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  • Generating new sources via Maven plugin after compile phase

    - by japher
    I have a Maven project within which I need execute two code generation steps. One generates some Java types, then the second depends on those Java types to generate some more code. Is there a way to have both of these steps happening during my build? At the moment my steps are: execute first code generation plugin (during generate-sources) add directory of generated types to build path execute second code generation plugin (during compile) However my problem is that anything generated by the second code generation plugin will not be compiled (because the compile phase has finished). If I attach the second code generation plugin to an earlier phase, it fails because it needs the classes from the first code generation plugin to be present on the classpath. I know I could split this into two modules with one dependent on the other, but I was wondering if this could be achieved in one pom. It seems like a need a way to invoke compile again after the normal compile phase is complete. Any ideas?

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  • What does sub error code 568 mean for Ldap Error 49 with Active Directory

    - by Dean Povey
    I am writing some Java code that authenticates to Active Directory using SASL GSSAPI. Mostly this code is working fine but for one user I am getting the response: javax.naming.AuthenticationException: [LDAP: error code 49 - 8 0090304: LdapErr: DSID-0C0904D1, comment: AcceptSecurityContext error, data 568, v1772 ] I know that 49 means this is an authentication failure, and that the relevant sub code is 568, but I am only aware of the following meanings for that data: 525 - user not found 52e - invalid credentials 530 - not permitted to logon at this time 532 - password expired 533 - account disabled 701 - account expired 773 - user must reset password So far I am unable to find an authorative source of these error codes from Microsoft (this list is pieced together from forum posts) and I can't find anything for that 568 error. Does anyone know what it means?

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  • Inserting the record into Database through JPA

    - by vinay123
    In my code I am using JSF - Front end , EJB-Middile Tier and JPA connect to DB.Calling the EJB using the Webservices.Using MySQL as DAtabase. I have created the Voter table in which I need to insert the record. I ma passing the values from the JSF to EJB, it is working.I have created JPA controller class (which automatcally generates the persistence code based on the data base classes) Ex: getting the entity manager etc., em = getEntityManager(); em.getTransaction().begin(); em.persist(voter); em.getTransaction().commit(); I have created the named query also: @NamedQuery(name = "Voter.insertRecord", query = "INSERT INTO Voter v values v.voterID = :voterID,v.password = :password,v.partSSN = :partSSN, v.address = :address, v.zipCode = :zipCode,v.ssn = :ssn, v.vFirstName = :vFirstName,v.vLastName = :vLastName,v.dob = :dob"), But still not able to insert the record? Can anyone help me in inserting the record into the Data base through JPA.(Persistence object)?

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  • To stop returning through SSH using Pexpect

    - by chrissygormley
    Hello, I am trying to use pexpect to ssh into a computer but I do not want to return back to the original computer. The code I have is: #!/usr/bin/python2.6 import pexpect, os def ssh(): # Logs into computer through SSH ssh_newkey = 'Are you sure you want to continue connecting' # my ssh command line p=pexpect.spawn('ssh [email protected]') i=p.expect([ssh_newkey,'password:',pexpect.EOF]) p.sendline("password") i=p.expect('-bash-3.2') print os.getcwd() ssh() This allows me to ssh into the computer but when I run the os.getcwd() the pexpect has returned me to the original computer. You see I want to ssh into another computer and use their environment not drag my environment using pexpect. Can anyone suggest how to get this working or an alternative way. Thanks

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  • Can django's auth_user.username be varchar(75)?

    - by perrierism
    Django's auth_user.username field is 30 characters. That means you can't have auth_user.username store an email address. If you want to have users authenticate based on their email address it would seem you have to do some wonky stuff like writing your own authentication backend which authenticates based on (email, password) instead of (username, password) and furthermore, figuring out what you're going to put in the username field since it is required and it is a primary key. Do you put a hash in there, do you try to put the id in there... bleh! Why should you have to write all this code and consider edge cases simply because username is too small for your (farily common) purposes? Is there anything wrong with running alter table on auth_user to make username be varchar(75) so it can fit an email? What does that break if anything?

