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  • Dynamically Delete inline formsets in Django

    - by BenMills
    Is it possible to have Django automatically delete formsets that are not present in the request? So for example if I had three inline formsets represented in HTML when I loaded my edit page and I use javascript to remove two of those when the request is processes Django sees that those two forms are no longer their and deletes them.

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  • Django template can't see CSS files

    - by Technical Bard
    I'm building a django app and I can't get the templates to see the CSS files... My settings.py file looks like: MEDIA_ROOT = os.path.join(os.path.abspath(os.path.dirname(__file__)), 'media') MEDIA_URL = '/media/' I've got the CSS files in /mysite/media/css/ and the template code contains: <link rel="stylesheet" type="text/css" href="/media/css/site_base.css" />` then, in the url.py file I have: # DEVELOPMENT ONLY (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': '/media'}), but the development server serves the plain html (without styles). What am I doing wrong?

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  • Storing dynamic fields in Django forms

    - by hekevintran
    Django's form library has a feature of form sets that allow you to process dynamically added forms. For example you would use form sets if your application has a list of bookmarks you could use form sets to process multiple forms that each represent a bookmark. What about if you want to dynamically add a field to a form? An example would be a survey creation page where you can dynamically add an unlimited number of questions. How do you handle this in Django?

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  • ASP.NET C# Write RSS feed for Froogle

    - by Peter
    Hi, I'm trying to create a RSS 2.0 feed in ASP.NET C# with products to provide to Froogle. The RSS feed should look like: http://www.google.com/support/merchants/bin/answer.py?answer=160589&hl=en I'm using the SyndicationFeed and SyndicationsItems to create the feed. But I'm having trouble adding the extra elements like g:image_link. I try the extra elements like; syndicationItem.ElementExtensions.Add(new XElement("image_link", product.ImageLink).CreateReader()); This works, but how can I add the namespace xmlns:g="http://base.google.com/ns/1.0" to the first RSS tag and use this for the extension elements? Thank you

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  • How to Setup an RSS Feed using Feedburner?

    - by Derick K.
    I've searched Google, but only found information on how to setup a feedburner for wordpress or other blogging services. I've also searched stackoverflow, but not found the right information. I'm creating a website, for which I want to have an RSS. Feedburner seems to be a good, free option - so I'd like to use that. When I go to feedburner, using my google account, it says the website I want to claim is invalid. And it's not clear how to make it valid. I also have no experience with RSS (and really websites in general), so I'm not sure where to go from here. What are the steps I need to take, starting from scratch, to add an RSS feed (with feedburner) to a website?

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  • using php to check if xml is atom or rss

    - by guest86
    i'm writing a php code which has to determine if given xml is in "atom" or "rss" format. After observing atom and rss xml files, i decided classify xml based on a root element. If root element is "<feed" it's an atom xml. If it's "<rss" it's not an atom. How can i perform that check using DOM? So far i have: $dom->loadXML($resp); $feed = $dom->getElementsByTagName("feed"); but it's not working quite right....

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  • RSS-Feed or XML-Stream?

    - by Maenny
    HI Folks, I am programming a website for online-reservation-management, preferably for holiday homes. I want to implement a service, which allows the user to pass all their occupation dates to other websites. My question is, what would be the most professional way to do this? Generate a XML-stream Create a valid RSS Feed I think that a XML file has the advantages of being straight to the point, without any information that noone needs. Webmasters of other websites surely prefer the structure of a simple XML file. On the other hand, when someone without programming knowledge wants to use the RSS-Feed with a feedreader or simply with the browser, it may be user-friendlier to use a RSS-FEED. What so you think, I'm unsure...? Greetz Maenny

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  • RSS Reader php (have already read related articles)

    - by lightingwrist
    Hey there. I've read all the related articles on here and can't find one that is specific to what I am looking for. I am new to RSS and am looking for the following reader if anyone know's the right direction to throw me in: An rss reader that I can put on my page that does NOT require mysql database A fairly light chunk of code that I can just add as many .xml,rss.php links/addresses to I can wrap div's around to style each segment specifically as possible can manually limit the amount of feeds that are read to conform to my desires of the pages content out put thanks in advance!

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  • RSS Feed is giving error in cloud

    - by stackuser1
    In my C# asp.net 3.5 application I am using RSS Feed to get current updates of my website. Its working fine and when we subscribe the feed also its updating the data as needed. Now our application is deployed in cloud. There also this RSS feed is opening and showing the data. But When I say Subscribe to this feed Its giving diagnose error page saying Internet Explorer Can not Display this page. Let me know how to work with RSS feed in cloud environment.

