Search Results

Search found 40581 results on 1624 pages for 'mysql select db'.

Page 233/1624 | < Previous Page | 229 230 231 232 233 234 235 236 237 238 239 240  | Next Page >

  • What schema documentation tools exist for PostgreSQL

    - by Brad Koch
    MySQL has MySQL Workbench for designing and documenting your schema, and generates CREATE and ALTER scripts based on your design. We're looking at migrating to PostgreSQL in the near future, and we do need a practical way of documenting and modifying the schema structure. What similar tools exist for Postgres (that are OS X/Linux compatible)? Alternatively, what equivalent conventions would be followed for designing and documenting the structure of your Postgres database?

    Read the article

  • Select (loop) or command not working in shell-script

    - by user208098
    I've been tinkering with Linux and Unix for years but still a novice in my mind and recently find myself trying to be more pro with it as I work in IT. So with that notion I'm studying shell scripting. I've hit a snag in ubuntu using the latest version 13.10 Saucy. When I use the select command in a sh script it doesn't work, depending on how I format the command it will either return Unexpected "do" or Unexpected "done". See the following two examples: This section of code produces an unexpected "do" error: #/bin/bash PS3='Please enter your choice' select opt in option1 option2 option3 quit do case $opt in "option1") echo "you chose choice 1" ;; "option2") echo "you chose choice 2" ;; "option3") echo "you chose choice 3" ;; "quit") break ;; *) echo invalid option ;; esac done This section of code produces an unexpected "done" error. #/bin/bash PS3='Please enter your choice' select opt in option1 option2 option3 quit ; do case $opt in "Option1") echo "you chose choice 1" ;; "Option2") echo "you chose choice 2" ;; "Option3") echo "you chose choice 3" ;; "quit") break ;; *) echo invalid option ;; esac done When I enter these parameters into the command line interactively or manually I get the desired result which is a list of choices to choose from. However when executed from a script I get the before mentioned errors. Also a side note I have tried this in Fedora as a script and it worked perfectly so my question is why isn't it working in Ubuntu, is this a difference between RHL and Debian? Or is it a bug in the latest version of Ubuntu? Thanks in advance for any help! KG

    Read the article

  • ???????/???MySQL?? ???

    - by user788995
    ????? ??:2012/05/28 ??:??????/?? MySQL???????????????????????????????????????????????MySQL?? ????????????????MySQL????????????????????? MySQL??????????????????????? ????????? ????????????????? http://otndnld.oracle.co.jp/ondemand/otn-seminar/movie/120518_MySQL%20Nyumon%20Jissen.wmv http://otndnld.oracle.co.jp/ondemand/otn-seminar/movie/mp4/120518_MySQL%20Nyumon%20Jissen.mp4 http://www.oracle.com/technetwork/jp/ondemand/mysql/120518-mysql-nyumon-jissen-jp-1641036-ja.pdf

    Read the article

  • OTN???DB???????????????·Oracle ACE????????????????!

    - by OTN-J Master
    ??????????? ???????????????????????????????????????? ????????????????????????”??????”??????????????????????????????????????????????????????????????????????????????????????(1)?????????????????(????????)?(2)?????????????????????(???????)????????????2??????????????????????????????????????????????????? ???????????????????????????????????????????????????????????????????????????? ????Oracle DBA & Developer Day??????????????????????????????????????????????????????????????????????????????????????????????OTN?????????????????? 2012???????????????????????????????? ?????????????? (??????) ?23????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????? >> ??????????????????! DBA??? (??????) ?12? ???????????????????????(1)????2?????????????????????????????????????????????????????????????????????????????????????1???????1?????????????????????????????????????????1?????????????????????????????????????????????????????????????????????????????????????????????????????????????????I/O???????????????????????????????????????????????>> ????? ????????Oracle Database?SQL?? (Oracle ACE ?? ???) (??????) ~Oracle SQL???????????????? ~ SQL??????????????????????Oracle SQL??????????????????????????????SQL???????????????? SQL?????????????????????????SQL????????????????????? ?8? Pivot?UnPivot?1? Pivot?UnPivot?? (Pivot?UnPivot??/select???Pivot?UnPivot?????)?2? Pivot???? (Pivot????/Pivot????/Pivot??Pivot???????/Pivot??????)?3? UnPivot???? (UnPivot????/UnPivot????/UnPivot??UnPivot???????/UnPivot??????) >> ?????

