Then I do the same for the other disk and offset is 1024KB I need to present 4T disk to this vm so I right click on disk 1 convert to simple volume then extend it by adding the second disk now when I do list partition, I see the off set is set to 31k. Can anyone please guide me. Thanks

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  • How to install Windows 8 from Ubuntu without a USB or DVD?

    - by 0xEDD1E
    Last week my windows 7 operating system crashed. So I installed Ubuntu 10.04 on the partition Windows 7 was previously on. I have two Partitions, C: and D:. In partition D: I have very important data and I can't format it (I can't backup because it's very heavy ~50 GB). Now I want to install Windows 8. I have downloaded the ISO file of Windows 8 Pro. I don't have a DVD writer or a USB device to Install this. I need to install this on C: partition (the partition on which I have already installed Ubuntu) and I need to protect the data in partition D:. How do I do this?

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  • SQL Server Interview Questions

    - by Rodney Vinyard
    User-Defined Functions Scalar User-Defined Function A Scalar user-defined function returns one of the scalar data types. Text, ntext, image and timestamp data types are not supported. These are the type of user-defined functions that most developers are used to in other programming languages. Table-Value User-Defined Function An Inline Table-Value user-defined function returns a table data type and is an exceptional alternative to a view as the user-defined function can pass parameters into a T-SQL select command and in essence provide us with a parameterized, non-updateable view of the underlying tables. Multi-statement Table-Value User-Defined Function A Multi-Statement Table-Value user-defined function returns a table and is also an exceptional alternative to a view as the function can support multiple T-SQL statements to build the final result where the view is limited to a single SELECT statement. Also, the ability to pass parameters into a T-SQL select command or a group of them gives us the capability to in essence create a parameterized, non-updateable view of the data in the underlying tables. Within the create function command you must define the table structure that is being returned. After creating this type of user-defined function, I can use it in the FROM clause of a T-SQL command unlike the behavior found when using a stored procedure which can also return record sets.

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  • Using a subset of GetHashCode() to increase AzureTable performance through partitioning

    - by makerofthings7
    Generally speaking, Azure Table IO performance improves as more partitions are used (with some tradeoffs in continuation tokens and batch updates I won't go into). Since the partition key is always a string I am considering using a "natural" load balancing technique based on a subset of the GetHashCode() of the partition key, and appending this subset to the partition key itself. This will allow all direct PK/RK queries to be computed with little overhead and with ease. Batch updates may just need an intermediate to group similar PKs together prior to submission. Question: Should I use GetHashCode() to compute the partition key? Is a better function available? If I use GetHashCode() does it matter which character I use for my PK? Is there an abstraction for Azure Table and Blob storage that does this for me already?

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  • SQL Server: How do I generate the table schema and populate it with inserts in a script?

    - by Paula DiTallo
    Originally posted on: http://geekswithblogs.net/AskPaula/archive/2014/05/20/156469.aspx In SSMS, there's a Generate Script utility (read:  only available under version 2008 and up) . Here are the steps you would need to take to make use of the utility: Right click on the database you're interested in and go to Tasks -> Generate ScriptsSelect the tables and/or any other objects you'd like in order to get them into the script.Navigate to Set scripting options. Click on Advanced.Under the General category, navigate to Type of data to scriptSelect the Schema and Data option to get the insert statements generated. Click OK.

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  • Ubuntu installation does not recognize drive partitioning

    - by Woltan
    I have a 1TB drive and installed Windows 7 on a 128GB partition. When I now try to install Ubuntu 11.04 it does not recognize the Windows partition but offers the complete 1TB drive to install Ubuntu on instead. It displays: However, in the Ubuntu Disk Utility the Windows partitions are recognized. What do I need to do in order for Ubuntu to recognize the Windows 7 partition and install Ubuntu as a dual boot? Response to comments The following commands were executed and the results are shown below: fdisk -l WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x34a38165 Device Boot Start End Blocks Id System /dev/sda1 * 1 13 102400 7 HPFS/NTFS Partition 1 does not end on cylinder boundary. /dev/sda2 13 16318 130969600 7 HPFS/NTFS Disk /dev/sdb: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x14a714a6 Device Boot Start End Blocks Id System /dev/sdb1 1 60801 488384001 83 Linux parted -l Warning: Unable to open /dev/sr0 read-write (Read-only file system). /dev/sr0 has been opened read-only. Error: /dev/sr0: unrecognised disk label

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  • How to list missing partitions?

