Search Results

Search found 17146 results on 686 pages for 'jquery'.

Page 235/686 | < Previous Page | 231 232 233 234 235 236 237 238 239 240 241 242  | Next Page >

  • Loading an FLV in Facebox with jQuery for IE7 and IE8

    - by Trip
    It goes almost without saying, this works perfectly in Chrome, Firefox, and Safari. IE (any version) being the problem. Objective: I am trying to load JWplayer which loads an FLV from S3 in a Facebox popup. jQuery(document).ready(function($) { $('a[rel*=facebox]').facebox() }) HTML (haml): %li#videoGirl = link_to 'What is HQchannel?', '#player', :rel => 'facebox' .grid_8.omega.alpha#player{:style => 'display: none;'} :javascript var so = new SWFObject('/flash/playerTrans.swf','mpl','640px','360px','0'); so.addParam('allowscriptaccess','always'); so.addParam('allowfullscreen','true'); so.addParam('wmode','transparent'); so.addVariable('file', 'http://hometownquarterlyvideos.s3.amazonaws.com/whatishqchannel.flv&autostart=true&controlbar=none&repeat=always&image=/flash/video_girl/whatishqchannel.jpg&icons=false&screencolor=none&backcolor=FFFFFF&screenalpha=0&overstretch'); so.addVariable('overstretch', 'true') so.write('player'); Problem: Despite the video being set to display: none;. It begins playing anyway. When clicking on the activation div, IE7 pops up a wrong sized blank div with a nav (params are set to not show nav and scrubber), and no buttons on the nav and srubber work. IE8 shows the right size but same behavior with nav and scrubber not working, and blank screen. My guess: I'm thinking that the problem is with the javascript not being called at the right times. It seems it's loading the facebox without the jwplayer. At least I assume. Hence the reason why the nav is there. I thinking that it did not read the javascript for that.

    Read the article

  • jQuery: select checkbox when upload field is clicked

    - by Arne Stephensson
    I'm working on a CMS. When a user wants to replace an existing thumbnail image, they can upload a replacement, and check a checkbox to certify that they are indeed replacing the image. The checkbox seems necessary because otherwise the form submits a blank value (due to the presence of the upload field with no value) and wipes out the existing image without a replacement image being specified. The problem is that I keep forgetting to manually activate the checkbox and the uploaded image does not actually replace the existing one because without the checkbox being clicked, the receiving PHP file does not (by design) process the incoming filename. I suspect that users will have the same problem and I want to keep this from happening by reducing the number of steps required. One solution would be to check the checkbox with jQuery whenever the upload field is clicked. So why doesn't this work: $('#upload_field').click(function () { if ($('#replace_image').attr('checked',true)) { $('#replace_image').removeAttr('checked'); alert('Unchecked'); } else if ($('#replace_image').attr('checked',false)) { $('#replace_image').attr('checked','checked'); alert('Checked'); } });

    Read the article

  • Trying to fadein divs in a sequence, over time, using JQuery

    - by user346602
    Hi, I'm trying to figure out how to make 4 images fade in sequentially when the page loads. The following is my (amateurish) code: Here is the HTML: <div id="outercorners"> <img id="corner1" src="images/corner1.gif" width="6" height="6" alt=""/> <img id="corner2" src="images/corner2.gif" width="6" height="6" alt=""/> <img id="corner3" src="images/corner3.gif" width="6" height="6" alt=""/> <img id="corner4" src="images/corner4.gif" width="6" height="6" alt=""/> </div><!-- end #outercorners--> Here is the JQuery: $(document).ready(function() { $("#corner1").fadeIn("2000", function(){ $("#corner3").fadeIn("4000", function(){ $("#corner2").fadeIn("6000", function(){ $("#corner4").fadeIn("8000", function(){ }); }); }); }); Here is the css: #outercorners { position: fixed; top:186px; left:186px; width:558px; height:372px; } #corner1 { position: fixed; top:186px; left:186px; display: none; } #corner2 { position: fixed; top:186px; left:744px; display: none; } #corner3 { position: fixed; top:558px; left:744px; display: none; } #corner4 { position: fixed; top:558px; left:186px; display: none; } They seem to just wink at me, rather than fade in in the order I've ascribed to them. Should I be using the queue() function? And, if so, how would I implement it in this case? Thank you for any assistance.