    Read the article

  • ??! ??! Oracle/DB??????~2011?1??????????(???)

    - by Yusuke.Yamamoto
    2011?1???????????(???)?????????????????? ????????RAC/ASM?????????????????? ??????????????????????????? Oracle GoldenGate ???/????????????? ???????????????! ??! Oracle????????????????????????????????????????? ???! ??! Oracle????????????????????? ???! ??! Oracle????????? ????????????Oracle Database 11gR2 ??????????????? Oracle Database 11gR2(11.2.0.2) ???????????????? ????????????????????????? Oracle Database 11gR2(11.2.0.2)????????????:???PSR???????? ?? ???? ???? ??? ??????(RAC) ?????????Oracle Database 11gR2 RAC ?????????·??? ASM ? Microsoft Windows x86-64 ??? ?????? ??????????????!? Oracle Database 11g Release2 - Windows? ??????????? ??? ?????? ??????Oracle Database 11gR2 Oracle Grid Infrastructure ?????? ??? ???? ???????????????!? ?????????? ??? ??????? ??????Oracle Database 11gR2 ???????????????? ??? ??????? ???????/??????????!? Export/Import??? ??? ??????? ???????/?????!! ???????·?????? ~Statspack??~ ??? ????? ????????Oracle GoldenGate:?????!! DB??/Upgrade????????? New! ??? ??????? ???????/??????????!? ???????·???????? ??? ??????? ???????????! ??! Oracle????????? ?????? New!

    Read the article

  • How to make MySQL utilize available system resources, or find "the real problem"?