    - by celebrimbor
    I have installed Ubuntu on one of my partition and Crunchbang on the other partition. As I wanted to make some continuous space, I moved Crunchbang partition and then checked fdisk output which looks like this Disk /dev/sda: 320.1 GB, 320072933376 bytes 255 heads, 63 sectors/track, 38913 cylinders, total 625142448 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xc7996dfa Device Boot Start End Blocks Id System /dev/sda1 * 63 80324 40131 de Dell Utility /dev/sda4 81918 625139711 312528897 f W95 Ext'd (LBA) /dev/sda5 81920 211816447 105867264 83 Linux /dev/sda6 299100160 341043199 20971520 83 Linux /dev/sda7 341045248 625139711 142047232 7 HPFS/NTFS/exFAT I cannot see sda2 and sda3 partition. How to find them?

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  • How can I choose different hints for different joins for a single table in a query hint?

    - by RenderIn
    Suppose I have the following query: select * from A, B, C, D where A.x = B.x and B.y = C.y and A.z = D.z I have indexes on A.x and B.x and B.y and C.y and D.z There is no index on A.z. How can I give a hint to this query to use an INDEX hint on A.x but a USE_HASH hint on A.z? It seems like hints only take the table name, not the specific join, so when using a single table with multiple joins I can only specify a single strategy for all of them. Alternative, suppose I'm using a LEADING or ORDERED hint on the above query. Both of these hints only take a table name as well, so how can I ensure that the A.x = B.x join takes place before the A.z = D.z one? I realize in this case I could list D first, but imagine D subsequently joins to E and that the D-E join is the last one I want in the entire query. A third configuration -- Suppose I want the A.x join to be the first of the entire query, and I want the A.z join to be the last one. How can I use a hint to have a single join from A to take place, followed by the B-C join, and the A-D join last?

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  • Combining data sets without losing observations in SAS

    - by John
    Hye guys, I know, another post another problem :D :(. I took a screenshot to easily explain my problem. http://i39.tinypic.com/rhms0h.jpg As you can see I want to merge two tables (again), the Base & Analyst table. What I want to achieve is displayed in the right bottom corner table. I’m calculating the number of total analysts and female analysts for each month in the analyst table. In the base table I have different observations for one company (here company Alcoa with ticker AA). When I use the following command: data want; merge base analyst; by month ; run; I get the right up corner problem. My observations in the main table are being narrowed down to only 4 observations (for each different year one observation, 2001, 2002, 2005, 2006). What I want is that the observations are not reduced but that for every year the same data is being placed as shown in the right bottom corner. What am I missing in my merge command? In both tables I have month as a time count variable ( the observations in my base table are monthly) on which I need to merge. For clarity I added 2 screenshots of my real databases in SAS. The base table: http://i42.tinypic.com/dr5jky.jpg The analyst table: http://i40.tinypic.com/eqpmqq.jpg Here is what my merged table looks like: http://i43.tinypic.com/116i62s.jpg You can clearly see that the merged table only has four observations left for AA (one for each unique year) instead of the original 8. Anyone an idea to solve this?

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  • How do I select a row in a table based on what ddl option is selected MVC?

