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  • JPA/Hibernate query with class name?

    - by Petteri Hietavirta
    In this example com.test.Cat extends com.test.Animal and there is no field DB in CAT table of com.test.Cat explicitly defining its type (it wasn't me). When I query my animals from DB I get a collection of Animals. It is possible to sort them by class name: order by r.class but is there a way to use class name as a criteria? For example I would like to get all animals expect dogs. But no luck - even this does not work: where r.class = ? (String "ccc.test.Cat") as I get an exception: Caused by: java.lang.ClassCastException: java.lang.String cannot be cast to java.lang.Integer at org.hibernate.type.IntegerType.set(IntegerType.java:64) at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:154) at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:136) at org.hibernate.param.PositionalParameterSpecification.bind(PositionalParameterSpecification.java:62) at org.hibernate.loader.hql.QueryLoader.bindParameterValues(QueryLoader.java:514) at org.hibernate.loader.Loader.prepareQueryStatement(Loader.java:1589) at org.hibernate.loader.Loader.doQuery(Loader.java:696) at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:259) at org.hibernate.loader.Loader.doList(Loader.java:2228) at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2125) at org.hibernate.loader.Loader.list(Loader.java:2120) at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:401) at org.hibernate.hql.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:361) at org.hibernate.engine.query.HQLQueryPlan.performList(HQLQueryPlan.java:196) at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1148) at org.hibernate.impl.QueryImpl.list(QueryImpl.java:102) at org.hibernate.ejb.QueryImpl.getResultList(QueryImpl.java:67)

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  • How to make a mapped field inherited from a superclass transient in JPA?

    - by Russ Hayward
    I have a legacy schema that cannot be changed. I am using a base class for the common features and it contains an embedded object. There is a field that is normally mapped in the embedded object that needs to be in the persistence id for only one (of many) subclasses. I have made a new id class that includes it but then I get the error that the field is mapped twice. Here is some example code that is much simplified to maintain the sanity of the reader: @MappedSuperclass class BaseClass { @Embedded private Data data; } @Entity class SubClass extends BaseClass { @EmbeddedId private SubClassId id; } @Embeddable class Data { private int location; private String name; } @Embeddable class SubClassId { private int thingy; private int location; } I have tried @AttributeOverride but I can only get it to rename the field. I have tried to set it to updatable = false, insertable = false but this did not seem to work when used in the @AttributeOverride annotation. See answer below for the solution to this issue. I realise I could change the base class but I really do not want to split up the embedded object to separate the shared field as it would make the surrounding code more complex and require some ugly wrapping code. I could also redesign the whole system for this corner case but I would really rather not. I am using Hibernate as my JPA provider.

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  • How to make an entity out of a join table without primary key

    - by tputkonen
    I'm trying to generate JPA entities out of an existing database having an "interesting" design. Database has a table called UserSet, which can have links to several other UserSets. There is a one to many relation between UserSets and LinkedUserSets. LinkedUserSets also has one to one relation to UserSets. I tried to generate a JPA Entity out of the database structure using Dali JPA Tools. The resulting entity Linkeduserset misses @Id or @EmbeddedId annotation and thus failes to compile. As the resulting entity contains only two @JoinColumns (which cannot be marked as @Id), I have not so far found a way around this issue. Database structure can not be modified in any way. Is there a way to overcome this somehow? Relevant pars of create table statements: CREATE TABLE `LinkedUserSets` ( `UsrSetID` INT(11) NOT NULL DEFAULT '0' , `ChildID` INT(11) NOT NULL DEFAULT '0' , CONSTRAINT `fk_LinkedUserSets_UserSet1` FOREIGN KEY (`UsrSetID` ) REFERENCES `UserSet` (`UsrSetID` )); CREATE TABLE `UserSet` ( `UsrSetID` INT(11) NOT NULL AUTO_INCREMENT , PRIMARY KEY (`UsrSetID`), CONSTRAINT `fk_UserSet_LinkedUserSets1` FOREIGN KEY (`UsrSetID` ) REFERENCES `LinkedUserSets` (`ChildID` )); Generated entities: @Entity @Table(name="linkedusersets") public class Linkeduserset { //bi-directional many-to-one association to Userset @ManyToOne @JoinColumn(name="UsrSetID") private Userset userset1; //bi-directional one-to-one association to Userset @OneToOne @JoinColumn(name="ChildID") private Userset userset2; } @Entity @Table(name="userset") public class Userset { private static final long serialVersionUID = 1L; @Id @Column(name="UsrSetID") private int jngSetID; //bi-directional many-to-one association to Linkeduserset @OneToMany(mappedBy="userset1") private Set<Linkeduserset> linkedusersets; //bi-directional one-to-one association to Linkeduserset @OneToOne(mappedBy="userset2") private Linkeduserset linkeduserset; } Error message: Entity "Linkeduserset" has no Id or EmbeddedId

