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  • SELECT TOP 1

    - by Derek Dieter
    There are many good uses of the SELECT TOP 1 method of querying. Essentially, the select top 1 method is used to find the min or max record for a particular value. There is some debate as to whether this is the ‘correct’ method of querying, however it should be known that this [...]

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  • Microsoft To Discontinue 'Select' Licensing

    Microsoft will no longer sell its Select software licensing after July 1, 2011, with Select Plus taking its place....Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • NVIDIA sort sa version 5 de CUDA, simplification de la programmation sur la plateforme de calcul parallèle la plus omniprésente

    NVIDIA sort sa version 5 de CUDA Simplification de la programmation sur la plateforme de calcul parallèle la plus omniprésente NVIDIA a sorti aujourd'hui la version de pré-production NVIDIA CUDA 5, une nouvelle version de la plateforme de calcul parallèle et du modèle de programmation les plus omniprésents, destinée à accélérer les applications scientifiques et d'ingénierie sur les processeurs graphiques. Elle est téléchargeable gratuitement à partir de la zone Développeurs du site Web NVIDIA. Avec plus de 1,5 millions de téléchargements et la prise en charge de plus de 180 applications d'ingénierie, scientifiques et commerciale...

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  • old kernel uninstall select video drivers

    - by Zero
    On synaptic selected my old kernel to uninstall: linux-generic linux-headers-3.2.0-31-generic linux-image-3.2.0-31-generic linux-image-3.2.0-33-generic linux-image-generic But if i select to uninstall linux-headers-3.2.0-33-generic it select my display drivers and after that wanna install pae kernel. It's possible delete header files without loosing my video drivers and without installing pae kernel ?

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  • Doit-on apprendre aux plus jeunes à programmer ? Un journaliste trouve cette idée ridicule

    Doit-on apprendre aux plus jeunes à programmer ? Un journaliste trouve cette idée ridiculeEst ce vraiment une bonne idée que d'avoir à enseigner la programmation aux plus jeunes ? Chacun a sa propre opinion sur la question. Pour le Royaume-Uni, la réponse est affirmative. Vu les nombreuses opportunités qu'offre l'informatique dans le domaine de l'emploi, pour le gouvernement Britannique il est impératif de familiariser les plus jeunes à l'informatique le plus tôt possible.Pour Willard Foxton journaliste...

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  • Why does this SELECT ... JOIN statement return no results?

    - by Stephen
    I have two tables: 1. tableA is a list of records with many columns. There is a timestamp column called "created" 2. tableB is used to track users in my application that have locked a record in tableA for review. It consists of four columns: id, user_id, record_id, and another timestamp collumn. I'm trying to select up to 10 records from tableA that have not been locked by for review by anyone in tableB (I'm also filtering in the WHERE clause by a few other columns from tableA like record status). Here's what I've come up with so far: SELECT tableA.* FROM tableA LEFT OUTER JOIN tableB ON tableA.id = tableB.record_id WHERE tableB.id = NULL AND tableA.status = 'new' AND tableA.project != 'someproject' AND tableA.created BETWEEN '1999-01-01 00:00:00' AND '2010-05-06 23:59:59' ORDER BY tableA.created ASC LIMIT 0, 10; There are currently a few thousand records in tableA and zero records in tableB. There are definitely records that fall between those timestamps, and I've verified this with a simple SELECT * FROM tableA WHERE created BETWEEN '1999-01-01 00:00:00' AND '2010-05-06 23:59:59' The first statement above returns zero rows, and the second one returns over 2,000 rows.

