Search Results

Search found 5720 results on 229 pages for 'django widget'.

Page 23/229 | < Previous Page | 19 20 21 22 23 24 25 26 27 28 29 30  | Next Page >

  • Django: Data corrupted after loading? (possible programmer error)

    - by Rosarch
    I may be loading data the wrong way. excerpt of data.json: { "pk": "1", "model": "myapp.Course", "fields": { "name": "Introduction to Web Design", "requiredFor": [9], "offeringSchool": 1, "pre_reqs": [], "offeredIn": [1, 5, 9] } }, I run python manage.py loaddata -v2 data: Installed 36 object(s) from 1 fixture(s) Then, I go to check the above object using the Django shell: >>> info = Course.objects.filter(id=1) >>> info.get().pre_reqs.all() [<Course: Intermediate Web Programming>] # WRONG! There should be no pre-reqs >>> from django.core import serializers >>> serializers.serialize("json", info) '[{"pk": 1, "model": "Apollo.course", "fields": {"pre_reqs": [11], "offeredIn": [1, 5, 9], "offeringSchool": 1, "name": "Introduction to Web Design", "requiredFor": [9]}}]' The serialized output of the model is not the same as the input that was given to loaddata. The output has a non-empty pre_req list, whereas the input's pre_reqs field is empty. What am I doing wrong?

    Read the article

  • Sorting related objects in the Django Admin form interface

    - by Carver
    I am looking to sort the related objects that show up when editing an object using the admin form. So for example, I would like to take the following object: class Person(models.Model): first_name = models.CharField( ... ) last_name = models.CharField( ... ) hero = models.ForeignKey( 'self', null=True, blank=True ) and edit the first name, last name and hero using the admin interface. I want to sort the objects as they show up in the drop down by last name, first name (ascending). How do I do that? Context I'm using Django v1.1. I started by looking for help in the django admin docs, but didn't find the solution As you can see in the example, the foreign key is pointing to itself, but I expect it would be the same as pointing to a different model object. Bonus points for being able to filter the related objects, too (eg~ only allow selecting a hero with the same first name)

    Read the article

  • Django: Why Doesn't the Current URL Match any Patterns in urls.py

    - by austin_sherron
    I've found a few questions here related to my issue, but I haven't found anything that has helped me resolve my issue. I'm using Python 2.7.5 and Django 1.8.dev20140627143448. I have a view that's interacting with my database to delete objects, and it takes two arguments in addition to a request: def delete_data_item(request, dataclass_id, dataitem_id): form = AddDataItemForm(request.POST) data_set = get_object_or_404(DataClass, pk=dataclass_id) context = {'data_set': data_set, 'form': form} data_item = get_object_or_404(DataItem, pk=dataitem_id) data_item.delete() data_set.save() return HttpResponseRedirect(reverse('detail', args=(dataclass_id,))) The URL in myapp.urls.py looks something like this: url(r'^(?P<dataclass_id>[0-9]+)/(?P<dataitem_id>[0-9]+)/delete_data_item/$', views.delete_data_item, name='delete_data_item') and the portion of my template relevant to the view is: <a href="{% url 'delete_data_item' data_set.id data_item.id %}">DELETE</a> Whenever I click on the DELETE link, django tells me that the request URL: http://127.0.0.1:8000/myapp/5/%7B%%20url%20'delete_data_item'%20data_set.id%20data_item.id%20%%7D doesn't match any of my URL patterns. What am I missing? The URL on which the DELETE links exist is myapp/(<dataclass_id>[0-9]+)/

    Read the article

  • Android seekbar widget: no vertical orientation?

    - by Silvio Donnini
    I can't believe there is no way to change the orientation of the SeekBar widget. I've been perusing this widget's properties and I can't find anything that allows me to change its orientation to vertical. So, am I missing something obvious? Do I have to write my own implementation of a seekbar to have its thumb slide up/down instead of left/right?

    Read the article

  • Android - where's code for Genie widget?

    - by DroidIn.net
    I've been looking all over http://android.git.kernel.org for Genie Widget code but unfortunately there's no top level search and lot of GITs to go through. If someone can point me to the right location I would really appreciate it. The Genie Widget is also known as News & Weather

    Read the article

  • Job scheduler UI widget?

    - by tinny
    Does anyone know of a good Job scheduler UI widget? The ideal component would be a Javascript widget (hopefully JQuery) that allows a user to select a frequency which is converted to a cron expression. Anything good out there?

