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  • Python to C# with openSSL requirement

    - by fonix232
    Hey there again! Today I ran into a problem when I was making a new theme creator for chrome. As you may know, Chrome uses a "new" file format, called CRX, to manage it's plugins and themes. It is a basic zip file, but a bit modified: "Cr24" + derkey + signature + zipFile And here comes the problem. There are only two CRX creators, written in Ruby or Python. I don't know neither language too much (had some basic experience in Python though, but mostly with PyS60), so I would like to ask you to help me convert this python app to a C# class. Also, here is the source of crxmake.py: #!/usr/bin/python # Cribbed from http://github.com/Constellation/crxmake/blob/master/lib/crxmake.rb # and http://src.chromium.org/viewvc/chrome/trunk/src/chrome/tools/extensions/chromium_extension.py?revision=14872&content-type=text/plain&pathrev=14872 # from: http://grack.com/blog/2009/11/09/packing-chrome-extensions-in-python/ import sys from array import * from subprocess import * import os import tempfile def main(argv): arg0,dir,key,output = argv # zip up the directory input = dir + ".zip" if not os.path.exists(input): os.system("cd %(dir)s; zip -r ../%(input)s . -x '.svn/*'" % locals()) else: print "'%s' already exists using it" % input # Sign the zip file with the private key in PEM format signature = Popen(["openssl", "sha1", "-sign", key, input], stdout=PIPE).stdout.read(); # Convert the PEM key to DER (and extract the public form) for inclusion in the CRX header derkey = Popen(["openssl", "rsa", "-pubout", "-inform", "PEM", "-outform", "DER", "-in", key], stdout=PIPE).stdout.read(); out=open(output, "wb"); out.write("Cr24") # Extension file magic number header = array("l"); header.append(2); # Version 2 header.append(len(derkey)); header.append(len(signature)); header.tofile(out); out.write(derkey) out.write(signature) out.write(open(input).read()) os.unlink(input) print "Done." if __name__ == '__main__': main(sys.argv) Please could you help me?

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  • not getting output from parmiko/ssh command

    - by Matt
    I am using paramiko/ssh/python to attempt to run a command on a remote server. When I ssh manually and run the command in question, I get the results I want. But if I use the python (co-opted from another thread on this site) below, there is no returned data. If I modify the command to be something more basic like 'pwd' or 'ls' I can then get the output. Any help is appreciated. Thanks, Matt import paramiko import time import sys, os, select import select username='medelman' password='Ru5h21iz' hostname='10.15.27.166' hostport=22 cmd='tail -f /x/web/mlog.txt' #works cmd='' #doesn't work client = paramiko.SSHClient() client.load_system_host_keys() client.connect(hostname=hostname, username=username, password=password) transport = client.get_transport() channel = transport.open_session() channel.exec_command(cmd) while True: rl, wl, xl = select.select([channel],[],[],0.0) if len(rl) 0: # Must be stdout print channel.recv(1024) time.sleep(1)

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  • Django database caching

    - by hekevintran
    I have a Django form that uses an integer field to lookup a model object by its primary key. The form has a save() method that uses the model object referred to by the integer field. The model's manager's get() method is called twice, once in the clean method and once in the save() method: class MyForm(forms.Form): id_a = fields.IntegerField() def clean_id_a(user_id): id_a = self.cleaned_data['id_a'] try: # here is the first call to get MyModel.objects.get(id=id_a) except User.DoesNotExist: raise ValidationError('Object does not exist') def save(self): id_a = self.cleaned_data['id_a'] # here is the second call to get my_model_object = MyModel.objects.get(id=id_a) # do other stuff I wasn't sure whether this hits the database two times or one time so I returned the object itself in the clean method so that I could avoid a second get() call. Does calling get() hit the database two times? Or is the object cached in the thread? class MyForm(forms.Form): id_a = fields.IntegerField() def clean_id_a(user_id): id_a = self.cleaned_data['id_a'] try: # here is my workaround return MyModel.objects.get(id=id_a) except User.DoesNotExist: raise ValidationError('Object does not exist') def save(self): # looking up the cleaned value returns the model object my_model_object = self.cleaned_data['id_a'] # do other stuff

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  • error in midlet while implementing command..