    - by user54197
    I have a table with a few rows of data. I would like to display a row based on what option is selected on the ddl. how do I do that? <script type="text/javascript" language="javascript"> function optionSelected() { alert('HELP!!'); } </script> ... <select id="optionSelect" onchange="optionSelected()"> <option id="1">1</option> <option id="2">2</option> <option id="3">3</option> </select> <br /> <table id="optionList"> <tr><td id="1">Option 1 Selected</td></tr> <tr><td id="2">Option 2 Selected</td></tr> <tr><td id="3">Option 3 Selected</td></tr> </table>

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  • tablecell not getting selected

    - by praseed
    hi friends,, I am facing a problem with the group table view in editing mode... I have one grouped table view with a edit button added to the navigation item . When the table is in non editing mode i can select the table cells and the selection is shown... But when table goes in editing mode ,by pressing the edit button, i cant select the table cells .. Can anyone point out a solution for this,,,,

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  • "Failed to create swap space" error during installation

    - by Welsh Heron
    I've been trying to install Ubuntu for the past two days or so, but I've been running into a problem: every time I run the installation program on the LiveCD, I always get the same (or a very similar) error: "Failed to create Swap space The creation of swap space in partition #3 of SCSI5 (0,0,0)(sda) failed." So far, I've run DBAN (Darik's Boot and Nuke) on my HDD once, to make absolutely sure that everything on it had been erased. Then, I simply put in the LiveCD, and let it run the automated install. I get the above error directly after I tell it to automatically partition the HDD (it will work for a second or so, then this will pop up), forcing me back to the screen that lets me choose whether I want to automatically or manually partition the HDD. Well, after failing to install the software manually, I did a little research and learned enough about partitioning Linux to use the 'Manual partitioning' option. I partitioned the HDD as follows (it's a 1TB drive): /home - (the rest)- ext2, / - 20GB - ext2, /boot - 100MB - ext2, /swap - 8GB /EFIboot - 40MB The only difference when I tried this method was that I got THIS message: "Failed to create Swap space The creation of swap space in partition #2 of SCSI5 (0,0,0)(sda) failed." Basically, the only difference was that there was now a '2' instead of a '3'. If I may ask, what exactly am I doing wrong? I've tried looking around the internet (that's basically all I've done for the last two days), but no one seems to have the same problem that I have, and I've tried most of the solutions for similar problems (DBAN, formatting partitions in ext2 format, etc). The only thing I haven't tried is using the terminal to manually partition the HDD...and I actually DID try to do this, but I wasn't able to get past 'su' 's password demand, so I wasn't able to use the terminal. Thank you for your help in advance. ~Welsh

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  • GridView paging inside an UpdatePanel or PlaceHolder components

    - by John
    Hello, I'm new to ASP.NET. Im developing ASP.NET C# web form which creating GridView components dynamically and filling them using the data received from my webservice. I'm creating these GridView components programmatically in server-side (cs file)- it has to be flexible - 1 GridView and sometimes 10 GridView components. The problem occurs when I'm trying to add pagination - whenever the user clicks the "next" page, the whole page is getting refreshed because of a postBack and I'm loosing all my data and the page returns Blank/Empty. I used PlaceHolder to hold the GridView components, while searching for a solution, I found UpdatePanel as a better alternative - as far as I understand the page can be partially refreshed - which means that only the UpdatePanel has to be refreshed...but it doesn't work. The following code sample is my TEST, the UpdatePanel is the only component initiated in the client side (aspx page), the rest initiated programmatically in CS. how can I solve the issue described above? Why does the whole page is getting refreshed and I'm loosing my data? can you recommend another way? can provide me with any code sample? If I'm not rebuilding the GridView, it doesn't work... Here is my Default.aspx.cs: public partial class TestAjaxForm : System.Web.UI.Page { DataTable table; protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) bindGridView(); } public void bindGridView() { GridView gridView1 = new GridView(); gridView1.AutoGenerateColumns = true; gridView1.PageSize = 2; gridView1.AllowPaging = true; gridView1.PagerSettings.Mode = PagerButtons.Numeric; gridView1.PagerSettings.Position = PagerPosition.Bottom; gridView1.PagerSettings.PageButtonCount = 10; gridView1.PageIndexChanging += new GridViewPageEventHandler(this.GridView1_PageIndexChanging); table = new DataTable(); table.Columns.Add("FirstName"); table.Columns.Add("LastName"); DataRow row = table.NewRow(); row["FirstName"] = "John"; row["LastName"] = "Johnoson"; table.Rows.Add(row); row = table.NewRow(); row["FirstName"] = "Johnny"; row["LastName"] = "Marley"; table.Rows.Add(row); row = table.NewRow(); row["FirstName"] = "Kate"; row["LastName"] = "Li"; table.Rows.Add(row); panel.ContentTemplateContainer.Controls.Add(gridView1); gridView1.DataSource = table; gridView1.DataBind(); } protected void GridView1_PageIndexChanging(object sender, GridViewPageEventArgs e) { GridView gridView1 = (GridView)sender; gridView1.PageIndex = e.NewPageIndex; gridView1.DataSource = table; gridView1.DataBind(); } } Please help me, Thank you.