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  • versioning fails for onetomany collection holder

    - by Alexander Vasiljev
    given parent entity @Entity public class Expenditure implements Serializable { ... @OneToMany(mappedBy = "expenditure", cascade = CascadeType.ALL, orphanRemoval = true) @OrderBy() private List<ExpenditurePeriod> periods = new ArrayList<ExpenditurePeriod>(); @Version private Integer version = 0; ... } and child one @Entity public class ExpenditurePeriod implements Serializable { ... @ManyToOne @JoinColumn(name="expenditure_id", nullable = false) private Expenditure expenditure; ... } While updating both parent and child in one transaction, org.hibernate.StaleObjectStateException is thrown: Row was updated or deleted by another transaction (or unsaved-value mapping was incorrect): Indeed, hibernate issues two sql updates: one changing parent properties and another changing child properties. Do you know a way to get rid of parent update changing child? The update results both in inefficiency and false positive for optimistic lock. Note, that both child and parent save their state in DB correctly. Hibernate version is 3.5.1-Final

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  • Help choose a code generation tools for ASP.NET

    - by Kintaro
    Hello, I am new to the code generation tools and I would like to know how does a tool like LLBGen Pro compares with the Entity Framework? On top of that my boos is really looking into a tool called CodeOnTime http://codeontime.com/default.aspx because he likes their good UI support. I am asking here because I really want an unbiased opinion. I am not sure if LLBGen can also generate the UI. So far all the development in the house we do it the classic way coding each layer manually. However we are in need of a fast prototyping tool. Any advice to help me choose wisely will be much appreciated thanks in advance.

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  • Hibernate HQL with interfaces

    - by Benju
    According to this section of the Hibernate documentation I should be able to query any java class in HQL http://docs.jboss.org/hibernate/core/3.3/reference/en/html/queryhql.html#queryhql-polymorphism Unfortunately when I run this query... "from Transaction trans where trans.envelopeId=:envelopeId" I get the message "Transaction is not mapped [from Transaction trans where trans.envelopeId=:envelopeId]". Transaction is an interface, I have to entity classes that implement it, I want on HQL query to return a Collection of type Transaction.

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  • Entity Framework v4 examples and tutorials of conceptual model mapping

    - by Rody van Sambeek
    In an application I'm writing I have a fairly complicated Database model. I'd like to use EF4 to map this to a whole lot nicer conceptual model. However all the tutorials I've read are with samples of 2 or 3 tables which all map 1 on 1 to the conceptual model. I'd like to learn how to correctly map the database model to a different conceptual model using VS 2010. However I can't find any good tutorials or (preferabally) instruction video's. Somebody got any tips, links or even books?

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  • How do I migrate a ManyToOne to a ManyToMany relationship in Hibernate?

    - by spderosso
    I have a instance field of a class X that is mapped using Hibernate as a Many to One relationship. E.g: public class X{ ... @ManyToOne(optional=false) private Y iField; ... } That is correctly working with a particular schema. I know want to change this instance field iField to a List and a Many to Many relationship. public class X{ ... @ManyToMany(optional=false) private List<Y> iField; ... } What steps should I follow? Do I have to change the schema? in which way? In case you need more info let me know. Thanks!

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  • Error when trying to use hibernate annotations.

    - by Wilhelm
    The error I'm receiving is listed here. That's my HibernateUtil.java package com.rosejapan; import org.hibernate.SessionFactory; import org.hibernate.cfg.AnnotationConfiguration;; public class HibernateUtil { private static final SessionFactory sessionFactory; static { try { // Create the SessionFactory from hibernate.cfg.xml sessionFactory = new AnnotationConfiguration().configure().buildSessionFactory(); } catch(Throwable e) { System.err.println("Initial sessionFactory creation failed. " + e); throw new ExceptionInInitializerError(e); } } public static SessionFactory getSessionFactory() { return sessionFactory; } } Everything looks all right... I've already included log4j-boot.jar in the CLASSPATH, but didn't resolved my problem.