    Read the article

  • Set Android Gallery widget to show specific starting image

    - by Dalmazio Brisinda
    Hi all, I have a task where the user can select an image from a GridView representing a photo album, and from this I start a new activity which displays a Gallery widget to show the images of the photo album. However, I can't seem to get the Gallery widget to show the contents of the photo album with a given image as the starting point. Ideally I would like a Gallery#setStartingImage(int position) or something similar. Any ideas would be greatly appreciated. Best, Dalmazio

    Read the article

  • Android App Widget: Data storage

    - by Jeffrey
    Hello everyone, I'm implementing a home screen app widget. I was wondering which is better to store/read data: SharedPreferences or a SQLite database? The data is accessed from an AppWidgetProvider (similar to a BroadcastReceiver), and any given instance of the widget displays different data based on appWidgetId. Is one way or the other frowned upon? Thanks for your time.

    Read the article

  • Getting a KeyError in DB backend of django-digest

    - by rtmie
    I have just started to integrate django_digest into my app. As a start I have added the @httpdigest decorator to one of my views. If I try to connect to it I get a KeyError exception thrown in django_digest/backend/db.py . Depending on which db I configure I get a different KeyError in a different location. I am using Django 1.2.1, with MySql (also tested with sqlite). I am using the default values for all the settings options. As far as I can see I have followed all instructions but am struggling all day with this. I am using the repository versions of django-digest and python-digest. Any steer would be greatly appreciated. Tracebacks for sqlite and mysql below: with sqlite: Traceback (most recent call last): File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/servers/basehttp.py", line 674, in __call__ return self.application(environ, start_response) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/wsgi.py", line 248, in __call__ signals.request_finished.send(sender=self.__class__) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/dispatch/dispatcher.py", line 162, in send response = receiver(signal=self, sender=sender, **named) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/backend/db.py", line 16, in close_connection _connection.close() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/sqlite3/base.py", line 186, in close if self.settings_dict['NAME'] != ":memory:": KeyError: 'NAME' with mysql: Traceback (most recent call last): File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/servers/basehttp.py", line 674, in __call__ return self.application(environ, start_response) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/wsgi.py", line 241, in __call__ response = self.get_response(request) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 142, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 166, in handle_uncaught_exception return debug.technical_500_response(request, *exc_info) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 80, in get_response response = middleware_method(request) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/middleware.py", line 13, in process_request if (not self._authenticator.authenticate(request) and File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/__init__.py", line 86, in authenticate partial_digest = self._account_storage.get_partial_digest(digest_response.username) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/backend/db.py", line 97, in get_partial_digest cursor = get_connection().cursor() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/__init__.py", line 75, in cursor cursor = self._cursor() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/mysql/base.py", line 281, in _cursor if settings_dict['USER']: KeyError: 'USER'

    Read the article

  • Non-Standard widget size for Android

    - by heorling
    I have a use-case for a vertical 1x4 home screen widget on android. The supported size is 4x1 ie horizontal. Does anyone know if the vertical version can be implemented? I realize changing screen orientation would scrunch the widget together, which I'm fine with. Even better would be if there was an equivalent to "overflow hidden" in css. Has anyone come across a way to do this?