    - by garima
    hi I have imported import com.sun.lwuit.Command; import javax.microedition.midlet.; import javax.microedition.lcdui.; in my code but still the following errors are coming... exitCommand = new Command("Exit", Command.EXIT, 2); //line 1 textbox.addCommand(exitCommand); //line 2 Command.EXIT cannot be resolved.. The method addCommand(Command) in the type Displayable is not applicable for the arguments (Command)

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  • How do I get PHP variables from this MySQL query?

    - by CT
    I am working on an Asset Database problem using PHP / MySQL. In this script I would like to search my assets by an asset id and have it return all related fields. First I query the database asset table and find the asset's type. Then depending on the type I run 1 of 3 queries. <?php //make database connect mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); //get type of asset $type = mysql_query(" SELECT asset.type From asset WHERE asset.id = 93120 ") or die(mysql_error()); switch ($type){ case "Server": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serial_number ,server.esc ,server.user ,server.prev_user ,server.warranty FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = 93120 "); break; case "Laptop": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,laptop.manufacturer ,laptop.model ,laptop.serial_number ,laptop.esc ,laptop.user ,laptop.prev_user ,laptop.warranty FROM asset LEFT JOIN laptop ON laptop.id = asset.id WHERE asset.id = 93120 "); break; case "Desktop": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,desktop.manufacturer ,desktop.model ,desktop.serial_number ,desktop.esc ,desktop.user ,desktop.prev_user ,desktop.warranty FROM asset LEFT JOIN desktop ON desktop.id = asset.id WHERE asset.id = 93120 "); break; } ?> So far I am able to get asset.type into $type. How would I go about getting the rest of the variables (laptop.model to $model, asset.notes to $notes and so on)? Thank you.

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  • WCF Multiple Services

    - by David
    Hi, im brand spanking new to WCF and Im trying to understand how to correctly expose my BLL to it. I created my first Resource.svc and IResource.svc Resource.svc [ServiceBehavior] public class Resources : IResources { #region IResources Members public List<Model.Resource> GetAll() { return Repository.Inventory.Resource.GetAll(true); } public List<Model.Resource> GetAllEnabled() { return Repository.Inventory.Resource.GetAllEnabled(true); } #endregion } IResource.cs [ServiceContract] public interface IResources { [OperationContract] List<Model.Resource> GetAll(); [OperationContract] List<Model.Resource> GetAllEnabled(); } So this all works, My windows app can talk to the service and all is great. So I now need to access some information, I have created another .svc file called Project.svc and IProject.cs, this contains the same info as resource (apart from the type is Project) But this now means I have another webservice, surley this is not right!?

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  • NSEntityDescription entityForName returning nil

    - by Kamchatka
    Hi, I did some changes to my model (but I don't want migration yet, so I just remove the application, built clean etc.) so my application works in the simulator. However, when I run it on the iPhone, I get the following error: *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'executeFetchRequest:error: A fetch request must have an entity.' I set the entity like this: NSEntityDescription *entity = [NSEntityDescription entityForName:@"Document" inManagedObjectContext:managedObjectContext]; My managedObjectContext is not nil. But I suspect that it doesn't load the object model correctly or something similar because If I display the entities in the model, the list is empty. How can I make sure the model is loaded? Thanks,

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  • Netbeans with Oracle connection java.lang.ClassNotFoundException

    - by Attilah
    I use NetBeans 6.5 . When I try to run the following code : package com.afrikbrain.numeroteur16; import java.sql.Connection; import java.sql.DriverManager; import java.sql.SQLException; import java.util.logging.Level; import java.util.logging.Logger; /** * * @author */ public class NumeroteurTest { public NumeroteurTest() { } public void doIt() throws ClassNotFoundException{ try { Class.forName("oracle.jdbc.OracleDriver"); Connection connection = DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:XE","user","pwd"); String newNUMERO = new Numeroteur16("MATCLI", connection).numeroter(); System.out.println("NUMERO GENERE : "+newNUMERO.toString()); } catch (SQLException ex) { Logger.getLogger(NumeroteurTest.class.getName()).log(Level.SEVERE, null, ex); ex.printStackTrace(); } catch (NumException ex) { System.out.println(ex.getMessage()); ex.printStackTrace(); } } public static void main(String[] args){ try { new NumeroteurTest().doIt(); } catch (ClassNotFoundException ex) { Logger.getLogger(NumeroteurTest.class.getName()).log(Level.SEVERE, null, ex); System.out.println("Driver not found."); } } } when running it, I get this error : java.lang.ClassNotFoundException: oracle.jdbc.OracleDriver at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) at java.lang.ClassLoader.loadClass(ClassLoader.java:252) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at com.afrikbrain.numeroteur16.NumeroteurTest.doIt(NumeroteurTest.java:27) at com.afrikbrain.numeroteur16.NumeroteurTest.main(NumeroteurTest.java:45) Driver not found. how do I solve this problem ?

