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  • What is your favorite way to read XML files?

    - by stacker
    Let's take this xml structure as example: <?xml version="1.0" encoding="utf-8"?> <Configuration-content> <XFile Name="file name 1" /> <XFile Name="name2" /> <XFile Name="name3" /> <XFile Name="name4" /> </Configuration-content> C# interface to implement: public class Configuration { public XFile[] Files { get; set; } } public interface IConfigurationRipository { Configuration Get(); void Save(Configuration entity); } I wonder what's the best way to do that. The task is to implement IConfigurationRipository using your favorite approach.

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  • What is the correct method to load an XML file and re-write it as a CVS? (C# Only)

    - by codesmack
    Hello, I have a XML file that I want to load into an unknown object type. (I say unknown object type because I am not sure what direction to go) Once I have the data loaded I need to do some processing on certain elements that are now loaded into the new object. For sake of example, we can say that the xml file is full of elements named and within the car element I need to process the element. Then once this is all done I need to write the file as a CSV file. I would like to do this is the most direct way possible. (The less code the better) I am using VS 2008 C# Thank you, CodeSmack

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  • What is the correct method to load an XML file and re-write it as a CSV?

    - by codesmack
    I have a XML file that I want to load into an unknown object type. (I say unknown object type because I am not sure what direction to go) Once I have the data loaded I need to do some processing on certain elements that are now loaded into the new object. For sake of example, we can say that the xml file is full of elements named <car> and within the car element I need to process the <mileage> element. Then once this is all done I need to write the file as a CSV file. I would like to do this is the most direct way possible. (The less code the better) I am using VS 2008 C#

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  • Do I have to worry about escaping XML reserved characters before I return a DataContract object from

    - by Brett Widmeier
    Hi, I am pretty inexperienced with WCF. I have a DataContract that implements the IExtensibleDataObject interface. Some of the members of this object are populated from freetext input and could contain XML reserved characters ('', for example). I imagine that I get escaping of these characters for free with WCF, but I have been looking around and could not find anything commenting on this one way or another. Is this the case? I have set my service to log the messages that it sends and receives for viewing in the Trace Viewer. Part of a message that my service returns looks like this: <sInstructions>"></sInstructions> Now, I have a couple questions about this. 1) Is it actually transmitting "&gt; and just showing it in a more readable form in the trace viewer? 2) If it is actually is transmitting ">, is this legal XML?

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  • Using variable for tag in getElementsByTagName() for PHP and XML?

    - by Jared
    See my PHP: $file = "routingConfig.xml"; global $doc; $doc = new DOMDocument(); $doc->load( $file ); $ElTag = "Route"; $tag = $doc->getElementsByTagName($ElTag); XML is: <Routes> <Route></Route> <Route></Route> <Routes> Error returned is: Fatal error: Call to a member function getElementsByTagName() on a non-object I'm not sure how to do this?

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  • What is the correct method to load an XML file and re-write it as a CSV? (C# Only)

    - by codesmack
    I have a XML file that I want to load into an unknown object type. (I say unknown object type because I am not sure what direction to go) Once I have the data loaded I need to do some processing on certain elements that are now loaded into the new object. For sake of example, we can say that the xml file is full of elements named <car> and within the car element I need to process the <mileage> element. Then once this is all done I need to write the file as a CSV file. I would like to do this is the most direct way possible. (The less code the better) I am using VS 2008 C#

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  • Is it possible to define XML schemata with node names specified via regular expressions?

    - by MartyIX
    Hello, I know it is probably a question against XML philosophy but still is it possible to define schemata for XML like this: <Root> <arbitrary-name-of-node> <Name></Name> <Position></Position> <!-- ... --> </arbitrary-name-of-node> <arbitrary-name-of-node> <Name></Name> <Position></Position> <!-- ... --> </arbitrary-name-of-node> </Root> where arbitrary-name-of-node matches regular expression [a-zA-Z0-9]? Thanks for an answer!