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  • SQL SERVER – Order By Numeric Values Formatted as String

    - by pinaldave
    When I was writing this blog post I had a hard time to come up with the title of the blog post so I did my best to come up with one. Here is the reason why? I wrote a blog post earlier SQL SERVER – Find First Non-Numeric Character from String. One of the questions was that how that blog can be useful in real life scenario. This blog post is the answer to that question. Let us first see a problem. We have a table which has a column containing alphanumeric data. The data always has first as an integer and later part as a string. The business need is to order the data based on the first part of the alphanumeric data which is an integer. Now the problem is that no matter how we use ORDER BY the result is not produced as expected. Let us understand this with example. Prepare a sample data: -- How to find first non numberic character USE tempdb GO CREATE TABLE MyTable (ID INT, Col1 VARCHAR(100)) GO INSERT INTO MyTable (ID, Col1) SELECT 1, '1one' UNION ALL SELECT 2, '11eleven' UNION ALL SELECT 3, '2two' UNION ALL SELECT 4, '22twentytwo' UNION ALL SELECT 5, '111oneeleven' GO -- Select Data SELECT * FROM MyTable GO The above query will give following result set. Now let us use ORDER BY COL1 and observe the result along with Original SELECT. -- Select Data SELECT * FROM MyTable GO -- Select Data SELECT * FROM MyTable ORDER BY Col1 GO The result of the table is not as per expected. We need the result in following format. Here is the good example of how we can use PATINDEX. -- Use of PATINDEX SELECT ID, LEFT(Col1,PATINDEX('%[^0-9]%',Col1)-1) 'Numeric Character', Col1 'Original Character' FROM MyTable ORDER BY LEFT(Col1,PATINDEX('%[^0-9]%',Col1)-1) GO We can use PATINDEX to identify the length of the digit part in the alphanumeric string (Remember: Our string has a first part as an int always. It will not work in any other scenario). Now you can use the LEFT function to extract the INT portion from the alphanumeric string and order the data according to it. You can easily clean up the script by dropping following table. DROP TABLE MyTable GO Here is the complete script so you can easily refer it. -- How to find first non numberic character USE tempdb GO CREATE TABLE MyTable (ID INT, Col1 VARCHAR(100)) GO INSERT INTO MyTable (ID, Col1) SELECT 1, '1one' UNION ALL SELECT 2, '11eleven' UNION ALL SELECT 3, '2two' UNION ALL SELECT 4, '22twentytwo' UNION ALL SELECT 5, '111oneeleven' GO -- Select Data SELECT * FROM MyTable GO -- Select Data SELECT * FROM MyTable ORDER BY Col1 GO -- Use of PATINDEX SELECT ID, Col1 'Original Character' FROM MyTable ORDER BY LEFT(Col1,PATINDEX('%[^0-9]%',Col1)-1) GO DROP TABLE MyTable GO Well, isn’t it an interesting solution. Any suggestion for better solution? Additionally any suggestion for changing the title of this blog post? Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL String, SQL Tips and Tricks, T SQL, Technology

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  • More useful Sql Server Serivce Broker Queries

