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  • Mysql-how to update the "domain.com" in "[email protected]"

    - by w00t
    Hi there, In my database I have a lot of users who've misspelled their e-mail address. This in turn causes my postfix to bounce a lot of mails when sending the newsletter. Forms include (but are not limited to) "yaho.com", "yahho .com" etc. Very annoying! So i have been trying to update those record to the correct value. After executing select email from users where email like '%@yaho%' and email not like '%yahoo%'; and getting the list, I'm stuck because I do not know how to update only the yaho part. I need the username to be left intact. So I thought I would just dump the database and use vim to replace, but I cannot escape the @ symbol.. BTW, how do I select all email addresses written in CAPS? select upper(email) from users; would just transform everything into CAPS, whereas I just needed to find out the already-written-in-CAPS mails.

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  • MySQL database design question

    - by Greelmo
    I'm trying to weigh the pros and cons of a database design, and would like to get some feedback as to the best approach. Here is the situation: I have users of my system that have only a few required items (username, password). They can then supply a lot of optional information. This optional information continues to grow as the system grows, so I want to do it in such a way that adding new optional information is easy. Currently, I have a separate table for each piece of information. For example, there's a table called 'names' that holds 'user_id', 'first_name', and 'last_name'. There's 'address', 'occupation', etc. You get the drift. In most cases, when I talk to my database, I'm looking only for users with one particular qualifier (name, address, etc.). However, there are instances when I want to see what information a user has set. The 'edit account' page, for example, must run queries for each piece of information it wants. Is this wasteful? Is there a way I can structure my queries or my database to make it so I never have to do one query for each piece of information like that without getting my tables to huge? If i want to add 'marital status', how hard will that be if I don't have a one-table-per-attribute system? Thanks in advance.

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  • Show last 4 table entries mysql php

    - by user272899
    I have a movie database Kind of like a blog and I want to display the last 4 created entries. I have a column in my table for timestamp called 'dateadded'. Using this code how would I only display the 4 most recent entries to table <?php //connect to database mysql_connect($mysql_hostname,$mysql_user,$mysql_password); @mysql_select_db($mysql_database) or die("<b>Unable to connect to specified database</b>"); //query databae $query = "SELECT * FROM movielist"; $result=mysql_query($query) or die('Error, insert query failed'); $row=0; $numrows=mysql_num_rows($result); while($row<$numrows) { $id=mysql_result($result,$row,"id"); $imgurl=mysql_result($result,$row,"imgurl"); $imdburl=mysql_result($result,$row,"imdburl"); ?> <div class="moviebox rounded"><a href="http://<?php echo $domain; ?>/viewmovie?movieid=<?php echo $id; ?>" rel="facebox"> <img src="<?php echo $imgurl; ?>" /> <form method="get" action=""> <input type="text" name="link" class="link" style="display:none" value="http://us.imdb.com/Title?<?php echo $imdburl; ?>"/> </form> </a></div> <?php $row++; } ?>

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  • MySQL search Chinese characters

    - by Jasie
    Hello, Let's say I have a row: ??????? Someone enters as a query: ?? Should I break up the characters in the query, and individually perform a LIKE % % match on each character against the row, or is there any easier way to get a row that contains one of the two characters? FULLTEXT won't work with CJK characters. Thanks!

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  • do's and don'ts for writing mysql queries

    - by nik
    One thing I always wonder while writing query is that am I writing most optimized query or not? I know certain things like: 1) using SELECT field1, filed2 instead of SELECT * 2) Giving proper indexes to the tables but I am sure there are more things that should be kept in mind for writing queries, since most of the database can only grow more and optimal query will help gr8 in execution time, Can u share some tips and tricks on writing queries?

