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  • Logging a specific package in log4j programmatically

    - by VinTem
    Hi there, here is the thing, I have to deploy a web app and the the log4j.properties file is created by the client so I dont have control over it. Their properties file is like this: log4j.rootCategory= FILE !-----------FILE--------------! log4j.category.FILE=DEBUG log4j.appender.FILE=org.apache.log4j.RollingFileAppender log4j.appender.FILE.File=${catalina.base}/logs/rcweb.log log4j.appender.FILE.MaxFileSize=1024KB log4j.appender.FILE.MaxBackupIndex=10 log4j.appender.FILE.layout=org.apache.log4j.PatternLayout log4j.appender.FILE.layout.ConversionPattern=%-2d{dd/MM/yyyy HH:mm:ss} [%t] %5p %c:%L - %m%n And in my classes I do something like this: private static final Logger LOG = Logger.getLogger(MaterialController.class); LOG.info("my log"); But the log file has never been created. I did the test and changed the log4j.properties file and deployed in my computer adding the following line: log4j.logger.br.com.golive.requisicaoCompras=DEBUG This works, but I cant use the file like this. Is there any ideas? Thanks

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  • C# Getting Just Date From Timestamp

    - by Soo
    If I have a timestamp in the form: yyyy-mm-dd hh:mm:ss:mmm How can I just extract the date from the timestamp? For instance, if a timestamp reads: "2010-05-18 08:36:52:236" what is the best way to just get 2010-05-18 from it. What I'm trying to do is isolate the date portion of the timestamp, define a custom time for it to create a new time stamp. Is there a more efficient way to define the time of the timestamp without first taking out the date, and then adding a new time?

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  • MySQLi Prepared Statement Query Issue

    - by Benjamin Flak
    I'm relatively new to MySQLi prepared statements, and running into an error. Take this code: $user = 'admin'; $pass = 'admin'; if ($stmt = $mysqli->query("SELECT * FROM members WHERE username='$user' AND password='$pass'")) { echo $stmt->num_rows; } This will display "1", as it should. This next piece of code though, returns "0": $user = 'admin'; $pass = 'admin'; if ($stmt = $mysqli->prepare("SELECT * FROM members WHERE username=? AND password=?")) { $stmt->bind_param("ss", $user, $pass); $stmt->execute(); echo $stmt->num_rows; } Any ideas why?

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  • htaccess - rewrite rule issue - not able to get 10th variable

    - by sandeepan-nath
    I am not able to get the 10th variable. I am getting 1st variable appended with a 0(zero) instead. RewriteRule ^(browse_by_exam)/(classes|packs|tutor_search)/([a-zA-Z0-9\.\á\á\â\ä\ã\å\æ\ç\è\é\ê\ë\ì\í\ï\ð\ñ\ò\ó\ô\õ\ö\ø\ù\ú\û\ü\ý\þ\¿\¡\«\»\ÿ\ß\$\*\!\-\=\@\#\%\^\(\)\_\&\{\}\;\,\<\>\?\`\~\[\|\"\'\]\\\ +]+)/([0-1])/([0-9]+)/([0-9]+)/([0-9]+),([0-9]+),([a-z]+),([a-z]+)?$ index.php?a=$1&type=$2&search_text=$3&new_search=$4&search_exam=$5&search_subject=$6&site=$7&count=$8&column=$9&direction=$10 I am not able to get the 10th variable using $_GET['direction'] in my php code - it returns me the 1st variable appended with a 0 i.e. browse_by_exam0. I read in many places about this thing. Here http://www.digimantra.com/tutorials/advanced-htaccess-for-more-than-10-group-of-backtrack-references/, they have given a workaround for the problem - using %1 instead of $10, but that too is not working. Please help. I am completely blocked.

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  • How to send a Timestamp field to Oracle stored proc. from Java despite the DB config?

    - by Alfabravo
    I'm making a request from a java webapp to an Oracle' stored procedure which happens to have a Timestamp IN parameter. In the testing environment, it works sending: SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MMM-yyyy hh:mm:ss a"); input.setTimestampField(dateFormat.format(new Date())); But in the production environment, it raises an exception ORA-01830: date format picture ends before converting entire input string. I know the testing environment should be a replica of the production site, but it is not in my hands to set them properly. And I need to send the Timestamp field despite the way they setup the database. Any ideas? Thanks in advance.