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  • SQL SERVER – Understanding XML – Contest Win Joes 2 Pros Combo (USD 198) – Day 5 of 5

    - by pinaldave
    August 2011 we ran a contest where every day we give away one book for an entire month. The contest had extreme success. Lots of people participated and lots of give away. I have received lots of questions if we are doing something similar this month. Absolutely, instead of running a contest a month long we are doing something more interesting. We are giving away USD 198 worth gift every day for this week. We are giving away Joes 2 Pros 5 Volumes (BOOK) SQL 2008 Development Certification Training Kit every day. One copy in India and One in USA. Total 2 of the giveaway (worth USD 198). All the gifts are sponsored from the Koenig Training Solution and Joes 2 Pros. The books are available here Amazon | Flipkart | Indiaplaza How to Win: Read the Question Read the Hints Answer the Quiz in Contact Form in following format Question Answer Name of the country (The contest is open for USA and India residents only) 2 Winners will be randomly selected announced on August 20th. Question of the Day: Is following XML a well formed XML Document? <?xml version=”1.0″?> <address> <firstname>Pinal</firstname> <lastname>Dave</lastname> <title>Founder</title> <company>SQLAuthority.com</company> </address> a) Yes b) No c) I do not know Query Hints: BIG HINT POST A common observation by people seeing an XML file for the first time is that it looks like just a bunch of data inside a text file. XML files are text-based documents, which makes them easy to read.  All of the data is literally spelled out in the document and relies on a just a few characters (<, >, =) to convey relationships and structure of the data.  XML files can be used by any commonly available text editor, like Notepad. Much like a book’s Table of Contents, your first glance at well-formed XML will tell you the subject matter of the data and its general structure. Hints appearing within the data help you to quickly identify the main theme (similar to book’s subject), its headers (similar to chapter titles or sections of a book), data elements (similar to a book’s characters or chief topics), and so forth. We’ll learn to recognize and use the structural “hints,” which are XML’s markup components (e.g., XML tags, root elements). The XML Raw and Auto modes are great for displaying data as all attributes or all elements – but not both at once. If you want your XML stream to have some of its data shown in attributes and some shown as elements, then you can use the XML Path mode. If you are using an XML Path stream, then by default all values will be shown as elements. However, it is possible to pick one or more elements to be shown with an attribute(s) as well. Additional Hints: I have previously discussed various concepts from SQL Server Joes 2 Pros Volume 5. SQL Joes 2 Pros Development Series – OpenXML Options SQL Joes 2 Pros Development Series – Preparing XML in Memory SQL Joes 2 Pros Development Series – Shredding XML SQL Joes 2 Pros Development Series – Using Root With Auto XML Mode SQL Joes 2 Pros Development Series – Using Root With Auto XML Mode SQL Joes 2 Pros Development Series – What is XML? SQL Joes 2 Pros Development Series – What is XML? – 2 Next Step: Answer the Quiz in Contact Form in following format Question - Answer Name of the country (The contest is open for USA and India) Bonus Winner Leave a comment with your favorite article from the “additional hints” section and you may be eligible for surprise gift. There is no country restriction for this Bonus Contest. Do mention why you liked it any particular blog post and I will announce the winner of the same along with the main contest. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Joes 2 Pros, PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Parsing XHTML results from Bing