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  • How does MySQL's ORDER BY RAND() work?

    - by Eugene
    Hi, I've been doing some research and testing on how to do fast random selection in MySQL. In the process I've faced some unexpected results and now I am not fully sure I know how ORDER BY RAND() really works. I always thought that when you do ORDER BY RAND() on the table, MySQL adds a new column to the table which is filled with random values, then it sorts data by that column and then e.g. you take the above value which got there randomly. I've done lots of googling and testing and finally found that the query Jay offers in his blog is indeed the fastest solution: SELECT * FROM Table T JOIN (SELECT CEIL(MAX(ID)*RAND()) AS ID FROM Table) AS x ON T.ID >= x.ID LIMIT 1; While common ORDER BY RAND() takes 30-40 seconds on my test table, his query does the work in 0.1 seconds. He explains how this functions in the blog so I'll just skip this and finally move to the odd thing. My table is a common table with a PRIMARY KEY id and other non-indexed stuff like username, age, etc. Here's the thing I am struggling to explain SELECT * FROM table ORDER BY RAND() LIMIT 1; /*30-40 seconds*/ SELECT id FROM table ORDER BY RAND() LIMIT 1; /*0.25 seconds*/ SELECT id, username FROM table ORDER BY RAND() LIMIT 1; /*90 seconds*/ I was sort of expecting to see approximately the same time for all three queries since I am always sorting on a single column. But for some reason this didn't happen. Please let me know if you any ideas about this. I have a project where I need to do fast ORDER BY RAND() and personally I would prefer to use SELECT id FROM table ORDER BY RAND() LIMIT 1; SELECT * FROM table WHERE id=ID_FROM_PREVIOUS_QUERY LIMIT 1; which, yes, is slower than Jay's method, however it is smaller and easier to understand. My queries are rather big ones with several JOINs and with WHERE clause and while Jay's method still works, the query grows really big and complex because I need to use all the JOINs and WHERE in the JOINed (called x in his query) sub request. Thanks for your time!

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  • Why is MySQL with InnoDB doing a table scan when key exists and choosing to examine 70 times more ro

    - by andysk
    Hello, I'm troubleshooting a query performance problem. Here's an expected query plan from explain: mysql> explain select * from table1 where tdcol between '2010-04-13:00:00' and '2010-04-14 03:16'; +----+-------------+--------------------+-------+---------------+--------------+---------+------+---------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+--------------------+-------+---------------+--------------+---------+------+---------+-------------+ | 1 | SIMPLE | table1 | range | tdcol | tdcol | 8 | NULL | 5437848 | Using where | +----+-------------+--------------------+-------+---------------+--------------+---------+------+---------+-------------+ 1 row in set (0.00 sec) That makes sense, since the index named tdcol (KEY tdcol (tdcol)) is used, and about 5M rows should be selected from this query. However, if I query for just one more minute of data, we get this query plan: mysql> explain select * from table1 where tdcol between '2010-04-13 00:00' and '2010-04-14 03:17'; +----+-------------+--------------------+------+---------------+------+---------+------+-----------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+--------------------+------+---------------+------+---------+------+-----------+-------------+ | 1 | SIMPLE | table1 | ALL | tdcol | NULL | NULL | NULL | 381601300 | Using where | +----+-------------+--------------------+------+---------------+------+---------+------+-----------+-------------+ 1 row in set (0.00 sec) The optimizer believes that the scan will be better, but it's over 70x more rows to examine, so I have a hard time believing that the table scan is better. Also, the 'USE KEY tdcol' syntax does not change the query plan. Thanks in advance for any help, and I'm more than happy to provide more info/answer questions.

