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  • UTF8 charset, diacritical elements, conversion problems - and Zend Framework form escaping

    - by imanc
    Hey, I am writing a webapp in ZF and am having serious issues with UTF8. It's using multi lingual content through Zend Form and it seems that ZF heavily escapes all of these characters and basically just won't show a field if there's diacritical elements 'é' and if I use the HTML entity equivalent e.g. é it gets escaped so that the user will see 'é'. Zend Form allows for having non escaped data, but trying to use this is confusing, and it seems it'd need to be used all over the place. So, I have been told that if the page and the text is in UTF8, no conversion to htmlentities is required. Is this true? And if the last question is true, then how do I convert the source text to UTF8? I am comfortable setting up apache so that it sends a default UTF8 charset heading, and also adding the charset meta tag to the html, but doing this I am still getting messed up encoding. I have also tried opening the translation csv file in TextWrangler on OSX as UTF8, but it has done nothing. Thanks! L

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  • CLI include paths to run zend framework via cron

    - by summerg
    I wrote a command line utility using Zend Framework to do some nightly reporting. It uses a ton of the same functionality the accompanying site. It works great when I run it by hand, but when I run it on cron I have include path issues. Seems like it should be easily fixed with set_include_path, but maybe I'm missing something? My directory structure looks like this: /var/www/clientname/ application Globals.php commandline commandline_bootstrap.php public_html public_bootstrap.php library Zend In public_bootstrap.php I use set_include_path without a problem, relative to the current directory: set_include_path('../library' . PATH_SEPARATOR . get_include_path()); If I understand correctly, in commandline_bootstrap.php I need to put in the absolute path, so cron knows where everything is. My file starts like this: error_reporting(E_ALL); set_include_path('/var/www/clientname/library' . PATH_SEPARATOR . get_include_path()); require_once "../application/Globals.php"; But when I run it via cron I get the following error: PHP Fatal error: require_once(): Failed opening required '../application/Globals.php' (include_path='/var/www/clientname/library/') in /var/www/clientname/commandline/zfcli.php on line 11 I think PHP is accepting my new path, because when I run it command line and dump the phpinfo I can see: include_path = /var/www/clientname/library/:.:/usr/share/pear:/usr/share/php = .:/usr/share/pear:/usr/share/php I admit the syntax here looks a little strange, but I can’t figure out how to fix it. Any suggestions would be greatly appreciated. Thanks summer

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  • Receive JSON payload with ZEND framework and / or PHP

    - by kent3800
    I'm receiving a JSON payload from a webservice at my site's internal webpage at /asset/setjob. The following is the JSON payload being posted to /asset/setjob: [{"job": {"source_filename": "beer-drinking-pig.mpg", "current_step": "waiting_for_file", "encoding_profile_id": "nil", "resolution": "nil", "status_url": "http://example.com/api/v1/jobs/1.json", "id": 1, "bitrate": "nil", "current_status": "waiting for file", "current_progress": "nil", "remote_id": "my-own-remote-id"}}] This payload posts one time to this page. The page is not meant for viewing but parsing the JSON object for the id and current_status so that I can insert it into a database. I'm using Zend framework. HOW DO I receive this payload in Zend? Do I $_GET['json']? $_POST['job']? None of these seem to work. I essentially need to assign this payload to a php variable so that I can then manipulate it. I've tried: $jsonStrGet = var_dump($_GET); $jsonStrPost = var_dump($_POST); And I've tried: $response = $this-getResponse(); $body = $response-getBody(); Blockquote Any help would be much appreciated! Thanks.

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  • Zend Framework - counting rows in select clause ?

    - by moogeek
    Hello! I'm investigating Zend Framework and currently stucked in counting resulting rows of sql query... Every method I try (from documentation and some blogposts and tutorials) returns an error (like Call to undefined function) or simply gives the incorrect value. I've tried this: $checkquery = $db->select() ->from('users', 'COUNT(*)') ->where('login = ?', $login) ->where('password = ?', $password) ->query(); $checkrequest=fetchRow($checkquery)->num; ...then this one: $checkquery = $db->select() ->from('users', '*') ->where('login = ?', $login) ->where('password = ?', $password) ->query(); $checkrequest=count($checkquery->fetchAll()); and even: $checkquery = $db->select() ->from('users', '*') ->where('login = ?', $login) ->where('password = ?', $password) ->query(); $checkrequest=$checkquery->fetchAll()->num; Also rowCount() and count(fetchRow()) and count(fetchAll()->toArray()). But always I got an error message or duplicate inserts in db in further insert function. So what is the correct way to do the resulting row calculation in select clause in Zend Framework 1.9 (I use this one) ?