    - by Nir
    Hello, i am trying to parse received search queries from bing search engines which are received in xhtml in java. I am using sax XmlReader to read the results but i keep on getting errors. here is my code-this one is for the hadler of the reader: import org.xml.sax.Attributes; import org.xml.sax.SAXException; import org.xml.sax.helpers.DefaultHandler; public class XHTMLHandler extends DefaultHandler{ public XHTMLHandler() { super(); } public void startDocument () { System.out.println("Start document"); } public void endDocument () { System.out.println("End document"); } public void startElement (String uri, String name,String qName, Attributes atts) { if ("".equals (uri)) System.out.println("Start element: " + qName); else System.out.println("Start element: {" + uri + "}" + name); } public void endElement (String uri, String name, String qName) { if ("".equals (uri)) System.out.println("End element: " + qName); else System.out.println("End element: {" + uri + "}" + name); } public void startPrefixMapping (String prefix, String uri) throws SAXException { } public void endPrefixMapping (String prefix) throws SAXException { } public void characters (char ch[], int start, int length) { System.out.print("Characters: \""); for (int i = start; i < start + length; i++) { switch (ch[i]) { case '\\': System.out.print("\\\\"); break; case '"': System.out.print("\\\""); break; case '\n': System.out.print("\\n"); break; case '\r': System.out.print("\\r"); break; case '\t': System.out.print("\\t"); break; default: System.out.print(ch[i]); break; } } System.out.print("\"\n"); } } and this is the program itself: import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStreamWriter; import java.net.HttpRetryException; import java.net.HttpURLConnection; import java.net.URL; import org.xml.sax.InputSource; import org.xml.sax.SAXException; import org.xml.sax.XMLReader; import org.xml.sax.helpers.XMLReaderFactory; public class Searching { private String m_urlBingSearch = "http://www.bing.com/search?q="; private HttpURLConnection m_httpCon; private OutputStreamWriter m_streamWriter; //private BufferedReader m_bufferReader; private URL m_serverAdress; private StringBuilder sb; private String m_line; private InputSource m_inputSrc; public Searching() { m_httpCon = null; m_streamWriter = null; //m_bufferReader = null; m_serverAdress = null; sb = null; m_line = new String(); } public void SearchBing(String searchPrms) throws SAXException,IOException { //set up connection sb = new StringBuilder(); sb.append(m_urlBingSearch); sb.append(searchPrms); m_serverAdress = new URL(sb.toString()); m_httpCon = (HttpURLConnection)m_serverAdress.openConnection(); m_httpCon.setRequestMethod("GET"); m_httpCon.setDoOutput(true); m_httpCon.setConnectTimeout(10000); m_httpCon.connect(); //m_streamWriter = new OutputStreamWriter(m_httpCon.getOutputStream()); //m_bufferReader = new BufferedReader(new InputStreamReader(m_httpCon.getInputStream())); XMLReader reader = XMLReaderFactory.createXMLReader(); XHTMLHandler handle = new XHTMLHandler(); reader.setContentHandler(handle); reader.setErrorHandler(handle); //reader.startPrefixMapping("html", "http://www.w3.org/1999/xhtml"); handle.startPrefixMapping("html", "http://www.w3.org/1999/xhtml"); m_inputSrc = new InputSource(m_httpCon.getInputStream()); reader.parse(m_inputSrc); m_httpCon.disconnect(); } public static void main(String [] args) throws SAXException,IOException { Searching s = new Searching(); s.SearchBing("beatles"); } } this is my error message: Exception in thread "main" java.io.IOException: Server returned HTTP response code: 503 for URL: http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLEntityManager.setupCurrentEntity(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLEntityManager.startEntity(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLEntityManager.startDTDEntity(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDTDScannerImpl.setInputSource(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$DTDDriver.dispatch(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$DTDDriver.next(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$PrologDriver.next(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source) at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source) at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source) at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(Unknown Source) at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(Unknown Source) at Searching.SearchBing(Searching.java:57) at Searching.main(Searching.java:65) can someone please help? i think it has something to do with dtd but i don't know hot to fix it

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  • How can I test a parser for a bespoke XML schema?

    - by Greg B
    I'm parsing a bespoke XML format into an object graph using .NET 4.0. My parser is using the System.XML namespace internally, I'm then interrogating the relevant properties of XmlNodes to create my object graph. I've got a first cut of the parser working on a basic input file and I want to put some unit tests around this before I progress on to more complex input files. Is there a pattern for how to test a parser such as this? When I started looking at this, my first move was to new up and XmlDocument, XmlNamespaceManager and create an XmlElement. But it occurs to me that this is quite lengthy and prone to human error. My parser is quite recursive as you can imagine and this might lead to testing the full system rather than the individual units (methods) of the system. So a second question might be What refactoring might make a recursive parser more testable?

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  • Xerces SAX parser ignore the xmlxs:xsi attribute as an attribute of an element

    - by user603301
    Hi, Using Xerces SAX parser I try to retrieve all elements and their attributes of this XML file: -------------- Begin XML file to parse ---------------- <?xml version="1.0" encoding="UTF-8"?> <invoice xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="my.xsd"> <parties> (...) -------------- End XML file to parse ---------------- When getting the attributes for the element 'invoice', Xerces++ does not insert the 'xmlns:xsi' attribute in the list of 'Attributes' for the element 'invoice'. However, the attribute 'xsi:noNamespaceSchemaLocation' is inserted in the list. Why? Is there a specific reason from an XML standard point of view ? Is there a way to configure Xerces++ SAX parser so that it inserts this attribute as well? (The documentation on setting the parser properties does not tell how). Thanks for your help.

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  • Parsing a text file with a fixed format in Java

    - by EugeneP
    Suppose I know a text file format, say, each line contains 4 fields like this: firstword secondword thirdword fourthword firstword2 secondword2 thirdword2 fourthword2 ... and I need to read it fully into memory I can use this approach: open a text file while not EOF read line by line split each line by a space create a new object with four fields extracted from each line add this object to a Set Ok, but is there anything better, a special 3-rd party Java library? So that we could define the structure of each text line beforehand and parse the file with some function thirdpartylib.setInputTextFileFormat("format.xml"); thirdpartylib.parse(Set, "pathToFile") ?