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  • Cookieless Django - Django with no cookies

    - by phoebebright
    As I'm writing a django site from government bodies I'm not going to be able to use cookies. I found this snippet http://djangosnippets.org/snippets/1540/ but it's currently not allowing users to login. Before I start debugging I wondered if anyone else has solved this problem with this snippet or in any other way?

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  • Django OpenID django-openid-auth Login Error.

    - by gramware
    I get the following error when attempting to use django-openid-auth OpenID discovery error: No usable OpenID services found for *******@gmail.com I have followed the instructions that come with it, though it seems there is something I am missing. the installation is on my localhost.

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  • No Module named django.core

    - by Sirish Kumar
    Hi, I have updated to latest Django version 1.0.2 after uninstalling my old Django version.But now when I run django-admin.py I get the following error. How can I resolve this? Traceback (most recent call last): File "C:\Python25\Lib\site-packages\django\bin\django-admin.py", line 2, in <module> from django.core import management ImportError: No module named django.core

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  • No Module named django.core

    - by Sirish Kumar
    Hi, I have updated to latest Django version 1.0.2 after uninstalling my old Django version.But now when I run django-admin.py I get the following error. How can I resolve this? Traceback (most recent call last): File "C:\Python25\Lib\site-packages\django\bin\django-admin.py", line 2, in <module> from django.core import management ImportError: No module named django.core

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  • Django - need to split a table across multiple locations [closed]

    - by MikeRand
    Hi all, I have a Django project to track our company's restructuring projects. Here's the very simple model: class Project(models.Model): code = models.CharField(max_length=30) description = models.CharField(max_length=60) class Employee(models.Model): project = models.ForeignKey(Project) employee_id = models.IntegerField() country_code = models.CharField(max_length=3) severance = models.IntegerField() Due to regulations in some European countries, I'm not allowed to keep employee-level severance information in a database that sits on a box outside of that country. In Django, how do I manage the need to have my Employee table split across multiple databases based on an Employee attribute (i.e. country_code) in a way that doesn't impact anything else in the project (e.g. views, templates, admin)? Thanks, Mike

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  • Use the Django ORM in a standalone script (again)

    - by Rishabh Manocha
    I'm trying to use the Django ORM in some standalone screen scraping scripts. I know this question has been asked before, but I'm unable to figure out a good solution for my particular problem. I have a Django project with defined models. What I would like to do is use these models and the ORM in my scraping script. My directory structure is something like this: project scrape #scraping scripts ... test.py web django_project settings.py ... #Django files I tried doing the following in project/scrape/test.py: print os.path.join(os.path.abspath('..'), 'web', 'django_project') sys.path.append(os.path.join(os.path.abspath('..'), 'web', 'django_project')) print sys.path print "-------" os.environ['DJANGO_SETTINGS_MODULE'] = 'django_project.settings' #print os.environ from django_project.myapp.models import MyModel print MyModel.objects.count() However, I get an ImportError when I try to run test.py: Traceback (most recent call last): File "test.py", line 12, in <module> from django_project.myapp.models import MyModel ImportError: No module named django_project.myapp.models One solution I found around this problem is to create a symbolic link to ../web/govcheck in the scrape folder: :scrape rmanocha$ ln -s ../web/govcheck ./govcheck With this, I can then run test.py just fine. However, this seems like a hack, and more importantly, is not very portable (I will have to create this symbolic link everywhere I run this code). So, I was wondering if anyone has any better solutions for my problem?

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  • Django: Using 2 different AdminSite instances with different models registered