    - by anonymous coward
    This is a MySQL 5.0.26 server, running on SuSE Enterprise 10. This may be a Serverfault question. The web user interface that uses these particular queries (below) is showing sometimes 30+, even up to 120+ seconds at the worst, to generate the pages involved. On development, when the queries are run alone, they take up to 20 seconds on the first run (with no query cache enabled) but anywhere from 2 to 7 seconds after that - I assume because the tables and indexes involved have been placed into ram. From what I can tell, the longest load times are caused by Read/Update Locking. These are MyISAM tables. So it looks like a long update comes in, followed by a couple 7 second queries, and they're just adding up. And I'm fine with that explanation. What I'm not fine with is that MySQL doesn't appear to be utilizing the hardware it's on, and while the bottleneck seems to be the database, I can't understand why. I would say "throw more hardware at it", but we did and it doesn't appear to have changed the situation. Viewing a 'top' during the slowest times never shows much cpu or memory utilization by mysqld, as if the server is having no trouble at all - but then, why are the queries taking so long? How can I make MySQL use the crap out of this hardware, or find out what I'm doing wrong? Extra Details: On the "Memory Health" tab in the MySQL Administrator (for Windows), the Key Buffer is less than 1/8th used - so all the indexes should be in RAM. I can provide a screen shot of any graphs that might help. So desperate to fix this issue. Suffice it to say, there is legacy code "generating" these queries, and they're pretty much stuck the way they are. I have tried every combination of Indexes on the tables involved, but any suggestions are welcome. Here's the current Create Table statement from development (the 'experimental' key I have added, seems to help a little, for the example query only): CREATE TABLE `registration_task` ( `id` varchar(36) NOT NULL default '', `date_entered` datetime NOT NULL default '0000-00-00 00:00:00', `date_modified` datetime NOT NULL default '0000-00-00 00:00:00', `assigned_user_id` varchar(36) default NULL, `modified_user_id` varchar(36) default NULL, `created_by` varchar(36) default NULL, `name` varchar(80) NOT NULL default '', `status` varchar(255) default NULL, `date_due` date default NULL, `time_due` time default NULL, `date_start` date default NULL, `time_start` time default NULL, `parent_id` varchar(36) NOT NULL default '', `priority` varchar(255) NOT NULL default '9', `description` text, `order_number` int(11) default '1', `task_number` int(11) default NULL, `depends_on_id` varchar(36) default NULL, `milestone_flag` varchar(255) default NULL, `estimated_effort` int(11) default NULL, `actual_effort` int(11) default NULL, `utilization` int(11) default '100', `percent_complete` int(11) default '0', `deleted` tinyint(1) NOT NULL default '0', `wf_task_id` varchar(36) default '0', `reg_field` varchar(8) default '', `date_offset` int(11) default '0', `date_source` varchar(10) default '', `date_completed` date default '0000-00-00', `completed_id` varchar(36) default NULL, `original_name` varchar(80) default NULL, PRIMARY KEY (`id`), KEY `idx_reg_task_p` (`deleted`,`parent_id`), KEY `By_Assignee` (`assigned_user_id`,`deleted`), KEY `status_assignee` (`status`,`deleted`), KEY `experimental` (`deleted`,`status`,`assigned_user_id`,`parent_id`,`date_due`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 And one of the ridiculous queries in question: SELECT users.user_name assigned_user_name, registration.FIELD001 parent_name, registration_task.status status, registration_task.date_modified date_modified, registration_task.date_due date_due, registration.FIELD240 assigned_wf, if(LENGTH(registration_task.description)>0,1,0) has_description, registration_task.* FROM registration_task LEFT JOIN users ON registration_task.assigned_user_id=users.id LEFT JOIN registration ON registration_task.parent_id=registration.id where (registration_task.status != 'Completed' AND registration.FIELD001 LIKE '%' AND registration_task.name LIKE '%' AND registration.FIELD060 LIKE 'GN001472%') AND registration_task.deleted=0 ORDER BY date_due asc LIMIT 0,20; my.cnf - '[mysqld]' section. [mysqld] port = 3306 socket = /var/lib/mysql/mysql.sock skip-locking key_buffer = 384M max_allowed_packet = 100M table_cache = 2048 sort_buffer_size = 2M net_buffer_length = 100M read_buffer_size = 2M read_rnd_buffer_size = 160M myisam_sort_buffer_size = 128M query_cache_size = 16M query_cache_limit = 1M EXPLAIN above query, without additional index: +----+-------------+-------------------+--------+--------------------------------+----------------+---------+------------------------------------------------+---------+-----------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------------------+--------+--------------------------------+----------------+---------+------------------------------------------------+---------+-----------------------------+ | 1 | SIMPLE | registration_task | ref | idx_reg_task_p,status_assignee | idx_reg_task_p | 1 | const | 1067354 | Using where; Using filesort | | 1 | SIMPLE | registration | eq_ref | PRIMARY,gbl | PRIMARY | 8 | sugarcrm401.registration_task.parent_id | 1 | Using where | | 1 | SIMPLE | users | ref | PRIMARY | PRIMARY | 38 | sugarcrm401.registration_task.assigned_user_id | 1 | | +----+-------------+-------------------+--------+--------------------------------+----------------+---------+------------------------------------------------+---------+-----------------------------+ EXPLAIN above query, with 'experimental' index: +----+-------------+-------------------+--------+-----------------------------------------------------------+------------------+---------+------------------------------------------------+--------+-----------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------------------+--------+-----------------------------------------------------------+------------------+---------+------------------------------------------------+--------+-----------------------------+ | 1 | SIMPLE | registration_task | range | idx_reg_task_p,status_assignee,NewIndex1,tcg_experimental | tcg_experimental | 259 | NULL | 103345 | Using where; Using filesort | | 1 | SIMPLE | registration | eq_ref | PRIMARY,gbl | PRIMARY | 8 | sugarcrm401.registration_task.parent_id | 1 | Using where | | 1 | SIMPLE | users | ref | PRIMARY | PRIMARY | 38 | sugarcrm401.registration_task.assigned_user_id | 1 | | +----+-------------+-------------------+--------+-----------------------------------------------------------+------------------+---------+------------------------------------------------+--------+-----------------------------+