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  • Parsing HTML with XPath and PHP

    - by Peter
    Is there a way (using XPath and PHP) to do the following (WITHOUT external XSLT files)? Remove all tables and their contents Remove everything after the first h1 tag Keep only paragraphs (INCLUDING their inner HTML (links, lists, etc)) I received an XSLT answer here, but I'm looking for XPATH queries that don't require external files. Currently, I've got the HTML in question loaded into a SimpleXmlElement via: $doc = @DOMDocument::loadHTML($xml); $data = simplexml_import_dom($doc); Now I need help with: $data = $data->xpath('??????'); Been working with this one for several days to no avail. I really appreciate the help. Edit: I don't particularly care what's inside the paragraphs, as I can use strip_tags to eliminate what I don't want. All I need to do is to isolate the paragraphs from the rest of the source. I suppose a more specific, accurate requirement would be this: Return only paragraphs (and their html contents) that aren't contained in tables, and only before the first h1 tag

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  • Java Plist XML Parsing

    - by Jannis
    Hello everyone, I'm parsing a (not well formed) Apple Plist File with java. My Code looks like this: InputStream in = new FileInputStream( "foo" ); XMLInputFactory factory = XMLInputFactory.newInstance(); XMLEventReader parser = factory.createXMLEventReader( in ); while (parser.hasNext()){ XMLEvent event = parser.nextEvent(); //code to navigate the nodes } The parts I"m parsing are looking like this: <dict> <key>foo</key><integer>123</integer> <key>bar</key><string>Boom &amp; Shroom</string> </dict> My problem is now, that nodes containing a ampersand are not parsed like they should because the ampersand is representing a entity. What can i do to get the value of the node as a complete String, instead of broken parts? Thank you in advance.

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  • Correct XML serialization and deserialization of "mixed" types in .NET

    - by Stefan
    My current task involves writing a class library for processing HL7 CDA files. These HL7 CDA files are XML files with a defined XML schema, so I used xsd.exe to generate .NET classes for XML serialization and deserialization. The XML Schema contains various types which contain the mixed="true" attribute, specifying that an XML node of this type may contain normal text mixed with other XML nodes. The relevant part of the XML schema for one of these types looks like this: <xs:complexType name="StrucDoc.Paragraph" mixed="true"> <xs:sequence> <xs:element name="caption" type="StrucDoc.Caption" minOccurs="0"/> <xs:choice minOccurs="0" maxOccurs="unbounded"> <xs:element name="br" type="StrucDoc.Br"/> <xs:element name="sub" type="StrucDoc.Sub"/> <xs:element name="sup" type="StrucDoc.Sup"/> <!-- ...other possible nodes... --> </xs:choice> </xs:sequence> <xs:attribute name="ID" type="xs:ID"/> <!-- ...other attributes... --> </xs:complexType> The generated code for this type looks like this: /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(TypeName="StrucDoc.Paragraph", Namespace="urn:hl7-org:v3")] public partial class StrucDocParagraph { private StrucDocCaption captionField; private object[] itemsField; private string[] textField; private string idField; // ...fields for other attributes... /// <remarks/> public StrucDocCaption caption { get { return this.captionField; } set { this.captionField = value; } } /// <remarks/> [System.Xml.Serialization.XmlElementAttribute("br", typeof(StrucDocBr))] [System.Xml.Serialization.XmlElementAttribute("sub", typeof(StrucDocSub))] [System.Xml.Serialization.XmlElementAttribute("sup", typeof(StrucDocSup))] // ...other possible nodes... public object[] Items { get { return this.itemsField; } set { this.itemsField = value; } } /// <remarks/> [System.Xml.Serialization.XmlTextAttribute()] public string[] Text { get { return this.textField; } set { this.textField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute(DataType="ID")] public string ID { get { return this.idField; } set { this.idField = value; } } // ...properties for other attributes... } If I deserialize an XML element where the paragraph node looks like this: <paragraph>first line<br /><br />third line</paragraph> The result is that the item and text arrays are read like this: itemsField = new object[] { new StrucDocBr(), new StrucDocBr(), }; textField = new string[] { "first line", "third line", }; From this there is no possible way to determine the exact order of the text and the other nodes. If I serialize this again, the result looks exactly like this: <paragraph> <br /> <br />first linethird line </paragraph> The default serializer just serializes the items first and then the text. I tried implementing IXmlSerializable on the StrucDocParagraph class so that I could control the deserialization and serialization of the content, but it's rather complex since there are so many classes involved and I didn't come to a solution yet because I don't know if the effort pays off. Is there some kind of easy workaround to this problem, or is it even possible by doing custom serialization via IXmlSerializable? Or should I just use XmlDocument or XmlReader/XmlWriter to process these documents?