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  • How to configure Spring JavaMailSenderImpl for Gmail

    - by Andrew Carlson
    I am trying to find the correct properties to use to connect to the Gmail SMTP sever using the JavaMailSenderImpl class. Let me first say that I have tried the approach found here. This worked fine. But when I tried the configuration below that post with the exact same authentication information I received a javax.mail.AuthenticationFailedException. My currently configuration looks like this. <bean id="mailSender" class ="org.springframework.mail.javamail.JavaMailSenderImpl" > <property name="username" value="[email protected]" /> <property name="password" value="XXX" /> <property name="javaMailProperties"> <props> <prop key="mail.smtp.host">smtp.gmail.com</prop> <prop key="mail.smtp.port">587</prop> <prop key="mail.smtp.auth">true</prop> <prop key="mail.smtp.starttls.enable">true</prop> </props> </property> </bean> Why am I still getting this javax.mail.AuthenticationFailedException if I know that my credentials are correct. Update Here is my updated code based on the answers below. I am still receiving the same exception. <bean id="mailSender" class ="org.springframework.mail.javamail.JavaMailSenderImpl" > <property name="username" value="[email protected]" /> <property name="password" value="XXX" /> <property name="javaMailProperties"> <props> <prop key="mail.smtp.from">[email protected]</prop> <prop key="mail.smtp.user">[email protected]</prop> <prop key="mail.smtp.password">XXX</prop> <prop key="mail.smtp.host">smtp.gmail.com</prop> <prop key="mail.smtp.port">587</prop> <prop key="mail.smtp.auth">true</prop> <prop key="mail.smtp.starttls.enable">true</prop> </props> </property> </bean>

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  • security issue of Linux sudo command?

    - by George2
    Hello everyone, 1. I am using Red Hat Enterprise 5 Linux box. I find if a user is in /etc/sudoers file, then if the user run command with sudo, the user will run this command with root privilege (without knowing root password, the user runs sudo only need to input the user's own password in order to run a command with sudo). Is that correct understanding? 2. If yes, then is it a security hole? Since users other than root could run with root privilege? thanks in advance, George

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  • LocalReport (WebForms) and Partial Trust, for PDF Generation

    - by Peet Brits
    My goal is to generate a PDF for display in a web page, either as aspx or with a generic handler. (This will link from a Silverlight page, but this is irrelevant to the problem.) The problem is that LocalReport (Microsoft.Reporting.WebForms; Microsoft.ReportViewer.WebForms.dll) requires full trust, and our hosting server does not allow full trust. I am aware that ReportViewer has a remote mode that will allow it to run with partial trust, but for that I need a report server url which should probably have full trust as well, which does not solve anything. So how do I generate PDFs from WebForms in a partially trusted environment?

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  • PHP Session when using desktop app

    - by Jonathan
    In this question I asked how to POST to a php file form a vb.net app: http://stackoverflow.com/questions/2615335/post-to-webpage-in-vb-net-win-forms-desktop-not-asp-net So now I've logged in the user user by posting their username and password to the php file, the php file then does security/checks they exist/etc and if both username and password are correct is stores the user ID in a session variable. Now if the vb.net app tries to download data off a page which needs the user to logged in, it checks this by doing: if (!isset($_SESSION['uid'])) { header("Location: index.php"); } However after having logged correctly in the app the session variable is not set. How does session work with a vb.net app like this? When the user logs in successfully should I download the user id and keep it in the vb.net app and then post it to each page that requires authentication?