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  • MySQL: updating a row and deleting the original in case it becomes a duplicate

    - by Silvio Donnini
    I have a simple table made up of two columns: col_A and col_B. The primary key is defined over both. I need to update some rows and assign to col_A values that may generate duplicates, for example: UPDATE `table` SET `col_A` = 66 WHERE `col_B` = 70 This statement sometimes yields a duplicate key error. I don't want to simply ignore the error with UPDATE IGNORE, because then the rows that generate the error would remain unchanged. Instead, I want them to be deleted when they would conflict with another row after they have been updated I'd like to write something like: UPDATE `table` SET `col_A` = 66 WHERE `col_B` = 70 ON DUPLICATE KEY REPLACE which unfortunately isn't legal in SQL, so I need help finding another way around. Also, I'm using PHP and could consider a hybrid solution (i.e. part query part php code), but keep in mind that I have to perform this updating operation many millions of times. thanks for your attention, Silvio Reminder: UPDATE's syntax has problems with joins with the same table that is being updated

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  • mysql join Two tables to get records

    - by Saranya
    Hai guys, I have two tables Incharge and property. My property table has three fields 1stIncharge,2ndIncharge and 3rdIncharge. InchargeId is set as foreign key for all the above fields in the property table.. How to write a select statement that joins both the table.. I ve tried a bit but no result select P.Id,P.Name,P.1stIncharge,P.2ndIncharge,P.3rdIncharge,I.Id from Property as P join Incharge as I where (\\How to give condition here \\) Guys 3 fields P.1stIncharge, P.2ndIncharge, P.3rdIncharge has foreign key I.Id Edit: select P.Id,P.Name,P.1stIncharge,P.2ndIncharge,P.3rdIncharge,I1.Id from Property as P inner join Incharge as I1 on I1.Id=P.1stIncharge inner join Incharge as I2 on I2.Id=P.2ndIncharge inner join Incharge as I3 on I3.Id=P.3rdIncharge and this query working

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  • compare string to date on mysql

    - by Mercer
    hello, i have a table with a date, this date is a string i want to compare this string with a date in my request. SELECT FE_CLIENT.* FROM FE_CLIENT WHERE D_DATFINPUBLI < '2010/06/03' How can i cast my column date_deb to a date for compare ..?

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  • Newbie question - MySQL index size

    - by Tommy
    I've just started to investigating how I should optimize my database. Indexing seems to be a good idea, so I want to index a VARCHAR column, the engine is MyISAM. From what I've read, I understand that an index is limited to a size of 1000 bytes. A VARCHAR character is 3 bytes in size. Does this mean that if I want to index a VARCHAR column with 50 rows, I need an index prefix of 6 characters? I came to that number by dividing 1000 with the row number 50, then the bytesize per character that is 3. 1000/50/3=6,66. It seems a little complicated, so I'm just wondering if I'm thinking right? It seems weird to me that you'd only be able to index 333 rows in a VARCHAR column, using a prefix of 1 character.

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  • getting a date array from a mysql database?

    - by user296516
    Hi guys, I have a database with date field is this format "2010.06.11. | 10:26 13" What is need is a php array that would hold all the different dates, .i.e. array[0] = "2010.06.09." array[1] = "2010.06.10." array[2] = "2010.06.11." Currently I am doing it by selecting the whole table, then looping through the result and adding the date substr to an array if it is not already there. But maybe there is a faster way? Thanks.

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  • Php fetch rows from multiple MySQL tables

    - by Jon McIntosh
    Right now I am fetching all of the rows from one of my tables: query = "SELECT * FROM thread WHERE threadid = 2 ORDER BY threadid DESC"; $result = mysql_query($query); $num_rows = mysql_num_rows($result); if((!is_bool($result) || $result) && $num_rows) { while($row = mysql_fetch_array($result)) { $thread = $row['title']; $threadID = $row['threadid']; $poster = $row['postusername']; } What I want to do is go to another table on my database: "post_display", and get the row 'text' where the threadid = 2.

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  • Problem importing mysql triggers generated from mysqldump

    - by OM The Eternity
    I am using phpmyadmin for using the mysqldump query, but as per my requirement i have to create a new database which is clone of the previous one, now in this case when i import the main DB it contain all the trigger information as well with the DB name mentioned in it.. As i import this DB to new one my triggers get imported as well but the trigger_schema are not changed as per new DB.. What could be done to get resolve this problem?