    Read the article

  • how to iterate through multiple select options with jquery

    - by amir
    I was just wondering if it's possible to go through multiple select options and get their values and text(if one is selected get the value and text, if 2 is selected get both of their values and text and so on) I have 15 select boxes in one page? any help would be appreciated. <form> <select class="select" name="select3" id="select3"> <option value="0">0</option> <option value="1.99">1</option> <option value="1.99">2</option> <option value="1.99">3</option> <option value="1.99">4</option> <option value="1.99">5</option> <option value="1.99">6</option> <option value="1.99">7</option> <option value="1.99">8</option> </select> </form> <form> <select class="select" name="select" id="select"> <option value="0">0</option> <option value="1.99">1</option> <option value="1.99">2</option> <option value="1.99">3</option> <option value="1.99">4</option> <option value="1.99">5</option> <option value="1.99">6</option> <option value="1.99">7</option> <option value="1.99">8</option> </select> </form> all the select options have the same class. thanks

    Read the article

  • Query returns too few rows

    - by Tareq
    setup: mysql> create table product_stock( product_id integer, qty integer, branch_id integer); Query OK, 0 rows affected (0.17 sec) mysql> create table product( product_id integer, product_name varchar(255)); Query OK, 0 rows affected (0.11 sec) mysql> insert into product(product_id, product_name) values(1, 'Apsana White DX Pencil'); Query OK, 1 row affected (0.05 sec) mysql> insert into product(product_id, product_name) values(2, 'Diamond Glass Marking Pencil'); Query OK, 1 row affected (0.03 sec) mysql> insert into product(product_id, product_name) values(3, 'Apsana Black Pencil'); Query OK, 1 row affected (0.03 sec) mysql> insert into product_stock(product_id, qty, branch_id) values(1, 100, 1); Query OK, 1 row affected (0.03 sec) mysql> insert into product_stock(product_id, qty, branch_id) values(1, 50, 2); Query OK, 1 row affected (0.03 sec) mysql> insert into product_stock(product_id, qty, branch_id) values(2, 80, 1); Query OK, 1 row affected (0.03 sec) my query: mysql> SELECT IFNULL(SUM(s.qty),0) AS stock, product_name FROM product_stock s RIGHT JOIN product p ON s.product_id=p.product_id WHERE branch_id=1 GROUP BY product_name ORDER BY product_name; returns: +-------+-------------------------------+ | stock | product_name | +-------+-------------------------------+ | 100 | Apsana White DX Pencil | | 80 | Diamond Glass Marking Pencil | +-------+-------------------------------+ 1 row in set (0.00 sec) But I want to have the following result: +-------+------------------------------+ | stock | product_name | +-------+------------------------------+ | 0 | Apsana Black Pencil | | 100 | Apsana White DX Pencil | | 80 | Diamond Glass Marking Pencil | +-------+------------------------------+ To get this result what mysql query should I run?

    Read the article

  • Javascript: how to document.print option value in Select block?

    - by HH
    The below returns [object HTMLOptionElement] while I try to return the value. document.write(document.getElementById("allSelect").options[0]).value; by value, I mean the thing called value there (there is a form around it but not relevant now): <select name="allSelect" id="allSelect" size=3> <option value="1"selected">1</option> <option value="2">2</option> <option value="3">3</option> </select> How can I return the value of an option?

    Read the article

  • MySQL & PHP - select/option lists and showing data to users that still allows me to generate queries

    - by Andrew Heath
    Sorry for the unclear title, an example will clear things up: TABLE: Scenario_victories ID scenid timestamp userid side playdate 1 RtBr001 2010-03-15 17:13:36 7 1 2010-03-10 2 RtBr001 2010-03-15 17:13:36 7 1 2010-03-10 3 RtBr001 2010-03-15 17:13:51 7 2 2010-03-10 ID and timestamp are auto-insertions by the database when the other 4 fields are added. The first thing to note is that a user can record multiple playings of the same scenario (scenid) on the same date (playdate) possibly with the same outcome (side = winner). Hence the need for the unique ID and timestamps for good measure. Now, on their user page, I'm displaying their recorded play history in a <select><option>... list form with 2 buttons at the end - Delete Record and Go to Scenario My script takes the scenid and after hitting a few other tables returns with something more user-friendly like: (playdate) (from scenid) (from side) ######################################################### # 2010-03-10 Road to Berlin #1 -- Germany, Hungary won # # 2010-03-10 Road to Berlin #1 -- Germany, Hungary won # # 2010-03-10 Road to Berlin #1 -- Soviet Union won # ######################################################### [Delete Record] [Go To Scenario] in HTML: <select name="history" size=3> <option>2010-03-10 Road to Berlin #1 -- Germany, Hungary won</option> <option>2010-03-10 Road to Berlin #1 -- Germany, Hungary won</option> <option>2010-03-10 Road to Berlin #1 -- Soviet Union won</option> </select> Now, if you were to highlight the first record and click Go to Scenario there is enough information there for me to parse it and produce the exact scenario you want to see. However, if you were to select Delete Record there is not - I have the playdate and I can parse the scenid and side from what's listed, but in this example all three records would have the same result. I appear to have painted myself into a corner. Does anyone have a suggestion as to how I can get some unique identifying data (ID and/or timestamp) to ride along on this form without showing it to the user? PHP-only please, I must be NoScript compliant!