    Read the article

  • Google App Engine with local Django 1.1 gets Intermittent Failures

    - by Jon Watte
    I'm using the Windows Launcher development environment for Google App Engine. I have downloaded Django 1.1.2 source, and un-tarrred the "django" subdirectory to live within my application directory (a peer of app.yaml) At the top of each .py source file, I do this: import settings import os os.environ["DJANGO_SETTINGS_MODULE"] = 'settings' In my file settings.py (which lives at the root of the app directory, as well), I do this: DEBUG = True TEMPLATE_DIRS = ('html') INSTALLED_APPS = ('filters') import os os.environ["DJANGO_SETTINGS_MODULE"] = 'settings' from google.appengine.dist import use_library use_library('django', '1.1') from django.template import loader Yes, this looks a bit like overkill, doesn't it? I only use django.template. I don't explicitly use any other part of django. However, intermittently I get one of two errors: 1) Django complains that DJANGO_SETTINGS_MODULE is not defined. 2) Django complains that common.html (a template I'm extending in other templates) doesn't exist. 95% of the time, these errors are not encountered, and they randomly just start happening. Once in that state, the local server seems "wedged" and re-booting it generally fixes it. What's causing this to happen, and what can I do about it? How can I even debug it? Here is the traceback from the error: Traceback (most recent call last): File "C:\code\kwbudget\edit_budget.py", line 34, in get self.response.out.write(t.render(template.Context(values))) File "C:\code\kwbudget\django\template\__init__.py", line 165, in render return self.nodelist.render(context) File "C:\code\kwbudget\django\template\__init__.py", line 784, in render bits.append(self.render_node(node, context)) File "C:\code\kwbudget\django\template\__init__.py", line 797, in render_node return node.render(context) File "C:\code\kwbudget\django\template\loader_tags.py", line 71, in render compiled_parent = self.get_parent(context) File "C:\code\kwbudget\django\template\loader_tags.py", line 66, in get_parent raise TemplateSyntaxError, "Template %r cannot be extended, because it doesn't exist" % parent TemplateSyntaxError: Template u'common.html' cannot be extended, because it doesn't exist And edit_budget.py starts with exactly the lines that I included up top. All templates live in a directory named "html" in my root directory, and "html/common.html" exists. I know the template engine finds them, because I start out with "html/edit_budget.html" which extends common.html. It looks as if the settings module somehow isn't applied (because that's what adds html to the search path for templates).

    Read the article

  • How to build a widget for my website

    - by Gublooo
    Hey guys I'm very new to the whole programming - so far I only have experience with building websites, database etc. I currently have a website where users can share their online purchases. I want to build a widget that other websites can integrate on their site. Users should be able to insert their purchases directly through this widget without having to come to my website. Thats the idea but I have no idea how to go about it - can anyone point me in the right direction. Thanks

    Read the article

  • django & postgres linux hosting (with SSH access) recommendations

    - by Justin Grant
    We're looking for a good place to host our custom Django app (a fork of OSQA) and its postgresql backend. Requirements include: Linux Python 2.6 or (ideally) Python 2.7 Django 1.2 Postgres 8.4 or later DB backup/restore handled by the hoster, not us OS & dev-platform-stack patching/maintenance handled by the hoster, not us SSH access (so we can pull source code from GitHub, so we can install python eggs, etc.) ability to set up cron jobs (e.g. to send out dail email updates) ability to send up to 10K emails/day good performance (not ganged up with a zillion other sites on one CPU, not starved for RAM) FTP or SCP access to web logs dedicated public IP SSL support Costs under $1000/month for a relatively small site (<5M pageviews/month) Good customer service We already have a prototype site running on EC2 on top of a Bitnami DjangoStack. The problem is that we have to patch the OS, patch postgres, etc. We'd really prefer a platform-as-a-service (PaaS) offering, like Heroku offers for Rails apps, where all we need to worry about is deploying our code instead of worrying about system software patching and maintenance. Google App Engine is closest to what we're looking for, but they don't offer relational DB access (not yet at least). Anyone have a recommendation?

    Read the article

  • Authenticate with Django 1.5

    - by gorjuce
    I'm currently testing django 1.5 and a custom User model, but I've some problems. I've created a User class in my account app, which looks like: class User(AbstractBaseUser): email = models.EmailField() activation_key = models.CharField(max_length=255) is_active = models.BooleanField(default=False) is_admin = models.BooleanField(default=False) USERNAME_FIELD = 'email' I can correctly register a user, who is stored in my account_user table. Now, how can I log in? I've tried with: def login(request): form = AuthenticationForm() if request.method == 'POST': form = AuthenticationForm(request.POST) email = request.POST['username'] password = request.POST['password'] user = authenticate(username=email, password=password) if user is not None: if user.is_active: login(user) else: message = 'disabled account, check validation email' return render( request, 'account-login-failed.html', {'message': message} ) return render(request, 'account-login.html', {'form': form}) I can correctly register a new User My forms.py which contains my register form class RegisterForm(forms.ModelForm): """ a form to create user""" password = forms.CharField( label="Password", widget=forms.PasswordInput() ) password_confirm = forms.CharField( label="Password Repeat", widget=forms.PasswordInput() ) class Meta: model = User exclude = ('last_login', 'activation_key') def clean_password_confirm(self): password = self.cleaned_data.get("password") password_confirm = self.cleaned_data.get("password_confirm") if password and password_confirm and password != password_confirm: raise forms.ValidationError("Password don't math") return password_confirm def clean_email(self): if User.objects.filter(email__iexact=self.cleaned_data.get("email")): raise forms.ValidationError("email already exists") return self.cleaned_data['email'] def save(self): user = super(RegisterForm, self).save(commit=False) user.password = self.cleaned_data['password'] user.activation_key = generate_sha1(user.email) user.save() return user My question is: Why does authenticate give me None? I know I'm trying to authenticate() with an email as username but is that not one of the reasons to use a custom User model?