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  • Error in playing a swf file on internet explorer

    - by Rajeev
    In the below code i get an error saying Error #2007: Parameter url must be non-null on Ineternet explorer only.What am i doing wrong here html <OBJECT classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" WIDTH="50" HEIGHT="50" id="myMovieName"> <PARAM NAME="movie" VALUE="/media/players/testsound.swf" /> <PARAM NAME="quality" VALUE="high" /> <PARAM NAME="bgcolor" VALUE="#FFFFFF" /> <EMBED href="/media/players/testsound.swf" src="/media/players/testsound.swf" flashvars="soundUrl=sound.mp3" quality=high bgcolor=#FFFFFF NAME="myMovieName" ALIGN="" TYPE="application/x-shockwave-flash"> </EMBED> </OBJECT> mxml ; import flash.net.; import mx.controls.Alert; import mx.controls.Button; import flash.events.Event; import flash.media.Sound; import flash.net.URLRequest; private function clickhandler(event:Event):void { var musicfile:String; var s:Sound = new Sound(); s.addEventListener(Event.COMPLETE, onSoundLoaded); var req:URLRequest = new URLRequest("/opt/cloodon/site/media/players/sound.mp3"); //musicfile = stage.loaderInfo.parameters["soundUrl"]; //var req:URLRequest = new URLRequest(musicfile); s.load(req); } private function onSoundLoaded(event:Event):void { //Alert.show("1"); //var localSound:Sound = event.currentTarget as Sound; var localSound:Sound = event.target as Sound; localSound.play(); } ]]> </fx:Script> <fx:Declarations> <!-- Place non-visual elements (e.g., services, value objects) here --> </fx:Declarations> <!--<mx:Button id="play" label="PLAY" click="clickhandler(event)" />--> <mx:Image id="loader1" source="@Embed(source='/opt/cloodon/site/media/img/speaker.gif')" click="clickhandler(event)" /> </s:Application>

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  • Getting broken link error whle Using App Engine service accounts

    - by jade
    I'm following this tutorial https://developers.google.com/bigquery/docs/authorization#service-accounts-appengine Here is my main.py code import httplib2 from apiclient.discovery import build from google.appengine.ext import webapp from google.appengine.ext.webapp.util import run_wsgi_app from oauth2client.appengine import AppAssertionCredentials # BigQuery API Settings SCOPE = 'https://www.googleapis.com/auth/bigquery' PROJECT_NUMBER = 'XXXXXXXXXX' # REPLACE WITH YOUR Project ID # Create a new API service for interacting with BigQuery credentials = AppAssertionCredentials(scope=SCOPE) http = credentials.authorize(httplib2.Http()) bigquery_service = build('bigquery', 'v2', http=http) class ListDatasets(webapp.RequestHandler): def get(self): datasets = bigquery_service.datasets() listReply = datasets.list(projectId=PROJECT_NUMBER).execute() self.response.out.write('Dataset list:') self.response.out.write(listReply) application = webapp.WSGIApplication( [('/listdatasets(.*)', ListDatasets)], debug=True) def main(): run_wsgi_app(application) if __name__ == "__main__": main() Here is my app.yaml file code application: bigquerymashup version: 1 runtime: python api_version: 1 handlers: - url: /favicon\.ico static_files: favicon.ico upload: favicon\.ico - url: .* script: main.py And yes i have added app engine service account name in google api console Team tab with can edit permissions. When upload the app and try to access the link it says Oops! This link appears to be broken. Ealier i ran this locally and tried to access it using link localhost:8080.Then i thought may be running locally might be giving the error so i uploaded my code to http://bigquerymashup.appspot.com/ but still its giving error.