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  • Mysql - What's wrong with the query...?

    - by SpikETidE
    Hi everybody.... I am trying to query a database to find the following If a customer searches for a hotel in a city between dates A and B, find and return the hotels in which rooms are free between the two dates. There will be more than one room in each room type(i.e. 5 Rooms in type A, 10 rooms in Type B etc) and we have to query the db to find only those hotels in which there is atleast one room free in atleast one type. This is my table structure.... **Structure for table 'reservations'** reservation_id hotel_id room_id customer_id payment_id no_of_rooms check_in_date check_out_date reservation_date **Structure for table 'hotels'** hotel_id hotel_name hotel_description hotel_address hotel_location hotel_country hotel_city hotel_type hotel_stars hotel_image hotel_deleted **Structure for table 'rooms'** room_id hotel_id room_name max_persons total_rooms room_price room_image agent_commision room_facilities service_tax vat city_tax room_description room_deleted And this is my query $city_search = '15'; $check_in_date = '29-03-2010'; $check_out_date = '31-03-2010'; $dateFormat_check_in = "DATE_FORMAT('$reservations.check_in_date','%d-%m-%Y')"; $dateFormat_check_out = "DATE_FORMAT('$reservations.check_out_date','%d-%m-%Y')"; $dateCheck = "$dateFormat_check_in >= '$check_in_date' AND $dateFormat_check_out <= '$check_out_date'"; $query = "SELECT $rooms.room_id, $rooms.room_name, $rooms.max_persons, $rooms.room_price, $hotels.hotel_id, $hotels.hotel_name, $hotels.hotel_stars, $hotels.hotel_type FROM $hotels,$rooms,$reservations WHERE $hotels.hotel_city = '$city_search' AND $hotels.hotel_id = $rooms.hotel_id AND $hotels.hotel_deleted = '0' AND $rooms.room_deleted = '0' AND $rooms.total_rooms - (SELECT SUM($reservations.no_of_rooms) as tot FROM $reservations WHERE $dateCheck GROUP BY $reservations.room_id) > '0'"; The number of rooms already reserved in each room type in each hotel will be stored in the reservations table... The thing is the query doesn't return any result at all...even though it should if i calculate it myself manually... I tried running the sub-query alone and i don't get any result... And i have lost quite some amount of hair trying to de-bug this query from yesterday... What's wrong with this...? Or is there a better way to do what i mentioned above...? Thanks for your time... Edit : Code edited to remove an bud... thanks to

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  • mysql concat all field table

    - by hafizan
    Is there a way we can concat all field in the table(1 sql statement)(automatic) ? The reason was before user updated or delete a record,the record will push to another table for future reference.

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  • mysql order-by original "where order"

    - by Benjamin Dobnikar
    I have this order-by problem I canot crack. I select from my table like this: SELECT * FROM 'sidemodules' WHERE name = 'module1' OR name = 'module2' OR 'name3' Which returns me the modules I want. But the modules lie the table, say in this order: module3 module1 module2 And they are returned to me in this order. How can I get them to display in order AS IN THE WHERE CLAUSE (1,2,3) ? Big thanks!

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  • MySQL - display rows of names and addresses grouped by name, where name occures more than once

    - by Stoob
    I have two tables, "name" and "address". I would like to list the last_name and joined address.street_address of all last_name in table "name" that occur more than once in table "name". The two tables are joined on the column "name_id". The desired output would appear like so: 213 | smith | 123 bluebird | 14 | smith | 456 first ave | 718 | smith | 12 san antonia st. | 244 | jones | 78 third ave # 45 | 98 | jones | 18177 toronto place | Note that if the last_name "abernathy" appears only once in table "name", then "abernathy" should not be included in the result. This is what I came up with so far: SELECT name.name_id, name.last_name, address.street_address, count(*) FROM `name` JOIN `address` ON name.name_id = address.name_id GROUP BY `last_name` HAVING count(*) > 1 However, this produces only one row per last name. I'd like all the last names listed. I know I am missing something simple. Any help is appreciated, thanks!