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  • Line break and also getting space in HL7 message

    - by user1280098
    My BizTalk receive XML message as a input message. I am converting that message to HL7 message using Transform in orchestration. Now if input message consists of any empty field in any of the node, the HL7 message breaks up at that postion and also include space in that message. Can anyone help me to resolve this issue? following is my HL7 message: Note --- Copy this message in Textpad to get to know exact space in it MSH|^~\&|EEHR^bbbbbbbbbb|aaaaaaaaaaaaaaaaa^12699^DNS|KYIR|CDP|201103060733||VXU^V04|14962|P|2.3.1|||| PID|1||765874316^^^^SS||ssssss^anan^T|wwwww^^^^^^M|20100217|M||2135-2^YYYYYYYY or jjjjjj^HL70005|5896 hyhyhyhy Ave^Apt# 112^Wanta Fe^NM^85678^XXX^H^^049||5033331120X ^PRN^PH^^^505^5551120^~^NET^X.400^[email protected]|5056083515X4365^WPN^PH^^^505^6086715^4365|es^English^HL70296||||215486702|||H^erererer or qwqwqw^HL70189|bnbnbn|Y|1|||| Thanks.

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  • Twitter date unparseable?

    - by Andreas
    Hi, I want to convert the date string in a Twitter response to a Date object, but I always get a ParseException and I cannot see the error!?! Input string: Thu Dec 23 18:26:07 +0000 2010 SimpleDateFormat Pattern: EEE MMM dd HH:mm:ss ZZZZZ yyyy Method: public static Date getTwitterDate(String date) { SimpleDateFormat sf = new SimpleDateFormat(TWITTER); sf.setLenient(true); Date twitterDate = null; try { twitterDate = sf.parse(date); } catch (Exception e) {} return twitterDate; } I also tried this: http://friendpaste.com/2IaKdlT3Zat4ANwdAhxAmZ but that gives the same result. I use Java 1.6 on Mac OS X. Cheers, Andi

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  • Criteria hibernate

    - by apb
    my code session.createCriteria(Input.class); DateFormat format = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss"); Date startDate = (Date)format.parse("2005-01-01 00:00:00"); Date endDate = (Date)format.parse("2005-03-03 00:00:00"); crit.add(Expression.between ("inputDate", new Date(startDate.getTime()), new Date(endDate.getTime()))); This code return a list, but there is no element present in it. i think it doesn't match the condition. Anybody help.

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  • Java Time Zone When Parsing DateFormat

    - by shipmaster
    I had code that parses date as follows: String ALT_DATE_TIME_FORMAT = "yyyy-MM-dd'T'HH:mm:ss.SSSZ"; SimpleDateFormat sdf = new SimpleDateFormat( ALT_DATE_TIME_FORMAT); Date date = sdf.parse(requiredTimeStamp); And it was working fine, suddenly, this stopped working. It turns out an admin made some config changes on the server and the date is currently being returned as "2010-12-27T10:50:44.000-08:00" which is not parse-able by the above pattern. I have two questions: The first would be what pattern would parse the date being returned by the JVM in the format above (specifically, just '-08:00' as the time zone)? And second, where exactly would one change such settings on a linux RHEL 5 server so that we are aware of such changes in the future?

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  • Retrieving NSDate from NSString

    - by Olivier de Jonge
    I have an iPhone app. that is receiving data with IRFC 3339 timestamp format (e.g. @"2010-01-29T11:30:00.000+01:00"), as in GData. I want to convert the data to an NSDate NSDateFormatter *inputFormatter = [[[NSDateFormatter alloc] init] autorelease]; [inputFormatter setDateFormat:@"yyyy-MM-dd'T'HH:mm:ss.SSS"]; [currentEntry setStartTime:[inputFormatter dateFromString: ][currentEntry startTimeString]]]; But I'm missing out how to convert the last part of the string @"2010-01-29T11:30:00.000+01:00": the time offset. Anyone knows what I have to add to this String to take the time offset in account too?