    Read the article

  • Images not showing in ie7 using jquery cycle and jCarouselLite plugin

    - by Geetha
    Hi All, I am using jquery cycle and jCarouselLite plugin to display images as slide. Images are getting displayed in ie7. but working perfect in ie6. Image Property inside the cycle control: Protocol: Not available Type: Not available Address(url): Not available Size: Not available Dimensions: 100X100 but control having the url. if i tried that image url separate it showing the image. Code: $('#slide').cycle({ fx: 'fade', continuous: true, speed: 7500, timeout: 55000, sync: 1 }); Html Code: <div id="slide"> <img src="samp1.jpg" width="664" height="428" border="0" /> <img src="samp2.jpg" width="664" height="428" border="0" /> <img src="samp3.jpg" width="664" height="428" border="0" /> <img src="samp4.jpg" width="664" height="428" border="0" /> <img src="samp5.jpg" width="664" height="428" border="0" /> <img src="samp6.jpg" width="664" height="428" border="0" /> <img src="samp7.jpg" width="664" height="428" border="0" /> <img src="samp8.jpg" width="664" height="428" border="0" /> </div> Geetha.

    Read the article

  • Jquery resizing image

    - by michele
    I'd like to start a discussion about the image resizing using jQuery. That's my contribution: But I think I'm far away from the solution. What about the cropping? Who can help me? $(document).ready(function() { $('.story-small img').each(function() { var maxWidth = 100; // Max width for the image var maxHeight = 100; // Max height for the image var ratio = 0; // Used for aspect ratio var width = $(this).width(); // Current image width var height = $(this).height(); // Current image height // Check if the current width is larger than the max if(width > maxWidth){ ratio = maxWidth / width; // get ratio for scaling image $(this).css("width", maxWidth); // Set new width $(this).css("height", height * ratio); // Scale height based on ratio height = height * ratio; // Reset height to match scaled image } // Check if current height is larger than max if(height > maxHeight){ ratio = maxHeight / height; // get ratio for scaling image $(this).css("height", maxHeight); // Set new height $(this).css("width", width * ratio); // Scale width based on ratio width = width * ratio; // Reset width to match scaled image } }); });

    Read the article

  • Jquery selectors question

    - by Ben
    Hi all, I am not an expert at jquery but trying to get a menu to work. Basically, I have a menu made of up to 3 levels of nested lists. The first level has a little arrow has a background image that opens or close when opening the first level list. Any other nested lists don't need to have the background image. My script opens the menu when you click on it and is also supposed to switch the first level list from a class "inactive" to a class "active". Here is the script: $(document).ready(function(){ $("#left-navigation-holder ul.level1 li.inactive").toggle(function(){ $(this).addClass("active"); }, function () { $(this).removeClass("active"); }); $("#left-navigation-holder li a").click(function(){ menu = $(this).parent('li').children('ul'); menu.toggle(); }); }); The problem is that the toggle function also happens when clicking on second and third level lists causing the arrows to toggle even if the first level list isn't clicked on. I thought using $("#left-navigation-holder ul.level1 li.inactive").toggle would limit the function to the first level list with a class "inactive". Any help would be really appreciated. Ben

