How do I embed an expect script that takes in arguments into a bash shell script?
- by fzkl
I am writing a bash script which amongst many other things uses expect to automatically run a binary and install it by answering installer prompts.
I was able to get my expect script to work fine when the expect script is called in my bash script with the command "expect $expectscriptname $Parameter". However, I want to embed the expect script into the shell script instead of having to maintain two separate script files for the job. I searched around and found that the procedure to embed expect into bash script was to declare a variable like VAR below and then echo it.:
VAR=$(expect -c "
#content of expect script here
")
echo "$VAR"
1) I don't understand how echoing $VAR actually runs the expect script. Could anyone explain?
2) I am not sure how to pass $Parameter into VAR or to the echo statement. This is my main concern.
Any ideas? Thanks.