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  • Good Hosting Providers With Zend Framework Support

    - by manyxcxi
    I currently use ixwebhosting for my hosting services. They're cheap and work (most of the time). The databases are horribly slow, the servers are horribly slow, and their support (though usually prompt) is tough to deal with. That being said, they're cheap, I've got like 20 domains hosted in my account, none of them are high volume, and they work JUST good enough- until today. This isn't meant to be a condemnation of ixwh though. Their prices are very low for what they do offer and most things work just fine, most of the time. I need to be able to host web apps written with Zend Framework in a fairly easy fashion. The server performance can't be worse than what I've already had (a pretty low hurdle to clear), and I don't want to spend $30/mo. These are not money making websites- they're projects. My requirements are PHP 5.3, ZF support, MySQL databases, multiple domains- not much. Who should I look at, and who should I look out for? Also- I put this on SO instead of SF because of the Zend Framework specific requirement. If I'm wrong, do as you wish.

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  • The Date type and the Android database

    - by cdonner
    I understand that SQLite stores dates as long integers. When I read rows into a cursor using the standard method (i.e. using the query() method that reads data into a cursor), the result is a date string that includes the time. If I want a different format, I have to parse the string back into a date - possible, but a bit backwards. By using a ViewBinder (as suggested in this question), I can pretty much do anything I want, but the date is already a string at the time the method executes. The accepted answer to the above question also suggests that storing dates as longs would help avoid this problem. I don't want to do that, just in case I want to interpret my data with something else than this application. Maybe I want to expose it via a provider. Is there a way to handle this in the database adapter instead, i.e. controlling the date format that the cursor contains, so that I don't have to change the schema, and don't have to parse the default output back into a Date type?

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  • Formatting the date in unix to include suffix on day (st, nd, rd and th)

    - by skymook
    How can I add the suffix on the day number of a unix date? I'll explain. I have a TextMate bundle snippit that writes out today's date. It uses unix date and formatting. Here is the code: `date +%A` `date +%d` `date +%B` `date +%Y` It outputs: Monday 22 March 2010 I would like to add the suffix to the day (st, nd, rd and th) like so: Monday 22nd March 2010 As far as I can see, there is no native function in the unix date formatting, like there is in PHP (j). How would I achieve this in unix? A complicated regex on the day number?

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  • Convert String to java.util.Date

    - by Vinayak.B
    Hi Folks, I storing the date to SQLite database in the format d-MMM-yyyy,HH:mm:ss aaa And again retrieving it with the same format, the problem now is, I am gettin every thing fine exepth the Hour. Hour I am geting 00 every time, Here the print statement String date--->29-Apr-2010,13:00:14 PM After convrting Date--->1272479414000--Thu Apr 29 00:00:14 GMT+05:30 2010 Please where I am doing wrong. Cheers, Vinayak

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  • Checking if date parsing is correct

    - by Javi
    Hello, I have this code for checking whether the Date is OK or not, but it's not ckecking all the cases. For example when text="03/13/2009" as this date doesn't exist in the format "dd/MM/yyyy" it parses the date as 03/01/2010. Is there any way to change this behaviour and getting an exception when I try to parse a Date which is not correct? What's the best way to do this validation? public static final String DATE_PATTERN = "dd/MM/yyyy"; public static boolean isDate(String text){ SimpleDateFormat formatter = new SimpleDateFormat(DATE_PATTERN); ParsePosition position = new ParsePosition(0); formatter.parse(text, position); if(position.getIndex() != text.length()){ return false; }else{ return true; } } Thanks.

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  • How to set default date in date_select helper in Rails

    - by brad
    I'm trying to set up a date of birth helper in my Rails app (2.3.5). At present it is like so. <%= f.date_select :date_of_birth, :start_year => Time.now.year - 110, :end_year => Time.now.year %> This generates a perfectly functional set of date fields that work just fine but.... They default to today's date which is not ideal for a date of birth field (I'm not sure what is but unless you're running a neonatal unit today's date seems less than ideal). I want it to read Jan 1 2010 instead (or 2011 or whatever year it happens to be). Using the :default option has proven unsuccessful. I've tried many possibilities including; <%= f.date_select :date_of_birth, :default => {:year => Time.now.year, :month => 'Jan', :day => 1}, :start_year => Time.now.year - 110, :end_year => Time.now.year %> and <%= f.date_select :date_of_birth, :default => Time.local(2010,'Jan',1), :start_year => Time.now.year - 110, :end_year => Time.now.year %> None of this changes the behaviour of the first example. Does the default option actually work as described? It seems that this should be a fairly straightforward thing to do. Ta.

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  • Java Date vs Calendar

    - by Marty Pitt
    Could someone please advise the current "best practice" around Date and Calendar types. When writing new code, is it best to always favour Calendar over Date, or are there circumstances where Date is the more appropriate datatype?

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  • Human readable and parsable date format in Java.

    - by Savvas Dalkitsis
    I want to save a Date object to a readable string (for example 22/10/2009 21:13:14) that is also parsable back to a Date object. I have tried many things and the best I could find was to use DateFormater for parsing and formating but it has a setback. When you format a date you lose seconds information. I tried to find if there is an option to format it and display the seconds (even better would be to the millisecond level since that's the resolution the Date object allows you to have) but I came up short. Any ideas?