    Read the article

  • IDs necessary in update script not being stored (or even seen!?) (PHP MySQL)

    - by Derek
    Hi guys, I really need help with this one...have spent 3 hours trying to figure it out... Basically, I have 3 tables necessary for this function to work (the query and PHP)... Authors, Books and Users. An author can have many books, and a user can have many books - that's it. When the admin user selects to update a book, they are presented with a form, displaying the current data within the fields, very straight forward... However there is one tricky part, the admin user can change the author for a book (incase they make a mistake) and also change the user for which the book is associated with. When I select to update the single book information I am not getting any values what so ever for author_id or user_id. Meaning that when the user updates the book info, the associations with the user and author is being scrapped altogether (when before there was an association)... I cannot see why this is happening because I can clearly see the IDs for the users and authors for my option values (this is because they are in select dropdowns). Here is what my sql to retrieve the user ID is: SELECT user_id, name FROM users and then i have my select options which brings up all the users in the system: <label>This book belongs to:</label> <select name="name" id="name"> <option value="<?php echo $row['user_id']?>" SELECTED><?php echo $row['name']?> - Current</option> <?php while($row = mysql_fetch_array($result)) { ?> <option value="<?php echo $row['user_id']; if (isset($_POST['user_id']));?>"><?php echo $row['name']?></option> <?php } ?> In the presented HTML form, I can select the users (by name) and within the source code I can see the IDs (for the value) matching against the names of the users. Finally, in my script that performs the update, I have this: $book_id = $_POST['book_id']; $bookname = $_POST['bookname']; $booklevel = $_POST['booklevel']; $author_id = $_POST['author_id']; $user_id = $_POST['user_id']; $sql = "UPDATE books SET bookname= '".$bookname."', booklevel= '".$booklevel."', author_id='".$author_id."', user_id= '".$user_id."' WHERE book_id = ".$book_id; The result of this query returns no value for either author_id or user_id... Obviously in this question I have given the information for the user stuff (with the HTML being displayed) but im guessing that I have the same problem with authors aswell... How can I get these ID's passed to the script so that the change can be acknowledge!! :(

    Read the article

  • Can SqlAnywhere's UltraLiteJ DB tables be viewed in the Database Explorer of the Eclipse IDE

    - by Tobias
    Hi, I am developing a Blackberry app which should be able to access a DB. Here is my development environment and the tools I am using: Eclipse (Galileo) IDE with the Blackberry plugin installed. Blackberry OS 5.0 SQLAnywhere's DB 11 with UltraLiteJ (I am targeting Blackberrys running OS 4.1 and above) I have successfully executed a sample project for building a Blackberry application that uses the UltraLiteJ DB, following the tutorial in the UltraLiteJ documentation*. The tutorial creates, populates and retrieves data from the DB using java code. Now, I want to be able to access the tables and view data in them from the Eclipse IDE. Something similar to the FireFox plugin for SqlLite or say the Enterprise Manager for Sql Server 2005 which is a DB Explorer providing access to the StoredProcedures, Views, DB Diagrams etc. for a Database. Can someone please direct me as to how to tackle this problem? I hope the question is descriptive and clear. Much Obliged. *http://dcx.sybase.com/index.html#1101en/ulj_en11/uj-ch03.html

    Read the article

  • [SQL] How to SELECT TOP 5 and then the following 5?