    - by ChrisD
    SELECT 'Checking Broker Service Status...' IF (select Top 1 is_broker_enabled from sys.databases where name = 'NWMESSAGE')=1     SELECT ' Broker Service IS Enabled'  -- Should return a 1. ELSE     SELECT '** Broker Service IS DISABLED ***' /* If Is_Broker_enabled returns 0, uncomment and run this code ALTER DATABASE NWMESSAGE SET SINGLE_USER WITH ROLLBACK IMMEDIATE GO Alter Database NWMESSAGE Set enable_broker GO ALTER DATABASE NWDataChannel SET MULTI_USER GO */ SELECT 'Checking For Disabled Queues....' -- ensure the queues are enabled --  0 indicates the queue is disabled. Select '** Receive Queue Disabled: '+name from sys.service_queues where is_receive_enabled = 0 --select [name], is_receive_enabled from sys.service_queues; /*If the queue is disabled, to enable it alter queue QUEUENAME with status=on; – replace QUEUENAME with the name of your queue */ -- Get General information about the queues --select * from sys.service_queues -- Get the message counts in each queue SELECT 'Checking Message Count for each Queue...' select q.name, p.rows from sys.objects as o join sys.partitions as p on p.object_id = o.object_id join sys.objects as q on o.parent_object_id = q.object_id join sys.service_queues sq on sq.name = q.name where p.index_id = 1 -- Ensure all the queue activiation sprocs are present SELECT 'Checking for Activation Stored Procedures....' SELECT  '** Missing Procedure:  '+q.name  From sys.service_queues q Where NOT Exists(Select * from sysobjects where xtype='p' and name='activation_'+q.name) and q.activation_procedure is not null DECLARE @sprocs Table (Name Varchar(2000)) Insert into @sprocs Values ('Echo') Insert into @sprocs Values ('HTTP_POST') Insert into @sprocs Values ('InitializeRecipients') Insert into @sprocs Values ('sp_EnableRecipient') Insert into @sprocs Values ('sp_ProcessReceivedMessage') Insert into @sprocs Values ('sp_SendXmlMessage') SELECT 'Checking for required stored procedures...' SELECT  '** Missing Procedure:  '+s.name  From @sprocs s Where NOT Exists(Select * from sysobjects where xtype='p' and name=s.name) GO -- Check the services Select 'Checking Recipient Message Services...' Select '** Missing Message Service:' + r.RecipientName +'MessageService' From Recipient r Where not exists (Select * from sys.services s where  s.name  COLLATE SQL_Latin1_General_CP1_CI_AS= r.RecipientName+'MessageService') DECLARE @svcs Table (Name Varchar(2000)) Insert into @svcs Values ('XmlMessageSendingService') SELECT  '** Missing Service:  '+s.name  From @svcs s Where NOT Exists(Select * from sys.services where name=s.name COLLATE SQL_Latin1_General_CP1_CI_AS) GO /*** To Test a message send Run: sp_SendXmlMessage  'TSQLTEST', 'CommerceEngine','<Root><Text>Test</Text></Root>' */ Select CAST(message_body as XML) as xml, * From XmlMessageSendingQueue /*** clean out all queues declare @handle uniqueidentifier declare conv cursor for   select conversation_handle from sys.conversation_endpoints open conv fetch next from conv into @handle while @@FETCH_STATUS = 0 Begin    END Conversation @handle with cleanup    fetch next from conv into @handle End close conv deallocate conv ***********************

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  • Multiple JOIN and SELECT Statements from eight tables

    - by user1486004
    I am trying to make an SQL statement that takes eight different numbers and searches eight different tables from one database for the corresponding value. I keep getting invalid syntax, but I can't figure out why. Here is my code: SELECT cable_length.ID, drawing.ID, optional.ID, output_type.ID, pressure_range.ID, pressure_type.ID, series.ID, termination.ID FROM ( SELECT value AS cable_length FROM A1 WHERE A1.id = %s JOIN SELECT value AS drawing FROM A2 WHERE A2.id = %s, JOIN SELECT value AS optional FROM A3 WHERE A3.id = %s, JOIN SELECT value AS output_type FROM A4 WHERE A4.id = %s, JOIN SELECT value AS pressure_range FROM A5 WHERE A5.id = %s, JOIN SELECT value AS pressure_type FROM A6 WHERE A6.id = %s, JOIN SELECT value AS series FROM A7 WHERE A7.id = %s, JOIN SELECT value AS termination FROM A8 WHERE A8.id = %s ); The %s will be changed to numbers only. The column name in each database is "ID" and "Value". I want to search by "ID" and return "Value". Any help is greatly appreciated.

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  • view to select specific period or latest when null

    - by edosoft
    Hi I have a product table which simplifies to this: create table product(id int primary key identity, productid int, year int, quarter int, price money) and some sample data: insert into product select 11, 2010, 1, 1.11 insert into product select 11, 2010, 2, 2.11 insert into product select 11, 2010, 3, 3.11 insert into product select 12, 2010, 1, 1.12 insert into product select 12, 2010, 2, 2.12 insert into product select 13, 2010, 1, 1.13 Prices are can be changed each quarter, but not all products get a new price each quarter. Now I could duplicate the data each quarter, keeping the price the same, but I'd rather use a view. How can I create a view that can be used to return prices for (for example) quarter 2? I've written this to return the current (=latest) price: CREATE VIEW vwCurrentPrices AS SELECT * FROM ( SELECT *, ROW_NUMBER() OVER (PARTITION BY productid ORDER BY year DESC, quarter DESC) AS Ranking FROM product ) p WHERE p.Ranking = 1 I'd like to create a view so I can use queries like select * from vwProduct where quarter = 2