    Read the article

  • Jquery Accordion : set action to a specific element inside header

    - by J.Tay
    by default, if we have something like this as a Header in jQuery Accordion : <h3> <div class="1">TEXT</div> <div class="2">ICON</div> <div class="3">BUTTON</div> </h3> by clicking anywhere on this , accordion works and toggle the next element and ... the question is , how can we set an option and select a specific element ( like: 'div' with class '1' ) to click on it to and toggle the accordion. i mean i don't want the whole Header remain click able. i just want to click on a icon or div o something inside the header and toggle open/close the accordion. thank you Update 1 : HTML : <div id="testAcc"> <h3> <div class="one">Text</div> <div class="two">Icon</div> <div class="three">Button</div> </h3> <div class="accBody"> text text text text text text text text text text </div> <h3> <div class="one">Text</div> <div class="two">Icon</div> <div class="three">Button</div> </h3> <div class="accBody"> text text text text text text text text text text </div> </div> JS : $('#testAcc').accordion({ autoHeight: false, header: 'h3', collapsible: 'ture', }); this codes working fine. but i want to use something like ( header: 'h3.one' ) means i want to set a specific class and element inside the header , then if user click ONLY on that element, the accordion will open or close ...

    Read the article

  • How to add divs inside a div using jquery

    - by Neal
    Hi, I am trying to insert a div inside another div using add() of jquery but it is not working " <div class="portlet" id="panel1"> <div class="portlet-header">1.Feeds</div> <div class="portlet-content">Lorem ipsum dolor sit amet, consectetuer adipiscing elit</div> </div> <div class="portlet" id="panel2"> <div class="portlet-header">2.News</div> <div class="portlet-content">Lorem ipsum dolor sit amet, consectetuer adipiscing elit</div> </div> " " <div class="portlet" id="panel3"> <div class="portlet-header">3.Shopping</div> <div class="portlet-content">Lorem ipsum dolor sit amet, consectetuer adipiscing elit</div> </div> " Actually panel1 and panel2 are inside a div, and panel3 is inside another div.I want to remove panel3 from its div and place it between panel1 and panel2 in their div.

    Read the article

  • jQuery Dialog form serialize reposting incorrect data on subsequent uses

    - by Ben Dauphinee
    I'm working with forms inside jQuery Dialog, and am having some issues with the data it's posting. First load and save works fine, posts the correct data. Until I refresh the page though, every subsequent load seems to work, as in the correct data is in the form, however, when saved, the data from the first load is what is posted every time. function formdialog(url, tack, divid, scriptload){ $.getJSON(url+tack+"/form", function(data){ var formwin = '<div><form id="formdialog">'+data['form']+'</form></div>'; var dialog = $(formwin).dialog({ title: data['title'], autoOpen: false, modal: true, buttons: { "Save": function(){ $.post(url+tack+"/process", $("#formdialog").serialize(), function(data){ alert($("#formdialog").serialize()); $(this).dialog('close'); $(this).remove(); } ); }, "Cancel": function(){$(this).dialog('close'); $(this).remove();} } }); dialog.dialog("open"); }); } $(function(){ $("a.edlnk").click(function(){ var url = $(this).attr("href"); formdialog(CONFIG_HREF_SITE+"ajax/"+appControl, "/"+url, divid); return false; }); });

    Read the article

  • Center DIV via jQuery

    - by tony noriega
    I have a footer that is fixed to the bottom of the viewport. I am using jQuery toggle to open a comment card for users to comment and submit: $('a#footer-comment').click(function() { $("#comment-card").toggle(300); return false; $('#comment-card').show({ position:); }); $('a#footer-comment-hide').click(function() { $("#comment-card").toggle(300); return false; $('#comment-card').hide(); }); naturally if i dont add any CSS selectors to #comment-card it shows up UNDER the footer, and out of sight. So i added: {position:absolute; bottom:30px; left:auto;} 30px so it shows up above the footer which is 30px high. Problem is, i can not get this to center in the viewport... if i use pixels, depending on the resolution, it is either too far left or right... how do i center this in the viewport?