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  • What's an easy way to set up object communication in Obj-C?

    - by seaworthy
    I am trying to send a slider value from a controller object to a method of a model object. The later is implemented in the separate file and I have appropriate headers. I think the problem is that I am not sure how to instantiate the receiver in order to produce a working method for the controller. Here is the controller's method. -(IBAction)setValue:(id)slider {[Model setValue:[slider floatValue]];} @implementation Model -(void)setValue:(float)n{ printf("%f",n); } @end What I get is 'Model' may not respond to '+setValue' warning and no output in my console. Any insight is appreciated.

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  • Django: Summing values

    - by Anry
    I have a two Model - Project and Cost. class Project(models.Model): title = models.CharField(max_length=150) url = models.URLField() manager = models.ForeignKey(User) class Cost(models.Model): project = models.ForeignKey(Project) cost = models.FloatField() date = models.DateField() I must return the sum of costs for each project. view.py: from mypm.costs.models import Project, Cost from django.shortcuts import render_to_response from django.db.models import Avg, Sum def index(request): #... return render_to_response('index.html',... How?

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  • Performance of looping over an Unboxed array in Haskell

    - by Joey Adams
    First of all, it's great. However, I came across a situation where my benchmarks turned up weird results. I am new to Haskell, and this is first time I've gotten my hands dirty with mutable arrays and Monads. The code below is based on this example. I wrote a generic monadic for function that takes numbers and a step function rather than a range (like forM_ does). I compared using my generic for function (Loop A) against embedding an equivalent recursive function (Loop B). Having Loop A is noticeably faster than having Loop B. Weirder, having both Loop A and B together is faster than having Loop B by itself (but slightly slower than Loop A by itself). Some possible explanations I can think of for the discrepancies. Note that these are just guesses: Something I haven't learned yet about how Haskell extracts results from monadic functions. Loop B faults the array in a less cache efficient manner than Loop A. Why? I made a dumb mistake; Loop A and Loop B are actually different. Note that in all 3 cases of having either or both Loop A and Loop B, the program produces the same output. Here is the code. I tested it with ghc -O2 for.hs using GHC version 6.10.4 . import Control.Monad import Control.Monad.ST import Data.Array.IArray import Data.Array.MArray import Data.Array.ST import Data.Array.Unboxed for :: (Num a, Ord a, Monad m) => a -> a -> (a -> a) -> (a -> m b) -> m () for start end step f = loop start where loop i | i <= end = do f i loop (step i) | otherwise = return () primesToNA :: Int -> UArray Int Bool primesToNA n = runSTUArray $ do a <- newArray (2,n) True :: ST s (STUArray s Int Bool) let sr = floor . (sqrt::Double->Double) . fromIntegral $ n+1 -- Loop A for 4 n (+ 2) $ \j -> writeArray a j False -- Loop B let f i | i <= n = do writeArray a i False f (i+2) | otherwise = return () in f 4 forM_ [3,5..sr] $ \i -> do si <- readArray a i when si $ forM_ [i*i,i*i+i+i..n] $ \j -> writeArray a j False return a primesTo :: Int -> [Int] primesTo n = [i | (i,p) <- assocs . primesToNA $ n, p] main = print $ primesTo 30000000

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  • How to extend models of other applications in Django?

    - by culebrón
    I have a small app with Category model and want to make a required foreign key referencing it from Photologue Gallery model. What's the right approach? I can make many-to-many field in Category, but this way it will not be required in Gallery. Use "register" and modify the Gallery model? Inherit it in my app?

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  • Joining different models in Django

    - by Andrew Roberts
    Let's say I have this data model: class Workflow(models.Model): ... class Command(models.Model): workflow = models.ForeignKey(Workflow) ... class Job(models.Model): command = models.ForeignKey(Command) ... Suppose somewhere I want to loop through all the Workflow objects, and for each workflow I want to loop through its Commands, and for each Command I want to loop through each Job. Is there a way to structure this with a single query? That is, I'd like Workflow.objects.all() to join in its dependent models, so I get a collection that has dependent objects already cached, so workflows[0].command_set.get() doesn't produce an additional query. Is this possible?