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  • jquery remove selected element and append to another

    - by KnockKnockWhosThere
    I'm trying to re-append a "removed option" to the appropriate select option menu. I have three select boxes: "Categories", "Variables", and "Target". "Categories" is a chained select, so when the user selects an option from it, the "Variables" select box is populated with options specific to the selected categories option. When the user chooses an option from the "Variables" select box, it's appended to the "Target" select box. I have a "remove selected" feature so that if a user "removes" a selected element from the "Target" select box, it's removed from "Target" and put back into the pool of "Variables" options. The problem I'm having is that it appends the option to the "Variables" items indiscriminately. That is, if the selected category is "Age" the "Variables" options all have a class of "age". But, if the removed option is an "income" item, it will display in the "Age Variables" option list. Here's the HTML markup: <select multiple="" id="categories" name="categories[]"> <option class="category" value="income">income</option> <option class="category" value="gender">gender</option> <option class="category" value="age">age</option> </select> <select multiple="multiple" id="variables" name="variables[]"> <option class="income" value="10">$90,000 - $99,999</option> <option class="income" value="11">$100,000 - $124,999</option> <option class="income" value="12">$125,000 - $149,999</option> <option class="income" value="13">Greater than $149,999</option> <option class="gender" value="14">Male</option> <option class="gender" value="15">Female</option> <option class="gender" value="16">Ungendered</option> <option class="age" value="17">Ages 18-24</option> <option class="age" value="18">Ages 25-34</option> <option class="age" value="19">Ages 35-44</option> </select> <select height="60" multiple="multiple" id="target" name="target[]"> </select> And, here's the js: /* This determines what options are display in the "Variables" select box */ var cat = $('#categories'); var el = $('#variables'); $('#categories option').click(function() { var class = $(this).val(); $('#variables option').each(function() { if($(this).hasClass(class)) { $(this).show(); } else { $(this).hide(); } }); }); /* This adds the option to the target select box if the user clicks "add" */ $('#add').click(function() { return !$('#variables option:selected').appendTo('#target'); }); /* This is the remove function in its current form, but doesn't append correctly */ $('#remove').click(function() { $('#target option:selected').each(function() { var class = $(this).attr('class'); if($('#variables option').hasClass(class)) { $(this).appendTo('#variables'); sortList('variables'); } }); });

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  • SQL SERVER – SELECT TOP Shortcut in SQL Server Management Studio (SSMS)

    - by pinaldave
    This is tool is pretty old, yet always comes as a handy tip. I had a great trip at TechEd in India. And, during one of my presentations, I was asked if there are any shortcuts to SELECT only TOP 100 records from SSMS. I immediately told him that if he explores the table in SSMS, he can just right click on it and SELECT TOP 1000 records. If he wanted only 100 records, then he could edit that 1000 to 100 by means of going to Options. Go to Options, then hover the mouse over the SQL Server Object Explorer, then proceed to Commands. Afterwards, change the Value for Select Top <n> Audit Records. After narrating the steps, he told me that he was not looking for the right click option; rather he was asking if there is any kind of keyboard shortcut for convenience’s sake. Actually, a keyboard shortcut is also possible. SQL Server Management Studio (SSMS) lets you configure the settings you want using a shortcut. Here is how you can do it. Go to Options, then to Environment. Proceed to Keyboard, and from there, configure your T-SQL with the desired keyword. Now, open SSMS New Query Window, and then click and type in any table name.  After that, just hit the shortcut you just made earlier. Doing this should display TOP 100 records in the Result window. I am sure this trick is quite old, but it is still helpful to many. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Add-On, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • jQuery "Auto Post-back" Select/Drop-Down List