    Read the article

  • jquery animate from object center

    - by mtwallet
    Hi. I am trying to create a product viewer similar to the one at the bottom of this page http://www.logitech.com/en-gb/. As you can see the product animates from the center rather than top left which I think is Jquery's default. So what I am doing is trying animate the width and height and then also the offset to make it look like it animates from the center. My code looks like this: <style> body { background: black; } .box { background: #fff url('pic.jpg') no-repeat 0 0; width: 200px; height: 200px; margin: 10px 4%; float: left; } </style> <script type="text/javascript"> $(document).ready(function() { $(".box").hover(function() { $(".box").not(this).fadeTo(500, 0.5); $(this).animate({ width: 300, height: 300, left: -100, top: -100 }, 500); }, function() { $(this).animate({ width: 200, height: 200, left: 100, top: 100 }, 500); $(".box").fadeTo(500, 1); }); }); </script> I cannot seem to get this working as I want. Can anyone help with this or suggest a better technique? Many thanks

    Read the article

  • jQuery removing elements from DOM put still reporting as present

    - by RyanP13
    Hi, I have an address finder system whereby a user enters a postcode, if postcode is validated then an address list is returned and displayed, they then select an address line, the list dissappears and then the address line is split further into some form inputs. The issue i am facing is when they have been through the above process then cleared the postcode form field, hit the find address button and the address list re-appears. Event though the list and parent tr have been removed from the DOM it is still reporting it is present as length 1? My code is as follows: jQuery // when postcode validated display box var $addressList = $("div#selectAddress > ul").length; // if address list present show the address list if ($addressList != 0) { $("div#selectAddress").closest("tr").removeClass("hide"); } // address list hidden by default // if coming back to modify details then display address inputs var $customerAddress = $("form#detailsForm input[name*='customerAddress']"); var $addressInputs = $.cookies.get('cpqbAddressInputs'); if ($addressInputs) { if ($addressInputs == 'visible') { $($customerAddress).closest("tr").removeClass("hide"); } } else { $($customerAddress).closest("tr").addClass("hide"); } // Need to change form action URL to call post code web service $("input.findAddress").live('click', function(){ var $postCode = encodeURI($("input#customerPostcode").val()); if ($postCode != "") { var $formAction = "customerAction.do?searchAddress=searchAddress&custpc=" + $postCode; $("form#detailsForm").attr("action", $formAction); } else { alert($addressList);} }); // darker highlight when li is clicked // split address string into corresponding inputs $("div#selectAddress ul li").live('click', function(){ $(this).removeClass("addressHover"); //$("li.addressClick").removeClass("addressClick"); $(this).addClass("addressClick"); var $splitAddress = $(this).text().split(","); $($customerAddress).each(function(){ var $inputCount = $(this).index("form#detailsForm input[name*='customerAddress']"); $(this).val($splitAddress[$inputCount]); }); $($customerAddress).closest("tr").removeClass("hide"); $.cookies.set('cpqbAddressInputs', 'visible'); $(this).closest("tr").fadeOut(250, function() { $(this).remove(); }); });

    Read the article

  • Lights off effect and jquery placement on wordpress

    - by Alexander Santiago
    I'm trying to implement a lights on/off on single posts of my wordpress theme. I know that I have to put this code on my css, which I did already: #the_lights{ background-color:#000; height:1px; width:1px; position:absolute; top:0; left:0; display:none; } #standout{ padding:5px; background-color:white; position:relative; z-index:1000; } Now this is the code that I'm having trouble with: function getHeight() { if ($.browser.msie) { var $temp = $("").css("position", "absolute") .css("left", "-10000px") .append($("body").html()); $("body").append($temp); var h = $temp.height(); $temp.remove(); return h; } return $("body").height(); } $(document).ready(function () { $("#the_lights").fadeTo(1, 0); $("#turnoff").click(function () { $("#the_lights").css("width", "100%"); $("#the_lights").css("height", getHeight() + "px"); $("#the_lights").css({‘display’: ‘block’ }); $("#the_lights").fadeTo("slow", 1); }); $("#soft").click(function () { $("#the_lights").css("width", "100%"); $("#the_lights").css("height", getHeight() + "px"); $("#the_lights").css("display", "block"); $("#the_lights").fadeTo("slow", 0.8); }); $("#turnon").click(function () { $("#the_lights").css("width", "1px"); $("#the_lights").css("height", "1px"); $("#the_lights").css("display", "block"); $("#the_lights").fadeTo("slow", 0); }); }); I think it's a jquery. Where do I place it and how do I call it's function? Been stuck on this thing for 6 hours now and any help would be greatly appreciated...