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  • How to deserialize an element as an XmlNode?

    - by mackenir
    When using Xml serialization in C#, I want to deserialize a part of my input XML to an XmlNode. So, given this XML: <Thing Name="George"> <Document> <subnode1/> <subnode2/> </Document> </Thing> I want to deserialize the Document element to an XmlNode. Below is my attempt which given the XML above, sets Document to the 'subnode1' element rather than the 'Document' element. How would I get the code to set the Document property to the Document element? using System; using System.IO; using System.Xml; using System.Xml.Serialization; [Serializable] public class Thing { [XmlAttribute] public string Name {get;set;} public XmlNode Document { get; set; } } class Program { static void Main() { const string xml = @" <Thing Name=""George""> <Document> <subnode1/> <subnode2/> </Document> </Thing>"; var s = new XmlSerializer(typeof(Thing)); var thing = s.Deserialize(new StringReader(xml)) as Thing; } } However, when I use an XmlSerializer to deserialize the XML above to an instance of Thing, the Document property contains the child element 'subnode1', rather than the 'doc' element. How can I get the XmlSerializer to set Document to an XmlNode containing the 'doc' element.

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  • Cinema4D XML scene not rendering texture

    - by George Profenza
    I was playing with the Cinema 4D command line options and ran into a problem that might not be specific to the command line options. I saved a basic scene(a textured cube) in two formats: the original .c4d(binary) format and .xml(Cinema 4D XML via File Export). the .c4d file renders with the texture applied, while the .xml file renders without the texture applied. I had a look at the xml file, and there is a node that holds a reference to the image used as texture, and there is another node which seems to store the pixels in xml. When I opened the .xml document in Cinema 4D, the document did store the material with the texture, but it was not applied to the object. Am I missing something when I export to XML ? How can I export a Cinema 4D XML that can render with the texture applied ?

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  • How to use the same element name in different purposes ( in XML and DTD ) ?

    - by BugKiller
    Hi, I Want to create a DTD schema for this xml document: <root> <student> <name> <firstname>S1</firstname> <lastname>S2</lastname> </name> </student> <course> <name>CS101</name> </course> </root> as you can see , the element name in the course contains plain text ,but the element name in the student is complex type ( first-name, last-name ). The following is the DTD: <!ELEMENT root (course|student)*> <!ELEMENT student (name)> <!ELEMENT name (lastname|firstname)> <!ELEMENT firstname (#PCDATA)> <!ELEMENT lastname (#PCDATA)> <!ELEMENT course (name)> When I want to validate it , I get an error because the course's name has different structure then the student's name . My Question: how can I make a work-around solution for this situation without changing the name of element name using DTD not xml schema . Thanks.

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  • XML Catalog in Eclipse is not working

    - by svaret
    Where I work we do not have any internet connection. We still want to have validation and code completion when editing xml files. I have tried the instructions here http://www.helmers.nu/?p=276 However, I try the instructions, restarts eclipse, do reload dependencies. I still cannot get any code completion nor validation. Can anyone point me in the right direction? I have tried both with Eclipse Galileo and Helios. My catalog.xml <?xml version="1.0" encoding="UTF-8" standalone="no"?> <catalog xmlns="urn:oasis:names:tc:entity:xmlns:xml:catalog"> <uri name="http://www.liquibase.org/xml/ns/dbchangelog/1.9" uri="file:///C:/dev/XMLSchemaDefinition/dbchangelog-1.9.xsd"/> </catalog> My xml-file: <?xml version="1.0" encoding="UTF-8" standalone="no"?> <databaseChangeLog xmlns="http://www.liquibase.org/xml/ns/dbchangelog/1.9" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.liquibase.org/xml/ns/dbchangelog/1.9 http://www.liquibase.org/xml/ns/dbchangelog/dbchangelog-1.9.xsd"> </databaseChangeLog>

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  • .NET and XML: How can I read nested namespaces (<abc:xyz:name attr="value"/>)?