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  • Monitor database table for external changes from within Rails application

    - by jhwist
    I'm integrating some non-rails-model tables in my Rails application. Everything works out very nicely, the way I set up the model is: class Change < ActiveRecord::Base establish_connection(ActiveRecord::Base.configurations["otherdb_#{RAILS_ENV}"]) set_table_name "change" end This way I can use the Change model for all existing records with find etc. Now I'd like to run some sort of notification, when a record is added to the table. Since the model never gets created via Change.new and Change.save using ActiveRecord::Observer is not an option. Is there any way I can get some of my Rails code to be executed, whenever a new record is added? I looked at delayed_job but can't quite get my head around, how to set that up. I imagine it evolves around a cron-job, that selects all rows that where created since the job last ran and then calls the respective Rails code for each row.

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  • test is null in the controller upon post

    - by user281180
    I have the following codes and the test value is always null in the controller after the post. What is wrong with the following code: Model: public class Suitcase { public string Color { get; set; } public string[] Size { get; set; } public List<string> Clothes { get; set; } public List<Test> test { get; set; } } public class Test { public string Name { get; set; } public int ID { get; set; } } The view: <fieldset> <legend>All about my baggage</legend> <div class="editor-label"> <%: Html.LabelFor(model => model.Color) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Color) %> </div> <br /> <div class="editor-label"> Width, Height, Depth: </div> <div class="editor-field"> ml.TextBoxFor(model => model.Depth, new { style = "width:50px;" })%> </div> <br /> <div class="editor-label">Suitcase Contents</div> <div class="editor-field"> <div id="clothes-editor"> Clothing Item: <input type="text" id="new-clothes-item" style="width:150px" /> <button id="add-clothes">Add to suitcase</button> </div> <b>Items currently in suitcase:</b> <ul id="clothes-list"> </ul> </div> <p> <button id="pack-it">Put on Baggage Carosel</button> </p> </fieldset> <script type="text/javascript" language="javascript"> $(function () { $("button").button(); // allow users to add items to the suitcase $("#add-clothes").click(function () { var clothesText = $("#new-clothes-item"); $("#clothes-list").append("<li>" + clothesText.val() + "</li>"); clothesText.val("").focus(); }); // pack the suitcase up and send it to the baggage carosel...erm...controller $("#pack-it").click(function () { var clothesList = []; $("#clothes-list li").each(function () { clothesList.push($(this).text()) }); var SizeList = []; SizeList[0] = "Medium"; SizeList[1] = "Large"; SizeList[2] = "small"; var Data = new Object(); Data.test = []; var reading = {}; reading.Name = "Micheal" reading.ID = 123; Data.test[0] = reading; reading.Name = "Rowen" reading.ID = 1234; Data.test[1] = reading; $.ajax({ type: 'POST', traditional: true, data: { Color: $("#Color").val(), Size: SizeList, Clothes: clothesList, test: Data.test } }); }); }); </script> Controller: [HttpPost] public EmptyResult Suitcase(Suitcase lookWhatIPacked) { return new EmptyResult(); }

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  • django: How to make one form from multiple models containing foreignkeys

    - by Tim
    I am trying to make a form on one page that uses multiple models. The models reference each other. I am having trouble getting the form to validate because I cant figure out how to get the id of two of the models used in the form into the form to validate it. I used a hidden key in the template but I cant figure out how to make it work in the views My code is below: views: def the_view(request, a_id,): if request.method == 'POST': b_form= BForm(request.POST) c_form =CForm(request.POST) print "post" if b_form.is_valid() and c_form.is_valid(): print "valid" b_form.save() c_form.save() return HttpResponseRedirect(reverse('myproj.pro.views.this_page')) else: b_form= BForm() c_form = CForm() b_ide = B.objects.get(pk=request.b_id) id_of_a = A.objects.get(pk=a_id) return render_to_response('myproj/a/c.html', {'b_form':b_form, 'c_form':c_form, 'id_of_a':id_of_a, 'b_id':b_ide }) models class A(models.Model): name = models.CharField(max_length=256, null=True, blank=True) classe = models.CharField(max_length=256, null=True, blank=True) def __str__(self): return self.name class B(models.Model): aid = models.ForeignKey(A, null=True, blank=True) number = models.IntegerField(max_length=1000) other_number = models.IntegerField(max_length=1000) class C(models.Model): bid = models.ForeignKey(B, null=False, blank=False) field_name = models.CharField(max_length=15) field_value = models.CharField(max_length=256, null=True, blank=True) forms from mappamundi.mappa.models import A, B, C class BForm(forms.ModelForm): class Meta: model = B exclude = ('aid',) class CForm(forms.ModelForm): class Meta: model = C exclude = ('bid',) B has a foreign key reference to A, C has a foreign key reference to B. Since the models are related, I want to have the forms for them on one page, 1 submit button. Since I need to fill out fields for the forms for B and C & I dont want to select the id of B from a drop down list, I need to somehow get the id of the B form into the form so it will validate. I have a hidden field in the template, I just need to figure how to do it in the views