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  • public key email encryption

    - by anatak
    Who has their email fully encrypted ? I would like to encrypt my email but I am not sure how to start. If I use encrypted email and I send an email to someone who does not encrypt his email how can the receiver read the email ? What email client would you recommend to run on a windows systems for encrypted email ? I am using Thunderbird at the moment. As I understand you have to generate 2 keys (one public and one private) but how do you generate this key? I also think that you have to put your key somewhere to download but I don't understand how you can trust the downloaded keys. Any links to a good (not too complicated) guide about the working an implementing of email encryption would be very much appreciated. kind regards wim hendrix anatak

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  • Error: java.security.AccessControlException: Access denied

    - by RMD
    Hi, I have to connect to a https url with username and password to read a file. I am not able to connect to the server (see the error log below). I do not have much java experience so I need help with this code. I would really appreciate some help to solve this! Thank you. Raquel CODE: import lotus.domino.; import java.net.; import java.io.*; import javax.net.ssl.HttpsURLConnection; public class JavaAgent extends AgentBase { public void NotesMain() { try { String username = "123"; String password = "456"; String input = username + ":" + password; String encoding = new sun.misc.BASE64Encoder().encode (input.getBytes()); //Open the URL and read the text into a Buffer String urlName = "https://server.org/Export.mvc/GetMeetings?modifiedSince=4/9/2010"; URL url = new URL(urlName); HttpsURLConnection connection = (HttpsURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); connection.setRequestProperty("Content-Length", String.valueOf (encoding.length())); connection.setUseCaches(false); connection.setDoInput(true); connection.setDoOutput(true); connection.setAllowUserInteraction(true); connection.setRequestProperty("Authorization", "Basic " + encoding); connection.setRequestProperty("Cookie", "LocationCode=Geneva"); connection.connect(); BufferedReader rd = null; try{ rd = new BufferedReader(new InputStreamReader(connection.getInputStream())); } catch (IOException e) { System.out.println("Read failed"); System.exit(-1); } String line; while((line = rd.readLine()) != null) { System.out.println(line.toString()); } rd.close(); connection.disconnect(); } catch(Exception e) { e.printStackTrace(); } } } LOG: java.security.AccessControlException: Access denied (java.lang.RuntimePermission exitVM.-1) at java.security.AccessController.checkPermission(AccessController.java:108) at java.lang.SecurityManager.checkPermission(SecurityManager.java:532) at COM.ibm.JEmpower.applet.AppletSecurity.superDotCheckPermission(AppletSecurity.java:1449) at COM.ibm.JEmpower.applet.AppletSecurity.checkRuntimePermission(AppletSecurity.java:1311) at COM.ibm.JEmpower.applet.AppletSecurity.checkPermission(AppletSecurity.java:1611) at COM.ibm.JEmpower.applet.AppletSecurity.checkPermission(AppletSecurity.java:1464) at java.lang.SecurityManager.checkExit(SecurityManager.java:744) at java.lang.Runtime.exit(Runtime.java:99) at java.lang.System.exit(System.java:275) at JavaAgent.NotesMain(Unknown Source) at lotus.domino.AgentBase.runNotes(Unknown Source) at lotus.domino.NotesThread.run(Unknown Source)

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  • WCF(HTTPS,UserName) calling by SilverLight

    - by Andrew Kalashnikov
    Hello colleagues. I've created wcf service with transport security over HTTPS. Also I use UserName authentication as described at http://msdn.microsoft.com/en-us/library/cc949025.aspx, so I can use my Membership,RoleProvider. When I work with this service with ASP.NET all is OK var client = new RegistratorClient(); client.ClientCredentials.UserName.UserName = ConfigurationManager.AppSettings["registratorLogin"]; client.ClientCredentials.UserName.Password = ConfigurationManager.AppSettings["registratorPassword"]; But at my SilverLight appliation I can't do the same. When I try setup credntials and call wcf I get standard browser window with username and password. When I insert it SL application works well, but this message is so annoyed. I can't use clientCredentialType="Basic" at my SL config. What should I do for silence calling my WCF. Big thanks

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  • Do passwords used for .htaccess need to be encrypted?