    - by omat
    Apart from the usual admin, I want to create a limited admin for non-staff users. This admin site will have different registered ModelAdmins. I created a folder /useradmin/ in my project directory and similar to contrib/admin/_init_.py I added an autodiscover() which will register models defined in useradmin.py modules instead of admin.py: # useradmin/__init__.py def autodiscover(): # Same as admin.autodiscover() but registers useradmin.py modules ... for app in settings.INSTALLED_APPS: mod = import_module(app) try: before_import_registry = copy.copy(site._registry) import_module('%s.useradmin' % app) except: site._registry = before_import_registry if module_has_submodule(mod, 'useradmin'): raise I also cretated sites.py under useradmin/ to override AdminSite similar to contrib/admin/sites: # useradmin/sites.py class UserAdminSite(AdminSite): def has_permission(self, request): # Don't care if the user is staff return request.user.is_active def login(self, request): # Do the login stuff but don't care if the user is staff if request.user.is_authenticated(): ... else: ... site = UserAdminSite(name='useradmin') In the project's URLs: # urls.py from django.contrib import admin import useradmin admin.autodiscover() useradmin.autodiscover() urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), (r'^useradmin/', include(useradmin.site.urls)), ) And I try to register different models in admin.py and useradmin.py modules under app directories: # products/useradmin.py import useradmin class ProductAdmin(useradmin.ModelAdmin): pass useradmin.site.register(Product, ProductAdmin) But when registering models in useradmin.py like useradmin.site.register(Product, ProductAdmin), I get 'module' object has no attribute 'ModelAdmin' exception. Though when I try this via shell; import useradmin from useradmin import ModelAdmin does not raise any exception. Any ideas what might be wrong? Edit: I tried going the @Luke way and arranged the code as follows as minimal as possible: (file paths are relative to the project root) # admin.py from django.contrib.admin import autodiscover from django.contrib.admin.sites import AdminSite user_site = AdminSite(name='useradmin') # urls.py (does not even have url patterns; just calls autodiscover()) import admin admin.autodiscover() # products/admin.py import admin from products.models import Product admin.user_site.register(Product) As a result I get an AttributeError: 'module' object has no attribute 'user_site' when admin.user_site.register(Product) in products/admin.py is called. Any ideas? Solution: I don't know if there are better ways but, renaming the admin.py in the project root to useradmin.py and updating the imports accordingly resolved the last case, which was a naming and import conflict.

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  • Pydev and Django: Shell not finding certain modules?

    - by Rosarch
    I am developing a Django project with PyDev in Eclipse. For a while, PyDev's Django Shell worked great. Now, it doesn't: >>> import sys; print('%s %s' % (sys.executable or sys.platform, sys.version)) C:\Python26\python.exe 2.6.4 (r264:75708, Oct 26 2009, 08:23:19) [MSC v.1500 32 bit (Intel)] >>> >>> from django.core import management;import mysite.settings as settings;management.setup_environ(settings) Traceback (most recent call last): File "<console>", line 1, in <module> ImportError: No module named mysite.settings >>> The dev server runs just fine. What could I be doing wrong? The models module is also conspicuously absent: >>> import mysite.myapp.models Traceback (most recent call last): File "<console>", line 1, in <module> ImportError: No module named mysite.myapp.models On the normal command line, outside of PyDev, the shell works fine. Why could this be happening?

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  • Django Database design -- Is this a good stragety for overriding defaults

    - by rh0dium
    Hi SO's I have a question on good database design practices and I would like to leverage you guys for pointers. The project started out simple. Hey we have a bunch of questions we want answered for every project (no problem) Which turned into... Hey we have so many questions can we group them into sections (yup we can do that) Which lead into.. Can we weight these questions and I don't really want some of these questions for my project (Yes but we are getting difficult) And then I'm thinking they will want to have each section have it's own weight.. Requirements So there's the requirements - For n number of project Allow a admin member the ability select the questions for a project Allow the admin member to re-weigh or use the default weights for the questions Allow the admin member to re-weight the sections Allow team members to answer the questions. So here is what I came up with. Please feel free to comment and provide better examples models.py from django.db import models from django.contrib.sites.models import Site from django.conf import settings class Section(models.Model): """ This describes the various sections for a checklist: """ name = models.CharField(max_length=64) description = models.TextField() class Question(models.Model): """ This simply provides a simple way to list out the questions. """ question = models.CharField(max_length=255) answer_type = models.CharField(max_length=16) description = models.TextField() section = models.ForeignKey(Section) class ProjectQuestion(models.Model): """ These are the questions relevant to the project """ question = models.ForeignKey(Question) answer = models.CharField(max_length=255) required = models.BooleanField(default=True) weight = models.FloatField(default = XXX) class Project(models.Model): """ Here is where we want to gather our questions """ questions = models.ManyToManyField(ProjectQuestion) Immediate questions: - When I start a project - any ideas on how to "pre-populate" the questions (and ultimately the weights) for the project? - Is there a generally accepted method for doing this process that I am missing? Basically the idea that you refer to the questions overide your own default weight, and store the answer? - It appears that a good chuck of the work will be done in the views and that a lot of checking will need to occur there? Is that OK? Again - feel free to give me better strategies!! Thanks

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  • django-social-auth for Facebook is redirecting home and not logging in