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  • Help with MySQL Query using CASE statement

    - by hairdresser-101
    I am trying to group a number of customers together based on their "Head Office" or "Parent" location. THis works ok except for a flaw which I didn't forsee when I was developing my system... For customers that did not have a "Parent" (standalone business) I defaulted the parent_id to 0. Therefore, my data would look like this: id parent_id customer 1 0 CustName#1 2 4 CustName#2 - Melbourne 3 4 CustName#2 - Sydney 4 0 CustName#2 (Head Office) What I want to do is Group my results together so that I have one row for CustName#1 and one row for CustName#2 BUT my problem is that there is no parent record for parent_id=0 and these rows are being excluded when using an inner join. I've tried using a case statement but that is not working either (parents are still being ignored) Any help would be greatly appreciated. Here is my query (My CASE is basically trying to get the business_name from the customer table based on the parent_id EXCEPT when the parent_id = 0, THEN just use the customer_name that is listed in the job_summary table): SELECT js.month_of_year, (CASE js.parent_id WHEN 0 THEN js.customer_name ELSE c.business_name END) as customer, SUM(js.jobs), SUM(js.total_cost), sum(js.total_sell) FROM JOB_SUMMARY js INNER JOIN customer c on js.parent_id=c.id group by js.month_of_year, (CASE c.parent_id WHEN 0 THEN js.customer_name ELSE c.business_name END) ORDER BY `customer` ASC

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  • double left MYSQL join?

    - by Haroldo
    I've been trying left joins but as there are 2 joins, i think the problem is the 2nd join roots from table_B not table_A. i am not getting any results where there is the required data in the db. I am not getting a query error the query (simplified) SELECT events.*, ven.*, events_genres.* FROM events LEFT JOIN ven //OPTIONAL JOIN ON events.ven_id = ven.ven_id //OPTIONAL JOIN LEFT JOIN events_genres //REQUIRED JOIN ON events.event_id = events_genres.event_id //REQUIRED JOIN WHERE events.date >= '$this->now' AND WHERE events_genres.g_id = $g_id //REQUIRED MATCH ORDER BY date ven = optional, i'll have the info if its there. events_genres = required, i dont want any results that do not have a genre

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  • JDBC with MySQL

    - by Josh K
    I'm working on getting my database to talk to my Java programs. What do I need to get started? Having already read through (and been thoroughly confused, something that does not happen often) with some other turorials I figured I'd best ask here. How do I import a jar file from the local directory? Can someone give me a quick and dirty sample program using the JDBC?

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  • php, mySQL & AJAX: Unable to use sessions across the scripts in the same domain

    - by Devner
    Hi all, I have the following pages: page1.php, page2.php and page3.php. Code in each of them is as below CODE: page1.php <script type="text/javascript"> $(function(){ $('#imgID').upload({ submit_to_url: "page2.php", file_name: 'myfile1', description : "Image", limit : 1, file_types : "*.jpg", }) }); </script> <body> <form action="page3.php" method="post" enctype="multipart/form-data" name="frm1" id="frm1"> //Some other text fields <input type="submit" name="submit" id="submit" value="Submit" /> </form> </body> page2.php <?php session_start(); $a = $_SESSION['a']; $b = $_SESSION['b']; $c = $_SESSION['c']; $res = mysql_query("SELECT col FROM table WHERE col1 = $a AND col2 = $b AND col3 = $c LIMIT 1"); $num_rows = mysql_num_rows($res); echo $num_rows; //echos 0 when in fact it should have been 1 because the data in the Session exists. //Ok let's proceed further //... Do some stuff... //Store some more values and create new session variables (and assume that page1.php is going to be able to use it) $_SESSION['d'] = 'd'; $_SESSION['e'] = 'e'; $_SESSION['f'] = 'f'; if (move_uploaded_file($_FILES['file']['tmp_name'], $file)) { echo "success"; } else { echo "error ".$_FILES['file']['error']; } ?> page3.php <?php session_start(); if( isset($_POST['submit']) ) { //These sessions are non-existent although the AJAX request //to page2.php may have created them when called via AJAX from within page1.php echo $_SESSION['d'].$_SESSION['e'].$_SESSION['f']; ?> } ?> As the code says it I am posting some info via AJAX call from page1.php to page2.php. page2.php is supposed to be able to use the session values from page1.php i.e. $_SESSION['a'], $_SESSION['b'] and $_SESSION['c'] but it does not. Why? How can I fix this? page2.php is creating some more sessions after some processing is done and a response is sent back to page1.php. The submit button of the form on page1.php is hit and the page gets POST'ed to page3.php. But when the SESSION info that gets created in page2.php is echoed, it's blank signifying that SESSIONS from page2.php are not used. How can I fix this? I looked over a lot of information and have spent about 50 hours trying to do different things with my scripts before arriving at the above conclusions. My app. is custom made using function (not OOPS) and does not use any PHP frameworks & I am not even about to use any as my knowledge of OOP concepts is limited any many frameworks are object oriented. I came across race conditions, but the solutions provided don't help too much. One more solution of using DB to hold sessions and seek and retrieve from DB is the last thing on my mind and I really want to avoid creating table, coding and maintaining code for a task as simple as just keeping sessions across pages in the same domain. So my request is: Is there a way that I can solve the above problem(s) via simple coding in present conditions? Any help is appreciated. Thank you.