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  • Can windows XP be better than any Ubuntu (and Linux) distro for an old PC?

    - by Robert Vila
    The old laptop is a Toshiba 1800-100: CPU: Intel Celeron 800h Ram 128 MB (works ok) HDD: 15GB (works ok) Graphics adapter: Integrated 64-bit AGP graphics accelerator, BitBIT, 3D graphic acceleration, 8 MB Video RAM Only WindowsXP is installed, and works ok: it can be used, but it is slow (and hateful). I thought that I could improve performance (and its look) easily, since it is an old PC (drivers and everything known for years...) by installing a light Linux distro. So, I decided to install a light or customized Ubuntu distro, or Ubuntu/Debian derivative, but haven't been successful with any; not even booting LiveCDs: not even AntiX, not even Puppy. Lubuntu wiki says that it won't work because the last to releases need more ram (and some blogs say much more cpu -even core duo for new Lubuntu!-), let alone Xubuntu. The problems I have faced are: 1.There are thousands of pages talking about the same 10/15 lightweight distros, and saying more or less the same things, but NONE talks about a simple thing as to how should the RAM/swap-partition proportion be for this kind of installations. NONE! 2.Loading the LiveCD I have tried several different boot options (don't understand much about this and there's ALWAYS a line of explanation missing) and never receive error messages. Booting just stops at different stages but often seems to stop just when the X server is going to start. I am able to boot to command line. 3.I ignore whether the problem is ram size or a problem with the graphics driver (which surprises me because it is a well known brand and line of computers). So I don't know if doing a partition with a swap partition would help booting the LiveCD. 4.I would like to try the graphical interface with the LiveCD before installing. If doing the swap partition for this purpose would help. How can I do the partition? I tried to use Boot Rescue CD, but it advises me against continuing forward. I would appreciate any ideas as regards these questions. Thank you

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  • Creating GPT partitions on EFI raw disk using diskpart

    - by kafka
    I've got a raw, blank GPT disk for use in a UEFI system. I need to create the partitions on it using diskpart. The only tutorial I've found so far is for diskpart.efi, which I believe is slightly different from the command-line diskpart. MS guide to GPT partitions with diskpart.efi Also the guide says to create a MSR of 32MB, but for a disk= 16GB I know it needs to be 128MB. I'm happy doing it with diskpart, just want to be sure I understand the fundamentals. I'm planning on installing, in this order: ESP partition, size 102 MB (create partition esp size=102) MSR partition, size 128 MB (create partition msr size=128) data partition, the remaining space (approx 460GB) Is this the correct thing to do, or is there anything I'm missing?

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  • Algorithm to find average position

    - by Simran kaur
    In the given diagram, I have the extreme left and right points, that is -2 and 4 in this case. So, obviously, I can calculate the width which is 6 in this case. What we know: The number of partitions:3 in this case The partition number at at any point i.e which one is 1st,second or third partition (numbered starting from left) What I want: The position of the purple line drawn which is positio of average of a particular partition So, basically I just want a generalized formula to calculate position of the average at any point.

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  • Need Help on entity framework

    - by Sarathi1904
    I have 3 tables(Roles,Actions and RoleActionLinks). Roles table has few columns(RoleID,RoleName,Desc). Actions table has few colums(ActionID,ActionName,Desc). In RoleActionLink is created for store the association between Roles and Actions and this table has the columns such as RoleID,ActionID When I created the data model(edmx). it shows only Role and Action as entity. i did not find RoleActionLink table. but even there is no direct relation between Roles and Actions table, both tables are automatically related using RoleActionLink table. When i create the new Action, a action record should be populated in Action table(this is works fine). At the same time, i need to populate record in RoleActionLinks table. But i dont have the entity to populate. Please tell me how to accomplish my needs.