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  • Is It Incorrect to Make Domain Objects Aware of The Data Access Layer?

    - by Noah Goodrich
    I am currently working on rewriting an application to use Data Mappers that completely abstract the database from the Domain layer. However, I am now wondering which is the better approach to handling relationships between Domain objects: Call the necessary find() method from the related data mapper directly within the domain object Write the relationship logic into the native data mapper (which is what the examples tend to do in PoEAA) and then call the native data mapper function within the domain object. Either it seems to me that in order to preserve the 'Fat Model, Skinny Controller' mantra, the domain objects have to be aware of the data mappers (whether it be their own or that they have access to the other mappers in the system). Additionally it seems that Option 2 unnecessarily complicates the data access layer as it creates table access logic across multiple data mappers instead of confining it to a single data mapper. So, is it incorrect to make the domain objects aware of the related data mappers and to call data mapper functions directly from the domain objects? Update: These are the only two solutions that I can envision to handle the issue of relations between domain objects. Any example showing a better method would be welcome.

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  • How to generate Doctrine models/classes that extend a custom record class

    - by Shane O'Grady
    When I use Doctrine to generate classes from Yaml/db each Base class (which includes the table definition) extends the Doctrine_Record class. Since my app uses a master and (multiple) slave db servers I need to be able to make the Base classes extend my custom record class to force writes to go to the master db server (as described here). However if I change the base class manually I lose it again when I regenerate my classes from Yaml/db using Doctrine. I need to find a way of telling Doctrine to extend my own Base class, or find a different solution to a master/slave db setup using Doctrine. Example generated model: abstract class My_Base_User extends Doctrine_Record { However I need it to be automatically generated as: abstract class My_Base_User extends My_Record { I am using Doctrine 1.2.1 in a new Zend Framework 1.9.6 application if it makes any difference.

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  • How to detect open database connection with Hibernate / JPA?

    - by John K
    I am learning JPA w/Hibernate using a Java SE 6 project. I'd simply like to be able to detect if the connection between Hibernate and my database (MS SQL Server) is open. For example, I'd like to be able to detect this, log it, and try reconnecting again in 60 seconds. This is what I thought would work but isOpen() doesn't appear to be what I want (always is true): EntityManagerFactory emf = Persistence.createEntityManagerFactory("rcc", props); if (emf != null && emf.isOpen()) { EntityManager em = emf.createEntityManager(); if (em == null || !emf.isOpen()) // error connecting to database else ... This seems to me to be a simple problem, but I cannot find an answer!

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  • Nhibernate not tracking changes

    - by Lavinski
    I'm using nhibernate and it appears that changes to my new object are not persisted. After creating and saving an object I then modify it and commit the transaction. However none of the modifications are saved. The strange thing is this code was working previously and I have no idea what could cause this. Nothing was changed that's obviously related.. As an attempted work around I saved the object later in the procedure after all the changes where made however I was greeted with an Assertion Failure collection [] was not processed by flush. Any ideas?

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  • How to use Linq with Castle ActiveRecord

    - by Ronnie Overby
    I am playing around with Castle ActiveRecord and noticed that the download included the file, Castle.ActiveRecord.Linq.dll. I haven't found any documentation for using Linq with ActiveRecord, only some old blog posts. What is the usage pattern? Is Castle.ActiveRecord.Linq ready for production use? I'm using reflector, pending an answer.

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  • FluentNHibernate Many-To-One References where Foreign Key is not to Primary Key and column names are