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  • Hibernate won't save into database

    - by Blitzkr1eg
    I mapped some classes to some tables with hibernate in java, i set hibernate to show SQL, it opens the session, it show that id does the SQL, it closes the session but there are no modifications to the database. Entity public class Profesor implements Comparable<Profesor> { private int id; private String nume; private String prenume; private int departament_id; private Set<Disciplina> listaDiscipline; //the teacher gives some courses} public class Disciplina implements Comparable<Disciplina>{ //the course class private int id; private String denumire; private String syllabus; private String schNotare; private Set<Lectie> lectii; private Set<Tema> listaTeme; private Set<Grup> listaGrupuri; // the course gets teached/assigmened to some groups of students private Set<Assignment> listAssignments;} Mapping <hibernate-mapping default-cascade="all"> <class name="model.Profesor" table="devgar_scoala.profesori"> <id name="id" column="id"> <generator class="increment"/> </id> <set name="listaDiscipline" table="devgar_scoala.`profesori-discipline`"> <key column="Profesori_id" /> <many-to-many class="model.Disciplina" column="Discipline_id" /> </set> <property name="nume" column="Nume" type="string" /> <property name="prenume" column="Prenume" type="string" /> <property name="departament_id" column="Departamente_id" type="integer" /> </class> <class name="model.Grup" table="devgar_scoala.grupe"> <id name="id" unsaved-value="0"> <generator class="increment"/> </id> <set name="listaStudenti" table="devgar_scoala.`studenti-grupe`"> <key column="Grupe_id" /> <many-to-many column="Studenti_nrMatricol" class="model.Student" /> </set> <property name="nume" column="Grupa" type="string"/> <property name="programStudiu" column="progStudii_id" type="integer" /> </class> <class name="model.Disciplina" table="devgar_scoala.discipline" > <id name="id" > <generator class="increment"/> </id> <property name="denumire" column="Denumire" type="string"/> <property name="syllabus" type="string" column="Syllabus"/> <property name="schNotare" type="string" column="SchemaNotare"/> <set name="listaGrupuri" table="devgar_scoala.`Discipline-Grupe`"> <key column="Discipline_id" /> <many-to-many column="Grupe_id" class="model.Grup" /> </set> <set name="lectii" table="devgar_scoala.lectii"> <key column="Discipline_id" not-null="true"/> <one-to-many class="model.Lectie" /> </set> </class> The only 'funny' thing is that the Profesor object gets loaded not with/by Hibernate but with manual classic SQL Java. Thats why i save the Profesor object like this p - the manually loaded Profesor object Profesor p2 = (Profesor) session.merge(p); session.saveOrUpdate(p2); //flush session of course After this i get in the Java console: Hibernate: insert into devgar_scoala.grupe (Grupa, progStudii_id, id) values (?, ?, ?) but when i look into the database there are no new rows in the table Grupe (the Groups table)

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  • Compiling Objective-C project on Linux (Ubuntu)