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  • jQuery Sparklines: $.getJSON data can't be read

    - by Bob Jansen
    I'm trying to generate a pie graph with Sparklines but I'm running into some trouble. I can't seem to figure out what I'm doing wrong, but I feel it is a silly mistake. I'm using the following code to generate a sparkline chart in the div #traffic_bos_ss: //Display Visitor Screen Size Stats $.getJSON('models/ucp/traffic/traffic_display_bos.php', { type: 'ss', server: server, api: api, ip: ip, }, function(data) { var values = data.views; //alert(values); $('#traffic_bos_ss').sparkline(values, { type: "pie", height: "100%", tooltipFormat: 'data.screen - {{value}}', }); }); The JSON string fetched: {"screen":"1220x1080, 1620x1080, 1920x1080","views":"[2, 2, 61]"} For some reason Sparklines does not process the variable values. When I alert the variable it outputs "[2, 2, 61]". Now the jQuery code does work when I replace the snippet: var values = data.views; with var values = [2, 2, 61]; What am I doing wrong?

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  • my NSDateFormatter works only in the iPhone simulator

    - by Manuel Spuhler
    I use a NSDateFormatter which works fine in the simulator, but I get a nil when I run it in the iPhone. I hardcoded the date to be sure of the format, but it fails anyway. NSString *strPubDate = @"Fri, 8 May 2009 08:08:35 GMT"; NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; [dateFormatter setFormatterBehavior:NSDateFormatterBehavior10_4]; [dateFormatter setDateFormat:@"EEE, d MMM yyyy HH:mm:ss Z"]; NSDate *myDate = [dateFormatter dateFromString:strPubDate]; I tried with different region settings, languages etc. on the iPhone. Any idea what is going wrong?

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  • How to convert string date to Timestamp in java?

    - by lakshmi
    Hi, I want to convert string Date into Timestamp in java. The following coding i have written.I have declare the date for date1 is: 7-11-11 12:13:14. SimpleDateFormat datetimeFormatter1 = new SimpleDateFormat( "yyyy-MM-dd hh:mm:ss"); Date lFromDate1 = datetimeFormatter1.parse(date1); System.out.println("gpsdate :" + lFromDate1); Timestamp fromTS1 = new Timestamp(lFromDate1.getTime()); I want to convert 7-11-11 12:13:14 this string date into timestamp. Now i got the output is 0007-11-11 00:13:14.000000 +05:30:00 but i want ( 7-11-11 12:13:14) this format Timestamp date. Can anyone please help me. Thank you.

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  • HTML element to use as a Javascript message display

    - by javanix
    I have a message display field on my website that I'd like to change the value of via JS. I've been using just a textfield, disabling it, and modifying the value via a JS function (after using a little CSS to make it not look like a text field): <input type="text" id="message" style="background: white; color: black" size="50" disabled> There has to be a better way (for instance, formatting is tricky whenever the message runs over the specified size), but I can't think of it off the top of my head. Can anyone point me in a better direction? Thanks! FYI: I am doing a timer function which I'd like to look something like "HH:MM:SS | 'my message here'"

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  • java.util.Date.toString() is printing out wrong format

    - by pacoverflow
    The following code prints out "vmtDataOrig.creationdate=2012-11-03" VmtData vmtDataOrig = VmtDataDao.getInstance().loadVmt(1); System.out.println("vmtDataOrig.creationdate=" + vmtDataOrig.getCreationDate().toString()); Here is the definition of the creationDate field in the VmtData class: private Date creationDate = null; Here is the hibernate mapping of the creationDate field to the database table column: <property name="creationDate" column="CREATIONDATE" type="date"/> The CREATIONDATE column in the MySQL database table is of type "date", and for the record retrieved it has the value "2012-11-03". The Javadoc for the java.util.Date.toString() method says it is supposed to print the Date object in the form "dow mon dd hh:mm:ss zzz yyyy". Anyone know why it is printing it out in the form "yyyy-MM-dd"?