    - by Todd Langdon
    I've been sitting here for an hour trying to figure this out... I've got 2 tables (abbreviated): CREATE TABLE TRUST ( TRUSTID NUMBER NOT NULL, ACCTNBR VARCHAR(25) NOT NULL ) CONSTRAINT TRUST_PK PRIMARY KEY (TRUSTID) CREATE TABLE ACCOUNTHISTORY ( ID NUMBER NOT NULL, ACCOUNTNUMBER VARCHAR(25) NOT NULL, TRANSAMT NUMBER(38,2) NOT NULL POSTINGDATE DATE NOT NULL ) CONSTRAINT ACCOUNTHISTORY_PK PRIMARY KEY (ID) I have 2 classes that essentially mirror these: public class Trust { public virtual int Id {get; set;} public virtual string AccountNumber { get; set; } } public class AccountHistory { public virtual int Id { get; set; } public virtual Trust Trust {get; set;} public virtual DateTime PostingDate { get; set; } public virtual decimal IncomeAmount { get; set; } } How do I do the many-to-one mapping in FluentNHibernate to get the AccountHistory to have a Trust? Specifically, since it is related on a different column than the Trust primary key of TRUSTID and the column it is referencing is also named differently (ACCTNBR vs. ACCOUNTNUMBER)???? Here's what I have so far - how do I do the References on the AccountHistoryMap to Trust??? public class TrustMap : ClassMap<Trust> { public TrustMap() { Table("TRUST"); Id(x => x.Id).Column("TRUSTID"); Map(x => x.AccountNumber).Column("ACCTNBR"); } } public class AccountHistoryMap : ClassMap<AccountHistory> { public AccountHistoryMap() { Table("TRUSTACCTGHISTORY"); Id (x=>x.Id).Column("ID"); References<Trust>(x => x.Trust).Column("ACCOUNTNUMBER").ForeignKey("ACCTNBR").Fetch.Join(); Map(x => x.PostingDate).Column("POSTINGDATE"); ); I've tried a few different variations of the above line but can't get anything to work - it pulls back AccountHistory data and a proxy for the Trust; however it says no Trust row with given identifier. This has to be something simple. Anyone? Thanks in advance.

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  • How to allow users to customize a DAL

    - by rsteckly
    Hi, I'm working in ASP.NET in an application where often users want to add fields or change field names. I'd like to be able to have an xml schema in place that is parsed and a dynamic object model created from it that can be accessed throughout the application. My initial reaction is that this is not realistic. I think there is flexibility about the dynamic nature of it. I think the people I'm trying to build this for wouldn't mind recompiling. Even if the app recompiled, I don't know how to abstract away enough in my code access the data to allow for users changing property names, etc. How can you write LINQ when the properties might change? In short, there's two questions here: 1) is there a way to dynamically generate an object model of the database and 2) is there a way to abstract away enough so that code accessing the database doesn't break when properties change?

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  • Is this a right way to use NHibernate?

    - by Venemo
    I spent the rest of the evening reading StackOverflow questions and also some blog entries and links about the subject. All of them turned out to be very helpful, but I still feel that they don't really answer my question. So, I'm developing a simple web application. I'd like to create a reusable data access layer which I can later reuse in other solutions. 99% of these will be web applications. This seems to be a good excuse for me to learn NHibernate and some of the patterns around it. My goals are the following: I don't want the business logic layer to know ANYTHING about the inner workings of the database, nor NHibernate itself. I want the business logic layer to have the least possible number of assumptions about the data access layer. I want the data access layer as simplistic and easy-to-use as possible. This is going to be a simple project, so I don't want to overcomplicate anything. I want the data access layer to be as non-intrusive as possible. Will all this in mind, I decided to use the popular repository pattern. I read about this subject on this site and on various dev blogs, and I heard some stuff about the unit of work pattern. I also looked around and checked out various implementations. (Including FubuMVC contrib, and SharpArchitecture, and stuff on some blogs.) I found out that most of these operate with the same principle: They create a "unit of work" which is instantiated when a repository is instantiated, they start a transaction, do stuff, and commit, and then start all over again. So, only one ISession per Repository and that's it. Then the client code needs to instantiate a repository, do stuff with it, and then dispose. This usage pattern doesn't meet my need of being as simplistic as possible, so I began thinking about something else. I found out that NHibernate already has something which makes custom "unit of work" implementations unnecessary, and that is the CurrentSessionContext class. If I configure the session context correctly, and do the clean up when necessary, I'm good to go. So, I came up with this: I have a static class called NHibernateHelper. Firstly, it has a static property called CurrentSessionFactory, which upon first call, instantiates a session factory and stores it in a static field. (One ISessionFactory per one AppDomain is good enough.) Then, more importantly, it has a CurrentSession static property, which checks if there is an ISession bound to the current session context, and if not, creates one, and binds it, and it returns with the ISession bound to the current session context. Because it will be used mostly with WebSessionContext (so, one ISession per HttpRequest, although for the unit tests, I configured ThreadStaticSessionContext), it should work seamlessly. And after creating and binding an ISession, it hooks an event handler to the HttpContext.Current.ApplicationInstance.EndRequest event, which takes care of cleaning up the ISession after the request ends. (Of course, it only does this if it is really running in a web environment.) So, with all this set up, the NHibernateHelper will always be able to return a valid ISession, so there is no need to instantiate a Repository instance for the "unit of work" to operate properly. Instead, the Repository is a static class which operates with the ISession from the NHibernateHelper.CurrentSession property, and exposes some functionality through that. I'm curious, what do you think about this? Is it a valid way of thinking, or am I completely off track here?