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  • Parse RSS pubDate to Date object in java

    - by Derk
    How can I parse a pubDate from a RSS feed to a Date object in java. The format in the RSS feed: Sat, 24 Apr 2010 14:01:00 GMT What I have at the moment: DateFormat dateFormat = DateFormat.getInstance(); Date pubDate = dateFormat.parse(item.getPubDate().getText()); But this code throws an ParseException with the message Unparseable date

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  • How to edit and display Date in ASP.Net MVC 2

    - by Picflight
    I am storing a date in my database and want the user to be able to edit this date in the Edit View. In the past with ASP.Net web forms I have used 3 dropdownlists for the Month, Day and Year to get the date from the user and to bind it on display. I want to do the same in ASP.Net MVC and not sure how to do it? I am not using any jQuery or Javascript, the design calls for simple postback.

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  • grails date from params in controller

    - by nils petersohn
    y is it so hard to extract the date from the view via the params in a grails controller? i don't want to extract the date by hand like this: instance.dateX = parseDate(params["dateX_value"])//parseDate is from my helper class i just want to use instance.properties = params you know :) in the model the type is java.util.Date and in the params is all the information (dateX_month, dateX_day, ...) i searched on the net and found nothing on this :( i hoped that grails 1.3.0 could help but still the same thing. i can't and will not belief that extracting the date by hand is nessesary!

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  • Core Data data type for just the date - not including time

    - by Jason
    I am new at Core Data, and it seems like it is a great way to manage the data store. However I am also very memory-conscious due to the fact that the iPhone doesn't have that much of it. I was a little surprised to see that the data types are so limited - eg. there is a Date type which includes also the time, but no Date type for just the date! All the time information takes up precious bytes of memory, if I just wanted an attribute with the date (e.g. 2/15/2010 rather than 2/15/2010 02:34:48), how could I do this? Is it possible?

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  • number of months between two dates - using boost's date

    - by MartinP
    I've used boost::gregorian::date a bit now. I can see that there are the related months & years & weeks duration types. I can see how to use known durations to advance a given date. Qu: But how can I get the difference between two dates in months (or years or weeks) ? I was hoping to find a function like: template<typename DURATION> DURATION date_diff<DURATION>(const date& d1,const date& d2); There would need to be some handling of rounding too.

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  • PHP / Zend Framework: Which object would handle a complex table join?

    - by Thomas
    I think one of the more difficult concepts to understand in the Zend Framework is how the Table Data Gateway pattern is supposed to handle multi-table joins. Most of the suggestions I've seen claim that you simply handle the joins using a $db-select()... Zend DB Select with multiple table joins Joining Tables With Zend Framework PHP Joining tables wthin a model in Zend Php Zend Framework Db Select Join table help Zend DB Select with multiple table joins My question is: Which object is best suited to handle this kind of multi-table select statement? I feel like putting it in the model would break the 1-1 Table Data Gateway pattern between the class and the db table. Yet putting it in the controller seems wrong because why would a controller handle a SQL statement? Anyway, I feel like ZF makes handling datasets from multiple tables more difficult than it needs to be. Any help you can provide is great... Thanks!

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  • convert variable with mixed date formats to one format in r

    - by jalapic
    A sample of my dataframe: date 1 25 February 1987 2 20 August 1974 3 9 October 1984 4 18 August 1992 5 19 September 1995 6 16-Oct-63 7 30-Sep-65 8 22 Jan 2008 9 13-11-1961 10 18 August 1987 11 15-Sep-70 12 5 October 1994 13 5 December 1984 14 03/23/87 15 30 August 1988 16 26-10-1993 17 22 August 1989 18 13-Sep-97 I have a large dataframe with a date variable that has multiple formats for dates. Most of the formats in the variable are shown above- there are a couple of very rare others too. The reason why there are multiple formats is that the data were pulled together from various websites that each used different formats. I have tried using straightforward conversions e.g. strftime(mydf$date,"%d/%m/%Y") but these sorts of conversion will not work if there are multiple formats. I don't want to resort to multiple gsub type editing. I was wondering if I am missing a more simple solution? Code for example: structure(list(date = structure(c(12L, 8L, 18L, 6L, 7L, 4L, 14L, 10L, 1L, 5L, 3L, 17L, 16L, 11L, 15L, 13L, 9L, 2L), .Label = c("13-11-1961", "13-Sep-97", "15-Sep-70", "16-Oct-63", "18 August 1987", "18 August 1992", "19 September 1995", "20 August 1974", "22 August 1989", "22 Jan 2008", "03/23/87", "25 February 1987", "26-10-1993", "30-Sep-65", "30 August 1988", "5 December 1984", "5 October 1994", "9 October 1984"), class = "factor")), .Names = "date", row.names = c(NA, -18L), class = "data.frame")

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