    Read the article

  • JQuery - Check when image is loaded?

    - by JasonS
    Hi, I am having a bit of trouble working out when an image has been loaded. I have been told that the following function will work but it isn't doing anything. $("#photos img:first").load(function (){ alert("Image loaded!"); }); There are no error's in my code. Everything else in my script works great. My HTML looks like this. <div id="photos"> <img src="../sample1.jpg" style="background-color:#000033" width="1" height="1" alt="Frog!"/> <img src="../sample2.jpg" style="background-color:#999999" width="1" height="1" alt="Zooey!"/> </div> Do I have the wrong JQuery function? It should also be noted that the visibility is set to hidden. However even when visible there is no alert. Any ideas?

    Read the article

  • Export to csv in jQuery

    - by Rahul Joshi
    I am dynamically generating a div which is like : <div id='PrintDiv'> <table id="mainTable"> <tr> <td> Col1 </td> <td> Col2 </td> <td> Col3 </td> </tr> <tr> <td> Val1 </td> <td> Val2 </td> <td> Val3 </td> </tr> <tr> <td> Val11 </td> <td> Val22 </td> <td> Val33 </td> </tr> <tr> <td> Val111 </td> <td> Val222 </td> <td> Val333 </td> </tr> </table> </div> And there are lot more elements on the page as well. Now, how can i get a csv file like this : Col1,Col2,Col3 Val1,Val2,Val3 Val11,Val22,Val33 Val111,Val222,Val333 using jQuery ? need a file save dailog box too,like this : Thanks.

    Read the article

  • jQuery sliding animation not working

    - by Jake Zeitz
    I have three divs stacked on each other but offset so that a part of each div is visible. When one of the bottom divs is clicked I want the top div to animate out and back into the stack at the bottom, then the div that is clicked will appear at the top. So far I only have the code for when the middle div is clicked, but I cannot get it to work properly. What am I doing wrong? (I also realize that the code I wrote is probably terrible, this is the first jQuery code I have written.) The css is very very simple: .first { z-index: 3; } .second { z-index: 2; } .third { z-index: 1; } The basic html is this: <div class="first"></div> <div class="second"></div> <div class="third"></div> Here is my code: $("div.second").click(function () { $("div.first").animate({ left: "-=200px"}, {duration: "fast", complete: function () { $("div.first").removeClass("first").addClass("third").animate({left: "+=350px", top: "+=60px"}, "fast"); } }); $("div.second").animate({ left: "-=24px", top: "-=30px"}, {duration: "fast", complete: function () { $("div.second").removeClass("second").addClass("first"); } }); $("div.third").animate({ left: "-=24px", top: "-=30px"}, {duration: "fast", complete: function () { $("div.third").removeClass("third").addClass("second"); } }); }); I can get the div.first to move to the side and back. But now I can't get the classes to stay changed. What keeps happening is the div.second will remove it's class and add .first in the animation, but when the animation is complete, it acts like it still has a class of .second.

    Read the article

  • Problem using the prependTo() in jQuery

    - by raulriera
    Hi all, I am having a problem trying to use the prependTo() function in jQuery... for some reason I can't get this to work $(" <div id="note178" class="note"> <div class="delete"><a href="/chart-notes/delete/178" onclick="$.ajax({ dataType: 'script', url: '/chart-notes/delete/178'}); return false;"><img src='/images/icons/delete.png'></a></div> <div class="timestamp">1 minute ago </div> <div class="content">ñasdas dasdasdasd conclusión</div> </div> ").prependTo(".notes").fadeIn("slow"); Although when doing it like this, it works fine $.ajax({ url:'/chart-notes/show/<cfoutput>#chartnote.id#</cfoutput>', success: function(data) { $(data).prependTo(".notes").fadeIn("slow"); // Scroll to the top of the annotations $('html, body').animate({scrollTop: $(".notes").offset().top}, 1000); // Clear the form $('#chartnote-notes').val(""); } }); The "data" response from that success function is the same <div id="note178" class="note"> <div class="delete"><a href="/chart-notes/delete/178" onclick="$.ajax({ dataType: 'script', url: '/chart-notes/delete/178'}); return false;"><img src='/images/icons/delete.png'></a></div> <div class="timestamp">1 minute ago </div> <div class="content">ñasdas dasdasdasd conclusión</div> </div> As before