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  • How should I store an Java Enum in JavaDB?

    - by Jonas
    How should I store an Java Enum in JavaDB? Should I try to map the enums to SMALLINT and keep the values in source code only? The embedded database is only used by a single application. Or should I just store the values as DECIMAL? None of these solutions feels good/robust for me. Is there any better alternatives? Here is my enum: import java.math.BigDecimal; public enum Vat { NORMAL(new BigDecimal("0.25")), FOOD(new BigDecimal("0.12")), BOOKS(new BigDecimal("0.06")), NONE(new BigDecimal("0.00")); private final BigDecimal value; Vat(BigDecimal val) { value = val; } public BigDecimal getValue() { return value; } } I have read other similar questions on this topic, but the problem or solution doesn't match my problem. Enum storage in Database field, Best method to store Enum in Database, Best way to store enum values in database - String or Int

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  • Hibernate: Check if object exists/changed

    - by swalkner
    Assuming I have an object Person with long id String firstName String lastName String address Then I'm generating a Person-object somewhere in my application. Now I'd like to check if the person exists in the database (= firstname/lastname-combination is in the database). If not = insert it. If yes, check, if the address is the same. If not = update the address. Of course, I can do some requests (first, try to load object with firstname/lastname), then (if existing), compare the address. But isn't there a simpler, cleaner approach? If got several different classes and do not like to have so many queries. I'd like to use annotations as if to say: firstname/lastname = they're the primary key. Check for them if the object exists. address is the parameter you have to compare if it stayed the same or not. Does Hibernate/JPA (or another framework) support something like that? pseude-code: if (database.containsObject(person)) { //containing according to compound keys if (database.containsChangedObject(person)) { database.updateObject(person); } } else { database.insertObject(person); }

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  • Looking for detailed explanation of Hibernate UserType methods for mutable objects

    - by Tom
    I am creating a custom UserType class in Hibernate. The specific case is for an HL7v3 clinical document (I work in health IT). It is a mutable object and most of the documentation around the Hibernate UserType interface seems to center around immutable types. I want a better understanding of how and when the interface methods are used, specifically: assemble - why two parameters (one Serializable, one Object)? What is the use case for this method? disassemble - should I just implement this method to return a serializable form (e.g. String representation)? When and how is this method invoked? equals - is this for update? read? contention? dirty reads? What are the consequences of simply returning false in most cases? replace - I really don't understand where the three Object parameters come from, when this method is invoked, and what Hibernate expects to return, or how that return value is used. Any pointers would be appreciated. I've searched and read all I can find on the subject, but have not found much documentation at all explaining how these methods are used for mutable objects.

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  • Is it a missing implementation with JPA implementation of hibernate??