    - by Alex
    How to make an Objective-C project work on Ubuntu? My files are: Fraction.h #import <Foundation/NSObject.h> @interface Fraction: NSObject { int numerator; int denominator; } -(void) print; -(void) setNumerator: (int) n; -(void) setDenominator: (int) d; -(int) numerator; -(int) denominator; @end Fraction.m #import "Fraction.h" #import <stdio.h> @implementation Fraction -(void) print { printf( "%i/%i", numerator, denominator ); } -(void) setNumerator: (int) n { numerator = n; } -(void) setDenominator: (int) d { denominator = d; } -(int) denominator { return denominator; } -(int) numerator { return numerator; } @end main.m #import <stdio.h> #import "Fraction.h" int main( int argc, const char *argv[] ) { // create a new instance Fraction *frac = [[Fraction alloc] init]; // set the values [frac setNumerator: 1]; [frac setDenominator: 3]; // print it printf( "The fraction is: " ); [frac print]; printf( "\n" ); // free memory [frac release]; return 0; } I've tried two approaches to compile it: Pure gcc: $ sudo apt-get install gobjc gnustep gnustep-devel $ gcc `gnustep-config --objc-flags` -o main main.m -lobjc -lgnustep-base /tmp/ccIQKhfH.o:(.data.rel+0x0): undefined reference to `__objc_class_name_Fraction' I created a GNUmakefile Makefile: include ${GNUSTEP_MAKEFILES}/common.make TOOL_NAME = main main_OBJC_FILES = main.m include ${GNUSTEP_MAKEFILES}/tool.make ... and ran: $ source /usr/share/GNUstep/Makefiles/GNUstep.sh $ make Making all for tool main... Linking tool main ... ./obj/main.o:(.data.rel+0x0): undefined reference to `__objc_class_name_Fraction' So in both cases compiler gets stuck at undefined reference to `__objc_class_name_Fraction' Do you have and idea how to resolve this issue?

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  • Apply a Quartz filter while saving PDF under Mac OS X 10.6.3

    - by olpa
    Using Mac OS X API, I'm trying to save a PDF file with a Quartz filter applied, just like it is possible from the "Save As" dialog in the Preview application. So far I've written the following code (using Python and pyObjC, but it isn't important for me): -- filter-pdf.py: begin from Foundation import * from Quartz import * import objc page_rect = CGRectMake (0, 0, 612, 792) fdict = NSDictionary.dictionaryWithContentsOfFile_("/System/Library/Filters/Blue \ Tone.qfilter") in_pdf = CGPDFDocumentCreateWithProvider(CGDataProviderCreateWithFilename ("test .pdf")) url = CFURLCreateWithFileSystemPath(None, "test_out.pdf", kCFURLPOSIXPathStyle, False) c = CGPDFContextCreateWithURL(url, page_rect, fdict) np = CGPDFDocumentGetNumberOfPages(in_pdf) for ip in range (1, np+1): page = CGPDFDocumentGetPage(in_pdf, ip) r = CGPDFPageGetBoxRect(page, kCGPDFMediaBox) CGContextBeginPage(c, r) CGContextDrawPDFPage(c, page) CGContextEndPage(c) -- filter-pdf.py: end Unfortunalte, the filter "Blue Tone" isn't applied, the output PDF looks exactly as the input PDF. Question: what I missed? How to apply a filter? Well, the documentation doesn't promise that such way of creating and using "fdict" should cause that the filter is applied. But I just rewritten (as far as I can) sample code /Developer/Examples/Quartz/Python/filter-pdf.py, which was distributed with older versions of Mac (meanwhile, this code doesn't work too): ----- filter-pdf-old.py: begin from CoreGraphics import * import sys, os, math, getopt, string def usage (): print ''' usage: python filter-pdf.py FILTER INPUT-PDF OUTPUT-PDF Apply a ColorSync Filter to a PDF document. ''' def main (): page_rect = CGRectMake (0, 0, 612, 792) try: opts,args = getopt.getopt (sys.argv[1:], '', []) except getopt.GetoptError: usage () sys.exit (1) if len (args) != 3: usage () sys.exit (1) filter = CGContextFilterCreateDictionary (args[0]) if not filter: print 'Unable to create context filter' sys.exit (1) pdf = CGPDFDocumentCreateWithProvider (CGDataProviderCreateWithFilename (args[1])) if not pdf: print 'Unable to open input file' sys.exit (1) c = CGPDFContextCreateWithFilename (args[2], page_rect, filter) if not c: print 'Unable to create output context' sys.exit (1) for p in range (1, pdf.getNumberOfPages () + 1): #r = pdf.getMediaBox (p) r = pdf.getPage(p).getBoxRect(p) c.beginPage (r) c.drawPDFDocument (r, pdf, p) c.endPage () c.finish () if __name__ == '__main__': main () ----- filter-pdf-old.py: end