    - by Crays
    Hi guys, as the comments always have it, you can select to show the top 5 comments (which i know how) and if there is more than 5, you can click a link and it will show the following 5 comments. The problem is that i don't know how the code should be for it to show the next 5. Better idea of what i'm saying Let's say i have 10 comments, i use SELECT * FROM news ORDER BY ID DESC LIMIT 5 that will show the TOP 5 comments say, the comments with ID 10,9,8,7,6 but what if i want the comments with ID 5,4,3,2,1 ?

    Read the article

  • How to update a table using a select group by in a second one as the data source in MySQL?

    - by Jader Dias
    I can't do this in MySQL UPDATE tableA, tableB SET tableA.column1 = SUM(tableB.column2) WHERE tableA.column3 = tableB.column4 GROUP BY tableB.column4 ; Neither can I UPDATE tableA, ( SELECT SUM(tableB.column2) sumB, tableB.column4 FROM tableB GROUP BY tableB.column4 ) t1 SET tableA.column1 = sumB WHERE tableA.column3 = column4 ; Besides it being illegal code, I think you can understand what I tried to do with the queries above. Both of them had the same intent. How can I do that in MySQL?

    Read the article

  • How should I build a privacy drop-down (select) menu?

    - by animuson
    I'm trying to build something similar to Facebook's privacy selection menu, except without the 'custom' option. It will only list a few options such as 'show to all', 'show to friends only', or 'completely hidden'. Right now I'm thinking of using simple JavaScript to change a hidden input field to the new value they click on, so if they clicked on the division for 'show to friends only' it would change the corresponding field, say 'email_privacy', to 1. Is there a better way to do this or am I pretty much on track? P.S. I am not planning on using a select element, I was planning on building a custom drop-down menu using CSS since select elements are so highly non-customizable. I'm doing it this way to save space, rather than having this massive selection menu at the right which takes up a bunch of space. Note: I'm not really interested in using jQuery, that's just extra libraries and crap that I don't want to load. I can do it in JavaScript just as easily so I might as well use that.

    Read the article

  • How can you tell MYSQL to TRIM the X number of characters, beginning from the Back?

    - by Tim
    How do I write the following in MYSQL? SELECT SUBSTRING(value - (1 TRAILING CHARACTER)) FROM table; Basically substring(value, 2) trims the first letters. But I need to trim the last letters. I can't use substring(value, -4, 3) because I don't know the length of the value. Here's another example: SELECT * FROM table WHERE SUBSTRING(value - (4 TRAILING CHARACTER)) in (SELECT SUBSTRING(value - (1 TRAILING CHARACTER)) FROM table);

    Read the article

  • Open Select using Javascript/jQuery?

    - by Newbie
    Hello! Is there a way to open a select box using Javascript (and jQuery)? <select style="width:150px;"> <option value="1">1</option> <option value="2">Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nunc arcu nunc, rhoncus ac dignissim at, rhoncus ac tellus.</option> <option value="3">3</option> </select> I have to open my select, cause of ie bug. All versions of IE (6,7,8) cut my options. As far as I know, there is no css bugfix for this. At the moment I try to do the following: var original_width = 0; var selected_val = false; if (jQuery.browser.msie) { $('select').click(function(){ if (selected_val == false){ if(original_width == 0) original_width = $(this).width(); $(this).css({ 'position' : 'absolute', 'width' : 'auto' }); }else{ $(this).css({ 'position' : 'relative', 'width' : original_width }); selected_val = false; } }); $('select').blur(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); }); $('select').blur(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); }); $('select').change(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); }); $('select option').click(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); selected_val = true; }); } But clicking on my select the first time will change the width of the select but I have to click again to open it.

    Read the article

  • PostgreSQL: return select count(*) from old_ids;

    - by Alexander Farber
    Hello, please help me with 1 more PL/pgSQL question. I have a PHP-script run as daily cronjob and deleting old records from 1 main table and few further tables referencing its "id" column: create or replace function quincytrack_clean() returns integer as $BODY$ begin create temp table old_ids (id varchar(20)) on commit drop; insert into old_ids select id from quincytrack where age(QDATETIME) > interval '30 days'; delete from hide_id where id in (select id from old_ids); delete from related_mks where id in (select id from old_ids); delete from related_cl where id in (select id from old_ids); delete from related_comment where id in (select id from old_ids); delete from quincytrack where id in (select id from old_ids); return select count(*) from old_ids; end; $BODY$ language plpgsql; And here is how I call it from the PHP script: $sth = $pg->prepare('select quincytrack_clean()'); $sth->execute(); if ($row = $sth->fetch(PDO::FETCH_ASSOC)) printf("removed %u old rows\n", $row['count']); Why do I get the following error? SQLSTATE[42601]: Syntax error: 7 ERROR: syntax error at or near "select" at character 9 QUERY: SELECT select count(*) from old_ids CONTEXT: SQL statement in PL/PgSQL function "quincytrack_clean" near line 23 Thank you! Alex