    - by Doug Lampe
    I have one common piece of jQuery code which I use to submit a form any time the selection changes on a drop-down list (HTML select tag).  This is similar to setting AutoPostBack = true in ASP.Net.  I use a single CSS class (autoSubmit) to annotate that I want the drop-down to force the form to submit on change so the HTML looks something like this: <select id="myAutoSubmitDropDown" name="myAutoSubmitDropDown" class="autoSubmit">     <option value="1">Option 1</option>     <option value="2">Option 2</option> </select> Then the following jQuery will look for any element with this CSS class and submit the parent form when the value is changed: function wireUpAutoSubmit() {   $(".autoSubmit").each(function (index) {     $(this).change(function () {       $(this).closest('form').submit();     })   }); } I put this in a separate function since I might need to wire this up explicitly after an ajax call.  Therefore I use the following code to set this method to fire when the DOM is loaded: $(document).ready(function () {   wireUpAutoSubmit(); });

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  • How-to create a select one choice listing common time zones

    - by frank.nimphius
    Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} ADF Faces provides an option to query a list of common timezones for display in a Select One Choice component. The EL expression for this is #{af:getCommonTimeZoneSelectItems()}. To use this expression in a Single Select One Choice component, drag and drop the component from the Oracle JDeveloper Component Palette into a JSF page.  In the opened dialog, copy the expression into the Value property below the Bind to list (select items) header. <af:selectOneChoice label="TimeZones" id="soc1">  <f:selectItems value="#{af:getCommonTimeZoneSelectItems()}"                          id="si1"/></af:selectOneChoice>

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  • Select (loop) or command not working in shell-script

    - by user208098
    I've been tinkering with Linux and Unix for years but still a novice in my mind and recently find myself trying to be more pro with it as I work in IT. So with that notion I'm studying shell scripting. I've hit a snag in ubuntu using the latest version 13.10 Saucy. When I use the select command in a sh script it doesn't work, depending on how I format the command it will either return Unexpected "do" or Unexpected "done". See the following two examples: This section of code produces an unexpected "do" error: #/bin/bash PS3='Please enter your choice' select opt in option1 option2 option3 quit do case $opt in "option1") echo "you chose choice 1" ;; "option2") echo "you chose choice 2" ;; "option3") echo "you chose choice 3" ;; "quit") break ;; *) echo invalid option ;; esac done This section of code produces an unexpected "done" error. #/bin/bash PS3='Please enter your choice' select opt in option1 option2 option3 quit ; do case $opt in "Option1") echo "you chose choice 1" ;; "Option2") echo "you chose choice 2" ;; "Option3") echo "you chose choice 3" ;; "quit") break ;; *) echo invalid option ;; esac done When I enter these parameters into the command line interactively or manually I get the desired result which is a list of choices to choose from. However when executed from a script I get the before mentioned errors. Also a side note I have tried this in Fedora as a script and it worked perfectly so my question is why isn't it working in Ubuntu, is this a difference between RHL and Debian? Or is it a bug in the latest version of Ubuntu? Thanks in advance for any help! KG

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  • how to iterate through multiple select options with jquery

    - by amir
    I was just wondering if it's possible to go through multiple select options and get their values and text(if one is selected get the value and text, if 2 is selected get both of their values and text and so on) I have 15 select boxes in one page? any help would be appreciated. <form> <select class="select" name="select3" id="select3"> <option value="0">0</option> <option value="1.99">1</option> <option value="1.99">2</option> <option value="1.99">3</option> <option value="1.99">4</option> <option value="1.99">5</option> <option value="1.99">6</option> <option value="1.99">7</option> <option value="1.99">8</option> </select> </form> <form> <select class="select" name="select" id="select"> <option value="0">0</option> <option value="1.99">1</option> <option value="1.99">2</option> <option value="1.99">3</option> <option value="1.99">4</option> <option value="1.99">5</option> <option value="1.99">6</option> <option value="1.99">7</option> <option value="1.99">8</option> </select> </form> all the select options have the same class. thanks

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  • Javascript: how to document.print option value in Select block?