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  • Haskell Type error

    - by Jon
    I am getting a Couldn't match expected type error on this code and am not sure why. Would appreciate it if someone could point me in the right direction as to fixing it. import qualified Data.ByteString.Lazy as S import Data.Binary.Get import Data.Word getBinary :: Get Word16 getBinary = do a <- getWord16be "Test.class" return (a) main :: IO () main = do contents <- S.getContents print getBinary contents Specifically it cannot match expected type 'S.ByteString - IO ()' to inferred type 'IO ()'

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  • Visual Studio Project File Help

    - by Alex Baranosky
    I would like to reconfigure the StyleCop import path in my project file. Currently it looks like this: <Import Project="$(ProgramFiles)\MSBuild\Microsoft\StyleCop\v4.3\Microsoft.StyleCop.targets" /> I would like to include the Microsoft.StyleCop.targets file in my project directory, and thus do something like this: <Import Project="$( ProjectDir)\Microsoft.StyleCop.targets" /> Is something like this possible, if so what is the proper way to do it?

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  • MVC pattern implementation. What is the n-relation between its components

    - by Srodriguez
    Dear all, I'm working in a C# project and we are , in order to get some unity across the different parts of our UI, trying to use the MVC pattern. The client is windows form based and I'm trying to create a simple MVC pattern implementation. It's been more challenging than expected, but I still have some questions regarding the MVC pattern. The problem comes mostly from the n-n relationships between its components: Here is what I've understood, but I'm not sure at all of it. Maybe someone can correct me? Model: can be shared among different Views. 1-n relationship between Model-View View: shows the state of the model. only one controller (can be shared among different views?). 1-1 relationship with the Model, 1-1 relationship with the controller Controller: handles the user actions on the view and updates the model. One controller can be shared among different views, a controller interacts only with one model? I'm not sure about the two last ones: Can a view have several controller? Or can a view share a controller with another view? Or is it only a 1:1 relationship? Can a controller handle several views? can it interact with several models? Also, I take advantage of this question to ask another MVC related question. I've suppressed all the synchronous calls between the different members of the MVC, making use of the events and delegates. One last call is still synchronous and is actually the most important one: The call between the view and the controller is still synchronous, as I need to know rather the controller has been able to handle the user's action or not. This is very bad as it means that I could block the UI thread (hence the client itself) while the controller is processing or doing some work. How can I avoid this? I can make use of the callback but then how do i know to which event the callback comes from? PS: I can't change the pattern at this stage, so please avoid answers of type "use MVP or MVVC, etc ;) Thanks!

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  • MVC pattern implementation. What is the n-relation between its components

    - by Srodriguez
    Dear all, I'm working in a C# project and we are , in order to get some unity across the different parts of our UI, trying to use the MVC pattern. The client is windows form based and I'm trying to create a simple MVC pattern implementation. It's been more challenging than expected, but I still have some questions regarding the MVC pattern. The problem comes mostly from the n-n relationships between its components: Here is what I've understood, but I'm not sure at all of it. Maybe someone can correct me? Model: can be shared among different Views. 1-n relationship between Model-View View: shows the state of the model. only one controller (can be shared among different views?). 1-1 relationship with the Model, 1-1 relationship with the controller Controller: handles the user actions on the view and updates the model. One controller can be shared among different views, a controller interacts only with one model? I'm not sure about the two last ones: Can a view have several controller? Or can a view share a controller with another view? Or is it only a 1:1 relationship? Can a controller handle several views? can it interact with several models? Also, I take advantage of this question to ask another MVC related question. I've suppressed all the synchronous calls between the different members of the MVC, making use of the events and delegates. One last call is still synchronous and is actually the most important one: The call between the view and the controller is still synchronous, as I need to know rather the controller has been able to handle the user's action or not. This is very bad as it means that I could block the UI thread (hence the client itself) while the controller is processing or doing some work. How can I avoid this? I can make use of the callback but then how do i know to which event the callback comes from? PS: I can't change the pattern at this stage, so please avoid answers of type "use MVP or MVVC, etc ;) Thanks!

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