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  • Ant - using vssadd to add multiple file

    - by mamendex
    Hi, I'm trying to use vssadd task to add a tree of source files to a recent created project on VSS. But it happens to be adding only the folder tree, all files missing. <vsscp vsspath="$/DEV/APL_${version}" ssdir="${vssapl}" serverPath="${vsssvr}"/> The vssadd task displays the name of the folders it's creating: ... (vssadd) $/DEV/APL_0.0.10c/src/domain: (vssadd) $/DEV/APL_0.0.10c/src/mbeans: (vssadd) $/DEV/APL_0.0.10c/src/service: ... The script runs successfully but the files never get in the repository. Trying to use wilcards are no good, the task says it found no matching files and ss returns with a code of 100: <vssadd ssdir="${vssapl}" localPath="C:\Workspace\APL_Build*.*" recursive="true" serverPath="${vsssvr}" comment="Build ${versao} at ${to.timestamp}"/ I've noticed that vssadd does not accept fileset tag either, so I'm kind of lost here. Any tips? tks

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  • Using an image as a border

    - by Tempname
    I am working on an custom container and I need a border for this container. I have a 15x15 image that I am creating a 9-slice border skin with. The issue that I am having is that the border skin does not appear the way that I had hoped it would. Here is a ss of the skin in place. Ideally I should have a transparent box with a 5 pixel border around it. Here is my current testing code: CSS Code: Box { borderSkin: Embed(source="15x15.png", scaleGridLeft="5", scaleGridTop="5", scaleGridRight="10", scaleGridBottom="10"); } MXML Code: <mx:WindowedApplication xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute"> <mx:Style source="MainTest.css"/> <mx:Box id="tw" width="400" height="400"> </mx:Box> </mx:WindowedApplication>

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  • Convert String value format of YYYYMMDDHHMMSS to C# DateTime

    - by SARAVAN
    I have a need to convert a string value in the form "YYYYMMDDHHMMSS" to a DateTime. But not sure on how, may be a DateTime.Tryparse can be used to make this happen. Or is there any other way to do it. I can do this using some string operations to take "YYYYMMDD" alone, convert to a datetime and then add HH, MM, SS separately to that DateTime. But is there any DateTime.TryParse() methods that I can use in one line to convert a "YYYYMMDDHHMMSS" format string value to a DateTime value?

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  • How to sanitize log messages in Log4j to save them in database

    - by Rafael
    Hello, I'm trying to save log messages to a central database. In order to do this, I configured the following Appender in log4j's xml configuration: <appender name="DB" class="org.apache.log4j.jdbc.JDBCAppender"> <param name="URL" value="jdbc:postgresql://localhost/logging_test" /> <param name="user" value="test_user" /> <param name="password" value="test_password" /> <param name="sql" value="INSERT INTO log_messages ( log_level, message, log_date ) VALUES ( '%p', '%m', '%d{yyyy-MM-dd HH:mm:ss}' )" /> </appender> This works fine, except some of the messages contain ', and then the appender fails. Is there an easy way to do this?

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  • ValueError: too many values to unpack in a tuple

    - by falosi
    Please put some light on why am getting a too many to unpack (ValueError in my for loop).Have tried deb naislist = [('CONTROL FILE', '0', '0', '0'), ('REDO LOG', '0', '0', '0'), ('ARCHIVED LOG', '.69', '.59', '3'), ('BACKUP PIECE', '46.54', '0', '192'), ('IMAGE COPY', '0', '0', '0'), ('FLASHBACK LOG', '10.15', '6.31', '82'), ('FOREIGN ARCHIVED LOG', '0', '0', '0')] print "size of naislist is ",len((naislist)) heading = ('MAIN MENU', 'LEVELS', 'LEVEL2', 'LEVEL3') rearrange = dict(zip((0, 1, 2, 3), (len(str(x)) for x in heading))) for tu, x in naislist: rearrange.update((i, max(rearrange[i], len(str(el)))) for i, el in enumerate(tu)) rearrange[4] = max(rearrange[4], len(str(x))) forkit = '|'. join('%%-%ss' % rearrange[i] for i in xrange(0, 4)) print '\n'.join((forkit % heading, '-|-'.join(rearrange[i] * '-' for i in xrange(4)), '\n'.join(forkit % (a, b, c, d) for (a, b, c), d in naislist)))

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  • Why is conversion from UTF-8 to ISO-8859-1 not the same in Windows and Linux?