    - by HH
    The below returns [object HTMLOptionElement] while I try to return the value. document.write(document.getElementById("allSelect").options[0]).value; by value, I mean the thing called value there (there is a form around it but not relevant now): <select name="allSelect" id="allSelect" size=3> <option value="1"selected">1</option> <option value="2">2</option> <option value="3">3</option> </select> How can I return the value of an option?

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  • [SQL] How to SELECT TOP 5 and then the following 5?

    - by Crays
    Hi guys, as the comments always have it, you can select to show the top 5 comments (which i know how) and if there is more than 5, you can click a link and it will show the following 5 comments. The problem is that i don't know how the code should be for it to show the next 5. Better idea of what i'm saying Let's say i have 10 comments, i use SELECT * FROM news ORDER BY ID DESC LIMIT 5 that will show the TOP 5 comments say, the comments with ID 10,9,8,7,6 but what if i want the comments with ID 5,4,3,2,1 ?

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  • How should I build a privacy drop-down (select) menu?

    - by animuson
    I'm trying to build something similar to Facebook's privacy selection menu, except without the 'custom' option. It will only list a few options such as 'show to all', 'show to friends only', or 'completely hidden'. Right now I'm thinking of using simple JavaScript to change a hidden input field to the new value they click on, so if they clicked on the division for 'show to friends only' it would change the corresponding field, say 'email_privacy', to 1. Is there a better way to do this or am I pretty much on track? P.S. I am not planning on using a select element, I was planning on building a custom drop-down menu using CSS since select elements are so highly non-customizable. I'm doing it this way to save space, rather than having this massive selection menu at the right which takes up a bunch of space. Note: I'm not really interested in using jQuery, that's just extra libraries and crap that I don't want to load. I can do it in JavaScript just as easily so I might as well use that.

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  • Open Select using Javascript/jQuery?

    - by Newbie
    Hello! Is there a way to open a select box using Javascript (and jQuery)? <select style="width:150px;"> <option value="1">1</option> <option value="2">Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nunc arcu nunc, rhoncus ac dignissim at, rhoncus ac tellus.</option> <option value="3">3</option> </select> I have to open my select, cause of ie bug. All versions of IE (6,7,8) cut my options. As far as I know, there is no css bugfix for this. At the moment I try to do the following: var original_width = 0; var selected_val = false; if (jQuery.browser.msie) { $('select').click(function(){ if (selected_val == false){ if(original_width == 0) original_width = $(this).width(); $(this).css({ 'position' : 'absolute', 'width' : 'auto' }); }else{ $(this).css({ 'position' : 'relative', 'width' : original_width }); selected_val = false; } }); $('select').blur(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); }); $('select').blur(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); }); $('select').change(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); }); $('select option').click(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); selected_val = true; }); } But clicking on my select the first time will change the width of the select but I have to click again to open it.

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  • MySQL SELECT combining 3 SELECTs INTO 1