    Read the article

  • Django running on Apache+WSGI and apache SSL proxying

    - by Lessfoe
    Hi all, I'm trying to rewrite all requests for my Django server running on apache+WSGI ( inside my local network) and configured as the WSGI's wiki how to, except that I set a virtualhost for it. The server which from I want to rewrite requests is another apache server listening on port 80. I can manage it to work well if I don't try to enable SSL connection as the required way to connect. But I need all requests to Django server encrypted with SSL so I generally used this directive to achieve this ( on my public webserver ): Alias /dirname "/var/www/dirname" SSLVerifyClient none SSLOptions +FakeBasicAuth SSLRequireSSL AuthName "stuff name" AuthType Basic AuthUserFile /etc/httpd/djangoserver.passwd require valid-user # redirect all request to django.test:80 RewriteEngine On RewriteRule (.*)$ http://django.test/$1 [P] This configuration works if I try to load a specific page trough the external server from my browser. It is not working clicking my django application urls ( even tough the url seems correct when I put my mouse over). The url my public server is trying to serve use http ( instead of https ) and the directory "dirname" I specified on my apache configuration disappear, so it says that the page was not found. I think it depends on Django and its WSGI handler . Does anybody went trough my same problem? PS: I have already tried to modify the WSGI script . I'm Using Django 1.0.3, Apache 2.2 on a Fedora10 (inside), Apache 2.2 on the public server. Thanks in advance for your help. Fab

    Read the article

  • 'NoneType' object has no attribute 'day'

    - by Asinox
    Hi guy, i dont know where is my error, but Django 1.2.1 is give this error: 'NoneType' object has no attribute 'day' when i try to save form from the Administrator Area models.py from django.db import models from django.contrib.auth.models import User class Editorial(models.Model): titulo = models.CharField(max_length=250,help_text='Titulo del editorial') editorial = models.TextField(help_text='Editorial') slug = models.SlugField(unique_for_date='pub_date') autor = models.ForeignKey(User) pub_date = models.DateTimeField(auto_now_add=True) activa = models.BooleanField(verbose_name="Activa") enable_comments = models.BooleanField(verbose_name="Aceptar Comentarios",default=False) editorial_html = models.TextField(editable=False,blank=True) def __unicode__(self): return unicode(self.titulo) def get_absolute_url(self): return "/editorial/%s/%s/" % (self.pub_date.strftime("%Y/%b/%d").lower(), self.slug) class Meta: ordering=['-pub_date'] verbose_name_plural ='Editoriales' def save(self,force_insert=False, force_update=False): from markdown import markdown if self.editorial: self.editorial_html = markdown(self.editorial) super(Editorial,self).save(force_insert,force_update) i dont know why this error, thanks guys sorry with my English

    Read the article

  • Returning user data for forms that have errors in when using ModelForms

    - by Sevenearths
    forms.py from django.forms import ModelForm from client.models import ClientDetails, ClientAddress, ClientPhone from snippets.UKPhoneNumberForm import UKPhoneNumberField class ClientDetailsForm(ModelForm): class Meta: model = ClientDetails class ClientAddressForm(ModelForm): class Meta: model = ClientAddress class ClientPhoneForm(ModelForm): number = UKPhoneNumberField() class Meta: model = ClientPhone views.py from django.shortcuts import render_to_response, redirect from django.template import RequestContext from client.forms import ClientDetailsForm, ClientAddressForm, ClientPhoneForm def new_client_view(request): formDetails = ClientDetailsForm(initial={'marital_status':'u'}) formAddress = ClientAddressForm() formHomePhone = ClientPhoneForm(initial={'phone_type':'home'}) formWorkPhone = ClientPhoneForm(initial={'phone_type':'work'}) formMobilePhone = ClientPhoneForm(initial={'phone_type':'mobi'}) return render_to_response('client/new_client.html', {'formDetails': formDetails, 'formAddress': formAddress, 'formHomePhone': formHomePhone, 'formWorkPhone': formWorkPhone, 'formMobilePhone': formMobilePhone}, context_instance=RequestContext(request)) (the new_client.html is nothing special) How should I write views.py so that if the user's data raises an error, instead of showing them the form again with the errors in but none of their original data, it shows them the form again with the errors AND their original data?