    - by webworm
    I am using .htaccess files to control access to various Apache2 directories. I have a main "password" file that contains usernames and passwords. All the instructions I have found regarding .htaccess talk about how the passwords added are encrypted. The usernames and passwords are created using the following command line syntax ... htpasswd -nb username password What I am wondering is ... do the passwords always need to be encrypted? Could I store usernames and passwords in a plain-text form someonewhere on the system (above the web root)? This would allow me to easily edit user names and passwords via FTP without requiring access to the Shelll (which I do not always have). Thank you.

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  • Error happening when running "rake db:create RAILS_ENV='development' "

    - by Dean
    Hi, I am getting this error in my terminal when i execute the command above, Deans-MacBook:depot dean$ rake db:create RAILS_ENV='development' (in /Users/dean/src/RailsBook/depot) Couldn't create database for {"username"=>"root", "adapter"=>"mysql", "database"=>"depot_development", "host"=>"localhost", "password"=>nil}, charset: utf8, collation: utf8_unicode_ci (if you set the charset manually, make sure you have a matching collation) In database config file i have the following: development: adapter: mysql database: depot_development username: root password: host: localhost I have the mysql gem installed and now i am unsure on what to do next. I am running snow leopard on a Macbook. Does anyone know why this error is happening? Thanks in Advance Dean

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  • WCF XmlSerializer assembly not speeding up first request

    - by Matt Dearing
    I am generating proxy classes to a clients java webservice wsdls and xsd files with svcutil. The first call made to each service proxy class takes a very long time. I was hoping to speed this up by generating the XmlSerializers assembly myself (based on the article How to: Improve the Startup Time of WCF Client Applications using the XmlSerializer), but when I do the first call to each service still takes the same amount of time. Here are the steps I am following: //generate strong name key file sn -k Blah.snk //generate the proxy class file svcutil blah.wsdl blah2.wsdl blah3.wsdl ... base.xsd blah.xsd ... /UseSerializerForFaults /ser:XmlSerializer /n:*,SomeNamespace /out:Blah.cs //compile the class into an assembly signing it with the strong name key file csc /target:library /keyfile:Blah.snk /out:Blah.dll Blah.cs //generate the XmlSerializer code this will give us Blah.XmlSerializers.dll.cs svcutil /t:xmlSerializer Blah.dll //compile the xmlserializer code into its own dll using the same key to sign it and referencing the original dll csc /target:library /keyfile:Blah.snk /out:Blah.XmlSerializers.dll Blah.XmlSerializers.dll.cs /r:Blah.dll I then create a standard Console application that references both Blah.dll and Blah.XmlSerializers.dll. I will then try something like: //BlahProxy is one of the generated service proxy classes BlahProxy p = new BlahProxy(); //this call takes 30ish seconds p.SomeMethod(); BlahProxy p2 = new BlahProxy(); //this call takes < 1 second p2.SomeMethod(); //BlahProx2y is one of the generated service proxy classes BlahProxy2 p3 = new BlahProxy2(); //this call takes 30ish seconds p3.SomeMethod(); BlahProxy2 p4 = new BlahProxy2(); //this call takes < 1 second p4.SomeMethod(); I know that the problem is not server side because I don't see the request made in Fiddler until around 29 seconds. Subsequent calls to each service take < 1 second, so thats why I was hoping the main slow down was the .net runtime generating the xmlserializer code itself, compiling it and loading the assembly. I figured this would be the reason the first call to each service is slow and the rest are fast. Unfortunatley, me generating the code myself is not speeding anything up. Does anyone see what I am doing wrong?