    - by Martin Tóth
    Consider following tables in MySQL database: entries: creator_id INT entry TEXT is_expired BOOL other: creator_id INT entry TEXT userdata: creator_id INT name VARCHAR etc... In entries and other, there can be multiple entries by 1 creator. userdata table is read only for me (placed in other database). I'd like to achieve a following SELECT result: +------------+---------+---------+-------+ | creator_id | entries | expired | other | +------------+---------+---------+-------+ | 10951 | 59 | 55 | 39 | | 70887 | 41 | 34 | 108 | | 88309 | 38 | 20 | 102 | | 94732 | 0 | 0 | 86 | ... where entries is equal to SELECT COUNT(entry) FROM entries GROUP BY creator_id, expired is equal to SELECT COUNT(entry) FROM entries WHERE is_expired = 0 GROUP BY creator_id and other is equal to SELECT COUNT(entry) FROM other GROUP BY creator_id. I need this structure because after doing this SELECT, I need to look for user data in the "userdata" table, which I planned to do with INNER JOIN and select desired columns. I solved this problem with selecting "NULL" into column which does not apply for given SELECT: SELECT creator_id, COUNT(any_entry) as entries, COUNT(expired_entry) as expired, COUNT(other_entry) as other FROM ( SELECT creator_id, entry AS any_entry, NULL AS expired_entry, NULL AS other_enry FROM entries UNION SELECT creator_id, NULL AS any_entry, entry AS expired_entry, NULL AS other_enry FROM entries WHERE is_expired = 1 UNION SELECT creator_id, NULL AS any_entry, NULL AS expired_entry, entry AS other_enry FROM other ) AS tTemp GROUP BY creator_id ORDER BY entries DESC, expired DESC, other DESC ; I've left out the INNER JOIN and selecting other columns from userdata table on purpose (my question being about combining 3 SELECTs into 1). Is my idea valid? = Am I trying to use the right "construction" for this? Are these kind of SELECTs possible without creating an "empty" column? (some kind of JOIN) Should I do it "outside the DB": make 3 SELECTs, make some order in it (let's say python lists/dicts) and then do the additional SELECTs for userdata? Solution for a similar question does not return rows where entries and expired are 0. Thank you for your time.

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  • SQL Express vs SQL Plus

    - by Bruce227
    Hi, I'm wondering what the difference is if any between SQL Express and SQL Plus. I know SQL Plus is used with Oracle but not sure if SQL Plus is a modification of SQL Express or a totally different installation. Thanks

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  • PostgreSQL: return select count(*) from old_ids;

    - by Alexander Farber
    Hello, please help me with 1 more PL/pgSQL question. I have a PHP-script run as daily cronjob and deleting old records from 1 main table and few further tables referencing its "id" column: create or replace function quincytrack_clean() returns integer as $BODY$ begin create temp table old_ids (id varchar(20)) on commit drop; insert into old_ids select id from quincytrack where age(QDATETIME) > interval '30 days'; delete from hide_id where id in (select id from old_ids); delete from related_mks where id in (select id from old_ids); delete from related_cl where id in (select id from old_ids); delete from related_comment where id in (select id from old_ids); delete from quincytrack where id in (select id from old_ids); return select count(*) from old_ids; end; $BODY$ language plpgsql; And here is how I call it from the PHP script: $sth = $pg->prepare('select quincytrack_clean()'); $sth->execute(); if ($row = $sth->fetch(PDO::FETCH_ASSOC)) printf("removed %u old rows\n", $row['count']); Why do I get the following error? SQLSTATE[42601]: Syntax error: 7 ERROR: syntax error at or near "select" at character 9 QUERY: SELECT select count(*) from old_ids CONTEXT: SQL statement in PL/PgSQL function "quincytrack_clean" near line 23 Thank you! Alex

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  • How to coerce type of ActiveRecord attribute returned by :select phrase on joined table?

    - by tribalvibes
    Having trouble with AR 2.3.5, e.g.: users = User.all( :select => "u.id, c.user_id", :from => "users u, connections c", :conditions => ... ) Returns, e.g.: => [#<User id: 1000>] >> users.first.attributes => {"id"=>1000, "user_id"=>"1000"} Note that AR returns the id of the model searched as numeric but the selected user_id of the joined model as a String, although both are int(11) in the database schema. How could I better form this type of query to select columns of tables backing multiple models and retrieving their natural type rather than String ? Seems like AR is punting on this somewhere. How could I coerce the returned types at AR load time and not have to tack .to_i (etc.) onto every post-hoc access?

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  • How do I select from a stored procedure in Sybase?

    - by Nick Fortescue
    My DBA has constructed me a stored procedure in a Sybase database, for which I don't have the definition. If I run it, it returns a resultset with a set of columns and values. I would like to SELECT further to reduce the rows in the result set. Is this possible? From this question it seems like I could insert the results into a temporary table, but I'm not sure I've got permissions to do this. Is there any way I can SELECT certain rows, or if not, can someone give me example code for simulating with a temporary table?

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