    Read the article

  • java.lang.NoClassDefFoundError at Runtime Android Widget

    - by pxrb66
    I have a problem during runtime of my Android widget with Android 2.3.3 and older. When i install my widget on the screen, this error is printed : 11-03 10:26:31.127: E/AndroidRuntime(404): FATAL EXCEPTION: main 11-03 10:26:31.127: E/AndroidRuntime(404): java.lang.NoClassDefFoundError: com.app.myapp.StackWidgetService 11-03 10:26:31.127: E/AndroidRuntime(404): at com.app.myapp.StackWidgetProvider.onUpdate(StackWidgetProvider.java:229) 11-03 10:26:31.127: E/AndroidRuntime(404): at android.appwidget.AppWidgetProvider.onReceive(AppWidgetProvider.java:61) 11-03 10:26:31.127: E/AndroidRuntime(404): at com.app.mobideals.StackWidgetProvider.onReceive(StackWidgetProvider.java:216) 11-03 10:26:31.127: E/AndroidRuntime(404): at android.app.ActivityThread.handleReceiver(ActivityThread.java:1794) 11-03 10:26:31.127: E/AndroidRuntime(404): at android.app.ActivityThread.access$2400(ActivityThread.java:117) 11-03 10:26:31.127: E/AndroidRuntime(404): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:981) 11-03 10:26:31.127: E/AndroidRuntime(404): at android.os.Handler.dispatchMessage(Handler.java:99) 11-03 10:26:31.127: E/AndroidRuntime(404): at android.os.Looper.loop(Looper.java:123) 11-03 10:26:31.127: E/AndroidRuntime(404): at android.app.ActivityThread.main(ActivityThread.java:3683) 11-03 10:26:31.127: E/AndroidRuntime(404): at java.lang.reflect.Method.invokeNative(Native Method) 11-03 10:26:31.127: E/AndroidRuntime(404): at java.lang.reflect.Method.invoke(Method.java:507) 11-03 10:26:31.127: E/AndroidRuntime(404): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:839) 11-03 10:26:31.127: E/AndroidRuntime(404): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:597) 11-03 10:26:31.127: E/AndroidRuntime(404): at dalvik.system.NativeStart.main(Native Method) The problem is due to the fact that the compilator don't arrive to perform the link to the StackWidgetService class at this line in onUpdate method of StackWidgetProvider class : public void onUpdate(Context context, AppWidgetManager appWidgetManager, int[] appWidgetIds) { // update each of the widgets with the remote adapter for (int i = 0; i < appWidgetIds.length; ++i) { // Here we setup the intent which points to the StackViewService which will // provide the views for this collection. Intent intent = new Intent(context, StackWidgetService.class); intent.putExtra(AppWidgetManager.EXTRA_APPWIDGET_ID, appWidgetIds[i]); The widget works well with other version of Android like 3.0, 4.0 etc... Please help me :)

    Read the article

  • Application widget with bundle?

    - by Varand pezeshk
    Hey guys, I have application widget, and I want to send some data to the intent that is attached to PendingIntent, by clicking the widget. here's my code final int N = appWidgetIds.length; for (int i = 0; i < N; i++) { int appWidgetId = appWidgetIds[i]; Intent intent = new Intent(context, UpComingBDays.class); if(bdaysAmount != 0){ Bundle bundle = new Bundle(); bundle.putIntegerArrayList("WIDGETIDS", tempAllIDS); intent.putExtras(bundle); System.out.println("bund insertedddddddddddddd....................."); } PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, intent, 0); RemoteViews remoteView = new RemoteViews(context.getPackageName(), R.layout.widget_layout); remoteView.setTextViewText(R.id.widget_text, finalText4TextView); remoteView.setOnClickPendingIntent(R.id.WidgetImageButton, pendingIntent); appWidgetManager.updateAppWidget(appWidgetId, remoteView); } super.onUpdate(context, appWidgetManager, appWidgetIds); I realize always "bund insertedddddddddd......" is printed on CatLog, but the intent's bundle is null. what is incorrect? how can i send data by clicking on widget. plz dont offer to use services as my code does not have anything with it. many thanks.