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  • Return order of MySQL SHOW COLUMNS

    - by rich
    Hey guys. Simple one this, but one I can't seem to find any information on so here goes. I need to find the columns in a specific table, which is no problem.... SHOW COLUMNS FROM tablename LIKE '%ColumnPrefix%'; But I need to know what order they will be returned, preferable by choosing to order the results ascending alphabetically. I have had no luck with using ORDER BY Field. Any ideas? Cheers!

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  • mySQL not saving data?

    - by tony noriega
    i have a PHP contact form that submits data, and an email...: <?php $dbh=mysql_connect ("localhost", "username", "password") or die ('I cannot connect to the database because: ' . mysql_error()); mysql_select_db ("guest"); if (isset($_POST['submit'])) { if (!$_POST['name'] | !$_POST['email']) { echo"<div class='error'>Error<br />Please provide your Name and Email Address so we may properly contact you.</div>"; } else { $age = $_POST['age']; $name = $_POST['name']; $gender = $_POST['gender']; $email = $_POST['email']; $phone = $_POST['phone']; $comments = $_POST['comments']; $query = "INSERT INTO contact_us (age,name,gender,email,phone,comments) VALUES ('$age','$name','$gender','$email','$phone','$comments')"; mysql_query($query); mysql_close(); $yoursite = "Mysite "; $youremail = $email; $subject = "Website Guest Contact Us Form"; $message = "$name would like you to contact them Contact PH: $phone Email: $email Age: $age Gender: $gender Comments: $comments"; $email2 = "[email protected]"; mail($email2, $subject, $message, "From: $email"); echo"<div class='thankyou'>Thank you for contacting us,<br /> we will respond as soon as we can.</div>"; } } ?> The email is coming through fine, but the data is not storing the dbase... am i missing something? Its the same script as i use on another contact us page, only difference is instead of parsing the data on teh same page, i now send this data to a "thankyou.php" page... i tried changing $_POST to $_GET but that killed the page... what am i doing wrong?

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  • Use of HAVING in MySQL

    - by KBrian
    I have a table from which I need to select all persons that have a first name that is not unique and that that set should be selected only if among the persons with a similar first name, all have a different last name. Example: FirstN LastN Bill Clinton Bill Cosby Bill Maher Elvis Presley Elvis Presley Largo Winch I want to obtain FirstN LastN Bill Clinton or FirstN LastN Bill Clinton Bill Cosby Bill Maher I tried this but it does not return what I want. SELECT * FROM Ids GROUP BY FirstN, LastN HAVING (COUNT(FirstN)>1 AND COUNT(LastN)=1)) [Edited my post after Aleandre P. Lavasseur remark]

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