    Read the article

  • Mysql's LIKE is missbehaving with Hebrew and backslashes, why?

    - by Itay Moav
    I have the following SQL query which returns the correct results: SELECT * FROM `tags` WHERE tag_name = '???\\\"?-???????' If I change it to SELECT * FROM `tags` WHERE tag_name LIKE '???\\\"?-???????' or to SELECT * FROM `tags` WHERE tag_name LIKE '???\\\"?-???????%' It doesn't work. It will work if I remove all the backslashes and " from the query.

    Read the article

  • Why SELECT N + 1 with no foreign keys and LINQ?

    - by Daniel Flöijer
    I have a database that unfortunately have no real foreign keys (I plan to add this later, but prefer not to do it right now to make migration easier). I have manually written domain objects that map to the database to set up relationships (following this tutorial http://www.codeproject.com/Articles/43025/A-LINQ-Tutorial-Mapping-Tables-to-Objects), and I've finally gotten the code to run properly. However, I've noticed I now have the SELECT N + 1 problem. Instead of selecting all Product's they're selected one by one with this SQL: SELECT [t0].[id] AS [ProductID], [t0].[Name], [t0].[info] AS [Description] FROM [products] AS [t0] WHERE [t0].[id] = @p0 -- @p0: Input Int (Size = -1; Prec = 0; Scale = 0) [65] Controller: public ViewResult List(string category, int page = 1) { var cat = categoriesRepository.Categories.SelectMany(c => c.LocalizedCategories).Where(lc => lc.CountryID == 1).First(lc => lc.Name == category).Category; var productsToShow = cat.Products; var viewModel = new ProductsListViewModel { Products = productsToShow.Skip((page - 1) * PageSize).Take(PageSize).ToList(), PagingInfo = new PagingInfo { CurrentPage = page, ItemsPerPage = PageSize, TotalItems = productsToShow.Count() }, CurrentCategory = cat }; return View("List", viewModel); } Since I wasn't sure if my LINQ expression was correct I tried to just use this but I still got N+1: var cat = categoriesRepository.Categories.First(); Domain objects: [Table(Name = "products")] public class Product { [Column(Name = "id", IsPrimaryKey = true, IsDbGenerated = true, AutoSync = AutoSync.OnInsert)] public int ProductID { get; set; } [Column] public string Name { get; set; } [Column(Name = "info")] public string Description { get; set; } private EntitySet<ProductCategory> _productCategories = new EntitySet<ProductCategory>(); [System.Data.Linq.Mapping.Association(Storage = "_productCategories", OtherKey = "productId", ThisKey = "ProductID")] private ICollection<ProductCategory> ProductCategories { get { return _productCategories; } set { _productCategories.Assign(value); } } public ICollection<Category> Categories { get { return (from pc in ProductCategories select pc.Category).ToList(); } } } [Table(Name = "products_menu")] class ProductCategory { [Column(IsPrimaryKey = true, Name = "products_id")] private int productId; private EntityRef<Product> _product = new EntityRef<Product>(); [System.Data.Linq.Mapping.Association(Storage = "_product", ThisKey = "productId")] public Product Product { get { return _product.Entity; } set { _product.Entity = value; } } [Column(IsPrimaryKey = true, Name = "products_types_id")] private int categoryId; private EntityRef<Category> _category = new EntityRef<Category>(); [System.Data.Linq.Mapping.Association(Storage = "_category", ThisKey = "categoryId")] public Category Category { get { return _category.Entity; } set { _category.Entity = value; } } } [Table(Name = "products_types")] public class Category { [Column(Name = "id", IsPrimaryKey = true, IsDbGenerated = true, AutoSync = AutoSync.OnInsert)] public int CategoryID { get; set; } private EntitySet<ProductCategory> _productCategories = new EntitySet<ProductCategory>(); [System.Data.Linq.Mapping.Association(Storage = "_productCategories", OtherKey = "categoryId", ThisKey = "CategoryID")] private ICollection<ProductCategory> ProductCategories { get { return _productCategories; } set { _productCategories.Assign(value); } } public ICollection<Product> Products { get { return (from pc in ProductCategories select pc.Product).ToList(); } } private EntitySet<LocalizedCategory> _LocalizedCategories = new EntitySet<LocalizedCategory>(); [System.Data.Linq.Mapping.Association(Storage = "_LocalizedCategories", OtherKey = "CategoryID")] public ICollection<LocalizedCategory> LocalizedCategories { get { return _LocalizedCategories; } set { _LocalizedCategories.Assign(value); } } } [Table(Name = "products_types_localized")] public class LocalizedCategory { [Column(Name = "id", IsPrimaryKey = true, IsDbGenerated = true, AutoSync = AutoSync.OnInsert)] public int LocalizedCategoryID { get; set; } [Column(Name = "products_types_id")] private int CategoryID; private EntityRef<Category> _Category = new EntityRef<Category>(); [System.Data.Linq.Mapping.Association(Storage = "_Category", ThisKey = "CategoryID")] public Category Category { get { return _Category.Entity; } set { _Category.Entity = value; } } [Column(Name = "country_id")] public int CountryID { get; set; } [Column] public string Name { get; set; } } I've tried to comment out everything from my View, so nothing there seems to influence this. The ViewModel is as simple as it looks, so shouldn't be anything there. When reading this ( http://www.hookedonlinq.com/LinqToSQL5MinuteOVerview.ashx) I started suspecting it might be because I have no real foreign keys in the database and that I might need to use manual joins in my code. Is that correct? How would I go about it? Should I remove my mapping code from my domain model or is it something that I need to add/change to it? Note: I've stripped parts of the code out that I don't think is relevant to make it cleaner for this question. Please let me know if something is missing.