    Read the article

  • Jquery unidentified data return when post

    - by Nhat Tuan
    <?php //load.php $myid = $_POST['id']; if($myid == 1){ echo '1'; }else if($myid == 0){ echo '0'; } ?> <html> <input id="id" /> <div id="result"></div> <input type="button" id="submit" /> <script type="text/javascript"> $('#submit').click( function(){ var send = 'id=' + $('#id').val(); $.post('load.php', send, function(data){ if(data == 1){ $('#result').html('Success'); }else if(data == 0){ $('#result').html('Failure'); }else{ $('#result').html('Unknow'); } }); }); </script> </html> I test this script in some free host and it work but in my real host jquery unidentified data return and it alway show 'Unknow'. When i change if(data == '1') it show 'Unknow' too EX: input id = 1 click submit & data return is 'Unknow' Why ?? I think this error from host, because i test it in some free host and it work, but now in my real host i got this error, how i can fix it ?

    Read the article

  • Jquery drag /drop and clone

    - by Sajeev
    Hi I need to achive this .. I have a set of droppable items ( basically I am droping designs on a apparel ) and I am dropping a clone.. If I don't like the dropped object (designs) - I want to delete that by doing something like hidden . But I am unable to do that. Please help me.. here is the code var clone; $(document).ready(function(){ $(".items").draggable({helper: 'clone',cursor: 'hand'}); $(".droparea").droppable({ accept: ".items", hoverClass: 'dropareahover', tolerance: 'pointer', drop: function(ev, ui) { var dropElemId = ui.draggable.attr("id"); var dropElem = ui.draggable.html(); clone = $(dropElem).clone(); // clone it and hold onto the jquery object clone.id="newId"; clone.css("position", "absolute"); clone.css("top", ui.absolutePosition.top); clone.css("left", ui.absolutePosition.left); clone.draggable({ containment: 'parent' ,cursor: 'crosshair'}); $(this).append(clone); alert("done dragging "); /lets assume I have a delete button when I click that clone should dissapear so that I can drop another design - but the following code has no effect //and the item is still visible , how to make it dissapear ? $('#newId').css("visibility","hidden"); } }); });

    Read the article

  • Recommendations for jQuery tooltips

    - by jerome
    I am looking for tooltip plugins for jQuery that would allow for the following type of behavior. <a href="somewhere.html"> <span> <img src="someimage.jpg" style="display: none;" /> Here is the tooltip content. </span> Here is the link to somewhere. </a> The behavior that I am hoping for is to hover over "Here is the link to somewhere" and have a tooltip pop up showing the content of the span containing "someimage.jpg" and "Here is the tooltip content". I would prefer that the tooltip track along with the mouse's movement over the link and that the tooltip's appearace (background color, opacity, border color, etc.) be configurable. The two most popular tooltips that I have found, "clueTip" and Jörn Zaefferer's "Tooltip" do not seem to fit the bill, unless I am missing something. Ultimately, the links and images will be dynamically generated.

    Read the article

  • How to cancel a jquery.load()?

    - by Dirk Jönsson
    I'd like to cancel a .load() operation, when the load() does not return in 5 seconds. If it's so I show an error message like 'sorry, no picture loaded'. What I have is... ...the timeout handling: jQuery.fn.idle = function(time, postFunction){ var i = $(this); i.queue(function(){ setTimeout(function(){ i.dequeue(); postFunction(); }, time); }); return $(this); }; ... initializing of the error message timeout: var hasImage = false; $('#errorMessage') .idle(5000, function() { if(!hasImage) { // 1. cancel .load() // 2. show error message } }); ... the image loading: $('#myImage') .attr('src', '/url/anypath/image.png') .load(function(){ hasImage = true; // do something... }); The only thing I could not figure out is how to cancel the running load() (if it's possible). Please help. Thanks! Edit: Another way: How do I prevent the .load() method to call it's callback function when it's returning?