    Read the article

  • Foreign keys in django admin list display

    - by Olivier
    If a django model contains a foreign key field, and if that field is shown in list mode, then it shows up as text, instead of displaying a link to the foreign object. Is it possible to automatically display all foreign keys as links instead of flat text? (of course it is possible to do that on a field by field basis, but is there a general method?) Example: class Author(models.Model): ... class Post(models.Model): author = models.ForeignKey(Author) Now I choose a ModelAdmin such that the author shows up in list mode: class PostAdmin(admin.ModelAdmin): list_display = [..., 'author',...] Now in list mode, the author field will just use the __unicode__ method of the Author class to display the author. On the top of that I would like a link pointing to the url of the corresponding author in the admin site. Is that possible? Manual method: For the sake of completeness, I add the manual method. It would be to add a method author_link in the PostAdmin class: def author_link(self, item): return '<a href="../some/path/%d">%s</a>' % (item.id, unicode(item)) author_link.allow_tags = True That will work for that particular field but that is not what I want. I want a general method to achieve the same effect. (One of the problems is how to figure out automatically the path to an object in the django admin site.)

    Read the article

  • Re-ordering child nodes in django-MPTT

    - by Dominic Rodger
    I'm using Ben Firshman's fork of django-MPTT (hat tip to Daniel Roseman for the recommendation). I've got stuck trying to re-order nodes which share a common parent. I've got a list of primary keys, like this: ids = [5, 9, 7, 3] All of these nodes have a parent, say with primary key 1. At present, these nodes are ordered [5, 3, 9, 7], how can I re-order them to [5, 9, 7, 3]? I've tried something like this: last_m = MyModel.get(pk = ids.pop(0)) last_m.move_to(last_m.parent, position='first-child') for id in ids: m = MyModel.get(pk = id) m.move_to(last_m, position='right') Which I'd expect to do what I want, per the docs on move_to, but it doesn't seem to change anything. Sometimes it seems to move the first item in ids to be the first child of its parent, sometimes it doesn't. Am I right in my reading of the docs for move_to that calling move_to on a node n with position=right and a target which is a sibling of n will move n to immediately after the target? It's possible I've screwed up my models table in trying to figure this out, so maybe the code above is actually right. It's also possible there's a much more elegant way of doing this (perhaps one that doesn't involve O(n) selects and O(n) updates). Have I misunderstood something? Bonus question: is there a way of forcing django-MPTT to rebuild lft and rght values for all instances of a given model?

    Read the article

  • django-mptt fields showing up twice, breaking SQL

    - by Dominic Rodger
    I'm using django-mptt to manage a simple CMS, with a model called Page, which looks like this (most presumably irrelevant fields removed): class Page(mptt.Model, BaseModel): title = models.CharField(max_length = 20) slug = AutoSlugField(populate_from = 'title') contents = models.TextField() parent = models.ForeignKey('self', null=True, blank=True, related_name='children', help_text = u'The page this page lives under.') removed fields are called attachments, headline_image, nav_override, and published All works fine using SQLite, but when I use MySQL and try and add a Page using the admin (or using ModelForms and the save() method), I get this: ProgrammingError at /admin/mycms/page/add/ (1110, "Column 'level' specified twice") where the SQL generated is: 'INSERT INTO `kaleo_page` (`title`, `slug`, `contents`, `nav_override`, `parent_id`, `published`, `headline_image_id`, `lft`, `rght`, `tree_id`, `level`, `lft`, `rght`, `tree_id`, `level`) VALUES (%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s)' for some reason I'm getting the django-mptt fields (lft, rght, tree_id and level) twice. It works in SQLite presumably because SQLite is more forgiving about what it accepts than MySQL. get_all_field_names() also shows them twice: >>> Page._meta.get_all_field_names() ['attachments', 'children', 'contents', 'headline_image', 'id', 'level', 'lft', 'nav_override', 'parent', 'published', 'rght', 'slug', 'title', 'tree_id'] Which is presumably why the SQL is bad. What could I have done that would result in those fields appearing twice in get_all_field_names()?

    Read the article

< Previous Page | 19 20 21 22 23 24 25 26 27 28 29 30  | Next Page >