    Read the article

  • Ruby On Rails : db:migrate do not run

    - by user332219
    Hi, When i run this command i have an error : rake db:migrate --trace rake aborted! NoMethodError: undefined method `ord' for 0:Fixnum: SET NAMES 'utf8' see the log file here : http://patxi.mayol.free.fr/public/trace.txt my database.yml file is here : MySQL. Versions 4.1 and 5.0 are recommended. # development: adapter: mysql encoding: utf8 reconnect: false database: annuaire_development pool: 5 username: root password: host: 127.0.0.1 test: adapter: mysql encoding: utf8 reconnect: false database: annuaire_test pool: 5 username: root password: host: 127.0.0.1 production: adapter: mysql encoding: utf8 reconnect: false database: annuaire_production pool: 5 username: root password: host: 127.0.0.1 Thanks My config : WampServer 2.0 with MySQL 5.0.51a Aptana 2.0.4 Ruby 1.8.5 Gems: actionmailer (2.3.4, 2.3.2) actionpack (2.3.4, 2.3.2) activerecord (2.3.4, 2.3.2) activeresource (2.3.4, 2.3.2) activesupport (2.3.4, 2.3.2) cgi_multipart_eof_fix (2.5.0) fastthread (1.0.1) gem_plugin (0.2.3) linecache (0.43) mongrel (1.1.5) mysql (2.8.1, 2.7.3) rack (1.0.0) rails (2.3.4, 2.3.2) rake (0.8.7) ruby-debug-base (0.10.3) ruby-debug-ide (0.4.5) sqlite3-ruby (1.2.1)

    Read the article

  • Is Mysql IF EXIST what should be used for this query?

    - by acctman
    select social_members.* , social_mcouple.* WHERE m_id='".$_SESSION['userid']."' AND c_id='".$_SESSION['userid']."' Select all fields from social_members.* and if social_mcouple.c_id = $_SESSION['userid'] then Select all fields from social_mcouple.* as well. Can this be done with IF EXIST and if so how. Thanks

    Read the article

< Previous Page | 229 230 231 232 233 234 235 236 237 238 239 240  | Next Page >