    - by Jegan
    Hi all, On my way in understanding the transaction-type attribute of persistence.xml, i came across an issue / discrepency between hibernate-core and JPA-hibernate which looks weird. I am not pretty sure whether it is a missing implementation with JPA of hibernate. Let me post the comparison between the outcome of JPA implementation and the hibernate implementation of the same concept. Environment Eclipse 3.5.1 JSE v1.6.0_05 Hibernate v3.2.3 [for hibernate core] Hibernate-EntityManger v3.4.0 [for JPA] MySQL DB v5.0 Issue 1.Hibernate core package com.expt.hibernate.core; import java.io.Serializable; public final class Student implements Serializable { private int studId; private String studName; private String studEmailId; public Student(final String studName, final String studEmailId) { this.studName = studName; this.studEmailId = studEmailId; } public int getStudId() { return this.studId; } public String getStudName() { return this.studName; } public String getStudEmailId() { return this.studEmailId; } private void setStudId(int studId) { this.studId = studId; } private void setStudName(String studName) { this.studName = stuName; } private void setStudEmailId(int studEmailId) { this.studEmailId = studEmailId; } } 2. JPA implementaion of Hibernate package com.expt.hibernate.jpa; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; @Entity @Table(name = "Student_Info") public final class Student implements Serializable { @Id @GeneratedValue @Column(name = "STUD_ID", length = 5) private int studId; @Column(name = "STUD_NAME", nullable = false, length = 25) private String studName; @Column(name = "STUD_EMAIL", nullable = true, length = 30) private String studEmailId; public Student(final String studName, final String studEmailId) { this.studName = studName; this.studEmailId = studEmailId; } public int getStudId() { return this.studId; } public String getStudName() { return this.studName; } public String getStudEmailId() { return this.studEmailId; } } Also, I have provided the DB configuration properties in the associated hibernate-cfg.xml [in case of hibernate core] and persistence.xml [in case of JPA (hibernate entity manager)]. create a driver and perform add a student and query for the list of students and print their details. Then the issue comes when you run the driver program. Hibernate core - output Exception in thread "main" org.hibernate.InstantiationException: No default constructor for entity: com.expt.hibernate.core.Student at org.hibernate.tuple.PojoInstantiator.instantiate(PojoInstantiator.java:84) at org.hibernate.tuple.PojoInstantiator.instantiate(PojoInstantiator.java:100) at org.hibernate.tuple.entity.AbstractEntityTuplizer.instantiate(AbstractEntityTuplizer.java:351) at org.hibernate.persister.entity.AbstractEntityPersister.instantiate(AbstractEntityPersister.java:3604) .... .... This exception is flashed when the driver is executed for the first time itself. JPA Hibernate - output First execution of the driver on a fresh DB provided the following output. DEBUG SQL:111 - insert into student.Student_Info (STUD_EMAIL, STUD_NAME) values (?, ?) 17:38:24,229 DEBUG SQL:111 - select student0_.STUD_ID as STUD1_0_, student0_.STUD_EMAIL as STUD2_0_, student0_.STUD_NAME as STUD3_0_ from student.Student_Info student0_ student list size == 1 1 || Jegan || [email protected] second execution of the driver provided the following output. DEBUG SQL:111 - insert into student.Student_Info (STUD_EMAIL, STUD_NAME) values (?, ?) 17:40:25,254 DEBUG SQL:111 - select student0_.STUD_ID as STUD1_0_, student0_.STUD_EMAIL as STUD2_0_, student0_.STUD_NAME as STUD3_0_ from student.Student_Info student0_ Exception in thread "main" javax.persistence.PersistenceException: org.hibernate.InstantiationException: No default constructor for entity: com.expt.hibernate.jpa.Student at org.hibernate.ejb.AbstractEntityManagerImpl.throwPersistenceException(AbstractEntityManagerImpl.java:614) at org.hibernate.ejb.QueryImpl.getResultList(QueryImpl.java:76) at driver.StudentDriver.main(StudentDriver.java:43) Caused by: org.hibernate.InstantiationException: No default constructor for entity: com.expt.hibernate.jpa.Student .... .... Could anyone please let me know if you have encountered this sort of inconsistency? Also, could anyone please let me know if the issue is a missing implementation with JPA-Hibernate? ~ Jegan

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  • Kohana PHP - Multiple apps with shared model

    - by Josamoto
    I'm using Kohana 3 to create a website that has two applications, an admin application and the actual site frontend. I have separated my folders to have the two applications separated, so the hierarchy looks as follows: /applications /admin /classes /controller /... /site /classes /controller /.... My question is, how I need to go about creating a shared /model folder. Essentially, both the admin and site itself operates on the same data, so the database layer and business logic remains more or less the same. So to me, it makes sense to have a single model folder, sitting outside of the two application folders. Is it possible to achieve the following hierarchy: /applications /model --> Where model sits in a neatly generic location, accessible to all applications /admin /classes /controller /... /site /classes /controller /.... Thanks in advance!

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  • JPA Secondary Table Issue

    - by Smithers
    I have a three tables: User, Course, and Test. Course has a User foreign key and Test has a Course foreign key. I am having trouble mapping the Test collection for each User since I need an intermediary step from User - Course - Test. I am trying to use a SecondaryTable since the User key for the Test is its associated Course row. Am I on the right track using SecondaryTable or is there a way to use a JoinTable without the inverseJoinColumn?

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