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  • Rogue black-box java application not responding to standard input redirect

    - by Stefan Kendall
    I have an external java application (blackbox), which requires authentication. I need to run this application in a batch setting, but it seems to be reading from standard input in some nonstandard way. That is, if I set the calling of the program to redirect STDIN to a file (... <password.txt) or pipe data to it (echo mypasword | ...), it does not recognize the input. As I run it, also, it seems to intercept Cntrl+c and Cntrl+d and Cntrl+z as legitimate password characters, so it must be doing something odd and not just reading from standard in. Any idea what this application could be doing to read in input? I need to be able to send it information programmatically, and I'm stumped for the moment.

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  • creating enumeration using .NET's CodeDom

    - by Manish Sinha
    Hi, I want to create an Enumeration using CodeDom API. I have searched enough on the internet and I get results which are hardly of any use. What I want to generate is public enum bug_tracker_type { [Description("Bugzilla")] Bugzilla, [Description("Debbugs")] Debbugs, [Description("PHP Project Bugtracker")] PHP_Project_Bugtracker, [Description("Google Code")] Google_Code } I used CodeTypeDeclaration and set it's IsEnum property as true, created a name, and set it's Attributes. Now the biggest problem is how to populate the body? I tried CodeTypeMember mem = new CodeTypeMember(); mem.Name = WadlSharpUtils.CreateIdentifier(discreteValue.value); mem.CustomAttributes.Add(new CodeAttributeDeclaration(discreteValue.value)); // enumCandidate is an instance of CodeTypeDeclaration enumCandidate.Members.Add(mem); Though using this solution I can generate the Description attributes, the end of line would be ; and not ,

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  • Tweepy + App Engine Example OAuth Help

    - by Wasauce
    Hi I am trying to follow the Tweepy App Engine OAuth Example app in my app but am running into trouble. Here is a link to the tweepy example code: http://github.com/joshthecoder/tweepy-examples Specifically look at: http://github.com/joshthecoder/tweepy-examples/blob/master/appengine/oauth_example/handlers.py Here is the relevant snippet of my code [Ignore the spacing problems]: try: authurl = auth.get_authorization_url() request_token = auth.request_token db_user.token_key = request_token.key db_user.token_secret = request_token.secret db_user.put() except tweepy.TweepError, e: # Failed to get a request token self.generate('error.html', { 'error': e, }) return self.generate('signup.html', { 'authurl': authurl, 'request_token': request_token, 'request_token.key': request_token.key, 'request_token.secret': request_token.secret, }) As you can see my code is very similar to the example. However, when I compare the version of the request_token.key and request_token.secret that are rendered on my signup page (this is for the request_token.key and request_token.secret found in the datastore. Any guidance on what I am doing wrong here? Thanks! Reference Links:

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  • SSH login with expect(1). How to exit expect and remain in SSH?

    - by Koroviev
    So I wanted to automate my SSH logins. The host I'm with doesn't allow key authentication on this server, so I had to be more inventive. I don't know much about shell scripting, but some research showed me the command 'expect' and some scripts using it for exactly this purpose. I set up a script and ran it, it worked perfectly to login. #!/usr/bin/env expect -f set password "my_password" match_max 1000 spawn ssh -p 2222 "my_username"@11.22.11.22 expect "*?assword:*" send -- "$password\r" send -- "\r" expect eof Initially, it runs as it should. Last login: Wed May 12 21:07:52 on ttys002 esther:~ user$ expect expect-test.exp spawn ssh -p 2222 [email protected] [email protected]'s password: Last login: Wed May 12 15:44:43 2010 from 20.10.20.10 -jailshell-3.2$ But that's where the success ends. Commands do not work, but hitting enter just makes a new line. Arrow keys and other non-alphanumeric keys produce symbols like '^[[C', '^[[A', '^[OQ' etc.[1] No other prompt appears except the two initially created by the expect script. Any ignored commands will be executed by my local shell once expect times out. An example: -jailshell-3.2$ whoami ls pwd hostname (...time passes, expect times out...) esther:~ user$ whoami user esther:~ ciaran$ ls Books Documents Movies Public Code Downloads Music Sites Desktop Library Pictures expect-test.exp esther:~ ciaran$ pwd /Users/ciaran esther:~ ciaran$ hostname esther.local As I said, I have no shell scripting experience, but I think it's being caused because I'm still "inside of" expect, but not "inside of" SSH. Is there any way to terminate expect once I've logged in, and have it hand over the SSH session to me? I've tried commands like 'close' and 'exit', after " send -- "\r" ". Yeah, they do what I want and expect dies, but it vindictively takes the SSH session down with it, leaving me back where I started. What I really need is for expect to do its job and terminate, leaving the SSH session back in my hands as if I did it manually. All help is appreciated, thanks. [1] I know there's a name for this, but I don't know what it is. And this is one of those frightening things which can't be googled, because the punctuation characters are ignored. As a side question, what's the story here?