    - by Scott Rogowski
    I have had django-social-auth working for Google for quite some time now but am having problems with Facebook. I am at the point where clicking on the /login/facebook/ link will take me to the Facebook authorization page. I then click "go to app" and it redirects me to my home page but does not log in or create a user but does put some strange "#=" onto the back of my URL. Reading up on that, here https://developers.facebook.com/blog/post/552/, and here https://github.com/omab/django-social-auth/issues/199, it seems that would be happening if the redirect uri was not defined. However, on my facebook app settings, I have the following (replacing my site with example.com): + App Namespace: "example" + Site URL: "http://example.com/complete/facebook/" + Site Domain: "example.com" + Sandbox Mode: "On" + Post-Authorize Redirect URL: "http://apps.facebook.com/example/" + Deauthorize URL: "http://www.example.com/" + Post-Authorize URL: "http://example.com/complete/facebook/" The request that django-social-auth is sending to facebook is (replacing my info again): "https://www.facebook.com/dialog/oauth?scope=email&state=*&redirect_uri=http%3A%2F%2Fexample.com%2Fcomplete%2Ffacebook%2F%3Fredirect_state%3D***&client_id=*" The /complete/facebook/ is what is in the documentation and google works as /complete/google/ What am I missing here?

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  • Using django and django-voting app, how can I order a queryset according to the votes of each item?

    - by snz3
    (I'm new to python and django so please bear with me for a second. I apologise if this has been answered elsewhere and couldn't find it) Let's say I have a Link model and through the django-voting application users can vote on link instances. How can I order those link instances according to their score, eg. display those with the higher score first. I assume I could use the get_top manager of django-voting, but that would only give me the top scoring link instances and wouldn't take into consideration other parameters I would like to add (for example, those links that belong to a specific user or paging or whatever). My guess would be to write a custom manager for my Link model where by I can filter a queryset according to each item's score. If I understand correctly that will require me to loop through each item, check its score, and then place it a list (or dictionary) which will then be sorted according to the score of each item. That wouldn't return a queryset but a dictionary with each item. Am I missing something here?

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  • Django IntegrityError: foreign key violation upon delete

    - by Lukasz Korzybski
    I have Order and Shipment model. Shipment has a foreign key to Order. class Order(...): ... class Shipment() order = m.ForeignKey('Order') ... Now in one of my views I want do delete order object along with all related objects. So I invoke order.delete(). I have Django 1.0.4, PostgreSQL 8.4 and I use transaction middleware, so whole request is enclosed in single transaction. The problem is that upon order.delete() I get: ... File "/usr/local/lib/python2.6/dist-packages/django/db/backends/__init__.py", line 28, in _commit return self.connection.commit() IntegrityError: update or delete on table "main_order" violates foreign key constraint "main_shipment_order_id_fkey" on table "main_shipment" DETAIL: Key (id)=(45) is still referenced from table "main_shipment". I checked in connection.queries that proper queries are executed in proper order. First shipment is deleted, after that django executes delete on order row: {'time': '0.000', 'sql': 'DELETE FROM "main_shipment" WHERE "id" IN (17)'}, {'time': '0.000', 'sql': 'DELETE FROM "main_order" WHERE "id" IN (45)'} Foreign key have ON DELETE NO ACTION (default) and is initially deferred. I don't know why I get foreign key constraint violation. I also tried to register pre_delete signal and manually delete shipment objects before delete on order is called, but it resulted in the same error. I can change ON DELETE behaviour for this key in Postgres but it would be just a hack, I wonder if anyone has a better idea what's going on here. There is also a small detail, my Order model inherits from Cart model, so it actually doesn't have id field but cart_ptr_id and after DELETE on order is executed there is also DELETE on cart, but it seems unrelated? to the shipment-order problem so I simplified it in the example.

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  • django: results in in_bulk style without IDs

    - by valya
    in django 1.1.1, Place.objects.in_bulk() does not work and Place.objects.in_bulk(range(1, 100)) works and returns a dictionary of Ints to Places with indexes - primary keys. How to avoid using range in this situation (and avoid using a special query for ids, I just want to get all objects in this dictionary format) >>> Place.objects.in_bulk() Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/lib/python2.5/site-packages/Django-1.1.1-py2.5.egg/django/db/models/manager.py", line 144, in in_bulk return self.get_query_set().in_bulk(*args, **kwargs) TypeError: in_bulk() takes exactly 2 arguments (1 given) >>> Place.objects.in_bulk(range(1, 100)) {1L: <Place: "??? ????">, 3L: <Place: "???????????? ?????">, 4L: <Place: "????????? "??????"">, 5L: <Place: "????????? "??????"">, 8L: <Place: "????????? "??????????????"">, 9L: <Place: "??????? ????????">, 10L: <Place: "????????? ???????">, 11L: <Place: "??????????????? ???">, 14L: <Place: "????? ????? ??????">}

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