    Read the article

  • Find and replace certain part of value (jquery)

    - by Hakan
    This might be a little complicated. See code below. When image is clicked I want to change "MY-ID-NUMBER" in "value" and "src" of object. But I want the other information to remain. When link is clicked I want to restore "value" and "src" so I can use the same function for next image that is clicked. Is it possible? Please help! My HTML: <img height="186" width="134" alt="4988" src="i123.jpg"> <img height="186" width="134" alt="4567" src="i124.jpg"> <a class="restore-to-default" href="#">DVD</a> <div class="tdt"> <object width="960" height="540"><param name="movie" value="http://www.domain.com/v3.4/player.swf?file=http://se.player-feed.domain.com/cinema/MY-ID-NUMBER/123-1/><param name="wmode" value="transparent" /><param name="allowFullScreen" value="true" /><param name="allowScriptAccess" value="always" /><embed id="player" name="player" type="application/x-shockwave-flash" src="http://www.player.domain.com/v3.4/player.swf?file=http://se.player-feed.domain.com/cinema/MY-ID-NUMBER/123-1/&display_title=over&menu=true&enable_link=true&default_quality=xxlarge&controlbar=over&autostart=true&backcolor=000000&frontcolor=ffffff&share=0&repeat=always&displayclick=play&volume=80&linktarget=_blank" width="960" height="540"allowFullScreen="true" allowScriptAccess="always"></embed></object> My jquery: $('img').click(function(){ var alt = $(this).attr("alt"); $('.tdt object').val("alt", alt); // Some how change "MY-ID-NUMBER" into the "alt-value" of image }); $('a').click(function(){ //restore to "MY-ID-NUMBER" }); Thanks!

    Read the article

  • jquery drag and drop

    - by eba
    I'm using JQuery draggable. If a table is in div then I can move this div with the table. When there is an input-button in the div then it doesnt move. Why? $(".multidraggable").draggable(); doesnt work: <div class="multidraggable" style="display: inline-block;"> <input type="button" value="????? ?? &#10; ??????????? ????? &#10; ??? ??? &rdquo;??????&rdquo;" id="button1" style="font-family:arial; width: 200px; height: 80px;max-height:80px;max-width:200px; font-size:15" /> </div> works: ...

    Read the article

  • How to do drag-n-drop and resize on an image using jQuery?

    - by Scott
    How do I resize and image using jQuery but keep its aspect ratio the same? <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <title>CrossSlide - A jQuery plugin to create pan and cross-fade animations</title> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script> </head> <body> <style type="text/css"> #resizebleImage { background: silver; } </style> <script type="text/javascript"> $(document).ready(function(){ $("#resizebleImage").resizable().parent().draggable(); }); </script> <img id="resizebleImage" src="http://images.askmen.com/galleries/singer/gloria-estefan/pictures/gloria-estefan-picture-4.jpg"> </body> </html>

    Read the article

  • Jquery number of clicks record

    - by Maxime
    Hi, I am working on this page where I'm using a Jquery Mp3 Player (Jplayer) with its playlist. What I want to do is very simple in theory: I want to record the number of clicks for every playlist element. When someone enters the page, his number of clicks are at 0 for every element. The visitor can click a few times on element #1, then go to element #2 (which will be at 0), then come back to element #1 and the number of clicks must be saved. We don't need to save it for next visits. Jplayer has this function that loads each time a new playlist element is being loaded: function playListChange( index ) In which every element has its own ID dynamically updated: myPlayList[index].song_id Here's my code: function playListChange( index ) { var id = myPlayList[index].song_id; if(!o) { var o = {}; } if(!o[id]) { o[id] = 0; } alert(o[id]); … $("#mydiv").click { o[id] = o[id]+1; } … But o[id] is reset every time and the alert always show 0. Why? Thanks for any reply.

    Read the article

< Previous Page | 231 232 233 234 235 236 237 238 239 240 241 242  | Next Page >