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  • deadlock because of foreign key?

    - by George2
    Hello everyone, I am using SQL Server 2008 Enterprise. I met with deadlock in the following store procedure, but because of my fault, I did not record the deadlock graph. But now I can not reproduce deadlock issue. I want to have a postmortem to find the root cause of deadlock to avoid deadlock in the future. The deadlock happens on delete statement. For the delete statement, Param1 is a column of table FooTable, Param1 is a foreign key of another table (refers to another primary key clustered index column of the other table). There is no index on Param1 itself for table FooTable. FooTable has another column which is used as clustered primary key, but not Param1 column. Here is my guess why there is deadlock, and I want to let people review whether my analysis is correct? Since Param1 column has no index, there will be a table scan, and will acquire table level lock, because of foreign key, the delete operation will also need to check master table (e.g. to acquire lock on master table); Some operation on master table acquires master table lock, but want to acquire lock on FooTable; (1) and (2) cause cycle lock which makes deadlock happen. My analysis correct? Any reproduce scenario? create PROCEDURE [dbo].[FooProc] ( @Param1 int ,@Param2 int ,@Param3 int ) AS DELETE FooTable WHERE Param1 = @Param1 INSERT INTO FooTable ( Param1 ,Param2 ,Param3 ) VALUES ( @Param1 ,@Param2 ,@Param3 ) DECLARE @ID bigint SET @ID = ISNULL(@@Identity,-1) IF @ID > 0 BEGIN SELECT IdentityStr FROM FooTable WHERE ID = @ID END thanks in advance, George

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  • EJB Persist On Master Child Relationship

    - by deepak.siddappa(at)oracle.com
    Let us take scenario where in users wants to persist master child relationship. Here will have two tables dept, emp (using Scott Schema) which are having master child relation.Model Diagram: Here in the above model diagram, Dept is the Master table and Emp is child table and Dept is related to emp by one to n relationship. Lets assume we need to make new entries in emp table using EJB persist method. Create a Emp form manually dropping the fields, where deptno will be dropped as Single Selection -> ADF Select One Choice (which is a foreign key in emp table) from deptFindAll DC. Make sure to bind all field variables in backing bean.Employee Form:Once the Emp form created, If the persistEmp() method is used to commit the record this will persist all the Emp fields into emp table except deptno, because the deptno will be passed as a Object reference in persistEmp method  (Its foreign key reference). So directly deptno can't be passed to the persistEmp method instead deptno should be explicitly set to the emp object, then the persist will save the deptno to the emp table.Below solution is one way of work around to achieve this scenario -Create a method in sessionBean for adding emp records and expose this method in DataControl.     For Ex: Here in the below code 'em" is a EntityManager.            private EntityManager em - will be member variable in sessionEJBBeanpublic void addEmpRecord(String ename, String job, BigDecimal deptno) { Emp emp = new Emp(); emp.setEname(ename); emp.setJob(job); //setting the deptno explicitly Dept dept = new Dept(); dept.setDeptno(deptno); //passing the dept object emp.setDept(dept); //persist the emp object data to Emp table em.persist(emp); }From DataControl palette Drop addEmpRecord as Method ADF button, In Edit action binding window enter the parameter values which are binded in backing bean.     For Ex:     If the name deptno textfield is binded with "deptno" variable in backing bean, then El Expression Builder pass value as "#{backingbean.deptno.value}"Binding:

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  • Slow retrieval of data in SQLITE takes a long using ContentProvider