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  • Signing in to Twitter from iPhone - is the cake poisoned?

    - by Tristan
    Hi there, I'm using MGTwitterEngine to add Twitter functionality to my app. It's very easy to simply prompt the user for a username and password and then start posting. Strangely, however, I've noticed other apps (eg Foursquare and Brightkite) require you to visit their website to associate your Twitter account with your foursquare/brightkite/whatever account. Why do they do it this way? Is there a reason why my app shouldn't prompt the user for a Twitter username and password, even though it would be so easy? Thanks a bunch! Tristan

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  • GWT load testing with jmeter

    - by user180152
    Hi folks, I have a GWT application and wanna to test load and functionality using a tool like jmeter. I am not sure jmeter is right tool for GWT. Can anybody direct me to proper tool or can tell me how to do it with jmeter? I want to test login functionality: I have two text box 'User name' and 'Password' on login screen and want to test how many users can log in simultaneously, how much time a round trip to server it takes. Don't know how jmeter can get 'user name' and 'password' and can submit it to validate against DB for GWT application? Thanks in advance.

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  • How do I debug a Net::HTTPInternalServerError error when using Mechanize?

    - by Janak
    c:/ruby/lib/ruby/gems/1.8/gems/mechanize-1.0.0/lib/mechanize.rb:259:in `get': 500 => Net::HTTPInternalServerError (Mechanize::ResponseCodeError) I get the above error when I try to navigate to the following webpage http://fakewebsite.com//admin/edit_building.cfm?page=buildings&updateMode=yes&id=1251 I can navigate just fine when copy and paste the link into a browser. Note: This website does require a login, which I handle with code like the following $agent = Mechanize.new $agent.get('http://fakewebsite//admin/login.cfm?res=-5') form = $agent.page.forms.first form.EMail = "admin" form.Password = "password" form.submit This login works just fine, since I access other webpages protected by the login. I'm not sure where to go from here, any suggestions?

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  • getting internal server error using rest-client in ruby to post to HTTP POST

    - by Angela
    Hi, this is my code and I don't know how to debug it because I just get an "internal server error": I am trying to HTTP POST to an external ASPX: def upload uri = 'https://api.postalmethods.com/2009-02-26/PostalWS.asmx' #postalmethods URI #https://api.postalmethods.com/2009-02-26/PostalWS.asmx?op=UploadFile #http://www.postalmethods.com/method/2009-02-26/UploadFile @postalcard = Postalcard.find(:last) #Username=string&Password=string&MyFileName=string&FileBinaryData=string&FileBinaryData=string&Permissions=string&Description=string&Overwrite=string filename = @postalcard.postalimage.original_filename filebinarydata = File.open("#{@postalcard.postalimage.path}",'rb') body = "Username=me&Password=sekret&MyFileName=#{filename}&FileBinaryData=#{filebinarydata}" @response = RestClient.post(uri, body, #body as string {"Content-Type" => 'application/x-www-form-urlencoded', "Content-Length" => @postalcard.postalimage.size} # end headers ) #close arguments to Restclient.post end

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