    - by user1895307
    I have the following in code to convert from UTF-8 to ISO-8859-1 in a jar file and when I execute this jar in Windows I get one result and in CentOS I get another. Might anyone know why? public static void main(String[] args) { try { String x = "Ä, ä, É, é, Ö, ö, Ãœ, ü, ß, «, »"; Charset utf8charset = Charset.forName("UTF-8"); Charset iso88591charset = Charset.forName("ISO-8859-1"); ByteBuffer inputBuffer = ByteBuffer.wrap(x.getBytes()); CharBuffer data = utf8charset.decode(inputBuffer); ByteBuffer outputBuffer = iso88591charset.encode(data); byte[] outputData = outputBuffer.array(); String z = new String(outputData); System.out.println(z); } catch(Exception e) { System.out.println(e.getMessage()); } } In Windows, java -jar test.jar test.txt creates a file containing: Ä, ä, É, é, Ö, ö, Ü, ü, ß, «, » but in CentOS I get: ??, ä, ??, é, ??, ö, ??, ü, ??, «, » Help please!

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  • why this assembly program is loaded from the address 0B3D:0000?

    - by viperchaos
    I have seen a assembly program written from a book about assemble: assume cs:code code segment dw 0123h,0456h,0789h,0abch,0defh,0fedh,0cbah,0987h mov bx,0 mov ax,0 mov cx,8 s: add ax,cs:[bx] add bx,2 loop s mov ax,4c00h int 21h code ends end This program's function is to add eight numbers. The author compiled this program in the DOS and use the DEBUG to see how this program be loaded. The author use the R command and got that DS = 0B2DH ES = 0B2D SS = 0B3D CS = 0B3D IP = 0000 And then the author said that this program is loaded from the address 0B3D:0000. I'm a confused that why this program is loaded from the address 0B3D:0000? Is this because the existence of the Program Segment Prefix(PSP)? If the answer is the existence of the PSP, what is in the PSP?

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  • How to change format of date/time?

    - by 4thSpace
    I have this date and time format: 2010-05-19 07:53:30 and would like to change it to: Wednesday @ 7:53PM 5/19/2010 I'm doing this, which gets the current format: NSDateFormatter *formatter = [[NSDateFormatter alloc] init]; formatter.dateFormat = @"yyyy-MM-dd HH:mm:ss"; but when I change the format, I end up with a null. For example: formatter.dateFormat = @"hh:mm tt MM-dd-yyyy"; date = [formatter stringFromDate:formattedDate]; date will be null. I want to put the end result into an NSString. It would be nice if time and date could come out as separate properties so I can arrange them however I like. Any ideas on how I can change the formatting?

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  • Java simple data format british time

    - by DD
    Hi, I am using simple date format to allow users to specify which time zone they are sending data in: DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss,z"); This works fine: e.g. df.parse("2009-05-16 11:07:41,GMT"); However, if someone is always sending time in London time (i.e. taking into account daylight savings), what would be the approriate time zone String to add? e.g. this doesnt work: df.parse("2009-05-16 11:07:41,Europe/London"); Thanks.

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  • How can i get the correct date?

    - by Haley
    Hi, I have a time of NSString type. i wonder get the day, but i find somethine strange. NSString *strTime = @"2010-05-14 16:00:01"; NSDateFormatter *formatter = [[NSDateFormatter alloc] init]; [formatter setDateFormat:@"yyyy-MM-dd HH:mm:ss"]; NSDate *oldDate = [formatter dateFromString:strTime]; unsigned int flags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit; NSCalendar* calendar = [NSCalendar currentCalendar]; NSDateComponents* components = [calendar components:flags fromDate:oldDate]; int day = [components day]; When NSString *strTime = @"2010-05-14 16:00:01" the day is 15,and when NSString *strTime = @"2010-05-14 16:00:00" the day is 14.I want to know why?

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