    - by Arlyn
    I have an application in Android (running 4.0.3) that stores a lot of data in Table A. Table A resides in SQLite Database. I am using a ContentProvider as an abstraction layer above the database. Lots of data here means almost 80,000 records per month. Table A is structured like this: String SQL_CREATE_TABLE = "CREATE TABLE IF NOT EXISTS " + TABLE_A + " ( " + COLUMN_ID + " INTEGER PRIMARY KEY NOT NULL" + "," + COLUMN_GROUPNO + " INTEGER NOT NULL DEFAULT(0)" + "," + COLUMN_TIMESTAMP + " DATETIME UNIQUE NOT NULL" + "," + COLUMN_TAG + " TEXT" + "," + COLUMN_VALUE + " REAL NOT NULL" + "," + COLUMN_DEVICEID + " TEXT NOT NULL" + "," + COLUMN_NEW + " NUMERIC NOT NULL DEFAULT(1)" + " )"; Here is the index statement: String SQL_CREATE_INDEX_TIMESTAMP = "CREATE INDEX IF NOT EXISTS " + TABLE_A + "_" + COLUMN_TIMESTAMP + " ON " + TABLE_A + " (" + COLUMN_TIMESTAMP + ") "; I have defined the columns as well as the table name as String Constants. I am already experiencing significant slow down when retrieving this data from Table A. The problem is that when I retrieve data from this table, I first put it in an ArrayList and then I display it. Obviously, this is possibly the wrong way of doing things. I am trying to find a better way to approach this problem using a ContentProvider. But this is not the problem that bothers me. The problem is for some reason, it takes a lot longer to retrieve data from other tables which have only upto 12 records maximum. I see this delay increase as the number of records in Table A increase. This does not make any sense. I can understand the delay if I retrieve data from Table A, but why the delay in retrieving data from other tables. To clarify, I do not experience this delay if Table A is empty or has less than 3000 records. What could be the problem?

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  • How to calculate the covariance in T-SQL

    - by Peter Larsson
    DECLARE @Sample TABLE         (             x INT NOT NULL,             y INT NOT NULL         ) INSERT  @Sample VALUES  (3, 9),         (2, 7),         (4, 12),         (5, 15),         (6, 17) ;WITH cteSource(x, xAvg, y, yAvg, n) AS (         SELECT  1E * x,                 AVG(1E * x) OVER (PARTITION BY (SELECT NULL)),                 1E * y,                 AVG(1E * y) OVER (PARTITION BY (SELECT NULL)),                 COUNT(*) OVER (PARTITION BY (SELECT NULL))         FROM    @Sample ) SELECT  SUM((x - xAvg) *(y - yAvg)) / MAX(n) AS [COVAR(x,y)] FROM    cteSource

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  • SQL query. An unusual join. DB implemented in sqlite-3

    - by user02814
    This is essentially a question about constructing an SQL query. The db is implemented with sqlite3. I am a relatively new user of SQL. I have two tables and want to join them in an unusual way. The following is an example to explain the problem. Table 1 (t1): id year name ------------------------- 297 2010 Charles 298 2011 David 300 2010 Peter 301 2011 Richard Table 2 (t2) id year food --------------------------- 296 2009 Bananas 296 2011 Bananas 297 2009 Melon 297 2010 Coffee 297 2012 Cheese 298 2007 Sugar 298 2008 Cereal 298 2012 Chocolate 299 2000 Peas 300 2007 Barley 300 2011 Beans 300 2012 Chickpeas 301 2010 Watermelon I want to join the tables on id and year. The catch is that (1) id must match exactly, but if there is no exact match in Table 2 for the year in Table 1, then I want to choose the year that is the next (lower) available. A selection of the kind that I want to produce would give the following result id year matchyr name food ------------------------------------------------- 297 2010 2010 Charles Coffee 298 2011 2008 David Cereal 300 2010 2007 Peter Barley 301 2011 2010 Richard Watermelon To summarise, id=297 had an exact match for year=2010 given in Table 1, so the corresponding line for id=297, year=2010 is chosen from Table 2. id=298, year=2011 did not have a matching year in Table 2, so the next available year (less than 2011) is chosen. As you can see, I would also like to know what that matched year (whether exactly , or inexactly) actually was. I would very much appreciate (1) an indication (yes/no answer) of whether this is possible to do in SQL alone, or whether I need to look outside SQL, and (2) a solution, if that is not too onerous.

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