    - by Entrase
    Suppose there is an element in XML data: <abc:xyz:name attr="value"/> I'm trying to read it with XmlReader. The problem is that I get XmlException that says The ‘:’ character, hexadecimal value 0x3A, cannot be included in a name I have already declared "abc" namespace. I have also tried adding "abc:xyz" and "xyz" namespaces. But this doesn't help at all. I could replace some text before parsing but there may be some more elegant solution. So what should I do? Here is my code: XmlReaderSettings settings = new XmlReaderSettings() NameTable nt = new NameTable(); XmlNamespaceManager nsmgr = new XmlNamespaceManager(nt); nsmgr.AddNamespace("abc", ""); nsmgr.AddNamespace("xyz", ""); XmlParserContext context = new XmlParserContext(null, nsmgr, null, XmlSpace.None); // So this reader can't read <abc:xyz:name attr="value"/> XmlReader reader = XmlReader.Create(path, settings, context);“

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  • How to use the same element name for different purposes ( in XML and DTD ) ?

    - by BugKiller
    Hi, I Want to create a DTD schema for this xml document: <root> <student> <name> <firstname>S1</firstname> <lastname>S2</lastname> </name> </student> <course> <name>CS101</name> </course> </root> as you can see , the element name in the course contains plain text ,but the element name in the student is complex type ( first-name, last-name ). The following is the DTD: <!ELEMENT root (course|student)*> <!ELEMENT student (name)> <!ELEMENT name (lastname|firstname)> <!ELEMENT firstname (#PCDATA)> <!ELEMENT lastname (#PCDATA)> <!ELEMENT course (name)> When I want to validate it , I get an error because the course's name has different structure then the student's name . My Question: how can I make a work-around solution for this situation without changing the name of element name using DTD not xml schema . Thanks.

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  • XML Schema: Can I make some of an attribute's values be required but still allow other values?

    - by scrotty
    (Note: I cannot change structure of the XML I receive, I am only able to change how I validate it.) Let's say I can get XML like this: <Address Field="Street" Value="123 Main"/> <Address Field="StreetPartTwo" Value="Unit B"/> <Address Field="State" Value="CO"/> <Address Field="Zip" Value="80020"/> <Address Field="SomeOtherCrazyValue" Value="Foo"/> I need to create an XSD schema that validates that "Street", "State" and "Zip" must be present. But I don't care if "StreetPartTwo" or "SomeOTherCrazyValue" is present. If I knew that only the three I care about could be included, I could do this: <xs:element name="Address" type="addressType" maxOccurs="unbounded" minOccurs="3"/> <xs:complexType name="addressType"> <xs:attribute name="Field" use="required"> <xs:simpleType> <xs:restriction base="xs:string"> <xs:enumeration value="Street"/> <xs:enumeration value="State"/> <xs:enumeration value="Zip"/> </xs:restriction> </xs:simpleType> </xs:attribute> </xs:complexType> But this won't work with my case because I may also receive those other Address elements (that also have "Field" attributes) that I don't care about. Any ideas how I can ensure the stuff I care about is present but let the other stuff in too? TIA! Sean

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  • PHP XML Parsing

    - by ashchawla
    Hi I am making get request in PHP but the parser is having issues. I am looking for a way to retreive the value of URL in the following example. The response xml looks like this. <?xml version="1.0" encoding="iso-8859-1" standalone="no"?> <testtemplate JobName="test1"> <Sources> <Source xmlns="http://www.microsoft.com/test/schema/api"> <System> <SystemIdentifier>HTTPS</SystemIdentifier> <URL>http://example.com</URL> </System> </Source> </Sources> <testtemplate> and my PHP code looks like this: $xml = DOMDocument::LoadXML($response); $mypath = new DOMXPath($xml); $mypath->registerNamespace("a", "http://www.microsoft.com/test/schema/api"); $url = $mypath->evaluate("/testtemplate/Sources/Source/System/URL"); $message = $url->item(0)->value; print($message); Any help would be appreciated. Thanks Ashish

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  • use multiple xsl files with one xml document

    - by paracaudex
    I have a single xml document (data.xml), which I display as HTML using an XSLT document (transform.xsl) with the following line in data.xml. <?xml-stylesheet type="text/xsl" href="transform.xsl"?> Suppose, however, I want to display this information in two different ways, one at http://www.domain.com/data.xml and one at http://www.domain.com/data2.xml. Both of these displays will use the same xml document but with different xsl's. Is there a way to do this without duplicating the xml file?

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